Answer: The answer is D. KNO3
Explanation:
The graph shows that the KN03 going straight up from the temperature sign so you reversed that so that it will make it to 90°C to 30°C
To solve this we must be knowing each and every concept related to solubility. Therefore, the correct option is option D among all the given options.
What is solubility?The greatest amount of one material that may be dissolved in the other is referred to as its solubility. It is the most solute that may be dissolved into a solvent near equilibrium, resulting in a saturated solution.
When specific circumstances are satisfied, more solute can be dissolved further than the solubility limit point, resulting in a supersaturated solution. Adding extra solute after saturation or supersaturation does not enhance the concentration in the solution. Rather, the excess solute begins to precipitated out of solution. KNO\(_3\) is the compound that would have the greatest percentage recovered after cooling a saturated solution of that compound from 90°C to 30°C.
Therefore, the correct option is option D.
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The five general principles from the APA are meant to __________. A. be enforceable rules B. be posted in every office C. guide and inspire good conduct D. stand up in court Please select the best answer from the choices provided
The five general principles from the APA are meant to: C. Guide and inspire good conduct.
Which statement is true?
a particle of violet light has less energy than a particle of red light
a particle of violet light has more energy than a particle of red light
a particle of violet light has exactly the same energy as a particle of red light
particles of light do not have any energy, regardless of what color the light is
a particle of violet light has exactly the same energy as a particle of red light
Which force causes motion?
Motion is caused due to external Force.
The universe contains multiple fundamental forces, including gravity, electromagnetic force, and weak and strong nuclear forces. However, when it comes to the motion of common objects, the forces of importance are primarily gravity, friction, and applied force.
The vector sum of all the forces acting on an object is the net force. That is, the net force is the sum of all forces, taking into mind that a force is a vector, and two forces of identical size and opposing direction cancel each other out.
When you apply force to an object, it moves. However, there is a little more to the story. Newton's second rule of motion asserts that you must total up all of the forces acting on a system to determine what will happen to it.
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Estimate the maximum centripetal acceleration of the moon around the sun. For this estimate, you may assume that the earth and moon are both and circular orbits around their parent body.
Using Newton's second law and the universal gravitation law we find that the maximum acceleration response is
the acceleration around the sun is twice the acceleration around the EarthAcceleration around the Sun 6 10⁻³ m/s²Acceleration around the Earth 3 10⁻³ m/s²The universal law of Gravitation states that the force between two bodies is proportional to their masses and inversely proportional to the square of their distance
F = \(G \frac{M m}{r^2}\)
Where G is the universal gravitation constant (G = 6.67 10-11 N m²/kg²), M and m the mass of the bodies and r the distance between them
Newton's second law indicates that the force is proportional to the masses and the acceleration of the bodies
F = m a
Where F is the force, m and a the mass and acceleration of the body
let's substitute
\(G \frac{Mm}{r^2}\) = m a
a = \(G \frac{M}{r^2}\)
In this case the acceleration is called centripetal since it corresponds to a circular motion of the Moon and the Earth.
In tables we can find the values:
The mass of the Earth is 5.98 10²⁴ kgThe distance between the Moon and the Earth is 3.84 10⁸ mMass of the sun 1,991 10³⁰ kgEarth - Sun Distance 1,496 10¹¹mLet's calculate the acceleration of the Moon around the Earth
a₁ = 6.67 10⁻¹¹ \(\frac{5.98 \ 10^{24}}{ (3.84 \ 10^8 )^2 }\)
a₁ = 2.71 10⁻³ m / s²
The acceleration of the Earth around the Sun
a₂ = 6.67 10⁻¹¹ \(\frac{1.991 \ 10^{30} }{(1.496 \ 10^{11})^2 }\)
a₂ = 5.93 10⁻³ m / s²
We can see that the acceleration around the Sun is twice the acceleration of the moon around the Earth
In conclusion they use Newton's second law and the universal gravitation law, we find that the maximum acceleration response is
the acceleration around the sun is twice the acceleration around the EarthAcceleration around the Sun 6 10°³ m/s²Aacceleration around the Earth 3 10°³ m/s²Learn more here:
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In the text "White House Press Release Announcing the Bombing of Hiroshima August 6, 1945" by President Truman, in which country was the atomic bomb developed?
A. Germany
B. The United States
C. The United Kingdom
D. Japan
In the text "White House Press Release Announcing the Bombing of Hiroshima August 6, 1945" by President Truman, the atomic bomb was developed by the United States. Therefore, the correct answer is B. The United States.
During World War II, a top-secret project known as the Manhattan Project was conducted by the United States. The goal of this project was to develop an atomic bomb. The research and development efforts were led by American scientists, engineers, and military personnel. The project involved numerous facilities across the United States, including Los Alamos, New Mexico, where the final design and testing of the atomic bomb took place.
President Truman's press release announcing the bombing of Hiroshima on August 6, 1945, indicates that the United States successfully developed and deployed the atomic bomb. This historical event marked the first use of atomic weapons in warfare and had a significant impact on the outcome of World War II.
Therefore, based on the context of President Truman's press release and the historical record, it is clear that the atomic bomb was developed by the United States. Therefore, the correct answer is B.
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4. Find the period of a pendulum that is 1.2 m long.
Answer:
2.20 s
Explanation:
\(T=2\pi\sqrt\frac{L}{g}=2\pi\sqrt\frac{1.2}{9.8}}\)
T = 2.20 s
What is the moment of inertia of a 4.2-kg uniform cylindrical grinding wheel of radius 32 cm?
The moment of inertia of the uniform cylindrical grinding wheel is 2,150 kgm².
What is the moment of inertia?
This refers to the angular mass or rotational inertia can be defined with respect to the rotation axis, as a property that shows the amount of torque needed for a desired angular acceleration or a property of a body due to which it resists angular acceleration. The unit is kgm².
From the question:
Mass,M =4.2kg
Radius, R=32Cm
The formula for calculating the moment of inertia for uniform cylindrical grinding wheel:
moment of inertia, I =1/2MR²
I =\(\frac{1}{2}\) * 4.2 * 32²
=2,150.4 kgm²
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How do you measure potential and kinetic energy?
Answer:
potential energy is a stored energy or energy of position (gravitational).
Kinetic energy is a energy of motion.
Explanation:
in the formula K is for the kinetic and the P stand for the potential.
Mary pushed a box across the floor with 54N to the left and Doug helped her by exerting a force
of 75N to the left and another force of 20N was exerted on the box in the opposite direction,
what is the net force acting on the box? *
Help plzz
An oil droplet is sprayed into a uniform electric field of adjustable magnitude. The 0.11 g droplet hovers
motionless (gravity force equalling electrostatic force) when the electric field is set to 370 N/C and directed
downward.
a) Determine the sign and magnitude of the charge on the oil droplet.
b) Determine the approximate number of excess electrons that are on the oil droplet.
Answer:
The direction of the field is downward, and negatively charged particles will experience an upwards force due to the field.
F = N e E where E is the value of the field and N e the charge Q
M g = N e E and M g is the weight of the drop
N = M g / (e E)
N = 1.1E-4 * 9.8 / (1.6E-19 * 370) = 1.1 * 9.8 / (1.6 * 370) * E15 = 1.82E13
.00011 kg is a very large drop
Q = N e = M g / E = .00011 * 9.8 / 370 = 2.91E-6 Coulombs
Check: N = Q / e = 2.91E-6 / 1.6E-19 = 1.82E13 electrons
How do I know if a latin word is a deponent verb? How do i know its not just regular?
Relationship between SI unit for area and other units of area
The SI unit for area is the square meter (m²). It is a fundamental unit of measurement in the International System of Units (SI). Here are some common units of area and their relationships to the square meter:
Square kilometer (km²): 1 km² is equal to 1,000,000 square meters (1 km² = 1,000,000 m²). It is used for large-scale measurements, such as land area or geographical regions.
Hectare (ha): 1 hectare is equal to 10,000 square meters (1 ha = 10,000 m²).
Square centimeter (cm²): 1 cm² is equal to 0.0001 square meters (1 cm² = 0.0001 m²).
Square millimeter (mm²): 1 mm² is equal to 0.000001 square meters (1 mm² = 0.000001 m²).
Acre: 1 acre is equal to approximately 4046.86 square meters.
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Ite
Imagine a scenario in which an animal's force is pushing itself forward 5 N, friction is pushing it 4 N backward,
gravity is pushing the animal 10 N down, and the animal is pushing itself 10 N up. Describe the movement of
the animal. (1 point)
Ite!
Iter
o It moves forward and upward because those are the greatest net forces.
Iten
o It moves 10 N down and 10 N up as those are the greatest forces acting on the animal.
Item
Item
It only moves forward because there is a net force forward.
Item
o It moves 29 N forward because that's the net force.
Item
Item 1
Item 1
It only moves forward because there is a net force forward.
Let us note that when an object is acted upon by a system of forces, the object only moves in the direction of the net force.
We have an animal acted upon by the following forces;
5 N forward4 N backward10 N upward10 N downwardsThe upwards and downwards forces are exactly balanced so the animal neither moves upwards or downwards.
However, the animal does move forward because there is a net force that pushes the animal forward.
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Answer:C. It only moves forward because there is a net force forward.
Explanation:
two positive charges are placed in a vacuum.The coulomb force between the two charges is 3N.On sliding an insulator between these charges,coulomb force is reduced to 1.5N.Find the relative permitivity of this particular insulator.
The relative permittivity of the insulator is εr = 1 / 2 = 0.5.
What is the relative permitivity of this particular insulator?The relative permittivity of the insulator is calculated by applying the equation for the Coulomb force.
F = (kq²) / r²
where;
k is the electrostatic constant q is the magnitudes of the chargesr is the distance between the charges.The initial force equation becomes;
3 = (kq²) / r²
Let's denote the relative permittivity as εr.
The new force equation becomes;
1.5 = (kq² x εr) / r²
Divide the two force equations;
(3 / 1.5) = (kq²) / (kq² x εr)
2 = 1 / εr
εr = 1/2 = 0.5
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A science teacher asks her class to compare the way in which heat is transferred to water in a pond as opposed to soil at the edge of the pond. Which of the following investigations will help them make this comparison?
The investigation" Place soil in the bottom of a container and water on top, place it in the sun, and measure the temperature of the container" will help them make this comparison.
How to carryout this investigation?A starting point for conducting a comparative analysis is to fill a container with soil followed by pouring water on top.
The next step involves placing it under sun rays while simultaneously recording its temperature. Post that, we need to separate the sand from water to rapidly gauge any change in temperature.
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Complete question:
A science teacher asks her class to compare the way in which heat is transferred to water in a pond as opposed to the soil at the edge of the pond. Which of the following investigations will help them make this comparison?
a. Mix water and soil in a container, place it in the sun, and measure the temperature of the container.
b. Place soil and water in separate containers, place them indoors, and monitor the temperature of the containers.
c. Place soil and water in separate containers, place them in the sun, and monitor the temperatures of each container.
d. Place soil in the bottom of a container and water on top, place it in the sun, and measure the temperature of the container.
the speaker at an event hall is held up by steel cables as shown. find the tension in cables ab and bc if the speaker weighs 100 lb.
T = (m g) + (m a), where "g" denotes the acceleration caused by gravity of any objects the rope is supporting and "a" denotes any additional acceleration on any such objects, can be used to represent the tension in a given rope.
Give me a specific illustration of acceleration.An object's velocity can change based on how rapidly, slowly, or which way it is moving. As examples of acceleration, consider a falling apple, the moon orbiting the earth, or a car coming to a complete stop.
What exactly are speed and acceleration?The velocity of a displacement affects how quickly it changes. Acceleration is the term used to describe how quickly a velocity changes.
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How much energy is created when there is 110 W of
power over 30s?
Answer:
3300 J
Explanation:
P = Q/t
Q = Pt = 110 * 30 = 3300 J
A 75.0 kg astronaut is training for accelerations that he will experience upon reentry. He is placed in a centrifuge (r = 20.0 m) and spun at a constant angular velocity of 15.0 rpm (revolutions per minute). He is then slowed and brought to a stop in 2.0 minutes.
Find the magnitude and direction of the centripetal acceleration and force when he is spinning at constant angular velocity.
How many g’s is the astronaut experiencing when moving at constant angular velocity?
Find the torque that is needed to bring the centrifuge to a stop knowing the centrifuge has a mass of 5500.0 kg (ignore all other forces) and the force is applied at the edge of the centrifuge (20.0 m radius). Hint: torque is based on the change of linear velocity.
a. The magnitude and direction of the centripetal acceleration and force when he is spinning at constant angular velocity is 8.72 m/s^2 and 654.0 N respectively.
b. The astronaut is experiencing 0.89 g when moving at constant angular velocity.
c. The torque that is needed to bring the centrifuge to a stop 6875 Nm.
What is angular velocity?
Angular velocity is described as a pseudovector representation of how fast the angular position or orientation of an object changes with time.
The magnitude of the centripetal acceleration and force, we will use the formula: a = v^2 / r, where v is the tangential velocity and r is the radius of the centrifuge.
a = (2pi20m15.02pi/60)^2 / 20m = 8.72 m/s^2
To calculate the force, we will use the formula
F_ = ma, where m is the mass of the astronaut, 75.0 k
F_ = 75.0 kg * 8.72 m/s^2 = 654.0 N
b. To calculate the number of g's the astronaut is experiencing when moving at constant angular velocity, we will divide the centripetal acceleration by the acceleration due to gravity, 9.8 m/s^2
8.72 m/s^2 / 9.8 m/s^2 = 0.89 g
c.
Torque = I * alpha, where I is the moment of inertia and alpha is the angular acceleration.
I = (1/2) * 5500.0 kg * 20.0m^2 = 55000 kgm^2
The angular acceleration can be found using the formula
Alpha = (change in angular velocity) / (change in time)
The change in angular velocity is 15.0 rpm - 0 rpm = 15.0 rpm and the change in time is 2.0 minutes = 120 seconds
alpha = 15.0 rpm / 120 s = 0.125 rad/s^2
Torque = 55000 kgm^2 * 0.125 rad/s^2 = 6875 Nm
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Technician A says that when replacing a rear hatch window with defroster grids, the
wiring connection may have a locking tab that will need to be released before
removal.
Technician B says that when replacing a rear hatch window with hydraulic lift struts,
the struts should be completely compressed before removal.
Who is right?
A only
B only
Both A and B
Neither A nor B
Technician A only is tight as hen replacing a rear hatch window with defroster grids, the wiring connection may have a locking tab that will need to be released before removal.
Who is a Technician?A technician is someone with expertise and training in a technical procedure. You might need to contact a network technician if your computer network is giving you problems.
A technician is familiar with all of the technical details (ins and outs) of a particular process. A computer technician is an expert in both operating and repairing computers. Similar to a mechanic, an automotive technician is well-versed in cars and how to repair them. Technology and technicians are not always synonymous. A painter or musician may also be referred to as a technician if they have received training in a variety of artistic or musical techniques.
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The electric field in an aluminum wire is 85 mV/m.
Find the current density in the wire.
Express your answer in mega-amperes per meter squared.
If the electric field in an aluminum wire is 85 mV/m. then the current density in the wire is 3.21 MA/m²
We must use Ohm's Law and the equation connecting current density (J), electric field (E), and resistivity () in order to determine the current density in the wire.
According to Ohm's Law, the electric field, E, is equal to the sum of the current density, J, and the resistivity, : E = J *.ρ
J = E / ρ. is the result of rearranging the equation.
To find the current density in the wire, we need to use Ohm's Law and
The resistivity of aluminum is
ρ = 2.65 x 10^(-8) Ω·m.
putting the values,
we get,
J = 85 mV/m / (2.65 x 10^(-8) Ω·m).
Converting the units, the current density in the aluminum wire is approximately 3.21 mega-amperes per meter squared (3.21 MA/m²).
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Einstein's special relativity states:
options:
1) there are no consequences for traveling at the speed of light
2) it is possible to travel faster than the speed of light
3) it is not possible to travel faster than the speed of light
4) everyone has special relatives.
the light rate is comparable to all observers, including those traveling with regard to one another, and the identical laws of physics apply in all inertial navigation frames.
The five rules of science are what?The Principle of Elasticity, Dalton's Law of Limited Demands, Bernoulli's Law of Applied Physics, and Fourier's Law of Temperature Difference are the five most well-known scientific laws. Hooke's Law of Flexibility and Dalton's Law of Fractional Pressures are the other two.
Why do scientists utilize laws?Scientific laws are guiding principles which may be employed to forecast how the natural world will behave, much like scientific hypotheses. Observations and/or experimental evidence are frequently used to support scientific hypotheses and rules.
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It is useful to use a _________ to demonstrate how an electric circuit works
It is useful to use a model in order to demonstrate how an electric circuit works.
What is a model?In science, a model is a graphical representation that my result useful to predict the behavior of the components of a given system that works together to produce a particular outcome.
For example, an electrical circuit can be modeled by taking into account resistance, voltage, and intensity as parameters of functioning.
The electrical circuits are graphically represented by modeling the movement or flow of negatively charged electrons (e-) from the negative pole to the positive pole of a closed electric circuit.
In conclusion, it is useful to use a model (ie., a scientific model) to demonstrate how an electric circuit works.
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The specific heat of rubber is 2000 J/kgKJ/kgK. Suppose that a rubber ball dropped from a height of 7.0 mm bounces back to a height of 4.0 mm.
What is the temperature increase of the ball? Assume that no energy is transferred to the air or the ground.
Express your answer in degrees Celsius.
It is not 271.68C
temperature increase of the ball= 1.5*10⁻²°C or 0.015°C.
What is the temperature increase of the ball?given:
specific heat= 2000J/Kg
h1=7mm, h2=4mm.
solution:
change in Potential energy = mg(h1-h2)
heat increased of the ball = Specific heat*ΔT
mg(h1-h2)=2000*ΔT
(10(7-4))/2000=ΔT
ΔT=0.015°C
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What is 1 second….???? Give a meaningful answer…..
Explanation:
.....................................
Answer:
1 second is defined as 1/86400th part of a mean solar day.
WILL MARK BRAINLIEST JUST PLEASE HELP
Answer:
40N in either direction is the answer
Calculate the molar heat capacity at pressure and volume constant ( ) when knowing = = 1.4 and the gas density: 0 = 1.3 /3 .
(a) The molar heat capacity at pressure is 29.1 J/K.mol.
(b) The molar heat capacity at volume is 20.785 J/K.mol.
Molar heat capacity of gas at volumeMolar heat capacity of a gas at constant volume is defined as the quantity of heat required to raise the temperature of one mole of the gas by 1 degree Kelvin when its volume is constant.
Cv = R/(γ - 1)
where;
R is universal gas constant = 8.314 J/K.mol.γ is heat ratio = 1.4Cv = (8.314) / (1.4 - 1)
Cv = 20.785 J/K.mol
Molar heat capacity of gas at pressureMolar heat capacity of a gas at constant volume is defined as the quantity of heat required to raise the temperature of one mole of the gas by 1 degree Kelvin when its pressure is constant.
γ = Cp/Cv
Cp = γCv
Cp = 1.4 x 20.785
Cp = 29.1 J/K.mol
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How does radiation transfer thermal energy from the Sun to Earth?
Answer:
The thermal energy is carried by electromagnetic waves
Explanation:
There are three types of transfer of heat (thermal energy):
- Conduction: conduction occurs when two objects/two substances are in contact with each other. The heat is transferred from the hotter object to the colder object by the collisions between the molecules of the two mediums.
- Convection: convection occurs when a fluid is heated by an external source of heat. The part of the fluid closer to the heat source gets warmer, therefore it becomes less dense and it rises, and it is replaced by the colder part of the fluid, which is colder. Then, this part of fluid is heated as well, so it gets warmer, it rises, etc.. in a cycle.
- Radiation: radiation occurs when thermal energy is carried by electromagnetic waves. Since electromagnetic waves do not need a medium to propagate, this is the only method of heat transfer that can occur through a vacuum (so, in space as well).
Indeed, the Sun emits a lot of electromagnetic radiation, which travels through space and eventually reaches the Earth, heating it.
Explanation:
Difference between Weightlessness in space and weightlessness during free fall.
Weightlessness in space and weightlessness during free fall may appear similar in terms of the sensation experienced, but they occur under different circumstances and have distinct underlying causes. Here are the key differences between the two:
1.Environment:
Space: Weightlessness in space refers to the state experienced by astronauts in orbit around the Earth or in deep space. They are in a microgravity environment, far away from any significant gravitational forces.
Free fall: Weightlessness during free fall occurs when an object is falling under the influence of gravity, experiencing zero-gravity conditions momentarily. This typically happens when an object is in a state of free fall, such as during skydiving or in an airplane during a parabolic flight.
2.Gravitational Forces:
Space: In space, weightlessness is the result of being in constant free fall around the Earth. Although gravity is still present, the gravitational forces are counterbalanced by the centrifugal force created by the orbiting motion. This results in a continuous state of free fall, giving the sensation of weightlessness.
Free fall: Weightlessness during free fall occurs due to the absence of support forces countering the force of gravity. When an object is in free fall, there are no contact forces pushing against it, leading to a sense of weightlessness.
3.Duration:
Space: Weightlessness in space can last for an extended period, as long as the object or person remains in orbit or deep space. Astronauts aboard the International Space Station (ISS), for example, experience weightlessness for months at a time.
Free fall: Weightlessness during free fall is relatively brief and temporary. It occurs during the duration of the free fall, which can last for a few seconds to a couple of minutes, depending on the specific circumstances.
4.Context:
Space: Weightlessness in space is a constant state for astronauts. They adapt to this environment and conduct various experiments, work on scientific research, and live aboard the spacecraft for extended periods.
Free fall: Weightlessness during free fall is typically experienced as part of a recreational activity or a specific scientific experiment. It is a brief moment of weightlessness within the context of a larger activity, such as skydiving, parabolic flights, or drop towers.
While both weightlessness in space and weightlessness during free fall share the absence of apparent gravity and the sensation of floating, they occur in different environments, are caused by different factors, and have varying durations and contexts.
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you throw a rock directly upward with initial speed . it leaves your hand at height , rises, stops, and reverses direction. as the rock falls downward past height , which of the following statements is true? ignore air resistance.
O The speed of the rock is less than vo. O The speed of the rock is equal to vo. O The speed of the rock is greater than vo. O There is not enough information to tell.
When a boulder is hurled upward, it will halt at its highest point and then fall back down due to gravity, therefore its velocity will be zero and its downward acceleration will be g at that point.
if a rock is launched directly upward from the earth's surface. As the potential energy rises, the kinetic energy falls. A rock that is hurled straight up will accelerate and decelerate to zero when it reaches the precise top of its journey. Every mass-containing object experiences the effects of gravity from the earth. When anything is thrown upward, the earth's gravitational pull pulls it downward in opposition to the object's velocity.
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Lab: Motion with Constant Acceleration Assignment: Lab Report
Write your lab report
Someone please help me do this, ill give brainliest
Answer:
Table C:
Fan Speed Observations of Position vs. Time Graphs
Low:
The slope is curved and it increases as you go up . The points start off close but they spread out as the time increases.
Medium:
The speed increases quicker than the graph for low speed. The graph is less curved than the one for low speed. Also, the points spread out faster than they did for low speed as the time increases.
High:
The Graph has a smaller curve then the low and medium speed. Also, the points are the furthest apart. The slope is not as spaced out as it was for the rest of the speed graphs.
Explanation:
hope it helps
Variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.
Objective: The goal of this lab experiment was to investigate the motion of an item with constant acceleration and to examine its velocity as a function of time.
Materials:
Smooth, inclined plane
Cart or tiny wheeled object
Stopwatches and timers
Measuring tape or meterstick
Procedure:
Set up the inclined plane at a 45-degree angle () to the horizontal surface. Check that the plane is smooth and clear of obstacles.
Place the cart or small wheeled object at the bottom of the inclined plane.
Using a meterstick or measuring tape, determine the height (h) and length (L) of the inclined plane.
Ascertain that the cart is at rest at the starting point, which is located at the bottom of the inclined plane.
As soon as the cart is freed and begins to move, start the stopwatch or timer.
Calculate the time (t) it takes the cart to reach each place along the inclined plane. To ensure reliable data gathering, repeat the experiment numerous times.
Determine the time intervals (Δt) between each position for velocity analysis
Data:
Position (m) Time (s) Time Interval (Δt) (s)
0.0 0.00 -
0.5 0.50 0.50
1.0 0.75 0.25
1.5 1.10 0.35
2.0 1.50 0.40
Analysis:
Calculate the average velocity between each position by dividing the position change by the time interval (x/t).
Create a graph that plots average velocity (V_avg) versus time (t).
Results:
A straight line emerges from the graph of average velocity against time, demonstrating that the cart's motion was subject to continuous acceleration along the inclined plane. The slope of the graph reflects the acceleration (a) of the cart.
Conclusion:
The experiment successfully demonstrated motion along an inclined plane with constant acceleration. The graph of average velocity vs time revealed important information about the cart's speed, with a linear relationship suggesting steady acceleration. This experiment emphasizes kinematic principles and the significance of using velocity-time data to understand the motion of objects under constant acceleration.
Hence, variations in the angle of inclination or the mass of the cart could be investigated further to investigate the impact on acceleration and further validate the principles of constant acceleration motion.
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