define condensation point

Answers

Answer 1

Answer:

This is a physical point where a substance changes from its gas state to a liquid state at a constant temperature.


Related Questions

5. The Hall coefficient and conductivity of Cu at 400 K have been measured to be 0.45x10-10 m³/As and 6.5 /ohm-meter respectively. Calculate the drift mobility of the electrons in Cu.

Answers

The drift mobility of electrons in Cu is the ratio of the electric field to the charge carried by an electron and the time it takes for an electron to reach from one end of a conductor to the other under an applied electric field.

The Hall coefficient is defined as \(RH = (1/ne) * (dVH/dB)\) where n is the charge density, e is the charge of an electron, VH is the Hall voltage, and B is the magnetic field. To calculate the drift mobility of the electrons in Cu, we will first determine the charge density n using the Hall coefficient.

We can then use the conductivity and charge density to calculate the drift mobility. Given, Hall coefficient \(RH = 0.45 × 10^-10 m^3/A s\)  and Conductivity \(σ = 6.5 /ohm\) meter at a temperature of 400K. (Magnetic field)

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All of the following are characteristic of a hybrid electric vehicle (HEV), except _________.

High voltages (safety issue)b
Lower fuel economy
Lower amount of carbon dioxide released to the atmosphere

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All of the following are characteristic of a hybrid electric vehicle (HEV), except Lower fuel economy.

What is hybrid electric vehicle (HEV)?

A hybrid vehicle that combines an electric propulsion system with a traditional internal combustion engine (ICE) system is known as a hybrid electric vehicle (HEV) (hybrid vehicle drivetrain). The use of an electric powertrain aims to produce either higher performance or better fuel economy than a traditional car.

There are various HEV kinds, and each one differs in how much it functions as an electric vehicle (EV). While hybrid electric buses, boats, cars, and tractors are all available, hybrid electric cars are the most popular type of HEV.

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a car approaches a stationary police car at 36 m/s. the frequency of the siren (relative to the police car) is 500 hz. what is the frequency (in hz) heard by an observer in the moving car as he approaches the police car? (assume the velocity of sound in air is 343 m/s.)

Answers

The frequency heard by an observer in the moving car as they approach the police car is approximately 541 Hz.

To determine the frequency heard by an observer in the moving car as they approach the police car, we need to consider the Doppler effect. The Doppler effect is the change in frequency of a wave as a result of relative motion between the source of the wave and the observer.

The speed of sound in air is given as 343 m/s.

The velocity of the car approaching the police car is 36 m/s.

The frequency of the siren (relative to the police car) is 500 Hz.

The observed frequency (heard by the moving observer) can be calculated using the Doppler effect equation for sound:

observed frequency = (speed of sound + velocity of observer) / (speed of sound + velocity of source) * source frequency.

Plugging in the given values:

observed frequency = (343 m/s + 36 m/s) / (343 m/s) * 500 Hz

≈ 1.181 * 500 Hz

≈ 590.5 Hz.

Note: The velocity of the observer (moving car) is positive since they are approaching the source.

However, we need to consider that the observed frequency is affected not only by the motion of the observer but also by the motion of the source (siren) relative to the observer. In this case, the source (siren) is also stationary relative to the police car.

Since both the observer and the source are in motion, we need to take into account the relative motion between them. As the observer approaches the source, the effective relative velocity is the sum of their velocities. In this case, the effective relative velocity is 36 m/s.

To account for the relative motion between the observer and the source, we need to adjust the observed frequency. The observed frequency is increased when the observer approaches the source.

By applying the Doppler effect equation again with the adjusted relative velocity, we get:

observed frequency = (343 m/s + 36 m/s) / (343 m/s) * 590.5 Hz

≈ 1.181 * 590.5 Hz

≈ 696.5 Hz.

Note: The adjusted observed frequency is higher than the initial observed frequency due to the relative motion of the observer and the source.

Therefore, the frequency heard by an observer in the moving car as they approach the police car is approximately 541 Hz.

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A 1.2-kg hot iron sphere with heat capacity
576 J °C-1 is cooled by immersing it in a tank of
water (Fig g). (See the photo that I uploaded)The mass of the water is 3 kg and
its initial temperature is 12 °C. After 5 minutes,
both the iron sphere and the water reach a final
temperature of 15 °C.

(a) Find the energy gained by the water.
(b) Find the average rate of energy transfer from
the iron sphere to the water.
(c) What is the initial temperature of the iron
sphere?

A 1.2-kg hot iron sphere with heat capacity576 J C-1 is cooled by immersing it in a tank ofwater (Fig

Answers

Given the data from the question, the heat gained by the water, the rate of energy transfer and the initial temperature of the iron are:

A. The energy gained by the water is 37656 J

B. The average rate of energy transfer from

the iron sphere to the water is 125.52 J/s (Watts)

C. The initial temperature of the iron

sphere is 65.4° C

A. How to determine the heat gained Mass of water (M) = 3 Kg = 3 × 1000 = 3000 gInitial temperature (T₁) = 12 °C Final temperature (T₂) = 15 °Change in temperature (ΔT) = 15 – 12 = 3 °C Specific heat capacity (C) = 4.184 J/gºC Heat (Q) =?

Q = MCΔT

Q = 3000 × 4.184 × 3

Q = 37656 J

B. How to determine the rate of energy transfer Heat (Q) = 37656 JTime (t) = 5 min = 5 × 60 = 300 sPower (P) =?

Power = energy / time

Power = 37656 / 300

Power = 125.52 J/s (Watts)

C. How to determine the initial temperature of the iron Mass of iron (M) = 1.2 Kg = 1.2 × 1000 = 1200 gHeat capacity (C) = 576 J/ºC Heat (Q) = 37656 JTemperature (T) =?

Q = CT

37656 = 576 × T

Divide both side by 576

T = 37656 / 576

T = 65.4° C

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what is the difference in seismic wave arrival of the epicenter is 5000 km away

Answers

Answer:

2 minutes 20 seconds

Q. Seismic station A is 5000 kilometers from the epicenter. What is the difference between the arrival time of the first P-wave and the arrival time of the first S-wave recorded at this station? answer choices 2 minutes 20 second

Explanation:

the doppler shift was first tested in 1845 by the french scientist b. ballot. he had a trumpet player sound an a, 440 hz, while riding on a flatcar pulled by a locomotive. at the same time, a stationary trumpet player played the same note. ballot heard 3.0 beats per second. how fast was the train moving toward him? (assume 343m/s for speed of sound):

Answers

The train was moving towards Ballot at a speed of approximately 51.45 meters per second.

The Doppler effect is the change in frequency of a wave (such as sound or light) due to the relative motion between the source of the wave and the observer. In this experiment, Ballot observed a frequency shift known as beats, which occur when two waves of slightly different frequencies interfere with each other. The beat frequency can be calculated by subtracting the frequency of the stationary source from the frequency observed by the moving observer.

Since Ballot heard 3.0 beats per second, it means that the observed frequency was slightly lower than the actual frequency. By using the formula for the beat frequency, we can calculate the difference between the observed frequency and the actual frequency:

Beat frequency = observed frequency - actual frequency

3.0 beats/second = (frequency observed by Ballot) - 440 Hz

Since the observed frequency is lower than 440 Hz, it implies that Ballot was moving towards the source of the sound. Using the speed of sound as 343 m/s, we can determine the speed of the train towards Ballot:

Speed of train = beat frequency × wavelength of sound

The wavelength of sound can be calculated using the formula:

Wavelength = speed of sound / frequency

Wavelength = 343 m/s / 440 Hz = 0.7795 m

Therefore, the speed of the train can be calculated as:

Speed of train = 3.0 beats/second × 0.7795 m/beat = 2.3385 m/s

Converting meters per second to kilometres per hour:

Speed of train = 2.3385 m/s × 3.6 km/h = 8.4186 km/h

Hence, the train was moving towards Ballot at a speed of approximately 8.42 km/h, or equivalently, 51.45 meters per second.

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A 1.30 kg ball is attached to a ceiling by a
1.93 m long string. The height of the room is
3.41 m.
The acceleration of gravity is 9.81 m/s^2.
What is the gravitational potential energy
associated with the ball relative to
a) the ceiling?
b.)the floor?
c.)a point at the same elevation as the ball?
(answer in J)

Answers

Answer:

A

Explanation:

Put A, It will help you.

which of the following statements is most true regarding the effects of labeling a child with a psychiatric disorder?

Answers

The effects of labeling a child with a psychiatric disorder can vary and are complex, making it difficult to make definitive statements about the most true effect. However, it is generally recognized that labeling a child with a psychiatric disorder can have both positive and negative consequences.

What is the psychiatric disorder?

Labeling a child with a psychiatric disorder can have positive effects by providing them with access to appropriate support and interventions. It can help professionals and educators better understand the child's needs and tailor their interventions accordingly. Labeling can also help reduce stigma and promote acceptance and understanding of mental health conditions.

On the other hand, labeling can also have negative effects. It may lead to self-fulfilling prophecies and reinforce negative stereotypes. It can create social and academic barriers for the child and contribute to feelings of shame, low self-esteem, and discrimination.

Additionally, misdiagnosis or overdiagnosis can occur, leading to unnecessary treatments or inappropriate expectations.

It is important to consider the individual circumstances, the accuracy of the diagnosis, and the support systems in place when assessing the effects of labeling a child with a psychiatric disorder.

A comprehensive approach that focuses on understanding and supporting the child's unique needs is crucial in mitigating potential negative consequences and maximizing positive outcomes.

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A sample of lead is heated up to a temperature of 100°C and then placed in a sample of water with an initial temperature of 5°C. If the mixture is thermally isolated from its surroundings, then it:

exchanges no thermal energy with the environment outside the system as it comes to a final temperature.

gains thermal energy from the environment outside the system as it comes to a final temperature.

both gains and loses thermal energy to the environment outside as it comes to a final temperature.

loses thermal energy to the environment outside as it comes to a final temperature.

None of these choices are correct.

Answers

If the mixture is thermally isolated from its surroundings, then it, loses thermal energy to the environment outside as it comes to a final temperature. The correct answer is d.

When the sample of lead is placed in the water, heat will flow from the lead to the water until they reach a common final temperature. Since the final temperature will be less than the initial temperature of the lead, heat must have flowed out of the lead into the surroundings, causing the lead to lose thermal energy to the environment outside the system.

Since the mixture is thermally isolated from its surroundings, no thermal energy is exchanged between the system (lead and water) and the environment during the process. However, heat can still flow within the system itself until thermal equilibrium is reached. Option d is correct.

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Regardless of which method of delivery a speaker might think is appropriate for a speaking event, the audience has expectations about how messages should be delivered as well. This is a situation that speakers need to carefully consider before selecting a delivery method for their speech.

-true

-false

Answers

Delivery method for their speech is True.

How does the context of the speaking event affect the audience's expectations for the delivery of a speech?

The context of the speaking event can greatly affect the audience's expectations for the delivery of a speech. For example, in a formal setting such as a business conference, the audience may expect a more professional and formal delivery, with the use of slides or visual aids and a well-structured speech. In contrast, at a casual event such as a family gathering, the audience may expect a more relaxed and conversational delivery, with less emphasis on visual aids and a more informal structure. Additionally, the topic of the speech, the background of the audience and the purpose of the speech can also affect the audience's expectations. Therefore, a speaker should be aware of the context of the event, and adjust their delivery method accordingly.

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5)what is the average power delivered to the circuit when it is in resonance?

Answers

In the case of a series RLC circuit in resonance, the average power can be determined by calculating the power dissipated by the resistor.

In a resonant circuit, the average power delivered to the circuit depends on the type of circuit involved. When a series RLC circuit is in resonance, the reactive components cancel each other out, leaving only the resistance as the dominant component. This results in the maximum current flow through the circuit, and the power delivered to the resistor is at its highest.

The average power delivered to the circuit in resonance can be calculated using the formula:

Average Power = (Vrms * Irms * cos θ)

Here, Vrms represents the RMS voltage across the circuit, Irms represents the RMS current flowing through the circuit, and cos θ represents the power factor (which is equal to 1 in a purely resistive circuit).

To obtain the exact values for Vrms and Irms, as well as the power factor, the specific values of the circuit parameters (resistance, inductance, and capacitance) would need to be provided.

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starting from rest, a 10 kg box slides down a 30 incline of length 3 meters. it is subject to a frictional force of 15 newtons while its sliding, what is the kinetic enegry at the bottom of the incline??

Answers

The potential energy of the box at the top of the incline is given by:

PE = mgh

where m is the mass of the box, g is the acceleration due to gravity, and h is the height of the incline. Since the box starts from rest, all of the potential energy is converted to kinetic energy at the bottom of the incline. The kinetic energy of the box is given by:

KE = (1/2)mv^2

where v is the velocity of the box at the bottom of the incline.

The height of the incline is given by h = Lsinθ, where L is the length of the incline and θ is the angle of incline. Substituting the given values, we have:

h = 3sin30° = 1.5 meters

The potential energy of the box at the top of the incline is:

PE = mgh = (10 kg)(9.8 m/s^2)(1.5 m) = 147 J

The work done by friction is given by:

W = Fd = (15 N)(3 m) = 45 J

The net work done on the box is:

W_net = PE - W = 147 J - 45 J = 102 J

This work is equal to the change in kinetic energy of the box:

W_net = ΔKE = KE_f - KE_i

Since the box starts from rest, the initial kinetic energy is zero. Therefore:

KE_f = W_net = 102 J

Substituting the mass of the box, we have:

KE_f = (1/2)mv^2

102 J = (1/2)(10 kg)v^2

Solving for v, we get:

v = sqrt(20.4) m/s

Therefore, the kinetic energy of the box at the bottom of the incline is 102 J, and the velocity of the box at the bottom of the incline is approximately 4.51 m/s.

the circuit is protected by a ground fault interrupter in the plug. the water in the tank is grounded. the two bare wires correspond to the two pins on the ground fault interrupter plug. if the __________ wire is touched to the water, the ground fault interrupter will disconnect the circuit.

Answers

If the hot wire is touched to the water, the ground fault interrupter will disconnect the circuit.

GFI or GFCI This device protected from collecting the electric shocks arise from the faults in the electric devices that are used at home. It would be work by comparing the current on the input side that shows the hot side to the current on the outside side that shows the neutral side of the circuit.

In the case when hot wire give 120 VAC current source while on the other hand the neutral wire gives the return path that are given by the hot wire

Therefore, if the hot wire is touched to the water, the ground fault interrupter will disconnect the circuit.

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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: The circuit is protected by a ground fault interrupter in the plug. The water in the tank is grounded. The two bare wires correspond to the two pins on the ground fault interrupter plug. If the __________ wire is touched to the water, the ground fault interrupter will disconnect the circuit. Select the best answer from the choices provided. Neutral, Hot, Ground]

1) TRUE/FALSE, an example of a quantitative observation is “That is a red doll.”

2) TRUE/FALSE, Potential energy is strongest at the top of a hill.

3) F= ?, m= 18 kg, a= 2 m/s2

help me pweeeees

Answers

Answer:

1) False

2) True

3) 36N

Explanation:

1) Quantitative observation is related to number of objects . But in that example , there isn't any number.

2) Potential energy depends on height. So potential energy increases when height increases.

3) F = m×a

In the question , m = 18 kg ; a = 2m/s^2

So, F = 18×2 = 36N

Taking Earth to be a perfect sphere, find the linear speed of a point located on the 32nd parallel, as a result of Earth’s rotation. The 32nd parallel north is a circle of latitude that is 32 degrees north of the Earth's equatorial plane. Take the Earth's radius to be 6,371,000 m

Answers

The linear speed of a point located on the 32nd parallel, as a result of Earth’s rotation is 392.91 m/s

We find the linear speed of a point on the 32nd parallel from v = rω where r = radius of 32nd parallel north = Rcos32° (since it is the radius of the small circle at the 32nd parallel) where R = radius of earth = 6,371,000 m and ω = angular speed of the earth = 2π/T where T = period of earth = 24h = 24 × 60 × 60 s = 86400 s.

So, v = rω

v = Rcos32° × 2π/T

v = 2πRcos32°/T

substituting the values of the variables into the equation, we have

v = 2πRcos32°/T

v = 2π × 6,371,000 m × cos32°/86400 s.

v = 2π × 6,371,000 m × 0.8480/86400 s.

v = 33947512.5035 m/86400 s

v = 392.91 m/s

So, the linear speed of a point located on the 32nd parallel, as a result of Earth’s rotation is 392.91 m/s

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Beryllium has a charge of 2, and bromine has a charge of –1. which is the best name for the ionic bond that forms between them? beryllium bromide beryllium bromine bromine berylliumide bromide berylliumide

Answers

The best name for the ionic bond that forms between them is Beryllium Bromide.

We have been provided with data,

Beryllium charge, q = 2

Bromine charge, q = -1

As we know the valance electron of Be is +2  and the valance electron of bromine is -1. Since one is metallic and the other is non-metallic.

Now, when they combine they exchange valance electron, and bromine change into bromide so they form Beryllium Bromide.

So, the best name for the ionic bond that forms between them is Beryllium Bromide.  

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what is the difference between copernicus and kepler description of planetary orbits?

Answers

Answer:

Kepler refined the Copernican model. Orbits are not circles along which planets move at a constant speed, but ellipses, in the central focus of which is the Sun. The planet moves in an ellipse with a variable speed depending on the distance to the Sun. On this basis, Kepler significantly simplified the Copernican model and formulated the laws of planetary motion in their orbits.

Prepare a report of at least 700 words, which may include text, illustrations, graphs, or maps, to educate your community about wind power.

Answers

Report about wind power.

Introduction

Wind power is a form of renewable energy that has gained increasing attention in recent years as a sustainable alternative to fossil fuels. It is a clean source of energy that can help reduce carbon emissions and mitigate the effects of climate change. Wind power uses wind turbines to convert the kinetic energy of the wind into electricity. This report aims to educate the community about wind power, its benefits, and its potential for the future.

Overview of Wind Power

Wind power is generated by using wind turbines that consist of blades, a rotor, a generator, and a tower. The blades capture the kinetic energy of the wind and rotate the rotor, which is connected to a generator that converts the rotational energy into electrical energy. The tower supports the turbine and ensures that the blades are at a sufficient height to capture the wind.

Benefits of Wind Power

One of the significant benefits of wind power is that it is a clean and renewable source of energy. Unlike fossil fuels, wind power does not release harmful pollutants into the environment, such as carbon dioxide, sulfur dioxide, and nitrogen oxides. Additionally, wind power does not produce any waste products that need to be disposed of. This makes wind power a sustainable and environmentally friendly option.

Another benefit of wind power is its potential for cost savings. Once a wind turbine is installed, it can generate electricity for several years with minimal maintenance costs. This is especially advantageous in areas with high electricity prices or limited access to traditional energy sources.

Wind power also has the potential to create jobs and stimulate the economy. The wind energy sector requires skilled workers, such as engineers, technicians, and project managers. Additionally, wind power projects can provide a source of income for landowners who lease their land for wind turbine installations.

Challenges of Wind Power

Although wind power has many benefits, it also faces several challenges. One of the primary challenges is that wind power is intermittent and dependent on weather conditions. Wind turbines can only generate electricity when the wind is blowing, which can vary throughout the day and year. This variability requires backup sources of energy to ensure a consistent supply of electricity.

Another challenge of wind power is that it can have negative impacts on wildlife, particularly birds and bats. Wind turbines can pose a collision risk for birds and bats, and their presence can disrupt migration patterns and habitats.

Finally, wind power installations can face opposition from communities concerned about the visual impact of wind turbines on the landscape. The size and placement of wind turbines can be a contentious issue, particularly in areas with scenic or historical value.

Wind Power in the Future

Despite the challenges, wind power has the potential to play an essential role in the future of energy. The International Energy Agency (IEA) has predicted that wind power could provide up to 18% of the world's electricity by 2040. This growth is expected to be driven by declining costs and increasing demand for renewable energy sources.

Advancements in technology, such as larger and more efficient turbines, are also contributing to the growth of wind power. These advancements allow wind turbines to capture more energy from the wind and generate electricity at a lower cost.

Conclusion

Wind power is a clean and renewable source of energy that has many benefits, including cost savings, job creation, and environmental sustainability. However, wind power also faces challenges, such as intermittency, wildlife impacts, and community opposition. Despite these challenges, wind power has the potential to play an essential role in the future of energy and contribute to a more sustainable and environmentally friendly world.

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what is 0.94kg divided by 2.4n

Answers

Answer:

0.39166666666

Explanation:

What is the temperature at 5000 meters given the temperature at sea level is 24. 8 0C?

Answers

The temperature at 5000 meters is approximately -7.70°C.

How to solve for the temperature

To calculate the temperature at 5000 meters, we can use the lapse rate formula:

Temperature at altitude = Sea level temperature - (Lapse rate x Altitude difference)

First, we need to convert the altitude from meters to kilometers:

5000 meters = 5 kilometers

Using the given sea level temperature of 24.80°C and the standard lapse rate of 6.5°C per kilometer, we can calculate the temperature at 5000 meters:

Temperature at 5000 meters = 24.80°C - (6.5°C/km x 5 km)

Temperature at 5000 meters = 24.80°C - 32.5°C

Temperature at 5000 meters = -7.70°C

Therefore, the temperature at 5000 meters is approximately -7.70°C.

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True or false, galaxies look the same whether viewed in visible or x-ray wavelengths.

Answers

False.

Galaxies do not look the same when viewed in visible or X-ray wavelengths. The electromagnetic spectrum consists of various wavelengths, including visible light and X-rays, each carrying different types of information about celestial objects.

When observing galaxies in visible light, we primarily see the light emitted by stars within the galaxies. This provides information about the distribution of stars, their colors, and the overall structure of the galaxy. Visible light observations are commonly used to study the morphology and stellar populations of galaxies.

On the other hand, X-ray observations reveal a different aspect of galaxies. X-rays are produced by extremely energetic processes, such as accretion onto black holes, supernova remnants, and hot gas in galaxy clusters. By observing galaxies in X-ray wavelengths, we can study active galactic nuclei, high-energy phenomena, and hot gas properties within galaxies and galaxy clusters.

Visible light observations provide insights into the stellar content and structure of galaxies, while X-ray observations give us information about the energetic processes and hot gas within galaxies. Therefore, galaxies can appear different when viewed in visible or X-ray wavelengths.

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What is the primary cause of earthquakes?

Answers

Answer:

Tectonic movement is the primary cause of earthquake.

Tectonic plates shifting / moving.

Please answer this
No links please

Please answer thisNo links please

Answers

your answer is- amplitudes

In a simplified model of the hydrogen atom, an electron moves with a speed of 1. 09×106 m/s in a circular orbit with a radius of 2. 12×10−10 m. Determine the time interval for one trip around the circle. Determine the current corresponding to the electron's motion. Determine the magnetic field at the center of the circular orbit. Determine the magnetic moment of the atom

Answers

o determine the time interval for one trip around the circular orbit, we can use the formula for the period of a circular motion:

T = (2πr) / v

where T is the period, r is the radius of the orbit, and v is the speed of the electron.

Plugging in the given values:

T = (2π * 2.12×10^(-10) m) / (1.09×10^6 m/s)

Calculating this expression gives us:

T ≈ 3.0×10^(-16) s

Therefore, the time interval for one trip around the circle is approximately 3.0×10^(-16) seconds.

To determine the current corresponding to the electron's motion, we can use the equation:

I = q / T

where I is the current and q is the charge of the electron.

The charge of an electron is approximately -1.6×10^(-19) coulombs. Plugging in this value and the previously calculated value of T:

I = (-1.6×10^(-19) C) / (3.0×10^(-16) s)

Calculating this expression gives us:

I ≈ -5.3×10^(-4) A

Therefore, the current corresponding to the electron's motion is approximately -5.3×10^(-4) amperes.

To determine the magnetic field at the center of the circular orbit, we can use Ampere's law, which states that the magnetic field (B) produced by a current-carrying loop is given by:

B = (μ0 * I) / (2πr)

where μ0 is the permeability of free space, I is the current, and r is the radius of the loop.

The permeability of free space (μ0) is approximately 4π × 10^(-7) T·m/A.

Plugging in the given values:

B = (4π × 10^(-7) T·m/A) * (-5.3×10^(-4) A) / (2π * 2.12×10^(-10) m)

Simplifying this expression gives us:

B ≈ -2.5×10^(-3) TTherefore, the magnetic field at the center of the circular orbit is approximately -2.5×10^(-3) teslas.

To determine the magnetic moment of the atom, we can use the formula:

μ = IA

where μ is the magnetic moment, I is the current, and A is the area of the loop.

The area of the loop can be calculated using the formula for the area of a circle:

A = πr^2

Plugging in the given values:

A = π * (2.12×10^(-10) m)^2

Calculating this expression gives us:

A ≈ 1.41×10^(-19) m^2

Now we can calculate the magnetic moment:

μ = (-5.3×10^(-4) A) * (1.41×10^(-19) m^2)

Simplifying this expression gives us:

μ ≈ -7.47×10^(-23) A·m^2

Therefore, the magnetic moment of the atom is approximately -7.47×10^(-23) ampere·meter^2.

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why does chelsea see sparks as she removes her clothes from the clothes dryer? conduction. induction. static discharge. loss of protons.

Answers

This is electrostatic phenomenon. Chelsea see sparks as she removes her clothes from the clothes dryer because of static discharge.

What is Static Electricity ?

Static electricity is produced by friction when two materials are rubbed together.

Why does Chelsea see sparks as she removes her clothes from the clothes dryer?

The correct answer is because of static discharge.

For instance, when a glass rod is rubbed with silk or cellulose acetate with silk, the glass will become positively charged by loosing electron to the silk whereby becoming negatively charged.

Static discharge occurs during thunder and lightning, and when combing our hair during harmattan season.

Therefore, Chelsea see sparks as she removes her clothes from the clothes dryer because of static discharge.

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Answer:

C) Static Discharge

Explanation:

A Carnot engine whose heat sink is at 27degree has an efficiency of 40% by how many degree should the temperature of source be change to increase the efficiency by 10% of the original efficiency

Answers

To increase the efficiency of the Carnot engine by 10% of the original efficiency, the temperature of the heat source should be increased by 0.067 times its original value

To solve this problem

The efficiency of a Carnot engine is given by:

Efficiency = 1 - (Tc/Th)

Where

Tc is the temperature of the heat sink Th is the temperature of the heat source

In this case, the efficiency of the engine is 40%, which can be expressed as 0.4 in decimal form. Therefore:

0.4 = 1 - (Tc/Th)

Rearranging this equation, we get:

Tc/Th = 0.6

We want to increase the efficiency by 10% of the original efficiency. This means that the new efficiency will be :

0.4 + 0.1(0.4) = 0.44

We can use this new efficiency to find the new ratio of Tc/Th:

0.44 = 1 - (Tc_new/Th_new)

Tc_new/Th_new = 0.56

Now we need to find by how many degrees the temperature of the heat source should change to achieve this new ratio of temperatures. We can set up an equation using the two ratios of temperatures:

(Tc/Th) / (Tc_new/Th_new) = 0.6 / 0.56

Substituting the first ratio we found earlier and simplifying, we get:

0.6 / (Th_new/Th) = 0.6 / 0.56

Th_new/Th = 0.56/0.6

Th_new/Th = 0.933

Multiplying both sides by Th, we get:

Th_new = 0.933 Th

So the temperature of the heat source should be increased by:

ΔT = Th_new - Th = 0.933 Th - Th = 0.067 Th

Where ΔT is the change in temperature and Th is the original temperature of the heat source.

Therefore, to increase the efficiency of the Carnot engine by 10% of the original efficiency, the temperature of the heat source should be increased by 0.067 times its original value.

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What is the electrical force between two charges that are each
2.5 x 10-6 C and separated by 3.0 cm from each other?
Remember to identify all data (givens and unknowns), list
equations used, show all your work, and include units and the
proper number of significant digits to receive full credit. (3
points)

Answers

Considering the Coulomb's Law, the electrical force between two charges that are each 2.5×10⁻⁶ C and separated by 3.0 cm from each other is 62.5 N.

Coulomb's Law

From Coulomb's Law it is possible to predict what the electrostatic force of attraction or repulsion between two particles will be according to their electric charge and the distance between them.

From Coulomb's Law, the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:

\(F=k\frac{Qq}{d^{2} }\)

where:

F is the electrical force of attraction or repulsion. It is measured in Newtons (N).Q and q are the values ​​of the two point charges. They are measured in Coulombs (C).d is the value of the distance that separates them. It is measured in meters (m).K is a constant of proportionality called the Coulomb's law constant. It depends on the medium in which the charges are located. Specifically for vacuum k is approximately 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\).

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

Electrical force in this case

In this case, you know that two charges are each 2.5×10⁻⁶ C and separated by 3.0 cm (or 0.03 m, being 1 cm= 0.01 m) from each other.

Replacing in the Coulomb's Law, you get:

F=\(9x10^{9}\frac{Nm^{2} }{C^{2} } \frac{2.5x10^{-6} Cx 2.5x10^{-6} C}{(0.03m)^{2} }\)

Solving:

F=\(9x10^{9}\frac{Nm^{2} }{C^{2} } \frac{6.25x10^{-12} C^{2} }{(0.03m)^{2} }\)

F=\(9x10^{9}\frac{Nm^{2} }{C^{2} } 6.94x10^{-9} \frac{ C^{2} }{m^{2} }\)

F= 62.5 N

Finally, the electrical force between two charges that are each 2.5×10⁻⁶ C and separated by 3.0 cm from each other is 62.5 N.

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Sound travels at approximately 1,500 m/s in sea water. How far will a sonar pulse travel in 90 s?

Answers

Answer:

135,000 m

Explanation:

(1500 m/s) (90 s) = 135,000 m

The distance travelled by sonar pulse will be 135,000 m. Distance is a numerical representation of the distance between two objects or locations.

What is wavelength ?

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

The length of a wave is measured in its propagation direction. The wavelength is measured in meters, centimeters, nanometers, and other units since it is a distance measurement.

The distance travelled by sonar pulse is found as;

\(\rm d = v \times t \\\\ \rm d = 1500\times 90 \\\\ \rm d = 135,000 \ m\)

Hence, the distance travelled by sonar pulse will be 135,000 m.

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what will happen to the gravitational force between two bodies if the distance between them is halved keeping their masses constant ?..

Answers

Since Fg=(Gm1m2)/r^2, if the masses are halted the gravitational force will be effected as well. In this case, the gravitational force would be lessened as well.

what are two
way to change the amount of pressure
being exerted ?

Answers

Answer:      Pressure can be increased by either increasing the force or by decreasing the area or can oppositely be decreased by either decreasing the force or increasing the area

Explanation:

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