Compute and expressed the result as a mixed fraction?

1) 2+ 3/4

Answers

Answer 1

Answer:

2 \(\frac{3}{4}\)

Step-by-step explanation:

2 + \(\frac{3}{4}\)

= 2 \(\frac{3}{4}\) ← as a mixed number


Related Questions

precalculus b dba given a vertical asymptote and a horizontal asymptote, how would you begin to find an expression for a rational function?

Answers

By finding the vertical and horizontal asymptotes, you can use them to help find an expression for the rational function

To find an expression for a rational function given a vertical asymptote and a horizontal asymptote, start by recognizing that the general form of a rational function is f(x) = (ax + b)/(cx + d), where a, b, c, and d are all constants.

Next, use the given information to solve for a, b, c, and d in the equation. The vertical asymptote represents the x-values at which the denominator of the equation equals zero, so set cx + d equal to zero and solve for x. Similarly, the horizontal asymptote can be found by setting ax + b equal to the asymptote’s y-value.

Once both equations are solved for x, substitute the x-values back into the equation for the rational function and solve for the corresponding a, b, c, and d values.

A vertical asymptote occurs when the denominator of the rational function is equal to zero, so you can set the denominator equal to zero and solve for the variable to find the vertical asymptote.

A horizontal asymptote occurs when the degree of the numerator and denominator are equal, so you can look at the leading coefficients of the numerator and denominator to find the horizontal asymptote.

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what is the distance from the number to 0 and is always positive.

Answers

Answer:

Absolute Value

Step-by-step explanation:

– The distance a number is from the zero on a number line. (Absolute value is always positive). Acute Angle - An angle with a measure > than 0° and < 90˚. Acute Triangle– A triangle that has all three angles that are acute.

348 car stereos were recently sold in a car audio store. 131 had a CD player, 133 had a cassette player, and 48 had both a CD and a cassette player. How many had a CD player only

Answers

The 83 car stereos had a CD player only.

Given that,

348 car stereos were recently sold in a car audio store.

131 had a CD player, 133 had a cassette player, and 48 had both a CD and a cassette player.

Let's denote the number of car stereos having only a CD player as 'x'.

Using the given data, we can write,

Total number of car stereos with CD player = number of car stereos with CD player only + number of car stereos with both CD and cassette players

Now, using the values from the given data, we get:

131 = x + 48

Solving this equation for x, we get:

x = 131 - 48 = 83

Therefore, 83 car stereos had a CD player only.

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Sketch curve of the given vector equation. Indicate with an arrow the direction in which t increases
r(t) = < t , 2 - t , 2t >

Answers

The curve of the given vector equation is shown below: It can be seen that the arrow points towards the positive x-axis, which is in the direction of increasing t.

To sketch curve of the given vector equation, r(t) = < t , 2 - t , 2t >, and indicate with an arrow the direction in which t increases, we need to follow some steps.

Step 1: Create a table for the vector. We need to create a table and fill in the values for t, x, y, and z. Let's do it below:

\(tt (time)xx (position)x(t)x(t)(2−t)(2−t)2t2t\)

Step 2: Plotting the points. We can plot the points by simply taking the x, y and z values from the table created above. The curve will pass through these points. The curve will be three-dimensional.

Step 3: Indicate the direction of t. To indicate the direction of t, we use an arrow on the curve. The arrow is drawn such that it starts from the initial point and points in the direction in which the parameter (in this case, t) increases. In this problem, since t increases in a positive direction, we take the arrow pointing towards the positive x-axis.

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Use trigonometric identities to simplify each expression
c) sec^2(pi/2-x) (sin^2(x)-sin^4(x))

Answers

Using trigonometric identities to simplify the expression, we have sec²(π/2 - x) (sin²(x)-sin⁴(x)) = cos²x

What are trigonometric identities?

Trigonometric identities are equations that contain the trigonometric ratios.

How to use trigonometric identities to simplify the expression?

Since we have the trigonometric expression sec²(π/2 - x) (sin²(x)-sin⁴(x))

We desire to simplify it as follows.

sec²(π/2 - x) (sin²(x)-sin⁴(x))

Using the trigonometric identity sec²(π/2 - x) = 1/cos²(π/2 - x), we have that

sec²(π/2 - x) (sin²(x)-sin⁴(x)) = 1/cos²(π/2 - x) × (sin²(x)-sin⁴(x))

Also, using the fact that cos²(π/2 - x) = sinx, we have that

1/cos²(π/2 - x) × (sin²(x)-sin⁴(x)) = (sin²(x) - sin⁴(x))/sin²x

Factorizing out sin²x, we have that

(sin²(x) - sin⁴(x))/sin²x = (sin²(x)(1 - sin²(x))/sin²x

= 1 - sin²x

= cos²x

So, sec²(π/2 - x) (sin²(x)-sin⁴(x)) = cos²x

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Find the lateral and surface area of a cone with an altitude of 5 and a slant height of 91/2 feet

Answers

Answer:

sry i cant i to dubm need points tho

Step-by-step explanation:

2) How much PURE copper must be added to 50.255kg of an allow containing 12% copper
to raise the copper content to 21%

Answers

Answer:

let x=amt of pure copper to add:

12%*50+100%x=21%(50+x)

6+x=10.5+.21x

.79x=4.5

x=5.7

amt of pure copper to add: 5.7 kg

Step-by-step explanation:

At a university, 10% of students smoke. Calculate the expected number of smokers in a random sample of 150 students from this university.

Answers

The expected number of smokers in a random sample of 150 students from this university is 15.

To calculate the expected number of smokers in a random sample of 150 students at a university where 10% of students smoke, you simply multiply the total number of students in the sample by the percentage of students who smoke:
Expected number of smokers = Total number of students x Percentage of smokers
= 150 students x 10%
= 150 x 0.10
= 15
So, if we know that 10% of students smoke at this university, and we have a random sample of 150 students, we can calculate the expected number of smokers as follows:

Expected number of smokers = 150 x 0.10 = 15

Therefore, we can expect that there will be approximately 15 smokers in a random sample of 150 students from this university.


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x + 23
5x + 13
please help

x + 235x + 13please help

Answers

Answer:

x = 2.5 or 5/2.

Step-by-step explanation:

They're congruent angle, so set them equal to each other

5x + 13 = x + 23

Solve for x:

4x = 10

x = 10/4 = 5/2 = 2.5

consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s in the $n^{\rm{th}}$ block. what is the sum of the first $1234$ terms of this sequence?

Answers

Therefore, the sum of the first 1234 terms of this sequence is 1234.

To find the sum of the first 1234 terms of the sequence consisting of 1's separated by blocks of 2's with n 2's in the nth block, we need to determine the number of blocks and the number of 1's in each block.

Let's examine the pattern of the sequence:

Block 1: 2's

= 1's

= 1 (1 2)

Block 2: 2's

= 2's

= 22 (1 22 1)

Block 3: 2's

= 3's

= 222 (1 222 1)

Block 4: 2's

= 4's

= 2222 (1 2222 1)

...

We observe that the number of 2's in each block is equal to the number of the block itself. So, in the nth block, there are n 2's.

Now, let's calculate the number of blocks required to reach the 1234th term:

To find the number of blocks, we need to determine the maximum block number before the 1234th term. We can calculate this by finding the sum of the series 1 + 2 + 3 + ... + n until the sum is greater than or equal to 1234.

The formula for the sum of the series 1 + 2 + 3 + ... + n is given by: S = (n/2)(n+1).

Let's solve this equation:

(n/2)(n+1) = 1234

\(n^2 + n - 2468 = 0\)

Using the quadratic formula:

n = (-1 + √(1 + 4*2468)) / 2

n ≈ 61.76

Since n must be a whole number, we take the ceiling of n, which gives us 62.

Therefore, there are 62 blocks in the sequence.

Next, let's calculate the number of 1's in each block:

In the nth block, there are n 2's. Since each 2 is separated by a 1, there are n + 1 terms in each block.

So, the number of 1's in each block is (n + 1) - n = 1.

Since there is always one 1 between two consecutive blocks, the total number of 1's in the sequence is equal to the number of blocks, which is 62.

Finally, let's calculate the sum of the first 1234 terms:

Each block has n + 1 terms, which gives us (n + 1) + (n + 1) + ... + (n + 1) (62 times).

Sum of (n + 1) repeated 62 times = 62(n + 1)

= 62 * 2

= 124.

In addition to the blocks, we have 1234 - 62 = 1172 remaining terms, which are all 1's.

So, the sum of the first 1234 terms is 62 + 1172 = 1234.

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How many permutations of the three letters C, D, and E are possible? a 3 b 0 c 8 d 6

Answers

The number of possible permutations of the three letters C, D, and E is d.6

A permutation is an arrangement of objects in a specific order. In this case, we are looking at the number of possible arrangements of the three letters C, D, and E. To find the number of permutations, we can use the formula:

n! = n x (n-1) x (n-2) x ... x 3 x 2 x 1

where "n" is the number of distinct objects to be permuted.

So for our problem, we have three distinct objects (C, D, and E). Therefore, we can plug in n=3 to get:

3! = 3 x 2 x 1 = 6

This means there are 6 possible ways to arrange the letters C, D, and E in different orders. We can list all of these permutations as follows:

CDE

CED

DCE

DEC

ECD

EDC

So the answer to the question is 6, as given in option (d).

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Show that the process X(t):=e t/2
cos(W(t)),0≤t≤T, is a martingale w.r.t. any filtration for Brownian motion and represent it as an Itô process on any time interval [0,T],T>0.

Answers

A stochastic process X(t) is called a martingale if the expected value of X(t) given all information available up to and including time s is equal to the value of X(s).

Thus, to show that the process X(t):=e^(t/2)cos(W(t)), 0 ≤ t ≤ T is a martingale w.r.t. any filtration for Brownian motion, we need to prove that E(X(t)|F_s) = X(s), where F_s is the sigma-algebra of all events up to time s.

As X(t) is of the form e^(t/2)cos(W(t)), we can use Itô's lemma to obtain the differential form:dX = e^(t/2)cos(W(t))dW - 1/2 e^(t/2)sin(W(t))dt

Taking the expectation on both sides of this equation gives:E(dX) = E(e^(t/2)cos(W(t))dW) - 1/2 E(e^(t/2)sin(W(t))dt)Now, as E(dW) = 0 and E(dW^2) = dt, the first term of the right-hand side vanishes.

For the second term, we can use the fact that sin(W(t)) is independent of F_s and therefore can be taken outside the conditional expectation:

E(dX) = - 1/2 E(e^(t/2)sin(W(t)))dt = 0Since dX is zero-mean, it follows that X(t) is a martingale w.r.t. any filtration for Brownian motion.

Now, let's represent X(t) as an Itô process on the interval [0,T]. Applying Itô's lemma to X(t) gives:

dX = e^(t/2)cos(W(t))dW - 1/2 e^(t/2)sin(W(t))dt= dM + 1/2 e^(t/2)sin(W(t))dt

where M is a martingale with M(0) = 0.

Thus, X(t) can be represented as an Itô process on [0,T] of the form:

X(t) = M(t) + ∫₀ᵗ 1/2 e^(s/2)sin(W(s))ds

Hence, we have shown that X(t) is a martingale w.r.t. any filtration for Brownian motion and represented it as an Itô process on any time interval [0,T], T > 0.

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A deck of cards has 5 pink, 2 gray, and 6 black cards. You pick 2 cards from the deck without replacement. What is the probability that the first card is gray and the second card is pink?

Answers

1/2 gray and 1/5 and the other one is a pretty good probability for the color

Answer:

\(\frac{5}{78}\)

Step-by-step explanation:

First, find the probability that the first card is gray.

Since there are 13 cards in total, and 2 are gray, the probability will be 2/13

Next, find the probability that the second card is pink.

Since there are now 12 cards in total (since there is no replacement), and 5 are pink, the probability is 5/12.

Now, to find the probability that these are drawn in order, multiply the probabilities together:

\(\frac{2}{13}\) x \(\frac{5}{12}\)

= \(\frac{5}{78}\)

So, the probability is \(\frac{5}{78}\)


Find the critical value Za/2 corresponding to a 99.5% confidence level.
0.0025
2.575
2.81
1.96​

Answers

Answer:

The correct option is;

2.81

Step-by-step explanation:

The critical value \(Z_{\alpha /2}\), is found from the z score table as follows, where the the confidence level is 99.5

Therefore, we have α = 1 - 99.5/100 = 1 - 0.995 = 0.005

α/2 = 0.0025

The critical value is thus found from the z-score table value of 1 - 0.0025 = 0.9975

From the z-table, we can find the 0.9975 score on the row  with z = 2.8 where 0.9975 can be located under the 0.1 column giving the critical value as 2.81

You have been given this probability distribution for the holding-period return for Cheese, Inc. stock: Assuming that the expected return on Cheese's stock is 14.35%, what is the standard deviation of these returns?
A. 4.72%
B. 6.30%
C. 4.38%
D. 5.74%
E.None of the options

Answers

Without the probability distribution, it is not possible to calculate the standard deviation accurately. Thus, none of the provided options can be considered correct without additional information.

Show me how to calculate the standard deviation of the returns?

To calculate the standard deviation of the returns, we need the probability distribution of the holding-period returns and their corresponding values. Since the probability distribution is not provided in your question, it is not possible to determine the standard deviation.

To calculate the standard deviation, you would typically need the individual returns and their corresponding probabilities. With that information, you can use the formula for calculating the weighted standard deviation:

σ = √[∑(Ri - E(R))^2 * P(Ri)],

where Ri represents the individual returns, E(R) is the expected return, and P(Ri) is the probability of each return.

Without the probability distribution, it is not possible to calculate the standard deviation accurately. Thus, none of the provided options can be considered correct without additional information.

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Solve this equation by taking the square roots

3x(2) -75=0


Please show the steps
30 POINTS

Solve this equation by taking the square roots 3x(2) -75=0 Please show the steps 30 POINTS

Answers

Answer:

Step-by-step explanation:

1 3^2 is =

subtract what u get from up here

boooooom

solve the following system by substitution y=5x-4 y=6x​

solve the following system by substitution y=5x-4 y=6x

Answers

Answer:

Step-by-step explanation:

y = 5x - 4

y = 6x $\Rightarrow$ x = y/6

y = 5*y/6 - 4

y = 5y/6 - 4

6y = 5y - 24

y = -24.

So, x = -4

a researcher obtained independent random samples of men from two different towns. she recorded the weights of the men. the results are summarized below: town a town b n 1

Answers

We do not have sufficient evidence to conclude that there is more variation in weights of men from town A than in weights of men from town B at the 0.05 significance level.

To test the claim that there is more variation in weights of men from town A than in weights of men from town B, we can perform an F-test for comparing variances. The null hypothesis (H₀) assumes equal variances, and the alternative hypothesis (Hₐ) assumes that the variance in town A is greater than the variance in town B.

The F-test statistic can be calculated using the sample standard deviations (s₁ and s₂) and sample sizes (n₁ and n₂) for each town. The formula for the F-test statistic is:

F = (s₁² / s₂²)

Substituting the given values, we have:

F = (29.8² / 26.1²)

Calculating this, we find:

F ≈ 1.246

To determine the critical value for the F-test, we need to know the degrees of freedom for both samples. For the numerator, the degrees of freedom is (n1 - 1) and for the denominator, it is (n₂ - 1).

Given n₁ = 41 and n₂ = 21, the degrees of freedom are (40, 20) respectively.

Using a significance level of 0.05, we can find the critical value from an F-distribution table or using statistical software. For the upper-tailed test, the critical value is approximately 2.28.

Since the calculated F-test statistic (1.246) is not greater than the critical value (2.28), we fail to reject the null hypothesis. Therefore, based on the given data, we do not have sufficient evidence to conclude that there is more variation in weights of men from town A than in weights of men from town B at the 0.05 significance level.

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The question is incomplete the complete question is :

A researcher obtained independent random samples of men from two different towns. She recorded the weights of the men. The results are summarized below:

Town A

n1 = 41

x1 = 165.1 lb

s1 = 29.8 lb

Town B

n2 = 21

x2 = 159.5 lb

s2 = 26.1 lb

Use a 0.05 significance level to test the claim that there is more variation in weights of men from town A than in weights of men from town B.

Two apps on your phone take away points for using your phone at school. You have 140 points on the first app and 80 points on the second app when a school day begins. Each time you check your phone, you lose 10 points on your first app and $p$ points on your second app. After you check your phone ten times, you have the same number of points on each app. Find the value of $p$

Answers

Answer: p = 4

Step-by-step explanation:

For app one, you start with 140 points, and you lose 10 each time you check your phone.

Then, if you check your phone x times, you will have:

140 - x*10 points in total.

For app two, you start with 80 points, and you lose p points each time you check your phone.

Then, if you check your phone x times, you will have:

80 - x*p points left

We know that when x = 10, you have the same number of points in both apps, then we have the equation:

140 - (10)*10 = 80 - (10)*p

We can solve this for p

140 - 10*10 = 80 - 10*p

140 - 100 = 80 - 10*p

40 = 80 - 10*p

10*p = 80 - 40

10*p = 40

p = 40/10 = 4

write the polynomial in standard form

(x - 3)(x - 3)(x - 1)

please help me, im so confused











pretty please

Answers

Answer:

Step-by-step explanation:

To write the polynomial in standard form, we first need to multiply out the terms using the distributive property. We can start by multiplying the first two factors:

(x - 3)(x - 3) = x(x) - 3(x) - 3(x) + 3(3) = x^2 - 6x + 9

Now we can multiply this result by the third factor:

(x^2 - 6x + 9)(x - 1) = x(x^2) - x(6x) + x(9) - 1(x^2) + 1(6x) - 1(9)

Simplifying this expression by combining like terms, we get:

x^3 - 8x^2 + 21x - 9

So the polynomial in standard form is:

f(x) = x^3 - 8x^2 + 21x - 9

X^3-7x^2+15x-9

Polynomial is 3

what number should be included in the data 2,8,7,4 and 9 so that the mean is 6?

Answers

6The mean is already six.2 + 8 + 7 + 4 + 9 = 3030 ÷ 5 = 6If you have to add another number, it would be six, so the mean stays the same :)2 + 8 + 7 + 4 + 9 + 6 = 3636 ÷ 6 = 6

pirya has picked 1 1/2 cups of raspberries, which is enough for 3/4 of a cake how many cups does she need for the whole cae

Answers

Pirya needs 1 1/2 cups of raspberries for 3/4 of a cake, so she needs 1 1/2 * (4/3) = 2 cups of raspberries for the whole cake.

What is fraction?

A fraction is a numerical representation of a portion of a total. It consists of two integers, a numerator and a denominator, separated by a line or slash. The numerator reflects the number of equal portions of the whole that are being considered, while the denominator represents the total number of equal parts in the whole. For instance, the fraction "1/2" denotes one of two identical pieces, or half, of the whole. Mathematicians frequently utilize fractions to represent quantities, ratios, and proportions. They are also used in everyday life to signify amounts, such as one-half of a pizza or one-third of a cups of sugar.

How to solve?

she needs 1 1/2 * (4/3) = 2 cups of raspberries for the whole cake.

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1.Consider a 64-bit architecture machine where physical memory is 128GB a.If we would like to run processes as big as 256GB how many bits would be required for the logical address? 38 2 9& 25661 b.If we are using pages of size 4KB, how many bits are needed for displacement into a page? 12 bits 4KB= c.If a single level page table is used, what is the maximum number of entries in this table? 38 26 entries d.What is the size of this single level page table in terms of 4KB pages? 2o Pages e. If a two-level page-table is used and the outer page table is an 4KB page,how many entries does it contain, maximally? f. How many bits of the logical address are used to specify an index into the inner page (page of page table)?

Answers

a).  2^38 bytes of memory

b). 12 bits

c). The maximum number of entries in the single-level page table would be 2^38.

d). The size would be 2^38 * 4KB, which equals 2^20 pages.

e). The maximum number of entries it can have depends on the remaining bits of the logical address.

f). The amount of bits required to denote an index into the inner page table is obtained by subtracting the offset and outer page index bits from the logical address.

a. To address a physical memory size of 128GB (2^37 bytes), a 64-bit architecture would require 38 bits for the logical address, allowing access to a maximum of 2^38 bytes of memory.

b. Given that the page size is 4KB (2^12 bytes), 12 bits would be needed to specify the displacement into a page. This means that the lower 12 bits of the logical address would be used for page offset or displacement.

c. With a single-level page table, the maximum number of entries would be equal to the number of possible logical addresses. In this case, since the logical address requires 38 bits, the maximum number of entries in the single-level page table would be 2^38.

d. The size of the single-level page table is determined by the number of entries it contains. Since each entry maps to a page of size 4KB, the size of the single-level page table can be calculated by multiplying the number of entries by the size of each entry. In this case, the size would be 2^38 * 4KB, which equals 2^20 pages.

e. For a two-level page table, the size of the outer page table is determined by the number of entries it can contain. Since the outer page table uses 4KB pages, the maximum number of entries it can have depends on the remaining bits of the logical address. The number of bits used for the index into the outer page table is determined by subtracting the bits used for the inner page index and the offset from the total number of bits in the logical address.

f. The number of bits used to specify an index into the inner page table can be determined by subtracting the bits used for the offset and the bits used for the outer page index from the total number of bits in the logical address. The remaining bits are then used to specify the index into the inner page table.

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Please quickly do number 12 & 13 I'll give brainliest.

Please quickly do number 12 &amp; 13 I'll give brainliest.

Answers

Answer:

y=3.7x + 120.3, 180

Step-by-step explanation:

Add them into a graphing calculator and you get y=3.7x + 120.3

Put 16 in for x:

3.7 (16) + 120.3

59.2 + 120.3 = 179.5, rounds to 180

A skateboarder wants to build a ramp to get over a cement wall. The height of the wall is 10 feet. If the ramp is 20 feet long, what is the angle of elevation between the ground and the ramp?

Answers

Answer:

θ = 30°

Angle of elevation is 30°

Step-by-step explanation:

Given;

Height of wall w = 10 ft

Length of ramp l = 20 ft

Angle of elevation = θ

Applying trigonometry;

Sinθ = opposite/hypothenuse

Where;

Height of wall w = opposite (it's opposite the angle of elevation)

Length of ramp l = hypothenuse

Sinθ = w/l

θ = arcsine (w/l)

Substituting the values;

θ = arcsine (10/20)

θ = arcsine (0.5)

θ = 30°

Angle of elevation is 30°

Which of these following lies between 6. 3 and 6. 6
6. 2
6. 9
6. 05
6. 41

Answers

The number that lies between 6.3 and 6.6 is 6.41.

What is the quotient of StartStartFraction 90 (cosine (StartFraction pi Over 4 EndFraction) + I sine (StartFraction pi Over 4 EndFraction) ) OverOver 2 (cosine (StartFraction pi over 12 EndFraction) + I sine (StartFraction pi Over 12 EndFraction) ) EndEndFraction ?


45 (cosine (StartFraction pi Over 3 EndFraction) + I sine (StartFraction pi Over 3 EndFraction) )

88 (cosine (StartFraction pi Over 3 EndFraction) + I sine (StartFraction pi Over 3 EndFraction) )

45 (cosine (StartFraction pi Over 6 EndFraction) + I sine (StartFraction pi Over 6 EndFraction) )

88 (cosine (StartFraction pi Over 6 EndFraction) + I sine (StartFraction pi Over 6 EndFraction) )


I think it's c/the third option

Answers

Answer:

The answer is C

Step-by-step explanation:

Answer:C

Step-by-step explanation:

got it right on edge2022

alr help me on this one.

alr help me on this one.

Answers

Answer:

-1

Step-by-step explanation:

In a trend that scientists attribute, at least in part, to global warming, a certain floating cap of sea ice has been shrinking since 1980.
the ice cap always shrinks in the summer and grows in winter. average minimum size of the ice cap, in square miles, can be
approximated by a= pir^2. in 2013, the radius of the ice cap was approximately 792 mi and was shrinking at a rate of approximately
4.1 mi/yr. how fast was the area changing at that time?
the area was changing at a rate of in 2013.
(round to the nearest integer as needed.)

Answers

Therefore, the area of the ice cap was changing at a rate of approximately -20629 square miles per year in 2013.

To find the rate at which the area of the ice cap was changing in 2013, we can use the formula for the derivative of the area with respect to time.

Given:

Radius of the ice cap (r) = 792 mi

Rate of change of radius (dr/dt) = -4.1 mi/yr (negative because the radius is shrinking)

The formula for the area of a circle is A = πr²

Taking the derivative of both sides of the equation with respect to time (t), we get:

dA/dt = 2πr(dr/dt)

Substituting the given values:

dA/dt = 2π(792)(-4.1)

Calculating the value:

dA/dt ≈ -20629

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2. The tensions T₁, T2 and 7 in a simple framework are given by the equations 5T₁ +3T2 +5T3=70 T₁ +2T₂ +4T3 = 24 4T1 +2T2= 40 Use Guases elimination ONLY to find T₁, T2. T 3.

Answers

The value of tensions are:

T₁ = 231/74

T₂ = -329/66

T₃ = 8/33

We can use Gaussian elimination to solve the system of equations:

5T₁ + 3T₂ + 5T₃ = 70

T₁ + 2T₂ + 4T₃ = 24

4T₁ + 2T₂ = 40

First, we'll use the third equation to eliminate T₂ from the first two equations:

4T₁ + 2T₂ = 40   (equation 3)

T₁ + 2T₂ + 4T₃ = 24   (equation 2)

Multiplying the third equation by 2 and subtracting it from the second equation:

T₁ + 2T₂ + 4T₃ = 24   (equation 2)

- 8T₁ - 4T₂ = -80   (2 × equation 3)

------------------------

-7T₁ + 4T₃ = -56

Now we have two equations:

5T₁ + 3T₂ + 5T₃ = 70   (equation 1)

-7T₁ + 4T₃ = -56   (from previous step)

Multiplying the first equation by 7/5 and adding it to the second equation:

5T₁ + 3T₂ + 5T₃ = 70   (equation 1)

-7T₁ + 4T₃ = -56   (from previous step)

------------------------

T₁ + 7T₃ = 14

Now we can use the third equation to eliminate T₂ from the first equation:

4T₁ + 2T₂ = 40   (equation 3)

5T₁ + 3T₂ + 5T₃ = 70   (equation 1)

Multiplying the third equation by 3/2 and subtracting it from the first equation:

4T₁ + 2T₂ = 40   (equation 3)

-11T₁ - T₃ = -35   (3 × equation 3 - 5 × equation 1)

Now we have two equations:

T₁ + 7T₃ = 14   (from previous step)

-11T₁ - T₃ = -35   (from this step)

Multiplying the second equation by -7 and adding it to the first equation:

T₁ + 7T₃ = 14   (from previous step)

74T₁ = 231

Therefore, T₁ = 231/74.

Substituting this value back into the equation T₁ + 7T₃ = 14, we get:

(231/74) + 7T₃ = 14

7T₃ = (74/231) × 20

T₃ = 8/33

Finally, substituting T₁ = 231/74 and T₃ = 8/33 into the equation -11T₁ - T₃ = -35, we get:

-11(231/74) - (8/33) = -329/66

Therefore, T₂ = -329/66.

So, the tensions are: T₁ = 231/74 T₂ = -329/66 T₃ = 8/33

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