Draw the Lewis structure for chloroform, CHCl3

Answer:

An ester of sulfuric acid in which only one sulfuric acid hydroxyl group has been esterified. The product of esterification of both sulfuric acid hydroxyl groups is a sulfate ester.

Answer:

Salt is effective as a preservative because it reduces the water activity of foods. .

Answer:

It affects the amount of a species that may be hunted by said predator, controlled you can say.

It can cause evolution in prey that causes them to not be caught, Darwins theory in a way.

Explanation:

Explanation:

At the level of the community, predation reduces the number of individuals in the prey population. The best example of predation involve carnivorous interactions, in which one animal consumes another, Think of wolves hunting moose, owls hunting mice, or shrews hunting worms and insects.

The number of moles of AgCl formed during the reaction is 0.0125 mol.

Given the reaction:2AgNO3(aq) + MgCl2(aq) → 2Ag Cl(s) + Mg (NO3)2(aq)We are supposed to determine the moles of solid AgCl formed when 50.0 ml of 0.250 M AgNO3 reacts with excess MgCl2 and in the previous step, we found that 0.0125 mol of AgNO3 reacts.

We can use the stoichiometry method to find the moles of AgCl formed.

To do so, we will have to balance the given chemical equation and find out the number of moles of AgCl formed from the given reactants.

The balanced chemical equation is:2AgNO3(aq) + MgCl2(aq) → 2Ag Cl(s) + Mg (NO3)2(aq)From the equation, we can say that 2 moles of AgCl form from 2 moles of AgNO3 reacted.

In the previous step, we have found the number of moles of AgNO3 reacted, which is 0.0125 mol.

As per the balanced chemical equation, 2 moles of AgCl form from 2 moles of AgNO3 reacted.

Therefore, the number of moles of AgCl formed = (0.0125 mol AgNO3 reacted × 2 moles AgCl / 2 moles AgNO3) = 0.0125 mol AgCl.

The number of moles of AgCl formed during the reaction is 0.0125 mol.

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Answer:

The number by which we divide is called the divisor. The result obtained is called the quotient. The number left over is called the remainder.

Explanation:

Answer:

8.909466637830

Explanation:

herp derp

Answer:

0.518 g

Explanation:

Step 1: Write the balanced equation

3 CaCl₂ + 2 H₃PO₄ ⇒ Ca₃(PO₄)₂ + 6 HCl

Step 2: Calculate the moles corresponding to 0.555 g of CaCl₂

The molar mass of CaCl₂ is 110.98 g/mol.

0.555 g × 1 mol/110.98 g = 5.00 × 10⁻³ mol

Step 3: Calculate the moles of Ca₃(PO₄)₂ produced

5.00 × 10⁻³ mol CaCl₂ × 1 mol Ca₃(PO₄)₂/3 mol CaCl₂ = 1.67 × 10⁻³ mol Ca₃(PO₄)₂

Step 4: Calculate the mass corresponding to 1.67 × 10⁻³ moles of Ca₃(PO₄)₂

The molar mass of Ca₃(PO₄)₂ is 310.18 g/mol.

1.67 × 10⁻³ mol × 310.18 g/mol = 0.518 g

Answer:

Explanation:

To determine the amount of chlorine needed to make 75.0 grams of C2H2Cl4, we need to balance the chemical equation and then use the molar ratio between the reactants and product to find the amount of Cl2 needed.

The balanced equation is:

2 Cl2(g) + C2H2(g) -> C2H2Cl4(l)

Next, we can use the molar mass of C2H2Cl4 to find the number of moles of C2H2Cl4 produced:

75.0 g C2H2Cl4 x (1 mole C2H2Cl4 / 153.8 g C2H2Cl4) = 0.489 moles C2H2Cl4

Since the balanced equation has a 1:2 ratio of C2H2 to Cl2, this means that we need 2 moles of Cl2 for every mole of C2H2Cl4 produced. Therefore, we will need 2 x 0.489 moles = 0.978 moles of Cl2.

Finally, to find the volume of Cl2 at STP, we can use the ideal gas law:

PV = nRT

Where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant (0.0821 L-atm/mol-K), and T is the temperature in Kelvin (273 K).

Since the pressure is 1 atm and the temperature is 273 K, we can rearrange the equation to solve for volume:

V = nRT / P = 0.978 moles x 0.0821 L-atm/mol-K x 273 K / 1 atm = 17.1 L

Therefore, 17.1 liters of Cl2 at STP will be needed to make 75.0 grams of C2H2Cl4.

Answer:

B. Solid

Explanation:

As the problem states, the stronger the cohesive forces of a substance, the more ordered that substance is.

Asking which state has the strongest cohesive forces is the same as asking which state is the most organized.

Solids are more organized than liquids (as solids have a definite shape and volume). Liquids are more organized than gases (as liquids have a definite volume).

Answer:LxWxH

Explanation:Multiply the Length times the Height times the Width.

Answer:

its sodium hydroxide

Explanation:

At Constant temperature, the behavior of a Ideal gas more closely approximates that of an ideal gas as its volume increases due to the average distance between the molecule becomes greater.

According to the Molecular Theory of gases, at constant temperature the behavior of a sample of a real gas more closely approximates that of an ideal gas as its volume is increased because the average distance between molecules becomes greater. The temperature did not change, so the average kinetic energy and average molecular speed did not change. The molecule size does not change either, so the molecule could not have expanded. The distance between the molecules increases causing a decrease in intermolecular forces, thus reducing the interaction between the molecules.

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Answer:

Like other legumes, peanut plants improve the soil by adding nitrogen, even as they grow tasty, nutritious nuts for this season's harvest. But peanuts need help as they take nitrogen from the air and "fix" it into the soil via their root systems.

Explanation:

Answer:

92.9 I think not sure but hope this helps

Answer:

Kinetic energy

Explanation:

Di ako sure kung Tama

The reduction half-reactions for O, P, and Cu:

• O: O2 + 4 e- → 2 O2-

• P: HPO42- + 2 H+ + 2 e- → H3PO4

• Cu: Cu2+ + 2 e- → Cu+

To write the reduction half-reactions for O, P, and Cu, we need to determine the oxidation numbers for each element. The guidelines for assigning oxidation numbers are:

Using these guidelines, we can determine the oxidation numbers for O, P, and Cu:

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To predict the spontaneity of an oxidation-reduction reaction, we can use the concept of redox potentials.

Each oxidation and reduction half-reaction has an associated redox potential, which is a measure of the tendency of the reaction to occur. The difference between the redox potentials of the oxidation and reduction half-reactions is called the cell potential (Ecell) and is a measure of the overall tendency of the reaction to occur.

If the Ecell value is positive, then the reaction is spontaneous (i.e., it will occur without the need for external energy input). If the Ecell value is negative, then the reaction is non-spontaneous (i.e., it will not occur without the input of external energy).

We can predict the Ecell value of an oxidation-reduction reaction using the Nernst equation:

Ecell = E°cell - (RT/nF) * ln(Q)

where E°cell is the standard cell potential (i.e., the cell potential under standard conditions), R is the gas constant, T is the temperature, n is the number of electrons transferred in the reaction, F is Faraday's constant, and Q is the reaction quotient (which depends on the concentrations of the reactants and products).

If the calculated Ecell value is positive, then the reaction is spontaneous, and if it is negative, then the reaction is non-spontaneous.

The best description of the relationship between population size, carrying capacity, and limiting factors is: "The size of a population usually stays near its carrying capacity due to limiting factors."

Carrying capacity refers to the maximum number of individuals that a particular environment can sustainably support. It represents the limit to which a population can grow given the available resources, such as food, water, and habitat. Limiting factors, on the other hand, are the factors that restrict population growth by reducing birth rates, increasing death rates, or limiting access to resources.As a population approaches its carrying capacity, limiting factors come into play and regulate the population size. These limiting factors can include competition for resources, predation, disease, availability of suitable habitat, and other environmental factors. They act as checks on population growth, preventing it from exceeding the carrying capacity of the ecosystem.

Therefore, the size of a population usually stays near its carrying capacity because the limiting factors ensure that the population does not exceed the available resources and ecological limits of the environment. If the population surpasses the carrying capacity, the limiting factors will intensify, causing a decline in resources and an increase in mortality rates, which ultimately brings the population back towards the carrying capacity.It's important to note that the relationship between population size, carrying capacity, and limiting factors is dynamic and can vary depending on various ecological and environmental factors.

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Answer:

m = 97.9 g

Explanation:

Given data:

Volume of water = 97.90 mL

Density of water = 1.00 g/mL

Mass of water  = ?

Solution:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

by putting values,

1.00 g/mL = m / 97.90 mL

m = 1.00 g/mL × 97.90 mL

m = 97.90 g

Mass in three significant figures:

m = 97.9 g

There are vacant orbitals on the phosphorus atom that allows it to expand its octet.

There is a concept that we would need to consider as we are answering the question that we here and that is the idea of the octet rule. The octet rule states that it is only about eight electrons that can be found on the outermost shell of an atom and as such all of the compounds can be formed in obedience to this rule.

Now we should know that there are no vacant d orbitals that are present on the nitrogen atom and this stems from the fact that it does not have a 3d level as such there are no orbitals that can be able to help the Nitrogen atom so as to be able to expand its octet. This is the reason why its pentafluoride can be easily formed.

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The value of the equilibrium constant Kc or Kp for ((ab)²)/((a₂)(b²))

The equilibrium constant expression for the given chemical reaction is:

Kc = [(ab)²] / [(a₂)(b²)]

where Kc is the equilibrium constant.

Let's assume that the gases have partial pressures of p(ab), p(a2), and p(b). Then, the equilibrium constant expression can be written as:

Kp = [(p(ab))²] / [(p(a₂))(p(b²))]

Now, we can use the ideal gas law to relate the partial pressures to the number of moles of each gas:

p(ab) = (n(ab) * RT) / V

p(a2) = (n(a2) * RT) / V

p(b) = (n(b) * RT) / V

where n is the number of moles, R is the gas constant, T is the temperature in Kelvin, and V is the volume.

Substituting these expressions into the equilibrium constant expression, we get:

Kp = [(n(ab) * RT / V)²] / [(n(a₂) * RT / V) * (n(b) * RT / V)²]

Simplifying, we get:

Kp = (n(ab)² / n(a₂) * n(b)²) * (RT / V)²

We can rewrite the expression in terms of the number of moles of the reactants and products, as:

Kp = ([ab]² / [a₂] * [b]²) * (RT / P)²

where [ab], [a₂], and [b] are the molar concentrations of the reactants and products, and P is the total pressure of the gases.

Therefore, the value of the equilibrium constant Kc or Kp for ((ab)²)/((a₂)(b²)) can be calculated using the above expression. However, the specific numerical value of Kc or Kp will depend on the temperature and pressure conditions of the reaction.

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Answer:

d=m/

Explanation:

d is density, m is mass, v is volume

Given: m =10.4g, v=12.2mL

substituting in equation,

d=10.4/ 12.2

d=0.8524g/mL

To learn more about density:

The density of the liquid is 0.852 g/mL.

To calculate the density of the liquid, we need to use the formula:

Density = Mass / Volume

Given that the mass of the liquid is 10.4 g and the volume is 12.2 mL, we can substitute these values into the formula:

Density = 10.4 g / 12.2 mL

Simplifying this expression, we find:

Density = 0.852 g/mL

Density is a physical property of a substance and is defined as the amount of mass per unit volume. In this case, the density tells us that for every milliliter of the liquid, there is 0.852 grams of mass. The units of grams per milliliter (g/mL) indicate that the density is a ratio of mass to volume.It is important to note that the density of a substance can vary with temperature, so this value is only valid under the conditions at which the measurement was made. Additionally, the density can provide valuable information about the identity of a substance, as different substances have different densities.

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Cr₂O₃ ( s ) + 3H₂S ( g ) → Cr₂S₃ ( s ) + 3H₂O ( l )

mol  Cr₂S₃ = 421 : 200.19 g/mol = 2.103

mol Cr₂O₃ ≈ mol Cr₂S₃ = 2.103 ( equivalent coefficient)

mass Cr₂O₃ = 2.103 x 151.99 g/mol = 319.63 gr

Answer:

To design a robot that propels itself across an ice rink using the same principles as rockets, I would start by considering the materials that would be suitable for use on ice. Some materials that might work well for this purpose include plastic, rubber, and certain types of metal, such as aluminum or stainless steel.

Explanation:

Answer:

Explanation:

Students learn about humankind’s search for life in outer space and how it connects to robotics and engineering. NASA is interested in sending exploratory missions to one of Jupiter’s moons, Europa, which requires a lot of preparatory research and development on Earth before it can happen. One robot currently being engineered as a proof of concept for a possible trip to explore Europa is the Icefin, which is an innovative robot that can explore under ice and in water, which are the believed conditions on Europa. This lesson provides students with intriguing information about far off (distance and time!) space missions and field robotics, and also sets up two associated robotics and arts integration activities to follow. The lesson can be used individually to provide new information to students, or as a precursor to the associated activities. A PowerPoint® presentation and worksheet are provided

Answer:

Molecular formula for the organic compound is:  C₉H₁₈O₃

Explanation:

We determine the combustion reaction:

CₓHₓOₓ  +  O₂  →  CO₂  +  H₂O

We don't know the subscrip of the organic compound, that's why we put x.

Notice we have C in the compound and in CO₂. Let's find out the mass of C.  1 mol of CO₂ contains 1 mol of C

Then (7.950 g /44g/mol) of CO₂ may contain ?

(7.950 g /44g/mol) represents the moles of dioxide → 0.181 moles of C

These moles came from the mass of the organic compound, the 3.498 g.

So now, we can know the subscript for C.

If 3.498 g of the compound contain 0.181 moles of C

174.27 g of the compound may contain (174.27 .  0.181)/ 3.498 = 9

Let's do the same for the H.

1 mol of water contain 2 moles of H

(3.255 g /18 g/mol) of water, may contain  ?

3.255 g /18 g/mol = 0.181 moles . 2 = 0.362 moles of H

These moles came from the mass of the organic compound, the 3.498 g.

Let's find out the subscript for H

If 3.498 g of the compound contain 0.362 moles of H

174.27 g of the compound may contain (174.27 .  0.362)/ 3.498 = 18

Organic compound is C₉H₁₈Oₓ. If the molar mass is 174.27 g we can easily determine the moles of O

12 g/mol . 9 + 1 g/mol . 18 + 16 g/mol . X = 174.27 g/mol

(174.27 g/mol - 12 g/mol . 9 - 1 g/mol . 18 ) / 16 = 3

Molecular formula for the organic compound is:  C₉H₁₈O₃.  Therefore the complete combustion reaction is:

C₉H₁₈O₃  +  12O₂  →  9CO₂  +  9H₂O

Answer:

.063 moles Cl-

Explanation:

To find moles multiply molarity by volume.

1.4*.045=.063 moles Cl-

A cation's name, symbol, and charge must be noted in order to determine the ionic compound's formula.The symbols for sodium and oxygen are respectively Na+ and O2.Na2O is the resultant substance.

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Answer:

C

Explanation:

Hosts are typically the organism that feeds a parasite and a parasite lives off of a host so it's not those two. Prey are what's hunted, leaving predator. A predator is an organism that naturally preys on others.

The maximum mass of water that could be produced by the chemical reaction is 162 g.

The given chemical equation is: 2 C8H18(l) + 25 O2(g) → 16 CO2(g) + 18 H2O(l)In the chemical reaction of liquid octane with gaseous oxygen, the products are gaseous carbon dioxide and gaseous water.According to the balanced chemical equation, 2 moles of C8H18 react with 25 moles of O2 to form 18 moles of H2O.So, 1 mole of C8H18 react with 25/2 = 12.5 moles of O2 to form 9 moles of H2O.The molar mass of C8H18 is 114 g/mol. So, the number of moles in 17 g of C8H18 is:17 g / 114 g/mol = 0.149 molThe molar mass of O2 is 32 g/mol. So, the number of moles in 112 g of O2 is:112 g / 32 g/mol = 3.5 molFrom the balanced chemical equation, 1 mole of C8H18 react with 12.5 moles of O2 to form 9 moles of H2O.So, the number of moles of O2 required to react with 0.149 mol of C8H18 to form H2O is:(12.5 mol / 1 mol) × (0.149 mol / 2 mol) = 0.935 molThe maximum number of moles of H2O that can be produced from 0.149 mol of C8H18 and 0.935 mol of O2 is 9 mol.So, the mass of water produced from 17 g of C8H18 and 112 g of O2 is:9 mol × 18 g/mol = 162 g

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