Answer:
\(\frac{F1}{F2}\)=5.4*\(10^{26}\)
Explanation:
Let
F1=Electric force
F2=Gravitational Force
F1=\(\frac{kq^{2} }{r^{2} }\)
F2=\(\frac{Gm^{2} }{r^{2} }\)
\(\frac{F1}{F2}\) = \(\frac{\frac{kq^{2} }{r^{2} } }{\frac{Gm^{2} }{r^{2} } }\)
\(\frac{F1}{F2}\) = \(\frac{kq^{2} }{Gm^{2} }\)
\(\frac{F1}{F2}\) =\(\frac{9*10^{9}*(20)^{2} }{6.67*10^{-11} *(0.01)^{2} }\)
\(\frac{F1}{F2}\) = 5.4*\(10^{26}\)
The equation for photon energy, E, is E = h X where h = 6.626x10^-34 J-s (Planck's constant) and c = 2.99x10^8 m/s (the speed of light). hc What is the wavelength, A, of a photon that has an energy of E= 4.73×10^-19 J? Express your answer numerically in meters.
The wavelength, A, of a photon that has an energy of E= 4.73 × 10⁻¹⁹ J is 4.17 × 10⁻⁷ m.
Photon energy can be calculated using the equation E = hc/λ, where λ is the wavelength of the photon.
We know that the photon energy, E, is given as E = 4.73 × 10⁻¹⁹ J.
Additionally, we know that Planck's constant, h, is equal to 6.626 × 10⁻³⁴ J·s and the speed of light, c, is equal to 2.99 × 10⁸ m/s.
Substituting the known values into the equation for photon energy, we get: E = hc/λ4.73 × 10⁻¹⁹ J = (6.626 × 10⁻³⁴ J·s)(2.99 × 10⁸ m/s)/λ
Simplifying the expression above, we get:λ = hc/Eλ = (6.626 × 10⁻³⁴ J·s)(2.99 × 10⁸ m/s)/(4.73 × 10⁻¹⁹ J)λ = 4.17 × 10⁻⁷ m
Therefore, the wavelength, A, of a photon that has an energy of E= 4.73 × 10⁻¹.
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A man with a weight of 450 N climbs a ladder to a height of 5.2 meters. How much work did he do?
Answer:
the work done by him is 2,340 joules
Explanation:
The computation of the work done by him is shown below:
= Weight of man × height
= 450 N × 5.2 meters
= 2,340 joules
Hence, the work done by him is 2,340 joules
We simply multiply the man weight with the height
who is the father of kinematics ?
explain +)
Answer:
FRANZ REULEAUX
Late 19th century kinematics and the theory of machines as seen through the contributions of the German engineering scientist, Franz Reuleaux (1829-1905), often called the "father of kinematics". Extremely famous in his time and one of the first honorary members of ASME, Reuleaux was largely forgotten in much of modern mechanics literature in English until the recent rediscovery of some of his work. In addition to his contributions to kinematics, we review Reuleaux's ideas about design synthesis, optimization and aesthetics in design, engineering education as well as his early contributions to biomechanics. A unique aspect of this review has been the use of Reuleaux's kinematic models at Cornell University and in the Deutsches Museum as a tool to rediscover lost engineering and kinematic knowledge of 19th century history of machine.
The velocity versus time graph of particle A is tangent to the velocity versus time graph for particle B at point O. What is the acceleration of the particle A at point O?
Answer:
Explanation:
Need a diagram....
5. A 6.0-kilogram mass is moving with a speed of 2.0 m/s. What is the kinetic energy of the mass?
Answer:
K.E. = ½ × mv²
= ½ × 6 × (2)²
= ½ × 6 × 4
= 3 × 4
= 12 J
How is the chemical bonding within a molecule of carbon dioxide (CO2) different from the chemical bonding within a crystal of iron (Fe)?
A.
In an iron crystal, the atoms are joined by sharing electrons. In carbon dioxide, atoms of carbon and oxygen are held together by freely moving electrons.
B.
In a carbon dioxide molecule, atoms of carbon and oxygen are joined by sharing electrons. In an iron crystal, the atoms are held together by freely moving electrons.
C.
In an iron crystal, the atoms are joined by their opposite electrical charges. In carbon dioxide, atoms of carbon and oxygen are held together by freely moving electrons.
D.
In a carbon dioxide molecule, atoms of carbon and oxygen are joined by their opposite electrical charges. In an iron crystal, the atoms are held together by freely moving electrons.
Answer:
I'ts B
Explanation:
:p
The chemical bonding within a molecule of carbon dioxide (CO2) different from the chemical bonding within a crystal of iron (Fe) in a carbon dioxide molecule, atoms of carbon and oxygen are joined by sharing electrons. In an iron crystal, the atoms are held together by freely moving electrons. Therefore, option B is correct.
What is chemical bonding ?The term chemical bonding is defined as the formation of a chemical bond between two or more atoms, molecules, or ions to form a chemical compound.
There are three main types of chemical bonding that are ionic bonding, covalent bonding, and metallic bonding.
The chemical bonding within a molecule of carbon dioxide (CO2) different from the chemical bonding within a crystal of iron (Fe) because in a carbon dioxide molecule, atoms of carbon and oxygen are joined by sharing electrons. In an iron crystal, the atoms are held together by freely moving electrons.
Thus, option B is correct.
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If and object undergoes a change in momentum of 12 kg*m/s over a 10
second interval, what was the force exerted?
The magnitude of the force exerted on this object is 1.2 Newton.
Given the following data:
Change in momentum = 12 Kgm/s.Time = 10 seconds.What is impulse?In Science, the impulse that is experienced by an object is always equal to the change in momentum of the object, due to the force acting on an object.
Mathematically, impulse is given by this formula:
\(Impulse = change\;in\;momentum\\\\Force \times time = m \Delta V\)
Substituting the given parameters into the formula, we have:
\(Force \times 10=12\\\\Force =\frac{12}{10}\)
Force = 1.2 Newton.
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You are lowering two boxes, one on top of the other,
down a ramp by pulling on a rope parallel to the surface of the
ramp (Fig. E5.33). Both boxes move together at a constant speed
of 15.0 cm>s. The coefficient of kinetic friction between the ramp
and the lower box is 0.444, and the coefficient of static friction
between the two boxes is 0.800. (a) What force do you need to
exert to accomplish this? (b) What are the magnitude and direction of the friction force on the upper box?
To solve this problem, we need to use Newton's second law to find the net force acting on the two boxes. The net force is equal to the mass of the two boxes times the acceleration. Since the boxes are moving at a constant speed, the acceleration is zero, and the net force is also zero. This means that the sum of all the forces acting on the two boxes must be zero.The force you exert on the boxes is the force of tension in the rope, and this force is equal in magnitude and opposite in direction to the force of friction on the lower box. The magnitude of the friction force on the lower box is equal to the coefficient of kinetic friction times the normal force acting on the lower box.The normal force is the force exerted by the ramp on the lower box, and it is equal in magnitude to the weight of the lower box. The weight of the lower box is equal to the mass of the lower box times the acceleration due to gravity.The magnitude of the friction force on the upper box is equal to the coefficient of static friction times the normal force acting on the upper box. The normal force acting on the upper box is equal in magnitude to the weight of the upper box.Now that we have all the forces, we can use Newton's second law to solve for the force you need to exert. The equation is:F_tension - F_friction_lower = 0
F_tension = F_friction_lowerF_friction_lower = u_k * N_lower
F_tension = u_k * m_lower * gWhere:F_tension is the force you need to exertF_friction_lower is the force of friction on the lower boxu_k is the coefficient of kinetic friction between the ramp and the lower boxN_lower is the normal force acting on the lower boxm_lower is the mass of the lower boxg is the acceleration due to gravitySubstituting the given values, we get:F_tension = (0.444) * (m_lower) * (9.8 m/s^2)The force you need to exert is therefore:F_tension = (0.444) * (m_lower) * (9.8 m/s^2)The magnitude of the friction force on the upper box is:F_friction_upper = u_s * N_upperWhere:F_friction_upper is the force of friction on the upper boxu_s is the coefficient of static friction between the two boxesN_upper is the normal force acting on the upper boxSubstituting the given values, we get:F_friction_upper = (0.800) * (m_upper) * (9.8 m/s^2)The direction of the friction force on the upper box is opposite to the direction of motion of the upper box.
what are the cell structures where proteins are made
Answer:
Ribosomes
Explanation:
thy are the sites in a cell in which protein synthesis takes place. cells have many ribosomes, and the exact number depends on how active a particular cell in synthesizing proteins.
Example (2):
Convert the flow rate of 5L/min to
cm³/s.
5L into cm³
=5000 cm³ (since 1cm³=1mL)
1 minute into seconds
=60 s (basic knowledge of universal quantities)
So, 5L/min =
\( \frac{5000}{60} {cm}^{3}/s = \boxed{ 83.33{cm}^{3} /s} \)
In the image which element is the most massive ?
Answer:
fluorine
Explanation: it has the largest mass number which is almost rounded to 19.
The toy car in the diagram runs off the edge of the table that is 1.225m high. The car lands 0.400m from the base of the table.
a. How long did it take the car to fall
b. how fast was the car going on the table
A body dropped over a fixed rough inclined plane of inclination 45 from height h. If after collision velocity of body becomes horizontal
then co-efficient of restitution if co-efficient of friction is 1/2
As per the given scenario, in this case, the coefficient of friction () is half and the coefficient of restitution (e) is zero.
Identify the body's starting velocity:
We may use the equation of motion to get the body's initial velocity (u)
\(v^2 = u^2 + 2as\)
\(0 = u^2 + 2(-9.8)m/s^2 * h\)
\(u^2 = 19.6h\)
u = √(19.6h)
Determine the coefficient of restitution (e):The body's initial velocity (u) and initial relative velocity (u_rel) are the same.
The body's horizontal velocity immediately following the collision, which is zero, is the final relative velocity (v_rel).
\(e = v_{rel }/ u_{rel}\)
e = 0 / u_rel = 0 / u
Now, one can investigate the forces affecting the body: When a body is on an inclined plane.
There are two main forces at work on it: the frictional force that prevents the body from moving and the gravitational force that pulls it downward (mg).
The gravitational force has two components that act perpendicular to and parallel to the inclined plane, respectively: m*g*cos(45°) and m*g*sin(45°).
Determine the conditions for the body to stop:
μ * N = m * g * sin(45°)
μ * (m * g * cos(45°)) = m * g * sin(45°)
μ * cos(45°) = sin(45°)
(1/2) * cos(45°) = sin(45°)
Simplifying further, we have:
√2 / 4 = √2 / 2
Thus, the body will come to rest following the collision if the equation is valid.
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If a 40 N block is resting on a rough horizontal table with a coefficient of static friction
If a 40 N block is resting on a rough horizontal table with a coefficient of static friction is 12 N.
What is static friction?Static friction is a force that resists the motion of two objects that are in contact with each other. It is caused by the forces of attraction between the two objects and is usually greater than the force of kinetic friction. The forces of static friction oppose the movement of the two objects and can be overcome by applying a force greater than the static friction.
The maximum force the block can withstand before it starts to move is 40 N multiplied by the coefficient of static friction.
The coefficient of static friction between the block and the table is determined by the materials of the block and the table and the surface roughness of the table.
If the coefficient of static friction is 0.3, then the maximum force the block can withstand before it starts to move is 40 N × 0.3 = 12 N.
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A well-coated structure is defined as A) 95% or better B) 90% or better C) 99% or better D) 93% or better
Answer and Explanation:
A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.
However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.
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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.
However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.
Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body
A sound wave has a frequency of 668 Hz in air
and a wavelength of 0.5 m.
What is the temperature of the air?
Relate the speed of sound in air to temper-
ature in units of Kelvin, but answer in units
of Celsius.
Assume the velocity of sound at 0°C is
334 m/s.
Answer in units of degC.
The temperature of the air would be 6.3 °C.
Sound wave and air temperatureThe speed of sound in air depends on the temperature of the air according to the equation:
v = 331.5 m/s * sqrt(T/273.15 K)
where v is the speed of sound, T is the temperature of the air in Kelvin, and 273.15 K is the temperature at which the speed of sound is 331.5 m/s.
We know the frequency and wavelength of the sound wave, which are:
f = 668 Hz
λ = 0.5 m
The speed of sound can be calculated from the formula:
v = fλv = (668 Hz) * (0.5 m) = 334 m/sSubstituting this value for v and the given value for the speed of sound at 0°C into the equation above and solving for T gives:
v = 331.5 m/s * sqrt(T/273.15 K)(T/273.15 K) = (v/331.5 m/s)^2(T/273.15 K) = (334 m/s / 331.5 m/s)^2(T/273.15 K) = 1.022T = 1.022 * 273.15 KT = 279.4 KThe temperature of the air is 279.4 K, which is equivalent to 6.3 °C, rounded to 1 decimal place.
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What is the economic term for the act of sacrificing one good or service to purchase or produce another?
Answer:
Trade-off. sacrificing one good or service to purchase or produce another.A 2.15-nC charged particle located at the origin is separated by a distance of 0.0690 m from a 3.78-nC charged particle located farther along the positive x axis. If the 2.15-nC particle is kept fixed at the origin, where along the positive x axis should the 3.78-nC particle be located so that the magnitude of the electrostatic force it experiences is twice as great as the magnitude of the electrostatic force it experiences at 0.0690 m?
The new distance of the 3.78 nC particle when the electrostatic force is doubled is 0.049 m.
What is the electrostatic force between the two particles?
The magnitude of the electrostatic force experienced by the 3.78 n C particle when it is 0.069 m from the 2.15 nC particle is calculated as follows;
F = kq₁q₂ / r²
where;
k is the Coulomb's constantq₁ is the magnitude of particle 1q₂ is the magnitude of particle 2r is the distance between the particlesF = ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 0.069² )
F = 1.536 x 10⁻⁵ N
When this electrostatic force is doubled, the new distance of 3.78 nC particle from the 2.15 nC is calculated as;
r² = kq₁q₂ / 2F
r = √ ( kq₁q₂ / 2F )
r = √ [ ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 2 x 1.536 x 10⁻⁵ ) ]
r = 0.049 m
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If the man and woman are taken to a planet where the acceleration due to gravity is twice that of earth repeat the woman mass was 25kg on earth and the man was 300N on another planet
The mass of the woman is 25 kg because the mass is constant.
The mass of the man can be found using the formula: W = mg, where g is double Earth's gravity.
\(\begin{gathered} m=\frac{W}{g} \\ m=\frac{300N}{2\cdot9.8\cdot\frac{m}{s^2}} \\ m=\frac{300}{19.6}kg \\ m\approx15.3\operatorname{kg} \end{gathered}\)The mass of the man is 15.3 kg.
The weight of the man on Earth can be found with the same formula but using Earth's gravity.
\(\begin{gathered} W=15.3\operatorname{kg}\cdot9.8\cdot\frac{m}{s^2} \\ W=149.94N \end{gathered}\)The weight of the man on Earth is 149.94 N.
At last, the weight of the woman on Earth can be found using the same method before.
\(\begin{gathered} W=25\operatorname{kg}\cdot9.8\cdot\frac{m}{s^2} \\ W=245N \end{gathered}\)The weight of the woman on Earth is 245N.
Explain the light detection technique of photovoltaic detection
Answer:
Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.
The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.
The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.
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A penny sinks to the bottom of a wishing well
What type of frictional force is that?
The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.
The figure shows five electric charges. Four charges with the magnitude of the charge 2.0 nC form a square with the size a = 4.0 cm . Positive charge with the magnitude of q = 5.5 nC is placed in the center of the square.
A) What is the magnitude of the force on the 5.5 nC charge in the middle of the figure due to the four other charges?
B) What is the direction of the force on the 5.5 nC charge in the middle of the figure due to the four other charges?
Considering the four electric charges forming a square with magnitude of charge of 2.0 nC on each. :
A) Magnitude of the force on the 5.5 nC charge in the middle of the figure = 3.48 * 10^-4 N
B) Direction of the force on the 5.5 nC charge in the middle of the figure = Leftward ( negative x -axis )
Using the given data :
size of square = 4 cm
magnitudes of four charges = 2.0 nC
a) magnitude of the force on the center charge
Electric force between two point charges = \(F = \frac{1}{4\pi *E_{o} } \frac{q1q2}{r^2}\) ----- ( 1 )
where ; \(\frac{1}{4\pi E_{o} } = 9 * 10^9 Nm^2/C^2\)
step 1 ; find r ( distance between charges )
r² = ( 2 )² + ( 2 )² = 8 cm²
back to equation 1
F = 9 * 10⁹ * \(\frac{2 * 10^{-9} * (5.5 * 10^{-9}) }{8*10^{-4} }\) = 1.23 * 10^-4 N
∴ magnitude of the force on the center charge ( Fnet )= 4F cos 45°
= 4 * ( 1.23 * 10^-4 ) * \(\frac{1}{\sqrt{2} }\) = 3.48 * 10^-4 N
b) The direction of the force at the center is along the negative x-axis ( leftward )
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A bungee jumper with mass 65.0 kg jumps from a high bridge. After reaching his lowest point, he oscillates up and down, hitting a low point eight more times in 38.0 s. After many oscillations, he finally comes to rest 25.0 m below the level of the bridge. Calculate the spring stiffness constant and the unstretched length of the bungee cord.
Explanation:
It is given that,
Mass of a bungee jumper is 65 kg
The time period of the oscillation is 38 s, hitting a low point eight more times.It means its time period is
\(T=\dfrac{38}{8}\\\\T=4.75\ s\)
After many oscillations, he finally comes to rest 25.0 m below the level of the bridge.
For an oscillating object, the time period is given by :
\(T=2\pi \sqrt{\dfrac{m}{k}}\)
k = spring stiffness constant
So,
\(k=\dfrac{4\pi ^2m}{T^2}\\\\k=\dfrac{4\pi ^2\times 65}{(4.75)^2}\\\\k=113.43\ N/m\)
When the cord is in air,
mg=kx
x = the extension in the cord
\(x=\dfrac{mg}{k}\\\\x=\dfrac{65\times 9.8}{113.6}\\\\x=5.6\ m\)
So, the unstretched length of the bungee cord is equal to 25 m - 5.6 m = 19.4 m
The spring stiffness constant is 116.7 N/m and the the unstretched length of the bungee cord is 19.54 m.
The given parameters;
mass of the bungee jumper, m = 65 kgtime of motion, t = 38 sdistance to come to rest, d = 25 mThe period of oscillation of the bungee jumper is calculated as follows;
\(T = \frac{t}{n} \\\\T = \frac{38}{8} \\\\T = 4.75 \ s\)
The spring stiffness constant is calculated as follows;
\(T = 2\pi \sqrt{\frac{m}{k} } \\\\\sqrt{\frac{m}{k} } = \frac{T}{2\pi} \\\\k = m \times \frac{T^2}{4\pi^2} \\\\k = 65 \times \frac{(4.75)^2}{4\pi ^2} \\\\k = 116.7 \ N/m\)
The extension of the cord is calculated as follows;
\(F = kx\\\\mg = kx\\\\x = \frac{mg}{k} \\\\x = \frac{65 \times 9.8}{116.7} \\\\x = 5.46 \ m\)
The unstretched length of the bungee cord is calculated as;
\(\Delta x = l_2-l_1\\\\l_1 = l_2 - \Delta x\\\\l_1 = 25 - 5.46\\\\l_1 = 19.54 \ m\)
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A smooth circular cylinder of radius 1.5m in a triangular grove, one side of which makes 15 °angle and the other 40° angle with the horizontal · Find the reaction. at the surface of contact, if there. is no fiction and the cylinder weigh 100N
Answer:
46.5 N
Explanation:
attached is explanation
0.3050 has
significant figures
?
Answer:
NO
Explanation:
because it just doesn't.
An object at rest is suddenly broken apart into two fragments by an explosion. The first fragment (with mass m1) acquires twice the kinetic energy of the second one (with mass m2).
What is the ratio of their masses?
Answer:
m1 ÷ m2 = 1 ÷ 2
Explanation:
The ratio of their masses is as follows:
As it is given that the mass m1 is twice of mass m2
So the equation could be written as
\(\frac{1}{2} m1 v1 v1 = 2 \times \frac{1}{2} m2 v2 v2\\\\\frac{m1}{m2} = \frac{2 v2 v2}{v1 v1} ..........(1)\)
Here we used the conservation of momentum
Prior to the explosion, the object is in rest so the momentum would be zero but after the explosion the total momentum would be m1v1 + m2v2, that is also zero.
So,
\(m1 v1 + m2 v2 = 0\\\\m1 v1 = - m2 v2\\\\\frac{m1}{m2} = \frac{- v2}{v1}\)
Now squaring to the both sides
m1 m1 ÷ (m2 m2) = v2 v2 ÷ (v1 v1) ........(2 )
Solved both the equations
After solving it, the ratio is
m1 ÷ m2 = 1 ÷ 2
what is capasistanceb
\(\sf\huge\underline\pink{Answer:-}\)
Capacitance is the ratio of the change in the electric charge of a system, to the corresponding change in its electric potential.\(\rightarrow\)The capacitance of any capacitor can be either fixed or variable depending on their usage.
\(\rightarrow\)Capacitance is expressed as the ratio of the electric charge on each conductor to the potential difference (i.e., voltage) between them.
\(\rightarrow\)The capacitance value of a capacitor is measured in farads (F), units named for English physicist Michael Faraday (1791–1867).
\(\sf\large\underline\blue{Formula:-}\)
➢ \(\sf\green{q = CV}\)
Where,
\(\rightarrow\sf{q = charge}\)
\(\rightarrow\sf{C = capacitance}\)
\(\rightarrow\sf{V = voltage}\)
_______________________________
The refractive index n of transparent acrylic plastic (full name Poly(methyl methacrylate)) depends on the color (wavelength) of the light passing through it. At wavelength 486.1 nm (blue, designated with letter F) -> nF=1.497, and at wavelength 656.3 nm (red, designated with letter C) -> nC=1.488. Two beams (one of each wavelength) are prepared to coincide, and enter the flat polished surface of an acrylic block at angle of 45 arc degree measured from the normal to the surface. What is the angle between the blue beam and the red beam in the acrylic block?
Answer:
The angle between the blue beam and the red beam in the acrylic block is
\(\theta _d =0.19 ^o\)
Explanation:
From the question we are told that
The refractive index of the transparent acrylic plastic for blue light is \(n_F = 1.497\)
The wavelength of the blue light is \(F = 486.1 nm = 486.1 *10^{-9} \ m\)
The refractive index of the transparent acrylic plastic for red light is \(n_C = 1.488\)
The wavelength of the red light is \(C = 656.3 nm = 656.3 *10^{-9} \ m\)
The incidence angle is \(i = 45^o\)
Generally from Snell's law the angle of refraction of the blue light in the acrylic block is mathematically represented as
\(r_F = sin ^{-1}[\frac{sin(i) * n_a }{n_F} ]\)
Where \(n_a\) is the refractive index of air which have a value of\(n_a = 1\)
So
\(r_F = sin ^{-1}[\frac{sin(45) * 1 }{ 1.497} ]\)
\(r_F = 28.18^o\)
Generally from Snell's law the angle of refraction of the red light in the acrylic block is mathematically represented as
\(r_C = sin ^{-1}[\frac{sin(i) * n_a }{n_C} ]\)
Where \(n_a\) is the refractive index of air which have a value of\(n_a = 1\)
So
\(r_C = sin ^{-1}[\frac{sin(45) * 1 }{ 1.488} ]\)
\(r_F = 28.37^o\)
The angle between the blue beam and the red beam in the acrylic block
\(\theta _d = r_C - r_F\)
substituting values
\(\theta _d = 28.37 - 28.18\)
\(\theta _d =0.19 ^o\)
A force of 40 N is applied tangentially to the rim of a solid disk of radius 0.10 m. The disk rotates about an axis through its center and perpendicular to its face with a constant angular acceleration of 145 rad/s2. Determine the mass of the disk.
Answer:
m = 2,759 kg
Explanation:
For this exercise we use the torque relationship
τ = I α
the moment is
τ= F r sin θ
since the force is tangential to the ring, the angle is 90º sin 90 = 1
τ = F r
the moment of inertia of a ring is given by
I = m r²
let's substitute
F r = m r²α
m = F / r α
let's calculate
m = 40 / (0.10 145)
m = 2,759 kg
In a baseball game, Joseph hits a ball to the outfield. When does the ball have the most potential energy?
A. when the ball is caught
B. when the bat hits the ball
C. when the ball reaches its greatest velocity
D. when the ball reaches its highest point
It has the greatest Potential energy when the ball reaches its highest point.The correct option is D
What is potential energy?Potential energy is the energy that an object possesses due to its position or state, which can be converted into work or kinetic energy when acted upon by a force.
There are three types of Potential Energy such as :
Elastic Potential Energy: Anything that can act like a spring or a rubber band can have elastic potential energyGravitational Potential Energy: There is a constant attractive force between the Earth and everything surrounding it, due to gravityChemical Potential Energy.Learn more about Potential Energy here: brainly.com/question/1242059
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Answer:
1) PE=mgh
2)when the ball reaches its highest point
3)21,599,200 J
4) The object’s mass, gravity, and height determine its potential energy.
5)Members of a team work together to create a plan, and then members choose different tasks to carry out the plan.