Can youguys helpplease its for marks and is due tommorow.

The structure of the branched ether of chemical formula c4h10o, is \(CH_3 - CH_2 - CH_2 - O - CH_2 - CH_2 - CH_3.\)

\(C_4H_{10} O\) is a branched ether, also known as an alkoxyalkane or a glycol ether. It is an organic compound composed of four carbon atoms, ten hydrogen atoms, and one oxygen atom. Its molecular formula is \(C_4H_{10} O\)and its molecular weight is 86.13 g/mol.

Its structure is linear, with a carbon backbone and an oxygen atom attached to two of the carbons in the chain. The oxygen atom is then connected to two methyl (\(CH_3\)) groups, one on each side of the central carbon atom.

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Answer:

  -172.6 °C

Explanation:

You want to know the Celsius equivalent of the temperature 100.6 K.

The relation is ...

  C = K - 273.15

  C = 100.6 -273.15 = -172.55

The temperature is -172.55 °C, about -172.6 °C.

__

Additional comment

We have rounded to tenths, because that is precision of the temperature given. If you use 273 as the conversion constant, you will get -172.4.

Answer:

Tom Zepf of the physics department at Creighton University in Omaha, Neb., notes that "Sunlight heats a material such as water or a brick primarily because the long wavelength, or infrared, portion of the sun's radiation resonates well with molecules in the material, thereby setting them into motion.

branliest pls?????/

Explanation:

The heat of reaction, or enthalpy of reaction, for a chemical reaction is the change in enthalpy that occurs when a certain number of reactants are converted to products. It is denoted by ∆H and is defined as the enthalpy of the products minus the enthalpy of the reactants.

To calculate the heat of reaction for the given reaction, we can use the following equation:

∆H = ∑nH°(products) - ∑nH°(reactants)

where ∑n is the sum of the stoichiometric coefficients of the reactants and products, and H° is the standard enthalpy of formation of the species.

The standard enthalpy of formation of a species is the enthalpy change that occurs when 1 mole of the species is formed from its elements in their standard states. It is denoted by H°f and is defined as the enthalpy of the species minus the sum of the enthalpies of the elements in their standard states.

For the given reaction, we can calculate the heat of reaction as follows:

∆H = (2 CO + 4 H₂O) - (2 CH₄ + 3 O₂)

= (2 CO + 4 H₂O - 2 CH₄ - 3 O₂)

= (2 CO - 2 CH₄ + 4 H₂O - 3 O₂)

= 2(H°f(CO) - H°f(C) - H°f(H₂)) + 4(H°f(H₂O) - H°f(H) - H°f(O)) - 3(H°f(O₂) - 2H°f(O))

= 2(-110.5 kJ/mol - 0 kJ/mol - 0 kJ/mol) + 4(-285.8 kJ/mol - 0 kJ/mol - 0 kJ/mol) - 3(-493.5 kJ/mol - 2(-0 kJ/mol))

=∆H = 2(-110.5 kJ/mol - 0 kJ/mol - 0 kJ/mol) + 4(-285.8 kJ/mol - 0 kJ/mol - 0 kJ/mol) - 3(-493.5 kJ/mol - 2(-0 kJ/mol))

= 2(-110.5 kJ/mol) + 4(-285.8 kJ/mol) - 3(-493.5 kJ/mol)

= (-221 kJ/mol) + (-1143.2 kJ/mol) - (-1480.5 kJ/mol)

= (-221 kJ/mol) + (-1143.2 kJ/mol) + 1480.5 kJ/mol

= (-221 kJ/mol) + (-1143.2 kJ/mol) + 1480.5 kJ/mol

= (-221 kJ/mol) + (-1143.2 kJ/mol) + 1480.5 kJ/mol

= (-221 kJ/mol) + (-1143.2 kJ/mol) + 1480.5 kJ/mol

= (-221 k

Answer:

less than 4.9 newtons Explanation:

When Boat A and Boat B have the same mass, the kinetic energy of Boat A is 9 times the kinetic energy of Boat B.

The energy that an object has because of its motion is called kinetic energy. We must apply a force to accelerate an object. Work is done  in applying a force. After work has been done and energy is transferred to the object, then the object will be move with a new constant speed.

Let' m' be the mass of both boats A and B.

It is given in the question that velocity of Boat A is three times greater than that of Boat B. Let the velocity of boat B be X, Kinetic energy of boat A be K₁  and kinetic energy of boat B be K₂

Kinetic energy of Boat A is:

K₁ = 1/2 * (mV₁)^2

  =1/2 * m *3X^2

   =9(1/2*m*X^2)

Kinetic energy of Boat B is:

K₂ = 1/2 *m *V₂^2

     =1/2* m* X^2

K₂ = 1/2*m*X^2

This implies that ,K₁  = 9* K₂

Kinetic energy of Boat A is 9 times the kinetic energy of Boat B.

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The molar absorptivity A for Co(NH3)6³ at 475 nm is 251.5 kJ/mol.

What is Molar Absorptivity?

Molar absorptivity, also known as molar extinction coefficient, is a measure of how strongly a substance absorbs light at a particular wavelength. It is defined as the absorption coefficient divided by the concentration of the absorbing species and the path length of the sample:

To calculate A in J/molecule, we can use the formula:

A = hc / λmax

where A is the molar absorptivity in J/molecule, h is Planck's constant (6.626 x 10^-34 J s), c is the speed of light (2.998 x 10^8 m/s), and λmax is the wavelength of maximum absorbance in meters.

Converting the wavelength of maximum absorbance from nm to meters, we have:

λmax = 475 nm * (1 m / 10^9 nm) = 4.75 x 10^-7 m

A = (6.626 x 10^-34 J s) * (2.998 x 10^8 m/s) / (4.75 x 10^-7 m)

= 4.18 x 10^-17 J/molecule

Therefore, the molar absorptivity A for Co(NH3)6³ at 475 nm is 4.18 x 10^-17 J/molecule.

To convert this value to kJ/mol, we can use the formula:

A (kJ/mol) = A (J/molecule) * N (Avogadro's number) / 1000

where N = 6.022 x 10^23 mol^-1 is Avogadro's number.

Substituting the values, we get:

A (kJ/mol) = (4.18 x 10^-17 J/molecule) * (6.022 x 10^23 mol^-1) / 1000

= 251.5 kJ/mol

Therefore, the molar absorptivity A for Co(NH3)6³ at 475 nm is 251.5 kJ/mol.

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Answer:

only god knows

Explanation:

Explanation:

To calculate the heat gained by nickel, we can use the formula:

q = m * c * ΔT

where q is the heat gained, m is the mass of the nickel, c is the specific heat of nickel, and ΔT is the change in temperature.

Given:

- Mass of nickel, m = 31.4 g

- Specific heat of nickel, c = 0.443 J/g · °C

- Change in temperature, ΔT = 64.2 °C - 27.2 °C = 37.0 °C

Substituting the values into the formula, we get:

q = (31.4 g) * (0.443 J/g · °C) * (37.0 °C)

Simplifying the calculation, we get:

q = 584 J

Therefore, the heat gained by nickel when 31.4 g of nickel is warmed from 27.2 °C to 64.2 °C is 584 J.

Answer:

Explanation:

Start with a balanced equation.

2H2 + O2 → 2H2O

Calculate mole H2 using the formula: n = m/M, where:

n = mole

m = mass (g)

M = molar mass (g/mol)

Calculate molar mass of H2.

M H2 = 2 × 1.008 g/mol = 2.016 g/mol

Calculate moles H2.

n H2 = 4.16 g H2/2.016 g/mol = 2.063 mol H2

Calculate moles H2O by multiplying moles H2 by the mole ratio between H2O and H2 from the balanced equation, so that moles H2 cancel.

2.063 mol H2 × (2 mol H2O/2 mol H2) = 2.063 mol H2O

The mass of water will be calculated by rearranging the n = m/M formula to isolate m;

m = n × M

Calculate the molar mass H2O.

M H2O = (2 × 1.008 g/mol) + (1 × 15.999 g/mol) = 18.015 g/mol

Calculate the mass H2O.

m = n × M = 2.063 mol H2O × 18.015 g/mol = 37.2 g H2O

4.16 g H2 with excess O2 will produce 37.2 g H2O.

The specific heat capacity of the given metal is 0.1234 J/g°C.

The specific heat capacity of a metal is the electricity required to elevate one kilogram (kg) of the cloth by one diploma Celsius (°C).

The specific heat capacity of a substance is the heating ability of a pattern of the substance divided by means of the mass of the pattern, also every so often called massic heat ability. precise warmth capability is a measure of the amount of heat power required to change the temperature of 1 kg of a material by 1 k.

q = m x C x DT

q = m x C x ( T f - T i )

q = amount of heat energy gained or lost by a substance

m = mass of the sample

C = heat capacity ( J oC⁻¹g⁻¹ or J K⁻¹ g⁻¹ )

T f = final temperature

T i = initial temperature

-q metal = q water

-(mCΔT) = mCΔT

-( mC (T f-T i ) =  mC( T f-T i )

- (240 g x C x (27°C-150°C) =  150g(4.18J/g°C ) × ( 27°C-21°C )

- ( 240g × C × -127 °C = 150 × 4.18 × 6°C

C =  150 × 4.18 × 6°C / 240g × -127 °

C = 3762 / 30480

C = 0.1234 J/g°C

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In 58.2 grams of Na there is 1.51 x 10^24 atoms.

To calculate the amount of atoms present in a mass sample, it is necessary to have knowledge of the molar mass of the element and Avogadro's constant, used in such a way that:

\(MM_Na= 23g/mol\)

\(C = 6\times 10^{23}\)

                                       \(MM = \frac{m}{mol}\)

                                    \(23 = \frac{58.2}{x} = > 2.53 atoms\)

Now, with the value of the number of moles, just calculate the number of atoms present, so that:

                                       \(atoms = mol \times C\)

                                     \(atoms = 2.53 \times 6 \times 10^{23}\)

                                        \(atoms = 1.51 \times 10^{24}\)

So, in 58.2 grams of Na there is 1.51 x 10^24 atoms.

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This is due to the fact that a substance's chemical qualities, such as its molecular form, polarity, and functional groups, govern how it behaves and interacts with other substances.

By illustrating the spatial arrangement of atoms and chemical bonds within the molecule, chemical structure establishes the molecular geometry of a compound. In doing so, chemists are given a crucial visual depiction of a chemical formula.

In a chemical reaction, reactants come into contact with one another, atoms in the reactants break their connections with one another, and then the atoms reorganise and form new bonds to create the products.

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Answer:

nuclear fusion

Explanation:

gravity pulls gas and dust together a protostar forms as mass increases nuclear fusion begins under high pressure

When two aqueous solutions are combined, a precipitation process takes place in which an insoluble substance (precipitate) develops. Reactions 1, 2, 3, and 5 in the list are precipitation reactions.

When an impermeable material called a precipitate separates from the solution, a reaction known as a precipitation reaction takes place. As an example, a white precipitate of barium sulphate and sodium chloride solution is created when sodium sulphate solution and barium chloride solution are mixed.

An insoluble material is called a precipitate. For instance, barium sulphate and sodium chloride solution is created when sodium sulphate solution and barium chloride solution are combined.

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Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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The decomposition of aspirin (acetylsalicylic acid,\(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)).

The decomposition of aspirin (acetylsalicylic acid, \(C_{9} H_{8} O_{4}\)) can occur through the hydrolysis reaction, resulting in the formation of acetic acid (\(CH_{3} COOH\)) and salicylic acid (\(C_{7} H_{6}O_{3}\)). To determine the moles of each product formed, we need to consider the balanced chemical equation for the reaction:

\(C_{9} H_{8} O_{4} = > C_{7} H_{6}O_{3} +CH_{3} COOH\)

From the equation, we can see that for every 1 mole of aspirin, 1 mole of salicylic acid and 1 mole of acetic acid are produced.

Therefore, the moles of salicylic acid and acetic acid formed will be equal to the number of moles of aspirin that decomposes. If we know the amount of aspirin in moles, we can directly calculate the moles of each product based on stoichiometry.

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The thickness of the aluminum is approximately 0.00172 cm or 0.0172 mm

To calculate the thickness of the aluminum, we need to use the formula:

Density = Mass / (Length x Width x Thickness)

Given:

Mass of aluminum = 0.475 g

Length of aluminum = 10.08 cm

Width of aluminum = 10.08 cm

We need to rearrange the formula to solve for thickness:

Thickness = Mass / (Length x Width x Density)

The density of aluminum is approximately 2.7 g/cm³.

Now we can substitute the given values into the formula:

Thickness = 0.475 g / (10.08 cm x 10.08 cm x 2.7 g/cm³)

Thickness ≈ 0.475 g / (102.4064 cm² x 2.7 g/cm³)

Thickness ≈ 0.475 g / 275.879104 cm³

Thickness ≈ 0.00172 cm or 0.0172 mm

Therefore, the thickness of the aluminum is approximately 0.00172 cm or 0.0172 mm.

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Answer:

NaOH is the limiting reactant.

204.9 g of sodium phosphate are formed.

51.94 g of excess reactant will remain.

Explanation:

The reaction that takes place is:

First we convert the mass of both reactants to moles, using their respective molar masses:

1.78 moles of H₃PO₄ would react completely with (1.78 * 3) 5.34 moles of NaOH. There are not as many NaOH moles so NaOH is the limiting reactant.

--

We calculate the produced moles of Na₃PO₄ using the limiting reactant:

Then we convert moles into grams:

--

We calculate how many H₃PO₄ moles would react with 3.75 NaOH moles:

We substract that amount from the original amount:

Finally we convert those remaining moles to grams:

The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1, depending on which rate was used to calculate it.

The rate of the reaction is given by the equation:

Rate = -k[A]

where k is the rate constant and [A] is the concentration of the reactant.

Rate at t=140 s:

Rate = (8.00×10−2 M - 0 M) / (140 s - 0 s)

= 5.71×10−4 M/s

Rate at t=400 s:

Rate = (4.00×10−2 M - 0 M) / (400 s - 0 s)

= 1.00×10−4 M/s

Since this is a zero-order reaction, the rate of the reaction is constant, and we can use either rate to calculate the rate constant:

k = Rate / [A]

Using the rate at t=140 s:

k = 5.71×10−4 M/s / 8.00×10−2 M = 7.14×10−3 s−1

Using the rate at t=400 s:

k = 1.00×10−4 M/s / 4.00×10−2 M

= 2.50×10−3 s−1

The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1.

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Answer:

no, and next time take it right

Explanation:

Daria had some beach sand with her. The sand has a 72 gramme mass. She calculated the volume using the graduated cylinder below. The graduated cylinder contains 15 mL of sand.

The volume of the sand is calculated using the graduated cylinder below. The sand's bulk is specified as 72 grammes.

We can use the water displacement method to calculate the volume of the sand. Following is a description of how to estimate the amount of sand using the water displacement method:

The graduated cylinder of water should first be measured for volume.

The graduated cylinder's water volume should then be measured after adding the sand to it. The volume of water increases by the same amount.

Let's use the provided problem to implement this approach.

In the beginning, there is 10 mL of water in the graduated cylinder. The graduated cylinder contains 25 mL of water once the sand has been added.

The amount of sand is therefore equal to the difference between the two volumes, which is: Sand volume equals final water volume minus initial water volume (25 - 10 = 15 mL).

As a result, there are 15 mL of sand in the graduated cylinder.

Answer : 15

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Answer:

It's d

Explanation:

They have two different meaning and jobs

The statement describes the relationship between between microscopic and macroscopic phenomena is microscopic phenomena are a direct cause of macroscopic phenomena. Hence option B is correct

Microscopic phenomena is defined as the processes that exhibit quantum behaviour on a macroscale as opposed to the atomic scale, where most quantum effects occur. The nature and structure of matter at the tiny scales of atoms and nuclei are the subject of the microscopic branch of physics.

Macroscopic phenomena is defined as include collective behaviour of massively interacting quantum particles, and it is very difficult to quantitatively analyse many of these systems. On a macroscopic scale, a quantum phenomena is referred to as a "macroscopic quantum effect" (MQE).

Thus, the statement describes the relationship between between microscopic and macroscopic phenomena is microscopic phenomena are a direct cause of macroscopic phenomena. Hence option B is correct.

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Answer:

endoskeleton i think

Explanation:

The value of Kp for the given reaction at equilibrium is approximately 192,986.689 L atm mol⁻¹.

To calculate the equilibrium constant Kp for the given reaction, we can use the relationship between Kc and Kp, which is expressed as:

Kp = Kc * (RT)^Δn

Where:

- Kp is the equilibrium constant in terms of partial pressures.

- Kc is the equilibrium constant in terms of concentrations.

- R is the ideal gas constant (0.08206 L atm K⁻¹ mol⁻¹).

- T is the temperature in Kelvin.

- Δn is the change in the number of moles of gas (sum of products - sum of reactants).

In this case, the reaction involves four moles of gas on the left-hand side (reactants) and five moles of gas on the right-hand side (products). Therefore, Δn = 5 - 4 = 1.

Given that Kc = 2367 at 999 K, we can substitute these values into the equation:

Kp = 2367 * (0.08206 L atm K⁻¹ mol⁻¹ * 999 K)^1

Simplifying the expression:

Kp = 2367 * (81.367 L atm mol⁻¹)

Calculating the product:

Kp ≈ 192,986.689 L atm mol⁻¹

Therefore, the value of Kp for the given reaction at equilibrium is approximately 192,986.689 L atm mol⁻¹.

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The mass percent of the sodium chloride in the saline solution is approximately 1.33%. The molar concentration of the saline solution is approximately 0.229 M.

To determine the mass percent and molar concentration of the saline solution, we need to analyze the mass of the sodium chloride residue and the initial mass of the sample.

Mass percent:

The mass percent is calculated by dividing the mass of the sodium chloride residue by the initial mass of the sample and then multiplying by 100%.

Mass percent = (Mass of NaCl / Initial mass of sample) × 100%

Mass of NaCl = 0.669 g

Initial mass of sample = 50.320 g

Mass percent = (0.669 g / 50.320 g) × 100% ≈ 1.33%

The mass percent of the sodium chloride in the saline solution is approximately 1.33%.

Molar concentration:

To calculate the molar concentration of the saline solution, we need to determine the number of moles of sodium chloride and the volume of the solution.

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

The molar mass of NaCl is 58.44 g/mol.

Moles of NaCl = 0.669 g / 58.44 g/mol ≈ 0.01144 mol

Since the volume of the sample is given as 50.0 mL, we need to convert it to liters.

Volume of solution = 50.0 mL = 50.0 mL × (1 L / 1000 mL) = 0.0500 L

Now we can calculate the molar concentration (Molarity) using the formula:

Molarity (M) = Moles of solute / Volume of solution (in liters)

Molarity = 0.01144 mol / 0.0500 L ≈ 0.229 M

The molar concentration of the saline solution is approximately 0.229 M.

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The vapor pressure of methanol at 40°C is 0.234 atm.

Only two types of alcohol are methanol and ethanol. Ethanol, sometimes referred to as ethyl alcohol, has a chemical composition of two carbon atoms. Methanol, sometimes referred to as methyl alcohol, is made up of just one carbon atom.

ln(P2/P1) = (ΔHvap/R) x (1/T1 - 1/T2)

ΔGvap = -RTln(Pvap/P) = ΔHvap - TΔSvap

ΔGvap = -RTln(Pvap/P) = -166.6 kJ/mol

ΔSvap = S(g) - S(l) = 239.9 J/mol-K - 126.8 J/mol-K = 113.1 J/mol-K

ΔHvap = ΔGvap + TΔSvap = -166.6 kJ/mol + (298.15 K)(113.1 J/mol-K) = -134.6 kJ/mol

Now we can use the Clausius-Clapeyron equation to find the vapor pressure of methanol at -30°C and 40°C.

At -30°C, we have:

T1 = 25°C + 273.15 = 298.15 K

T2 = -30°C + 273.15 = 243.15 K

ΔHvap = -134.6 kJ/mol

R = 8.314 J/mol-K

ln(P2/5 atm) = (-134.6 kJ/mol / 8.314 J/mol-K) x (1/298.15 K - 1/243.15 K)

P2 = 0.0038 atm

Therefore, the vapor pressure of methanol at -30°C is 0.0038 atm.

At 40°C, we have:

T1 = 25°C + 273.15 = 298.15 K

T2 = 40°C + 273.15 = 313.15 K

ΔHvap = -134.6 kJ/mol

R = 8.314 J/mol-K

ln(P2/5 atm) = (-134.6 kJ/mol / 8.314 J/mol-K) x (1/298.15 K - 1/313.15 K)

P2 = 0.234 atm

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