Determine if the Sequence is Arithmetic. 1,3,9,27,81,...

A) Arithmetic

B) Not Arithmetic

Answers

Answer 1

Answer:

Arithmetic

Step-by-step explanation:

Each number is multiplied by three

Answer 2

Answer:

No, this isn't an Arithmetic Sequence

Step-by-step explanation:

An Arithmetic Sequence should have a constant. There are several differences in the Sequence, but no constant difference.

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Related Questions

Write the equation of the line fully simplified slope-intercept form.

Write the equation of the line fully simplified slope-intercept form.

Answers

Answer:

y = -3x + 7

Step-by-step explanation:

I see points (0, 7) and (1, 4).

slope = m = (4 - 7)/(1 - 0) = -3

y-intercept = 7

y = mx + b

y = -3x + 7

In a certain city, projections for the next year indicate there is a 20% chance that electronics jobs will increase by 1200, a 50% chance that they will increase by 300 and a 30% chance they will decrease by 700. Find the expected change in the number of electronics jobs in that city in the year.

Answers

We have the next information

\(\begin{gathered} X=1200\rightarrow P(X)=0.2 \\ X=300\rightarrow P(X)=0.5 \\ X=-700\rightarrow P(X)=0.3 \end{gathered}\)

So, the the expected change is

\(\begin{gathered} 1200(0.2)+300(0.5)-700(0.3) \\ =240+150-210=180 \end{gathered}\)

Finally, the expected change in the number of electronics jobs in that city in the year is 180

14 hours 40 minutes ÷ 5?​

Answers

Answer:

112 seconds

Step-by-step explanation:

According to my calculations girl here to tell you how.

40*14=560

560/5=112

if 14 is hours and 40 is minutes, multiplying and dividing by five gives you

*DRAMATIC MUSIC*

112 seconds

Answer:

176 minutes

Step-by-step explanation:

14 hours equals 840minutes + 40 minutes = 880 minutes

880/5=176

Question 2 Part a
Let's revisit Kinko's problem familiar to us from previous assignments. Kinko spends all his money on whips and leather jackets. Now, Kinko's utility function is U(x, y) = min{x^1/2+y^1/2,x/4+y), where x is his consumption of whips and y is his consumption of leather jackets. Kinko is consuming 4 whips and 16 leather jackets. The price of whips is $6. Find Kinko's income. Make sure to draw Kinko's indifference curves and budget line to show your answer.
Question 2 Part b
Now, imagine that the price of leather jackets increases by 16 times. What will Kinko's optimal consumption be now?

Answers

Part a: Kinko's income is $280.

Part b: Kinko's optimal consumption will change due to the increased price of leather jackets, but the specific values cannot be determined without further calculations.

To find Kinko's income, we need to determine his budget line based on his current consumption and the price of whips. Kinko is consuming 4 whips and 16 leather jackets, and the price of whips is $6.

The budget line equation is given by: Px * x + Py * y = I, where Px is the price of whips, Py is the price of leather jackets, x is the consumption of whips, y is the consumption of leather jackets, and I is the income.

Since Kinko spends all his money on whips and leather jackets, his income equals the total expenditure on these goods. Thus, the budget line equation becomes: 6x + 16y = I.

We can substitute Kinko's consumption values into the equation: 6 * 4 + 16 * 16 = I.

Simplifying, we have: 24 + 256 = I.

Therefore, Kinko's income is $280.

To visualize this, we can plot Kinko's indifference curves and the budget line on a graph with whips (x) on the horizontal axis and leather jackets (y) on the vertical axis.

The budget line represents all the affordable combinations of whips and leather jackets given Kinko's income and the prices. The indifference curves represent Kinko's preferences, showing the combinations of whips and leather jackets that provide him with the same level of utility.

Part b:

If the price of leather jackets increases by 16 times, the new price of leather jackets becomes $16 * Py = $16 * 1 = $16.

To determine Kinko's optimal consumption, we need to find the new tangency point between an indifference curve and the new budget line. Since Kinko's utility function is non-standard, we need to use calculus to find the optimal consumption bundle.

Using the Lagrange multiplier method, we set up the following optimization problem:

Maximize U(x, y) = min{x½ + y½, x/4 + y}

Subject to the constraint: Px * x + Py * y = I, where Px = $6 and Py = $16.

By solving the optimization problem, we can find the new optimal consumption bundle in terms of whips (x) and leather jackets (y).

However, without the specific values for x and y, it is not possible to provide the exact optimal consumption bundle in one line.

The solution would involve finding the tangency point between the new budget line (with the increased price of leather jackets) and the indifference curves, and determining the corresponding values of x and y.

Therefore, without further information, we can only state that Kinko's optimal consumption will change due to the change in the price of leather jackets, but we cannot provide the specific values without additional calculations.

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IM.MP3.PC.2020-2021 Question: 1-10

IM.MP3.PC.2020-2021 Question: 1-10

Answers

Answer:

All of the Questions are the Same btw its -5/3

Step-by-step explanation:

James works in a flower shop. He will put 60 tulips in vases for a wedding. He must use the same number of tulips in each vase. The number of tulips in each vase must be greater than 1 and less than 10. How many tulips could be in each vase?

Answers

Answer:

• if he has 30  vases, he would be able to put two tulips in each

• if he has 20 vases, he would be able to put three tulips in each  

• if he has 15 vases, he would be able to put four tulips in each

if he has 12 vases, he would be able to put 5 tulips in each

if he has 10 vases, he would be able to put 6 tulips in each

Step-by-step explanation:

The number of tulips in each vase has to be multiples of 60

Multiples of 60 = 1 ,2, 3, 4, 5, 6, 10, 15, 20, 30 ,60

The question states that the number of flowers have to be greater than 1 and less than 10 so there can only be 2, 3, 4, 5, 6 in each verse

to estimate the true mean speed of vehicles traveling on a particular section of roadway, a speed-detection device is programmed to measure the speed of the first 100 vehicles that pass it. are the conditions for constructing a t confidence interval met? no, the random condition is not met. no, the 10% condition is not met. no, the normal/large sample condition is not met. yes, the conditions for inference are met.

Answers

It's difficult to say whether the conditions for constructing a t-confidence interval are met based on the information provided. To construct a t-confidence interval, three conditions must be met:

The sampling method must be random. It's not specified in the problem whether the method of selecting the vehicles was random or not, so it's impossible to say whether this condition is met.

The sample size must be large enough. A sample size of 100 vehicles is considered to be large enough for the normal/large sample condition to be met.

The population must be approximately normally distributed or the sample size must be large. Since the problem does not specify anything about the distribution of the population, it is not clear if this condition is met.

Given that the information provided does not give enough details to state whether the conditions for constructing a t-confidence interval are met or not.

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Please solve this and I will give u brainlst.
A pipe at an amusement park sprays water onto visitors. A cross section of each pipe has the shape of a parallelogram. Answer parts ​(a)​(c).

Please solve this and I will give u brainlst.A pipe at an amusement park sprays water onto visitors.
Please solve this and I will give u brainlst.A pipe at an amusement park sprays water onto visitors.

Answers

Answer:

a. The interior angles of Parallelogram B (Pipe B) are 30°, 150°, 150°, and 30°. Angle x measures 60° because the 120° angle and angle x are supplementary angles.

c. Correct answers, in order: 360, 360, 150, supplementary, 30, complementary, 60

Given square ABCD, which line segment could be an image of side AD using only a translation?

Given square ABCD, which line segment could be an image of side AD using only a translation?

Answers

Answer:

The second one

Step-by-step explanation:

Line segment BC will be an image of side AD using only a translation.

Option 2 is true.

What is Translation?

A transformation that occurs when a figure is moved from one location to another location without changing its size or shape is called translation.

Given that;

A figure ABCD is a square.

Now,

Since, ABCD is a square.

So, All sides of square ABCD are equal to each other.

Since, A translation occurs when a figure is moved from one location to another location without changing its size or shape.

Thus, Line segment BC will be an image of side AD using only a translation.

Therefore, Line segment BC will be an image of side AD using only a translation.

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{2x+5y=33.
3x-5y=-13

Answers

Answer:

x = 4, y =5

Step-by-step explanation:

2x+5y=33.

3x-5y=-13

Add the two equations together to eliminate y

2x+5y=33.

3x-5y=-13

-------------------

5x = 20

Divide by 5

5x/5 = 20/5

x = 4

Now find y

2x + 5y = 33

2(4) +5y = 33

8+5y = 33

Subtract 8 from each side

8+5y-8 = 33-8

5y = 25

Divide each side by 5

5y/5 = 25/5

y = 5

The total bill (parts and labor) for the repair of a car was $458. The cost of parts was $339. The cost of labor was $34 per hour. How many hours of labor did it take to fix the car?​

Answers

Answer:

3.5 Hours MARK ME AS BRAINLIEST PLEASE

Step-by-step explanation:

Take 458, and subtract 339 from it. Then, divide that by 34.

Answer:

3 and a half hours

Step-by-step explanation:

Subtract 399 from both sides

119 = 34h

Divide both sides by 34

3.5 = h

The ratio of wins to losses is 7 to
8. How many wins did the team
have if they had 48 losses?

Answers

Answer:

42 wins

Step-by-step explanation:

If there have been 48 losses, we know that there have been "6 sets" of 8 losses (48 / 8 = 6).

The ratio of 7 : 8 has occurred 6 times in this scenario.

This means that the total number of wins will also happen 6 times, because we have had 6 sets (the ratio for losses has occurred 6 times, meaning that the ratio for wins has also occurred 6 times)

So, to find the total number of wins, we can multiply 7 x 6 to find how many wins happened if we have created the 7 : 8 ratio 6 times

7 x 6 = 42

So, if we have had 48 losses, we have had 42 wins

In a circle with radius 4, an angle intercepts an arc of length 8pi. Find the angle inradians in simplest form.

In a circle with radius 4, an angle intercepts an arc of length 8pi. Find the angle inradians in simplest

Answers

Answer: 2π

Explanation

Given the radius (r = 4 ) and the arc length (s = 8π), we can use the following formula to find the angle:

\(s=r\cdot\theta\)

where θ is the angle.

Thus, by replacing the values and simplifying we get:

\(8\pi=4\theta\)\(4\theta=8\pi\)\(\frac{4\theta}{4}=\frac{8\pi}{4}\)\(\theta=2\pi\)

What are the next 3 numbers in the Geometric sequence 9, 3, 1, 1/3?

Answers

Answer:

The common ratio of this sequence is 1/3, so to find the next three terms we can continue multiplying by 1/3:

1/3 * 1/3 = 1/9

1/9 * 1/3 = 1/27

1/27 * 1/3 = 1/81

Therefore, the next three terms in the sequence are 1/9, 1/27, and 1/81.

1/9, 1/27, and 1/81 are the next 3 numbers in the Geometric sequence 9, 3, 1, 1/3

The given geometric sequence is 9, 3, 1, 1/3.

To find the common ratio, we divide any term by the previous term. Let's use the second and first terms:

3 ÷ 9 = 1/3

The common ratio is 1/3.

To find the next three terms, we can continue multiplying each term by the common ratio.

1/3 * (1/3) = 1/9

(1/3) * (1/9) = 1/27

(1/9) * (1/27) = 1/81

Therefore, the next three terms in the geometric sequence are 1/9, 1/27, and 1/81.

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Which parallelogram will have the smallest area?

b = 4 cm, h = 9 cm
b = 10 cm, h = 4 cm
b = 6 cm, h = 7 cm
b = 7 cm, h = 5 cm

Answers

The last one

Step-by-step explanation:

the one with b=7 & h=5 because you have to multiply both numbers together , so you multiply and then see the smallest answer

Answer:

B=7 H=5

Step-by-step explanation:

Find the equation of the line of best fit. Round all decimals to the nearest hundredth.



Points: (57,45),(65,61),(34,30),(87,78),(42,41),(35,36),(59,35),(61,57),(25,23),(35,34)

Answers

Using a calculator, the equation of the line of best fit is given by:

y = 0.81019x + 3.49074.

How to find the equation of linear regression using a calculator?

To find the equation, we need to insert the points (x,y) in the calculator.

In this problem, the points are:

(57,45),(65,61),(34,30),(87,78),(42,41),(35,36),(59,35),(61,57),(25,23),(35,34)

Using a calculator, the line of best fit is:

y = 0.81019x + 3.49074.

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What is the area of this quadrilateral?
9 ft
14 ft
4 ft i
3 ft
9 ft
3 ft
A. 60 square feet
B. 36 square feet
C. 48 square feet
O D. 34 square feet

What is the area of this quadrilateral?9 ft14 ft4 ft i3 ft9 ft3 ftA. 60 square feetB. 36 square feetC.

Answers

Answer:

the answer is c.48 square feet

The parking lot is 348 centimeters long in the drawing. The actual parking lot is 120 meters long. What scale did Angie use for the drawing?

Answers

Angie used a scale of 1:344 in her drawing of the parking lot, where 1 centimeter represents 344 centimeters in reality.

To determine the scale used in Angie's drawing, we can compare the length of the parking lot in the drawing (348 centimeters) to its actual length (120 meters). We need to convert the actual length to centimeters for an accurate comparison.

Since 1 meter is equal to 100 centimeters, the actual length of the parking lot is 120 meters * 100 centimeters/meter = 12,000 centimeters. Dividing the length of the drawing (348 centimeters) by the actual length in centimeters (12,000 centimeters) gives us a scale of 1:34.4.

However, the question states that the length of the parking lot in the drawing is 348 centimeters, so the scale used by Angie is 1:344 (348 centimeters = 1 meter).

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Will give brainliest!

Will give brainliest!

Answers

Let me help you out on future questions like this. Go to Math/way .com (it’s free) and type in the question and it solves it. Please mark brainliest.

3. Find the measure of the sides of the triangle if the vertices of AEFG are E
(1,4), F(5, 4), and G(1,0). Then classify the triangle by its sides.

Answers

The triangle EFG is an isosceles triangle as side EF is congruent to side EG.

How to determine a triangle according to its sides

In this question we have a triangle whose vertices are known. We need to define the figure according to the congruency among its sides. Two sides are congruent when both have the same length. There are three kinds of triangles:

Scalene - Three sides of different length.Isosceles - Two sides of equal length.Equilateral - All sides are of equal length.

Sides are formed each pair of vertices. The length of each side can be found by means of Pythagorean theorem:

l = √[(Δx)² + (Δy)²]

First, write the locations of the vertices:

E(x, y) = (1, 4), F(x, y) = (5, 4), G(x, y) = (1, 0)

Second, determine the length of every side of the triangle:

EF = √[(5 - 1)² + (4 - 4)²]

EF = 4

FG = √[(1 - 5)² + (0 - 4)²]

FG = √[4² + (- 4)²]

FG = 4√2

EG = √[(1 - 1)² + (0 - 4)²]

EG = 4

By direct comparison, we conclude that the triangle EFG is an isosceles triangle.

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Pooja's plant began sprouting 2days before pooja bought it, and she had it for 98 days until it died. at its tallest, the plant was 30 centimeters tall. h(t) models the height of pooja's plant (in centimeters), t days after she bought it. which number type is more appropriate for the domain of h? choose 1 answer:

Answers

The number type which is more appropriate for the domain of h is Real number and the appropriate domain is -2 ≤ t ≤ 98.

The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x).

The domain of a function is the set of all inputs for which the function is defined. In this case, the input variable t represents the time since Pooja bought her plant.

Since time is a continuous quantity, the appropriate number type for the domain of this function is the real numbers.

2/3

The lower bound is -2 because the plant began sprouting 2 days before Pooja bought it. The bound is inclusive because we know the plant's height when it just began sprouting (0 centimeters). Using function notation, we can express this as: h(-2) = 0.

The upper bound is 98 because the plant died 98 days after Pooja bought it. The bound is inclusive because we can assign the plant's height when it died to this input. Using function notation, this means that h(98) is defined.

3/3

The appropriate number type for the domain of the function is: Real numbers

The interval of the domain is: -2 ≤ t ≤ 98.

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Help with this question

Help with this question

Answers

Answer:

\( \: \: \: \: \: \: \: \)

Lola was hiking 670 feet above sea level Dan was to 720 feet below her what was Dan’s elevation

Answers

Answer:

-50

Step-by-step explanation:

Dan's elevation is -50 feet below sea level. If Lola is at an elevation of 670 feet and Dan is 720 feet below her, you need to subtract; 670 - 720. This would get you to -50 feet which is Dan's elevation. Hope this helps!

Water has a freezing point of 32 mercury has a freezing point that is 70 lower heat is the freezing point of mercury

Answers

Mercury is used to measure high temperatures and alcohol has a lower freezing point that mercury.

The freezing point of any substance, describe the transition of liquid into solid.

The freezing point of water is \(0\) °C or \(32\) °F.

At zero-degree water molecules are moving very slowly, and formation of solid begins i.e. Ice.

When salt or sugar is combined that is mixed with water or ice and it is evenly distributed, the freezing point is lowered.

Lowering of freezing point allows the street ice to melt at lower temperatures, it prevent the accumulation of dangerous, slippery ice.

Alcohol is used to measure the lower temperatures.

Mercury boils at \(357\) degree Celsius where as alcohol boils at \(78\) degree Celsius.

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Help please this is not a quiz I need help I’m practicing and I don’t understand

Help please this is not a quiz I need help Im practicing and I dont understand

Answers

Solution:

Since the height of the freefall is parabolic as shown below,

the standard form of expressing a parabola is given as

\(\begin{gathered} y=a(x-h)^2+k\text{ ----- equation 1} \\ \text{where} \\ (h,k)\text{ is the coordinate of the vertex of the parabola} \end{gathered}\)

Step 1: Evaluate the coordinate of the vertex of the parabola.

In the above graph, the coordinate of the vertex is (0,0).

Thus,

\(\begin{gathered} h=0 \\ k=0 \end{gathered}\)

Step 2: Substitute the values of h and k into equation 1.

Thus,

\(\begin{gathered} y=a(x-h)^2+k \\ h=0,\text{ k=0} \\ y=a(x-0)^2+0 \\ \Rightarrow y=ax^2\text{ ----- equation 2} \end{gathered}\)

Step 3: Select a point on the curve, and substitute the values of x and y into equation 2, to obtain a.

Thus, using the point (0.2, -3) as shown above, where x=0.2 and y=-3, we have

\(\begin{gathered} y=ax^2 \\ x=0.2,\text{ y=-3} \\ \Rightarrow-3=a(0.2)^2 \\ -3=0.04a \\ \Rightarrow a=-\frac{3}{0.04} \\ a=75 \end{gathered}\)

Substitute the value of a into equation 2.

Thus,

\(\begin{gathered} y=75x^2 \\ \text{where} \\ y\Rightarrow h(d) \\ x\Rightarrow d \end{gathered}\)

Hence, the function that describes these coordinates is expressed as

\(h(d)=75d^2\)

Help please this is not a quiz I need help Im practicing and I dont understand

find the jacobian of the transformation x=3u, y=2uv and sketch the region g: 3<3u<6, 2<2uv<4

Answers

It is a rectangular region with u and v values ranging from 1 to 2.

To find the Jacobian of the transformation x = 3u, y = 2uv, we need to compute the partial derivatives ∂x/∂u, ∂x/∂v, ∂y/∂u, and ∂y/∂v.

Given:

x = 3u

y = 2uv

Calculating the partial derivatives:

∂x/∂u = 3

∂x/∂v = 0 (since x does not depend on v)

∂y/∂u = 2v

∂y/∂v = 2u

Now, we can construct the Jacobian matrix J:

J = [∂x/∂u   ∂x/∂v]

   [∂y/∂u   ∂y/∂v]

Substituting the partial derivatives we calculated earlier:

J = [3   0]

   [2v  2u]

Therefore, the Jacobian of the transformation is:

J = [3   0]

   [2v  2u]

To sketch the region described by the inequalities g: 3 < 3u < 6, 2 < 2uv < 4, we can consider the ranges of u and v that satisfy these conditions.

From the inequality 3 < 3u < 6, we have:

1 < u < 2

From the inequality 2 < 2uv < 4, we can divide both sides by 2:

1 < uv < 2

Since u and v must both be greater than 1, we can determine the range of v:

1 < v < 2

Now, we can sketch the region in the u-v plane bounded by the conditions:

1 < u < 2

1 < v < 2

It is a rectangular region with u and v values ranging from 1 to 2.

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One angle of an isosceles triangle measures 56°. What measures are possible for the other two angles? Choose all that apply.

Answers

The possible measures of the other two angles would be -

56° and 68° respectively.

What are triangles?

A triangle is a polygon with three edges and three vertices. It is one of the basic shapes in geometry. In Euclidean geometry, any three points, when non-collinear, determine a unique triangle and simultaneously, a unique plane

Given is that one angle of an isosceles triangle measures 56°.

Angles opposite to equal sides are equal. In a isosceles triangle, two sides are equal. So, we can write -

∠1 = ∠2 = 56°    {Angles opposite to equal sides are equal}

∠3 + ∠1 + ∠2 = 180

∠3 = 180 - 2 x 56

∠3 = 180 - 112

∠3 = 68°

Therefore, the possible measures of the other two angles would be -

56° and 68° respectively.

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Certify Completion Icon Tries remaining: 3 A high school has 52 players on the football team. The summary of the players' weights is given in the box plot. What is the median weight of the players?

Answers

Certify Completion Icon Tries remaining: 3 A high school has 52 players on the football team. The summary of the players' weights is given in the box plot. The median weight of the players on the football team is 160 pounds.

The box plot shows that the median weight of the players is the middle value of the distribution. In this case, the median weight is halfway between the 26th and 27th players, which is 160 pounds.

The box plot also shows that the minimum weight of the players is 150 pounds and the maximum weight is 212 pounds. The interquartile range, which is the range of the middle 50% of the data, is 20 pounds.

In conclusion, the median weight of the players on the football team is 160 pounds. This means that half of the players on the team weigh more than 160 pounds and half of the players weigh less than 160 pounds.

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Find the area of a cross section parallel to the base of a cylinder with a radius of 2.5 cm and a height of 12 cm

Answers

Answer: 227.77 cm 2 here is your answer,

Can i have brainliest? i need one more to rank up

Step-by-step explanation:

tina, stacey, and amir were all born in july 4th. stacy is one year younger than tina. amir is 2 years older than tina. the product of all three of their ages is 2340.

Answers

Answer:

2339

Step-by-step explanation:

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