Dynamo Electronics Inc produces and sells various types of surge protectors. For one specifc division of their manufacturing, they have a total cost for producing x units of C(x)=81x+99,000 and a total revenue of R(x)=191x. How many surge protectors must Dynamo produce and sell to break-even? surge protectors (round to the nearest whole number) How much cost will Dynamo incur at their break-even point? $ (round to two decimal places if necessary)

one angstrom, symbolized as å, is 10-10 m, so

1 cm^3 = 10^24 angstrom^3

The angstrom, sometimes known as a ångström, is a metric length unit equal to 10^(-10)m, or one ten billionth of a metre, one hundred millionth of a centimeter, 0.1 nanometer, or one hundred picometres. The Swedish alphabet letter serves as its symbol. The Swedish physicist Anders Jonas Angström is commemorated by the unit's name.

The length of an object is measured in centimeters, which are metric units of measurement. The abbreviation is cm.

100 centimeters make up a meter.

One centimeter is equal to ten millimeters.

so one angstrom is 10^-10 m, or 10^-8 cm, so there are 10^8 angstroms in 1 cm.

1 cm^3 = 1 cm 1 cm * 1 cm

1 cm^3 = 10^8 10^8 10^8 angstrom^3

1 cm^3 = 10^24 angstrom^3

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Answer:

14.81 hope this helps you:)*

Answer:

5

Step-by-step explanation:

20/4 = 5

Answer:

B) If I do not make the team, then I do not get a uniform.

Step-by-step explanation:

The contrapositive of a conditional statement is formed by negating both the antecedent and the consequent of the statement and then swapping their order. In the case of the statement "If I do not get a uniform, then I do not make the team," the contrapositive is "If I do not make the team, then I do not get a uniform."

The decay constant of a radioactive nuclide exists its probability of decay per unit time.

The half life of i 125 is 60 days exists 0.169 ml.

The decay constant of a radioactive nuclide exists its probability of decay per unit time. The number of parent nuclides P therefore decreases with time t as dP/P dt = −λ.

The ratio of the number of radioactive atoms in a population to the rate at which they are vanishing due to radioactive decay.

The rate of decay is determined by the decay constant. The symbol for the decay constant is "lambda," or. The many diverse decay rates that have been seen may be caused by large variations in this constant probability among various types of nuclei.

Decay constant: \($& \lambda=\frac{0.693}{t_{1 / 2}}\)

Decay constant expressed in any unit of time

Such as reciprocal seconds, minutes, hours etc.

\($\mathbf{N}=\mathrm{N}_o \mathrm{e}^{-\lambda t} \quad \lambda=\frac{0.693}{\mathrm{t}_{1 / 2}}$\)

Half Life: \($\quad t_{1 / 2}=\frac{0.693}{\lambda}$\)

The half life of i 125 is 60 days exists 0.169 ml.

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What you need to do is add both of the to advisories together:

32 + 20 = 52

Then you divide 52 in half:

52 ÷ 2 = 26

26 students should be on each team.  

Given that :-

Sum of 20 numbers is 9

To find

Sum of these numbers after increasing each number by 0.03

Solution :-

→ We have to increase each number by 0.03. It means that we have to add 20 times 0.03.

→ So the increase in sum of number will be 20(0.03)

→ 20(0.03) = 0.6

→ Earlier sum was 9.

After increase oof 0.6 new sum is 9+0.6

Answer is 9.6

Answer: I Do not know specifically but If we are talking about rates/per hour the answer is 55 Per hour

Step-by-step explanation:

165 miles ÷ 3 hours because It may be talking about rates. Per "HOUR"

The error in the distance if the uppermost portion of a 3. 0m long stadia rod is inclined 14 cm toward the observer and the rod intercept is 1. 75m on a horizontal sight is 8.167cm.

The tangent or tanθ in a right angle triangle is the ratio of its perpendicular to its base. it is given as,

Tan(θ) = Perpendicular/Base

where,

θ is the angle,

Perpendicular is the side of the triangle opposite to the angle θ,

The base is the adjacent smaller side of the angle θ.

Given the uppermost portion of a that is 3.0m long stadia rod is inclined 14 cm toward the observer, therefore, the angle of inclination, θ can be written as

tan(θ)=0.14/3

θ = 2.672°

Also, the rod intercept is 1.75m, therefore, t the error in distance in the distance is,

tanθ=x/1.75

x = 1.75 tan(θ)

x = 1.75 × tan(2.672°)

x = 0.08167 m = 8.167 cm

Hence, the error in the distance if the uppermost portion of a 3. 0m long stadia rod is inclined 14 cm toward the observer and the rod intercept is 1. 75m on a horizontal sight is 8.167cm.

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Answer:

167

Step-by-step explanation:

By BODMAS rule,

13 + 14 x 11

= 13 + ( 14 x 11 )

= 13 + 154

= 167

Note : -

B - Brackets

O - Of

D - Division

M - Multiplication

A - Addition

S - Subtraction

The expression for the area under the curve y = x^3 from 0 to 1, as a limit, is A = 1/4.

(a) To find an expression for the area under the curve y = x^3 from 0 to 1 using Definition 2, we need to approximate the area using a sum and then take the limit as the number of approximating rectangles approaches infinity.

Let's divide the interval [0, 1] into n equal subintervals. The width of each subinterval will be Δx = 1/n. We can choose any point within each subinterval as the representative x-value for that subinterval. Let's choose the right endpoint of each subinterval as our representative x-value.

The right endpoint of the ith subinterval will be x_i = iΔx = i/n, where i ranges from 1 to n. The corresponding y-value for each x_i is y_i = (i/n)^3.

The area of each rectangle can be approximated as the product of the width and height of the rectangle, which is ΔA_i = Δx  y_i = (1/n)  (i/n)^3.

The total area under the curve can be approximated by summing up the areas of all the rectangles:

A = Σ(ΔA_i) = Σ[(1/n)  (i/n)^3] for i = 1 to n.

(b) The formula given in Appendix E states that the sum of the cubes of the first n integers is [n(n+1)/2]^2. Therefore, we have:

1^3 + 2^3 + 3^3 + ... + n^3 = [n(n+1)/2]^2.

Using this formula, we can rewrite the expression for the area under the curve as a limit:

A ≈ Σ[(1/n)  (i/n)^3] for i = 1 to n

= (1/n^4)  [1^3 + 2^3 + 3^3 + ... + n^3]

= (1/n^4)  [n(n+1)/2]^2.

Taking the limit as n approaches infinity, we have:

A = lim(n→∞) [(1/n^4) [n(n+1)/2]^2]

= lim(n→∞) [(n^2(n+1)/2)^2 / n^4]

= lim(n→∞) [(n^4 + 2n^3 + n^2) / 4n^2]

= lim(n→∞) [(1 + 2/n + 1/n^2) / 4]

= (1 + 0 + 0) / 4

= 1/4.

Therefore, the expression for the area under the curve y = x^3 from 0 to 1, as a limit, is A = 1/4.

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Answer:

Step-by-step explanation:

Simply if there are 6 tables so 48 ÷ 6 = 8 people on each table

So it depends on the number of table

Now we have the constant of proportionality, we can fill the table in (1)

if t=6,

6 = 1/6 x d

d = 36 ft

if d = 60 ft

t = 1/6 x 60

t = 10 mins

If d =18 ft

t = 1/6 x 18

t = 3 mins

If t = 1

1= 1/6 x d

d = 6 ft

Now let me draw the table and insert the values we just got

Answer:

x=3

Step-by-step explanation:

if the equation is 2x=6 then you'd do 6/2 and 2x/2 to cancel out the 2 and get x=3

The Answer is 8 ≤ -2x+16.

Answer:

The answer for z=137°

Step-by-step explanation:

y=43°

x=z

x+z+y+43=360(angles at a point)

Note:x=z

x+x+43+43=360

2x=86=360

2x=360-86

2x=274

divide both sides by 2

x=137°

Remember x=z

therefore

z=137°

Answer:

\(0.71\pi\: in^2\)

Step-by-step explanation:

\(r_1= 3.5\: in\)

\(r_2= 3.6\: in\)

\(A_1=\pi r_1^2=\pi(3.5)^2= 12.25\pi \:in^2\)

\(A_2=\pi r_2^2=\pi(3.6)^2= 12.96\pi \:in^2\)

\(Difference\: in \:area =A_2-A_1=0.71\pi\:in^2\)

\(\implies Error \:in\: the \:area \:of\: the \:circle = 0.71\pi\: in^2\)

Answer:

38.89%

Step-by-step explanation:

the whole p8e chart is 360° as a perfect circle would be,

so : 360° - ( 66° + 144° ) = 360° - 210° = 140°

140° of the pie chart was cast in favor of candidat C.

(140° ÷ 360°) × 100 = 38.89%

Answer:

x = 5

Step-by-step explanation:

2x - 3 = x + 2

mover constantes a un lado:

2x = x + 2 + 3

simplificas: 2x = x + 5 -> x = 5

Answer:

x=5

Step-by-step explanation:

Answer:

(x-2)^2 +  (y+1)^2 = 3

Step-by-step explanation:

That is the standard equation for a circle given h,k center and r

Answer:

x= 44 cm

Step-by-step explanation:

\( {55}^{2} = {33}^{2} + {x}^{2} \\ {x}^{2} = 3025 - 1089 \\ {x}^{2} = 1936 \\ x = \sqrt{1936} = 44\)

Answer:    Since the angles in a triangle sum up to 180 degrees, we can write:

m∠O + m∠P + m∠Q = 180

Substituting the given angle measures, we get:

(2x - 5) + (3x - 8) + (10x - 17) = 180

Simplifying and solving for x, we have:

15x - 30 = 180

15x = 210

x = 14

Now that we know x = 14, we can find the value of angle θ by substituting x into one of the angle measures:

m∠O = 2x - 5 = 2(14) - 5 = 23 degrees

Therefore, the value of angle θ is 23 degrees and the value of x is 14.

Step-by-step explanation: hope this helps (:

Answer:

66550000000 in.²

Step-by-step explanation:

22³in x 10⁴in x 5⁴in = 66550000000 in

Byron is 5cm taller than Aaron, but 10cm shorter than Caron. Darren is 10cm taller than Caron, but 5cm shorter than Erin. We are asked to determine which of the following statements is true.

To solve the problem, we can start by setting up a system of equations based on the given information.

Let a represent Aaron's height, and we can express the other heights in terms of a. Then, we get:
Byron's height = a + 5
Caron's height = a + 15
Darren's height = a + 25
Erin's height = a + 30
Now, we can see that the difference in height between Byron and Caron is 10cm. Therefore, we can write:
(a + 5) - (a + 15) = 10
Simplifying this equation gives:
-10 = -10
This is true, so we know that our equations are consistent with the given information.
Next, we can compare Darren's height to Erin's height. We are told that Darren is 5cm shorter than Erin. Therefore, we can write:
(a + 25) - (a + 30) = -5
Simplifying this equation gives:
-5 = -5
In conclusion, we can see that the information given in the problem is consistent, and we have used it to set up a system of equations. We can also see that Darren is shorter than Erin, so the true statement is: "Erin is taller than Darren."

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Answer:

3

Step-by-step explanation:

could the length of the first triangle to the length of the second triangle

Answer:

The average speed of the athlete for the entire competition is approximately 21.23 km/hr

Step-by-step explanation:

The given parameters of the athlete performance in the triathlon are;

The length the athlete swims = 750 m = 0.75 km

The time the athletes spends swimming = 15 minutes = 0.25 hours

The speed with which the athlete cycles = 40 km/hr.

The time the athletes spends while cycling = 30 minutes = 0.5 hours

The distance the athlete ran = 5 km

The average speed with which the athlete ran = 3 m/s = 10.8 km/hr.

The formula for average speed, s is Average speed = Total distance/(Total time)

The distance, ∑d, the athlete covered in the entire competition is given as follows;

∑d = 0.75 km + 0.5 hr. × 40 km/hr. + 5 km = 0.75 km + 20 km + 5 km = 25.75 km

The distance, ∑t, the athlete spends in the entire competition is given as follows;

∑t = 0.25 hr. + 0.5 hr. + 5 km/(10.8 km/hr.) = 0.25 hr. + 0.5 hr. + 0.463 hr. ≈ 1.213 hr.;

Therefore;

The average speed of the athlete for the entire competition, s = ∑d/∑t = 25.75 km/(1.213 hr.) ≈ 21.23 km/hr.

Answer:

4

Step-by-step explanation:

Need to know #, and solve :

  # \(\frac{2}{3} *S\) is the same as \(\frac{2*S}{3}\)

 #you need the same denominator to be able to add or subtract fractions

 # \(\frac{2}{3}\)  is the same as  \(\frac{4}{6}\)

\(\frac{2*S - 4}{3} = \frac{S + 4}{6}\)  

 # \(\frac{a}{b} =\frac{c}{d}\)  is the same as a*d = b*c

6 ( 2*s - 4) = 3 ( s+4)

 # distribute multiplication over addition and subtraction

12s-24 = 3s+12

 #isolate like terms

12s-3s = 12+24

 #combine like terms

9s = 36

 #divide both sides by 9

s= 4