a) The horizontal component of initial velocity is 2.722 m/s.b) The vertical component of initial velocity is 2.023 m/s.c) The maximum height of the motion is 0.982 m.d) The landing location on carbon paper is 1.746 m.
Projectile motion is the path of an object through the air when it's acted upon by gravity. It's described as a two-dimensional motion since the object is moving in two directions. It has horizontal and vertical components, and each component is independent of the other. It can be calculated with the help of horizontal and vertical components of initial velocity, time, and acceleration due to gravity.
Projectile motion can be studied with the help of a Pasco projectile launcher, and it involves finding the horizontal component of initial velocity, vertical component of initial velocity, maximum height of the motion, and the landing location on carbon paper.a) To find the horizontal component of initial velocity, we can use the following formula:v₀ = v₀ cos(θ₀)Where v₀ is the initial velocity, and θ₀ is the initial angle. We're given:v₀ = 3.4 m/sθ₀ = 37°.
Therefore:v₀ = 3.4 cos(37°)v₀ ≈ 2.722 m/sThe horizontal component of initial velocity is 2.722 m/s. (to two significant figures)b) To find the vertical component of initial velocity, we can use the following formula:v₀ = v₀ sin(θ₀)Where v₀ is the initial velocity, and θ₀ is the initial angle. We're given:v₀ = 3.4 m/sθ₀ = 37°Therefore:v₀ = 3.4 sin(37°)v₀ ≈ 2.023 m/sThe vertical component of initial velocity is 2.023 m/s. (to two significant figures)c) To find the maximum height of the motion, we can use the following formula:y = H + v₀² sin²(θ₀) / 2gWhere H is the initial height, v₀ is the initial velocity, θ₀ is the initial angle, and g is the acceleration due to gravity.
We're given:H = 33.5 in = 0.8509 mv₀ = 3.4 m/sθ₀ = 37°g = 9.81 m/s²Therefore:y = 0.8509 + (3.4² sin²(37°)) / (2 x 9.81)y ≈ 0.982 mThe maximum height of the motion is 0.982 m. (to two significant figures)d) .
To find the landing location on carbon paper, we can use the following formula:x = v₀ cos(θ₀) tWhere v₀ is the initial velocity, θ₀ is the initial angle, and t is the time taken. The time taken can be calculated with the help of the following formula:y = H + v₀ sin(θ₀) t - 1/2 g t²Where H is the initial height, v₀ is the initial velocity, θ₀ is the initial angle, and g is the acceleration due to gravity. We're given:H = 33.5 in = 0.8509 mv₀ = 3.4 m/sθ₀ = 37°g = 9.81 m/s²We can convert the initial height into meters:0.8509 m = 2.79 ftv₀y = v₀ sin(θ₀) = 2.023 m/st = v₀y / g + sqrt(2gh) / gWe can plug in the values: t = 2.023 / 9.81 + sqrt(2 x 9.81 x 0.8509) / 9.81t ≈ 0.421 sThe time taken is 0.421 seconds. (to three significant figures).
Now we can find the landing location:x = v₀ cos(θ₀) tWhere v₀ is the initial velocity, θ₀ is the initial angle, and t is the time taken. We're given:v₀ = 3.4 m/sθ₀ = 37°t = 0.421 sTherefore:x = 3.4 cos(37°) x 0.421x ≈ 1.746 mThe landing location on carbon paper is 1.746 m. (to three significant figures)
Answer:a) The horizontal component of initial velocity is 2.722 m/s. (to two significant figures)b) The vertical component of initial velocity is 2.023 m/s. (to two significant figures)c) The maximum height of the motion is 0.982 m. (to two significant figures)d) The landing location on carbon paper is 1.746 m. (to three significant figures)
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what sound characteristics can be compared between the two ears to locate the source of a sound? group of answer choices sound shadows and pitch loudness and phase frequency and loudness we cannot localize sounds well
Intensity and time interval of a sound can be compared between the two ears to locate the source of a sound.
Intensity of the sound is defined as the proportion of energy that flows per unit time through a unit area perpendicular to the direction of motion of such sound waves.
The time it takes for a sound wave to complete one cycle is called its time interval or the time period.
The time period is inversely proportional to the frequency and is given by: Time period = 1/FrequencyA person's loudness perception is affected by the amount of sound they hear.
The volume or loudness of a sound is determined by its intensity, which itself is governed by its frequency. Sounds are measured by their intensity or the energy they have in them. Intensity is measured in decibels (dB) and the volume of sounds is determined by their intensity. The intensity of sound is determined by two factors: the size of the sound waves and the distance from their source.and the time taken by the sound wave to reach the ear is dependent on the distance between the source and the ear.Therefore intensity and time interval can be considered as the sound characteristics to compare between the two ears to locate the source of a sound.
The question is incomplete, the complete question is:
'What sound characteristics can be compared between the two ears to locate the source of the sound?
a. sound shadows and frequency
b. frequency and amplitude
c. intensity and time of arrival
d. timbre and rhythm'
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What are the five types of contact forces?
Answer:
Applied force
Normal force
Frictional force
Tension force
Wind force
Answer: Reaction force. An object at rest on a surface experiences reaction force .
Tension. An object that is being stretched experiences a tension force.
Friction. Two objects sliding past each other experience friction forces. ...
Air resistance. An object moving through the air experiences air resistance .
Gravitational Force.
Explanation:
The distance of east-west highway is 1.030 x 10^6m. How much is the value of mantissa in this number?
(a) 1.030
(b) 0.030
(d) 6
(c) 10
The mantissa distance, which is referred to as the decimal portion of a logarithm, has a value of 0.030 in this number.
Is the decimal portion of a number's logarithmic value referred to as the mantissa?A common logarithm's integral portion is known as the characteristic, and its non-negative decimal portion is known as the mantissa. If log 39.2 equals 1.5933, then 1 is the characteristic and 5933 is the logarithm's mantissa.
What is the number's logarithmic mantissa?The base-10 logarithm's mantissa, which represents the digits of the provided integer but not its magnitude, is a common logarithm's fractional component. For instance, both ㏒10201.3010 and ㏒102002.3010 have a mantissa of 0.3010.
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what metal can you melt using 1000 degress celcius
If you'll looking for a metal that melts at exactly 1000 degrees celcius, then Red Brass melts at exactly 1000 degrees celcius
Surfaces on the same body are assumed to experience meteorite impacts with the same frequency. If this is true, what could account for the stark contrast in impact crater density on bordering regions of Ganymede in the photo?
Answer:
The surface with fewer impact craters is a newer surface. It hasn’t been impacted as many times as the older surfaces
Explanation:
Sample Answer
Answer:
Newer surfaces are less damaged by impact craters, because they are less damaged by impact.
Explanation:
This is my answer.
please no irrelevant answers!
Light enters a glass block at an angle of incidence of 46°. The light refracts at an angle of refraction of 26°. What is the refractive index of the glass?
A 0.57
B 0.61
C 1.64
D 1.77
Answer:
Choice C: Approximately \(1.64\).
(Assuming that light entered into this glass block from air.)
Explanation:
Let \(n_{1}\) denote the refractive index of the first medium (in this example, air.) Let \(\theta_{1}\) denote the angle of incidence.
Let \(n_{2}\) denote the refractive index of the second medium (in this example, the glass block.) Let \(\theta_{2}\) denote the angle of refraction.
By Snell's Law:
\(n_{1} \, \sin(\theta_{1}) = n_{2}\, \sin(\theta_{2})\).
Rearrange the equation to find an expression for \(n_{2}\), the refractive index of the second medium (the glass block.)
\(\begin{aligned}n_{2} = \left(\frac{\sin(\theta_{1})}{\sin(\theta_{2})}\right)\, n_{1}\end{aligned}\).
The refractive index of air is approximately \(1.00\). Substitute in the values and solve for \(n_{2}\), the refractive index of the glass block:
\(\begin{aligned}n_{2} &= \left(\frac{\sin(\theta_{1})}{\sin(\theta_{2})}\right)\, n_{1} \\ &= \left(\frac{\sin(46^{\circ})}{\sin(26^{\circ})}\right)\times 1.00 \\ &\approx 1.64\end{aligned}\).
A kangaroo jumps 2 meters high. At what speed must the kangaroo have left the ground at for it to reach such a height?
In order to reach the maximum height of 2 meters, Kangaroo should jump with an initial speed of 6.26 m/s.
What are the three equations of motion?The three equations of motion are -
first law → v = u +at
second law → S = ut + 1/2 at²
Third law → v² - u² = 2aS
Given is a kangaroo who jumped 2 meters high.
Assume that the kangaroo jumped with an initial velocity of 'u' m/s.
The maximum height achieved is 2 meters.
Acceleration due to gravity will be -9.8 m/s²
At maximum height, the velocity will be zero. Therefore, the final velocity 'v' will be zero. Using third law →
v² - u² = 2aS
- u² = - 2gS
u² = 2gS
u² = 2 x 9.8 x 2
u² = 39.2
u = 6.26 m/s
Therefore, in order to reach the maximum height of 2 meters, Kangaroo should jump with an initial speed of 6.26 m/s.
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When you hold your cardboard square between the lights source and the wall what do you observe
When you hold your cardboard square between the lights source and the wall you observe a shadow.
Does light penetrate a cardboard?We know that light is a source of energy. Light travels in straight lines and this is called the rectilinear propagation of light. Having known that light travels along a straight path, we know that light would pass through the cardboard which is not too thick.
This cardboard is now able to scatter the light waves. We would then see a shadow at the wall. This shadow would have two regions; the region of complete darkness called umbra and the region of partial darkness called penumbra.
Thus, when you hold your cardboard square between the lights source and the wall you observe a shadow.
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Confused about this question. Can someone help? :)
Answer:
1 it could have been the way he put them in and 2it could be the directions there in.
suppose you lift a stone that has a mass of 5.9 kilograms off the floor onto a shelf that is 0.5 meters high. how much work have you done?
Work done to lift the stone of mass 5.9 kg is 28.91 J.
The work done through pressure is made of the displacement and the component of the carried-out force of the object inside the direction of displacement. whilst we push a block with a few pressure ' F ' the body movements with a few accelerations, paintings are carried out. paintings executed is written as W = F.
The paintings executed by using pressure are defined to be manufactured from the aspect of the force in the path of the displacement and the significance of this displacement. formula. work can be calculated by multiplying pressure and Distance within the course of force as follows. W = F × d.
Work is achieved whenever a pressure actions something over a distance. you can calculate the strength transferred, or work carried out, by multiplying the pressure via the space moved in the route of the pressure.
Calculation:-
mass = 5.9
g = 9.8 m/s
f = 0.5 m
work done = mgh
= 5.9 × 9.8 × 0.5 J
= 28.91 J
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A _______ strategy increases sales by introducing new products into new markets, while a _______ strategy entails creating a new product targeted to its current customers.
A market development strategy increases sales by introducing new products into new markets, while a product development strategy entails creating a new product targeted to its current customers.
In a market development strategy, a company seeks to expand its customer base by entering new markets or geographic regions. This involves identifying untapped market segments or regions where the company's existing products can be introduced to attract new customers. The goal is to increase sales by reaching a wider audience with existing products.
On the other hand, a product development strategy focuses on creating new products or improving existing ones to cater to the needs and preferences of the company's current customer base. This strategy aims to enhance customer loyalty and satisfaction by providing them with innovative or improved products that meet their evolving demands. The company leverages its understanding of its existing customers to develop products that will resonate with them and generate additional sales.
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The Diversification strategy is used by businesses to boost sales by introducing new products into unexplored markets, whereas a Product Development strategy involves creating new products for the company's existing customers.
Explanation:A Diversification strategy increases sales by introducing new products into new markets. This involves entering into an area, both in terms of product and market, where the company hasn't ventured before. For instance, a computer manufacturing company choosing to produce smartphones for a global market.
On the other hand, a Product Development strategy entails creating a new product targeted to its current customers. This strategy focuses on introducing a new product or innovation to the company's existing market to leverage the customer base. For example, a bread company introducing a new flavor of bread to existing customers.
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Which actions most likely cause the domains in a ferromagnetic material to align? Check all that apply. heating the material rubbing the material against a magnet passing electricity around the material placing the material in a magnetic field of opposite polarity placing the material near a strong magnet hitting the material
Answer:
i. rubbing the material against a magnet
ii. placing the material in a magnetic field of opposite polarity
iii. placing the material near a strong magnet
Explanation:
Ferromagnetic materials are majorly metals which can be easily attracted by a magnet. ferromagnetic materials are made up of domains, behaves as minute pieces of magnet. They can be rearranged to align when under the influence of an external magnetic field.
The alignment of the domains in a ferromagnetic material can be caused by either of the following: rubbing the material against a magnet, placing the material in a magnetic field of opposite polarity, placing the material near a strong magnet.
Answer:
B, D, E
Explanation:
edg2020
Plzz Help easy quesion for 20 points Why does someone get burned if they touch an old filament bulb that has been on for a few hours? Plzz Help
Answer:
In reality, the filament gets so hot it in a real sense bubbles off molecules and electrons. Now and again this material gathers as a dull spot at the highest point of the bulb. Eventually, the filament falls apart, gets frail, and breaks, subsequently finishing the life of the light. Lights radiate light by siphoning an electric flow through a dainty tungsten fiber. The filament warms and emits light. Over the long haul, the filament oxidizes and turns out to be increasingly fragile, until it splits up and the bulb goes out. ... Tungsten picks up obstruction as it warms.
Hope this helped :)
variations in the density of the earth's crust do not affect the value of the gravitational constant g at all. true false
The given statement is false, variations in the density of the earth's crust do not affect the value of the gravitational constant g at all.
What's the density of the Earth's crust?When compared to oceanic crust, which is basaltic (i.e., richer in iron and magnesium than granite) and has a density of about 2.9 to 3 grammes per cubic cm, continental crust is generally granitic and has a density of about 2.7 grammes per cubic cm.
The Earth has a density of 5.513 g/cm³. This represents the planet's entire material on average. Since water is less dense than iron, an average is required for usability.
G's value is independent of the types and dimensions of the bodies. Furthermore, it is independent of the type of medium separating the two bodies. Because of this, G is known as the universal gravitational constant.
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a merry-go-round rotates at the rate of 0.30 rad/s with a(n) 80.0 kg man standing at a point 2.0 m from the axis of rotation. what is the new angular speed when the man walks to a point 1.0 m from the center? assume that the merry-go-round is a solid 6.50 x 102 kg cylinder with a radius of 2.00 m.
The new angular speed of the merry-go-round after the man walks to a point 1.0 m from the center is approximately 1.80 rad/s.
Let's denote the initial angular speed of the merry-go-round as ω₁, and the new angular speed after the man walks to a point 1.0 m from the center as ω₂.
Given:
Initial angular speed ω₁ = 0.30 rad/s
Mass of the man m = 80.0 kg
Initial distance of the man from the axis of rotation r₁ = 2.0 m
New distance of the man from the axis of rotation r₂ = 1.0 m
Mass of the merry-go-round (cylinder) M = 6.50 * 10² kg
Radius of the merry-go-round (cylinder) R = 2.00 m
The conservation of angular momentum can be applied in this scenario, where the initial angular momentum of the system is equal to the final angular momentum of the system.
The initial angular momentum of the system is given by:
Initial angular momentum L₁ = Moment of inertia of the man about the axis of rotation x initial angular speed of the merry-go-round
The moment of inertia of the man about the axis of rotation can be calculated using the formula for the moment of inertia of a point mass rotating about an axis at a distance r from the axis of rotation:
Moment of inertia of the man about the axis of rotation I₁ = m x r₁²
The final angular momentum of the system is given by:
Final angular momentum L₂ = Moment of inertia of the man about the new axis of rotation x new angular speed of the merry-go-round
The moment of inertia of the man about the new axis of rotation can be calculated using the same formula as above, but with the new distance r₂:
Moment of inertia of the man about the new axis of rotation I₂ = m x r₂²
Setting the initial and final angular momenta equal to each other, we can solve for the new angular speed ω₂:
L₁ = L₂
I₁ * ω₁ = I₁ * ω₂
Substituting the expressions for I₁, I₂, and the given values:
m * r₁² * ω₁ = m * r₂² * ω₂
Simplifying:
r₁² * ω₁ = r₂² * ω₂
Plugging in the given values for r₁, r₂, and ω₁, and solving for ω₂:
2.0² * 0.30 = 1.0² * ω₂
\(\omega_2 = \frac{(2.0^2*0.30)}{1.0^2}\)
ω₂ ≈ 1.80 rad/s.
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NOTICE: BRAINLIEST WILL BE GIVEN!
what is radioactivity?
Answer:
As its name implies, radioactivity is the act of emitting radiation spontaneously. This is done by an atomic nucleus that, for some reason, is unstable; it "wants" to give up some energy in order to shift to a more stable configuration.
Explanation:
Too many neutrons in a nucleus lead it to emit a negative beta particle, which changes one of the neutrons into a proton. Too many protons in a nucleus lead it to emit a positron (positively charged electron), changing a proton into a neutron. Too much energy leads a nucleus to emit a gamma ray, which discards great energy without changing any of the particles in the nucleus. Too much mass leads a nucleus to emit an alpha particle, discarding four heavy particles (two protons and two neutrons).
how does the frequency of a radio wave compare to the frequency of the vibrating electrons that produce it?
Answer:
mass
Explanation:
consecutive resonances occur at wavelengths of 8 m and 4.8 m in an organ pipe closed at one end. what is the length of the organ pipe? (note: resonances occur at l
The length of the organ pipe closed at one end is 2.4 meters.
To find the length of the organ pipe closed at one end, we need to consider the relationship between the length of the pipe and the wavelength of the resonances.
The fundamental frequency (first harmonic) of a closed organ pipe occurs when the wavelength is twice the length of the pipe. In this case, the fundamental frequency corresponds to a wavelength of 8 m.
The second harmonic occurs when the wavelength is equal to the length of the pipe. In this case, the second harmonic corresponds to a wavelength of 4.8 m.
The difference between the two consecutive resonances (wavelengths) is equal to half of the fundamental frequency.
Difference in wavelength = (8 m - 4.8 m) = 3.2 m.
This difference is equal to half of the fundamental wavelength:
Difference in wavelength = Fundamental wavelength / 2.
Therefore, the fundamental wavelength is 2 * (Difference in wavelength) = 2 * 3.2 m = 6.4 m.
The length of the organ pipe closed at one end is equal to half of the fundamental wavelength:
Length of the pipe = Fundamental wavelength / 2 = 6.4 m / 2 = 3.2 m.
However, since the pipe is closed at one end, we need to account for the displacement node (antinode) at the closed end. This means that the length of the pipe is equal to a quarter of the fundamental wavelength:
Length of the pipe = Fundamental wavelength / 4 = 6.4 m / 4 = 1.6 m.
Therefore, the length of the organ pipe closed at one end is 2.4 meters.
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what is the leading hypothesis for venus’s lack of water?
Answer:
Its water molecules were broken apart, and hydrogen was lost to space. What kind of gas is most affected by thermal escape? What causes the release of oxygen into Earth's atmosphere?
Explanation:
The initial temperature of 150 g of ethanol was 22 C. What will be the final temperature of the ethanol if 3240 J was needed to raise the temperature of the ethanol
Answer:
30.405°CExplanation:
Using the formula for heart capacity;
Q = mcΔt
m is the mass = 150g = 0.15kg
initial temperature = 22°C
Quantity of heat = 3240J = 3.24kJ
specific heat capacity of ethanol = 2.57 [kJ/kg K]
Substitute and get the final temperature
3.240 = 0.15(2.57)(T - 22)
3.240 = 0.3855(T-22)
3.240/0.3855 = T - 22
8.405 = T - 22
T = 22+8.405
T = 30.405°C
Hence the final temperature of the ethanol if 3240 J was needed to raise the temperature of the ethanol is 30.405°C
How far apart are two conducting plates that have an electric field strength of 4. 4 kv/m between them, if their potential difference is 15 kv?
Conducting plates will be 3.75 m apart if an electric field strength of 4. 4 kV/m between them, if their potential difference is 15 kV
The potential difference, also referred to as voltage difference between two given points is the work in joules required to move one coulomb of charge from one point to the other. The SI unit of voltage is the volt. Volt Formula.
In a simple parallel-plate capacitor, a voltage applied between two conductive plates creates a uniform electric field between those plates. The electric field strength in a capacitor is directly proportional to the voltage applied and inversely proportional to the distance between the plates.
E = V/d
E = Electric field strength
d = distance between the plates
V = potential difference
Electric field strength = 4 kV/m
Potential difference = 15 kV
d = V / E = 15 kV / 4 kV/m
= 3.75 m
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A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?
The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
The cooling law is given by:
$$\frac{dQ}{dt}=-k(T-T_0)$$
where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.
We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.
Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.
Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:
dQ = - dQ where dQ is the heat energy gained by the environment.
We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.
We can rearrange the equation as follows:
$$-\frac{dQ}{dt}=k(T-T_0)$$
$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$
$$\frac{d}{dt}T=-k(T-T_0)$$
The differential equation above can be solved using separation of variables as follows:
$$\frac{d}{dt}\ln(T-T_0)=-k$$
$$\ln(T-T_0)=-kt+c_1$$
$$T-T_0=e^{-kt+c_1}$$
$$T=T_0+Ce^{-kt}$$
where C = e^(c1).
We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.
$$T=T_0+Ce^{-kt}$$
$$73=18+C\cdot e^{-0.09t}$$
$$55=C\cdot e^{-0.09t}$$
$$C=55e^{0.09t}$$
$$T=18+55e^{0.09t}$$
We can now solve for the value of t when T=93 as follows:
$$93=18+55e^{0.09t}$$
$$e^{0.09t}=\frac{93-18}{55}$$
$$e^{0.09t}=1.3636$$
$$t=\frac{\ln(1.3636)}{0.09}$$
Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
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A particular article reported the accompanying data on phenotypes resulting from crossing tall cut-leaf tomatoes with dwarf potato-leaf tomatoes. There are four possible phenotypes: (1) tall cut-leaf, (2) tall potato-leaf, (3) dwarf cut-leaf, and (4) dwarf potato-leaf.
Phenotype
1 2 3 4
Frequency 926 288 294 101
Mendel's laws of inheritance imply thatp1 =
9
16
,p2 =
3
16
,p3 =
3
16
, andp4 =
1
16
The correct answer is: Mendel's laws of inheritance imply that p1 = 9/16,p2 = 3/16,p3 = 3/16, andp4 = 1/16
Mendel’s laws of inheritance implies that if the dominant gene and the recessive gene are present, then the dominant gene is expressed while the recessive gene is hidden.
The four possible phenotypes:
Total Number of plants = 1609
Mendel's laws of inheritance imply that there are four possible phenotypes:
(1) tall cut-leaf, (2) tall potato-leaf, (3) dwarf cut-leaf, and (4) dwarf potato-leaf.
Mendel’s first law of segregation states that an organism contains two alleles for each trait. The alleles separate during the formation of gametes. The egg or sperm gets only one of the two alleles that are present in the organism.
The genotype and phenotype ratios obtained in the F2 generation can be predicted using the Punnett square.
When the Punnett square is used, it can be predicted that the offspring of P1 generation will have the following genotype and phenotype ratios:9/16 tall cut-leaf tomatoes (P1)3/16 tall potato-leaf tomatoes (P2)3/16 dwarf cut-leaf tomatoes (P3)1/16 dwarf potato-leaf tomatoes (P4)
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A wheel with rotational inertia I is mounted on a fixed, frictionless axle. The angular speed ω of the wheel is increased from zero to ωf in a time interval T.
What is the amount of work done by the net torque to the wheel during this time interval?
A: \(\frac{1}{2}l\omega_{f}^{2}\)
B: \(l\omega_{f} T\)
C: \(l\omega_{f} ^{2}\)
D: \(l\omega_{f} ^{2} /T\)
The wheel's average net torque over the course of interval T is Iωf/T (option-D).
Does net torque match net force?An object's rotational velocity is altered by net torque. The velocity of an object is affected by net force. When pushed, the block moves horizontally and, assuming low friction, does not rotate.
Given ,
The wheel's initial angular speed, \(w_{i}\) = 0
Final wheel angular velocity, \(w_{f}\) = \(w_{f}\)
The amount of time required to increase the wheel's angular speed t = T
The wheel's angular acceleration,
α = \(w_{f}\) - \(w_{i}\)/T
α = \(w_{f}\) - 0/T
α = \(w_{f}\)/T
Newton's Second Law of Rotation states:
The moment of inertia times the angular acceleration are equal when multiple torques are acting on a rigid body about a fixed axis.
τ = Iα
An expression for angular acceleration is:
α = (ωf - ωi) / T
α = ωf/T
As an alternative to the second law:
τ = Iωf/T.
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in a double-slit experiment, the slit separation is 2.0 mm , two wavelengths of 900 nm and 700 nm illuminate the slits, the screen is placed 2.6 meters away from the slits. at what distance from the central maximum on the screen will a dark fringe from one pattern first coincide with a dark fringe from the other?
Distance from the central maximum on the screen will a dark fringe from one pattern first coincide with a dark fringe from the other is -0.26 mm
How is the distance calculated?Since the slit separation is 2.0 mm , and two wavelengths, 900 nm and 700 nm , illuminate the slits. A screen is placed 2.6 m from the slits
λ\(1\) = 900 nm
λ\(2\) = 700 nm
D = 2.6 m
d = 2 mm
The distance is calculated using formula ,
\(Y\)= λD/d
Hence,
\(Y1\) = λ\(1\) D/d
\(Y2\) = λ\(2\) D/d
\(Y1\) = 900 × \(10^{-9}\) × 2.6 / 2 × \(10^{-3}\)
Therefore, \(Y1\) = 1.170 mm
\(Y2\) = 700 × \(10^{-9}\) × 2.6 / 2 × \(10^{-3}\)
Therefore, \(Y2\) = 0.910 mm
So the spacing between these two bright stripes is: \(Y2\) -\(Y1\) = -0.26 mm
What is double-slit experiment?Young's double-slit experiment uses two coherent light sources spaced apart. Usually only a few orders of magnitude larger than the wavelength of light are used. Young's double-slit experiment helped us understand the wave theory of light.
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Newton's reformulation of Kepler's third law allows us to measure the masses of bodies in orbit around each other, if we can measure:_______.
A. the distances and periods of revolution
B. the distance to the objects from Earth
C. the force and the reaction force
D. the eccentricities and semi-major axes
E. the rotation rate of each object
The masses of the bodies in orbit around each other can be measured, if we can measure the distances and periods of revolution.
Kepler's third lawKepler's third law states that, the square of the period of a planet's orbit is proportional to the cube of its semimajor axis.
Newton reformed this law and the reformulation of Kepler's third law allows us to measure the masses of bodies in orbit around each other, if we can measure;
the distances, and the periods of revolutionThus, the masses of the bodies in orbit around each other can be measured, if we can measure the distances and periods of revolution.
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Calculate the amount of energy a 3 kg ball on top of 10 m hill will have. Show your work with the correct ending units.
Answer:
This question is hard I will edit my answer when I find the answer
Explanation:
Can someone pls help me
Which factors affect friction between two solid surfaces? Select two options. The weight of the objects the surface area of the objects the shape of the objects the roughness of the objects’ surfaces.
The friction between the two solid surfaces depends on the weight of the objects on the surface and the roughness of the object surfaces.
When the two bodies are in contact such that a force acts to restrict the motion of each body, then the force is known as frictional force. And the phenomenon is called friction.
The expression for the frictional force is given as,
\(F = \mu \times N\)
Here,
\(\mu\) is the frictional coefficient and N is the normal reaction. (N = mg)
Clearly, the frictional force is dependent on the frictional coefficient of the surfaces and in turn, depends on the roughness of object surfaces. Also, friction depends on a normal reaction whose value is equivalent to the weight of objects on the surface.
Thus, we can conclude that the friction between the two solid surfaces depends on the weight of the objects on the surface and the roughness of the object surfaces.
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Answer:
A,d
Explanation:
the weight of the objects and the roughness of the objects’ surfaces i took the test
harry and sue cycle at the same speed. the tires on harry’s bike have a larger diameter than those on sue’s bike. which tires have the greater rotational speed?
Although both Harry and Sue cycle at the same speed, the tires on Sue's bike will have a greater rotational speed due to their smaller diameter.
The rotational speed of a tire is determined by the number of rotations it completes in a given time. It is directly related to the distance traveled by a point on the tire's circumference.
Since Harry and Sue cycle at the same speed, their linear speeds (or the speeds at which they move forward) are equal. However, the tires on Harry's bike have a larger diameter than those on Sue's bike.
The rotational speed of a tire is inversely proportional to its diameter. A larger diameter tire covers more distance with each rotation compared to a smaller diameter tire.
Therefore, the tires on Sue's bike will have a greater rotational speed. This means that for every rotation of Sue's smaller diameter tires, a point on the circumference will cover a shorter distance compared to Harry's larger diameter tires.
Consequently, Sue's tires will rotate more times in the same amount of time compared to Harry's tires.
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