Describe an experiment to show that the force pulling an object increase
with the increase in the mass of the object.
​

Purchasing uses information from the  sales order plan to place purchase orders for raw materials with qualified suppliers.

The term purchasing has to do with the process of the buying of goods and services. The process of purchasing a very essential part of the business venture such that in some areas, an entire department may be devoted to the coordination of the processes involved in purchasing in the establishment.

A purchasing manager may be given the task of seeing to the coordination of the entirety of all the purchasing activities.

Thus, we could see that purchasing is a chain of activities that is based on the principles of demand and supply.

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If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

option D is the correct answer.

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is calculated as follows;

1,000 ---------- 0 time

500 ----------- 10.4 hours

125 ------------- 20.8 hours

Thus, from the calculation done above, we can see that If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

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Answer:

false : In distance time graph,time is shown on the x -axis

Answer: Polish creates a thin layer of wax on the surface of the leather which protects the leather from getting wet and undergoing wear and tear. It also has a lubricating effect on the leather keeping it supple and preventing the leather from drying out and cracking

We will have the following:

First, we determine the time it takes for the motorcycle to traverse the 40 m:

Now, we will use the time to determine the height of the ramp:

So, the ramp was located 0.784 meters in height.

Answer:

4 m/s

Explanation:

10/2.5= 4 m/s

Answer:

Tournament play

Explanation:

Answer:

An filtration is the answer.

A) Work done by net external forces is 8100 J. B) Work done by friction is 8856 J.C) Work done by the net external forces is 8100 J.

Force that is generated between surfaces that slide against each other is called frictional force.

A. Total energy = mgh + (1/2)mv² = (1/2)mv'²

v' is final velocity of the roller coaster at top of the second hill, which is twice its initial velocity (2 m/s).

100 kg × 10 m/s² × 8 m + (1/2) × 100 kg × (2 m/s)² = (1/2) × 100 kg × (2 × 2 m/s)² + 100 kg × 10 m/s² × h

8000 J + 200 J = 400 J + 1000 J + 1000 J × h

h = (8000 J + 200 J - 400 J - 1000 J) / (1000 J × 10 m/s²) = 6.8 m

Therefore,  height of the second hill must be 6.8 meters.

B. mgh + (1/2)mv² - Wf = 1/2mvf²

Wf is work done by friction, vf is final velocity of the roller coaster at the point where it comes to a stop (zero)

100 kg × 10 m/s² × 6.8 m + (1/2) × 100 kg × (2 m/s)² - Wf = 0

Wf = 8856 JTherefore, the work done by friction as the roller coaster moves up the second hill is 8856 J.

C. PE = mgh

ΔPE = PE_final - PE_initial = mgh

KE = (1/2)mv²

W = KE = (1/2)mv²

W_total = ΔPE + KE

W_total = mgh + (1/2)mv²

m = 100 kg

h = 8 m

v = 2 m/s

g = 10 m/s²

W_total = (100 kg)(10 m/s²)(8 m) + (1/2)(100 kg)(2 m/s)²

W_total = 8000 J + 100 J

W_total = 8100 J

Therefore, work done by net external forces that moved the car from where it was at rest on the ground to top of the first hill with its initial velocity is 8100 J.

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→ The magnitude of the wagons horizontal acceleration is 8.5755 m/s².

First, apply the Second Law of Newton in the 'y' direction. Note: The P force has a component in the axis, it is Psin(40)! Therefore:

\(\Large \text {$N + Psin(40) = W$}\\\\\Large \text {$N + 2N \times sin(40) = m \times g$}\\\\\Large \text {$N(1+ \times 2sin(40)) = m \times g$}\\\\\Large \text {$ \sf N = \dfrac {12 \times 9.8}{1+2sin(40)} = 51.453 $ N}\)

So, in the X direction:

\(\Large \text {$m \times a = 2N \times cos(40)$}\\\\\Large \text {$ \sf a = \dfrac {2 \times 51.453}{12} = 8.5755 m/s^2$}\)

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Explanation:

\(power = \frac{work}{time} \)

Given

POWER=1000 W

TIME=5s

WORK=POWER×TIME

=1000×5

5×10³

OPTION C

The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.

Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.

Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:

∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du

The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.

Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.

Let us work through the steps:

Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x

Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du

Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.

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Coulomb's law states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, it is expressed as F = k(q1q2/r^2), where F is the force, k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them.

To calculate the force that acts on q2 due to q, we need to know the charges and the distance between them. Let's assume that q has a charge of 2C and is located 3 meters away from q2, which has a charge of 4C. The value of Coulomb's constant is 9 x 10^9 Nm^2/C^2.

Substituting these values into the formula, we get F = (9 x 10^9 Nm^2/C^2) x (2C x 4C)/(3m)^2 = 3.2 x 10^9 N. Therefore, the force that acts on q2 due to q is 3.2 x 10^9 N.

In conclusion, Coulomb's law provides a mathematical expression to calculate the force between two charged particles. By knowing the charges and the distance between them, we can use this law to determine the magnitude of the force acting on them.

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Answer:

\(\boxed {\boxed {\sf 299.568 \ Joules }}\)

Explanation:

Kinetic energy can be found using the following formula:

\(E_k=\frac{1}{2}mv^2\)

where m is the mass and v is the velocity.

The mass of the person is 60 kilograms and the velocity is 3.16 meters per second

\(m= 60 \ kg \\v= 3.16 \ m/s\)

Substitute the values into the formula.

\(E_k=\frac{1}{2} (60 \ kg) *(3.16 \ m/s)^2\)

First, evaluate the exponent.

\(E_k=\frac{1}{2}(60 \ kg ) (9.9856 \ m^2/s^2)\)

Multiply 60 kg by 9.9856 m²/s²

\(E_k=\frac{1}{2} (599.136 \ kg*m^2/s^2)\)

Multiply 599.136 kg*m²/s² by 1/2, or divide by 2.

\(E_k=299.568 \ kg*m^2/s^2\)

\(E_k= 299.568 \ J\)

The running person has a kinetic energy of 299.568 Joules.

Solution:

We know that, Kinetic energy(kE)= 1/2×m×v^2

By applying formula,we get

Or,KE=1/2×60×3.16^2

Or,kE=299.57j

So,her kinetic energy is 2999.5j

A) The diameter of spherical gold nugget worth 1.00 million dollars would be approximately 16.6 cm.

B)  the platinum nugget of the same size would be worth about 2.22 million dollars.

A) We can start by finding the mass of the gold nugget using its value and the price per ounce:

1 million dollars / 411 dollars per ounce = 2431.3 ounces

Converting this to grams using the conversion factor given in the problem, we get:

2431.3 ounces * 31.1035 g/ounce = 75,629.3 g

Using the formula for the volume of a sphere, V = (4/3)πr^3, and the density of gold, we can solve for the radius:

V = (4/3)πr^3 = m/density = 75,629.3 g / 19.3 g/cm^3 = 3926.9 cm^3

r = (3V/4π)^(1/3) = (3*3926.9 cm^3 / 4π)^(1/3) ≈ 8.3 cm

Finally, we can compute the diameter of the sphere:

diameter = 2r ≈ 16.6 cm

B) The platinum nugget of the same size would have the same volume, so we can use the formula for its value in dollars:

value = volume * density * price per ounce / conversion factor

value = 3926.9 cm^3 * 21.4 g/cm^3 * 884 dollars/ounce / 31.1035 g/ounce ≈ 2.22 million dollars

Therefore, the platinum nugget of the same size would be worth about 2.22 million dollars.

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The net force on the box, if it experiences a force of 15 N to the left, along with the 20 N force acting to the right is 5 N.

Force can be defined as the product of mass and acceleration of a body.

To calculate the net force on the box, we use the formula below.

Formula:

Where:

F' = Net force on the box

F₁ = Force acting to the left

F =  Force acting to the right

From the question,

Given:

Substitute these values into equation 1

Hence, the net force on the box is 5 N.

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Answer:

No

Explanation:

Some objects gain momentum.

Answer:

B. False

Hope you could understand.

If you have any query, feel free to ask.

\(\huge{ \mathrm{  \underline{ Answer }\:  \:  ✓ }}\)

Total force acting on right side = 800 N

Total force acting on left side :

Now, equivalent force acting on the plane is :

And the direction of equivalent force will be the direction of greater force, that is right direction.

Hence, Correct option is :

_____________________________

\(\mathrm{ \:TeeNForeveR\:}\)

Answer:

1. speed is the distance travelled by an object in unit time

2. velocity is the displacement of a body in in unit time

3. formula of speed =total distance (d)÷ total elapsed time

A heat engine operates by converting thermal energy into mechanical energy. The efficiency of a heat engine is defined as the ratio of the useful work output to the heat absorbed from the hot reservoir.

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This pRTICULAR QUESTION IS HARD TO anSwer <3

Answer:

-8

5.092×10

Explanation:

given,

distance (d) =15m

mass (M1) =350kg

mass(M2) = 492kg

Gravitational constant (G)=6.67×10^-11

we know,

gravitational force=(Gm1m2)÷d^2

=(6.67×10^-11×350×492)÷15^2

= (1.14857×10^-5)÷225

= 5.092×10^-8

Answer:

104.3 cm  or 179.7

Explanation:

First find time that it takes for the object to hit the ground

\(\sqrt{(2H)/g} -> \sqrt{(2 x 179)/ 9.8} = 6.04s\\\)*

Then find xf of projectile \(xf= 5.9(6.04) = 37.7\\\\\)

not 100% sure if the projectile is going away from the object or towards it but you either do 142- 37.7   or    142+37.7  

hope that helps

"217 cm" would be the difference throughout the landing locations of the two objects.

Given:

Initial horizontal speed,

Height,

By applying equation of motion, we get

→               \(S = ut+\frac{1}{2}at^2\)

By substituting the values, we get

→ \(179\times 10^{-2}=0+\frac{1}{2}\times 9.8\times t^2\)

→            \(3.58= 9.8t^2\)

                 \(t^2 =\frac{3.58}{9.8}\)

                  \(t = \sqrt{0.36531}\)

                     \(= 0.61 \ s\)

now,

The horizontal distance travelled by the first particle will be:

→ \(d = v\times t\)

     \(= 5.9\times 0.61\)

     \(= 3.59 \ m\)

or,

     \(= 359 \ cm\)

hence,

The distance between particle will be:

= \(d -142\)

= \(359-142\)

= \(217 \ cm\)

Thus the above approach is right.

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The magnitude of vector c is 10 units, and its direction is approximately 63.4 degrees above the negative x-axis.

To find the magnitude of vector c, we can use the formula for vector addition. Vector c is obtained by multiplying vector a by 3 and vector b by 2, and then adding the resulting vectors together. The components of vector c are calculated as follows:

c_x = 3(−1.00) + 2(3.00) = −1.00 + 6.00 = 5.00

c_y = 3(−2.00) + 2(4.00) = −6.00 + 8.00 = 2.00

The magnitude of vector c can be found using the Pythagorean theorem, which states that the magnitude squared is equal to the sum of the squares of the individual components:

|c| = sqrt(c_\(x^2\) + c_\(y^2\)) = sqrt(5.0\(0^2\) + \(2.00^2\)) = sqrt(25.00 + 4.00) = sqrt(29.00) ≈ 5.39

To determine the direction of vector c, we can use trigonometry. The angle θ can be found using the inverse tangent function:

θ = arctan(c_y / c_x) = arctan(2.00 / 5.00) ≈ 22.62 degrees

However, this angle is measured with respect to the positive x-axis. To obtain the angle above the negative x-axis, we subtract this value from 180 degrees:

θ' = 180 - θ ≈ 157.38 degrees

Therefore, the direction of vector c is approximately 157.38 degrees above the negative x-axis.

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Diatomaceous earth filters can be used for public water supplies, but they should be augmented by chlorination. Option A is the correct answer.

Diatomaceous earth filters are effective at removing small particles and can be used for public water supplies. However, they should be augmented by chlorination to ensure the complete removal of harmful microorganisms.

These filters consist of a thin layer of diatomaceous earth on top of a support structure. As water passes through the filter, particles are trapped in the diatomaceous earth layer.

Over time, the diatomaceous earth becomes clogged with particles and must be cleaned or replaced.

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The question is -

Diatomaceous earth filters:

a. Should be supplemented by a chlorination system

b. Should be integrated into a rapid sand filtration system

c. Can be used for a public water treatment system

d. Cane be used in a public sewer treatment system

Answer:

1. A car moving 40 mph has four times as much kinetic energy as one moving 20 mph, while at 60 mph a car carries nine times as much kinetic energy as at 20 mph. Thus a modest increase in speed can cause a large increase in kinetic energy.

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Answer:

a car moving 40mph has four times as much kinetic energy as one moving 20 mph, while at 60 mph a car carries nine times as much kinetic energy as at 20 mph.

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The base of table is "1.08856 m" far away from the ball land.

Given:

Distance travelled by ball,

Initial velocity,

Acceleration,

Constant speed,

As we know the formula,

→ \(S = ut+\frac{1}{2}at^2\)

By substituting the values, we get

→ \(1.2=\frac{1}{2}\times 9.8t^2\)

→ \(1.2 = 4.9 t^2\)

→    \(t = \sqrt{\frac{1.2}{4.9} }\)

→      \(= 0.4948 \ seconds\)

Let,

→ \(x = 2.2\times t\)

     \(= 2.2\times 0.4948\)

     \(= 1.08856 \ m\)

Thus the solution above is right.

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Answer:-37.5 m/s

Explanation:

Answer:

-37.5

Explanation: