Answers
Complete Question
The complete question is shown on the first uploaded image
Answer:
The pressure difference of the first bubble is \(\Delta P _1 =10 J/m^3\)
The pressure difference of the second bubble is \(\Delta P _2 =20 J/m^3\)
The pressure difference on the second bubble is higher than that of the first bubble so when the valve is opened pressure from second bubble will cause air to flow toward the first bubble making is bigger
Explanation:
From the question we are told that
The radius of the first bubble is \(r_1 = 10 \ mm=0.01 \ m\)
The radius of the second bubble is \(r_2 = 5 \ mm = 0.005 \ m\)
The surface tension of the soap solution is \(s = 25 \ mJ/m^2 = 25*10^{-3} J/m^2\)
Generally according to the Laplace's Law for a spherical membrane the pressure difference is mathematically represented as
\(\Delta P = \frac{4 s}{R}\)
Now the pressure difference for the first bubble is mathematically evaluated as
\(\Delta P _1 = \frac{4 s}{r_1}\)
substituting values
\(\Delta P _1 = \frac{4 *25 *10^{-3}}{0.01}\)
\(\Delta P _1 =10 J/m^3\)
Now the pressure difference for the second bubble is mathematically evaluated as
\(\Delta P _2 = \frac{4 s}{r_1}\)
\(\Delta P _2 = \frac{4 *25 *10^{-3}}{0.005}\)
\(\Delta P _2 =20 J/m^3\)
Related Questions
On half of the moon appears to be lit (Light is on the RIGHT side of the moon)
this is science btw!!
Answers
Answer:
Moon appears lit on the right half of the Moon during the First Quarter. The Moon appears lit on the left side during the Third Quarter because the Moon is on the other side of Earth. Again, if you think of the baseball analogy, and you’re standing at home plate, the first base or First Quarter is on your right side.
Explanation:
i hope is help
The temperature of an object is
A. The average kinetic energy of its atoms and molecules
B. The total potential and kinetic energy of its atoms and molecules
C. The transfer of kinetic energy from one place or object to another through collisions between atoms and molecules
Answers
A sharpshooter fires a rifle while standing with the butt of the gun against her shoulder. If the forward momentum of a bullet is the same as the backward momentum of the gun, why isn't it as dangerous to be hit by the gun as by the bullet? (Select all that apply.)
The butt distributes the recoil force over an area much larger than that of the bullet.
The rifle has a much lower speed than the bullet.
The rifle has a much smaller kinetic energy than the bullet.
The rifle has much less mass than the bullet.
The rifle has much more total momentum than the bullet.
Answers
It as dangerous to be hit by the gun as by the bullet because of the following;
(A) The butt distributes the recoil force over an area much larger than that of the bullet.
(B) The rifle has a much lower speed than the bullet.
What is principle of conservation of linear momentum?
The principle of conservation of linear momentum states that in an isolated system, the total momentum of the system is conserved.
That is the sum of the initial momentum is equal to the sum of the final momentum.
momentum of the gun = momentum of the bullet
Mu = mU
where;
M is mass of the gunu is the velocity of the gunm is mass of the bulletU is the velocity of the bulletIf the forward momentum of a bullet is the same as the backward momentum of the gun, the speed of the gun will be smaller than the speed of the bullet since the mass of the gun is bigger than mass of the bullet.
We cannot conclude on the kinetic energy, since it depends on both mass and velocity.
Finally, the butt distributes the recoil force over an area much larger than that of the bullet, since the butt has a larger surface area and will hit more surface area than the bullet.
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This circuit has more than one loop. When one light goes out, the
others stay on.
A.open circuit
B.series circuit
C.parallel circuit
D.closed circuit
Answers
Answer:
Parallel circuit
Explanation:
A parallel circuit has a direct current allowing it to go back and forth making it have more pathways and loops. if one light bulb goes out the pathways will allow the electricity to still flow inti the other light bulbs.
How does opening a parachute slow the fall rate of a skydiver?
Answers
Answer:
the air is being stopped in the pocket of the parachutes theys why the parachute has a certain shape so that the air that gets caught inside of it as the skydiver goes down slows down the landing
What happens to the energy of a wave if the amplitude of the wave is doubled?
Answers
If the Amplitude of the wave is doubled the Energy of the wave is quadrupled.
For a wave with Energy \(E\) and Amplitude \(A\) :
\(E \propto A^2\\ \Rightarrow E=kA^2\qquad(1)\)
where \(k\) is the proportionality Constant
If Amplitude is doubled, Then the Energy \(E'\) is given as:
\(E'=k(2A)^2 \\ \Rightarrow E'=4(kA^2) \qquad (2)\)
Using equation (1) in (2), we get:
\(\boxed{E'=4E}\)
So, If the Amplitude of the wave is doubled the Energy of the wave is quadrupled.
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A 100 kg block slides down a frictionless ramp which is at an angle of 26.6 ∘ with the horizontal. Find the magnitude of the velocity of the block when it gets to the bottom of the ramp if the length of the incline is 50 meters. V=_____m/s
Answers
The block accelerates down the ramp due to the component of its weight that acts parallel to the ramp; this force has magnitude
(100 kg) g sin(26.6°) ≈ 438 N
(Note that the positive sign here means we take "down the ramp" to be the positive direction.)
Since the ramp is frictionless, this is the only force acting on the block in this direction. By Newton's second law, the block's acceleration is a such that
438 N ≈ (100 kg) a ⇒ a ≈ 4.38 m/s²
The block accelerates uniformly, so that it attains a speed v as it moves 50 m such that
v² = 2a (50 m)
Solve for v :
v = √(2a (50 m)) ≈ 20.9 m/s
A 0.700kg block is attached to a spring with spring constant 15.0N/m . While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 37.0cm/s . What are
A. The amplitude of the subsequent oscillations?
B. The block's speed at the point where x= 0.400 A?
Answers
The amplitude of the subsequent oscillations is 0.08m and The block's speed at the point where x= 0.400 A is 0.34m/s.
a) conservation of energy
1/2 mv^2 = 1/2 kx^2 + 1/2 mv^2
0.7*.37^2 =15*x^2
x=0.08 m
b) The velocity is
1/2 mv^2 = 1/2 kx^2 + 1/2 mv^2
0.7*.37^2 = 15*(0.4*0.08)^2 + 0.7*v^2
v = 0.34 m/s
Oscillations refer to repetitive back-and-forth motions or fluctuations around a central equilibrium point. These motions can be observed in a wide range of physical systems, such as pendulums, springs, electrical circuits, and waves.Oscillations play an important role in many areas of science and engineering, including physics, chemistry, biology, and electronics.
Oscillations can be characterized by several key properties, including their amplitude (the maximum displacement from the equilibrium point), frequency (the number of oscillations per unit time), and period (the time required to complete one full oscillation). The behavior of oscillatory systems can be described using mathematical equations, such as the harmonic oscillator equation, which relates the restoring force to the displacement of the system from its equilibrium position.
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The dwarf planet, Pluto has 5 known moons. The largest moon, Charon, has a diameter half the size of pluto and a mass about one-eighth of Pluto’s mass. Let the distance between the centres of Charon and Pluto be d. Where along the line joining their centres (with respect to d) would a spaceship feel no net gravitational force? (Assume no other masses impact the spaceship’s gravitational force)
Answers
Pluto Mass: M Diameter: D | Charon: Mass: (1/8)M Diamater: (1/2)D
In order to find where there would be no net gravitational force we need to find where the force of gravity would be equal to each other
f(g) = Gm1(M)/r^2
f(p) = f(c) where p = Pluto and c = Charon
G(m1)(M)/r^2 = G(m1)(M/8)/(d-r)^2 --> start canceling variables
1/r^2 = (1/8)/(d-r)^2
1/r^2 = 1/(8)(d^2 - 2dr +r^2)
r^2 = 8d^2 - 16dr + 8r^2
7r^2 - 16dr + 8d^2 = 0
Solve for r using quadratic formula
r = 16d +- sqrt((16d)^2 - 4(7)(8d^2))/(14)
r = 16d +- sqrt(256d^2 - 224d^2) / 14
r = 16d +- sqrt(32d^2) / 14
r has to be a fraction of d because if it was greater than d, it would be on the other side of Charon
so
r = 16d - 5.6568d / 14 = 10.3432d/14 = ~0.7388d
ow much power does a sound source generate if the intensity is 2.4 X 10-6 w/m2 at a distance of 2.3m?
Answers
The power is generated by the source is \(1.59* 10^-^4\) W.
What is Power?Power is defined as the amount of energy transferred or changed per unit time. The SI unit of power is the watt, which is equal to one joule per second. Power is a scalar quantity.
For above given information,
Intensity= \(2.6* 10^-^6\) \(W/m^2\)
Distance, r= 2.3m
Power is expressed in terms of intensity
\(I=\frac{P}{4\pi r^2}\)
Where, I= intensity
P= Power
r= distance
\(P=I*4\pi r^2\)
\(P=\)\(2.6*10^-^6* (2.3)^2\)
\(P=1.59*10^-^4\) W
Thus, the power is generated by the source is \(1.59* 10^-^4\) W.
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Relate Bernoulli's principle to the sport of your choice.
Answers
Answer:
Daniel Bernoulli – a Swiss physicist and mathematician – discovered that for an inviscid flow of a non-conducting fluid, an increase in the speed of the fluid occurs simultaneously with a decrease in pressure or a decrease in the fluid’s potential energy. * This is known as the Bernoulli Principle.The Bernoulli principle can also be used to describe a downward lift force, such as that required by speed skiers, cyclists and racing cars. The car, bike and skis need to be pushed down into the ground so a greater frictional force is created
Explanation:
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6. A 286 kg gold nugget is attached to the ceiling by a spring with a constant of 9500 N/m and
released from a height of 1.70 m above the floor. If the spring stretches 59.0 cm, what is the elastic
potential energy associated with the spring-nugget system?
Answers
4764 joule is potential energy associated with the spring-nugget system
Potential energy ,P =mgh
mass= 286 kg
g=9.8 m/s^2
h= 1.70 m
P =mgh
P=×286 kg×9.8×1.70
P=4764 joule
Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is squeezed or extended, its potential energy increases. If a steel ball is lifted above the ground as opposed to falling to the ground, it has higher potential energy. It is capable of performing more work when raised. Potential energy is a characteristic of systems rather than of particular bodies or particles; for instance, the system made up of Earth and the elevated ball has greater potential energy as they get further apart.
Potential energy develops in systems having components whose configurations, or relative positions, determine the amount of the forces they apply to one another.
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Which two statements below are central ideas in the article, "How Gross Is Your Bathroom"?
a. What you can't see might hurt you.
b. Different numbers of bacteria are hiding on various surfaces around your bathroom.
c. Most bacteria are harmless, and some are even good for you.
d. Your bathroom is filled with germs that you might not know anything about, including
viruses and bacteria.
Answers
b. Different numbers of bacteria are hiding on various surfaces around your bathroom.
d. Your bathroom is filled with germs that you might not know anything about, including
viruses and bacteria.
1,
An 11-ohm resistor, a 5-ohm resistor, and a 4-ohm resistor are connected in a series across a
10-volt potential difference.
Answers
The current in the circuit is 0.5 A. This is clear from the compilation of the question.
What is the current?We know that the current has to do with the the quotient of the resistance and the voltage of the circuit. In this case we would follow the provisions of the Ohm's law.
Given the Ohm's law;
The effective resistance can be obtained as; 11 + 5 + 4 = 20 ohm
Where V = IR
V = voltage
R = resistance
I = current
Then;
I = V/R
= 10-volt/20 ohm
= 0.5 A
Thus there is the flow of a current of about 0.5 A in the circuit as shown.
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Missing parts;
An 11-ohm resistor, a 5-ohm resistor, and a 4-ohm resistor are connected in a series across a 10-volt potential difference. Find the current
Why do we think that Venus has so much more atmospheric gas than Earth?
Most of the gases that have been released from volcanoes on Earth later returned to the surface.
Venus has gained much more gas through outgassing than has Earth.
Earth has lost much more gas to thermal escape than has Venus.
Because of its lack of magnetic field, Venus has been able to gain gas through the impacts of solar wind particles, while Earth has not gained gas in this way.
Answers
We think Venus has more atmospheric gas than Earth because of its lack of magnetic field, Venus has been able to gain gas through the impacts of solar wind particles, while Earth has not gained gas in this way.
Venus's densest atmosphere of the four terrestrial planets consists of 96% carbon dioxide. Venus's surface atmospheric pressure is 92 times greater than Earth's. With an average surface temperature of 735 K (462 °C; 863 °F), Venus is the hottest planet in the Solar System. The planet has no carbon cycle that captures carbon in rocks and surface features, and no organic life that can sequester carbon in the form of biomass.
Venus may have had oceans, but those oceans are evaporating due to increasing temperatures caused by the continuous greenhouse effect. Much of the water may have photodissociated, and the solar wind has sent free hydrogen rage into space as a result of the lack of an internal magnetic field on Venus. The surface of Venus itself is deserted, dry, and punctuated with rock that is periodically renewed by volcanic activity.
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the temperature of a substance depends on what two types of energy
Answers
Answer:
Thermal and kinetic.
Explanation:
Thermal energy is the energy generated by heat. Kinetic energy is the movement of particles in a substance which is responsible for the heat increase.
Answer:Thermal and kinetic.
Explanation:
an electric field of 800N/C cause a charged ball of 50g mass to make an angle of 30 degree from the vertical whats the charge om fhe ball
Answers
Answer: Charge on the ball is 3.6 ×10^-4 C.
In this question we have given the Electric field of the region we need to find the Charge on the ball .
What is Electric Field?
--An electric field is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.
We used the concept of string ball-- i.e
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A gas is contained in a cylinder with a frictionless moveable piston at a pressure of 2.7 * 105 pascals and a volume of 0.04 cubic meters. What is the work done by the gaseous system if the volume is increased to 0.12 cubic meters ?
Answers
The work done by the gaseous system if the volume is increased to 0.12 cubic meters is given as 21,600 joules
How to solve for the workdoneTo find the work done by the gas, we can use the formula:
W = PΔV
where W is the work done, P is the pressure of the gas, and ΔV is the change in volume.
At the initial state, the pressure is P = 2.7 × 10^5 Pa and the volume is V1 = 0.04 m^3. At the final state, the volume is V2 = 0.12 m^3.
The change in volume is ΔV = V2 - V1 = 0.12 m^3 - 0.04 m^3 = 0.08 m^3.
Substituting these values into the formula, we get:
W = PΔV = (2.7 × 10^5 Pa) × (0.08 m^3) = 21,600 J
Therefore, the work done by the gaseous system is 21,600 joules (J).
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Answer:
4.6x10^4 joules
Explanation:
consider two bodies A and B of masses m1 and m2 moving along the same straight line in the same direction with velocities u1 and u2. the bodies A and B suffer a head on collision when they strike and continue to move along the same straight line of velocities v1 and v2 respectively. Assume the collision is elastic , show that u1 + v1 = u2 + v2
Answers
As the collision is elastic, u₁ + u₂ = v₁ + v₂ must be satisfied.
What is law of momentum conservation?According to the law of momentum conservation, momentum is never created nor destroyed inside a problem domain.
Before collision,
velocity of body A = u₁ velocity of body B = u₂
After collision,
velocity of body A = v₁ velocity of body B = v₂
Hence, according to law of momentum conservation
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
As the collision is elastic, total kinetic energy is also conserved.
1/2m₁u₁² + 1/2m₂u₂² = 1/2m₁v₁² + 1/2m₂v₂²
This two equation satisfy that:
u₁ + u₂ = v₁ + v₂
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Oil-water separation is a very important process in petroleum engineering, as well as in industries that produces oily wastewater and other oil-water pollution. The basic process of oil-water separation is illustrated in the figures below. From left to right, the figures show a simple emulsion in which dispersed (Dutch: verspreidt) oil droplets in water coalesce (come together to form one mass) as time passes. Assume that the number of oil droplets decreases with time (in minutes) following the equation: ൌ െ0.02 a) Calculate how long it takes for half of the oil droplets to coalesce. (3p) b) How long will it take for practically all the oil droplets to coalesce? (2p) c) Provide a sketch of the number of oil droplets as function of time in the oily water. Add relevant values along the axis. (1p) To speed up the process of coalescence, a chemical component (surfactant) is added to the oily water. Assume that now the number of oil droplets decreases with time following the equation: ൌ െ0.02ଶ d) After adding the surfactant to the mixture, can the process still be considered a natural process? Explain. (1p) e) Show that, after adding the surfactant to the oil-water mixture, less time is needed for half of the oil droplets to coalesce. (
Answers
The time required for half of the oil droplets to coalesce is 34.65 minutes.b) Calculation to find how long it takes for practically all of the oil droplets to coalesce:To find the time it would take for practically all of the oil droplets to coalesce, we need to use the following formula and solve for time when n is equal to 0.0 = e^(-0.02t)-infinity = -0.02tNo oil droplets remain after an infinite amount of time. Therefore, it takes an infinite amount of time for all the oil droplets to coalesce.Answer: It takes an infinite amount of time for all the oil droplets to coalesce.
Sketch:We need to sketch the number of oil droplets as a function of time in the oily water. The axis should contain relevant values. As the oil droplets coalesce, the number of oil droplets decreases with time. This is shown by the line in the graph below.Answer: The figure is attached below. The x-axis shows the time in minutes, and the y-axis shows the number of oil droplets present. After adding the surfactant to the mixture, can the process still be considered a natural process? Explain. When a chemical component such as a surfactant is added to the oily water, the oil droplets are artificially made to coalesce. As a result, the process is no longer a natural one because it has been modified by human intervention. Answer: No, the process can no longer be considered natural, because a surfactant was added to the oily water to speed up the coalescence of the oil droplets. Show that less time is needed for half of the oil droplets to coalesce after adding the surfactant to the oil-water mixture. In order to find how long it takes for half of the oil droplets to coalesce after adding the surfactant, we will utilize the new equation that incorporates the surfactant.0.5 = e^(-0.02x)ln(0.5) = -0.02x17.32 minutes = xAnswer: After the addition of the surfactant, it only takes 17.32 minutes for half of the oil droplets to coalesce. This is less time than the original 34.65 minutes that it took before the surfactant was added.For such more question on coalesce
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Which is the correct Lewis structure for carbon monoxide?
А. А
В. B
С. С
D. D
Answers
Answer: Choice B
There are triple bonds between the carbon (C) and oxygen (O) atoms. Then there are 2 dots on either side
==========================================================
Explanation:
When it comes to interaction and chemistry, all that matters is the valence shell or valence electrons. This is the outermost shell. This is because various elements do not interact with the inner electrons (they're locked in place so to speak and don't move to other elements).
Carbon has 6 protons, which is what uniquely makes up this element. This means there are 6 electrons. The inner shell has 2 electrons and the valence shell has 4 electrons. Two electrons are shown as the two blue dots on the left side of the C. The other two electrons form two of the lines, or the bonds, between the C and O.
-------------
Oxygen has 8 protons and 8 electrons. It has 2 electrons in the inner shell and 6 electrons in the valence shell. Two of those electrons are the red dots on the right side of the O. The other 4 electrons are shared to form the bonds with the carbon atom.
This is where things get a bit tricky. I've shown a diagram below indicating that one of the oxygen electrons (red dot) is passed to the carbon, as this carbon atom is pulling on the oxygen electron. But the oxygen atom is pulling on it as well, which forms one of the triple bonds.
So this is why diagram B is the final answer. This is something you can logically determine (remembering the rules of how each electron shell is formed), or it's something you'll need to memorize. In the real world, it's easy to forget a lot of info like this, so that's why having it handy as a lookup reference is preferable.
How do you find the centripetal acceleration without the radius???? I genuinely don’t know what to do.
Answers
Answer:
In order to calculate the value of force without radius, you may need the circumference whose formula is C=2πr. You can also find this force by calculating just acceleration using the formula: And this is also called Newton’s second law of motion, which can be calculated by entering acceleration and mass of the object.
hope this is what you want
Explanation:
“while parachuting” does this has effectWhile parachuting, a 65.0kg person experiences a downward acceleration of 2.70m/s^2. What is the downward force on the parachute from the person?
Answers
We have the next information
m=mass=65
a=acceleration=2.70 m/s^2
We can use the next formula to find the force
\(DF=mg-ma\)where DF is the downward force and g is the gravity
\(DF=(65)(9.8)-(65)(2.7)\)\(DF=461.5\text{ N}\)what is the pressure of a tank of uniform cross sectional area 4.0m2 when the tank is filled with water a depth of 6m when given that 1 atm=1.013 x 10^5pa density of water=1000kgm-3 g=9.8m/s2
Answers
The pressure of the tank, when filled with water at a depth of 6 m, is approximately 580.124 atmospheres (atm). To calculate the pressure of the tank, one can use the equation: Pressure (P) = Density (ρ) × g × Depth (h)
Pressure (P) = Density (ρ) × g × Depth (h)
Given: Density of water (ρ) = 1000 kg/m³
Acceleration due to gravity (g) = 9.8 m/s²
Depth (h) = 6 m
Using the given values, one can calculate the pressure:
Pressure = 1000 kg/m³ × 9.8 m/s² × 6 m Pressure
= 58800 kg·m⁻¹·s⁻²
Now, let's convert the units to pascals (Pa) using the conversion 1 atm = 1.013 x \(10^5\) Pa:
Pressure = 58800 kg·m⁻¹·s⁻² × (1 atm / 1.013 x\(10^5\) Pa)
Pressure = 580.124 atm
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Water moves through a constricted pipe in steady, ideal flow. At the lower point shown in the figure below, the pressure is 1.65 ✕ 105 Pa and the pipe radius is 2.50 cm. At the higher point located at y = 2.50 m, the pressure is 1.22 ✕ 105 Pa and the pipe radius is 1.60 cm. Find the speed of flow in the lower section.
(b) Find the speed of flow in the upper section.
m/s
(c) Find the volume flow rate through the pipe.
m3/s
Answers
The negative outcome indicates a flaw in the information provided or how the issue was put up because the flow rate cannot be fictional or negative.
Calculation-It can be expressed as:
P1 + (1/2)ρv1^2 + ρgh1 = P2 + (1/2)ρv2^2 + ρgh2
the terms involving h cancel out in the equation, and we can solve for v1:
P1 + (1/2)ρv1^2 = P2 + (1/2)ρv2^2
v1 = √(P2 - P1))/ρ)
Substituting the given values for P1, P2, and ρ into the equation,
\(v1 = \sqrt(1.22 x 10^5 - 1.65 x 10^5))/1000) = \sqrt(-0.43)\)
B) The same formula (v2) may be used to get the flow rate in the top part.
v2 = sqrt((2(P1 - P2))/ρ)
\(v2 = \sqrt{2} (1.65 x 10^5 - 1.22 x 10^5))/1000) =\sqrt(0.86) ≈ 0.93 m/s\)
C) The following formula may be used to get the volume flow rate (Q) via the pipe:
Q = Av
A1 = πr1\(1^{2}\); at point 2, the cross-sectional area A2 = πr\(2^2\).
we get:
Q = A1v1 = πr1^2v1
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Pick 3 different acitivities of those listed or of your own preference. Make a prediction about which activity should use the most work energy and power. Fill out the chart below as you complete 10 reps of each activity.mass = 82 kgPush-ups:t= 14.64s (10)d= 56cm -30cm =26cmStair rund= 146cmt1= 2.39st2= 2.05st(3-10)= 2.05sSquatsd= 100cm-79cm = 21cmt= 14.43s (10)
Answers
Given that the mass is m = 82 kg.
For pushups,
The initial velocity is u = 0 m/s
The distance is 26 cm = 0.26 m
The time is
\(\begin{gathered} t=\frac{14.64}{10} \\ =1.464\text{ s} \end{gathered}\)First, we have to find final velocity,
\(\begin{gathered} v=\frac{d}{t} \\ =\frac{0.26}{1.464} \\ =0.177\text{ m/s} \end{gathered}\)The acceleration can be calculated as
\(\begin{gathered} a=\frac{v-u}{t} \\ =\frac{0.177-0}{1.464} \\ =0.12m/s^2 \end{gathered}\)The force will be
\(\begin{gathered} F=ma \\ =82\times0.12 \\ =9.84\text{ N} \end{gathered}\)The number of reps = 10
The work done will be
\(\begin{gathered} W=\text{Force}\times dis\tan ce \\ =9.84\times0.26\text{ m} \\ =2.5584\text{ J} \end{gathered}\)This is for one repetition.
For 10 repetitions the work will be
\(\begin{gathered} W_{10}=2.5584\times10 \\ =25.584\text{ J} \end{gathered}\)The time taken for 10 repetitions will be 14.64 s.
The power will be
\(\begin{gathered} P=\frac{W_{10}}{t} \\ =\text{ }\frac{\text{25.584}}{14.64} \\ =1.747\text{ W} \end{gathered}\)For staircase,
Distance, d = 146 cm = 1.46 m
The time will be
\(\begin{gathered} t\text{ = }\frac{2.39+(9\times2.05)}{10} \\ =2.084\text{ s} \end{gathered}\)The initial velocity is u = 0 m/s
The final velocity is
\(\begin{gathered} v=\frac{d}{t} \\ =\frac{1.46}{2.084\text{ }} \\ =0.700\text{ m/s} \end{gathered}\)The acceleration will be
\(\begin{gathered} a=\frac{0.7-0}{2.084} \\ =0.335m/s^2 \end{gathered}\)The force will be
\(\begin{gathered} F=\text{ ma} \\ =82\times0.335 \\ =27.47\text{ N} \end{gathered}\)The number of repetitions = 10
The work will be
\(\begin{gathered} W=F\times d \\ =27.47\times1.46 \\ =40.106\text{ J} \end{gathered}\)For 10 repetitions, the work done will be
\(\begin{gathered} W=10\times40.106 \\ =401.06\text{ J} \end{gathered}\)The time will be
\(t=\text{ 20.84 s}\)The power will be
\(\begin{gathered} P=\frac{W_{10}}{t} \\ =\frac{401.06}{20.84} \\ =19.24\text{ W} \end{gathered}\)For squats,
The distance will be d = 21 cm = 0.21 m
The time will be
\(\begin{gathered} t=\frac{14.43}{10} \\ =1.443\text{ s} \end{gathered}\)The initial velocity is u = 0 m/s
The final velocity will be
\(\begin{gathered} v=\frac{d}{t} \\ =\frac{0.21}{1.443} \\ =0.145\text{ m/s} \end{gathered}\)The acceleration will be
\(\begin{gathered} a=\frac{v-u}{t} \\ =\frac{0.145-0}{1.443} \\ =0.1004m/s^2 \end{gathered}\)The force will be
\(\begin{gathered} F=ma \\ =82\times0.1004 \\ =8.23\text{ N} \end{gathered}\)The number of repetitions will be 10.
The work done will be
\(\begin{gathered} W=F\times d \\ =8.23\times0.21 \\ =1.73\text{ J} \end{gathered}\)The work done for 10 repetitions will be
\(\begin{gathered} W_{10}=1.73\times10 \\ =17.3\text{ J} \end{gathered}\)The time taken will be 14.43 s.
The power will be
\(\begin{gathered} P=\frac{W_{10}}{t} \\ =\frac{17.3}{14.43} \\ =1.19\text{ W} \end{gathered}\)Which statement correctly describes both gas and liquids?
Answers
Answer:
Their shape change when they are in different cointainers
1.Has no definate shape......!
Which is an electric circuit that produces a magnetic field?
Magnetic battery
coil magnet
coil circuit
electromagnet
Answers
Answer:
its and electromagnet
Answer:
D
Explanation:
an ac generator is connected across the terminals of a 3.25-µf capacitor. determine the frequency at which the capacitive reactance is 375 ω.
Answers
The frequency at which the capacitive reactance is 375 ω and the Capacitance of 3.25 μF is 131 s⁻¹.
Capacitance is the ability or capacity of the substance to collect and store electrical energy and the unit of capacitance is Farad (F). Capacitive reactance is the term that measures the opposition to current flow in the AC circuits and the unit of capacitive reactance is the ohm(Ω).
From the given,
The capacitive reactance (Xc) = 375ω
capacitance (C) = 3.25μF
capacitive reactance Xc = 1/(2π×f×C)
Frequency (f) = 1/(2π×Xc×C)
= 1/(2×3.14×375×3.25×10⁻⁶)
= 131 s⁻¹.
Thus, the frequency of the capacitive reactance is 131 s⁻¹.
To learn more about Capacitive reactance:
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Peter, a 100 kg basketball player, lands on his feet after completing a slam dunk and then immediately jumps up again to celebrate his basket. When his feet first touch the floor after the dunk, his velocity is 5 m/s downward; when his feet leave the floor 0.50 s later, as he jumps back up, his velocity is 4 m/s upward. a. What is the impulse exerted on Peter during this 0.50 s
Answers
Answer:
Explanation:
Impulse = change in momentum
Initial momentum = mass x initial velocity = 100 x 5 = 500 kg m/s
final momentum = mass x final velocity = 100 x - 4 = -400 ( - ve sign due to reversal of direction )
change in momentum = final momentum - initial momentum
= - 400 - 500 = - 900 kg m/s .
As it is - ve , it acts upwards .
So magnitude of impulse on Perter = 900 kg m/s