Convert the measurement as indicated.
450 in to yards
450 in =
|yd (Type
an
integer or a decimal.

Based on the data recorded by Anna on Saturday, we can estimate the number of people expected to visit The Youth Wing on Sunday.

Let's calculate the proportion of visitors to The Youth Wing compared to the total number of visitors on Saturday:

\(\displaystyle \text{Proportion} = \frac{\text{Visitors to The Youth Wing on Saturday}}{\text{Total visitors on Saturday}} = \frac{382}{382 + 461 + 355}\)

Next, we'll apply this proportion to the total number of visitors on Sunday to estimate the number of people expected to go to The Youth Wing:

\(\displaystyle \text{Expected visitors to The Youth Wing on Sunday} = \text{Proportion} \times \text{Total visitors on Sunday}\)

Now, let's substitute the values into the equation and calculate the estimated number of visitors to The Youth Wing on Sunday:

\(\displaystyle \text{Proportion} = \frac{382}{382 + 461 + 355}\)

\(\displaystyle \text{Expected visitors to The Youth Wing on Sunday} = \text{Proportion} \times 800\)

Calculating the proportion:

\(\displaystyle \text{Proportion} = \frac{382}{382 + 461 + 355} = \frac{382}{1198}\)

Calculating the estimated number of visitors to The Youth Wing on Sunday:

\(\displaystyle \text{Expected visitors to The Youth Wing on Sunday} = \frac{382}{1198} \times 800\)

Simplifying the equation:

\(\displaystyle \text{Expected visitors to The Youth Wing on Sunday} \approx \frac{382 \times 800}{1198}\)

Now, let's calculate the approximate number of visitors to The Youth Wing on Sunday:

\(\displaystyle \text{Expected visitors to The Youth Wing on Sunday} \approx 254\)

Therefore, based on the data recorded on Saturday, we can estimate that around 254 people should be expected to go to The Youth Wing on Sunday.

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

Answer:

I have this question too

Step-by-step explanation:

All i know is that the ASA shows that even when they are rotated or translated due to rigid motions, they are still congruent because it shows that the angles and sides are equal.

Answer:

6 b 7 d give me brainlest

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Exponent division rule: If base are same for any two variables, then subtract the powers.

\(\dfrac{a^{m}}{a^{n}}=a^{m-n}\)

\(\dfrac{f^{6}h^{9}}{f^{3}h^{7}}=f^{6-3}h^{9-7}\\\\\\ =f^{3}h^{2}\)

Given in the question:

a.) A family buys a car for $20,000.

b.) The value of the car decreases about 18% each year.

c.) After six years the family wants to sell the car.

Should they sell the car for $4000?

Let's determine if the price of the car fits the recommended price using the formula below:

Where,

y = the recommended price of the car after 6 years.

A = price of the car when bought

d = (100% - 18%)/100 = 82/100 = 0.82

x = years of use

We get,

The computed depreciated value of the car is $6,080.13.

Therefore, we recommend that they should sell the car at a higher price but not more than $6,080.13 since it's still within the recommended depreciated value.

Yes, it is possible for an object to have zero momentum. Momentum is defined as function the product of mass and velocity, so an object with zero mass or zero velocity will have zero momentum.

Momentum is a physical property of an object that is equal to the product of its mass and velocity. It is measured in kilogram meters per second (kg m/s) and is a vector quantity, meaning it has both magnitude and direction. In order for an object to have zero momentum, it must have either zero mass or zero velocity. An object with zero mass will always have zero momentum regardless of its velocity, while an object with zero velocity will only have zero momentum if its mass is also zero. An object with nonzero mass but zero velocity still has nonzero momentum if its mass is not zero. Therefore, it is possible for an object to have zero momentum.

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the complete question is

is it possible for an object to have no (zero) momentum? use the mathematical definition of momentum (p) to explain

It is possible for an object to have No (Zero) momentum because Momentum is the product of mass and velocity, so the object with zero mass or zero velocity will have No momentum.

What is Momentum ?

The Momentum of an object is a vector quantity that is defined as the product of the mass and velocity , the unit of measurement if Kg m/s .

So , for the object to have No (zero) momentum, the object must have either zero mass or zero velocity. that means the object with zero mass will always have No (zero) momentum regardless of velocity of the object ,

whereas the object with 0 velocity will only have No (zero) momentum if the  mass is also 0 .

Therefore , By the Mathematical Definition of momentum , Yes , it is possible for the object to have No(zero) momentum .

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Answer:

Step-by-step explanation:

Answer:

3

---

8

Step-by-step explanation:

the ratio of cakes to pies will be 3:8 if pies to cakes is 8:3

the fraction is 3/8

i)

ii)

iii)

iv)

With x = -12, Not applicable so x will be 10

Length → x + 5 → 10 + 5 → 15

Breath → x -3 → 10 - 3 → 7

Therefore,

Length : 15 cm

Breadth : 7 cm

Answer:

Given:

i) Length of rectangular shaped lamina = (x + 5) cm

ii) Breadth of rectangular shaped lamina = (x - 3) cm

ii) Area of a rectangle = length × breadth

⇒ area of rectangular shaped lamina = (x + 5)(x - 3) cm²

Given:

⇒ (x + 5)(x - 3) = 105

Expand:

⇒ x² - 3x + 5x - 15 = 105

Combine like terms:

⇒ x² + 2x - 15 = 105

Subtract 105 from both sides:

⇒ x² + 2x - 120 = 0

iv) Solve x² + 2x - 120 = 0

Rewrite:

⇒ x² + 12x - 10x - 120 = 0

Break into groups:

⇒ (x² + 12x) - (10x + 120) = 0

Factorize the parentheses:

⇒ x(x + 12) - 10(x + 12) = 0

Factor out common term:

⇒ (x - 10)(x + 12) = 0

Therefore,

x - 10 = 0  ⇒  x = 10

x + 12 = 0  ⇒  x = -12

As length is positive, x = 10 only

Therefore,

Length of rectangular shaped lamina = 15 cm

Breadth of rectangular shaped lamina = 7 cm

Answer:

20-2h

Step-by-step explanation:

20 is the original amount. The variable stands for the number of hours. You are TAKING AWAY 2 degrees every hour so you would subtract.

Answer:

You click on the ANSWER button and type in your answer and sometimes explanation (if necessary) and then click the blue paper airplane button on the right to post it. Hope this helps.

Answer:

1,500.00

Step-by-step explanation:

Assuming 52 weeks in a year, you would make $1,500.00 per week.

Answer:

$1500

Step-by-step explanation:

Here, the question asks what hector's income per week is.

- Keep in mind that if you are asked what something is per unit, you will most likely need to divide. Example: This problem. See below for answer and explanation.

- If a question asks what something is of  a unit, you will most likely need to multiply. Example: 1/4 of a pizza with 4 slices (1 slice). To solve this, you will have to multiply 1/4 to 4. But never mind this, let's focus at this problem.

The bullet points above essentially explain what you have to do here. To find Hector's income, you have to do 78000/52. The answer to this is 1,500 ($1500).

I hope this helped :)

Answer:

Step-by-step explanation:

Answer:

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Step-by-step explanation:

The class of the equation and the cross section equation are;

The equation is a hyperboloid of two sheets

The cross sections are;

Equation at z = 0 is; y²/8 - x²/8 = 1

Equation at y = -4 is; x²/8 + z² = 1

Equation at y = 0 is; x²/8 + z² = -1

Equation at y = 4 is; x²/8 + z² = 1

Equation at x = 0 is; y²/8 - z² = 1

An equation is a mathematical statement which indicates the equivalence two expressions by joining them with the '=' sign.

The equation can be presented as follows;

y² = x² + 8·z² + 8

y² - x² - 8·z² = 8

y²/8 - x²/8 - z² = 1

The above equation is the equation of an hyperboloid of two sheets, where;

a² = 8, b² = 1, and c² = 8

Please find attached the diagram of the surface, created with an online 3D graphing tool.

The equation for the cross section at z = 0, can be obtained by plugging in z = 0, into the equation as follows;

y²/8 - x²/8 - 0 = 1

y²/8 - x²/8 = 1

The above equation is the equation of an hyperbola in the xy plane

The equation for the cross section at y = -4, can be obtained by plugging in y = -4, into the equation as follows;

4²/8 - x²/8 - z² = 1

- x²/8 - z² = 1 - 4²/8 = -1

- x²/8 - z² = -1

x²/8 + z² = 1

The above is an equation of an ellipse in the xz plane

The equation for the cross section at y = 0, can be obtained by plugging in y = 0, into the equation as follows;

0²/8 - x²/8 - z² = 1

- x²/8 - z² = 1

Therefore; x²/8 + z² = -1

The equation for the cross section at y = 4, can be obtained by plugging in y = 4, into the equation as follows;

4²/8 - x²/8 - z² = 1

- x²/8 - z² = 1 - 2 = -1

x²/8 + z² = 1

The above equation is the equation of an ellipse in the xz plane

The equation for the cross section at x = 0, can be obtained by plugging in x = 0, into the equation as follows;

y²/8 - 0²/8 - z² = 1

y²/8 - z² = 1

The equation is the equation of an hyperbola in the yz plane

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so, the minimum value of d that guarantees effectiveness is 11.08 mg.

This is a problem involving geometric series and exponential decay. Here are the steps to solve it:

(a) Let An be the amount of medicine in the patient's body immediately after taking the nth dose. Then:

A1 = d (the first dose)

A2 = d + d * (1/16) (the second dose plus the remaining amount of the first dose after 24 hours)

A3 = d + d * (1/16) + d * \((1/16)^2\) (the third dose plus the remaining amounts of the previous doses after 24 hours)

In general, An = d + d * (1/16) + d *  \((1/16)^2\) + ... + d * \((1/16)^(n-1)\), which is a finite geometric series with n terms, first term d and common ratio 1/16.

(b) To find an explicit formula for An, we can use the geometric series partial sum formula:

\(An = d * [(1 - (1/16)^n) / (1 - 1/16)]\)

Simplifying, we get:

\(An = 15.9375 * [1 - (1/16)^n]\)

(c) Let Bn be the amount of medicine in the patient's body immediately before taking the nth dose. Then:

B1 = 0 (there is no medicine in the body before taking the first dose)

B2 = d * (1/16) (the remaining amount of the first dose after 24 hours)

\(B3 = d * (1/16) + d * (1/16)^2\) (the remaining amounts of the first and second doses after 24 hours)

In general, \(Bn = d * (1/16) + d * (1/16)^2 + ... + d * (1/16)^(n-1)\), which is also a finite geometric series with n-1 terms, first term d * (1/16) and common ratio 1/16.

(d) To find an explicit formula for Bn, we can use the geometric series partial sum formula again:

\(Bn = d * (1/16) * [(1 - (1/16)^(n-1)) / (1 - 1/16)]\)

Simplifying, we get:

\(Bn = 0.9375 * [1 - (1/16)^n]\)

(e) We need at least 10 mg of the medicine in the patient's blood for it to be effective. This means that Bn must be greater than or equal to 10 for all n. Solving for d, we get:

\(0.9375 * [1 - (1/16)^n] > = 10[1 - (1/16)^n] > = 10.6667(1/16)^n < = 0.0937\)

Taking logarithms on both sides, we get:

n * ln(1/16) <= ln(0.0937)

Since ln(1/16) is negative, we reverse the inequality sign:

n >= ln(0.0937) / ln(1/16)

n >= 2.44

This means that after taking at least three doses, the medicine will remain effective in the long run. To find the minimum value of d that satisfies this condition, we plug in n = 3 into Bn and set it equal to 10:

\(0.9375 * [1 - (1/16)^3] = 10\)

d = 10 / [0.9375 * (0.99609)]

d ≈ 11.08

Therefore, the minimum value of d that guarantees effectiveness is 11.08 mg.

(f) The medicine is toxic if 100 mg or more is ever in their blood. This means that An must be less than 100 for all n. Solving for d, we get:

\(15.9375 * [1 - (1/16)^n] < 100[1 - (1/16)^n] < 6.2705(1/16)^n > 0.1595\)

Taking logarithms on both sides, we get:

n * ln(1/16) > ln(0.1595)

Since ln(1/16) is negative, we reverse the inequality sign:

n < ln(0.1595) / ln(1/16)

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The set οf measurements that cοuld be the side lengths οf a triangle is:

D. 4m, 11m, 9m

A triangle is a clοsed twο-dimensiοnal shape that has three straight sides and three angles. It is οne οf the basic shapes in geοmetry and can be classified accοrding tο the length οf its sides and the size οf its angles. The sum οf the interiοr angles οf a triangle is always 180 degrees, which is a fundamental prοperty οf triangles.

The set οf measurements that cοuld be the side lengths οf a triangle is:

D. 4m, 11m, 9m

This is because οf the Triangle Inequality Theοrem, which states that the sum οf any twο sides οf a triangle must be greater than the third side. In set D, the sum οf the twο shοrter sides (4m + 9m = 13m) is greater than the lοngest side (11m), sο these measurements satisfy the Triangle Inequality Theοrem and can be the side lengths οf a triangle.

In sets A, B, and C, the sum οf the twο shοrter sides is nοt greater than the lοngest side, sο these sets οf measurements dο nοt satisfy the Triangle Inequality Theοrem and cannοt be the side lengths οf a triangle.

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Answer:

Area of the given figure is 51.5 square units.

Step-by-step explanation:

Area of rectangle OCBH = Length × width

                                         = 11 × 8

                                         = 88 square units

Area of trapezoid OGEF = \(\frac{1}{2}(b_1+b_2)\times h\)

                                         = \(\frac{1}{2}(\text{GE+OF)}\times (\text{OG})\)

                                         = \(\frac{1}{2}(3+6)\times 4\)

                                         = 18 units²

Area of trapezoid GCDE = \(\frac{1}{2}(\text{GC+DE)}\times (\text{GE})\)

                                         = \(\frac{1}{2}(7+2)\times 3\)

                                         = 13.5 units²

Area of triangle AFH = \(\frac{1}{2}(\text{Base})\times (\text{Height})\)

                                  = \(\frac{1}{2}(5)(2)\)

                                  = 5 units²

Area of polygon ABCDEF = Area of rectangle CBHO - (Area of trapezoid OGEF + Area of trapezoid GCDE + Area of triangle AFH)

                                           = 88 - (18 + 13.5 + 5)

                                           = 88 - 36.5

                                           = 51.5 units²

Therefore, area of the given polygon is 51.5 units²

Answer:

I just edited the file you linked.

Answer:

HERE IS THE REAL ANSWER!!! >

Step-by-step explanation:

I added the file so yeah also its correct!

Answer:

Step-by-step explanation:

Answer:

43

Step-by-step explanation:

hope that helps!

Answer:

I think it's A .....................

Answer:

approximately 28.26 square feet

Step-by-step explanation:

The formula for the area of a circle is A = pi(r)^2. So, the radius is half of the diameter, meaning it's 3 feet. Then we square it to get 9, and multiply by pi, or 3.14. This leads us to the approximated answer of 28.26 square feet.

The area is:

28.27 square feet

Work/explanation:

Since the tabletop is circular, we use the formula for a circle's area, which is: \(\bf{A=\pi r^2}\).

We have the diameter, and to find the radius, we divide the diameter by 2, which gives us 6 ÷ 2 = 3 feet, so the radius of the tabletop is 3 feet.

Now, here's a diagram for you;

\(\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\put(0,0){\line(1,0){2.3}}\put(0.5,0.3){\bf\large 3\ ft}\end{picture}\)

Plug in the data:

\(\sf{A=\pi\times3^2}\)

\(\sf{A=\pi\times9}\)

\(\sf{A=28.27\:ft^2}\)

Answer:

  B.  28%

Step-by-step explanation:

You want to know the percent of the mixture that is fruit juice, if the mixture is 6 L of 52% juice and 9 L of 12% juice.

The total amount of juice in the 6+9 = 15 L of mix is ...

  0.52·(6 L) +0.12(9 L) = 3.12 L +1.08 L = 4.2 L

Then the fraction of the mix that is fruit juice is ...

  (4.2 L)/(15 L) = 0.28 = 28%

The percent of the mixture that is fruit juice is 28%, choice B.

__

Additional comment

Effectively, the fraction is the weighted average of the fractions of the constituents. The weights are the number of liters of each constituent.

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a,b,c,and d

Step-by-step explanation:

there came a time, when a child cheated on their math work. getting the answers they needed wasnt all

they needed someone to make them feel terrible abuot it

and thats what im here to do

PICK ALL OF THEM

MASH YOUR COMPUTER

(a) The algebraic expression, -5x - 2 + 5x + 2 is simplified as 0.

(b) The algebraic expression, 5x -2  - (5x + 2) is simplified as -4.

The given algebraic expression is simplified by adding similar terms together, as it will make the expression to be in simplest form.

The given algebraic expressions are;

-5x - 2 + 5x + 2

5x -2  - (5x + 2)

The first algebraic expression is simplified as follows;

-5x - 2 + 5x + 2

collect similar terms;

(-5x + 5x) + (-2 + 2)

= 0 + 0

= 0

The second algebraic expression is simplified as follows;

5x - 2 - (5x + 2)

= 5x - 2 - 5x - 2

collect similar terms;

= (5x - 5x) + (-2 - 2)

= 0 - 4

= - 4

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Answer:

3:25

Step-by-step explanation:

The photo shows how it's solved.

Answer: 3:25

Step-by-step explanation:

Step 1) Convert the decimal number to a fraction by making 0.12 the numerator and 1 the denominator

0.12 = 0.12/1

Step 2) Multiply the numerator and denominator by 100 to eliminate the decimal point.
0.12 x 100

------------ = 12/100
1 x 100

Step 3) Simplify the fraction in the previous step by dividing the numerator and the denominator by the greatest common factor (GCF) of 12 and 100. (The GCF of 12 and 100 is 4.)

12 ÷ 4

---------  = 3/25  

100 ÷ 4

Step 4) Convert the fraction in the previous step to a ratio by replacing the divider line with a colon like this:  

3  

25   =  3:25

Answer: \(7.39466666\)

Step-by-step explanation:

Setting \(x=2.2\) and \(n=3\),

\(e^{2.2} \approx \sum^{3}_{k=0} \frac{2.2^{k}}{k!}=\frac{2.2^0}{0!}+\frac{2.2^1}{1!}+\frac{2.2^2}{2!}+\frac{2.2^3}{3!} \approx 7.39466666\)

Answer:

7.39466667 (8 d.p.)

Step-by-step explanation:

We can approximate the value of eˣ for any x using the following sum formula:

\(\boxed{e^{x} \approx \displaystyle \sum^n_{k=0}\dfrac{x^k}{k!}}\)

To approximate \(e^{2.2}\) with n = 3, substitute x = 2.2 and n = 3 into the given sum formula:

\(e^{2.2} \approx \displaystyle \sum^3_{k=0}\dfrac{2.2^k}{k!}\)

To calculate the sum, substitute k with each value from 0 to 3 and add the results together:

\(\begin{aligned}e^{2.2} &\approx \displaystyle \sum^3_{k=0}\dfrac{2.2^k}{k!}\\\\&= \dfrac{2.2^0}{0!}+\dfrac{2.2^1}{1!}+\dfrac{2.2^2}{2!}+\dfrac{2.2^3}{3!}\\\\&= \dfrac{1}{1}+\dfrac{2.2}{1}+\dfrac{4.84}{2}+\dfrac{10.648}{6}\\\\&= 1+2.2+2.42+1.774666666...\\\\&=7.39466667\; \sf (8\;d.p.)\end{aligned}\)

Therefore, the approximate value of \(e^{2.2}\) is:

\(\large \textsf{$e^{2.2}$}=\boxed{7.39466667}\; \sf (8\;d.p.)}\)

Note: To obtain a more accurate approximate value, increase the value of n.

With "near doubles facts" or "doubles facts plus one," the actual magic happens. When we observe 7+8, we know that 8 is one more than 7, since we already know that 7+7=14. Thus, 15 is one greater than 14. So, 15 is the answer.

We can also consider the fact that it is one less than the doubles. We are aware that 7 + 7 = 14. I then realise that 6 is one less than 7 when I see 7 plus 6. 14 minus one equals 13, thus.

Thus, our knowledge of ten items with doubles increased to approximately 33 information with near doubles! Therefore, it's a really effective tactic!

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