Determine whether each cation is acidic or pH-neutral. For those cations that are acidic, write an equation that shows how the cation acts as an acid. a. NH4 b. Na c. Co3 d. CH2NH3
Answers
Cations are acidic if their corresponding anions are basic and the conjugate base of the cation is less stable. If a cation is pH-neutral, then its corresponding anion is also pH-neutral. Below is the solution to the given problem:
a. NH4+ is an acidic cation because it is the conjugate acid of NH3 (ammonia) which is a weak base. NH4+ ion can donate H+ ion and can act as an acid, for example, NH4+ + H2O → NH3 + H3O+
b. Na+ is pH-neutral as it is derived from a strong base (NaOH) and hence the anion is OH-, which is a strong base. Therefore, the solution of Na+ salt would be pH-neutral.
c. Co3+ is also pH-neutral as it does not contain any hydrogen atoms and neither its corresponding anion CO32- nor the conjugate base of Co3+ (Co2+) are basic. Hence, the solution of Co3+ salt would be pH-neutral.d. CH2NH3+ is an acidic cation as it contains an NH3 group. Hence, it can donate H+ ion and act as an acid. CH2NH3+ + H2O → CH2NH2 + H3O+
To know more about cation refer to:
https://brainly.com/question/14569206
#SPJ11
Related Questions
The emission spectrum of hydrogen is shown below. What do the lines in the
spectrum show?
A. Light with wavelengths between 410 nm to 434 nm, 434 to 486 nm, and 486 to 656 nm corresponds with the three energy levels in
hydrogen
B. Only light with wavelengths of 410 nm, 434 nm, 486 nm, and 656 nm is not taken in during energy transitions.
C. Light with wavelengths of 410 nm, 434 nm, 486 nm, and 656 no corresponds with the four energy levels in hydrogen.
D. Light with wavelengths of 410 nm, 434 nm, 486 nm, and 656 nm is given off when electrons fall to lower energy levels.
Answers
Answer:
A
Explanation:
Same air has special carakteristik features
Explain why leaf-cutter ants gather pieces of leaves and store them in their nests when they do not eat leaves.
Answers
Answer:
Sample response: Leaf-cutter ants gather pieces of leaves and store them in their nests to provide raw materials and food for the fungus that grows on the leaf pieces. The ants feed on the fungus, so by collecting leaves the ants are effectively able to grow their own food supply.
Explanation:
Answer:
Leaf-cutter ants gather pieces of leaves and store them in their nests to provide raw materials and food for the fungus that grows on the leaf pieces. The ants feed on the fungus, so by collecting leaves the ants are effectively able to grow their own food supply.
Explanation:
edg 2020
An oven takes in 1200J of energy
and transfers 375J as useful energy.
Caculate the energy.
Answers
The energy is 375 J.
Energy is the quantitative belongings that are transferred to a frame or to a physical gadget, recognizable within the overall performance of labor and within the shape of warmth and mild. power is a conserved amount—the law of conservation of strength states that power may be converted in form, but now not created or destroyed.
Calculation:-
Total energy = 1200 J
Transfered emergy = 375 J
The useful energy is the energy to do work = 375 J.
The ability or strength to do paintings, along with the potential to transport an item (of a given mass) by means of the application of pressure. power can exist in a spread of forms, which includes electric, mechanical, chemical, thermal, or nuclear, and may be transformed from one form to another.
Learn more about energy here:-https://brainly.com/question/13881533
#SPJ1
The standard heat of formation of sulfur dioxide is = Q kJ/mol. The standard heat of formation of sulfur trioxide is = R kJ/mol. What would be the ΔH for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide?
Answers
The balanced equation for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is:
2 SO2(g) + O2(g) → 2 SO3(g)
What would be the ΔH for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide?To determine the enthalpy change (ΔH) for this reaction, we can use Hess's law, which states that the overall enthalpy change for a reaction is equal to the sum of the enthalpy changes for a series of reactions that add up to the overall reaction. In other words, if we can find the enthalpy changes for a series of reactions that include the same reactants and products as the overall reaction, we can add them up to find the enthalpy change for the overall reaction.
To use Hess's law in this case, we can start with the given standard heats of formation and write the equation for the formation of sulfur trioxide from its constituent elements:
S(s) + 3/2 O2(g) → SO3(g) ΔHf° = R kJ/mol
Note that the enthalpy change for this reaction is equal to the standard heat of formation of sulfur trioxide (ΔHf°). Next, we can write the equation for the decomposition of sulfur dioxide into sulfur and oxygen:
2 SO2(g) → 2 S(s) + 2 O2(g) ΔH1
Note that this reaction is the reverse of the formation of sulfur dioxide from its constituent elements, so we need to reverse the sign of the enthalpy change (ΔH1) for that reaction. Finally, we can write the equation for the reaction we are interested in, which is the sum of the formation of sulfur trioxide and the decomposition of sulfur dioxide:
2 SO2(g) + O2(g) → 2 SO3(g) ΔH2
Using Hess's law, we can express the enthalpy change for the overall reaction (ΔH2) in terms of the enthalpy changes for the two component reactions:
ΔH2 = ΔHf° - ΔH1
Substituting the given values, we get:
ΔH2 = R kJ/mol - (-Q kJ/mol) = R + Q kJ/mol
Therefore, the enthalpy change for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is equal to the sum of the standard heats of formation of sulfur trioxide and sulfur dioxide, which is R + Q kJ/mol.
Learn more about enthalpy change from
https://brainly.com/question/27197408
#SPJ1
The balanced equation for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is:
2 SO2(g) + O2(g) → 2 SO3(g)
What would be the ΔH for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide?To determine the enthalpy change (ΔH) for this reaction, we can use Hess's law, which states that the overall enthalpy change for a reaction is equal to the sum of the enthalpy changes for a series of reactions that add up to the overall reaction. In other words, if we can find the enthalpy changes for a series of reactions that include the same reactants and products as the overall reaction, we can add them up to find the enthalpy change for the overall reaction.
To use Hess's law in this case, we can start with the given standard heats of formation and write the equation for the formation of sulfur trioxide from its constituent elements:
S(s) + 3/2 O2(g) → SO3(g) ΔHf° = R kJ/mol
Note that the enthalpy change for this reaction is equal to the standard heat of formation of sulfur trioxide (ΔHf°). Next, we can write the equation for the decomposition of sulfur dioxide into sulfur and oxygen:
2 SO2(g) → 2 S(s) + 2 O2(g) ΔH1
Note that this reaction is the reverse of the formation of sulfur dioxide from its constituent elements, so we need to reverse the sign of the enthalpy change (ΔH1) for that reaction. Finally, we can write the equation for the reaction we are interested in, which is the sum of the formation of sulfur trioxide and the decomposition of sulfur dioxide:
2 SO2(g) + O2(g) → 2 SO3(g) ΔH2
Using Hess's law, we can express the enthalpy change for the overall reaction (ΔH2) in terms of the enthalpy changes for the two component reactions:
ΔH2 = ΔHf° - ΔH1
Substituting the given values, we get:
ΔH2 = R kJ/mol - (-Q kJ/mol) = R + Q kJ/mol
Therefore, the enthalpy change for the reaction of two moles of sulfur dioxide with oxygen to produce two moles of sulfur trioxide is equal to the sum of the standard heats of formation of sulfur trioxide and sulfur dioxide, which is R + Q kJ/mol.
Learn more about enthalpy change from
brainly.com/question/27197408
#SPJ1
A climatologist studies the effect of the COVID-19 pandemic on the CO2 levels in the atmosphere over industrial regions. In a random sample of 6 regions in the pre-pandemic period, the observed levels amounted to (in ppm ): 630,606,598,555,543,518, while in a random sample of 5 regions in the pandemic period, the observed levels amounted to (in ppm): 677,656,630,621,606. We assume that CO2 levels follow a normal distribution. - The climatologist wishes to verify whether the average levels of CO2 during the pre-pandemic and pandemic periods are equal, against the alternative that they are not, using a standard procedure of testing the equality of means, at a 1% significance level. The value of the appropriate test statistic amounts to p-value of this outcome is so at the adopted significance level we the null. Please provide numerical values approximated to two decimal digits and use ". " for decimal separator
Answers
The value of the appropriate test statistic is 2.11. The p-value of this outcome is 0.04. At a 1% significance level, we reject the null hypothesis.
How to find p-value?# Pre-pandemic period
mean = 590.83
std = 36.17
# Pandemic period
mean = 642.20
std = 25.03
# Pooled variance
variance = (6 × 36.17² + 5 × 25.03²) / (6 + 5) = 328.08
# Standard error
std_err = √(variance / (6 + 5)) = 18.12
# Test statistic
t = (mean_pre - mean_pandemic) / std_err = 2.11
# p-value
p = 1 - t.cdf(2.11, df=10) = 0.04
The p-value is the probability of obtaining a test statistic at least as extreme as the one observed, assuming that the null hypothesis is true. In this case, the p-value is 0.04, which is less than the significance level of 1%. This means that we can reject the null hypothesis with 99% confidence and conclude that the average CO₂ levels in the pre-pandemic and pandemic periods are not equal.
Find out more on COVID-19 pandemic here: https://brainly.com/question/29643338
#SPJ1
PLEAS HELP
Help………..
Answers
Because data will always be needed when making a hypothesis that leads into a theory,
Secondly, a teenager is a group of multiple people who which can be tested and that is why it’s a scientific theory
Answer:
Question 1: B. A set of hypotheses accepted as an undeniable fact.
Question 2: C. Will fish living in freshwater be happier than those living in sa.lt.water.
Explanation:
A scientific theory is a rule of nature that can never be changed.
A hypothesis is a supposition or a proposed idea that can be tested.
What is the future of Nanoparticles in medicine
Answers
Answer:
nanoparticle cancer drugs could act like biological missiles that destroy tumors while minimizing damage to healthy organs
are Li, Na and K in the same group
Answers
Answer: Yes, they are.
Explanation:
Yes, they are. Li, Na, and K are referring to Lithium, sodium, and potassium.
They are all belonging to the same group which is called the alkali metals group.
They are having the same number of valence electrons i.e. 1.
This group of the alkali metals are considering tree more metals in it which are Rb, Cs, and Fr.
Which type of reaction is NaCl + AgNO3 → NaNO3 + AgCl? synthesis decomposition oxidation replacement
Answers
Hope this helps! :)
The type of reaction represented by the equation is replacement reaction.
Definition of replacement reactionA replacement reaction also known as displacement reaction is a reaction in which the ions of the reactant exchange to produce a new product. For example
AB + CD —> AD + CB
In the above reaction, we can see that D replaces B in the product which shows that the reaction is a replacement reaction.
How to determine the type of reactionNaCl + AgNO₃ → NaNO₃ + AgCl
In the above reaction, we can see that Cl replaces NO₃ in the product. This simply indicates that the reaction is a replacement reaction.
Learn more about chemical reactions:
https://brainly.com/question/8625202
100G. Gomori methenamine silver
Preferred fixative:
Preferred thickness:
Control tissue:
Major reagents:
Purpose of stain:
Results:
Answers
Preferred fixative: Neutral buffered formalin
Preferred thickness: 4-5 micrometers
Control tissue: Kidney tissue
Major reagents: Methenamine silver solution, ammoniacal silver nitrate solution, sodium borohydride
Purpose of stain: Gomori methenamine silver (GMS) stain is a histological staining method used to identify fungal organisms and other microorganisms in tissue sections. It stains the fungal cell walls and some types of microorganisms black or dark brown against a light background, allowing for their visualization under a microscope.
Results: The fungal or microorganism cell walls appear black or dark brown, while the background appears light. The stain may also reveal other tissue components such as collagen fibers and basement membranes.
learn more about Methenamine here :
https://brainly.com/question/4499791
#SPJ11
The decomposition of HI(g) is represented by the equation
2HI(g) = H2(g) + I2(g)
The following experiment was devised to determine the equilibrium constant of the reaction.
HI (g) is introduced into five identical 400-cm3 glass bulbs, and the five bulbs are maintained at 623 K. The amount of I2 produced over time is measured by opening each bulb and titrating the contents with 0. 0150 M Na2S2O3 (aq). The reaction of I2 with the titrant is
I2 + 2Na2S2O3 = Na2S4O6 + 2NaI
Data for the experiment are provided in this table.
Bulb Initial mass of HI (g) Time(hours) Volume of titrant(mL)
1 0. 0300 2 20. 96
2 0. 0320 4 27. 90
3 0. 315 12 32. 31
4 0. 406 20 41. 50
5 0. 280 40 28. 68
What is the value of Kc for the decomposition of HI at 623 K?
Answers
The value of Kc for the decomposition of HI at 623 K is 0.0168 \(M^-^1\)
How do we calculate?\(I_2\) + \(2Na_2S_2O_3\) → \(Na_2S_4O_6\)+ 2NaI is the balanced equation:
moles of \(I_2\) = volume of titrant in mL)* (0.0150 mol/L) / 1000
for Bulb 1:
moles of \(I_2\) = (20.96 mL) * (0.0150 mol/L) / 1000
= 0.003144 mol
The concentration of \(I_2\) = moles of I2 / volume of the bulb (in L)
= 0.003144 mol / 0.400 L
= 0.00786 M
The concentration of HI = initial mass of HI / molar mass of HI / volume of the bulb (in L)
= 0.0300 g / 127.91 g/mol / 0.400 L
= 0.592 M
Kc = ([H2] * [\(I_2\)]) / ([HI]²)
Kc = [\(I_2\)] / ([HI]²)
Kc = (0.00786 M) / (0.592 M)²
Kc = 0.022 \(M^-^1\)
The Kc for each bulb
Bulb 2: Kc = 0.00834 M / (0.640 M)² = 0.020
Bulb 3: Kc = 0.00950 M / (0.788 M))² = 0.015
Bulb 4: Kc = 0.0122 M / (1.03 M))² = 0.011
Bulb 5: Kc = 0.00818 M / (0.710 M))² = 0.016
In conclusion, the average Kc
= (0.022 + 0.020 + 0.015 + 0.011 + 0.016) / 5
= 0.0168 \(M^-^1\)
Learn more about volume at:
https://brainly.com/question/27710307
#SPJ1
what is the empirical formula for the ionic compound composed of calcium ions and bromide ions?
Answers
The empirical formula for an ionic compound is typically written in the form of "AxBy," where "A" is the number of atoms of the "parent" element and "x" and "y" are the numbers of atoms of the "daughter" element.
The empirical formula for an ionic compound is a simplified formula that represents the simplest ratio of the number of atoms of each element in the compound. To determine the empirical formula for an ionic compound composed of calcium ions (Ca) and bromide ions (Br), you would need to know the molar mass of each ion and the ratio of the number of moles of calcium ions to the number of moles of bromide ions in the compound.
The molar mass of calcium (Ca) is 40.08 g/mol, and the molar mass of bromide (Br) is 79.9 g/mol. Therefore, the molar mass of the compound is the sum of the molar masses of the ions:
Molar mass of compound = molar mass of Ca + molar mass of Br-
= 40.08 g/mol + 79.9 g/mol
= 119.98 g/mol
To determine the empirical formula, you would need to know the ratio of the number of moles of calcium ions to the number of moles of bromide ions in the compound. For example, if there are 2 moles of calcium ions and 1 mole of bromide ions in the compound, the empirical formula would be "Ca, Br".
Learn more about empirical formula visit: brainly.com/question/1439914
#SPJ4
separate this redox reaction into its balanced component half‑reactions. use the symbol e− for an electron. cl2 2cu⟶2cucl cl2 2cu⟶2cucl
Answers
The balanced redox reaction can be separated into two half-reactions: the oxidation half-reaction and the reduction half-reaction. Oxidation half-reaction: 2Cl^- → Cl2 + 2e^-, Reduction half-reaction: Cl2 + 2e^- → 2CuCl
In the oxidation half-reaction, chloride ions (Cl^-) are oxidized to form chlorine gas (Cl2) and release two electrons (2e^-). This represents the loss of electrons, which is characteristic of an oxidation process. In the reduction half-reaction, chlorine gas (Cl2) gains two electrons (2e^-) to form copper chloride (CuCl). This represents the gain of electrons, which is typical of a reduction process. When combined, the two half-reactions form the overall balanced redox reaction: 2Cl^- + Cl2 → 2CuCl.
To know more about half-reactions : brainly.com/question/18403544
#SPJ11
Which is a characteristic of aromatic hydrocarbons?
O A. They have single and double bonds.
B. They have only double bonds.
C. They have single and triple bonds.
D. They have triple and double bonds.
Answers
A characteristic of aromatic hydrocarbons is : ( A ) They have single and double bonds
What are Aromatic hydrocarbons ?Aromatic hydrocarbons are a class of unsaturated hydrocarbons which are based of 6 carbon ring moiety. They are gotten during the extraction of fossil fuels and can be used as solvents for the production of industrial products as well as consumer products. They contain single and double bonds of carbon atoms.
Hence we can conclude that They have single and double bonds
Learn more about aromatic hydrocarbons : https://brainly.com/question/22599756
#SPJ1
For full credit you must show charges, atom-to-atom ratio, and a balance chemical reaction
1. 5.00g of silver reacts with nitrogen. Predict the product and calculate the amount produced.
2. 5.00 silver carbonate decomposes. Predict the products and calculate the amount of each product produced. (will have to do 2 separate calculations)
Answers
The mass of the silver nitride that is produced in the process is 5.1 g
What are the products of a reaction?Stoichiometry involves balancing chemical equations and using mole ratios to determine the amounts of reactants and products involved in a reaction. By determining the number of moles of each reactant and product, stoichiometry allows us to calculate the mass or volume of each substance involved in the reaction.
We have the reaction equation as;
6Ag + N2 → 2Ag3N
Number of moles of Ag = 5g/108 g/mol
= 0.046 moles
If 6 moles of Ag produced 2 moles of silver nitride
0.046 moles of Ag will produce 0.046 * 2/6
= 0.015 moles
Mass of silver nitride = 0.015 moles * 338 g/mol
= 5.1 g of silver nitride
Learn more about stoichiometry:https://brainly.com/question/30215297
#SPJ1
Conduction can only occur between two objects when – both objects are exactly the same temperature. Both objects are exactly the same temperature. One of the objects is made of a metal. One of the objects is made of a metal. Both objects are in physical contact with each other. Both objects are in physical contact with each other. One object is less dense than the other. One object is less dense than the other.
Answers
Answer:
Both objects are in physical contact with each other
Explanation:
Conduction refers to the flow of heat from one object to another when the both objects are in contact with each other.
Hence, before heat can flow from one object to another, the two objects must be in contact with each other. This is a key requirement before conduction can take place.
what evidence have you discovered to explain how the structure of compounds determens the properties of the compounds
Answers
All of the properties such as ice floating on water, while most solids would sink when placed in its liquid are all due to the structure of the compounds.
The structure of the compounds includes the bonding angle, the type of bonds, the size of the molecule, the interactions between the molecules etc. Slight changes in the chemical structure and affect the properties if the compound.
Isomeric compounds with the same chemical formula but different structures can have different melting and boiling point and differ in reactivity and flammability.
Another common change in isomers are with the double bonds. A double bond can be in the cis formation or in the trans formation, and this will affect its properties as trans isomers will be having high melting point than the cis isomer.
Thus, structure of compounds do determine the properties of the compounds.
To know more about the structure and properties of compounds
https://brainly.com/question/4661963
#SPJ1
(b) Why is nitrogen used for storage of semen
in artificial insemination?
Answers
Which equation is balanced?
A) A
B) B
C) C
D) D
Answers
The balanced equation among them is ;
\(A. \: \: N_23H_3 + H_2 \longrightarrow2NH_4\)
Answer:
\(N _{2}{3H} _{2} + H_{2} = > 2NH _{2}\)
is ur answer
Explanation:
equation for balanced is
\(N _{2}{3H} _{2} + H_{2} = > 2NH _{2}\)
PLEASE I NEED HELP I WILL GIVE YOU BRAINLIST
Answers
Answer:
First Q :B
Second Q:C
Enter the cycle number, n, in the x column and the
number of radioactive atoms in the y column.
When you finish, resize the window.
DONE
Answers
7. The structural formula below is incomplete. It shows all of the carbon-hydrogen bonds, but none of the carbon-carbon bonds. Draw the MISSING BONDS BETWEEN THE CARBON ATOMS ONLY! (Do not add any other atoms to the structural formula below.) What is the name of the structural formula?
Answers
Step-by-step explanation:
The number of carbon atoms present in the structure is 5
Each carbon atom carry four hydrogen atoms
The above organic structure is Pentane
Having a molecular formula of C5H12
what is the mass of 2.50 mol of (C3H5)2S
Answers
Hey there!
We need to start this by finding the molar mass of (C₃H₅)₂S.
This molecule consists of 6 carbon atoms, 10 hydrogen atoms, and one sulfur atom. We need to add the molar masses of each atom up.
C: 6 x 12.01 = 72.06
H: 10 x 1.008 = 10.08
S: 1 x 32.07 = 32.07
-------------------------------
114.21 g/mol
Ok, now that we have established that the molar mass of (C₃H₅)₂S is 114.21 g/mol, we have 2.50 mol of (C₃H₅)₂S. If 1 mol has a mass of 114.21 g, then 2.50 mol will have a mass of 2.50 time 114.21.
2.50 x 114.21 = 285.525 grams
This should go to just three significant figures, so:
The mass of 2.50 mol of (C₃H₅)₂S is 286 grams.
Hope this helps!
at what point was the sodium bicarbonate in beaker "b" neutralized? in other words, how much acid had to be added to bring the acidic solution to a neutral ph?
Answers
The amount of acid needed to neutralize the sodium bicarbonate solution in beaker "b" can vary depending on the concentration of the bicarbonate solution and the acid being used.
The neutralization point can be determined by monitoring the pH of the solution as acid is added and determining when the pH reaches 7, which is considered neutral. The exact amount of acid needed can be calculated using the balanced chemical equation for the reaction between the acid and sodium bicarbonate.
When a sodium bicarbonate solution is neutralized with an acid, the following reaction takes place:
HCl + NaHCO3 -> NaCl + H2O + CO2
where HCl is the acid, NaHCO3 is the sodium bicarbonate, NaCl is the salt formed, H2O is water, and CO2 is carbon dioxide.
To determine how much acid is required to neutralize the sodium bicarbonate solution, the initial molarity of the bicarbonate solution and the acid must be known. This information, along with the balanced chemical equation, can be used to calculate the amount of acid required to neutralize the solution.
Learn more about acid here:
https://brainly.com/question/29796621
#SPJ4
Why are anions larger than neutral atoms of the same element?
Answers
Answer:
In general, anions are larger than the corresponding neutral atom, since adding electrons increases the number of electron-electron repulsion interactions that take place.
Explanation:
I hope it's helpful for you(e) The table shows some information about an investigation on the decomposition of H2O2(aq) using two different catalysts. In each experiment, 0.100g of the catalyst and
25.0 cm3 of H2O2(aq) were used. The concentration and temperature of the H2O2(aq) Use were kept constant.
manganese(IV) oxide 25 95
peroxidase 10
For Examiner’s
catalyst
time taken to collect 50 cm3 of oxygen / s
total volume of oxygen made at the end of the reaction / cm3
© UCLES 2010
5070/21/M/J/10
(i)
(ii)
What is the total volume of oxygen made at the end of the reaction in which peroxidase was used as a catalyst?
volume of oxygen = ............................. cm3
Answers
The volume of oxygen made at the end of the reaction in which peroxidase was used as a catalyst is 10 cm3.
Given : The table shows some information about an investigation on the decomposition of H2O2(aq) using two different catalysts. In each experiment, 0.100g of the catalyst and 25.0 cm3 of H2O2(aq) were used. The concentration and temperature of the H2O2(aq) Use were kept constant.
Manganese(IV) oxide 25 95 Peroxidase 10.
For Examiner’s catalystTime taken to collect 50 cm3 of oxygen / sTotal volume of oxygen made at the end of the reaction / cm3(i)What is the total volume of oxygen made at the end of the reaction in which peroxidase was used as a catalyst.
So, we need to determine the total volume of oxygen made at the end of the reaction in which peroxidase was used as a catalyst.Volume of oxygen made at the end of the reaction in which peroxidase was used as a catalyst = 10 cm3.
for more questions on peroxidase :
https://brainly.com/question/30087947
#SPJ11
can there be 4 electrons in the first energy level
Answers
What conclusions can you make about the relationship between the volume of a gas and its pressure?
Answers
Answer:
\(V \alpha \frac{1}{P}\)
Explanation:
According to Boyle's law, the volume of a given mass of gas is inversely proportional to its pressure at constant temperature.
This implies that, if the volume of a gas is halved, its pressure is doubled and vice versa.
This is mathematically represented as; \(V \alpha \frac{1}{P}\) hence \(PV = K\). This is the mathematical statement of Boyle's law.
PLEASE HELP I ACTUALLY WANT TO LEARN THIS PROBLEM!!! 125 g Fe₂O3 reacts according to the equation below. Calculate the % yield if
87,000 milligrams of iron are formed?
Fe₂O3 +
C →
125g Fez03x
Fe +
CO
Answers
To calculate the % yield, you need to determine the actual yield of the reaction and compare it to the theoretical yield. The actual yield is the amount of product that is actually produced during the reaction, while the theoretical yield is the maximum amount of product that could be produced based on the amounts of reactants used.
In this case, the theoretical yield is 87,000 milligrams of iron, since this is the amount of product that was actually produced. The % yield is calculated by dividing the actual yield by the theoretical yield and multiplying by 100%.
Since the actual yield and the theoretical yield are the same in this case, the % yield is 100%. This means that the reaction had a perfect yield, with all of the reactants being converted into product.
A sample of kerosene has a mass of 36.4g. It’s volume is 45.6mL. What is the density of kerosene?
Answers
Answer:
Density = 0.8 g/cm³Explanation:
The density of an object can be found using the formula
\(Density(\rho) = \frac{mass}{volume} \)From the question
mass of kerosene = 36.4 g
volume of kerosene = 45.6 mL
To find the density substitute the values into the above formula and solve
We have
\(Density = \frac{36.4}{45.6} \)= 0.7982
We have the final answer as
Density = 0.8 g/cm³Hope this helps you