Consider the following matrix.
A = 1 2 −1 1
2 1 −1 3
1 −4 1 3
Find a basis for the column space of A. (If a basis does not exist, enter DNE into any cell.) Find a basis for the row space of A. (If a basis does not exist, enter DNE into any cell.) Find a basis for the null space of A. (If a basis does not exist, enter DNE into any cell.) Verify that the Rank-Nullity Theorem holds. (Let m be the number of columns in matrix A.) rank(A) = nullity(A) = rank(A) + nullity(A) = = m

Answer:

hola hi

La verdad no se Inglés y no te podría ayudar

Answer:

x=6

Step-by-step explanation:

25^3=15,625

5^6=15,625

Therefore, x=6

Answer:

x=6.........................................................

Answer:

134.4

Step-by-step explanation:

134.4432966

Just find the Square Root of 18,075 (I punched it into my calculator.)

Answer:

-134.44 and 134.44.

Step-by-step explanation:

There are 2 numbers +/- √18,075

= +/- 134.44

Answer:

36

Step-by-step explanation:

Divide the carton weight by the weight of 1 jar

27 ÷ \(\frac{3}{4}\)

= 27 × \(\frac{4}{3}\)

= \(\frac{27(4)}{3}\)

= \(\frac{108}{3}\)

= 36

There are 36 jars in a carton

Answer:

Step-by-step explanation:

j - h(j - h),  if j = 4, h = -6

y(5 - (6 - z)), if y = 4, z = -6

x(h - x/2) + h, if x = 2, h = 6

Answer:

it's the last one

Answer:

Step-by-step explanation:

D- 28/-4

Answer:

a) y=4

b) x=8

Step-by-step explanation:

a) y will always be equal to 4 for this equation, so y=4

b) y will always be equal to 8 for this equation, so x=8

Answer:

Only A is true

for sure

....................

Answer:

-13 is the answer I think so but wait for others also because my could be wrong

Answer: r  =  3.2666  or 3.3

Step-by-step explanation:

use the distributive property

     3r +9. 6 + 1 = 19.9

     3r + 10.1 = 19.9

          - 10.1    - 10.1

     3r = 9.8

     3r/3  =  9.8/3

       r  =  3.2666

              3.3

Answer:

C. 50%

Step-by-step explanation:

Sana makatulong

Answer:

d. 60%

Explanation:

12 ÷ 20 × 100%

= 0.6 × 100%

= 60%

i hope this helps! :D do comment if you need me to clarify anything

If A and B are sets with A⊆B the a) A ∪B = B, b) A∩B = A.

a) Let A⊆B

Let x ∈ A∪B

Then x ∈ A or x ∈ B .....(i)

By definition of union we have

x ∈ A ⇒ x ∈ B .....(ii)

Using (i) and (ii), if x ∈ A, then x ∈  b. If x ∈ B, then clearly x ∈ B.

Thus given A⊆ B, then A∪B = B.

b) First assume A∩B which implies that x ∈ A and x ∈ B.

Hence we can implies the

A∩ B ⊆ A (we started with the element in A∩B and concluded that it is in A) ------(i)

Now, let x ∈ A which implies x ∈ B ( as A⊆ B)

Hence, x ∈ A∩B, which in turn imply

A ⊆ A∩B -----(ii)

From (i) and (ii) we get

A∩B = A

Therefore if A and B are sets with A⊆B, then A ∩B = B and A∩B = A.

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\(▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)

Value of x is :

\( \large \boxed{ \mathfrak{Explanation}}\)

\(\huge{\mathfrak{Kaul}}\)

Answer:

5,000 passengers

Step-by-step explanation:

1. Find out how many trains leave each hour.

6 min – 60/6 = 10 x 200 passengers = 2000

10 min – 60/10 = 6 x 200 passengers = 1200

12 min – 60/12 = 5 x 200 passengers = 1000

15 min – 60/15 = 4 x 200 passengers = 800

2. Add it all up.

2000 + 1200 + 1000 + 800 = 5000 passengers

Answer:

5000

Step-by-step explanation:

6 minute train leaves 10 times

10 x 200 = 2000 passengers

10 minute train leaves 6 times

6x200 = 1200

12 minute train leaves 5 times

5x200 =1000

15 minute train leaves 4 times

4x200 =800

2000+1200+1000+800=5000

assuming more than 1 train can be at the station at once

Answer:

Step-by-step explanation:

As per the picture

also

Therefore

The value of 7 after converted into decimals is 7.0.

To convert the integer 7 into a decimal, you simply need to place a decimal point after the 7 and add a zero to the right of the decimal point. This is because in the decimal system, each digit to the right of the decimal point represents a power of 10, starting with 10^-1 or 0.1.

Therefore, 7 can be represented as 7.0 in decimal form. Note that trailing zeros to the right of the decimal point do not change the value of the number. In other words, 7, 7.0, and 7.00 all represent the same value in decimal form.

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TRUNCATED to one decimal place, it's 50.2

ROUNDED to one decimal place, it's 50.3

The round-off of 50.272 to 1 decimal place using rules of rounding

numbers are 50.3.

Rounding off numbers means making a number simpler by adjusting it to its nearest place according to certain rules.

Rounding a number to one decimal place means keeping only the first digit after the decimal point and neglecting the rest. In this case, the digit in the second decimal place is 7, which is greater than or equal to 5. As per the rounding rules, if the digit is greater than 5, the preceding digit is increased by 1.

So, 50.272 becomes 50.3 when rounded to one decimal place.

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Step-by-step explanation:

for the perimeter you have to say two brackets live plus height plus with plastic

The surface integral ∫∫aw F. dà directly is zero.To evaluate the surface integral ∫∫aw F.

dà directly, we need to compute the flux of the vector field F across the boundary surfaces of the solid unit cube W.

Let's consider the six faces of the cube: x=0, x=1, y=0, y=1, z=0 and z=1.

For the face x=0, the outward unit normal is -i. So, the flux of F across this face is given by:

∫∫S F. dà = ∫∫D F(-i). dA

where D is the region of the face projected onto the yz plane, which is the square [0, 1] × [0, 1], and dA is the area element on the face.

Thus, we have:

∫∫S F. dà = ∫∫D (-y)i. dA = -∫∫D y dA = -½

Similarly, we can compute the flux across the other faces as follows:

For the face x=1, the outward unit normal is i. So, the flux of F across this face is given by ∫∫D F(i). dA = ½.

For the face y=0, the outward unit normal is -j. So, the flux of F across this face is given by ∫∫D F(-j). dA = -½.

For the face y=1, the outward unit normal is j. So, the flux of F across this face is given by ∫∫D F(j). dA = ½.

For the face z=0, the outward unit normal is -k. So, the flux of F across this face is given by ∫∫D F(-k). dA = -½.

For the face z=1, the outward unit normal is k. So, the flux of F across this face is given by ∫∫D F(k). dA = ½.

Therefore, the total flux of F across the boundary surfaces of the solid unit cube W is:

∫∫aw F. dà = (-½ + ½ - ½ + ½ - ½ + ½) = 0

Hence, the surface integral ∫∫aw F. dà directly is zero.

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When you roll 3 dice, if if you get the same number, you earn 10 $. if you get two numbers the same, you get 5 $. if the numbers are all different, you lose $2, the expected win is $1.25.

Given,

You  roll 3 dice.

In each dice there will be 6 outcomes

Total number of  outcomes = \(6^{3}=216\)

Conditions are

We can find the number of each cases by using the combination method

Number of cases all the outcomes are same =6

Number of cases you get two numbers same = \(6C_{2}\)×3!

=90

Number of cases the numbers are all different= 6×5×4

=120

Therefore the expected win = (6×10+90×5-120×2)÷216

=270÷216

= $1.25

Hence, when you roll 3 dice, if if you get the same number, you earn 10 $. if you get two numbers the same, you get 5 $. if the numbers are all different, you lose $2, the expected win is $1.25.

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Answer:

bag 1 weight minus bag 2 weight

Answer:

y=1/3x-4

Step-by-step explanation:

The point where the line intercepts the y-axis is the y-intercept and where the digit -4 comes from

1/3 comes from how many times the line rises (1) and run (3)

Hope this helps!

Answer:

6885.1 yd^3

Step-by-step explanation:

the shape in the attached image is a sphere.

thus, we are to find the volume of a sphere

Volume = 4/3 nr^3

n = 22/7

r = radius

the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.

A radius is half of the diameter

radius = 23.6/2 = 11.8 ft

4/3 x 22/7 x 11,8^3 = 6885.1 yd^3

the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero

Answer:

Step-by-step explanation:

You want to solve systems of equations by substitution.

Using substitution to solve a system of equations means substituting an expression or variable in one equation with an equal expression or variable found using the other equation.

Here, all of the equations are of the form "y = ( )", so it is appropriate to use one expression for y to substitute for y in the other equation.

Substituting for y, we have ...

  x +6 = -x +2

  2x = -4 . . . . . . . . add x-6 to both sides

  x = -2 . . . . . . . . . divide by 2

  y = -2 +6 = 4 . . . . find y

The solution is (x, y) = (-2, 4).

Substituting for y, we have ...

  2x -2 = x +8

  x = 10 . . . . . . . . add 2-x to both sides

  y = 10 +8 = 18 . . . . find y

The solution is (x, y) = (10, 18).

Substituting for y, we have ...

  -x +4 = 3x

  4 = 4x . . . . . . . . . add x

  1 = x . . . . . . . . . . divide by 4

  y = 3·1 = 3 . . . . . find y

The solution is (x, y) = (1, 3).

If 10% of all resistance exceeding 10.256 ohms, and 5% have resistance less than 9.671 ohms, then the mean value is 10 ohms and standard deviation of resistance distribution is 0.2 ohms.

To determine mean-value and standard deviation of resistance distribution, we use properties of normal-distribution and given information.

We denote the mean value of resistance distribution as μ and standard deviation as σ.

We know that 10% of all resistors exceed 10.256 ohms, The z-score represents the number of standard deviations away from the mean.

We know that the z-score corresponding to the 10% percentile is approximately 1.28,

Similarly, also given that 5% of resistors have resistance smaller than 9.671 ohms, We also know that the z-score for the 5% percentile is approximately -1.64,

The z-score equation for the 10% percentile : 10.256 = μ + 1.28σ,

The z-score equation for the 5% percentile : 9.671 = μ - 1.64σ,

Now we solve these two equations to find the values of μ and σ.

From equation(1), we rewrite it as : μ = 10.256 - 1.28σ,

Substituting this expression for μ into equation(2), We get :

9.671 = (10.256 - 1.28σ) - 1.64σ

9.671 = 10.256 - 1.28σ - 1.64σ

9.671 = 10.256 - 2.92σ

2.92σ = 10.256 - 9.671

2.92σ = 0.585

σ ≈ 0.2,

Substituting this value of σ into equation(1),

We get,

μ = 10.256 - 1.28σ

μ = 10.256 - 1.28 × 0.2

μ ≈ 10.256 - 0.256

μ ≈ 10,

Therefore, the required mean is 10 ohms and standard-deviation is 0.2 ohms.

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The mean value of the resistance distribution is μ and the standard deviation is σ.

To find the mean and standard deviation of the resistance distribution, we can use the properties of a normal distribution.

Let's denote the mean as μ and the standard deviation as σ.

From the given information, we know that 10% of the resistance values exceed 10.256 ohms, and 5% have resistance smaller than 9.671 ohms.

Using the properties of a normal distribution, we can determine the z-scores corresponding to these percentages.

The z-score represents the number of standard deviations a data point is away from the mean.

For the 10% exceeding 10.256 ohms, the z-score can be calculated as:

z = (x - μ) / σ

where x is the resistance value and z is the z-score.

Using a standard normal distribution table or a calculator, we can find the z-score corresponding to the 10% exceeding value. Let's denote this z-score as z1.

Similarly, for the 5% smaller than 9.671 ohms, we can find the z-score corresponding to this percentage and denote it as z2.

Now, we have two equations:

z1 = (10.256 - μ) / σ

z2 = (9.671 - μ) / σ

We can solve these two equations simultaneously to find the values of μ and σ.

Once we have the values of μ and σ, we can conclude that the mean value of the resistance distribution is μ and the standard deviation is σ.

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sin(x) = O(x) and sin(sin(x)) = O(sin(x)) as x → 0, we have sin(sin(x)) = O(x) as x → 0. Therefore, we can write f(x) = O(x) - x = O(x), which means that \(f(x) = O(x^p) if p ≥ 1\). Therefore, f(x) = O(x^p) holds for all p ≥ 1.

lim x→0 |f(x)|/|x^p| = C > 0, then f(x) = O(x^p). For a polynomial f(x) = a_nx^n + a_{n-1}x^{n-1} + ... + a_1x + a_0, we know that f(x) = O(x^p) if p ≥ n. This is because |f(x)|/|x^p| ≤ |a_n| + |a_{n-1}|/|x| + ... + |a_0|/|x^p|, and since all terms except for the last one go to 0 as x → 0, we must have p ≥ n to ensure that |f(x)|/|x^p| → C > 0.For part (a), we have f(x) = x^2, so we know that f(x) = O(x^p) if p ≥ 2.

Therefore, f(x) = O(x^2) as x → 0.For part (b), we have f(x) = 1/x, so we know that f(x) = O(x^p) if p ≤ -1. Therefore, f(x) = O(x^p) does not hold for any p ≥ 0.For part (c), we have f(x) = cos(x) - 1, so we know that f(x) = O(x^p) if p ≥ 0.

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Answer:

skew right;

most of the data is on the left (the start)

Step-by-step explanation:

Observing the data distribution in the leaf plot given, we would see that most of the data are occuring at the start. This can be referred to as a positively skewed data. The tail of the distribution (the thin side) is to the right.

Therefore, the shape can be described as SKEW RIGHT.