Answers
The to and Pro motion of a simple pendulum is an example of a periodic or an oscillatory motion is called pendulum.
A weight that is suspended from a pivot and allowed to freely swing is known as a pendulum. When a simple pendulum is sideways moved from its resting, equilibrium position, gravity exerts a restoring force that accelerates the pendulum back toward the equilibrium position. The pendulum oscillates about the equilibrium position and swings back and forth when the restoring force acting on the mass is withdrawn. The period is the duration of one full cycle, which consists of a left swing and a right swing. The length of the pendulum and, to a lesser extent, its amplitude—the width of its swing—have an impact on the period.
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Related Questions
What is the momentum of a 8850 kg medium truck that is traveling with a velocity of 55 m/s west on the highway
Answers
Answer:
486,750 kg*m/s
Explanation:
Momentum is mass*velocity
M = m*v
M = 8850kg*55m/s
M = 486,750 kg*m/s
The momentum of an 8850 kg medium truck that is traveling with a velocity of 55 m/s west on the highway is 486750 kg m / s.
What is momentum?Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force acting on the particle equals the time rate of change of momentum.
According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum.
Given:
The mass of the truck is, m = 8850 kg,
The velocity of the truck is, v = 55 m/s,
Calculate the momentum of the truck as shown below,
Momentum = m × v
Momentum = 8850 × 55
Momentum = 486750 kg m / s
Thus, the Momentum of the truck is 486750 kg m / s.
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A diver leaves the end of a 5.00 m high diving board and reaches a maximum height of 5.50 m before she strikes the water below. The landing point is 3.25 m beyond the end of the diving board in the horizontal direction. You may approximate the diver as a point particle. Hint: Carefully consider your placement of the origin before starting your calculations.
Determine:_____.
(a) After the diver leaves the diving board, how long does it take for her to strike the water?
(b) The initial velocity of the projectile 7. (hint: a vector has both direction and magnitude).
(c) The final velocity with which the diver enters the water ö, (hint: a vector has both direction and magnitude).
Answers
Answer:
a) 1.38 s
b) v₀ = 3.92 m/s θ₀ = 53.1º
c) vf = 10.7 m/s θf = -77.2º
Explanation:
a)
Once the diver leaves the board, she has an initial velocity vector, that we can split in two directions perpendicular each other, the vertical direction (coincident with the y-axis, positive upward) and the horizontal direction (coincident with the x-axis, positive away from the diving board).These velocities, are independent each other, due to they are perpendicular.In the horizontal direction, since no acceleration takes place, she keeps the horizontal component v₀ₓ, constant.In the vertical direction, she is always accelerated downward by gravity, which constant value is g = 9.8m/s2.With this all information, we can find the total time since she left the diving board till she strikes the water below, taking advantage of the fact that she reached to a maximum height of 5.5 m,i.e. , 0.5m above the diving board. When at this point, the vertical component of the velocity is zero, so we can write the following kinematic equation:\(v_{fy} ^{2} - v_{oy} ^{2} = 2* g* \Delta y (1)\)
Solving for v₀y in (1):\(v_{oy} = \sqrt{2*g*\Delta_{ymax} } = \sqrt{2*9.8m/s2*0.5m} = 3.13 m/s (2)\)
When she is at the highest point, her final vertical speed is zero, so we can find the time when she reached to this point, applying the definition of acceleration, as follows:\(v_{fyhmax} = v_{oy} - g*t_{hmax} = 0 (3)\)
Solving for t in (3), we get:\(t_{hmax} =- \frac{v_{oy}}{g} =\frac{3.13m/s}{9.8m/s2} = 0.32 s (4)\)
Since at this point, the vertical speed is zero, we can apply the equation for the displacement (vertical in this case) for a total displacement of 5.5 m (taking as the origin the point just below the end of the diving board, on the surface of the water), with initial speed equal to zero, as follows:\(\Delta y = \frac{1}{2}* g * t^{2} = 5.5 m (5)\)
Solving for t (which we will call t₂) in (5), we get:\(t_{2} = \sqrt{\frac{2*\Delta y}{g}} = \sqrt{\frac{2*5.5m}{9.8m/s2} } = 1.06 s (6)\)
The total time will be just the sum of (4) (since leaving the diving board till reaching the maximum height) and (6) (from there until she strikes the water), as follows:Δt = thmax + t₂ = 0.32 s + 1.06 s = 1.38 s (7)b)
In order to know the value of v₀, we need first to get the values of vox and voy.We know that the horizontal speed remains constant, so, if we know the total time traveled (same as in a)) and the horizontal distance (given), we can find v₀ₓ applying the definition of average velocity, as follows:\(v_{ox} =\frac{\Delta x}{\Delta t} =\frac{3.25m}{1.38s} = 2.36 m/s (8)\)
We know the value of v₀y from (2):\(v_{oy} = 3.13 m/s (9)\)
Applying the Pythagorean theorem, we can get the magnitude of v₀ as follows:\(v_{o} = \sqrt{v_{ox}^{2} + v_{oy}^{2}} = \sqrt{(2.36m/s)^{2} + (3.13m/s)^{2}} = 3.92m/s (10)\)
We can find the angle that it makes with the horizontal, applying the definition of tangent of an angle, as follows:\(tg_{(\theta o)} = \frac{v_{oy}}{v_{ox} } = \frac{3.13}{2.36} = 1.33 (11)\)
⇒ θ₀ = tg⁻¹ (1.33) = 53.1º
c)
In order to find the vertical component of the final velocity, we can use the following kinematic equation, for the total vertical displacement of 5.5 m since it started to fall after reaching to the maximum speed:\(v_{fy} ^{2} - v_{oy} ^{2} = 2* g* \Delta y (12)\)
When it started to fall, in the vertical direction, the diver was at rest, so in (12) we have v₀y = 0.Solving for vfy in (12) we get:\(v_{fy} = \sqrt{2*g*\Delta_{y} } = \sqrt{2*9.8m/s2*5.5m} = -10.4 m/s (13)\)
We already know that the horizontal component is the same as the initial v₀ₓ, so we can find the magnitude of the final velocity applying the Pythagorean Theorem as follows:\(v_{f} = \sqrt{v_{fx}^{2} + v_{fy}^{2}} = \sqrt{(2.36m/s)^{2} + (-10.4m/s)^{2}} = 10.7 m/s (14)\)
Finally, as we did in (11) to find the angle that it makes with the horizontal, we can find θf as follows:\(tg_{(\theta f)} = \frac{v_{fy}}{v_{fx} } = \frac{-10.4}{2.36} = -4.41 (15)\)
⇒ θf = tg⁻¹ (-4.41) = -77.2º
What is the frequency of highly energetic ul-
traviolet radiation that has a wavelength of
124 nm?
The speed of light is 3 x 108 m/s.
Answer in units of Hz.
Answers
Frequency = (speed) / (wavelength)
Frequency = (3 x 10⁸ m/s) / (124 x 10⁻⁹ m)
Frequency = 2.42 x 10¹⁵ Hz
Analyze the circuit shown below in the figure below.
Solve with an equation(s) from the equation sheet.
Answers
The circuit is a series circuit since all of the components are connected in a single path.
The current that flows through each component is the same, and the voltage across each component is proportional to its resistance.
In this circuit, there are two resistors, R1 and R2, and a battery with an electromotive force (EMF) of E.
The voltage across each resistor can be determined using Ohm's law, which states that
V = IR,
where V is the voltage
I is the current
R is the resistance.
The total resistance of the circuit can be calculated using the formula:
R = R1 + R2.
Using Ohm's law, the current in the circuit can be found by dividing the voltage by the total resistance:
I = E / R
The voltage across each resistor can be found using
V1 = IR1 and V2 = IR2.
The total voltage of the circuit is equal to the sum of the voltages across each resistor
V = V1 + V2
Substituting the equations for V1 and V2 into the equation for V, we get;
V = I(R1 + R2)
Thus, we can use the following equations to solve for the different variables in the circuit:
R = R1 + R2
I = E / R
V1 = IR1
V2 = IR2
V = I(R1 + R2)
Using these equations, we can calculate the current, voltage, and power of the circuit.
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You have to lift a 15 kg object. What is your output force?
Using a lever, you push down 20 N to lift a 10 kg object.
A) Find the output force.
B) What is the input force?
C) How much does the ramp multiply your force?
You push with 10 N up a ramp to move a 40 N object to the top
of a table. By how much does the ramp multiply your force?
Answers
Answer:
Explanation:
A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:
Output force = Weight of object = m * g
where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:
Output force = 15 kg * 9.81 m/s^2 = 147.15 N
Therefore, the output force required to lift a 15 kg object would be 147.15 N.
B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.
C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:
Mechanical advantage = Output force / Input force = 40 N / 10 N = 4
So, the ramp multiplies your force by a factor of 4.
Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.
What is the strength of the electric force between two charges, each of charge + 1 C, separated by 1 cm?
Answers
ANSWER
EXPLANATION
By Coulomb's Law, the electric force is,
\(F=k\cdot\frac{q_1q_2_{}}{r^2}\)Where q₁ and q₂ are the amount of charge in each particle, r is the distance between them and k is the Coulomb's constant, whose value is about 9x10⁹ N*m²/C²
If a cyclist is traveling along a road due east at 12km/h and wind is blowing from south-west at 5km/h. find the velocity of the wind relative to the cyclist.
Answers
The velocity of the wind with respect to the cyclist is 9.173 m/s its direction is 67.33⁰ from the southeast.
What is Triangle law?It states that "when two vectors are represented in a direction and magnitude by two sides of a triangle in the same order then its results will be represented in magnitude and direction of the closing side of the triangle in the opposite order."
then the resultant will be calculated as:
R= \(\sqrt{F1^{2} +F2^{2} +2F1F2cos\alpha }\)
Here in the given question
F1= -12m/s because the wind is opposing the cyclist who is moving with 12m/s so its direction is now east to west.
F2=5m/s
here angle between the two vectors is =45 degrees
now resultant of the vectors are
Vwc=\(\sqrt{(-12^{2}+5^{2} -2*12*5cos(45) }\)
=9.173km/h
Its direction will be applying sine the law
\(\frac{sin(45)}{9.173} =\frac{sine(\alpha) }{12}\)
\(\alpha =\)67.67⁰
now \(\beta =180-75-67.67\)
=67.33⁰
Hence the velocity of wind w.r.t. cyclist is 9.173m/s and its direction is towards the southeast.
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An ideal gas initially at pressure P0, volume V0, and temperature T0 is taken through the cycle described in the figure below. (Assume n = 4 and m = 5.)
a) Find the net work done by the gas per cycle in terms of P0 and V0.
b)What is the net energy Q added to the system per cycle? (Use any variable or symbol stated above as necessary.)
c) Obtain a numerical value (kJ) for the net work done per cycle for 1.00 mol of gas initially at 0°C. Hint: Recall that the work done by the system equals the area under a PV curve.
Answers
The net work done per cycle for 1.00 mol of gas initially at 0°C is 4.88 kJ.
An isothermal process is a thermodynamic process in which the temperature of the system remains constant, while other state variables such as pressure and volume may change. An adiabatic process is a thermodynamic process in which there is no exchange of heat between the system and its surroundings, while other state variables such as pressure and volume may change.
a) The net work done by the gas per cycle is equal to the area enclosed by the cycle on the PV diagram. From the given figure, the cycle can be divided into two parts: the first part is an isothermal expansion from volume V0 to volume 5V0 and the second part is an adiabatic compression from volume 5V0 to volume V0.
For the isothermal expansion, the pressure decreases from P0 to P0/4. Using the equation for the work done during an isothermal process, the work done by the gas during this part of the cycle is:
W1 = nRT0 ln(5) = 4RT0 ln(5)
For the adiabatic compression, the pressure increases from P0/4 to P0. Using the equation for the work done during an adiabatic process, the work done by the gas during this part of the cycle is:
W2 = (P0V0^m/P0/4*(5V0)^m)^(1 - m)/1-m - (P0/4*(5V0)^m/P0/4)^(1 - m)/1-m = 4P0V0/3(1 - 1/5^(4/5))
The net work done by the gas per cycle is the sum of the work done in each part of the cycle:
W = W1 + W2 = 4RT0 ln(5) + 4P0V0/3(1 - 1/5^(4/5))
b) Since the cycle is closed, the net energy added to the system per cycle must be equal to the net work done by the gas per cycle:
Q = W = 4RT0 ln(5) + 4P0V0/3(1 - 1/5^(4/5))
c) To obtain a numerical value for the net work done per cycle for 1.00 mol of gas initially at 0°C, we need to substitute the appropriate values for R, T0, P0, V0, n, and m. Assuming the gas is an ideal gas, R = 8.314 J/mol K. At 0°C (273 K), the pressure of 1.00 mol of gas in a volume of V0 = 22.4 L (molar volume of ideal gas at STP) is P0 = 1 atm. Therefore,
W = 4(8.314 J/mol K)(273 K) ln(5) + 4(1 atm)(22.4 L)/3(1 - 1/5^(4/5))) = 4.88 kJ
Therefore, the net work done per cycle for 1.00 mol of gas initially at 0°C is 4.88 kJ.
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The following table lists the speed of sound in various materials. Use this table to answer the question.
Substance Speed (m/s)
Glass 5,200
Aluminum 5,100
Iron 4,500
Copper 3,500
Salt water 1,530
Fresh water 1,500
Mercury 1,400
Hydrogen at 0°C 1,284
Ethyl Alcohol 1,125
Helium at 0°C 965
Air at 100°C 387
Air at 0°C 331
Oxygen at 0°C 316
Sound will travel fastest in air at _____.
-5°C
0°C
10°C
15°C
Answers
Sound will travel fastest in air at 15°C.
Speed of sound in air
The speed of sound in air, given in the range of 100 degrees Celsius and 0 degree Celsius include;
Air at 100°C 387 m/s
Air at 0°C 331 m/s
From the date above, the speed of sound in air increases with increases in temperature. Thus, Sound will travel fastest in air at 15°C.
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A bowling sphere is sitting on the ground. One of your classmates
takes a mallet and gives a bowling sphere a brief push. A moment
after the push, which of the following forces act on the bowling
sphere? (choose all that apply)
- the force of gravity
- a normal force
- inertia
- the force of the push
Answers
normal force because it is perpendicular to the surface
The resistance of a wire of length 100cm and diameter 0.3m is found to be 30 ohm's.calculate:(1) resistivity (2) conductivity (3) what length of the wire will produce 5 ohm's resistance.
Answers
Hi there!
1)
We can use the following equation to solve for resistivity.
\(R = \frac{\rho L}{A}\)
R = Resistance (30 Ω)
ρ = Resistivity (? Ωm)
L = Length (100cm = 1 m)
A = Cross-sectional area of wire (r = 0.15m, A = πr², A = 0.0707 m²)
Rearrange the equation to solve for resistivity.
\(\rho = \frac{RA}{L}\\\\\rho = \frac{30 * 0.0707}{1} = \boxed{2.121 \Omega m}\)
2)
The conductivity of a resistor is equivalent to:
\(\sigma = \frac{1}{\rho}\)
σ = Conductivity (S/m)
ρ = Resistivity (2.121 Ωm)
Solve:
\(\sigma = \frac{1}{2.121} =\boxed{0.472 \frac{S}{m}}\)
3)
We can use the equation for resistivity to solve. Rearrange the equation for length:
\(R = \frac{\rho L}{A}\\\\L = \frac{AR}{\rho}\\\\L = \frac{0.0707 * 5}{2.121} = \boxed{0.167 m}\)
A 15 kg block rest on a surface of a smooth plane incline at an angle 30 degree to the horizontal. A light in extensible string passing over a small Smooth Pulley at the top of the plane connect to the block to another 13/kg block hanging freely. find the acceleration of the resulting motion and the tension in the string.
If the coeficient of kinetic friction between the plane and the 15kg mass is 0.25. find the acceleration of the resulting motion
Answers
The acceleration of the system is 2.77 m/s² and the tension in the string is 127.4 N, given the provided values.
Given: Mass of the first block (m1) = 15 kgMass of the second block (m2) = 13 kgAngle of the plane (θ) = 30°Coefficient of kinetic friction (μk) = 0.25, Acceleration of the resulting motion (a) = ? Tension in the string (T) = ?First, we need to resolve the weight of the first block into its components perpendicular to and along the plane. Then we can use the component parallel to the plane to find the force of friction acting on the first block. We can then use the net force acting on the first block to find its acceleration. Finally, we can use the acceleration of the first block to find the tension in the string.Resolving the weight of the first block into components parallel to the plane: m1gsinθ = 15 x 9.8 x sin30° = 73.5 N. Perpendicular to the plane: m1gcosθ = 15 x 9.8 x cos30° = 127.5 N. Finding the force of friction acting on the first block: μk = coefficient of kinetic friction = 0.25f = force of friction acting on the first block N = normal force acting on the first block N = perpendicular force acting on the first block = 127.5 Nf = μkN = 0.25 x 127.5 = 31.88 NThe net force acting on the first block:F = maF = m1aF = m1g sinθ - fF = 15 x 9.8 x sin30° - 31.88F = 73.5 - 31.88F = 41.62 N. Acceleration of the first block: a = F/m1a = 41.62/15a = 2.77 m/s². Finding the tension in the string: The tension in the string is the force acting on the second block. We can use the weight of the second block and the acceleration of the first block to find the tension.T - m2g = m1aT = m2g + m1aT = 13 x 9.8 + 15 x 2.77T = 127.4 NTherefore, the acceleration of the resulting motion is 2.77 m/s² and the tension in the string is 127.4 N.For more questions on acceleration
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An insect crawls 4 m east along a hiking path in
20 seconds, and then a bird swoops down and eats it. What was the insect's velocity?
Answers
The insect's velocity is 0.2 meter/second along east.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given parameters:
An insect crawls 4 m east along a hiking path.
Time taken by it: t = 20 seconds.
We have to fine: the insect's velocity, v =?
So, the magnitude of velocity: v= 4/20 meter/second = 0.2 meter/second.
And the direction velocity is along east.
Hence, the insect's velocity is 0.2 meter/second along east.
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Water flows steadily from an open tank as shown in the figure. (Figure 1)The elevation of point 1 is 10.0 m , and the elevation of points 2 and 3 is 2.00 m . The cross-sectional area at point 2 is 4.80×10−2 m2 ; at point 3, where the water is discharged, it is 1.60×10−2 m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe. What is the gauge pressure p_gauge at point 2?
Answers
The gauge pressure at point 2 is 98100 Pa or 9.81 x\(10^4\) Pa, which is equivalent to 6.97 x\(10^4\) Pa when rounded to two significant figures.
Step 1: Identification of the given data:
- Elevation at point 1 (h1) = 10.0 m
- Elevation at points 2 and 3 (h2 = h3) = 2.00 m
- Cross-sectional area at point 2 (A2) = 0.0480 \(m^2\)
- Cross-sectional area at point 3 (A3) = 0.0160 \(m^2\)
Step 2: Determination of the discharge rate:
As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.
Therefore, the discharge rate is 0 cubic meters per second.
Step 3: Determination of the gauge pressure at point 2:
To find the gauge pressure at point 2, we'll use Bernoulli's equation:
P1 + (1/2)ρ\(v1^2\) + ρgh1 = P2 + (1/2)ρ\(v2^2\) + ρgh2
Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ\(v2^2\) can be ignored.
The equation simplifies to:
Patm + ρgh1 = P2 + ρgh2
We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:
\(P_g_a_u_g_e\) = P2 - Patm
Now let's substitute the given values into the equation:
\(P_g_a_u_g_e\) = (Patm + ρgh1) - Patm
\(P_g_a_u_g_e\) = ρgh1
Plugging in the values:
\(P_g_a_u_g_e\) = (1000 kg/m^3) * (9.81 \(m/s^2\)) * (10.0 m)
\(P_g_a_u_g_e\) = 98100 Pa
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27 1 point
A student has tested several types of wood for density. The best way of presenting this information graphically would be to use which item?
Scatterplot
Pie Chart
Line Graph
Bar Graph
Previous
Search
Answers
The best way of presenting the information on density graphically would be to use a D, bar graph.
What is a bar graph?A bar graph is a type of chart that uses rectangular bars to represent data. The bars are typically arranged in columns, with the independent variable (in this case, the type of wood) on the x-axis and the dependent variable (in this case, the density) on the y-axis.
A bar graph is the best choice for this data because it allows for easy comparison of density of different types of wood. We can see at a glance which type of wood is the densest and which type of wood is the least dense.
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what's a beam of light?
Answers
Answer: If you aim a Prisma in the light it will have every color
Explanation:
A cell contains 20% solute. If it is placed in a solution with 35% solute, what will happen to the cell?
Answers
What force prevents a machine from having 100% efficiency? A. Magnetic B. Electric O C. Friction O D. Gravity
Answers
Answer:
I believe it would be C ? my apologies if I'm wrong.
Do you think the "energy" used by people and the energy used by cars is the same thing? Why or why not? *
Answers
Answer:No
Explanation:Because car use the energy produced by the car battery and humans get energy from the food they eat
How long will it take an object to accelerate from a velocity of 4.8 m/s to a velocity of 15.6 m/s if it is accelerating at a rate of 0.9 m/s2
Answers
Initial velocity of the object (u) = 4.8 m/s
Final velocity of the object (v) = 15.6 m/s
Acceleration of the object (a) = 0.9 m/s²
By using equation of motion, we get:
\( \bf \longrightarrow v = u + at \\ \\ \rm \longrightarrow 15.6 = 4.8 + 0.9t \\ \\ \rm \longrightarrow 15.6 - 4.8 = 4.8 - 4.8 + 0.9t \\ \\ \rm \longrightarrow 10.8 = 0.9t \\ \\ \rm \longrightarrow 0.9t = 10.8 \\ \\ \rm \longrightarrow \dfrac{0.9}{0.9} t = \dfrac{10.8}{0.9} \\ \\ \rm \longrightarrow t = 12 \: s\)
\( \therefore \) Time taken by the object (t) = 12 s
18.
As air temperature decreases, the speed of sound in air decreases.
True
False
Answers
Answer:
True
the velocity of sound in air decreases with decrease in temperature.
what is a likely consequence of continued human population growth
Answers
Answer:
Rapid human population growth has a number of consequences. Population grows fastest in the world's poorest countries. High fertility rates have historically had a strong relation with poverty, and high childhood mortality rates
Explanation:
i got it from goo.gle but i hope that helps:)
have a good day bro
When Simon grows (let’s say he doubles his mass) what happens to his GPE when he is at the balcony?
Answers
Answer:
His gravitational potential energy will increase as well.
Explanation:
Let gpe represent gravitational potential energy.
gpe = mass × gravitational field strength × height
From the formula above, we can conclude that as the mass of a body increases, it's gpe increases too.
You want to double the radius of a rotating solid sphere while keeping its kinetic energy constant. (The mass does not change.) To do this, the final angular velocity of the sphere must be Group of answer choices
Answers
The Final angular velocity of the sphere is : Half of its initial value ( W/2 )
Kinetic energy of a rotating body
Given that The kinetic energy of a rotating body ( K ) = 1/2 IW² --- ( 1 )
where : I = moment of inertia, w = angular velocity
I = \(\frac{2}{5} MR^{2}\)
Therefore equation ( 1 ) becomes
K = \(\frac{1}{5}MR^2W^2\) ----- ( 2 )
After doubling the radius
R' = 2R
K' = K
Mass = unchanged
therefore :
\(\frac{1}{5}MR'^2W'^2 = \frac{1}{5}MR^2W^2\)
= ( 2R )² W'² = R²W²
Resolving equation above
Hence : W' ( new angular velocity ) = W / 2
In conclusion The Final angular velocity of the sphere is : Half of its initial value ( W / 2).
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
Answers
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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a healthy person has a body temperature of 37 degree celsius. if they jump into an ice bath after sports training their temperature only decreases slowly. how can you explain this when a lump of metal at 37 celsius degree placed in the same ice bath cools down to 0 celsius degree in only a couple of minutes
Answers
1. Heat Capacity: The heat capacity of the human body is much higher than that of a small lump of metal. The human body has a large mass and contains a significant amount of water, which has a high heat capacity. This means that it requires more energy to change the temperature of the body compared to a small metal object. As a result, the body cools down more slowly in the ice bath.
2. Insulation: The human body is well-insulated with layers of skin, fat, and clothing. These layers act as thermal barriers and slow down the transfer of heat between the body and the surroundings. On the other hand, a small metal object does not have any significant insulation, allowing heat to transfer more rapidly to the colder environment.
3. Biological Regulation: The human body has mechanisms to regulate its temperature, such as vasoconstriction (narrowing of blood vessels) and shivering, which help generate heat and maintain core temperature. These regulatory processes help to slow down the cooling process and preserve the body's temperature within a narrow range.
4. Surface Area-to-Volume Ratio: The surface area-to-volume ratio is higher for a small lump of metal compared to a human body. A higher surface area facilitates faster heat transfer. Since the metal object has a relatively larger surface area compared to its volume, it cools down more quickly in the ice bath.
Overall, the combination of the human body's higher heat capacity, insulation, biological regulation, and lower surface area-to-volume ratio compared to a small metal object contributes to the slower cooling rate when immersed in an ice bath.
An object of volume 0.0004m^3 and density 6000kg/m^3 is immersed inside a fluid of density 5000kg/m^3. The force exerted by the fluid on the object is 0.7N. Calculate the density of the fluid.
Answers
We have that the density of the fluid is
\(\rho_f=178.57 kg/m3\)
From the question we are told that
object of volume 0.0004m^3
density 6000kg/m^3
fluid of density 5000kg/m^3.
Force F=0.7N
Generally the equation for the Force is mathematically given as
\(F= v*\rho_f*g\\\\0.7= 0.0004*\rho_f*9.8\\\\\rho_f=\frac{0.7}{0.0004*9.8}\)
\(\rho_f=178.57 kg/m3\)
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13. List the general strengths and weaknesses of epidemiology for providing an answer to Mary Beth’s question.
14. List the specific strengths and weaknesses of this study.
15. List the general strengths and weaknesses of toxicology for providing an answer to Mary Beth’s question.
Answers
The general strengths of epidemiology for providing an answer to Mary Beth’s question.
epidemiology can study a large populationepidemiology can identify patterns and trends in health and diseaseepidemiology can be used to study different diseases and health conditionsThe general weaknesses of epidemiology for providing an answer to Mary Beth’s question:
epidemiology may not provide a definitive answer or explanationepidemiology results may be affected by biases and confounding variablesThe Specific strengths of a study:
Big sample sizeLengthy follow-up periodThe specific weaknesses of a study are :
Use of self-recorded data, which may be inaccurate or biasedBiased selection due to non-random samplingWhat is epidemiology?Epidemiology is described as the study and analysis of the distribution, patterns and determinants of health and disease conditions in a defined population.
The main objective of epidemiology has been said is to find out what causes different health outcomes in different groups of people.
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If you put a leash on a 12kg cat and try to take it for a walk, it will not be happy. Eventually it will refuse to walk and you will have to drag it home. If you are dragging the cat with a horizontal force of 55 N and the coefficient of friction between the cat and the grass is 0.3. What is the Acceleration of the cat
Answers
Answer: \(1.64 m/s^{2}\) (3 sig figs)
\(1.6 m/s^{2}\) (2 sig figs)
Explanation:
First we need to find the weight of the cat using F=ma (117.72 = 12 * 9.81)
Using 117.72 we can find the force of friction by doing F = μ * N (35.316 = 0.3 * 117.72)
After we find the friction force we simply subtract the friction force from the applied force (19.684 = 55 - 35.316)
Using 19.684 we can find the acceleration using F / m = a (19.684 / 12 = 1.64)
From there you reduce your answer to the number of sig figs, which I think is 2 unless otherwise specified.
What is the formula for Angular velocity?
Answers
Answer:
The formulas are down below
Explanation:
\(w = \frac{o}{t} \)
From V=rw
\(w = \frac{v}{r} \)