a) The impedance of the air conditioner is approximately 16.55 Ω.
b)The RMS current in the circuit is approximately 14.51 A.
c)The average power consumed by the air conditioner is approximately 1.57 kW.
To solve this problem, we can use the principles of AC circuit analysis and the formulas related to impedance, current, and power in an AC circuit.
Given:
Resistance (R) = 7.0 Ω,
Inductive reactance (X_L) = 15 Ω,
Frequency (f) = 60.0 Hz,
RMS voltage (V) = 240 V.
Impedance of the Air Conditioner:
The impedance (Z) of an AC circuit with both resistance and reactance is given by the formula:
Z = √(R² + X_L²).
Substituting the given resistance and inductive reactance values:
Z = √((7.0 Ω)² + (15 Ω)²)
≈ √(49 Ω² + 225 Ω²)
≈ √274 Ω²
≈ 16.55 Ω.
Therefore, the impedance of the air conditioner is approximately 16.55 Ω.
RMS Current:
The RMS current (I) in an AC circuit can be calculated using Ohm's law for AC circuits:
I = V / Z,
where V is the voltage and Z is the impedance.
Substituting the given values:
I = (240 V) / (16.55 Ω)
≈ 14.51 A.
Therefore, the RMS current in the circuit is approximately 14.51 A.
Average Power Consumed:
The average power consumed by an AC circuit can be calculated using the formula:
P = V × I × cos(θ),
where P is the average power, V is the voltage, I is the current, and θ is the phase angle between the voltage and current
Since the air conditioner has only resistance and inductive reactance, the power factor (cosθ) is given by:
cosθ = R / Z,
where R is the resistance and Z is the impedance.
Substituting the given resistance and impedance values:
cosθ = (7.0 Ω) / (16.55 Ω)
≈ 0.423.
Now we can calculate the average power:
P = V × I × cos(θ)
= (240 V) × (14.51 A) × (0.423)
≈ 1.57 × 10³ W.
Therefore, the average power consumed by the air conditioner is approximately 1.57 kW.
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The impedance of the circuit is determined as 16.55 ohms.
What is the impedance of the circuit?The impedance of the circuit is calculated by applying the following formula as follows;
Z = √ (R² + Xl²)
where;
R is the resistance of the circuitXl is the inductive reactance of the circuitThe given parameters include;
the resistance of the circuit, R = 7 ohm
the inductive reactance of the circuit, Xl = 15 ohm
The impedance of the circuit is calculated as;
Z = √ (7² + 15²)
Z = 16.55 ohms
Thus, the impedance of the circuit is determined as 16.55 ohms.
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The student concluded that the current in the LDR is inversely proportional to the potential difference across the LDR. Explain why the student's conclusion is incorrect.
The given question is incomplete as the essential graphical result is missing, however the correct graph is attached with the answer :
Answer:
The correct answer is - According to the graph, the current in the LDR is directly proportional to the potential difference across the LDR.
Explanation:
Two variables that are in directly proportion will consistently deliver a straight-line graph that goes through the beginning. On the off chance that the steady of proportionality is sure, the chart will have a positive slope. On the off chance that the steady is negative, the graph will have a negative angle.
In the given data and graph of the result collected by the student shows a straight line in between the current in the LDR and the potential difference across the LDR. It means they are in relation of directly proportional.
Thus, the correct answer is - According to the graph, the current in the LDR is directly proportional to the potential difference across the LDR.
therbligs are: the smallest unit of time used in methods time measurement exercises. the largest unit of time used in methods time measurement exercises. basic physical elements of motion as used in methods time measurement exercises. the full range of motions required to complete a job as used in methods time measurement exercises. the smallest amount of time required to complete a job.
Therbligs are basic physical elements of motion used in methods time measurement exercises to analyze and measure work processes. They represent the smallest unit of time and the full range of motions required to complete a job.
Therbligs were introduced by Frank B. Gilbreth, an industrial engineer, as a means to analyze and improve work processes. They are used in methods time measurement exercises to break down a task or job into its fundamental motions. Each therblig represents a specific basic physical element of motion, such as grasp, position, release, search, transport, and so on. These elements can be combined in different sequences to represent the full range of motions required to complete a job. Therbligs are used to measure the time required to perform each individual motion, and by summing up the times for all therbligs involved, the total time to complete a job can be determined. By analyzing the therbligs involved in a task, engineers can identify inefficiencies, eliminate unnecessary motions, and streamline work processes to increase productivity and reduce fatigue or strain on workers.
Therefore, therbligs serve as a standardized method for measuring and evaluating work processes, allowing for improvements in efficiency and productivity. They represent both the smallest unit of time used in methods time measurement exercises (individual motions) and the largest unit of time (the full range of motions required to complete a job).
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An Olympic high diver has gravitational potential energy because of her height. As she dives, what becomes of her energy just before she hits the water
Just before an Olympic diver hits the water all her potential energy converts into kinetic energy.
Law of conservation of energy states that the total energy of a system remains conserved.
Total mechanical energy = Kinetic energy + Potential energy = Constant.
Thus, the sum of potential energy and kinetic energy for the diver must be constant. So just before she hits the water all her potential energy converts into kinetic energy.
Therefore, just before an Olympic diver hits the water all her potential energy converts into kinetic energy.
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steam is to be extracted at a point between the high and low pressure turbines at a pressure that are to determine. the extracted steam will be isobarically heat-exchanged to supply the process hot water and exit the heat exchanger as saturated liquid. this liquid is then throttled to the condenser pressure and mixed with the fluid exiting the lowpressure turbine. the fuel will be natural gas which has a higher heating value (hhv) of 23,860 btu/lbm and an availability of 21930 btu/lbm. the boiler efficiency based on the hhv is 0.85. heat losses from the turbines, pump and lines are assumed negligible and the generator efficiency may be assumed to be 0.90. neglect pressure drops in the piping and heat exchangers.
Steam, Heat Exchange, Natural Gas, Throttle The steam is extracted between the high and low pressure turbines at a pressure to be determined, which is then isobarically heat exchanged with the process hot water, exiting the heat exchanger as a saturated liquid. This liquid is then throttled to the condenser pressure and mixed with the fluid exiting the low-pressure turbine.
To calculate the power output of the system, the energy and mass balances for the process must be established. These balances can be used to calculate the mass flow rate of the natural gas, the mass flow rate of the steam, the heat input and the power output. In addition, the properties of the natural gas can be used to calculate the enthalpy of the inlet gas, the enthalpy of the steam, and the enthalpy of the inlet air.
The energy balance equation states that the total energy entering the system is equal to the total energy leaving the system. The mass balance equation states that the total mass entering the system is equal to the total mass leaving the system. From these two equations, the enthalpy of the steam and the mass flow rate of the natural gas can be calculated.
The heat input to the system is equal to the total enthalpy of the steam plus the enthalpy of the natural gas. The power output of the system is equal to the heat input multiplied by the efficiency of the generator. This can be used to calculate the power output of the system.
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How are stars formed and classified?
Given the equation describing the displacement of an object undergoing simple harmonic motion, Find the maximum acceleration of the object.
The maximum acceleration of the object is 10.94 x 10² m/s².
The equation of displacement is given as,
y(t) = 4.8 cos(15.1 t)
It is in the form, y(t) = A cos(ωt)
So, the amplitude of the SHM, A = 4.8 m
Angular frequency, ω = 15.1 s⁻¹
The maximum acceleration,
a(max) = -Aω²
the -ve sign indicates that the acceleration is acting towards the mean position.
a(max) = 4.8 x 15.1²
a(max) = 10.94 x 10² m/s²
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You arrive in my class 45 seconds after leaving math which is 90 meters away. How fast did you travel?
Answer:
2m/s
Explanation:
speed = distance÷time
speed =90÷45=2m/s
a car starts from the rest and accelerates at 9.54m/s for 6.5 seconds. what is the distance covered by the car
Answer:
= 201.53 meters
Explanation:
A car started from rest and accelerated at 9.54 m/s^2 for 6.5 seconds. How much distance was covered by the car?
Use the formula d = \(\frac{at^{2} }{2} ,\)
where d is the distance, t is the time and "a" is the acceleration.
\(d=\frac{9*54*6*5^{2} }{2} = 201.53 m\)
A man is attempting to push a mule into a fenced area. He exerts 225 N of force on the animal for 20 min, but the mule does not budge. How much work has the man done
The work done by the man while attempting to push a mule into a fenced area is zero. Work is defined as the application of a force over a distance in the direction of the force.
The definition of work is the amount of energy it takes to move an object over a certain distance. Work is calculated using the formula: Work = force x distance x cos(theta),Where force is the force applied to the object, distance is the distance over which the force is applied, and cos(theta) is the angle between the force vector and the displacement vector.
The force the man exerts is 225 N, but since the mule does not budge, there is no displacement, and therefore, no work is done by the man.So, the answer is zero work.
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a group of students launches a model rocket in the vertical direction. based on tracking data, they determine that the altitude of the rocket was 89.6 ft at the end of the powered portion of the flight and that the rocket landed 17 s later. the descent parachute failed to deploy so that the rocket fell freely to the ground after reaching its maximum altitude. assume that g
The speed of rocket is ,V₀ = 268.42ft/sec
A projectile is an object upon which the only force is gravity.
a rocket launched in vertical direction by a group of students.
The path of projectile will be parabola.
to find the speed of the rocket is we use the equation of a projectile motion the data determined by them is
Initial height is.\(y_{0 } =\) 89.6 ft
final height is \(y_{f} =\) 0ft
time taken, t = 17sec
as we know , g = 32.2 ft/s²
g is acceleration due to gravity.
\(y_{f} - y_{o} = V_{o}t - \frac{1}{2} g t^{2}\)
0 = 89.6 + 17V₀ - 16.1 × (17)²
V₀ = 268.42ft/sec
The speed of rocket is ,V₀ = 268.42ft/sec
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Considering only this generation, a tortoise that lived to 100 and had 10
surviving offspring had equal fitness as a tortoise that lived to 30 and had 10
surviving offspring. Likely or Unlikely
It is unlikely that a tortoise that lived to 100 and had 10 surviving offspring had equal fitness as a tortoise that lived to 30 and had 10 surviving offspring considering only this generation.
The concept of fitness in evolutionary biology refers to an organism's ability to survive and produce offspring in its environment. Fitness is measured by an individual's reproductive success relative to others in the same population. In this case, both tortoises had the same number of surviving offspring (10), which suggests that they had the same reproductive success.
Therefore, it is unlikely that they had equal fitness, despite the difference in lifespan. However, it's worth noting that this is a simplified example, and in reality, there are many factors that can affect an organism's fitness, including its ability to survive and reproduce over multiple generations.
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1. Why are the outer planets called “gas planets?”
Answer:
They are also called the gas planets because they consist mainly of hydrogen, or the giant planets because of their size. These planets usually have complicated system of many moons and often even rings of ice and/or dust. There are four Jovian planets in the Solar System: Jupiter, Saturn, Uranus and Neptune.
Answer:
They are also called the gas planets because they consist mainly of hydrogen, or the giant planets because of their size. These planets usually have complicated system of many moons and often even rings of ice and/or dust. There are four Jovian planets in the Solar System: Jupiter, Saturn, Uranus and Neptune.
Explanation:
i hope this helps :)
why is it easier to stop a lightly loaded truck than a heavier one that has equal speed?
It is easier to stop a lightly loaded truck than a heavier one with equal speed due to the concept of inertia and the relationship between mass and momentum.
Inertia is the tendency of an object to resist changes in its state of motion. The greater the mass of an object, the greater its inertia. When a truck is in motion, it possesses kinetic energy and momentum.
When we apply brakes to stop a moving truck, we need to counteract its momentum. Momentum is the product of an object's mass and velocity and is a measure of how difficult it is to change the object's motion. The momentum of an object is directly proportional to its mass.
In the case of a heavily loaded truck, it has a greater mass compared to a lightly loaded truck. Consequently, it possesses a greater amount of momentum at the same speed. The greater momentum requires a greater force to stop the truck.
When braking is applied, the force of friction between the truck's tires and the road surface acts as the decelerating force. The force of friction is the same for both the lightly loaded and heavily loaded truck, assuming all other factors remain constant. However, the heavier truck has a greater resistance to changes in motion due to its higher mass and momentum. As a result, it requires a stronger and longer-lasting braking force to overcome its inertia and bring it to a stop.
In summary, the greater mass and momentum of a heavily loaded truck make it more challenging to stop compared to a lightly loaded truck with the same speed. The heavier truck's increased inertia necessitates a greater force to counteract its momentum and bring it to a halt.
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Why do reference points change based on who is observing?
Reference points change based on who is observing because they are subjective and depend on the frame of reference of the observer. A frame of reference is the set of coordinates and axes used to describe the position and motion of objects.
Different observers may have different perspectives, locations, or velocities relative to the observed object, leading to different reference points.
For example, consider two people observing a moving car. If one person is standing still on the sidewalk, their reference point would be the stationary position relative to the car. However, if another person is in a moving car alongside the observed car, their reference point would be the moving car itself.
Therefore, each observer's unique frame of reference affects their perception and measurement of position, velocity, and other physical quantities. Recognizing the relativity of reference points is crucial in understanding how different observers may have different interpretations of the same event or object's motion.
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If the mass of an object is 8 kg and its momentum is 48 kgm/s, what is its velocity?
A. 12 m/s
B. 384 m/s
C. 8 m/s
D. 6 m/s
Question :-
If the Mass of an Object is 8 kg and its Momentum is 48 kg m/s . What is its Velocity ?12 m/s384 m/s8 m/s6 m/sAnswer :-
Velocity of the Object is 6 m/s .Explanation :-
As per the provided information in the given question, we have been given that the Mass of the Object is 8 kg . Its Momentum is given as 48 kg m/s . And, we have been asked to calculate the Velocity of the Object .
For calculating the Velocity , we will use the Formula :-
\( \bigstar \: \: \: \boxed{ \sf{ \: Velocity \: = \: \dfrac{Momentum}{Mass} \: }} \)
Therefore , by Substituting the given values in the above Formula :-
\( \dag \: \: \: \sf {Velocity \: = \: \dfrac {Momentum}{Mass} } \)
\( \longmapsto \: \: \sf {Velocity \: = \: \dfrac {48}{8} } \)
\( \longmapsto \: \: \textbf {\textsf {Velocity \: = \: 6 \: m/s}} \)
Hence :-
Fourth Option is Correct Answer .\( \underline {\rule {180pt} {4pt}} \)
1. Which of the following statements is false? A) During a reaction, electrons move from an electrophile to a nucleophile B) Homolytic bond cleavage yields neutral radicals in which each atom gains on
The false statement is B) Homolytic bond cleavage yields neutral radicals in which each atom gains one electron.
In homolytic bond cleavage, each atom retains one electron from the shared pair of electrons, resulting in the formation of two neutral radicals, where each atom retains its original number of electrons.
No atoms gain or lose electrons in this process.
In a homolytic bond cleavage, a covalent bond is broken, and the shared pair of electrons is split equally between the two atoms involved in the bond.
This results in the formation of two neutral radicals, with each atom retaining one of the electrons from the shared pair.
A radical is a chemical species characterized by the presence of an electron that is unpaired, meaning it does not have a partner electron with which it forms a complete pair. When a covalent bond is homolytically cleaved, each atom involved in the bond gains one electron, resulting in the formation of two radicals.
These radicals are highly reactive due to the presence of the unpaired electron, which makes them prone to participate in further chemical reactions.
It's important to note that in homolytic bond cleavage, there is no transfer of electrons from one atom to another.
Instead, the bond is broken in a way that allows each atom to retain one of the electrons, leading to the formation of two neutral radicals.
Therefore, statement B, which suggests that each atom gains one electron, is false.
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Convert 149 °F into a °C, (b) Kelvin
Answer:
a.149 °F into °C
149 - 32 = 117
117 x 5 = 585
585 / 9 = 65
149 °F = 65 °C
b.149 °F into Kelvin
(149°F − 32) × 5/9 + 273.15 = 338.15K
when being charged electrical pressure voltage higher than that of the batteryties total cell_____
When being charged with electrical pressure voltage higher than that of the batteries' total cell count.
When being charged with electrical pressure voltage higher than that of the batteries' total cell count, there is a risk of overcharging the batteries. This can cause damage to the batteries, such as electrolyte loss, heat buildup, and even explosions. It is important to use a charger that is specifically designed for the batteries being used and to never exceed the recommended charging voltage. Additionally, monitoring the charging process and ensuring the batteries do not become too hot can help prevent damage and prolong the lifespan of the batteries.
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A jogger that is initially running in a straight line on level ground at 3.0 m/s uniformly accelerates at 2.0 m/s
2
for a time of 3.0 s. How far does the jogger run in this time interval? a. 16 m b. 20 m c. 12 m d. 14 m e. 18 m
The jogger runs a distance of 18.0 meters in the given time interval.
Hence, the correct answer is e. 18 m.
To determine the distance the jogger runs in the given time interval, we can use the equation of motion for uniformly accelerated motion:
s = ut + (1/2)at^2,
where s is the distance, u is the initial velocity, a is the acceleration, and t is the time. Velocity is a vector quantity that describes the rate of change of an object's position with respect to time.
Mathematically, velocity (v) is calculated using the formula:
v = Δx / Δt,
Given:
Initial velocity, u = 3.0 m/s
Acceleration, a = 2.0 m/s^2
Time, t = 3.0 s
Substituting these values into the equation, we get:
s = (3.0 m/s)(3.0 s) + (1/2)(2.0 m/s^2)(3.0 s)^2
s = 9.0 m + (1/2)(2.0 m/s^2)(9.0 s^2)
s = 9.0 m + 9.0 m
s = 18.0 m
Therefore, the jogger runs a distance of 18.0 meters in the given time interval.
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suppose you drive to and from work on a street that runs east to west. on what day would you most likely have the sun shining directly in your eyes while driving to and from work?
On the autumnal equinox, you would probably be driving to and from work with the sun shining directly in your eyes.
Autumnal equinox, either of the two points in the sky where the ecliptic (the Sun's annual pathway) and the celestial equator intersect. These two times of the year when the Sun is exactly above the Equator and day and night are of equal length.
On Thursday, September 22, the autumnal equinox takes place, and at that time the sun will be directly overhead the equator of the planet. This implies that each day and night last roughly 12 hours for everyone on Earth. The first day of autumn in the Northern Hemisphere is the September equinox.
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8. Give the net force for the following:
10 N
30 N
3N
3N
2N →
4N->
Js
SN
Answer:
i think it's is 30N
Explanation:
i got it right
Which line on the graph represents the greatest positive acceleration?
D
A
B
C
Answer:
I think it's B, if that's wrong I apologize. You might want to do more research on it and find the correct answer if you can, if it's right then you could like my comment, so others know if not give it 1 star, keep it low lol.
Explanation:
The line that represents the greatest positive acceleration is A.
In a velocity-time graph, the slope of the line represents the acceleration. The greater the slope, the greater the acceleration. Line A has the steepest slope, so it represents the greatest positive acceleration.
Line B has a positive slope, but it is not as steep as line A. Line C has a negative slope, which means it represents negative acceleration, or deceleration. Line D is a horizontal line, which means it represents a constant velocity, or zero acceleration.
Therefore, the line that represents the greatest positive acceleration is A.
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if you Launch a cannonball at a launch angle of 55° and an initial speed of 30m/s. What is the cannonball's range?
Answer:
86.2 m range
Explanation:
Vertical component of initial shot = 30 sin 55= 24.575 m/s
Now you can find out for how long it is in the air
when it hits the ground , position = 0
0 = 24.575 t - 1/2 ( 9.81) t ^2
finds t = 5.01 seconds (Using quadratic formula)
HORIZONTAL component = 30 cos 55 = 17.21 m/s
it travels this speed for 5.01 seconds
5.01 * 17.21 = 86.2 m
You slide a TV up a ramp to move it into a house. What kind of simple
machine are you using?
O A. Screw
B. Inclined plane
O c. Wheel and axle
O D. Lever
SUBMIT
Answer:
inclined plane
Explanation:
An inlcined plane is a simple machine used to slide an object over an obstacle
toge
e
6. Refer to the illustration below.
90
www
R₂ 1513
www
R₂ 1013
a. what is the total power in the circuit?
b. What is the total resistance of this
circuit?
The total resistance of this circuit is 15Ω and the total power of the circuit is 60W.
The power is the ratio of the square of voltage and resistance. The total resistance is obtained from the addition of series and parallel resistance.
From the given,
Total resistance (Requ) = R₁ + R₂
R₁ is a series resistance
R₂ is the parallel resistance
R₂ = 1/15 Ω + 1/10 Ω
= 10×15 / (15+10)
= 150 / 25
= 6Ω
Parallel resistance R₂ = 6Ω
R(equivalent) = R₁ + R₂
= 9 + 6
= 15Ω
Thus, the total resistance is 15 Ω.
The total power, P = E² / R(equivalent)
E represents the voltage
R(equivalent) is the equivalent resistance
P = 30×30 / 15
= 60 watts.
Thus, the total power in the circuit is 60 watts.
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A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8.0 m from the takeoff point.
If the kangaroo leaves the ground at a 22˚ angle, what is its takeoff speed?
What is its horizontal speed?
The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.
What is the sound's velocity?By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.
Briefing:The following equation relates the distance to the direction and initial velocity:
d = [v₀²sin2θ]/g, where θ – the angle of the jump.
Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62
v₀ = 10.65 m/s ( the take off speed).
The horizontal velocity equals:
vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s
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A baseball is thrown with a speed of 36 meters per second (m/s). What is the distance
from the mound to home plate if the ball takes 0.5 seconds to leave the pitcher's hand
and cross the plate?
72 meters
41 meters
31 meters
18 meters
18 meters
36m/s ÷ 2 = 18 m/s
Answer:
D
Explanation:
Formula
d = r * t
Givens
r = 36 m/s
t = 0.5 sec
Solution
d = r * t
d = 36 * 0.5
d = 18 m/s
A rocket travels vertically at a speed of 1200 km/h. The rocket is tracked through a telescope by an observer located 16km from the launching pad. Find the rate at which the angle between the telescope and the ground is increasing 3 min after lift-off. Round your answer to the nearest hundredth rad/hr
Answer:
w = 0.01 t⁻² rad/h
Explanation:
Let's use trigonometry to find the elevation angle of the telescope, we assume that the rocket remains fixed in the telescope.
tan θ = CO / CA
the adjacent leg is CA = 16 km = 16 10³ m
Let's use kinematics to find the height of the rocket
v = y / t
y = v t
this height is equal to the opposite leg
CO = v t
we substitute
tan θ = vt / 16
tan θ = 1200/16 t
tan θ = 75 t
θ = tan⁻¹ ( 75 t )
speed is defined by
w = dθ/dt
w = \(\frac{1}{1 + (75 t)^2} \ 75\)
as time increases we can neglect the 1 of the denominator
w = 1/75 t²
w = 0.0133 t⁻²
Using three significant figures
w = 0.01 t⁻² rad/h
for this answer the time must be given in hours
The plates of a parallel-plate capacitor are connected to a battery. if the distance between the plates is halved, the energy of the capacitor
A. Increases by a factor of 4.
B. Doubles.
C. Remains the same.
D. Is halved.
E. Decreases by a factor of 4.
As 'd' becomes doubled in the parallel-plate capacitor are connected to a battery, energy decreases by the factor of 2.
The energy stored in a parallel plate capacitor is given by the following formula:
\(U=\frac{1}{2} CV^{2}\)
\(C= \frac{A}{d}\)∈
then,
\(U= \frac{1}{2} \frac{A}{d} V^{2}\) ----- (1)
As it can be seen from the equation (1) that energy is inversely proportional to the separation between the plates. 'D' becomes doubled, and energy decreases by the factor of 2.
Energy stored in a capacitor can be expressed as the following:
E = (1/2)CV^2 .....1
We must know that the capacitance of a capacitor is inversely proportional to the distance between the two plates.
C = kA/d ....2
Whenever the value d doubles, and every other determinant of capacitance remains the same, the value of capacitance is halved.
Cf = kA/2d = C/2
Cf = C/2
Potential difference remains the same, the energy stored would also be halved since the energy stored in the capacitor is directly proportional to the capacitance.
Ef = (1/2)(Cf)V^2
Ef = (1/2)(C/2)V^2 = [(1/2)CV^2]/2
Ef = E/2
Where;
E is the initial energy stored in the capacitor respectively
Ef is the final energy stored in the capacitor respectively
C is the initial capacitance of the capacitor.
Cf is the final capacitance of the capacitor.
d is the distance between the plates
A is the area of plates
k is the permittivity of dielectrics
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i.the heater has power output of 3kw
What does the 'k' stand for in 'kW'?
How much energy (in joules) does the heater deliver in one second?
ii.
How much energy (in joules) does the heater deliver in 7 minutes?
Answer:
2
cos
(
x
)
−
√
3
=
0
2
cos
(
x
)
-
3
=
0
5
3
y
+
5
2
=
5
5
3
y
+
5
2
=
5
x
−
4
≥
0
Explanation:hopefully this helps you