During a run near the end of Cross-Country practice, Savanna maintained an average speed of 6.78 m/s for 2.00 minutes. What distance (in meters) did Savanna run during this time?

Answers

Answer 1

The distance (in meters) that Savanna run during this time will be 13.56 meters.

How to calculate the distance?

From the information, we are told that during a run near the end of Cross-Country practice, Savanna maintained an average speed of 6.78 m/s for 2.00 minutes.

Average speed is calculated by dividing total distance that something has traveled by the total amount of time that it took it to travel that distance. The average speed is how fast something is going at a particular moment. Average speed simply measures the average rate of speed over the extent of a trip.

It should be noted that the distance will be calculated as:

Distance = Speed × Time

Distance = 6.78 × 2

Distance = 13.56

Therefore, based on the information given it can be seen that the distance (in meters) that Savanna run during this time will be 13.56 meters.

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Related Questions

Which of the following processes is an important part of star formation? A. nuclear fusion B. nuclear fission C. molecular fusion D. molecular fission

Answers

Answer:

B

Explanation:

Answer:

Option A is correct.

Explanation:

At the temperature \(10^{7}K\) the hydrogen atoms fuse to form helium thus a large amount of heat is produced and stars are formed.

What causes a star to form?

Due to gravitational pull the particles and the molecules of gases become condense and by which it becomes hot. The process goes unless the temperature of the core becomes 10,000,000K.

At this temperature, the fusion takes place and energy is released.

Thus the star shines.

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Part 1
An engine absorbs 1969 J from a hot reservoir and expels 1223 J to a cold reservoir in each cycle. What is the engine’s efficiency? Answer with an efficiency in decimal form.


Part 2
How much work is done in each cycle?
Answer in units of J.


Part 3
What is the mechanical power output of the engine if each cycle lasts for 0.345 s?
Answer in units of kW

Answers

Answer:

Part 1: 0.3789

Part 2: 746 J

Part 3: 2.162 kW

Explanation:

Part 1:

Eff=  \(1-\frac{1223}{1969}\)

Eff= 0.378873 ≈ 0/3789

Part 2:

W= 0.3789(1969)

W= 746 J

Part 3:

\(Power=\frac{W}{t}\)

\(Power= \frac{746}{0.345}\)

Power= 2162.3188 Watts

2162.3188 W-----> 2.162 kW

A light ray, traveling parallel to the axis of a convex thin lens, strikes the lens near its midpoint. After traveling through the lens, this ray emerges traveling obliquely to the axis of the lens:

a. passing between the lens and its focal point.
b. passing through its focal point.
c. crossing the axis at a point equal to one-half the focal length.
d. such that it never crosses the axis.

Answers

Answer:

d. such that it never crosses the axis.

Explanation:

A convex lens is type of converging lens. When parallel rays of light pass through a convex lens, the rays which are refracted converge at the principal focus. Focal length is the distance between the principal focus and the centre of the lens.

A light ray, traveling parallel to the axis of a convex thin lens, strikes the lens near its midpoint. After traveling through the lens, this ray emerges traveling obliquely to the axis of the lens such that it never crosses the axis.

Please help with these MCQs.

1. Filter absorbs __________________.
- only primary coloured lights
- only secondary coloured lights
- only tertiary coloured lights
- all colors of white light

2. The light that has passed through a filter, is always ______________.
- dim
- bright
- sharp
- blur

Answers

1. Filter absorbs all colors of white light.

2. The light that has passed through a filter, is always dim.

Which colors are being absorbed by the filter?

The filter selectively transmits the red and blue portions of the incident white light spectrum, but absorbs most of the green wavelength.

Color filters absorb certain wavelengths of color and transmit the other wavelengths allowing them to be seen.

Therefore in conclusion, the right filter can reduce glare, increase contrast, and make lunar features pop.

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⦁ A 18 kg rock starting from rest free falls through a distance of 7.0 m with no air resistance. Find the momentum change of the rock caused by its fall and the resulting change in the magnitude of earth’s velocity. Earth’s mass is 6.0 × 1024 kg. Show all your work, assuming the rock-earth system is closed.

Answers

Answer:

First, we can find the velocity of the rock just before it hits the ground using the equation:

v^2 = 2gh

where v is the final velocity, g is the acceleration due to gravity (9.81 m/s^2), and h is the height the rock falls from (7.0 m).

v^2 = 2(9.81 m/s^2)(7.0 m) = 136.89 m^2/s^2

v = √136.89 m^2/s^2 = 11.7 m/s

The momentum change of the rock caused by its fall is:

Δp = mv = (18 kg)(11.7 m/s) = 211.2 kg m/s

The resulting change in the magnitude of earth's velocity can be found using the conservation of momentum equation:

m1v1 + m2v2 = (m1 + m2)v'

where m1 and v1 are the mass and velocity of the rock before it falls, m2 and v2 are the mass and velocity of the earth before the rock falls (which we can assume is negligible), and v' is the velocity of the rock-earth system after the rock falls.

We can rearrange this equation to solve for v':

v' = (m1v1)/(m1 + m2)

v' = (18 kg)(11.7 m/s)/(18 kg + 6.0 × 10^24 kg)

v' = 1.95 × 10^-24 m/s

This means that the change in the magnitude of earth's velocity is essentially zero (which makes sense, since the mass of the earth is so much greater than the mass of the rock).

The momentum change of the rock caused by its fall is 211.2 kg·m/s, and the resulting change in the magnitude of earth’s velocity is 3.5 × 10⁻²³ m/s.

What is Momentum?

Momentum is a physics concept that describes the amount of motion an object has.  The units of momentum are kg m/s. In a closed system, the total momentum before an event or interaction is equal to the total momentum after the event or interaction.

To solve this problem, we need to use the law of conservation of momentum, which states that the momentum of an isolated system remains constant.

The momentum change of the rock is given by the formula:

Δp = mv

where m is the mass of the rock, and v is the change in velocity.

First, we need to find the final velocity of the rock. We can use the formula for the velocity of a falling object:

v² = 2gh

where g is the acceleration due to gravity, and h is the height of the fall.

Plugging in the given values, we get:

v² = 2 × 9.8 m/s² × 7.0 m

v² = 137.2

v = √137.2

v = 11.7 m/s

The change in the magnitude of Earth's Velocity  can be found using the formula:

Δv = Δp / M

where M is the mass of the earth.

The mass of the earth is given as 6.0 × 10²⁴ kg.

Δp = mΔv

Δp = 18 kg × 11.7 m/s

Δp = 211.2 kg·m/s

Δv = Δp / M

Δv = 211.2 kg·m/s / 6.0 × 10²⁴ kg

Δv = 3.5 × 10⁻²³ m/s

Therefore, the momentum change of the rock caused by its fall is 211.2 kg·m/s, and the resulting change in the magnitude of earth’s velocity is 3.5 × 10⁻²³ m/s.

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A lightning bolt may carry a current of 1.00 10⁴ A for a short time. What is the resulting magnetic field 170 m from the bolt? Suppose that the bolt extends far above and below the point of observation.


__________μT

Answers

The resulting magnetic field of the bolt is 11.8  μT.

What is magnetic field?

Magnetic field is the region or space around which a magnetic force can be felt or experienced.

To calculate the magnetic field of the lightning bolt, we use the formula below

⇒ Formula:

B = μ₀I/2πr..................... Equation 1

⇒ Where:

B = Magnetic field of the lightning boltI = Currentr = distance of the field from the bolt μ₀ = Permeability of free space

From the question,

⇒ Given:

I = 1.00×10⁴ Ar = 170 mμ₀ = 4π×10⁻⁷ H/m

Substitute these values into equation 1

B = (1×10⁴×4π×10⁻⁷)/(2π×170)B = 1.18×10⁻⁵ TB = 11.8 μT

Hence, the resulting magnetic field of the bolt is 11.8  μT.

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Soda from a mS = 12 oz can at temperature TS = 12.5°C is poured in its entirety into a glass containing a mass mI = 0.17 kg amount of ice at temperature TI = -19.5°C. Assume that ice and water have the following specific heats: cI = 2090 J/(kg⋅°C) and cS = 4186 J/(kg⋅°C), and the latent heat of fusion of ice is Lf = 334 kJ/kg. In this problem you can assume that 1 kg of either soda or water corresponds to 35.273 oz.

Answers

The final temperature of the mixture of ice and soda is equal to 5 °C with a specific heat of soda and ice.

From the given,

mass of soda = 12 oz

temperature (Ts) = 12.5 °C

mass of ice (Mice) = 0.17 Kg

The temperature of ice (Tice) = -19.5°C

Specific heat of ice (Cice) = 2090 J/kg°C

Specific heat of water (Cwater) = 4186 J/kg°C

Latent heat of fusion of ice (Lf) = 334 kJ/kg.

The final temperature (T₂)=?

Mass of water = 12 / 35.274 = 0.34 kg

The heat lost by soda = heat gained by the ice

heat (Q) = m×c×ΔT where m is mass, C is specific heat and ΔT is a change in temperature.

M(soda)×C(water)×ΔT = M(ice)×Lf + M(ice)×C(ice)(T₂-T₁) + M(ice)×C(w)(T₂-0)

0.34×4186×(T₂-12.5) = (0.17×334) + (0.17× 2090×(T₂ + 19.5)+ (0.17×4186×T₂)

17790.5 - 1423.24 (final temp)= 6985.13 + 711.62 (final temp)

10805.37 = 2134.56 (final.temp)

T₂= 10805.37 / 2134.56

   = 5 °C.

Thus, the final temperature of the mixture is 5°C.

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A horse slows from a velocity of 9.5 m/s to 5.5 m/s over a distance of 32 m. Find time.

Answers

Answer:

8

Explanation:

Finding time= t=change in velocity or distance/acceleration

so 32/9.5-5.5

32/4

8

A car engine operates at 2000 RPM (revolutions per minute). What is the period? Give your answer in seconds

Answers

Take into account that the period is the inverse of the frequency. In this case, the frequency is 2000 rev/min, then, you have:

\(T=\frac{1}{f}=\frac{1}{2000}=0.0005\min \)

The period is 0.0005 minutes.

In seconds the answer results in:

0.0005 min = 0.0005*60 seconds = 0.03 seconds

The period is 0.03 seconds

Convert 27 Fahrenheit to Celsius

Answers

Answer:

27 degrees Fahrenheit is -2.78°c

-2.77778 celcius
I hope this helps

An object starts from rest with constant acceleration of 8m/s2

along a straight line. Find The distance travelled during the 5th second.

Answers

Initial velocity=u=0m/sAcceleration=a=8m/s^2Time=t=5sDistance=s=?

Using second equation of kinematics

\(\boxed{\sf s=ut+\dfrac{1}{2}at^2}\)

\(\\ \qquad\quad\sf{:}\dashrightarrow s=0(5)+\dfrac{1}{2}(8)(5)^2\)

\(\\ \qquad\quad\sf{:}\dashrightarrow s=4(25)\)

\(\\ \qquad\quad\sf{:}\dashrightarrow s=100m\)

what dose current equal?

Answers

There is a basic equation in electrical engineering that states how the three terms relate. It says that the current is equal to the voltage divided by the resistance or I = V/R. This is known as Ohm's law.

Hope this helps! :)

Question 1 of 7What is the change in internal energy if 90 J of thermal energy is added to asystem, and the system does 30 J of work on the surroundings? Use AU = Q -W.OA. 130 JB. -60 JC. -130 JSUBMITOD. 60 J

Answers

Given:

The thermal energy added to the system is Q = 90 J

The work done by the system on the surroundings is W = 30 J

To find the change in internal energy.

Explanation:

According to the first law of thermodynamics, the change in internal energy can be calculated by the formula

\(\Delta U=\text{ Q-W}\)

On substituting the values, the change in internal energy will be

\(\begin{gathered} \Delta U\text{ =90-30} \\ =60\text{ J} \end{gathered}\)

Final Answer: The chage in internal energy is 60 J (option D)

To describe a position in more than one
dimension, you must use more than one______

Answers

Answer:

To describe a position in more than one dimension you must use more than one reference point. The reference point is a basis for evaluation, assessment or comparison; a criterion.

Explanation:

Hope this answer help :D

Answer:

reference point

Explanation:

how we will measure centimeters

Answers

Answer:

.

Explanation:

——»To measure centimeters, we can use ruler.

Use a ruler with the side marked either cm or mm. Align the edge of the object with the first centimeter line on the ruler, then find the length in whole centimeters, or the larger numbers on the ruler.

A 500 g squirrel with a surface area of 895 cm2 falls from a 5.6-m tree to the ground. Estimate its terminal velocity. (Use the drag coefficient for a horizontal skydiver. Assume that the squirrel can be
approximated as a rectanglar prism with cross-sectional area of width 11.3 cm and length 22.6 cm. Note, the squirrel may not reach terminal velocity by the time it hits the ground. Give the squirrel's
terminal velocity, not it's velocity as it hits the ground.)
x m/s
What will be the velocity of a 50.0 kg person hitting the ground, assuming no drag contribution in such a short distance?
x m/s

Answers

8.3 m/s is the terminal velocity of the squirrel can be calculated using the equation for terminal velocity and 10.8 m/s is the velocity of a 50.0 kg person hitting the ground.

What is velocity?
Velocity is a measure of the speed of an object's motion in a particular direction. It is a vector quantity, meaning it has both magnitude and direction. Velocity is usually measured in meters per second (m/s).

The terminal velocity of the squirrel can be calculated using the equation for terminal velocity of an object in a fluid, which is given by Vt = (2×m×g)/(ρ×Cd×A). Here, m is the mass of the object, g is the acceleration due to gravity, ρ is the density of the fluid, Cd is the drag coefficient, and A is the reference area of the object. The drag coefficient for a horizontal skydiver is 0.8, and the density of air is 1.225 kg/m^3. Therefore, the terminal velocity of the squirrel can be calculated as Vt = (2×500×9.8)/(1.225×0.8×895) = 8.3 m/s.

The velocity of a 50.0 kg person hitting the ground can be calculated using the equation for the velocity at the end of a fall, which is given by Vf = sqrt(2×g×h). Here, g is the acceleration due to gravity and h is the height of the fall. Therefore, the velocity of the person hitting the ground can be calculated as Vf = sqrt(2×9.8×5.6) = 10.8 m/s.

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5. Use the algebraic technique for adding vectors to find the total displacement of a person who walks the following three paths (displacements-on a flat field. First, she walks 25.0 m in a direction 49.00 north of east. Then she walks 23.0 m heading 15.00 north of east. Finally, she turns and walks 32.0 m in a direction 68.0° south of east. ​

Answers

Answer:

jjjjjjjjjjjjjjjj

Explanation:

The figure below shows a ball resting on a frictionless track at position A.

The ball has a mass of 20 kg and is released from position A, the acceleration due to gravity is 9.8 m/s. How much kinetic energy will the ball have at position B?

 The figure below shows a ball resting on a frictionless track at position A.The ball has a mass of 20

Answers

To find the kinetic energy at position B, we need to know the height or the velocity at position B. Without this information, we cannot calculate the exact value of the kinetic energy.

To determine the kinetic energy of the ball at position B, we need to consider the m conservation of Mechanical energy. Since the ball is released from position A, we can assume that there is no initial kinetic energy (velocity is zero), and the total mechanical energy at position A is equal to the potential energy.

The potential energy at position A can be calculated using the formula:

Potential energy at A = mass * gravitational acceleration * height

Potential energy at A = 20 kg * 9.8 m/s² * height

Now, at position B, all the potential energy is converted into kinetic energy. The kinetic energy at position B is given by the formula:

Kinetic energy at B = 1/2 * mass * velocity²

Since the ball is released from rest, the velocity at position B can be determined using the conservation of mechanical energy:

Potential energy at A = Kinetic energy at B

20 kg * 9.8 m/s² * height = 1/2 * 20 kg * velocity²

Simplifying the equation, we get:

9.8 m/s² * height = 1/2 * velocity²

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Suppose that we attach Velcro® to the non-magnetic ends of the two carts in the video and remove the mass bars, so that both carts have the same mass. We repeat the experiment shown in the video, and the carts stick together after they collide. If the launch cart travels at a speed v0
, then how fast will the combined two-cart system travel after the collision?

Suppose that we attach Velcro to the non-magnetic ends of the two carts in the video and remove the mass

Answers

In light of this, the combined two-cart system will move at the same speed as the launch cart before to the accident, or v0.

After the collision, how can the cart's velocity be calculated?

The cumulative momentum of the two carts after the collision must match the incoming momentum (vector sums, use proper signs). With the formula p = mrivri = mrfvrf + mbfvbf, you should be able to determine the missing velocity since you already know the mass, velocity, and one of the two cars' speeds.

The conservation of momentum, which is represented by the following:

m1v1 + m2v2 = (m1 + m2)vf

where the two carts' initial velocities are v1 and v2, their masses are m1 and m2, and their final velocity is vf following a collision.

Given that the two carts in this instance have the same mass, we can reduce the equation to read as follows:

2m*v0 = (2m)*vf

where m represents each cart's mass.

Solving for vf, we get:

vf = v0

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It is fun to exercise outside, but you have to be careful when it's hot. What are two things you should always do when you exercise in the heat?

Answers

Hydrate adequately and ensure you have sun protection.

Answer:

When exercising in the heat, it's important to take precautions to prevent heat-related illnesses. Two things you should always do when exercising in the heat are:

1.Stay hydrated: Drink plenty of water before, during, and after your workout to avoid dehydration. Sip water frequently, even if you don't feel thirsty.

2.Take breaks and rest in the shade: If you start feeling dizzy, lightheaded, or excessively fatigued, take a break in a cool, shaded area. Resting can help your body cool down and prevent heat exhaustion or heat stroke.







Explanation:

hope its help <:

An 8-ohm resistor is connected to a 120-volt circuit. What current will it draw?

Answers

Answer:

15 A (15 amperes of current)

Explanation:

From Ohm's Law,

Voltage, V = Current, I × Resistance, R

Making Current, I the subject:

Current, I = Votage, V/ Resistance,R

= V/R

= 120volts /8ohms

= 15 A

what happens to the momentum when two objects with same masses but different velocities collide?

Answers

The velocities will not collide and will stay the same. The masses will not either.

How the government can ensure basic human dignity is maintained in relation to safe and healthy living

Answers

To ensure basic human dignity in relation to safe and healthy living, governments can implement various measures such as accessible healthcare, adequate housing, and sanitation and clean water.

How government can ensure basic human dignity is maintained

Governments should place a high priority on ensuring that everyone has access to healthcare services, enabling them to receive the essential medical care without suffering financial difficulty. This entails providing access to necessary pharmaceuticals, cheap healthcare, and a strong healthcare system.

All citizens should have access to affordable and good housing, according to governments. Policies may include restrictions on rental costs, programs to expand the supply of affordable housing, and efforts to combat homelessness. Basic hygienic and safety criteria should be met by housing.

Governments must make sure that everyone has access to clean, safe drinking water and adequate sanitary facilities. The spread of diseases and the maintenance of sanitary living circumstances can be aided by investments in sewage systems, water treatment facilities, and public hygiene education.

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1.) A roller coaster travels on a frictionless track as shown in the illustration.
a.) If the speed of the car at Pt A is 5.0 m/s, what is the speed at Pt B

(More in the photo provided)

1.) A roller coaster travels on a frictionless track as shown in the illustration. a.) If the speed of

Answers

For the roller coaster on a frictionless track:

a. The speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.b. The height between Points A and B where kinetic energy equals potential energy is 5.0 m.c. For the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.d. For the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.

How to solve speed and height?

a. The speed of the car at Point B can be determined using the principle of conservation of energy. The total mechanical energy (sum of kinetic energy and potential energy) remains constant in the absence of external forces like friction. Therefore, if there is no energy loss, the kinetic energy at Point A is equal to the kinetic energy at Point B.

Given that the speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.

Answer: A. 5.0 m/s

b. To find the height at which kinetic energy equals potential energy, we can set the equations for kinetic energy and potential energy equal to each other.

At Point A, the roller coaster has both kinetic energy and potential energy. The total mechanical energy is the sum of these two:

Initial mechanical energy at Point A = Kinetic energy at Point A + Potential energy at Point A

At Point B, the roller coaster will have kinetic energy and potential energy, but we want to find the height at which kinetic energy equals potential energy. Let's call this height "h."

Mechanical energy at Point B = Kinetic energy at Point B + Potential energy at Point B

Since the speed at Point B is the same as the speed at Point A (5.0 m/s), the kinetic energy at both points is the same.

Equating the mechanical energy at Point A to the mechanical energy at Point B:

Initial mechanical energy at Point A = Mechanical energy at Point B

Kinetic energy at Point A + Potential energy at Point A = Kinetic energy at Point B + Potential energy at Point B

Since the kinetic energy is the same at both points, simplify the equation:

Potential energy at Point A = Potential energy at Point B

The potential energy at any point is given by the formula mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.

Therefore, at the height h between Points A and B, the potential energy equals the potential energy at Point A:

mgh = mghA

Since the mass and acceleration due to gravity are the same, cancel them out:

h = hA

This means that the height where kinetic energy equals potential energy is the same as the height at Point A.

Answer: The height between Points A and B where kinetic energy equals potential energy is 5.0 m.

c. To determine if the car will reach Point C, compare the potential energy at Point B with the potential energy at Point C. If the potential energy at Point B is greater than or equal to the potential energy at Point C, the car will reach Point C.

Potential energy at Point B = mghB

Potential energy at Point C = mghC

Given that the height at Point C is 8.0 m, compare the potential energies:

Potential energy at Point B ≥ Potential energy at Point C

mghB ≥ mghC

Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:

hB ≥ hC

Therefore, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.

d. The minimum speed needed at Point A for the car to reach Point C can be determined by comparing the potential energy at Point A with the potential energy at Point C. If the potential energy at Point A is greater than or equal to the potential energy at Point C, the car will have enough energy to reach Point C.

Potential energy at Point A = mghA

Potential energy at Point C = mghC

Given that the height at Point A is 5.0 m, compare the potential energies:

Potential energy at Point A ≥ Potential energy at Point C

mghA ≥ mghC

Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:

hA ≥ hC

Therefore, for the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.

To summarize, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m, and the height at Point A must also be greater than or equal to 8.0 m.

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Very Good! Has your understanding widened about the different physical fitness tests involved in our daily lives after the discussion? Let us see how much you have learned in this module. Directions: Base on your Physical Fitness Tests conducted, state your understanding about your results by completing the phrases below. Write your answers in your activity notebook. Activity 1: Fill in the Gap 1. In this lesson, I have learned that ______________________________________________________________ ______________________________________________________________ 2. Base on the results of my physical fitness tests, I have found out that I am capable of doing ________________________________________________ and needs improvement in ________________________________________ 3. The health-related fitness component that I like the most is_____________________because_________________________________ ______________________________________________________________ 4. As a student, I will promise ________________________________________ ____________________________________________________________

Answers

In this lesson, I have learned that physical fitness tests are essential in assessing and measuring various aspects of our physical well-being.

They provide valuable information about our current fitness levels, strengths, and areas that require improvement. These tests help in determining our overall health, identifying potential health risks, and developing personalized fitness programs.

Based on the results of my physical fitness tests, I have found out that I am capable of doing a moderate level of cardiovascular endurance exercises, such as running or cycling, and I have good flexibility.

However, I need improvement in my muscular strength and endurance, as well as my agility and coordination. These areas require more attention and targeted exercises to enhance my overall physical fitness.

The health-related fitness component that I like the most is cardiovascular endurance because it allows me to engage in activities that raise my heart rate and improve the efficiency of my cardiovascular system.

It not only enhances my overall stamina but also has numerous health benefits, such as reducing the risk of cardiovascular diseases and improving mental well-being.As a student, I will promise to incorporate regular physical activity into my daily routine.

I understand that physical fitness is crucial for my overall well-being and academic performance. I will make a conscious effort to engage in activities that target my areas of improvement, such as strength training exercises and agility drills.

Additionally, I will strive to maintain a balanced and nutritious diet to support my physical fitness goals. By prioritizing my health and fitness, I aim to lead a more active and fulfilling lifestyle while achieving my academic objectives.

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3a Define resistivity​

Answers

Question :-

\(\huge\color{red}\mathcal{\colorbox{bla}{Define resistivity}}\)

Answer :-

a measure of the resisting power of a specified material to the flow of an electric current.

Hope it is Helpful to you

3. If you puth 350 ON on a 45kg box to move it in the same direction as the push, while using 4462.53 of work. How far did you move it?

3. If you puth 350 ON on a 45kg box to move it in the same direction as the push, while using 4462.53

Answers

Given,

The applied force, F=350.0 N

The mass of the box, m=45 kg

The work done by the applied force, W=4462.5 J

The work is given by the product of the applied force and the distance through which the force is applied.

Thus the work done by the applied force on the box is given by,

\(W=F\times d\)

Where d is the distance covered by the box.

On rearranging the above equation,

\(d=\frac{W}{F}\)

On substituting the known values,

\(\begin{gathered} d=\frac{4462.5}{350} \\ =12.75\text{ m} \end{gathered}\)

Thus the box move for a distance of 12.75 m

Which well will give the most water.

YOU WILL GET 50 POINTS

Which well will give the most water. YOU WILL GET 50 POINTS

Answers

The well that will have most of the water will be well A.

What is an underground water supply?

The underground water supply is defined as a type of water that exists underground in saturated zones beneath the land surface.

From the two wells represented in the diagrams above, Well A has water supply from underground which is lacking in well B.

Therefore, well A will have most of the water more than B.

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An upright cylindrical tank with radius 5 m is being filled with water at a rate of 2 m3/min. How fast is the height of the water increasing? (Round the answer to four decimal places.)

Answers

Answer:

The height of water increasing is 8.5 x 10^-4 m/s.  

Explanation:

radius, r = 5 m

Volume per second, dV/dt = 2 m^3/min = 2/60 m^3/s

Let the height of cylinder is h.

The volume of the cylinder is given by

\(V = \pi r^2 h \\\\\frac{dV}{dt} = \pi r^2 \frac{dh}{dt}\\\\\frac{2}{30} = 3.14\times 5\times 5\times \frac{dh}{dt}\\\\\frac{dh}{dt}=8.5 \times 10^{-4} m/s\)

An object of a mass 1.50 kg is suspended from a rough pulley of a radius 30.0 cm by light stirring as shown in Figure 1. This pulley has a moment of inertia 0.030 kg m² about the axis of the pulley. The object is released from rest and the pulley rotates without encountering frictional force. Assume that the string does not slip on the pulley, Determine

a) the angular acceleration of the pulley
b) the tension in the string​

An object of a mass 1.50 kg is suspended from a rough pulley of a radius 30.0 cm by light stirring as

Answers

Newton's second law allows us to find the results for the tension of the rope and the angular acceleration of the body are  

      a) The angular acceleration is α = 26.7 rad / s²

      b) The tension of the rope T = 2.67 N

Given parameters

The mass of the block m = 1.50 kg The radius of the pulley R = 0.30 m The moment of inertia I = 0.030 kg m²

To find

Angular acceleration The tension of the rope

Newton's second law indicates that the net force is proportional to the product of the mass and the acceleration of the bodies

          ∑ F = m a

Where the bold letters indicate vectors, F is the external forces, m the mass and the acceleration of the body

A free body diagram is a diagram of the forces without the details of the bodies, in the attached we see a free body diagram of the system

Let's apply Newton's second law to the block

                     W - T = m a

Body weight is

                     W = mg

Let's substitute

                    mg - T = ma                  (1)

The pulley is a body that is in rotational motion so we use Newton's second law for rotation

           Σ τ = I α  

Where τ is the torque, I the moment of inertia and α the angular acceleration

             

In this case the reference system is located at the turning point  

            T R = I α

            T = \(\frac{I \alpha }{R}\)  

Linear and angular variables are related

            a = α R

We substitute in equation 1 and write the system of equations

            mg - T = m α R

                    T = \(\frac{I \alpha }{R}\)

We resolve

              mg = α  (m R + I / R)

             α = \(\frac{g}{R + \frac{I}{mR} }\)  

We calculate

            α = \(\frac{ 9.8}{ 0.30+\frac{0.030}{1.50 \ 0.30} }\)  

            α = 26.7 rad / s²

Let's calculate the tension of the rope

           T = \(\frac{I \alpha }{R}\)  

           T = \(\frac{0.030 \ 26.7 }{0.30}\)

           T = 2.67 N

In conclusion with Newton's second law we can find the results for the tension of the rope and the angular acceleration of the body are  

      a) The angular acceleration is alpha = 26.7 rad / s²

      b) The tension of the rope T = 2.67 N

Learn more here:  brainly.com/question/12515285

An object of a mass 1.50 kg is suspended from a rough pulley of a radius 30.0 cm by light stirring as
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