complete the table of values y=x² - 4x - 2

Answer:

No, Dale Isn't correct because 3:5 is greater than 2:10

Step-by-step explanation:

3:5 and 2:10 is the same as in \(\frac{3}{5}\)  and \(\frac{2}{10}\)

First Find the least common denominator or LCM of the two denominators:

LCM of 5 and 10 is 10

Next, find the equivalent fraction of both fractional numbers with denominator 10

For the 1st fraction, since 5 × 2 = 10,

\(\frac{3}{5} =\frac{3*2}{5*2} =\frac{6}{10}\)

Likewise, for the 2nd fraction, since 10 × 1 = 10,

\(\frac{2}{10} =\frac{2*1}{10*1} =\frac{2}{10}\)

Since the denominators are now the same, the fraction with the bigger numerator is the greater fraction

\(\frac{6}{10} >\frac{2}{10} Or\frac{3}{5} >\frac{2}{10}\)

Hence, \(\frac{3}{5}\) is Greater than \(\frac{2}{10}\)

Hence, 3:5 is Greater than 2:10

Answer: x = 25

Step-by-step explanation:

A square on an angle basically means that the angle is 90 degrees in total.

But your angle is divided up into 2 sections.

The one you need to find is x, and the known angle, 65.

You basically have 65 + x = 90 because those 2 angles have to equal 90 degrees.

When you solve for x, subtract 65 on both sides and you get x = 25.

(a) To find the probability that the item is requested more than 5 times on a given day, we would need to know the distribution of the demand for the item. Without that information, it is not possible to calculate this probability.

(b) To find the probability that the item is not requested at all on a given day, we would need to know the probability distribution of the demand for the item. Without that information, it is not possible to calculate this probability.

(a) To find the probability that the item is requested more than 5 times on a given day, we would need to know the distribution of the demand for the item. Without that information, it is not possible to calculate this probability. This is because the average demand of 5 times per day does not provide enough information to determine the likelihood of the demand exceeding 5 times. We would need to know more information such as the standard deviation, skewness, kurtosis and the underlying distribution of the data, in order to calculate this probability.

(b) To find the probability that the item is not requested at all on a given day, we would also need to know the distribution of the demand for the item. Without that information, it is not possible to calculate this probability. The average demand of 5 times per day does not provide enough information to determine the likelihood of the demand being zero. We would need to know more information such as the standard deviation, skewness, kurtosis and the underlying distribution of the data, in order to calculate this probability.

It's important to note that if the demand follows a Poisson distribution, you can use the expected value (λ = 5) to calculate the probability of the demand being zero (P(X = 0) = e^(-λ)).

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Answer:

The second choice is correct.

Step-by-step explanation:

As we go right on the number line, we are getting to larger and larger values.

D is greater than C because it is to the right of C, so the first choice is not correct.

The third choice is showing absolute value.  This is saying that the letters C and D are both the same distance from zero. They are not.

The last choice says that A is to the right of B and it is not.

The second choice that is B≥ C is correct.

The basics of this question requires us to read the number line perfectly

As we go right on the number line, we are getting to larger and larger values.

D is greater than C because it is to the right of C, so the first choice is not correct.

The third choice is showing absolute value.  This is saying that the letters C and D are both the same distance from zero. They are not.

The last choice says that A is to the right of B and it is not.

Thus option 2) is correct

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Jared bought 7 cans of paint. Let the number of red paint cans that Jared bought be x. The number of black paint cans he bought would be 7 - x. A can of red paint costs $3.75 and a can of black paint costs $2.75.

He spent $22 in all. Therefore we can write:3.75x + 2.75(7 - x) = 22 Multiplying out the second term and collecting like terms gives:0.5x + 19.25 = 22Subtracting 19.25 from both sides:0.5x = 2.75Dividing by 0.5:x = 5.5Since Jared can't buy half a can of paint, we should round the answer to the nearest integer. Hence, he bought 5 cans of red paint and 2 cans of black paint. The total cost of the 5 cans of red paint would be 5 x $3.75 = $18.75.The total cost of the 2 cans of black paint would be 2 x $2.75 = $5.50.The total cost of all 7 cans of paint would be $18.75 + $5.50 = $24.25.We spent more than Jared's budget. The value of $24.25 exceeds Jared's budget of $22. Hence, there is a problem with this problem statement.

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Answer::))

Step-by-step explanation:xong r

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Step-by-step explanation:

............solution

322 rounded to the nearest hundred is 300

Step-by-step explanation:

Hope this helps

The number 322 rounded to the nearest hundred is given by the equation A = 320

What is rounding up numbers?

There are basically two rules while rounding up numbers

If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down and if the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up.

Non-zero digits are always significant

Zeros between non-zero digits are always significant

Leading zeros are never significant

Trailing zeros are only significant if the number contains a decimal point

Given data ,

Let the rounded number be represented as A

Let the number be represented as n

The value of n = 322

The number n is to be rounded to the nearest hundreds place

So , the 3 in the hundreds place rounds down to 3, or stays the same, because the digit to the right in the tens place is 2. When the digit to the right is less than 5 we round toward 0

And , the number 322 is rounded to 300

Therefore , the value of A is 300

Hence , the number is 300

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Rashid spent a total of 1 hour and 30 minutes on homework for these three subjects.

If Rashid spent 30 minutes on each piece of homework for three subjects, we can calculate the total time he spent by multiplying the time spent per subject (30 minutes) by the number of subjects (3).

30 minutes * 3 = 90 minutes.

To convert this into hours and minutes, we divide 90 minutes by 60 since there are 60 minutes in an hour.

90 minutes ÷ 60 = 1 hour and 30 minutes.

Therefore, Rashid spent a total of 1 hour and 30 minutes on homework for these three subjects.

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Answer:10^9

Step-by-step explanation: they both equal 1000000000

The value of the line integral ∫F · dr along the path C from (1,-1,2) to (2,2,3) is approximately 10.833.'

To evaluate the integral ∫F · dr along the path C from (1,-1,2) to (2,2,3), where F = <2xy + z, x^2, x>, we can parameterize the path C and then perform the line integral using the parameterization.

Let's parameterize the path C by a vector function r(t) = <x(t), y(t), z(t)>, where t ranges from 0 to 1. We need to find the specific parameterization that satisfies the given endpoints (1,-1,2) and (2,2,3).

We can choose the following parameterization:

x(t) = 1 + t

y(t) = -1 + 3t

z(t) = 2 + t

Now, let's find the derivative of r(t) with respect to t:

r'(t) = <1, 3, 1>

The integral ∫F · dr can be written as:

∫[2xy + z, x^2, x] · [dx, dy, dz]

Substituting the parameterization and r'(t) into the integral:

∫[(2(1 + t)(-1 + 3t) + (2 + t)), (1 + t)^2, (1 + t)] · [1, 3, 1] dt

Expanding the dot product and simplifying:

∫[(2 - 2t + 6t^2 + 2 + t), (1 + 2t + t^2), (1 + t)] · [1, 3, 1] dt

Simplifying further:

∫[(9t^2 - t + 4), (t^2 + 2t + 1), (t + 1)] dt

Now, we can integrate each component separately:

∫(9t^2 - t + 4) dt = 3t^3 - (1/2)t^2 + 4t + C1

∫(t^2 + 2t + 1) dt = (1/3)t^3 + t^2 + t + C2

∫(t + 1) dt = (1/2)t^2 + t + C3

Combining the results and adding the constant of integration, we get:

3t^3 - (1/2)t^2 + 4t + C1 + (1/3)t^3 + t^2 + t + C2 + (1/2)t^2 + t + C3

Simplifying and combining the constants of integration:

(3t^3 + (1/3)t^3) - ((1/2)t^2 - t^2) + (4t + t + t) + (C1 + C2 + C3)

The final result of the line integral is:

(10/3)t^3 + (3/2)t^2 + 6t + C

To find the definite integral along the path C from t = 0 to t = 1, we can substitute these values into the expression:

[(10/3)(1)^3 + (3/2)(1)^2 + 6(1)] - [(10/3)(0)^3 + (3/2)(0)^2 + 6(0)]

= (10/3) + (3/2) + 6

= 3.333 + 1.5 + 6

= 10.833

Therefore, the value of the line integral ∫F · dr along the path C from (1,-1,2) to (2,2,3) is approximately 10.833.'

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Answer:

x=3, y= -2

Step-by-step explanation:

3x + 9y = -9

x + y = 1

Multiply the second equation by -3

-3x-3y = -3

Add this to the first equation to get rid of the x's

3x + 9y = -9

-3x -3 y = -3

------------------------

     6y = -12

Divide by 6

6y/6 = -12/-6

y = -2

3x + 9y = -9

x + y = 1

Multiply the second equation by -9

-9x-9y = -9

Add this to the first equation to get rid of the y's

3x + 9y = -9

-9x -9 y = -9

------------------------

     -6x = -18

Divide by -6

-6x/-6 = -18/-6

x = 3

Answer:

Here

the given equations are:-

3x + 9y = -9

or,3(x +3y)= -9

or,x+ 3y = -3 ................. (1)

x + y = 1 ................... (2)

Now , subtracting equation (2) from (1) , we ger:-

x + 3y = -3

x + y = 1

- - -

__________

0 + 2y = -2

or, y = -1

putting value of y in equation (2) , we get:-

x +(-2) = 1

or, x - 2 = 1

or x = 3

HENCE,

x = 3 and y = -1 are the values of x and y .

Thank me later.

Answer: y = x + 7

Step-by-step explanation:

the slope is rise / run which is 1 /1 so our slope would be 1 aka x

next is the y intercept which is 7

so the equal would be y = x + 7

Answer:

Step-by-step explanation:

This is a quadrilateral. A quadrilateral is a plane figure that has four sides or edges, and also has four corners or vertices.

The interior angles of a simple quadrilateral ABCD add up to 360 degrees of arc.

Answer:

Angle x = 40°

Step-by-step explanation:

All angles of any quadrilateral sum up to 360°.

So here, already measure of 3 angles are given.

So if we add up all angles + Angle x then it sums up to 360°.

So, the following steps will lead you to the answer:

73° + 157° + 90° + Angle x = 360°

(Now add up the measure of the three given angles)

320° + Angle x = 360°

(Now, through transposition moves 320° to the RHS) (Remember when transposing the signs change)

Angle x = 360° - 320°

Finally,

Angle x = 40°

Hope it helps!!!

Answer:

Send me a clarity question.

Answer\((-1)^{x}\)×\(x^{2}\)

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

18 US tons are equal to 36,000 pounds

Histograms are a waste of time and provide no meaningful information about process variation are true statement

A machine should be calibrated closer to the lower spec limit than the upper spec limit if the cost of fixing output that is too high is greater than the cost of fixing output that is too low.

If the cost of fixing output that is too high is greater than the cost of fixing output that is too low then it make sense to calibrate the machine closer to the lower spec limit.

This way if the machine produces less output than is required, it can be fixed at a lower cost than if the machine had been set to the upper spec and produces output that is too high.

Histograms are a waste of time and provide no meaningful information about process variation

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Answer:

so this uses proportions.

you need to find the side BF which is proportional to the side BF.

You do:

9/6=x/42

and cross multiply

9*42=6*x

378=6x

divide by 6 on both sides

x=63

the answer is 63

Answer:

These are similar triangles.

By changing the length of the base of the corresponding triangle, the 3 interior angles of this triangle remain equal to the original

Therefore, if these triangles are similar, their corresponding sides must give equal ratios to each other:

This means that BF/FE = BC/CD=FC/ED

The total length of line segment BD=BC+CD; BC=6, CD=42; BD=6+42, BD=48

BE=BF+FE; BE=9+?

if BF/FE=BC/CD then 9/BE=6/42; 6/42=3/21 or 1/7. 9/BE=1/7; 1/7=9/BE

1x9=9, 7x9=63

63=BE

Step-by-step explanation:

\(~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] ~\dotfill\\\\ (4)^{\frac{-4}{2}} \implies (4)^{-2}\implies 4^{-2}\implies \cfrac{1}{4^2}\implies \cfrac{1}{16}\)

Answer:

In counting to a base, when we get to the point where the base integer comes up, we replace by 10, on the first time and by 10 at every other time the integer is about to come up

We now this in base 10 as when we get to 10 we input 10 and so and so till we get to 99 where since we are in base 10 the next number is 100 because that is the highest we can go while in base 11 100 in base is equivalent to 91

So we have for base 5

1 , 2, 3, 4, 10, 11, 12, 13, 14, 20, 21, 22, 23, 24, 30, 31, 32, 33, 34, 40, 41, 42, 43, 44, 100, 101, 102, 103, 104, 110, 111, 112, 113, 114, 120, 121, 122, 123, 124, 130, 131, 132, 133, 134, 140, 141, 142, 143, 144, 200

We see that on getting to 4 instead of the next digit to be 5 we replace it with 10 because 5 cannot be displayed in base 5

Similarly after 14 is 20 because 5 cannot be displayed at 24 the next number is 30 because 5 cannot be displayed

at 34 the next  40, while at 44 the next is (we could have written 50 but 5 is 10 in base 5 so we write 100) 100

At 144, we note that 44 = 100 + 44, therefore, the next number will be 100 + 44+ 1 = 100 + (45 but 45 = 100 in base 5) 100 so that the next number is 200

Base 2

In base 2 we have;

1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1100, 1101, 1110, 1111, 10000, 10001, 10010, 10011, 10100, 10101, 10110, 10111, 11000, 11001, 11010, 11011, 11100, 11101, 11110, 11111, 100000, 100001, 100010, 100011, 100100, 100101, 100110, 100111, 101000, 101001, 101010, 101011, 101100, 101101, 101110, 101111, 110000, 110001, 110010

We see that there are no 2s and after 11 we get 100 just like after 99 we get 100 in base 10 and after 44 we get 100 in base 5

So we need to still have an idea of the number system just as we did for base 10

Step-by-step explanation:

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

\(y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{5}{7}}x+1\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\)

so for the parallel line we're really lookikng for the equation of aline whose slope is 5/7 and that it passes through (-5 , 6)

\((\stackrel{x_1}{-5}~,~\stackrel{y_1}{6})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{5}{7} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{ \cfrac{5}{7}}(x-\stackrel{x_1}{(-5)}) \implies y -6= \cfrac{5}{7} (x +5) \\\\\\ y-6=\cfrac{5}{7}x+\cfrac{25}{7}\implies y=\cfrac{5}{7}x+\cfrac{25}{7}+6\implies {\Large \begin{array}{llll} y=\cfrac{5}{7}x+\cfrac{67}{7} \end{array}}\)

now, keeping in mind that perpendicular lines have negative reciprocal slopes

\(\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{5}{7}} ~\hfill \stackrel{reciprocal}{\cfrac{7}{5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{7}{5}}}\)

so for the perpendicular line we're really looking for the equation of a line whose slope is -7/5 and that it passes through (-5 , 6)

\((\stackrel{x_1}{-5}~,~\stackrel{y_1}{6})\hspace{10em} \stackrel{slope}{m} ~=~ - \cfrac{7}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{- \cfrac{7}{5}}(x-\stackrel{x_1}{(-5)}) \implies y -6= -\cfrac{7}{5} (x +5) \\\\\\ y-6=-\cfrac{7}{5}x-7\implies {\Large \begin{array}{llll} y=-\cfrac{7}{5}x-1 \end{array}}\)

There are 462 ways to choose 5 books from a shelf of 12, if you cannot choose two adjacent books.

To solve this problem, we can use a technique called "complementary counting." First, let's find the total number of ways to choose 5 books from a shelf of 12. This is simply 12 choose 5, which is:
12! / (5! × 7!) = 792
Now, let's count the number of ways to choose 5 books from a shelf of 12 where two adjacent books are chosen. We can do this by treating the adjacent books as a single unit, and then choosing 4 more books from the remaining 11. This gives us:
11 choose 4 = 330
So, there are 330 ways to choose 5 books from a shelf of 12 where two adjacent books are chosen.
Finally, we can subtract this number from the total number of ways to choose 5 books to get the number of ways to choose 5 books where no two adjacent books are chosen:
792 - 330 = 462
Therefore, there are 462 ways to choose 5 books from a shelf of 12, if you cannot choose two adjacent books.

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(a) Find the dual of the LP.Primal problem isminimize \($b_1y_1+C_1x_1+...+C_nx_n$\) subject to \($a_{11}x_1+a_{12}x_2+...+a_{1n}x_n \leq\) \(b_1$...$a_{m1}x_1+a_{m2}x_2+...+a_{mn}x_n \leq b_m$ and $x_1, x_2,\)..., x_n\(\geq 0$\)

Let us find the dual of the above primal problem.

Dual problem ismaximize \($b_1y_1+...+b_my_m$\)subject to \($a_{11}y_1+a_{21}y_2+...+a_{m1}y_m \leq\)\(C_1$...$a_{1n}y_1+a_{2n}y_2+...+a_{mn}y_m \leq C_n$\)

and\($y_1, y_2, ..., y_m \geq 0$\)

(b) Find the standard form of the LP and dual.Standard form of the primal problem isminimize \($b_1y_1+C_1x_1+...+C_nx_n$\)subject to \($a_{11}x_1+a_{12}x_2+...+a_{1n}x_n +s_1 = b_1$...$a_{m1}x_1+a_{m2}x_2+...+a_{mn}x_n +s_m = b_m$\) and\($x_1, x_2, ..., x_n, s_1, s_2, ..., s_m \geq 0$\)

Standard form of the dual problem ismaximize \($b_1y_1+...+b_my_m$\)subject to \($a_{11}y_1+a_{21}y_2+...+a_{m1}y_m \leq 0$...$a_{1n}y\)

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The point on the curve y=tanh(x) at which the tangent has slope 16/25 is approximately (1.075, 0.789).

To find this point, we start by taking the derivative of y=tanh(x) to get y' = sech^2(x). We then set sech^2(x) equal to 16/25 and solve for x to get x = arccosh(sqrt(9/16)). This gives us the x-coordinate of the point on the curve where the tangent has slope 16/25. To find the corresponding y-coordinate, we evaluate y = tanh(arccosh(sqrt(9/16))) to get approximately 0.789. Therefore, the point on the curve where the tangent has slope 16/25 is approximately (1.075, 0.789).

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The point d will be assigned probabilities to belong to both clusters in a soft clustering method.

In the given data set with seven points (a, b, c, e, f, g) and d being equidistant from c and e, we are interested in finding two clusters using a soft clustering method like Gaussian Mixture Models (GMM).

Let me explain what will happen to point d in this situation.

In a Gaussian Mixture Model, data points can belong to multiple clusters with certain probabilities. Since d is equidistant from both the left cluster (a, b, c) and the right cluster (e, f, g), GMM will assign a probability to d for each cluster, effectively sharing d between the two clusters.

In summary, point d will be assigned probabilities to belong to both clusters (left and right) in a soft clustering method like Gaussian Mixture Models.

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Answer:

Heart sounds

Step-by-step explanation: