D
Learning Task : Read the statement below, draw THUMBS UP ($) if you agree
with the statement and THUMBS DOWN ( P )if not. Explain the reason for your
answer. Do this activity in your answer sheet.
1. Mom and Dad provide my basic needs.
2. Security is the priority of my parents.
3. Parents give love and care to their children.
4. We live under the bridge because our parents are jobless.
5. I get what I want from my parents.​

The volume of hydrogen (H₂) which will be produced at Standard Temperature and Pressure (STP) is 1.254 liter.

To determine the volume of hydrogen gas that would be produced in this reaction, we need to know the balanced equation for the reaction of potassium with water. The balanced equation for the reaction of potassium with water is:

2 K + 2 H₂O → 2 KOH + H₂

From the equation above, we can see that for every 2 moles of potassium that react, 1 mole of hydrogen gas is produced. The molar mass of potassium is 39.098 g/mol and molar volume of H₂ at STP is 22.4 L/mol

To calculate the volume of hydrogen gas produced at STP, we need to convert the mass of potassium (2.18 g) to moles. This is done by dividing the mass by the molar mass of potassium (39.098 g/mol).

2.18 g / 39.098 g/mol = 0.056 moles

Use the balanced equation to determine how many moles of hydrogen gas are produced per mole of potassium. In this case, the balanced equation tells us that 1 mole of hydrogen gas is produced per 2 moles of potassium. Multiply the number of moles of potassium (0.056 moles) by the moles of hydrogen produced per mole of potassium (1 mole/2 moles) to find the number of moles of hydrogen produced.

0.056 moles × (1 mole / 2 moles) = 0.028 moles

Calculate the volume of hydrogen gas produced at STP using the molar volume of hydrogen gas (22.4 L/mol) and the number of moles of hydrogen gas calculated above.

0.028 moles × 22.4 L/mol = 0.628 L

Therefore the volume of hydrogen (H₂) which will be produced at Standard Temperature and Pressure (STP) is 0.628 liter.

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3a. The mass concentration of H2O in the air when mole fraction of water in the air is 2 percent at P=1 atm at 15 ∘C is 13.5 g/m³.

3b. The mass concentration of oxygen atoms in this gas is 1909.85 μg/m³.

3a. Given: Mole fraction of water in the air = 2%

Pressure, P = 1 atm

Temperature, T = 15 ∘C

We can find the mass concentration of H2O using the formula:

mass concentration = (partial pressure of H2O) / (RT) x MW x 1000

Where, R = 0.0821 L atm mol-1 K-1

T = 15 + 273 = 288 KMW of H2O = 18 g/mol

The partial pressure of H2O can be calculated using Dalton's law of partial pressure:

P H2O = mole fraction of H2O x total pressure

= 0.02 x 1 atm

= 0.02 atm

Substitute the values into the mass concentration equation:

mass concentration = (0.02 atm) / (0.0821 L atm mol-1 K-1 × 288 K) × (18 g/mol) × 1000

= 13.5 g/m³

Therefore, the mass concentration of H2O in the air when mole fraction of water in the air is 2 percent at P=1 atm at 15 ∘C is 13.5 g/m³.

3b. Given:

Pressure, P = 1 atm

Temperature, T = 15 ∘C

We need to find the mass concentration of oxygen atoms in this gas. For this, we first need to find the mole fraction of oxygen. We can use the following formula:

mole fraction of oxygen = 1 - (mole fraction of water + mole fraction of other gases)

Mole fraction of water = 2/100 = 0.02

Mole fraction of other gases = 1 - mole fraction of water

= 1 - 0.02

= 0.98

At standard conditions, 1 mole of gas occupies 22.4 L.

But at given conditions (P=1 atm and T=15 ∘C),

the volume occupied by 1 mole of gas can be found using the following equation:

PV = nRTV = (nRT) / PM

where, V = volume of 1 mole of gas

n = number of moles of gas

R = universal gas constant = 0.0821 L atm mol-1 K-1

T = 15 + 273 = 288 K

Now, we can find the number of moles of oxygen atoms using the following formula:

number of moles of oxygen atoms = (mass concentration of other gases) / (MO of O2)

Where, MO of O2 = 32 g/mol

Now, we can calculate the mass concentration of oxygen atoms using the following formula:

mass concentration of oxygen atoms = (number of moles of oxygen atoms) × (MO of O2) × (1000 μg/mg) / (volume of 1 mole of gas)

Substitute the values into the above equations:

V = (1 × 0.0821 × 288) / 1

= 23.74 L/mol

Number of moles of oxygen atoms = (0.98) / (32 g/mol)

= 0.030625 mol

Mass concentration of oxygen atoms = (0.030625 mol) × (32 g/mol) × (1000 μg/mg) / (23.74 L/mol)

= 1909.85 μg/m³

Therefore, the mass concentration of oxygen atoms in this gas is 1909.85 μg/m³.

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Answer:

33 minutes

Explanation:

60 km/h = 37.28 mi/h

20/37.28 = 0.5364 h

0.5364 * 60 min = 32.2 minutes

The female part is the pistil. The pistil usually is located in the center of the flower and is made up of three parts: the stigma, style, and ovary. The stigma is the sticky knob at the top of the pistil. It is attached to the long, tube like structure called the style.

Answer:

These are largely the result of human reliance on fossil fuels and heavy industry, but can also be due to the accumulation of waste, modern agriculture, and other man-made processes. The combustion of fossil fuels like coal, petroleum and other factory combustibles is a major cause of air pollution

Answer:

If you increase the pressure of a reaction that involves gas molecules, the equilibrium will shift towards the side with fewer gas molecules to relieve the stress of the increased pressure.

In this case, the reaction has 4 moles of gas molecules on the left side (1 mole of N2 and 3 moles of H2) and 2 moles of gas molecules on the right side (2 moles of NH3). Therefore, the equilibrium will shift towards the right to decrease the number of gas molecules and relieve the stress of the increased pressure.

The main difference between substrate level phosphorylation and oxidative phosphorylation is that substrate level phosphorylation is a direct phosphorylation of ADP with a phosphate group by using the energy obtained from a coupled reaction whereas oxidative phosphorylation is the production of ATP from the oxidized ...

Answer:

the bike is moving at a speed of 0.115810 mph

The solubility product is 4n³.

The equilibrium constant for a solid's dissolving into an aqueous solution is called the solubility product constant. It is represented as K(sp).

A solution is said to be saturated when it has dissolved all of the solutes it can. At a certain temperature, no additional solute can dissolve in a saturated solution.

Consider the equilibrium for a saturated PbCl₂ aqueous solution.

PbCl₂(s) ⇄⇄ Pb₂ (aq) + 2Cl⁻ (aq)

The equilibrium constant for the dissociation reaction of the PbCl₂ solution is:

K(sp) = [Pb²⁺] [Cl⁻]²

Now, [Pb²⁺] = n mol/L

In the solution, there is one-mole Pb²⁺ and two moles of Cl⁻ .

Therefore,

[Cl⁻] = 2n mol/L

So, the equilibrium constant for the dissociation reaction will be:

K(sp) = [Pb²⁺] [Cl⁻]²

K(sp) = n × (2n)²

K(sp) = n × 2n × 2n

K(sp) = 4n³

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0Answer: 0.6094

Explanation:

no of moles = mass / molar mass = 100/164.088= 0.6094 mole

Answer:

0.609 moles

Explanation:

mass in g ÷ atomic mass = moles

Ca(NO₃)₂ = 1 Ca 40.078 amu

2 N 28.0134 amu

+ 6 O 95.994 amu

____________________

164.0854 amu

100 g ÷ 164.0854 amu = 0.609 moles

three significant digits

The molarity of the NaOH solution is 0.0754 M. Answer: 0.0754 M.

Molarity can be defined as the number of moles of solute present in per liter of solution. To calculate the molarity of the NaOH solution, we need to use the given information. Given that 35.22 mL of NaOH solution completely neutralizes a solution containing 0.544 g of KHP.We can use the formula for molarity:

Molarity = (mass of solute / molar mass of solute) / volume of solution in L

First, we need to calculate the number of moles of KHP.Number of moles of KHP = mass of KHP / molar mass of KHP

Number of moles of KHP = 0.544 / 204.22 = 0.00266 mol

Now, we can use the balanced chemical equation for the reaction between NaOH and KHP:

NaOH + KHC8H4O4 → KNaC8H4O4 + H2O

From the equation, we can see that one mole of NaOH reacts with one mole of KHP. Therefore, the number of moles of NaOH used in the reaction is also 0.00266 mol.Since the volume of the NaOH solution used is 35.22 mL, we need to convert it into liters.Volume of NaOH solution used = 35.22 mL = 0.03522 L

Now we can calculate the molarity of the NaOH solution:

Molarity = number of moles / volume of solution

Molarity = 0.00266 / 0.03522

Molarity = 0.0754 M

Therefore, the molarity of the NaOH solution is 0.0754 M. Answer: 0.0754 M.

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Answer:

In the same phase

Explanation:

Because when you make a solution you have to keep them in the same phase or you will oof.

Answer:

i do not uterstand

Explanation:

Answer:

Word equation carbon + oxygen → carbon dioxide

Chemical equation C + O2 → CO2

The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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Answer:

Hmm 65

Explanation:

Dimethylsulfoxide has the formula C2H6SO.Therefore, the correct answer is option D: 25.4.

Option D.

To determine the mass percent of carbon in this compound, we need to calculate the molar mass of the compound first. Molar mass is the sum of the atomic masses of all the atoms in the molecule. We can use the periodic table to obtain the atomic masses. For this compound, the molar mass will be:2 (atomic mass of carbon) + 6 (atomic mass of hydrogen) + 32 (atomic mass of sulfur + 16 (atomic mass of oxygen) = 78 g/molNext, we need to determine the mass of carbon in one mole of the compound. We can do this by multiplying the number of carbon atoms by the atomic mass of carbon. In this case, there are 2 carbon atoms in one mole of the compound. Therefore, the mass of carbon in one mole of the compound is:2 (number of carbon atoms) x 12.01 (atomic mass of carbon) = 24.02 g/molFinally, we can calculate the mass percent of carbon in dimethylsulfoxide using the formula:mass percent of carbon = (mass of carbon / total molar mass) x 100%Substituting the values we obtained:mass percent of carbon = (24.02 g/mol / 78 g/mol) x 100% = 30.77%Rounding to three significant figures gives us a final answer of 30.7%.

Option D.

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Answer:

cilicon 14

Explanation:

Answer:

Cold

Explanation:

Because 0°C And below or 32°F Refers To Cold Weather

Answer:

Mg (NO3)2+ K2CO3 ⇒ Mg CO3 + KNO3

Mg=1 ,N =2, O =6 +3 9 ,K =2 ,C=1 ,  (reactant side)

Mg =1, C = 1  ,O = 3+3 = 6 , K= 1., N =1 (product side)

Mg(NO3)2 + K2CO3  ⇒ Mg CO3 + 2KNO3

Mg =1 , C = 1, O =3+6=9, K = 2 IN product side

ANS:

Mg (NO3)2 +K2CO3 ⇒ MgCO3 +2 KNO3

Explanation:

Answer:

533.12 L

Explanation:

The balanced chemical equation for the decomposition of CaCO₃ is the following:

CaCO₃(s) → CaO(s) + CO₂(g)

According to the equation, 1 mol of CaCO₃ produces 1 mol of gas (CO₂). We convert the moles of CaCO₃ to mass in grams with the molar mass of the compound:

molar mass CaCO₃ = 40 g/mol Ca + 12 g/mol C + (3 x 16 g/mol O)= 100 g/mol

mass of CaCO₃ = 1 mol x 100 g/mol = 100 g CaCO₃

Now, we know that 1 mol of any gas at STP occupies a volume of 22.4 L:

1 mol CO₂ = 22.4 L CO₂

Thus, the stoichiometric ratio is: 22.4 L CO₂/100 g CaCO₃

Finally, we multiply this ratio by the mass of CaCO₃ to calculate how many liters of CO₂ at STP are produced:

2380 g CaCO₃ x 22.4 L CO₂/100 g CaCO₃ = 533.12 L

The 533.12 L of carbon dioxide will be produced at STP if 2380 g of calcium carbonate reacts completely.

The balanced chemical equation for the decomposition of CaCO₃ is the following:

CaCO₃(s) → CaO(s) + CO₂(g)

A balanced chemical reaction is an equation that has equal numbers of each type of atom on both sides of the arrow.

According to the equation, 1 mol of CaCO₃ produces 1 mol of gas (CO₂).

We need to convert the moles of CaCO₃ to mass in grams with the molar mass of the compound:

Molar mass CaCO₃ = 100 g/mol

Mass of CaCO₃ = 1 mol x 100 g/mol = 100 g CaCO₃

Now, we know that 1 mol of any gas at STP occupies a volume of 22.4 L:

1 mol CO₂ = 22.4 L CO₂

Thus, the stoichiometric ratio is:  

\(\frac{22.4 L\; CO_{2} }{100 g \;CaCO_3 }\)

Finally, we multiply this ratio by the mass of CaCO₃ to calculate how many liters of CO₂ at STP are produced:

2380 g CaCO₃ x 22.4 L CO₂/100 g CaCO₃

= 533.12 L

Hence, the 533.12 L of carbon dioxide will be produced at STP if 2380 g of calcium carbonate reacts completely.

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The abbreviation "DTMP" is not commonly possible as it is not a recognized abbreviation for a nucleotide. The correct abbreviation for thymidine monophosphate is "TMP".

The following abbreviations for a nucleotide is not commonly possible: A) CMP, B) AMP, C) DGMP, D) dUMP, E) DTMP. The abbreviation that is not commonly possible is C) DGMP. Here's an explanation for each abbreviation:

A) CMP - Cytidine monophosphate: a common nucleotide
B) AMP - Adenosine monophosphate: a common nucleotide
C) DGMP - Deoxyguanosine monophosphate: not commonly possible because the correct abbreviation is dGMP (deoxyguanosine monophosphate)
D) dUMP - Deoxyuridine monophosphate: a common nucleotide
E) DTMP - Deoxythymidine monophosphate: a common nucleotide

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Answer:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

Explanation:

hope that helps

The ionization constant of the acid is 0.00072

The ionization constant (Ka) of the monoprotic acid can be calculated using the equation:

Ka = ([H+][A-])/[HA]

where [H+] is the concentration of hydrogen ions, [A-] is the concentration of the conjugate base, and [HA] is the initial concentration of the acid.

We know that the acid is 12 percent ionized, which means that only 12 percent of the initial concentration of the acid has ionized into hydrogen ions and the conjugate base.

Therefore, the concentration of hydrogen ions and the conjugate base can be calculated using the following equations:

[H+] = 0.12 x 0.038 M = 0.00456 M
[A-] = 0.12 x 0.038 M = 0.00456 M

The initial concentration of the acid ([HA]) can be calculated by subtracting the concentration of hydrogen ions and the conjugate base from the initial concentration of the solution:

[HA] = 0.038 M - 0.00456 M - 0.00456 M = 0.02888 M

Substituting these values into the equation for Ka, we get:

Ka = (0.00456 M)2 / 0.02888 M = 0.00072

Therefore, the ionization constant (Ka) of the monoprotic acid is 0.00072.

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Given that ionization constant of water (Kw) at 40°C is 2.9x10^-14 .

We need to calculate H3O+, OH-, pH and pOH for pure water at 40°C.

The ionization of water can be given as:

2H2O ⇌ H3O+ + OH-Kw = [H3O+][OH-]

Putting the values:Kw = [H3O+][OH-]2.9x10^-14 = [H3O+][OH-]

Let [H3O+] = [OH-]= x

∴ Kw = x2∴ x = √2.9x10^-14x = 1.7x10^-7mol/L

Hence, [H3O+] = [OH-] = 1.7x10^-7mol/LpH = -log[H3O+]pH = -log(1.7x10^-7)pH = 6.7689pOH = -log[OH-]pOH = -log(1.7x10^-7)pOH = 6.7689

Therefore, pH and pOH of pure water at 40°C are 6.7689.

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Answer:

iodine

Explanation:

To determine the concentration of NaOH in the resulting solution, we need to calculate the number of moles of NaOH and then divide it by the volume of the solution. The given mass of NaOH and the volume of the flask can be used to find the concentration.

The concentration of a solution is defined as the amount of solute (in moles) divided by the volume of the solution (in liters). In this case, we are given the mass of NaOH as 36.0 g and the volume of the volumetric flask as 500.0 mL (which can be converted to liters by dividing by 1000).

To find the number of moles of NaOH, we divide the given mass by the molar mass of NaOH. The molar mass of NaOH is 40.00 g/mol. By dividing 36.0 g by 40.00 g/mol, we can determine the number of moles of NaOH.

Once we have the number of moles of NaOH, we divide it by the volume of the solution (500.0 mL or 0.500 L) to obtain the concentration in moles per liter (M).

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A silicon chip used in an integrated circuit of a computer has a mass of 0.692 cg then there are approximately 1.635 × 10^20 silicon atoms in the chip.

First, we need to convert the mass of the silicon chip from centigrams to grams:

0.692 cg = 0.00692 g

The molar mass of Si is 28.0855 g/mol, which means that 1 mole of Si contains 6.022 × 10^23 atoms.

We can use dimensional analysis to calculate the number of Si atoms in the chip:

0.00692 g Si × (1 mol Si / 28.0855 g Si) × (6.022 × 10^23 atoms Si / 1 mol Si) = 1.635 × 10^20 atoms Si

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