determine the volume in ml of a 0.505 m naoh solution required to titrate 40 ml of 0.25 mh2 so4 solution

The pH of 250ml of 2. 1 M HBr with 200 mL of 2. 5 M KOH is 1.6. Therefore the correct option is option B.

First, we need to determine the limiting reagent to calculate the moles of each reactant that will react.

2.1 M HBr x 0.25 L = 0.525 moles HBr

2.5 M KOH x 0.2 L = 0.5 moles KOH

Since KOH is the limiting reagent (it has fewer moles than HBr), all of the KOH will react with the HBr. The balanced chemical equation for the reaction is:

HBr + KOH → KBr + H2O

The moles of HBr that react is also 0.5 moles. The moles of KBr formed is also 0.5 moles.

To determine the pH of the resulting solution, we need to calculate the concentration of the final solution, which will be the sum of the moles of HBr and KOH (since they react completely) divided by the total volume of the resulting solution:

moles HBr + moles KOH = 0.525 + 0.5 = 1.025 moles

volume of resulting solution = 0.25 L + 0.2 L = 0.45 L

concentration = 1.025 moles / 0.45 L = 2.28 M

To find the pH, we can use the equation:

pH = -log[H+]

Since HBr is a strong acid, it dissociates completely in water to form H+ and Br-. Therefore, the concentration of H+ in the solution will be equal to the concentration of HBr.

[H+] = 2.28 M

pH = -log(2.28) = 0.64

Therefore, the pH of the resulting solution is 0.64. The 1.6 (rounded to one decimal place).

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Answer:

Calcium carbonate is another example of a compound with both ionic and covalent bonds. Here calcium acts as the cation, with the carbonate species as the anion. These species share an ionic bond, while the carbon and oxygen atoms in carbonate are covalently bonded.

It is necessary to determine the wavelength of maximum absorbance (aka λmax) of the copper sulfate solution before the absorbance of the five standard solutions because this helps in getting the molar concentration of the unknown solution.

In the absorbance vs wavelength graph for a  solution of copper sulfate notice that solutions absorb strongly from approximately 600 to 800 nm, with the maximum absorbance is around 750 nm. Thus in an experiment, we would choose a wavelength within that range. There is an vital distinction between the color of the light we observed reflected and the color the light absorbed.  A wavelength of 750 nm indicates to red light, while a solution of copper sulfate appears to be blue. Copper sulfate solution reflects or transmits blue light, but absorbs red light.

Higher absorbance of the wavelength provides higher sensitivity observes at a wavelength of maximum absorbance (aka λmax) that helps to get the molar concentration of the unknown solution.

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Answer:

6=100  

Explanation:

Answer:

D. The change in velocity divided by the time during which the change occurs.

Explanation: I took the quiz on Accelerate and it was correct

Answer:

D. The change in velocity divided by the time during which the change occurs.

Explanation:

Answer:

scientific law is the answer of these questions

If 13 % of the carbon-14 in a sample of cotton cloth remains, what's the approximate age of the cloth?

To solve a half-life problem we usually use this formula:

amount remaining = initial amount (1/2)^n

Where n is the number of half-lives. We can replace n for T/Thalf:

amount remaining = initial amount (1/2)^(T/Thalf)

Where t is the age or time elapsed and Thalf is the half-life or our isotope. The half life of C-14 is 5730 years. Then:

Thalf = 5730 years

Let's supose that the cotton cloth originally had 100 g of C-14. If 13 % remains, the amount remaining is 13 g. So:

amount remaining = 13 g initial amount 100 g

Rearranging the formula we get:

amount remaining = initial amount (1/2)^(T/Thalf)

amount remaining/initial amount = (1/2)^(T/Thalf)

ln (amount remaining/initial amount) = ln [(1/2)^(T/Thalf)]

ln (amount remaining/initial amount) = (T/Thalf) *ln (1/2)

T = Thalf * ln (amount remaining/initial amount) /ln (1/2)

Now we can replace the given values:

T = 5730 years * ln(13 g/100g) / ln(1/2)

T = 5730 years * ln(0.13)/ln(0.5)

T = 5730 years * 2.94

T = 16825 years

Answer: the approximate age of the cloth is 16825 years.

In the given molecules, the carbon-oxygen bond is predicted to be the longest in (B) H3COCH3 (dimethyl ether). among the given molecules or ions, (C) IF4- does not exhibit a tetrahedral molecular geometry.

The carbon-oxygen bond is predicted to be the longest in (B) H3COCH3 (dimethyl ether). This is because the carbon-oxygen bond in H3COCH3 is a single bond, which is longer compared to the double bond in CO2 (A) and H2CO (D), and the triple bond in CO (C). In (E) (CH3)2CO (acetone), the carbon-oxygen bond is also a double bond, so it is not the longest.

Regarding tetrahedral molecular geometry, among the given molecules or ions, (C) IF4- does not exhibit a tetrahedral molecular geometry. Instead, it has a square planar molecular geometry. The other molecules or ions (A) CH4, (B) NH4+, (D) SiCl4, and (E) BF4- exhibit tetrahedral molecular geometry.

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1. It takes a lot of energy to break all of the bonds because the ions in this big structure are tightly bound. It has a high melting point because of this.

2. Its ions are unrestricted in the molten state. Therefore, electricity can flow through molten magnesium oxide.

In order for electrolysis to take place, ionic compounds must be molten or in solution. The reason for this is that the ions—the charged particles that make them up—need to be able to freely move to the electrodes.

Some furnace linings are made from magnesium oxide. It is known as a refractory material, which simply means that it has a high thermal conductivity.

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4.20325g of oxygen was used.

The reaction described is represented chemically by the equation 4NH3 + 5O2 = 4NO + 6H2O.

Ammonia produced by industry is used as fertilizer in agriculture to the tune of 80%. In addition to these uses, ammonia is made into polymers, explosives, textiles, insecticides, dyes, and other chemicals. It is also used to purify water sources.

As a result, 4 moles of NH3 and 5 moles of O2 react.

The molar mass of 1 mole of oxygen is 2 * 16 = 32g.

5 moles of oxygen are equal to 5 * 32, or 160g.

68g is equal to 4 (14 + 3*1) moles of NH3.

68g of NH3 reacts with 160g of O2 as a result.

However, we only have 9.89 g of oxygen.

68g and 160g interact.

9.89 and Xg react to form 4.20325g (Xg = 68*9.89/160).

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Answer:

61,000

Explanation:

Answer:

36 protons

Explanation:

Because atomic number Z is equal number of protons while mass  number is protons plus neutrons

Answer:

En la mejora de la investigación y la medicina.

Explicación:

La aparición del microscopio ha permitido la creación de nuevas áreas de estudio, tanto en la mejora de la investigación como en la medicina. La invención del microscopio nos permite crecer y desarrollarnos en el campo de la investigación y el estudio. Con este microscopio, los científicos pudieron descubrir la estructura de la célula, así como las partículas subatómicas que están presentes dentro del átomo. Gracias a este microscopio, los científicos pudieron crecer y desarrollarse en el campo de la creación de nuevos medicamentos.

Answer:

I guess 1-mole carbon dioxide contains 6.02 x 10^23 molecules.

Answer:

C

Explanation:

looking at a periodic table X is fluorine and Y is potassium

Fluorine is in group 7 and forms a 1- charge (which gains electrons) and potassium is in group 1 and forms a 1+ charge (which loses electrons)

Fluorine (X) has an electronic structure of 2,7 and needs to gain an electron from Potassium (Y) to have a full outer shell and potassium has an electronic structure of 2,8,8,1 so needs to lose an electron to have a full outer shell as well. This means that the electron that potassium (Y) has lost is given away to fluorine (X), so both elements become stable.

This is known as ionic bonding where metals (like potassium) lose electrons and non-metals (like fluorine) gain electrons to become more stable, forming ions

Any further clarification let me know

Anionic polymerization of acrylonitrile involves the initiation by a free-radical initiator, followed by propagation through the attack of an anion on the acrylonitrile monomer's double bond. The process continues with the repetitive addition of monomer units to the growing polymer chain.

Anionic polymerization of acrylonitrile typically proceeds through a free-radical initiator, which generates an anion that initiates the polymerization. Here's a step-by-step description:

Initiation: A free-radical initiator, such as a peroxide, generates a reactive anion (e.g., a radical anion) that initiates the polymerization.

Propagation: The anion attacks the double bond of an acrylonitrile monomer, forming a new carbon-carbon bond and creating a new reactive anion. This step repeats, resulting in the addition of multiple monomer units to the growing polymer chain.

Termination: Polymerization terminates when two reactive anions or a reactive anion and a polymer chain end interact, leading to the formation of a covalent bond and stopping further chain growth. Throughout the process, it is essential to consider the charges and the movement of electrons, represented by curved arrows, which facilitate the formation of new bonds and chain elongation.

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Answer:

18.88 grams of Al2O3

Explanation:

Here's my work

10g Al    l    1 mol Al    l    1 mol Al2O3  l   102g Al2O3

             l    27g Al       l   2 mol Al         l    1 mol Al2O3

Balanced equation: 2Al +Fe2O3  --> Al2O3 + 2Fe

So pretend it's in a chart,  you fill it out starting from the top left corner and then moving diagonally down and then straight up and then diagonally down and the straight up, etc.  You start with 10 grams of Al, so the first thing you want to do is convert it into moles.   So you find the mass of Al(which is 27) and then you have 1 mol of Al on top.  So the next thing you have to do is to change it to Al2O3 since that is what the question is asking for.  This is where it's important you balanced the equation correctly because you're going to compare the mol ratios.  To do this, you have to look at the coefficients in front of Al, which is a 2.  so you write 2 mol Al on the second bottom section.  and then on top you look at the balanced equation again and look at the coefficient in front of Al2O3, which there is none so it's a 1.   Then all you have to do is convert back to grams because the question wants it in grams.  so you put 1 mol on the bottom and then you look at your periodic table to figure out the mass of Al2O3.    Al= 27,  O= 16.   (27x 2) +  (16 x 3)  = 102.     Finally you just multiply all the numbers on the top row and then multiple all the numbers on the bottom row and then divide what you get on the top by the bottom.  

The density of the Helium atom is 9.5 * 10^35 g/cm^2.

Density is a measure of mass per unit of volume of a substance or object. It is calculated as the ratio of the mass of an object to its volume and is usually expressed in kilograms per cubic meter (kg/m^3) or grams per cubic centimeter (g/cm^3).

We know that the mass of the atom of the helium is 4 g and the density of the atom is  0.10 nm or 1 * 10^-12 cm.

Volume of the atom = 4/3 πr^3

= 4.2 * 10^-36 cm^3

Then we must write that;

Density = mass/volume

Density = 4 g /4.2 * 10^-36 cm^3

Density = 9.5 * 10^35 g/cm^2

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Answer:

GROUP 2

Explanation:

u asked this already

i just dont understand...

The enamine product formed by the reaction between cyclohexanone and pyrrolidine can be represented by the following structural formula: Enamines are a class of organic compounds that are formed by the reaction of a primary amine and a carbonyl compound.

The amine group in the primary amine reacts with the carbonyl group in the carbonyl compound to form a double bond (C=N). This double bond is referred to as an imine bond. The enamine formed can be considered as a resonance hybrid of the two isomeric structures. The enamine product formed in the reaction between cyclohexanone and pyrrolidine has a five-membered ring (pyrrolidine) and a six-membered ring (cyclohexanone). The nitrogen atom in the pyrrolidine ring is attached to the carbonyl carbon atom of the cyclohexanone ring. The resulting enamine has a double bond (C=N) between the carbon atom of the cyclohexanone ring and the nitrogen atom of the pyrrolidine ring.

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The number of moles of magnesium, chlorine, and oxygen atoms in 2.70 moles of magnesium perchlorate is 2.70, 5.40, 21.60.

The formula of the compound is Mg(ClO​​​​4)2.

From the formula, we can see that 1 molecule of Mg(ClO4)2 contains 1 atom of Mg, 2 atoms of Cl and 8 atoms of O.

So 2.70 mol Mg(ClO4)2  contains

1 * 2.70 mol Mg = 2.70 mol Mg

2 * 2.70 mol Cl = 5.40 mol Cl

8 * 2.70 mol O = 21.60 mol O

So, the required answer is 2.70, 5.40, 21.60.

Therefore, the number of moles of magnesium, chlorine, and oxygen atoms in 2.70 moles of magnesium perchlorate is 2.70, 5.40, 21.60.

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Answer:

precipitation occur

Explanation:

the solute do not dissolve in water

The percent yield of compound C is 46%.

To calculate the theoretical yield of compound C, we first need to determine the limiting reagent between A and B. We can do this by calculating the number of moles of each compound, using their respective molar masses;

moles of A = 2.5 g / molar mass of A

moles of B = 6.5 g / molar mass of B

Next, we need to compare the mole ratio of A and B in the balanced chemical equation to the actual mole ratio in the reaction mixture. Whichever reactant has a lower mole ratio is the limiting reagent. Let's assume that the balanced chemical equation is;

2 A + 3 B → 4 C

From this equation, we can see that the mole ratio of A to B is 2:3. Let's assume that the actual mole ratio of A to B in the reaction mixture is 1:2. This means that B is the limiting reagent.

To calculate the theoretical yield of C, we can use stoichiometry to convert the mass of B to the mass of C, using the mole ratio from the balanced chemical equation

moles of B = 6.5 g / molar mass of B

moles of C = (4 moles of C / 3 moles of B) x moles of B

mass of C = moles of C x molar mass of C

Substituting the values and rounding to the nearest 0.1 g, we get;

moles of B = 6.5 g / molar mass of B = 6.5 g / 80.0 g/mol = 0.0813 mol

moles of C = (4/3) x 0.0813 mol = 0.1084 mol

mass of C = 0.1084 mol x 120.0 g/mol = 13.0 g

Therefore, the theoretical yield of compound C is 13.0 g.

To calculate the percent yield of compound C, we can use the formula;

percent yield = (actual yield/theoretical yield) x 100%

Substituting the values and rounding to the nearest whole percent, we get;

percent yield = (6.0 g / 13.0 g) x 100% = 46%

Therefore, the percent yield of compound C is 46%. This means that only 46% of the maximum amount of product that could have been obtained from the limiting reagent was actually obtained in the experiment.

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--The given question is incomplete, the complete question is

"Suppose 2.5g of compound A and 6.5g of compound B are consumed in a reaction that produces only one product, compound C. calculate the theoretical yield of C. Round your answer to the nearest O.1g. suppose 6.0g of C are actually isolated at the end of the reaction. what is the percent yield of compound C? round your answer to the nearest whole percent."--

Explanation:

In chemistry, a salt is a chemical compound consisting of an ionic assembly of cations and anions.[1] Salts are composed of related numbers of cations (positively charged ions) and anions (negatively charged ions) so that the product is electrically neutral (without a net charge). These component ions can be inorganic, such as chloride (Cl−), or organic, such as acetate (CH

3CO−

2); and can be monatomic, such as fluoride (F−) or polyatomic, such as sulfate (SO2−

4).

Answer:

University of University of South New York Jersey has is a the best in the world the most important most important aspect of aspect of life is life and marriage is in my a lot more of a urban

Answer:

Density = 0.27 decagrams/cm³

Explanation:

From conversion tables, we know that;

1 g/cm³ = 0.1 decagrams/cm³

We are given;

Density of aluminium = 2.7 g/cm³

Thus;

Density = 2.7 * 0.1

Density = 0.27 decagrams/cm³

Answer:

270000 decagrams/m³

Explanation:

1.

Density=mass/Volume

=2.7g/1cm3

=(2.7/1000)/(1/1000000)

=2.7x1000

Density=2700kg/ m3

= 270000 decagrams/m³

2.

1000g=1kg

1g=1/1000kg

1cm3= ? m3

100cm=1m

1cm=1/100 m

1cm3=1/1000000 m3

When a nitrile is treated with an excess of LiAlH4 followed by water, the obtained product is a primary amine.

1. Nitrile (RC≡N) reacts with excess LiAlH4 (lithium aluminum hydride), which is a strong reducing agent.
2. The LiAlH4 reduces the nitrile to an imine (RCH=NH) intermediate.
3. The imine intermediate is further reduced by the excess LiAlH4 to form an aldimine (RCH2-NH2).
4. Finally, water (H2O) is added to the reaction to hydrolyze any remaining LiAlH4, and the primary amine (RCH2-NH2) is obtained as the final product.

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