Choose the correct answer below. A. Bar charts that are sorted from most frequent to least frequent B. Histograms that are sorted from least frequent to most frequent C. Bar charts that are sorted from least frequent to most frequent D. Dotplots that are sorted from most frequent to least frequent

Answers

Answer 1

According to the information we can infer that Pareto charts are bar charts that are sorted from most frequent to least frequent.

What are Pareto charts?

A Pareto chart is a graphical tool used for prioritizing and displaying the relative importance of different categories or factors. It combines both a bar chart and a line graph.

The bars in a Pareto chart represent the frequency or count of each category, and they are arranged in descending order from the most frequent to the least frequent category. The line graph is superimposed on the bars and represents the cumulative percentage or cumulative contribution of each category.

Pareto charts are commonly used to identify the most significant factors contributing to a problem or to focus efforts on addressing the most impactful issues.

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Choose The Correct Answer Below. A. Bar Charts That Are Sorted From Most Frequent To Least Frequent B.

Related Questions

identify the open intervals on which the function is increasing or decreasing. (select all that apply.) f(x) = sin x -1, 0 < x < 2 π
Increasing:
A. (π/2, 3π/2)
B. (0, π/2)
C. (3π/2, 2π)
D. (0, [infinity])
E. (-[infinity],0)

Answers

The intervals on which function f(x) = sin x -1 increasing or decreasing is (0, π/2) (B).



The given function is f(x) = sin x -1, 0 < x < 2 π.

A sinusoidal function is a function that can be written in the form f(x) = a sin(bx + c) + d or f(x) = a cos(bx + c) + d, where a, b, c, and d are constants.

The graph of the given function is a sine curve shifted downward by 1 unit.

The function is increasing on the interval (0, π/2) because the slope of the curve is positive on this interval.

The function is decreasing on the interval (π/2, 3π/2) because the slope of the curve is negative on this interval.

The function is increasing again on the interval (3π/2, 2π) because the slope of the curve is positive on this interval.

Therefore, the correct answer is option B. (0, π/2).

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can I get helpppppppppppppppppppppppp??

can I get helpppppppppppppppppppppppp??

Answers

Answer:

6 + -15? That does equal -9.

At one school, the average amount of time that spend watching television each week is The principal introduces a campaign to encourage the students to watch less television. One year later, the principal wants to perform a hypothesis test to determine whether the average amount of time spent watching television per week has decreased from the previous mean of

Answers

Answer:

21.6 hours

Step-by-step explanation:

Hypothesis testing allows to identify a event test. The correct order of the steps of a hypothesis test is given following  

1. Determine the null and alternative hypothesis.

2. Select a sample and compute the z - score for the sample mean.

3. Determine the probability at which you will conclude that the sample outcome is very unlikely.

4. Make a decision about the unknown population.

These steps are performed in the given sequence to test a hypothesis.

The principal tests the hypothesis with a mean of 21.6 hours for the determination of average amount of time spent watching television.

A confectionery company mixes three types of toffees to form one kilogram " toffee packs. the pack is sold at rs. 17. the three types of toffees cost rs.20, rs. 10, rs. 5 per kg. resp. the mixture must contain atleast 300 gms of first type. also weight of first two types must be at least be equal to weight of third type. find the optimal mix for maximum profit.answer

Answers

The maximum profit is 6 and it is obtained when we mix 0.6 kg of type A, 0 kg of type B, and 0.4 kg of type C.

The optimal mix for the maximum profit can be found as follows:

The company mixes three types of toffees, A, B, and C. Let the weights of type A, B, and C be a, b, and c kg, respectively. Let us assume that we are making 1kg of toffee pack. Therefore, the weight of type C should be 1 - (a + b) kg. Also, the mixture must contain at least 300 gms of type A i.e a >= 0.3 kg

Also, the weight of the first two types (A and B) must be at least equal to the weight of type C, i.e a + b >= c. This condition can also be written as a + b - c >= 0

Let us now calculate the total cost of making 1kg of toffee pack.

Cost = 20a + 10b + 5c

If the pack is sold at Rs. 17, then the profit per 1kg of toffee pack is by

Profit = Selling Price - Cost = 17 - (20a + 10b + 5c)

Now we have the following linear programming problem:

Maximize P = 17 - (20a + 10b + 5c)

Subject to constraints: a + b + c = 1 (since we are making 1kg of toffee pack)

a >= 0.3a + b - c >= 0a, b, c >= 0

We can use the simplex method to solve this linear programming problem. However, to save time, we can solve it graphically. The feasible region is as follows:

We can see that the corner points of the feasible region are: (0.3, 0, 0.7), (0.6, 0, 0.4), (0, 0.5, 0.5), and (0, 1, 0).

Let us calculate the profit at each of these corner points. For example, at the point (0.3, 0, 0.7), we have a = 0.3, b = 0, and c = 0.7. Therefore, the profit is

P = 17 - (20(0.3) + 10(0) + 5(0.7)) = 3.5

Similarly, we can calculate the profit at the other corner points as well. The corner point (0.3, 0, 0.7) gives a profit of 3.5

Corner point (0.6, 0, 0.4) result in a profit of 6

Corner point (0, 0.5, 0.5) results in a profit of 5

Corner point (0, 1, 0) gives a profit of 3

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If a given set of data has a variance of 64.58 and a sample size of 26, the the standard deviation is equivalent to

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Standard deviation is a statistic that measures the dispersion of a dataset relative to its mean and is calculated as the square root of the variance.

Standard deviation = √ {(xi – x)^2 / (n-1)}

here (xi – x)^ 2 means variance and n is sample size .

so we can say

Standard deviation = √{ (variance / sample size – 1 )}

here variance is 64.58 and sample size is 26 is given.

So stand deviation = √{64.58 / (26-1)}

standard deviation =0.32144673

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the standard deviation will be 0.32144673 for the data having variance as 64.58 and sample size as 26.

Standard deviation is a statistic that measures the dispersion of a dataset relative to its mean and is calculated as the square root of the variance.

Standard deviation = √ {(xi – x)^2 / (n-1)}

here (xi – x)^ 2 means variance and n is sample size .

so we can say

Standard deviation = √{ (variance / sample size – 1 )}

here variance is 64.58 and sample size is 26 is given.

So standard deviation = √{64.58 / (26-1)}

standard deviation = 0.32144673

Therefore, the standard deviation will be 0.32144673 for the data having variance as 64.58 and sample size as 26.

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In your reservoir, you have a production well which flows for 48 hours at 200 STB/day, and then shut-in for 24 hours. The following additional data are given : Pi = 3100 psi Ct = 15x10^-6 psi^-1 Bo = 1.3 bbl/STB ϕ = 15% μ=1.2 cp K = 45 md and h = 60 ft
a-) Calculate the pressure in this production well at 12 hours of shut in
b-) Explain how can you use superposition in time to analyze a pressure build-up test.

Answers

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

We have,

a) To calculate the pressure in the production well at 12 hours of a shut-in, we can use the equation for pressure transient analysis during shut-in periods, known as the pressure buildup equation:

P(t) = Pi + (Q / (4πKh)) * log((0.14ϕμCt(t + Δt)) / (Bo(ΔP + Δt)))

Where:

P(t) = Pressure at time t

Pi = Initial reservoir pressure

Q = Flow rate

K = Permeability

h = Reservoir thickness

ϕ = Porosity

μ = Viscosity

Ct = Total compressibility

t = Shut-in time (12 hours)

Δt = Time since the start of the flow period

Bo = Oil formation volume factor

ΔP = Pressure drop during the flow period

Given:

Pi = 3100 psi

Q = 200 STB/day

K = 45 md

h = 60 ft

ϕ = 15%

μ = 1.2 cp

Ct = 15x10^-6 psi^-1

Bo = 1.3 bbl/STB

t = 12 hours

Δt = 48 hours

ΔP = Pi - P(t=Δt) = Pi - (Q / (4πKh)) * log((0.14ϕμCt(Δt + Δt)) / (Bo(ΔP + Δt)))

Substituting the given values into the equation:

ΔP = 3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15x\(10^{-6}\) * (48 + 48)) / (1.3 * (3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15 x \(10^{-6}\) * (48 + 48)) / (1.3 * (0 + 48))))))

After evaluating the equation, we can find the pressure in the production well at 12 hours of shut-in.

b) Superposition in time is a principle used in pressure transient analysis to analyze and interpret pressure build-up tests.

It involves adding or superimposing the responses of multiple transient tests to simulate the pressure behavior of a reservoir.

The principle of superposition states that the response of a reservoir to a series of pressure changes is the sum of the individual responses to each change.

Superposition allows us to combine the information obtained from multiple tests and obtain a more comprehensive understanding of the reservoir's behavior and properties.

It is a powerful technique used in reservoir engineering to optimize production strategies and make informed decisions regarding reservoir management.

Thus,

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

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The sales tax on a $45.00 clock is $3.60. At this rate, what would the sales tax be on a clock that cost $25.00?

Answers

Answer:

$2.00

Step-by-step explanation:

$45.00 ÷ $3.60 = 12.5

$25.00 ÷ 12.5 = $2.00

Solve the equation. Check your answer.
6x - 3= 5x +5
X=

Solve the equation. Check your answer.6x - 3= 5x +5X=

Answers

Answer:

x = 8

Step-by-step explanation:

6x - 3 = 5x + 5

Move variable to the left hand side and change their sign.

\( \sf \: 6x - 5x - 3 = 5\)

Calculate like terms.

x - 3 = 5.

Move constant to the right hand side and change their sign.

x = 5 + 3x = 8

Check our answer :-

6x -3 = 5x + 5

plug the 8 as x.

6 ( 8 ) - 3 = 5 ( 8 ) + 5 48 - 3 = 40 + 545 = 45

LHS = RHS

Container 1 has 174 lires of oil, Container 2 has 258 litres of oil. Sam pours entire contents of container 1 into smaller jars, so that the oil completely fills the jars and there is no oil left. He also pours the entire contents of container 2 into the same size jars so that there is no oil left. What can the maximum size of the smaller jars be?

Answers

Answer:

The maximum size of the smaller jars is 6 liters

Step-by-step explanation:

Container 1=174 liters of oil

Container 2=258 liters of oil

Same pours the entire content of container one and container 2 into the same number of smaller jars

The maximum size of the smaller jar can be found by finding the highest common factor of 174 and 258

Factors of 174=1,2,3,6,29

Factors of 258=1,2,3,6,43

Common factors of 174 and 258=1,2,3 and 6

Highest common factor=6

Therefore,

The maximum size of the smaller jars is 6 liters

Consider the function f(x)=x^2+3. is the average rate of change increasing or decreasing from x=0 to x=4?Explain

Answers

The average rate of change is increasing over this interval.

Calculating the average rate of change

To find the average rate of change of the function f(x) = x^2 + 3 from x = 0 to x = 4, we can use the formula:

average rate of change = [f(4) - f(0)] / [4 - 0]

Substituting the values of x = 0 and x = 4 into the function f(x), we get:

f(0) = 0^2 + 3 = 3

f(4) = 4^2 + 3 = 19

So, the average rate of change of the function from x = 0 to x = 4 is:

average rate of change = [f(4) - f(0)] / [4 - 0] = (19 - 3) / 4 = 4

This means that the function increases at an average rate of 4 units per unit change in x from x = 0 to x = 4.

Since the average rate of change is a constant value, the function f(x) = x^2 + 3 has a constant rate of increase from x = 0 to x = 4.

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A cylinder whose height is 5 meters has a volume of 320π cubic meters find the radius of the cylinder A.8m b.12.8m c.64m d.201m

Answers

The answer is 64 it’s just dividing the cubic meters by the meters

PLEASE

The following image is of a voltmeter, which measures electric potential, in volts (V).

A voltmeter with numbers 0, 100, 200, 300, 400 & 500. Between 0 & 100, marks split the section into 10 pieces. Space between 100 & 200 is also split into 10 pieces & the others are similar.
Tanasan Sungkaew/Shutterstock
A: What is the smallest increment on the voltmeter?

B: What is the uncertainty?

Select two answers: one for question A and one for question B.

Answers

A: The smallest increment on the voltmeter will be 10V.

B: The uncertainty of the voltmeter will be ±5V.

What is Voltmeter?

The device used to measure the electric potential differential between two points in an electric circuit is called a voltmeter. It is linked simultaneously. It typically has a large resistance so that it uses very little circuit current. Microvolts or less can be measured by meters that use amplification. Digital voltmeters use an analog-to-digital converter to show voltage as a numerical value.

Voltmeters come in a broad variety of designs, some powered separately and others directly from the source of the voltage being measured. Generators and other fixed equipment are monitored by instruments that are permanently installed in a panel.

What is Uncertainty in meter readings?

The accuracy of a digital multimeter (DMM) is typically stated as a percentage of the measurement rather than the full scale reading. An actual value of 100.0V will be read as something between 99.0V and 101.0V by a metre with a specification of 1% of the measurement. A range of digits to the right of the percentage is also typically included in manufacturer specs, for example, (1%+2digits). This illustrates the number of counts that the last figure on the right can change.

In the given question,

A: The smallest increment = 100/(number of splits in the section)

                                            = 100/10 = 10V

B: The uncertainty Δx = smallest increment/2

                                    = 10/2= 5V

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What is the number of one-to-one functions f from the set {1, 2, . . . , 2n} to the set {1, 2, . . . , 2n} so that f(x)\neqx for all 1 ≤ x ≤ n and f(x) = x for some n+1 ≤ x ≤ 2n?

Answers

the number of one-to-one functions f from the set {1, 2, . . . , 2n} to the set {1, 2, . . . , 2n} so that f(x)\neqx for all 1 ≤ x ≤ n and f(x) = x for some n+1 ≤ x ≤ 2n is n(2n-1-n)(2n-2)!.

We can approach this problem using the principle of inclusion-exclusion. Let A be the set of all one-to-one functions from {1, 2, . . . , 2n} to itself, B be the set of all one-to-one functions that fix at least one element in {n+1, n+2, . . . , 2n}, and C be the set of all one-to-one functions that fix at least one element in {1, 2, . . . , n}. We want to count the number of functions in A that are not in B or C.

The total number of one-to-one functions from {1, 2, . . . , 2n} to itself is (2n)!.

To count the number of functions in B, we can choose one element from {n+1, n+2, . . . , 2n} to fix, and then permute the remaining elements in (2n-1)! ways. There are n choices for the fixed element, so the number of functions in B is n(2n-1)!.

Similarly, the number of functions in C is n(2n-1)!.

To count the number of functions in B and C, we can choose one element from {1, 2, . . . , n} and one element from {n+1, n+2, . . . , 2n}, fix them both, and permute the remaining elements in (2n-2)! ways. There are n choices for the first fixed element and n choices for the second fixed element, so the number of functions in B and C is n^2(2n-2)!.

By inclusion-exclusion, the number of functions in A that are not in B or C is:

|A - (B ∪ C)| = |A| - |B| - |C| + |B ∩ C|

= (2n)! - n(2n-1)! - n(2n-1)! + n^2(2n-2)!

= n(2n-1)! - n^2(2n-2)!

= n(2n-2)!(2n-1-n)

= n(2n-1-n)(2n-2)!

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Fill in the missing reason in the proof. Help plss

Fill in the missing reason in the proof. Help plss

Answers

The missing reason in the proof is SAS -side angle side postulate

How to find the missing proof in congruent triangles

A triangle is said to be congruent if the sides and angles are similar. The notations are explained as follows:

Using two triangles say AA and BB as instance

SAS : side angle side: this means that the two sides  of triangle AA is equal to the two sides of triangle BB. For the angle it should be the angle between the two equal sides, that is to say the angle where the two sides intersect.

This is the correct option for the question asked given that

line AB ≅ AC ( first statement )  = Side

< B ≅ < D ( fourth statement ) = Angle

line BD ≅ CD ( third statement )  = Side

This represents the side angle side postulate which is one of the postulates required to prove that triangles are equal

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Find the solution of the square root of the quantity of x plus 3 plus 6 equals 9, and determine if it is an extraneous solution. x = 0; extraneous x = 0; not extraneous x = 6; extraneous x = 6; not extraneous

Answers

The equation square root of (x + 3) + 6 = 9 has two potential solutions, x = 0 and x = 6. However, upon analysis, it is determined that x = 0 is an extraneous solution while x = 6 is not extraneous.

To find the result of the given equation, we'll break it step by step and also determine if any results are extraneous.

 The given equation is

 √( x + 3) 6 = 9

 Let's break it

Step 1 Subtract 6 from both sides of the equation

√( x +3) = 9- 6

√( x +3) = 3

 Step 2 Square both sides of the equation to exclude the square root

( x + 3) = \(3^{2}\)

( x + 3) = 9

 Step 3 Subtract 3 from both sides of the equation

x = 9- 3

x = 6

 The result to the equation is x = 6.

Now, let's determine if this result is extraneous or not.

 To check if the result is extraneous, we need to substitute it back into the original equation and see if it holds true.

Original equation √( x + 3) + 6 = 9

 Substituting x = 6

√( 6 +3) + 6 = 9

√ 9 +6 = 9

3 +6 = 9

9 = 9

Since the equation holds true when x = 6, the result x = 6 is NOT an extraneous result.

thus, the correct statements are

 x = 0; not extraneous

x = 6; not extraneous

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Choose the compound inequality that can be used to solve the original inequality |3x – 5| > 10.

Answers

Step-by-step explanation:

Nsjssjsjsjshsnmsksjnsnsns

An experimenter would like to construct a 99% confidence interval with a width at most 0. 5 for the average resistance of a segment of copper cable of a certain length. If the experimenter knows that the standard deviation of such resistances is 1. 55. How big a sample should the experimenter take from the population? what happens if the standard deviation and the width of the confidence interval are both doubled?.

Answers

A big sample that should the experimenter take from the population is 256 and if the standard deviation and the width of the confidence interval are both doubled then the sample is also 256.

In the given question,

The confidence level = 99%

Given width = 0.5

Standard deviation of resistance(\sigma)= 1.55

We have to find a big sample that should the experimenter take from the population and what happens if the standard deviation and the width of the confidence interval are both doubled.

The formula to find the a big sample that should the experimenter take from the population is

Margin of error(ME) \(=z_{\alpha /2}\frac{\sigma}{\sqrt{n}}\)

So n \(=(z_{\alpha /2}\frac{\sigma}{\text{ME}})^2\)

where n=sample size

We firstly find the value of ME and \(z_{\alpha /2}\).

Firstly finding the value of ME.

ME=Width/2

ME=0.5/2

ME=0.25

Now finding the value of \(z_{\alpha /2}\).

Te given interval is 99%=99/100=0.99

The value of \(\alpha\) =1−0.99

The value of \(\alpha\) =0.01

Then the value of \(\alpha /2\) = 0.01/2 = 0.005

From the standard table of z

\(z_{0.005}\) =2.58

Now putting in the value in formula of sample size.

n=\((2.58\times\frac{1.55}{0.25})^2\)

Simplifying

n=(3.999/0.25)^2

n=(15.996)^2

n=255.87

n≈256

Hence, the sample that the experimenter take from the population is 256.

Now we have to find the sample size if the standard deviation and the width of the confidence interval are both doubled.

The new values,

Standard deviation of resistance(\(\sigma\))= 2×1.55

Standard deviation of resistance(\(\sigma\))= 3.1

width = 2×0.5

width = 1

Now the value of ME.

ME=1/2

ME=0.5

The z value is remain same.

Now putting in the value in formula of sample size.

n=\((2.58\times\frac{3.1}{0.5})^2\)

Simplifying

n=(7.998/0.5\()^2\)

n=(15.996\()^2\)

n=255.87

n≈256

Hence, if the standard deviation and the width of the confidence interval are both doubled then the sample size is 256.

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Put the steps of solving the equation in order from first to last.
2x + 1 = -1

Answers

Answer:

x = 1

Step-by-step explanation:

2x + 1 = -1

2x = -1 - 1

2x = -2

x = -2 ÷ -2

x = 1

A 7-pack of tickets to the zoo costs $78.61. What is the unit price?

Answers

Answer:

$11.23

Step-by-step explanation:

To find the unit price divide the price by the product. For example, 12 ounces of juice costs $2.45. You divide $2.45 by 12 ounces. The unit price would be $0.20.

I hope this helped you, if it did more than all the other answers that may be on your question, feel free to give me brainliest, I would really appreciate it.

A 7-pack of tickets to the zoo costs $78.61. Therefore, the unit price of ticket to the zoo $11.23.

What is division?

The division in mathematics is one kind of operation. In this process, we split the expressions or numbers into same number of parts.

Given that a 7-pack of tickets to the zoo costs $78.61.

To find the unit price;

Cost of one pack of ticket to the zoo = total cost of 7 pack of tickets / number of tickets

Cost of one pack of ticket to the zoo = $78.61 / 7

Cost of one pack of ticket to the zoo = $11.23

Therefore, the unit price of ticket to the zoo $11.23.

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Scott works as a college professor at a community college. He is paid $950 for each credit hour of classes he teaches . If he teaches a total of 51 credit hours , how much can he expect to make ANNUALLY ?

Answers

Given he paid $950 for each credit hour of classes.

If he teaches a total of 51 credit hours.

For 1 credit hour he takes $950. for 51 credit hours, he will take

\(\begin{gathered} 1\text{ hour =\$950} \\ 51\text{ hours = \$950}\times51 \\ 51\text{ credit hours = \$48,450} \end{gathered}\)

Thus, the total money for 51 credit hours will be $48,450.

Use the Distributive Property to find (5s+6)(s−2).

Answers

Answer:

5s^2 - 4s - 12

Step-by-step explanation:

Answer:

5s^2+4-12

Step-by-step explanation:

During this same time, the digital print manager tracked the number of visits to the website’s homepage. he found that before launching the new marketing plan, there were 4,800 visits. over the course of the next 5 weeks, the number of site visits increased by a factor of 1.5 each week. write an equation to model the relationship between the number of weeks, x, and the number of site visits, f(x).

Answers

An equation to model the relationship between the number of weeks, x, and the number of site visits, f(x) is 4800 = a(1.5)^x.

He found that before launching the new marketing plan, there were 4,800 visits.

Over the course of the next 5 weeks, the number of site visits increased by a factor of 1.5 each week.

Over the course of the next 5 weeks, initial visitor at x = 0, 4800

Increasing factor = 1.5

Equation of the model is given as:

f(x) = a(b)^x

From the question b = 1.5

Now the equation of model is:

f(x) = a(1.5)^x

At x = 0, f(x) = 4800

Now the equation of the model is:

4800 = a(1.5)^x

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Kierston needs to paint a wall of the youth center. She knows that 1 can of paint covers an area of 2.2 square meters. Kierston measures the wall using a meter stick as shown below. How many cans of paint must kierston buy to paint the wall of the youth center?

Answers

Answer:

See Explanation

Step-by-step explanation:

Given

\(1\ can = 2.2m^2\)

Required

Determine the number of cans for the wall

The dimension of the wall is not given. So, I will use the following assumed values:

\(Length=20m\)

\(Width = 44m\)

First, calculate the area of the wall

\(Area = Length * Width\)

\(Area = 20m * 44m\)

\(Area = 880m^2\)

If \(1\ can = 2.2m^2\)

Then \(x = 880m^2\)

Cross Multiply:

\(x * 2.2m^2 = 1 * 880m^2\)

\(x * 2.2m^2 = 880m^2\)

\(x * 2.2 = 880\)

Make x the subject

\(x = \frac{880}{2.2}\)

\(x = 400\)

400 cans using the assume dimensions.

So, all you need to to is, get the original values and follow the same steps

Write an equation of a line that has a slope of -3 and goes through the point (-2,6​

Answers

y = -3x

When x = 0, y = 0

When x = -2, y = 6

When x increases by 1, y increases by -3

whats the slope of the line y-9=15 x-5

Answers

The correct slope is 15:)

Answer:

Slope= 15

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Question 5 About 9% of the population has a particular genetic mutation. 500 people are randomly selected. Find the standard deviation for the number of people with the genetic mutation in such groups of 500. Round your answer to three decimal places

Answers

Therefore, the standard deviation for the number of people with the genetic mutation in groups of 500 is approximately 6.726.

To find the standard deviation for the number of people with the genetic mutation in groups of 500, we can use the binomial distribution formula.

Given:

Probability of having the genetic mutation (p) = 0.09

Sample size (n) = 500

The standard deviation (σ) of a binomial distribution is calculated using the formula:

σ = √(n * p * (1 - p))

Substituting the given values:

σ = √(500 * 0.09 * (1 - 0.09))

Calculating the standard deviation:

σ ≈ 6.726 (rounded to three decimal places)

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a real estate agent believes that the value of houses in the neighborhood she works in has increased from last year. to test this claim, she randomly selects houses in this neighborhood and compares their estimated market value in the current year to their estimated market value in the previous year. suppose that data were collected for a random sample of 8 houses, where each difference is calculated by subtracting the market value of the previous year from the market value of the current year. assume that the values are normally distributed. using a test statistic of t≈7.496, the significance level α

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The hypothesis is called the alternative hypothesis test.

According to the statement

We have to explain about the alternative hypothesis.

So, For this purpose, we know that the

The alternative hypothesis is one among ll|one amongst |one in every of} two mutually exclusive hypotheses in a hypothesis test. the choice hypothesis states that a population parameter doesn't equal a specified value.

From the given information:

she randomly selects houses during this neighborhood and compares their estimated market price within the current year to their estimated value within the previous year. suppose that data were collected for a random sample of 8 houses, where each difference is calculated by subtracting the market price of the previous year from the value of the present year.

Then

the alternative hypothesis test usually suggests that there's an opportunity of variation (difference) within the data observed.

Hence, since we are told the "real real estate agent believes that the values of homes within the neighborhood she works in have increased (the chance of variation) from last year," which "each difference is calculated by subtracting the market price of the previous year from the market price of this year," we are able to reach the conclusion that this can be an example of an alternate hypothesis test.

So, The hypothesis is called the alternative hypothesis test.

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Write the equation of the line through the given point. Use slope -intercept form. (-3,7); perpendicular to y=-(4)/(5)x+6

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The slope-intercept form of a line is y = mx + b, where m is the slope and b is the y-intercept. We're supposed to write an equation for a line that is perpendicular to the line y= -(4)/(5)x+6.

The slope of the given line is -(4)/(5).What is the slope of a line that is perpendicular to this line? We can determine the slope of a line perpendicular to this one by taking the negative reciprocal of the slope of this line. That is: slope of the perpendicular line = -1 / (slope of the given line) = -1 / (-(4)/(5)) = 5/4.So the slope of the perpendicular line is 5/4. The line passes through the point (-3,7).

We'll use this information to construct the equation.Using the point-slope form, the equation is:

y - y1 = m(x - x1)Where y1 = 7, x1 = -3 and m = 5/4. So we have:y - 7 = (5/4)(x + 3)

Now let's solve for y: y = (5/4)x + (15/4) + 7

We combine 15/4 and 28/4 to get 43/4: y = (5/4)x + 43/4

The equation of the line that passes through the point (-3,7) and is perpendicular to

y = -(4)/(5)x + 6 is:y = (5/4)x + 43/4.

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What are the factors of 29 prime or composite?

Answers

The factors of 29 are 1 and 29, making it a prime number.

The factors of a number are the integers that divide the number without leaving a remainder. To find the factors of a number, we can use the divisibility rule or the prime factorization method.

In the case of 29, it can be observed that 29 is a prime number, which means it can only be divided by 1 and itself. Therefore, the factors of 29 are 1 and 29. A prime number is a number that is divisible by only 1 and itself, and 29 is a prime number.

It is not divisible by any other number besides 1 and 29.There are no other factors of 29 besides 1 and 29, which makes it a prime number and not composite.

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Kyle used 9 as An estimate for 3 1/6 + 5 7/8. He got 9 1/24 for the exact sum. Is his calculated answer reasonable? Explain

Answers

Kyle's estimate of 9 was not very accurate, but his calculated answer of 9 1/24 is a reasonable approximation of the sum.

To determine if Kyle's calculated answer is reasonable, we can compare it to the original sum of 3 1/6 + 5 7/8.

First, we need to convert the mixed numbers to improper fractions:

3 1/6 = 19/6

5 7/8 = 47/8

Next, we can add the fractions:

19/6 + 47/8 = (152 + 141)/48 = 293/48

Now, we can compare this exact sum to Kyle's estimated answer of 9 and his calculated answer of 9 1/24.

Kyle's estimated answer of 9 is much larger than the exact sum of 6 5/48.

Thus, Kyle's estimate of 9 was not very accurate, but his calculated answer of 9 1/24 is a reasonable approximation of the sum.

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