The wavelength of the x-rays is 1.094 * 10⁻⁵ pm.
What is the relationship between the frequency and wavelength of a wave?The frequency of a wave is the number of complete oscillations completed by the wave per second. Its unit is Hertz.
The wavelength of a wave is the distance between successive points in phase in the wave. It is measured in units of meter.
The relationship between the wavelength and frequency of a wave is given below.
Wavelength = velocity of the wave / frequency
The frequency of X-rays = 3.0 * 10⁸ m/s
frequency of the wave = 2.74 × 10¹⁹ Hz
Wavelength = (3.0 * 10⁸ m/s) / (2.74 × 10¹⁹ Hz)
wavelength = 1.094 * 10⁻¹¹ m
wavelength = 1.094 * 10⁻⁵ pm.
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pls this this solutions
The freezing and thawing action of water affects a rock by...
A. leaving behind sedimentary particles from evaporation
B. gradually breaking down the rock into smaller pieces
C. chemically weathering the rock
D. transforming the rock into igneous rock
Answer:
B
Explanation:
When 161.0 mL of water at 26.0°C is mixed with 41.0 mL of water at 85.0°C, what is the final temperature
Answer: The final temperature is \(38.0^0C\)
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
\(heat_{released}=heat_{absorbed}\)
\(Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})\)
\(-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)]\)
\(-[m_1\times (T_{final}-T_1)]=[m_2\times (T_{final}-T_2)]\) (as \(c_1=c_2\))
Q = heat absorbed or released
\(m_1\) = mass of water at \(85.0^0C\) = \(volume\times density=41.0ml\times 1g/ml=41.0g\)
\(m_2\) = mass of water at \(26.0^0C\) = \(volume\times density=161.0ml\times 1g/ml=161.0g\)
\(T_{final}\) = final temperature = ?
\(T_1\) = temperature of 41.0 ml of water = \(85.0^0C\)
\(T_2\) = temperature of 161.0 ml of water = \(26.0^0C\)
Now put all the given values, we get
\(-[41.0\times (T_f-85.0)^0C]=161.0\times (T_f-26.0)^0C\)
\(T_f=38.0^0C\)
Thus the final temperature is \(38.0^0C\)
Sayid recorded the temperatures of four substances in a chart.
According to the forces of attraction and data collected,particles in substance Z has greatest amount of kinetic energy.
What are forces of attraction?
Forces of attraction is a force by which atoms in a molecule combine. it is basically an attractive force in nature. It can act between an ion and an atom as well.It varies for different states of matter that is solids, liquids and gases.
The forces of attraction are maximum in solids as the molecules present in solid are tightly held while it is minimum in gases as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.
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Your question is incomplete, but most probably your full question was,Sayid recorded the temperatures of four substances in a chart.
Which conclusion is best supported by the data?
The particles in substance W have a greater average kinetic energy than the particles in substance Z.
The particles in substance X have a greater average kinetic energy than the particles in substance Z.
The particles in substance W have a lower average kinetic energy than the particles in substance X.
The particles in substance Z have a lower average kinetic energy than the particles in substance Y
It takes 330 joules of energy to raise the temperature of 24.6 g of benzene from 21 degrees Celsius to 28.7 degrees Celsius at constantpressure. What is the molar hear capacity of benzene at constantpressure?
Answer: Molar heat capacity C = 136.09 JK-1mole-1
Explanation:
Heat capacity, C = Q/ ΔT
where C = heat capacity
Q =heat energy= Q = 330 J
ΔT is temperature difference =Change in temp =
ΔT = (28.7 +273)-( 21 + 273)= 7.7 K
But
No. of moles of benzene= mass / molar mass
= 24.6g / 78.11g/mol
= 0.3149 moles
Molar heat capacity C = Q/ nΔT
= 330 / ( 0.3149 x 7.7 )
= 136.09 JK-1mole-1
In the combustion of hydrogen gas, hydrogen reacts with oxygen from the air to form water vapor. hydrogen+oxygen⟶water
If you burn 46.2g of hydrogen and produce 413g of water, how much oxygen reacted?
mass of oxygen:
Answer:
ok, here is your answer
Explanation:
AI-generated answer
To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.
First, we need to find the number of moles of hydrogen that reacted:
Molar mass of hydrogen (H₂) = 2.016 g/mol
Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol
Next, we need to use the balanced chemical equation to find the number of moles of water produced:
hydrogen + oxygen → water
2H₂ + O₂ → 2H₂O
From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:
Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol
Finally, we can find the mass of oxygen that reacted by using its molar mass:
Molar mass of oxygen (O₂) = 32.00 g/mol
Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g
Therefore, the mass of oxygen that reacted is 366.72 g.
mark me as brainliestBrainliest get's +20 points!
Answer:
i think thats correcr!
Explanation:
Arrange the following elements in order of decreasing atomic radius: Ba, Sn, S, Pb, and As. Rank elements from largest to smallest.
Answer:
Ba>Sn>Pb>As>S
Explanation:
Hello,
In this case, we can write the atomic radius for the given elements:
\(r_{Ba}=268pm\\r_{Sn}=225pm\\r_{S}=100pm\\r_{Pb}=202pm\\r_{As}=185pm\)
In such a way, the required order is:
Ba>Sn>Pb>As>S
This is also in agreement as a periodic trend which states that the higher the period, the higher the radius.
Regards.
2) What is the pH when the concentration of [H*] is 4.22 x 108
3) What is the pH when the pOH is 7
4) What is the concentration of [OH¹¹] when the pH is 4.3
5) What does it mean to be diprotic?
6) What does amphoteric mean?
7) WHat can you use to measure pH?
8) WHat does a buffer solution do?
9) What does titration do?
10) What is the difference between a strong acid and a weak acid?
2. The pH is 4.22 × 10⁸. 3. pH is 7, 4. pOH is 9.7, 5. diprotic is explained below, 6. Amphoteric is explained below, 7. pH meter, 8. A buffer solution is explained below, 9. Titration is explained below, 10. Difference between strong and weak acids is explained below.
2. pH = -log[H⁺]
pH = -log(4.22 x 10⁻⁸)
pH ≈ 7.375
3. pH + pOH = 14
pH + 7 = 14
pH = 14 - 7
pH = 7
4. pH + pOH = 14
pOH = 14 - pH
pOH = 14 - 4.3
pOH ≈ 9.7
Now,
[H⁺] × [OH⁻] = 1.0 x 10⁻¹⁴
[OH⁻] = 1.0 x 10⁻¹⁴ / [H⁺]
[OH⁻] = 1.0 x 10¹⁴ / 10^(-pOH)
[OH⁻] = 1.0 x 10⁻¹⁴ / 10^(-9.7)
[OH⁻] ≈ 1.99 x 10⁻⁶ M
5. Being diprotic means that a molecule or ion can donate or release two protons (H⁺ ions) in an acid-base reaction.
6. Amphoteric refers to a substance that can act as both an acid and a base.
7. The pH can be measured using a pH meter or a pH indicator.
8. A buffer solution is a solution that can resist changes in pH when small amounts of acid or base are added to it.
9. Titration is a laboratory technique used to determine the concentration of a solution by reacting it with a solution of known concentration (titrant) of another substance.
10. A strong acid is an acid that completely ionizes in water, releasing all of its hydrogen ions. A weak acid is an acid that does not completely dissociate into ions when dissolved in water.
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4. A gas occupies 8.7L at a temperature of 29.0°c. What is thevolume at 133°C? (Charles Law)
Step 1
Charles' law states that the volume of an ideal gas is directly proportional to the absolute temperature at constant pressure.
Mathematically:
V1/T1 = V2/T2 (1)
V = volume in L
T = temperature in K
----------------
Step 2
Data provided:
V1 = 8.7 L
T1 = 29.0 °C + 273 = 302 K
-----
V2 = unknown
T2 = 133 °C + 273 = 406 K
----------------
Step 3
V2 is cleared from (1):
V1/T1 x T2 = V2 = 8.7 L/302 K x 406 K = 11.7 L approx.
Answer: V2 = 11.7 L
Enthalpy Lab + Questions NEED HELP ASAP FOR THE ANALYSIS QUESTIONS (be sure to show your work) + CONCLUSION
PURPOSE OF EXPERIMENT: To find Heat of Solution of sodium hydroxide and to find the heat of neutralization between sodium hydroxide and hydrochloric acid.
Experiment 1 Procedure:
1. Measure 50.0 mL of water (tap) into a 100 mL graduated cylinder and pour it into a large coffee cup.
2. Determine the temperature of this water
3. Measure out 2.00 g of sodium hydroxide into a piece of paper towel *tare scale!
4. Add the sodium hydroxide to the water in the coffee cup and put a small cup over it, with the thermometer through the hole. Stir GENTLY with the thermometer and record the temperature every 30 seconds for 3 minutes or until it peaks. Record this in a properly labelled table.
5. Let this stand for 45 minutes before proceeding to Exp. 2.
WHAT WE FOUND IN EXP 1:
T (temp.) initial = 20 degrees C
T (temp) FINAL = 28.5 degrees C
moles of sodium hydroxide = 0.0518mol
the molar mass of sodium hydroxide = 39.969g/mol
C (specific heat of water) = 4.184J/g degrees C
THE NUMBER OF TRIALS FOR TEMP IN EXP 1
1st trial = 21 C
2nd trial = 24.5 C
3rd trial = 26 C
4th trial = 26 C
5th trial = 28 C
6th trial = 28.5 C
7th trial = 28.5 C (final temp)
ANALYSIS FOR EXPERIMENT ONE:
1. Determine the moles of sodium hydroxide (NaOH) from the experiment.
2. Determine Qsurroundings and Qrxn
3. Determine the enthalpy for the dissociation of sodium hydroxide (delta H sol)
4. Write the thermochemical equation for the dissociation of sodium hydroxide TWO ways and write an enthalpy diagram
5. What assumptions did you make to calculate #2? (some example assumptions to make: assume that the solution is water and that heat and density COULD be the same as water, etc)
6. Research the actual value and determine the percent error
7. In terms of bonds breaking and forming, what is RESPONSIBLE FOR ENTHALPY CHANGE?
EXPERIMENT 2 PROCEDURE:
1. Measure out 50.0 mL of 0.75 concentration M HCl into a graduated cylinder
2. Measure and record the temperature of the sodium hydroxide solution from exp. 1.
3. Add the hydrochloric acid solution to the sodium hydroxide solution, put the small cup on, and record the temperature change every 15 seconds for 1 minute. Stir GENTLY. Record this in a properly labelled table (will be given below)
4. Solutions can be discarded down the sink.
WHAT WE FOUND IN EXP. 2:
T (temp) initial = 23.5 C
T (temp) FINAL = 27 C
THE NUMBER OF TRIALS FOR TEMP IN EXP 2
1st trial = 27 C
2nd trial = 27 C
3rd trial = 27 C
4th trial = 27 C (FINAL TEMP)
ANALYSIS FOR EXPERIMENT 2:
1. Determine the moles of HCl added to this mixture
2. Write the chemical equation for this reaction
3. Determine the limiting reagent
4. Determine the Qsurr and Qrxn *CONVERT TO kJ*
5. Determine the enthalpy for the neutralization reaction.
6. Write the thermochemical equation for the dissociation of sodium hydroxide TWO WAYS and write an enthalpy diagram
7. Research the actual value and determine the percent error.
8 Explain sources of experimental error for both experiments and BE SPECIFIC! (NOT CALCULATION ERRORS, SPILLING, OR LOSING REACTANTS - DO NOT COUNT AS ERRORS! They can be EXPERIMENTAL due to heat loss/gain, room temp *specific heat capacity is for 25 C*, and atmospheric pressure is constant. And they can be MEASUREMENTS - consider the precision and the potential range of error for each measurement)
9. In terms of bonds breaking and forming, what's responsible for the enthalpy change?
CONCLUSION: write a brief statement that refers to the purpose.
The difference between the energy needed to break the bonds in the reactants and the energy released when new bonds are created in the products is what essentially determines the enthalpy change.
What impact does bond breaking have on enthalpy?In general, a bond must be broken by a positive change in enthalpy, whereas a bond must be formed by a negative change in enthalpy. In other words, the process of breaking a bond is endothermic, whereas the process of forming a bond is exothermic.
What is the bond-breaking and bond-forming reaction's enthalpy change?The energy needed to break the links between the reactants less the energy released during the formation of new bonds in the products is the enthalpy of reaction.
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In terms of bonds breaking and forming, what's responsible for the enthalpy change?
At the same temperature and pressure, balloons of equal volume always contain
a.equal masses of gas.
b.equal numbers of molecules.
c.equal densities of gas.
d.equal numbers of atoms.
Answer:
B. equal numbers of molecules
Explanation:
Chemistry Lab Determination of the Universal Gas Constant (R)
SHOW ALL WORK
Given:
Initial mass of butane lighter: 54.24g
Final Mass of Butane Lighter: 54.01g
Temperature of water: 23.0°C
Volume of gas collected: 100.0mL
FIND:
Barometric pressure of room: 766.86 mmHg CONVERTED TO atm
Vapor pressure of water at room temperature(PH2O) (IN atm)
FIND:
Mass difference if butane lighter in grams
Moles of Butane gas collected in moles of C4H10
Partial pressure if butane gas in atm
Converted temperature of water in Kelvin
Converted volume of gas collected in Liters
Experimental value of R in Latm/molk
Accepted value of R in Latm/molk
Percent error in experimental value of R in %
CONCLUSION QUESTIONS:
1. List at least 3 factors that either did it could contribute to the percent error
2. Should the value of R go up or down if the gas had not been corrected for the partial pressure of water. Why?
3. How could this experiment be repeated to increase the accuracy, or in other words, decrease the percent error?
NOTE: LET ME KNOW IF YOU WANT A PICTURE OF THE LAB INSTRUCTIONS TO HELP SOLVE
ALSO SHOW ALL WORK PLS
To solve this problem, I'll need some additional information related to the molar mass of butane (C4H10). Please provide the molar mass of butane so that I can proceed with the calculations.
explain how matter and energy cycle through the Chaparral
Answer:
the scrubby plants in the chaparral biome fix CO2 from the atmosphere through photosynthesis and store carbon as starch. The energy from these carbohydrates is passed on to animals and insects that consume the plants. These primary consumers will pass on the carbon’s energy to other animals that prey on them. When plants or animals die and decompose, the carbon in their bodies returns to the earth. Fossil fuels, which are made from ancient decomposed matter, release carbon back into the atmosphere as CO2 when they are burned
For a school event 1/6 of the athletic field is reversed for the fifth -grade classes the reserved part of the field is divided equally Among the 4 fifth grade classes in the school what fraction of the whole athletic field is reserved for each fifth class
Answer:
\(\frac{1}{24}\)
Explanation:
Given:
For a school event, 1/6 of the athletic field is reserved for the fifth -grade classes and the reserved part of the field is divided equally among the 4 fifth grade classes in the school.
To find: fraction of the whole athletic field reserved for each fifth class
Solution:
Fraction of the whole athletic field reserved for four fifth classes = \(\frac{1}{6}\)
So, fraction of the whole athletic field reserved for each fifth class = \(\frac{1}{4}(\frac{1}{6})=\frac{1}{24}\)
Beryllium-9 and an alpha particle combine to form carbon-13. The carbon-13 nucleus then emits a neutron.
True, when one bombarded beryllium with alpha particle , a carbon-12 nucleus was formed and a neutron was emitted.
What is a neutron and what is the balanced chemical equation for carbon bombardment with carbon-12?Neutron as we have already studied is a neutral atom without any charge but of same mass of proton.Here an alpha particle bombarded with carbon-12 and forms carbon-13 as the product .The formation of carbon-13 takes place with a release of a neutron that is finalized with the emission of neutron.Be + He = C + n , is the equation depicting the whole bombardment with a release of neutron.Though the neutron is electrically neutral or no charge , hence when a alpha particle bombarded with a carbon-12 results into the formation of carbon-13.To know more about neutron visit:
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A 15.0 L rigid container was charged with 0.5 atm of Krypton gas and 1.5 atm of chlorine gas at 350 C. The krypton and chlorine react to form tetrachloride. What mass of krypton tetrachloride can be produced assuming 100% yield?
The mass of krypton tetrachloride that can be produced assuming 100% yield is mathematically given as
molar mass=33.29g
What mass of krypton tetrachloride can be produced assuming 100% yield?Generally, the equation for ideal gas is mathematically given as
PV=nRT
Therefore
n=(0.50)(15.)/0.082*623
n=0.147mol
Hence for clorine
n=0.441mol
Given the reaction
Kr+2cl2---->KrCL4
Hence
molar mass=225.60*0.147
molar mass=33.29g
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How many oxygen molecules will be needed to combust two molecules of hexane
resulting in twelve molecules of carbon dioxide and fourteen molecules of
water ?
Answer: 19
Explanation:
2C6H14 + 19O2 —> 12CO2 + 14H2O
Cumulative Exam Active
41 42 43 144
The electron configuration of nitrogen (N) is
O 1s²2s²2p³
O 1s²2s²2p4
O 1s²2s²2p5
O 1s²2s²2p6
The answer is: The electronic configuration of Nitrogen is \(1s^22s^22p^3\).
Electronic configuration: The electronic configuration is defined as the distribution of electrons of an atom in the atomic or molecular orbitals and is written using the labels for the subshell.
How to decide which orbital is filled first?
The order in which electrons are filled in atomic orbitals as:(Shown in image)
Just follow the arrows to select the orbitals, s orbital can have 2 electrons, p can have 6 electrons, d can have 10 electrons and f can 14 electrons.The electronic configuration in which the outer shell is completely filled is known as noble-gas configuration as they are similar to electronic configurations of noble gases.Now, the given element is nitrogen (\(N\)). The atomic number of Nitrogen is 7. Thus, these 7 electrons are filled as-\(1s^22s^22p^3\)
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Nitrogen's complete electron configuration is 12s2s22p3.
The shorthand electron configuration for noble gases is [He] 2s22p3. Nitrogen has an atomic number of 7. The nitrogen atoms' nucleus contain this many protons. An atom that is neutral has an equal number of protons and electrons. Thus, the ground state electron configuration will consist of 7 electrons in the suitable s and p orbitals (state of lowest energy). For nitrogen, the entire electron configuration is 1s22s22p. Scientists may easily express and explain how the electrons are organized around the nitrogen atom's nucleus by using the configuration notation for nitrogen (N). As a result, it is simpler to comprehend and forecast how atoms will cooperate to form chemical bonds.
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what is the mass of 1mol of chlorine ions?
Answer:
71g
Explanation:
i think thats right?
One mole of chlorine would be 71 g unless they said "1 mole of chlorine ATOMS".
Sugar (C12H22011) is a molecular substance. Which of the following properties would you expect it to
have?
a. conducts electricity in water
b. doesn't dissolve in water
c. held together by opposite charges
d. low melting point
If you measure pressure in bars instead of atmospheres, calculate the corresponding value of R in L −bar/ mol −K .
The value of the constant R in L*atm/(mol*K) is approximately 0.082057 L*atm/(mol*K). The units are a little complex so it is easier for us to viasualize it as a fraction:
\(R\approx0.082057\times\frac{L\cdot atm}{mol\cdot K}\)To get the constant value in terms of bar, that is, L*bar/(mol*K), we can use the convertion of atm-bar:
\(1atm=1.01325bar\Rightarrow1=\frac{1.01325bar}{1atm}\)So, we have:
\(R\approx0.082057\times\frac{L\cdot atm}{mol\operatorname{\cdot}K}=0.082057\times\frac{L\operatorname{\cdot}atm}{mol\operatorname{\cdot}K}\times\frac{1.01325bar}{1atm}\approx0.083144\times\frac{L\operatorname{\cdot}bar}{mol\operatorname{\cdot}K}\)So, the value of the constant R is approximately 0.083144 L*bar / (mol*K).
For each of the substances below, label them as acids (A), bases (B), or neutral (N), then place them where they best belong on the pH scale. You may need to research some substances' pH if you are not familiar with them.
__ baking soda
__ Vinegar
__ Distilled water
__ “Pure” rain
__ Ammonia
__ Lemon juice
__ Hair and skin
To research some substances pH 0 to less than 7 is acidic, 7 is neutral and more than 7 is neutral.
baking soda - base
Vinegar - acid
Distilled water - neutral
Pure rain - neutral
Ammonia - nasic
Lemon juice - acid
Hair and skin - acidic
An acid is a molecule or ion capable of both donating a proton, referred to as a Brønsted–Lowry acid, or forming a covalent bond with an electron pair, known as a Lewis acid. the first class of acids are the proton donors, or Brønsted–Lowry acids.
An acid is any substance that in water answer tastes sour, adjusts blue litmus paper to red, reacts with a few metals to liberate hydrogen, reacts with bases to form salts, and promotes chemical reactions (acid catalysis). An acid is a substance that produces hydrogen (H+) ions when it's far delivered to water. A hydrogen ion is simply the proton and no electron
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Which of the following items are made from renewable resources? Select the two correct answers. (1 point)
Responses
plastic fork
plastic fork
metal can
metal can
leather jacket
leather jacket
electronics
electronics
printer paper
A leather jacket and printer paper are examples of items that can be made from renewable resources, while plastic forks, metal cans, and electronics are not considered renewable due to their reliance on non-renewable materials and processes. Option C, E
The two correct answers that are made from renewable resources are:
C) Leather jacket: Leather is derived from animal hides, which are a byproduct of the meat industry. As long as there is a sustainable and responsible approach to animal farming, the production of leather can be considered renewable. The hides are obtained from animals that are raised for meat consumption, and their use in leather production helps reduce waste.
E) Printer paper: Printer paper can be made from various sources, including trees, bamboo, and recycled paper fibers. If the paper is sourced from sustainably managed forests or from fast-growing plants like bamboo, it can be considered renewable. Additionally, the use of recycled paper fibers reduces the demand for materials and promotes a more circular economy.
The other options, A) plastic fork, B) metal can, and D) electronics, are not made from renewable resources:
A) Plastic fork: Plastics are typically derived from fossil fuels, which are non-renewable resources. The production of plastic involves the extraction and processing of petroleum or natural gas, both of which are finite resources.
B) Metal can: Metal cans are predominantly made from aluminum or steel. While these metals can be recycled, their initial production requires the extraction of raw materials from the Earth, which is not a renewable process.
D) Electronics: Electronics are made from a wide range of materials, including metals, plastics, and various chemical compounds. The production of electronics involves the extraction of raw materials, many of which are non-renewable resources.
Option C and E.
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Options:
1. Unsaturated fat or saturated fat
2. Fatty acids, carbohydrates, sterols, or phospholipids
3. Fatty acids, carbohydrates, or triglycerides
Please helppp
Answer:
1. saturated
2. fatty acids
3. fatty acids
Explanation:
Answer:
option 2 is correct
Explanation:
A high temperature reaction vessel is charged with 0.5860 mol of iron powder and 35.1 L of oxygen gas at standard temperature pressure. On heating, the iron and oxygen react according to the balanced reaction below.
4Fe(s) + 3O2(g) ®️ 2Fe2O3(s)
After the reaction vessel is called, and assuming the reaction goes to completion, what volume of oxygen remains?
Answer: 25.1195 L
Explanation:
Given:
There are 0.5860 mol of Iron powder (Fe)
The volume of oxygen gas at STP is 31.5 L
The volume filled by a gas at STP is approximately 22.71 L
Therefore, the moles of oxygen gas at STP = Volume of oxygen gas at STP/ 22.71
= 35.1/22.71
= 1.5456 mol
The balanced chemical equation given for this reaction is:
4Fe(s) + 3O2 (g) ----> 2Fe2O3 (s)
Dividing the above equation by 2, yields:
2Fe(s) + 3/2O2(g) -------> Fe2O3 (s)
From the equation we see:
2 moles of Fe reacts with 3/2 mole of O2 to give one mole of Fe2O3
Thus, let x moles of O2 react with 0.5860 moles of Fe
0.5860/2=x/3/2
0.5860*3=4*x
x = 1.758/4
x =0.4395 mol
So the remaining moles of oxygen gas = 1.5456 - 0.4395
= 1.1061 mol
Therefore, the amount of oxygen gas, in litres, remaining is = 1.1061*22.71
= 25.1195 L
Each of the following sets of quantum numbers is supposed to specify an orbital. Choose the one set of quantum numbers that does NOT contain an error.
a. n = 4, l = 3, ml =-4
b. n = 2, l = 2, ml =0
c. n = 3, l = 2, ml =-2
d. n = 2, l = 2, ml =+1
Answer:
n = 3, l = 2, ml =-2
Explanation:
Quantum numbers are a set of values which can be used to describe the energy and position of an electron in space.
There are four sets of quantum numbers;
1) principal quantum number
2) orbital quantum number
3) spin quantum number
4) magnetic quantum number.
The values of orbital quantum number include; -l to +l;
The set of quantum numbers without error is ; n = 3, l = 2, ml =-2
Student was identifying the formula of 1 mole of unknown powder. When it was placed on a scale, it was reading 399.91 g/mol. Which of
the following compounds can it be?
A AI(NO3)3
B. C3H8
C. Fe2(SO4)3
D. CaCl2
Answer: The compound is \(Fe_2(SO_4)_3\)
Explanation:
Molar mass is defined as the mass in grams of 1 mole of a substance.
S.I Unit of Molar mass is gram per mole and it is represented as g/mol.
A. 1 mole of \(Al(NO_3)_3\) weighs = 26.98(1)+14.01(3)+15.99(9) =212.99 g/mol
B. 1 mole of \(C_3H_8\) weighs = 12.01(3)+1.007(8) = 44.1 g/mol
C. 1 mole of \(Fe_2(SO_4)_3\) weighs = 55.84(2)+32.06(3)+15.99(12) = 399.91 g/mol
D. 1 mole of \(CaCl_2\) weighs = 40.07(1)+35.5(2)= 110.98 g/mol
Thus the compound is \(Fe_2(SO_4)_3\)
base and? The carbonate buffer is responsible for the pH regulation of the extracellular environment. A carbonic acid-hydrogencarbonate is prepared in a ratio 1.25:1. The Ka is 4.5 x 10^-7 what is the concentration of t hydrogen carbonate ion if the physiological pH = 7.35 what is the concentration of H₂CO₂ lon
The concentration of the hydrogen carbonate ion ([HCO₃⁻]) is approximately 3.15 x 10⁷ and the concentration of the carbonic acid ([H₂CO₃]) is approximately 2.52 x 10⁷.
The carbonate buffer system plays a crucial role in maintaining the pH balance of the extracellular environment. In this system, carbonic acid (H₂CO₃) and hydrogen carbonate (HCO₃⁻) act as a conjugate acid-base pair. Given that the ratio of carbonic acid to hydrogen carbonate is 1.25:1, we can assume that the initial concentration of carbonic acid is higher. Let's denote the initial concentration of carbonic acid as [H₂CO₃] and the concentration of hydrogen carbonate as [HCO₃⁻]. The dissociation of carbonic acid can be represented by the equation: H₂CO₃ ⇌ H⁺ + HCO₃⁻. The equilibrium constant (Ka) for this reaction is given as 4.5 x 10⁻⁷. At physiological pH (7.35), the concentration of H⁺ is determined by the dissociation of carbonic acid and is tightly regulated. To calculate the concentration of hydrogen carbonate ion ([HCO₃⁻]), we need to make use of the Henderson-Hasselbalch equation:
pH = pKa + log([HCO₃⁻]/[H₂CO₃])
Substituting the given values, we have:
7.35 = -log(4.5 x 10⁻⁷) + log([HCO₃⁻]/[H₂CO₃])
Rearranging the equation, we find:
log([HCO₃⁻]/[H₂CO₃]) = 7.35 + log(4.5 x 10⁻⁷)
Taking antilog of both sides, we get:
[HCO₃⁻]/[H₂CO₃] = 10^(7.35 + log(4.5 x 10⁻⁷))
Simplifying the right-hand side, we have:
[HCO₃⁻]/[H₂CO₃] ≈ 3.15 x 10⁷
Since the initial ratio of H₂CO₃ to HCO₃⁻ is 1.25:1, we can set up the equation:
[HCO₃⁻] = 1.25 x [H₂CO₃]
Substituting the value of [HCO₃⁻]/[H₂CO₃] from above, we find:
1.25 x [H₂CO₃] = 3.15 x 10⁷
Solving for [H₂CO₃], we get:
[H₂CO₃] ≈ 2.52 x 10⁷
Therefore, the concentration of the hydrogen carbonate ion ([HCO₃⁻]) is approximately 3.15 x 10⁷ and the concentration of the carbonic acid ([H₂CO₃]) is approximately 2.52 x 10⁷.
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How much volume (in cm3) is gained by a person who gains 12.3 lb of pure fat?
Answer:
So we are given with the mass while we are asked for the amount of volume. So this means, we must need an information on the density. From literature, the density of human fat is 0.918 g/cm³. Convert grams to lb by the conversion that 1,000 g = 2.2 lbs.
Density = 0.918 g/cm³ * (2.2 lbs/1,000 g) = 0.0020196 lb/cm³
Volume = Mass/Density = 12.2 lb / 0.0020196 lb/cm³
Volume = 6,040.8 cm³