Explanation:
let's take the volume of each first:
ice cream: 10×10×4=400cm^3
freezer: 40×40×20=32,000cm^3
now we just divide: 32000/400=80
A boat sailed 7 hours at speed of 80km/h
Answer:
No it’s 1,130
Explanation:
I did online
a golf club is swung and strikes a golf ball with a force of 12.2 N. The golf ball accelerates at 265.2 m/s2. Calculate the mass of the golf ball. Show your work and include the correct unit.
Answer:
\(0.046\ kg\)
Explanation:
\(We\ are\ given\ that,\\Acceleration\ produced\ on\ the\ golf\ ball\ due\ to\ Force\ exerted=265.2\ m/s^2\\Magnitude\ of\ the\ Force\ exerted\ over\ the\ Golf-Ball=12.2\ N\\We\ know\ that,\\'The\ force\ acting\ on\ an\ object\ is\ equivalent\ to\ the\ product\ of\ it's\ mass\\ and\ the\ acceleration\ produced'.\\Or,\\F=ma\\Let\ the\ mass\ of\ the\ golf\ ball\ be\ m,\\Hence,\\12.2=265.2\ m\\m=\frac{12.2}{265.2}=0.046\ kg\)
On a separate sheet of paper:
17. David kicks a football at 43.0° to the horizontal at 67.0 m/s from the ground.
a) How high did Aaron kick the ball?
b) Find the time of travel.
c) How far away does it hit the ground?
18. Emiliano kicks a soccer ball to score a goal at 18.0° to the horizontal at 43.0 m/s from the
ground. She is standing 100 m away from the goal.
a. How high did Hailey kick the ball?
b.
Find the time of travel in the air.
c. How far away does it hit the ground? Will she score
Answer of the all following horizontal force question as follows.
What is horizontal force?Horizontal force is a type of force that acts parallel to the ground, or in a horizontal direction. It is also known as a lateral force. This type of force is often encountered in everyday life and in physics.
a) The height of Aaron's kick can be calculated using the equation: h = (v^2sin2θ)/2g, where v is the initial velocity, θ is the angle of projection and g is the acceleration due to gravity. Plugging in the given values, we get h = (67^2sin(43))/ (2*9.8) = 36.3 m.
b) The time of travel can be found using the equation: t = (2v sinθ)/g. Plugging in the given values, we get t = (2*67sin(43))/9.8 = 7.72 s.
c) The distance of the kick can be found using the equation: d = (v^2sin2θ)/g. Plugging in the given values, we get d = (67^2sin(2*43))/9.8 = 130.3 m.
18-
a. Hailey kicked the ball to a height of 21.5 m.
b. The time of travel in the air was 2.5 s.
c. The ball hit the ground 91 m away from the goal. Since she was standing 100 m away, she will not score a goal.
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Astronomers were at first surprised to find complicated molecules in the interstellar medium. They thought ultra-violet light from stars would break apart such molecules. What protects the molecules we observe from being broken apart
Answer:
The dust present in the clouds.
Explanation:
The complicated composition molecules that can be found in space are generally associated with clouds of dust. The significant amount of dust in these clouds provides protection not only for these molecules, but for any body that makes up or is associated with dust clouds.
It is exactly this dust that protects the molecules against the action of ultraviolet rays.
1. At 1.7 atm sample of gas takes up 4.25L. If the pressure on the gas
is increased to 2.40 atm. What will the new volume be?
The new volume corresponding to a new pressure can be calculated using Boyle's law. The volume of the gas when pressure increased to 2.40 atm is 3.01 L.
What is Boyle's law?According to Boyle's law, the volume of a gas is inversely proportional to the pressure of the gas. Thus PV = a constant.
If a system have initial pressure P1 and volume of V1 when changes to final pressure of P2 and volume V2, the relation between them can be written as follows:
P1V1 = P2V2
Thus for the initial pressure of 1.7 atm and 4.25 l volume, the final volume corresponding to 2.4 atm pressure is calculated as follows:
1.7 atm × 4.25 L = 2.4 atm × V2
V2 = (1.7 atm × 4.25 L)/2.4 atm
= 3.01 L.
Thus, volume of the gas when pressure increased to 2.40 atm is 3.01 L.
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Look up the radius and mass of the Moon. Using this information to calculate the acceleration of gravity on its surface. If a person weighs 120 lb on Earth, how much does he/she weigh on Moon?
A person who weighs 120 pounds on earth would weigh approximately 20 pounds on the moon. This is because the force of gravity is weaker on the moon due to its lower mass and smaller size. The radius of the moon is about 1,737 km (1,080 miles) while its mass is approximately 7.342 × 10²² kg (81 billion tons).
Using this data, we can calculate the acceleration of gravity on the moon's surface which is about 1.62 m/s².A person who weighs 120 pounds on earth would weigh approximately 20 pounds on the moon.
Here's how to calculate the acceleration of gravity on the moon's surface:G = GM / R² where G is the acceleration of gravity, M is the mass of the moon, and R is the radius of the moon.
We know that M = 7.342 × 10²² kg and R = 1,737 km = 1,737,000 meters so we can plug in these values to find G.G = (6.67 × 10⁻¹¹ N(m/kg)²) (7.342 × 10²² kg) / (1,737,000 m)²G = 1.62 m/s²
Therefore, the acceleration of gravity on the moon's surface is 1.62 m/s².
A person who weighs 120 pounds on earth would weigh approximately 20 pounds on the moon. This is because the force of gravity is weaker on the moon due to its lower mass and smaller size.
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A rectangular block measures 4.1 cm by 2.8 cm by 2.1 cm.
Calculate its volume giving your answer to an appropriate
number of significant figures.
Answer:v=l x w x h
Explanation:
h=height
w=width
l=length
Answer:
24.108 cm3
Explanation:
4.1x2.8x2.1
24.108cm3
for the bullet that produces the minimum spring compression, what is the compression dd if the spring has the force constant calculated in part c? express your answer with the appropriate units.
The compression dd of the spring with the minimum spring compression and force constant calculated in part c depends on the specifics of the problem and cannot be determined without further information.
The compression of a spring is defined as the amount of deformation that a spring undergoes when a force is applied to it. The force constant of a spring is the amount of force required to stretch or compress the spring by a certain amount. Therefore, the compression dd of a spring depends on the applied force and the force constant of the spring. The minimum spring compression occurs when the force applied is minimum or zero, in which case the compression is also zero. However, without knowing the specifics of the problem, such as the mass of the bullet or the initial velocity, we cannot determine the exact value of the compression dd. Therefore, the answer to this question is that it depends on the specifics of the problem and cannot be determined without further information.
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If the partial pressure of nitrogen in the human body is approximately 593 mm hg at sea level, the partial pressure of nitrogen cannot be ______________ in a scuba diver that is at a depth of 30 feet.
If the partial pressure of nitrogen in the human body is approximately 593 mm hg at sea level, the partial pressure of nitrogen cannot be 760mm Hg in a scuba diver that is at a depth of 30 feet.
Nitrogen narcosis :
The partial pressure of nitrogen increases with pressure, which produces a narcotic effect. Nitrogen narcosis affects both scuba divers and free divers. It causes depression of the central nervous system, which leads to feelings of euphoria, disorientation and irrational behavior. Divers need to consider absorption rates of different gases in order to avoid conditions such as nitrogen narcosis, and decompression sickness.
What is the partial pressure of the nitrogen?
Therefore, at sea level, where atmospheric pressure is known to be 760 mm Hg, the partial pressures of the various gases can be estimated to have partial pressures of approximately 593 mm Hg for nitrogen, 160 mm Hg for oxygen, and 7.6 mm Hg for argon.
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A 1.5-kg physics textbook is initially at rest on a steel table. The textbook is then
pushed with a constant force of 5.0 N. Friction with a magnitude of 3.0 N is
exerted on the moving book by the surface of the table. Determine the final
velocity of the textbook after it has been pushed 0.50 meter across the table.
∑F = m.a
5 - 3 = 1.5 x a
a = 1.3 m/s²
vf² = vi² + 2ad (vi = o at rest)
vf² = 2 x 1.3 m/s² x 0.5
vf² = 1.3
vf = 1.14 m/s
Question 7 Points 2
The bicycle lamp glows when the bicycle's generator touches the wheel. This is because
Answer:
The dynamo has a wheel that touches the back tyre. As the bicycle moves, the wheel turns a magnet inside a coil. This induces enough electricity to run the bicycle's lights. The faster the bicycle moves, the greater the induced voltage - and the brighter the lights.
Because of the bicycle's actions, the wheel turns a magnet internal a coil. This induces enough strength to run the bicycle's lighting fixtures. The faster the bicycle movements, the greater the caused voltage - and the brighter the lights.
What type of modern is produced with the aid of a bicycle dynamo?A trendy dynamo creates an instantaneous modern-day (DC) – a one-directional waft of electrical rate. A bicycle dynamo creates an alternating current (AC), which reverses course from time to time.
A dynamo is a tool normally positioned inside the hub of a motorcycle's wheel that converts the energy generated by means of the wheel spinning to electric power. That energy is then used to run front and rear dynamo lights at the bike, offering constantly-on illumination without the want to change the lighting.
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Describe the motion of the box:
A)The box will not move because the forces acting on the box are balanced.
B)The box will move 75N to the right, because the forces are unbalanced.
C)The box will move 75N to the left, because the forces are unbalanced.
Answer:
B
Explanation:
because that's the answer
An external force of 25 N acts on a system for 10 s. What is the impulse delivered to the system?
Answer:
I = 250N*s
Explanation:
I = F*t
I = impulse or momentum
F = Force
t = time
I = 25N*10s
I = 250N*s
What is the maximum weight of a luminaire (lighting fixture) permitted to be hung directly from an outlet box in a ceiling?
The maximum weight of a luminaire (lighting fixture) permitted to be hung directly from an outlet box in a ceiling 50 pound.
A luminaire that weighs more than 23 kg (50 lb) shall be supported independently of the outlet box, unless the outlet box is listed for not less than the weight to be supported.
Luminaire, or light fixture, complete lighting unit, consisting of one or more lamps (bulbs or tubes that emit light), along with the socket and other parts that hold the lamp in place and protect it, wiring that connects the lamp to a power source, and a reflector that helps direct and distribute the light.
Fluorescent fixtures usually have lenses or louvers to shield the lamp (thus reducing glare) and redirect the light emitted. Luminaires include both portable and ceiling- or wall-mounted fixtures.
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Infrared light waves are the closest or farthest in wavelength to visible light?.
During first half of a journey by a body it travel with a speed of 40km/hr and in the next half it travels with a speed of 20 km/hr .Calculate the average speed of the whole journey.
Answer:
Average speed = 26.67 km/h
Explanation:
It is given that,
The first half of the journey by a body is traveled with a speed of 40 km/h and the next half is covered with a speed of 20 km/h
We need to find the average speed of the whole journey. When two speeds are given, the average speed is given by :
\(v=\dfrac{2v_1v_2}{v_1+v_2}\\\\v=\dfrac{2\times 40\times 20}{40+20}\\\\v=26.67\ km/h\)
So, the average speed of the body of the whole journey is 26.67 km/h.
Marking as brainliest last attempt
(ZOOM IN THE PHOTO)
write a paragraph about the topic : bullying in schools
Answer:
Bullying in the schools has negative effects on individual students and on the school climate as a whole. Bullying can cause long-term problems for both the victims of bullying and the bullies themselves. To explore the effects of bullying on adolescents, we will define bullying, identify the characteristics of bullies and victims, outline the extent and consequences of bullying, and present resources for further information and assistance.
Bullying is any behavior that is initiated by one or more students against a victim or victims that causes physical or psychological intimidation. Bullying behaviors can be classified as either direct (such as teasing, threatening, hitting, or stealing) or indirect (such as rumor spreading or social isolation). Boys typically employed direct methods of bullying, while girls tend to use in direct methods. Either way, behaviors must occur repeatedly overtime to be classified as bullying.
Characteristics of Bullies and Victims
There are specific behaviors that bullies tend to exhibit. The bullies often need to feel powerful and in control. They may feel no remorse when they inflict injury and suffering on others. Bullies tend to defy authority and are likely to break school rules. They seem to have little anxiety and appear to possess high self-esteem. Students who come from homes characterized by physical punishment tend to be more likely to exhibit these types of behaviors.
Victims also tend to exhibit specific characteristics. They are often anxious, insecure, cautious, and have low self-esteem. Victims tend to be socially isolated, and may lack social skills and friends. Because they tend to be weaker than their peers, either physically or socially, victims rarely retaliate against bullies. Students who have close ties with their parents/guardians or who have overprotective parents/guardians are more likely to be victimized by bullies.
An airplane travels 640 miles from topeka to houston in 3. 2 hours, going against the wind. The return trip is with the wind, and takes only 2 hours. Find the rate of the airplane with no wind. Find the rate of the wind.
When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr
Let Va is the velocity of the airplane
Va is the velocity of the wind
When flying against the wind then
(Va+Vw)*(3.2 hours) = 640
3.2Va + 3.2Vw = 640
3.2Vw = 640 - 3.2Va
Vw = 200 - Va----------------(1)
When flying with the wind:
(Va-V)*(2 hours) = 640km
2Va - 2Vw = 640
Va - Vw = 320 ----------------(2)
Putting the value of VW in equation (2) we get
Va - (200-Va) = 320
2Va = 320 +200
2Va = 520
Va = 260
Putting this value in equation (2)
Vw =Va - 360
Vw = 100
Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr
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An atmospheric layer of a specific gas provides shielding from harmful ultraviolet light from the sun, allowing life to thrive on earth. What gas makes up this layer?.
The gas that makes up this layer is O3 (Ozone).
The ozone layer protects the earth from most of the sun's UVB rays. Greenhouse gases are a set of gases that accumulate in the lower layer of the atmosphere the troposphere and absorb infrared radiation to increase the average temperature of the Earth's surface. At the top of the stratosphere, 30 miles up, ozone absorbs most of the sun's harmful UV rays.
At the top of the troposphere 12 miles, up ozone acts as a greenhouse gas and traps heat. The troposphere is the lowest layer of the Earth's atmosphere. Most of the atmospheric mass is in the troposphere. Most types of clouds are in the troposphere, and almost all weather phenomena occur in this layer. Greenhouse gases are so named because they absorb infrared radiation from the sun in the form of heat which circulates in the atmosphere and is eventually lost to space.
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What should be done in order to decrease the gravitational force between two objects?
Increase the distance between the two objects.
Increase the mass of both of the objects.
Increase the mass of one of the objects.
Decrease the distance between the two objects.
Answer:
Actually for people in K12 (me) the answer is, "Increase the distance between the two objects"
Explanation:
I used the answer above me and got it wrong
:))
Answer: increase the distance between the two objects
Explanation: its the correct one trust me
who would benefit of your own handled problem?why?
Answer:
Define the problem . what's exactly going on ?
- set some goals
- examine the consequences
- put your solution into practice
- brainstorm possible solutions
- Team working
Explanation:
ANY PROBLEM RELATED TO MANI CUSTOMER BILLING ACCOUNTING IN BOOKKEEPING ETC
NING A WAY TO MAKE THE COMPANY MORE PRODUCTS FIDABLE THROUGH NEW SERVICE OR PRODUCT OFFERING NEW PRICING IDEA PROMOTING AND SALES IDEA
Two resistors, one having half the resistance of the other, are connected to a battery as shown. What is the voltge across the bigger resistor?
The voltage across the bigger resistor, given the size, is 2/3 of the battery voltage.
How to find the voltage ?Assuming the battery voltage is V. Also assuming the smaller resistor has the resistance, R, it means the bigger resistor would have the resistance of 2 R.
The current will be the same for both resistors and will be V / ( R + 2 R ) = V / 3 R.
The voltage for the smaller resistor is therefore:
IR = V / 3 R x R
= V / 3
The voltage across the bigger resistor is V - V / 3 = 2 V / 3. This is 2 / 3 of the battery voltage.
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The voltage across the bigger resistor (R) is (2 V_B ) / 3.
What is the voltage across the bigger resistor?The voltage across the bigger resistor is calculated by applying Ohm's law as shown below;
V = IR
where;
V is the of the batteryI is the current flowing in the circuitR is the resistance of the circuitSince the two resistors are in series, the equivalent resistance is calculated as follows;
Re = R + R/2
Re = 3R/2
The current flowing in the circuit is calculated as follows;
I = V_B/Re
I = ( V_B ) x 2/3R
The voltage across the bigger resistor (R) is calculated as follows;
V' = IR
V' = ( V_B) x 2/3R x R
V' = (2V_B) / 3
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The form of energy stored in a stretched spring would be elastic kinetic energy intermolecular binding energy a mixture of elastic and mechanical transformational energy elastic potential energy The result of simultaneous application of two forces, facing away from each other on a spring, may be some shear in the spring some elongation in the spring some contraction in the spring some bending in the spring
The form of energy stored in a stretched spring is elastic potential energy. When a spring is stretched or compressed, it possesses potential energy due to the deformation of its structure.
This potential energy is called elastic potential energy because it is associated with the elasticity of the spring.
As the spring is stretched, work is done to overcome the forces within the spring that resist the change in its length. This work is converted into potential energy, which is stored in the spring. The amount of potential energy stored in the spring is directly proportional to the amount by which it is stretched or compressed.
When two forces are simultaneously applied to a spring in opposite directions, it may result in elongation or contraction of the spring, depending on the magnitude and direction of the forces. If the applied forces are strong enough to overcome the spring's elasticity, the spring will undergo deformation and exhibit elongation or contraction. This deformation is a manifestation of the stored elastic potential energy being converted into mechanical energy.
Shear, bending, and intermolecular binding energy are not directly related to the stretching of a spring.
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Which type of wave moves both energy and the particles in the same direction as the medium?
Answer:
Longitudinal waves
Explanation:
With sound waves, the energy travels along in the same direction as the particles vibrate. This type of wave is known as a longitudinal wave , so named because the energy travels along the direction of vibration of the particles.
Un puente de acero de 100 m de largo a 8° C aumenta su temperatura a 24°C ¿Cuánto medirá su longitud? Valor del coeficiente de dilatación para el acero: 11.5 X 10^-6
La longitud final del puente de acero es 100.018 metros.
Asumamos que la dilatación térmica experimentada por el puente de acero es pequeña, de modo que podemos emplear la siguiente aproximación lineal para determinar la longitud final del puente de acero (\(L\)), en metros:
\(L = L_{o}\cdot [1+\alpha\cdot (T_{f}-T_{o})]\) (1)
Donde:
\(L_{o}\) - Longitud inicial del puente, en metros. \(\alpha\) - Coeficiente de dilatación, sin unidad.\(T_{o}\) - Temperatura inicial, en grados Celsius.\(T_{f}\) - Temperatura final, en grados Celsius.Si tenemos que \(L_{o} = 100\,m\), \(\alpha = 11.5\times 10^{-6}\), \(T_{o} = 8\,^{\circ}C\) y \(T_{f} = 24\,^{\circ}C\), entonces la longitud final del puente de acero es:
\(L = (100\,m)\cdot [1+(11.5\times 10^{-6})\cdot (24\,^{\circ}C - 8\,^{\circ}C)]\)
\(L = 100.018\,m\)
La longitud final del puente de acero es 100.018 metros.
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a wire of radius 6 mm and length 400 m is melted into a sphere calculate the radius of the sphere in centimetres
Answer:
22.6 cm
Explanation:
The volume of the wire is equal to the volume of the sphere. The volume of a cylinder (the wire) is given by the formula V = πr^2h, where r is the radius and h is the height (length). The volume of a sphere is given by the formula V = 4/3πR^3, where R is the radius of the sphere.
Let’s first convert the radius of the wire from millimeters to meters:
6 mm = 0.006 m.
The volume of the wire is then V = π(0.006 m)^2(400 m) = 0.04524 m^3.
Now we can solve for the radius R of the sphere:
0.04524 m^3 = 4/3πR^3.
Solving for R gives
R = (0.04524 m^3 / (4/3π))^(1/3) ≈ 0.226 m.
Finally, let’s convert the radius from meters to centimeters:
0.226 m = 22.6 cm.
So, the radius of the sphere is approximately 22.6 cm.
A very important control of the DAILY range of temperature is _____.
A very important control of the daily range of temperature is the atmosphere.
The atmosphere is considered the most important control of the daily temperature range. The atmosphere is the layer of gases surrounding Earth that helps regulate temperature, holds oxygen, and shields us from harmful solar radiation.Therefore, this means that the atmosphere plays a vital role in regulating the temperature range experienced in different parts of the world. The atmosphere has various layers, which include the troposphere, the stratosphere, the mesosphere, and the thermosphere.
Air and moisture in the atmosphere have varying heating and cooling rates. This causes a vertical mixing of the air masses and leads to temperature control. Different atmospheric conditions, such as temperature, pressure, and humidity, cause the air to move around. The combination of these movements and other factors leads to a change in temperature in the atmosphere as a whole.
The atmosphere plays a significant role in regulating the temperature range of the Earth. Its different atmospheric conditions, such as temperature, pressure, and humidity, create a mix of air masses that leads to the change in temperature.
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A balloon has a mass of 104g and a volume of 7 cm. What is its density?
54 S
13.2
cm
14.868
Cm
0.07
cm
Answer:
14.868
Density equals mass divided by volume
Convert the following from °C to K: For example, 0°C = 273 K, and -100°C = 173 K.
50°C
10°C
17°C
-40°C
Explanation:
To convert from °C to K, we use the expression below;
tK = t°C + 273
tK = temperature in Kelvin
t°C = temperature in celcius
A. 50°C;
tK = 50 + 273 = 323K
B. 10°C;
tK = 10 + 273 = 283K
C. 17°C;
tK = 17 + 273 = 290K
D, -40°C
tK = -40 + 273 = 233K
Blank explains why earth's distance from the sun varies over the course of each year.target 1 of 6
The distance from Sun to Earth varies each year due to the difference in orbits. It is due to Tidal stress.
Earth is pulled along in the Sun's orbit around the galaxy. The motion of the sun causes a slight distortion in the planets' orbits as Earth travels around our star. Earth’s orbit is therefore elliptical, or somewhat egg-shaped. The Moon experiences the same effects due to Earth's motion and the Moon's gravitational pull. It is known as tidal stress.
Earth's orbit is slightly elliptical because it is not a perfect circle. And as a result, Earth is either moving from the perihelion point to the aphelion point (constantly getting closer to the Sun) or from the aphelion point to the perihelion point (constantly getting farther from the Sun).
Thus, the above phenomenon can be explained through tidal stress.
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