Answers
Answer:
#1 ( Balanced ) ( Rest)
#2 ( Unbalanced) ( Accelerating)
Explanation:
Related Questions
A bus of mass 2500 kg goes round a corner of radius 50 m at a speed of 5 m/s. What force is needed for the bus to go round the corner?
Answers
Answer:
force needed for the bus to go round the corner is 50,000 N.
Explanation:
To find the force needed for the bus to go round the corner, we can use the formula for centripetal force:
F = (mv^2)/r
where F is the centripetal force, m is the mass of the object, v is the velocity of the object, and r is the radius of the circular path.
Plugging in the values given in the problem, we get:
F = (2500 kg)(5 m/s)^2 / 50 m
= 50,000 N
So the force needed for the bus to go round the corner is 50,000 N.
The archerfish uses a remarkable method for catching insects sitting on branches or leaves above the waterline. The fish rises to the surface and then shoots out a stream of water precisely aimed to knock the insect off its perch into the water, where the archerfish gobbles it up. Scientists have measured the speed of the water stream exiting the fish's mouth to be 3.7 m/s. An archerfish spots an insect sitting 18 cm above the waterline and a horizontal distance of 28 cm away. The fish aims its stream at an angle of 39° from the waterline.
Required:
Determine the height above the waterline that the stream reaches at the horizontal position of the insect.
Answers
Answer:
The fish gobbles the mosquito at height 18 cm.
Explanation:
Initial velocity, u = 3.7 m/s
horizontal distance, d = 28 cm
Angle, A = 39 degree
Let the time is t.
Horizontal distance = horizontal velocity x time
d = u cos A x t
0.28 = 3.7 cos 39 x t
t = 0.097 s
Let the height is h.
Use the second equation of motion
\(h =u t-0.5 gt^2\\\\h= u sin A t - 0.5 gt^2\\\\h= 3.7 sin 39 \times 0.097 - 0.5\times 9.8\times 0.097\times0.097\\\\h =0.226 -0.046 \\\\h=0.18 m=18 cm\)
A 1420-kg car moving east at 17.0 m/s collides with a 1880-kg car moving south at 15.0 m/s, and the two cars connect together.A. What is the magnitude of the velocity of the cars right after the collision? (m/s )B. What is the direction of the cars right after the collision? Enter the angle in degrees where positive indicates north of east and negative indicates south of east. (°)C. How much kinetic energy was converted to another form during the collision? (kJ)
Answers
Given,
The mass of the car moving east, m=1420 kg
The mass of the car moving south, M=1880 kg
The velocity of the car moving east, u₁=17.0 m/s
The velocity of the car moving south, u₂=-15.0 m/s
Here we assume that the eastward direction is the positive x-direction and the southward direction is the negative y-direction.
From the law of conservation of momentum, the momentum is conserved in both directions simultaneously and independently.
Considering the conservation of momentum in the x-direction,
\(mu_1=(m_{}+M)v_x\)Where v_x is the x-component of the final velocity of the two cars.
On substituting the known values,
\(\begin{gathered} 1420\times17.0=(1420+1880)v_x \\ v_x=\frac{1420\times17.0}{(1420+1880)} \\ =7.32\text{ m/s} \end{gathered}\)Considering the conservation of momentum in the y-direction,
\(Mu_2=(m+M_{})v_y\)Where v_y is the y-component of the final velocity of the cars.
On substituting the known values,
\(\begin{gathered} _{}1880\times-15.0=(1420+1880)v_y \\ v_y=\frac{1880\times-15.0}{(1420+1880)} \\ =-8.55\text{ m/s} \end{gathered}\)A.
The magnitude of the velocity of the cars tight after the collision is given by,
\(v=\sqrt[]{v^2_x+v^2_y}\)On substituting the known values,
\(\begin{gathered} v=\sqrt[]{7.32^2+(-8.55)^2} \\ =11.26\text{ m/s} \end{gathered}\)Thus the magnitude of the velocity of the cars right after the collision is 11.25 m/s
B.
The direction of the cars right after the collision is given by,
\(\theta=\tan ^{-1}(\frac{v_y}{v_x})\)On substituting the known values,
\(\begin{gathered} \theta=\tan ^{-1}(\frac{-8.55}{7.32}) \\ =-49.4^{\circ} \end{gathered}\)Thus the direction of the cars right after the collision is -49.4°. That is 49.4° south of the east.
C.
The total kinetic energy of the system is before the collision is
\(K_1=\frac{1}{2}mu^2_1+\frac{1}{2}Mu^2_2\)On substituting the known values,
\(\begin{gathered} K_1=\frac{1}{2}\times1420\times17.0^2+\frac{1}{2}\times1880\times15.0^2 \\ =205.19\times10^3+211.5\times10^3 \\ =416.69\times10^3\text{ J} \end{gathered}\)The kinetic energy of the system of two cars after the collision is,
\(\begin{gathered} K_2=\frac{1}{2}(m+M)v^2 \\ =\frac{1}{2}\times(1420+1880)11.26^2 \\ =209.2\times10^3\text{ J} \end{gathered}\)Thus the kinetic energy lost during the collision is,
\(\Delta K_{}=K_1-K_2\)On substituting the known values,
\(\begin{gathered} \Delta K=416.69\times10^3-209.2\times10^3 \\ =207.49\times10^3\text{ J} \\ \approx207.5\text{ kJ} \end{gathered}\)Thus the total kinetic energy lost during the collision is 207.5 kJ
the 10 ib weight is supported by the cord ac and roller and by a spring. if the spring has an unstreftched length of 8 in. and the weight is in equilibrium when d
Answers
The Spring constant k (Stiffness ) will be 6.8 Ib/in for the spring which has an unstretched length of 8 in for 10 lb when d = 4in as given in the problem.
As shown in the picture attached the net force on the y-axis is 0. And Fab*4/\(\sqrt{160\\}\)} = 10
Fab = 31.61 Ib.
Fab = K(L-L0)
31.62 = k (\(\sqrt{160}\) -8 => 6.8 Ib/in
As spring force is a conservative force where each spring has its own k(Spring constant ) which depends upon the material, Turns, and Size of the spring. To calculate Spring force F = -kx, where k is constant and x, is the length displayed by the force (Stretched or unstretched). The Force might be affected by the temperature around as of material used for making the spring.
Learn More about Spring Force: https://brainly.com/question/28203351
#SPJ4
Louis Armstrong ride his bike 55km east time trial in 51 minutes what was his average velocity in KM/min?
Answers
Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.
How to determine average velocity?To calculate the average velocity, divide the total displacement by the total time taken. In this case, Louis Armstrong rode his bike 55 km to the east in a time trial lasting 51 minutes.
Average Velocity = Displacement / Time
Displacement = 55 km (since he rode 55 km to the east)
Time = 51 minutes
Average Velocity = 55 km / 51 min
To express the average velocity in km/min, convert the time from minutes to minutes.
1 hour = 60 minutes
Average Velocity = 55 km / 51 min × (1 hour / 60 min)
Average Velocity = 55 km / 51 min × (1/60) hour
Simplifying the expression:
Average Velocity = 1.078 km/min
Therefore, Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.
Find out more on average velocity here: https://brainly.com/question/24445340
#SPJ1
A 40.0-kg football player leaps through the air to collide with and tackle a 50.0-kg player heading toward him, also in the air. If the 40.0-kg player is heading to the right at 9.0 m/s and the 50.0-kg player is heading toward the left at 2.0 m/s, what is the speed and direction of the tangled players
Answers
Answer:
The speed and direction of the tangled players is 2.89 m/s towards right.
Explanation:
Given;
mass of the player heading right, m₁ = 40 kg
initial velocity of the player heading right, u₁ = 9.0 m/s
mass of the player heading left, m₂ = 50 kg
initial velocity of the player heading left, u₂ = -2.0 m/s
let the speed of the tangled players = v
Apply the law of conservation of linear momentum;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(40 x 9) + (50 x - 2) = v(40 + 50)
360 - 100 = v(90)
260 = v(90)
v = 260 / 90
v = 2.89 m/s (towards right, since it is in position direction)
Therefore, the speed and direction of the tangled players is 2.89 m/s towards right.
A 52.07kg cannon has a recoil velocity of 7.75m/s after it launches a 9.06kg projectile horizontally. The cannon ball hits a 26.28kg target (haystack) several meters away. It takes only 0.32 seconds for the cannon ball to pass through the target breaking it into two segments of equal mass one launching at 27.89 degrees off center in the x, the other 39.62 degrees off center in the y. Assume the cannon ball continues in a true horizontal trajectory.what is the momentum of the cannon ball before the collision with the haystack?
Answers
Given data:
* The mass of the cannon is 52.07 kg.
* The recoil velocity of the cannon is 7.75 m/s.
* The mass of the cannon ball is 9.06 kg.
Solution:
By the law of conservation of the momentum,
The momentum of the cannon ball before the collision is the same as the momentum of the cannon ball from the cannon.
The momentum of the cannon ball from the cannon is,
\(p=mv\)where m is the mass of the cannon and v is the recoil velocity of the cannon,
Substituting the known values,
\(\begin{gathered} p=52.07\times7.75 \\ p=403.54kgms^{-1} \end{gathered}\)Thus, the momentum of the cannon ball before the collision is 403.54 kgm/s.
You are working on a project to make a more efficient engine. Your team is investigating the possibility of making electrically controlled valves that open and close the input and exhaust openings for an internal combustion engine. Determine the stability of the valve by calculating the force on each of its sides and the net force on the valve.
The valve is made of a thin but strong rectangular piece of non-magnetic material that has a current-carrying wire along its edges. The rectangle is 0.35 cm x 1.83 cm. The valve is placed in a uniform magnetic field of 0.15 T such that the field lies in the plane of the valve and is parallel to the short sides of the rectangle. The region with the magnetic field is slightly larger than the valve. When a switch is closed, a 1.7 A current enters the short side of the rectangle on one side and leaves on the opposite short side of the rectangle. At the suggestion of a colleague, who is hoping to ensure different currents along the sides of the valve, resistors have been included along the wire on each of the short sides of the valve. The value of the resistor on one side is twice that on the other side.
Answers
Answer:
The answer is "0.00466 N".
Explanation:
\(F=(B \times i) L\\\\\)
therefore the smaller side is parallel to magnetic field
\(\therefore \\\\F= B i L\ \sin\ 'o'=0 \ N\)
calculating the force on the layer side:
\(\to F=0.15 \times 1.7 \times 0.0183 \times \sin 90^{\circ}=0.00466\ N\\\\\)
Therefore \(F_o\) the net force on the rectangular loop \(= 0.00466 \ N\)
QUESTIONS An athlete, during his race in the 100 m sprint in the 2008 Beijing Olympics, exerted #force of 850 s on the race track using his show on the right foot at an angle of 50/' to the horizontal, 850 N 3.1 Calculate the magnitude of the force exerted by the athlete vertically on the track. 3.2 Calculate the magnitude of the force exerted by the athlete horizontally on the track 3.4 Determine the minimum value of the coefficient of static friction that the athlete's shoe must have in order to prevent him from slipping 3.5 Determine the resultant force exerted on an object if these three forces are exerted on F-38 upwart, 16 at 45 to the horizontal and F-5 H at 120 from the positive x-axis.
Answers
I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.
3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).
3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).
3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.
3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.
Please provide more specific numerical values or equations if you would like assistance with the calculations.
URGENT HELP PLS
(a) Find the frequency ratio between the two frequencies f1 = 320 Hz and
½2 = 576 Hz.
S) If we go down from / by an interval of a fourth, find the frequency ratio filfi.
(c) Find the frequency of f3.
Answers
The frequency of f3 is approximately 716 Hz.
What is frequency?The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.
a. Given two frequencies, f1 and f2, the frequency ratio is as follows:
frequency ratio= \(\frac{f2}{f1}\)
Inputting the values provided yields:
frequency ratio = \(\frac{576}{320Hz}\) =1.8.
As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.
b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:
frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)= \(\frac{f}{ (f1 / 1.3348) }\)
By dividing the numerator and denominator by 1.3348, we may make this more straightforward:
frequency ratio= (f × 1.33348)/f1
As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.
c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831
Therefore, the frequency of f3 is:
f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz
Therefore, the frequency of f3 is approximately 716 Hz.
To know more about frequency, visit:
brainly.com/question/14316711
#SPJ1
QUICK!!!!
newtons second law of motion states that an object acceleration is equal to
1. The net force on an object divided by its mass
2. The mass of an object divided by its net force
3. The net force of an object divided by its speed
4. the speed of an object divided by its net force
QUICKKKK!!!!!!!!!
Answers
HELP!!! I HAVE NO IDEA!!!!!!!!!!!!!
1. A rocket has a mass of 0.8 kg and an engine that provides 100 N of force. A second rocket is being designed to use the same engine but accelerate at half the rate of the first rocket. What is the mass of the second rocket?
a. 0.4 kg
b. 1.6 kg
c. 2.4 kg
d. 0.8 kg
2. Which of the following would be a situation with unbalanced forces?
a. Two people pulling on the same side of a wheelbarrow
b. A team of players in tug of war pulling on the rope, each team with equal numbers of people pulling with equal strength
c. Two people of opposite sides of a big tire. One pushes the tire and one pulls it with equal force
d. Two people not touching a crate that is sitting stationary.
3. Why is it generally easier to push a heavy object that is already moving instead of the same heavy object that is stationary
a. The force of gravity on the object is different if it is stationary or not.
b. The force of friction on the object is different if it is stationary or not
c. The force of the push on the object is different if it is stationary or not
d. The normal force on the object is different if it is stationary or not.
Thanks In Advance!! (I will mark brainliest) :)
Answers
Answer:
Explanation:
The engine should create the same force
1) F = ma
F = M(½a)
therefore
ma = ½Ma
m = ½M
M = 2m
M = 2(0.8)
M = 1.6 kg
2) Unbalanced forces
a. Two people pulling on the same side of a wheelbarrow
c. Two people of opposite sides of a big tire. One pushes the tire and one pulls it with equal force
3) b. The force of friction on the object is different if it is stationary or not
Which type of force enables all the matter made up of atoms to exist?
A. Electromagnetic
B. Normal
C. Strong nuclear
D. Gravitational
Answers
Answer:
D
Explanation:
Answer:
The answer is C. Strong Nuclear
Explanation:
I took this test and it was correct!
HONI A ball is rolling steady on the floor. (a) Draw and label all the forces acting on the ball. (b) Describe the relationships between all the forces acting on the ball
Answers
a) The image is attached to this answer
b) The kinetic friction force affects the forward force of the ball.
What is the relationship between the forces that act on a rolling ball?
The force that opposes a rolling ball's motion is called rolling friction. It slows the ball down by acting in the opposite direction to that of the ball's motion. The weight of the ball and the type of the surface are two variables that affect rolling friction.
The force that a surface uses to maintain the weight of an object that is resting on it is known as the normal force. When a ball is rolling, the normal force exerts itself perpendicular to the surface the ball is moving on. It maintains the ball's weight balance and offers the required reaction force for rolling motion.
Learn more about rolling ball:https://brainly.com/question/29409976
#SPJ1
A 9.700-g bullet is fired into a stationary block of wood having mass m = 4.970 kg. The bullet imbeds into the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.6010 m/s. What was the original speed of the bullet?
Answers
0.3 m/s was the original speed of the bullet.
m1v1=m2(v1+v2)
v1=m2(v1+v2)/m1
v1=4.9×0.6÷9.7
v1=0.3 m/s
Speed is a scalar variable that expresses how much an object's location changes over time or how much it changes per unit of time. It is frequently abbreviated as "s." The distance traveled by an object over a period of time divided by the length of the period gives the average speed of the object over that period.
The speed-related metrics are time divided by distance. The most prevalent unit of speed in daily life is the kilometer per hour (kph), while the SI unit of speed is the meter per second (m/s).
To know more about speed visit : brainly.com/question/93357
#SPJ9
2. A 70.0-kg man and a 55.0-kg woman holding a 2.50-kg purse on ice skates stand facing eac other. (a) If the woman pushes the man backwards so that his final speed is 1.50 m/s, with what average force did she push him, assuming they were in contact for 0.500 s? (b) What i the woman's recoil speed? (c) If she now throws her 2.50-kg purse at him at a 20.0° angle ac
Answers
a) The average force with which the woman pushed the man is 210 N.
b. the woman's recoil speed is still 3.68 m/s
c. If she now throws her 2.50-kg purse at him at a 20.0° angle, the speed is 0.
How do we calculate?We first calculate the Momentum = (70.0 kg)(-1.50 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s)
0 = (70.0 kg)(0 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s) - (70.0 kg)(-1.50 m/s)
v = 3.68 m/s
Δp = (70.0 kg)(1.50 m/s) - (70.0 kg)(0 m/s) = 105 kg·m/s
The average force exerted on the man by the woman is:
Average force = Δp / Δt
Average force = 105 kg·m/s / 0.500 s
Average force = 210 N
b) The woman's recoil speed is :
0 = (70.0 kg)(-1.50 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s)
v = 3.68 m/s
c) If the woman throws her 2.50-kg purse at the man at a 20.0° angle, we apply the conservation of momentum equation in two dimensions and get the speed as 0.
Learn more about recoil speed at:
https://brainly.com/question/26714844
#SPJ1
the answer for this pls
Answers
The solubility of a substance in a solvent is affected by many factors, including temperature. In general, increasing the temperature of a solvent increases the solubility of a solute in that solvent. This relationship is known as the temperature-solubility relationship.
How to explain the relationshipThere are a few different ways in which temperature can affect solubility, depending on the specific solute and solvent in question. For example:
For most solid solutes in liquid solvents, increasing the temperature of the solvent will increase the solubility of the solute. This is because increasing the temperature generally increases the kinetic energy of the solvent molecules, which in turn makes it easier for them to break apart the intermolecular forces holding the solute together and form new solute-solvent interactions.
In some cases, however, the opposite may be true: the solubility of a solute in a solvent may decrease with increasing temperature. This is often observed for gases dissolved in liquids, where increasing the temperature decreases the solubility of the gas. This is because increasing the temperature of the liquid also increases the kinetic energy of the gas molecules, making them more likely to escape from the liquid and form a gas phase.
In rare cases, the temperature-solubility relationship may be more complex and exhibit unusual behavior. For example, for some solutes, the solubility may initially increase with temperature but then decrease at higher temperatures.
Overall, the relationship between temperature and solubility is an important consideration in many chemical processes, including crystallization, precipitation, and dissolution. Understanding this relationship can help scientists and engineers optimize their processes and achieve their desired outcomes.
Learn more about temperature on
https://brainly.com/question/25677592
#SPJ1
A pottery wheel with rotational inertia 40 kgm^2 rotates at 10 rev/s. 4 kg of clay is dropped onto the wheel 1.2 m from the axis. What angular speed will the wheel have after this?1. 55 rad/s2. 8.7 rad/s3. 70 rad/s4. 0 rad/s
Answers
Given:
• Rotational inertia = 40 kg.m²
,• Initial angula speed = 10 rev/s
,• Mass, m = 4 kg
,• Diameter, d = 1.2 m
Let's find the angular speed of the wheel.
To find the angular speed, apply the formula:
\(L_i=(I+md^2)*w_f\)Where wf is the final angular speed
I is the rotational inertia
m is the mass
d = 1.2
Li is the angular momentum.
To find the angular momentum, we have:
\(\begin{gathered} L_i=40*10*2\pi \\ L_i=2513.27\text{ kg.m}^2\text{ rad/s} \end{gathered}\)Now, to find the final angular speed, wf, plug in values in the first equation and solve for wf:
\(\begin{gathered} Li=(I+md^2)w_f \\ \\ 2513.27=(40+4*1.2^2)w_f \\ \\ 2513.27=45.76w_f \\ \\ w_f=\frac{2513.27}{45.76} \\ \\ w_f=54.9\approx55\text{ rad/s} \end{gathered}\)Therefore, the final angular speed is 55 rad/s.
ANSWER:
1.) 55 rad/s
A labourer who supports a load on his back walks along a horizontal straight path.Is there any work done if the speed of the labourer is uniform ?A. Work is done.B. There is no work done.C. Both of these
Answers
The work done in terms of the force and displacement is,
\(W=F\times d\)where F is the force and d is the displacement,
The labourer is moving along the horizontal path with the constant speed, thus, no force must be acting on the labourer along the horizontal direction.
The work done in the horizontal direction is zero.
As there is a gravitational force acting on the load supported by the labourer but the load remains in its same position. Thus, no displacement of the load takes place.
The work done on the load is also zero (in the vertical direction).
Hence, option B is the correct answer (no work is done in the given case).
A car of mass m going around a curve of radius r at constant speed v experiences a net force F. What is the net force on a truck of mass 5m traveling around a curve of radius 5r with constant speed 5v?
Answers
a Given that the mass of the truck is 5m, moves along a curve having radius of, 5r and the speed of the truck is 5v.
The formula of the net force is
\(F=\frac{mv^2}{r}\)Here, m is the mass, v is the speed and r is the radius.
Substituting the values of a truck in the net force formula, we get
\(\begin{gathered} F=\frac{5m\times(5v)^2}{5r} \\ =\frac{25mv^2}{r} \end{gathered}\)
A 0.300 kg mass is attached toa 26.6 N/m spring. It is pulled0.120 m and released. How much Potential Energy does it have when it is 0.0600 m from equilibrium?(Unit = J)
Answers
0.144 Joules
Explanationelastic potential energy is given by
\(\begin{gathered} PE=\frac{1}{2}kx^2 \\ where\text{ K is the spring constatn} \\ x\text{ is the amount of compresion \lparen}relative\text{ to equilibrium\rparen} \end{gathered}\)so
Step 1
Diagram:
given
\(\begin{gathered} m=0.3\text{ kg} \\ k=26.6\frac{N}{m} \\ x=0.120\text{ m} \end{gathered}\)Step 1
a) energy when the spting is compressed
Total elastic energy of the spring = Kinetic energy of the spring + potential energy of the spring
so
\(\begin{gathered} E=\frac{1}{2}kx^2=\frac{1}{2}(26.6\text{ N/m\rparen\lparen0.12}^2)=0.19152\text{ J} \\ EP=\frac{1}{2}kx^2=\frac{1}{2}(26.6)(0.6^2)=0.04788 \\ hence \\ Ek=0.19152\text{ J-0.04788} \\ Ek=0.144\text{ Joules} \end{gathered}\)the kinetic energy is given by
Answer: 0.0479
Explanation: This answer works for Acellus! :D
hope this helped!
A person drops a marble from the top of a skyscraper. After falling four floors the marble has gained a certain speed. How many more floors will the marble have to fall to triple this speed?
a. 8
b. 12
c. 32
d. 48
Answers
Answer:
B. 12
Explanation:
4 x 3 = 12
A long piece of wire with a mass of 0.100 kg and a total length of 4.00 m is used to make a square coil with a side of 0.100 m. The coil is hing along a horizontal side, carries a 3.80 A current, and is placed in a vertical magnetic field with a magnitude of 0.010 0 T.
a, Determine the angle that the plane of the coil makes with the vertical when the coil is in equilibrium. b Find the torque acting on the coil due to the magnetic force at equilibrium.
Answers
The torque is equal to zero since the coil is in equilibrium. As a result, will also equal zero, indicating that the coil's plane is parallel to the vertical direction at equilibrium.
Calculation-The current-carrying coil in a magnetic field is given by:
τ = μ * B * I * A * sin(θ)
where:
τ = torque (in Nm)
μ = magnetic moment of the coil (in Am^2)
B = magnetic field strength (in T)
I = current flowing through the coil (in A)
A = area of the coil (in m^2)
θ = angle between the plane of the coil and the magnetic field (in radians)
μ = N * A * I
N = number of turns of the coil
A = area of the coil (in m^2)
I = current flowing through the coil (in A)
the equations to calculate the angle θ:
m = 0.100 kg (mass of the wire)
L = 4.00 m (total length of the wire)
side length = 0.100 m
I = 3.80 A (current flowing through the coil)
B = 0.0100 T (magnetic field strength)
Calculations:
A = side length^2 * N = 0.100^2 * 1 = 0.0100 m^2
μ = N * A * I = 1 * 0.0100 * 3.80 = 0.0380 Am^2
Now we can rearrange the equation for torque to solve for θ:
θ = arcsin(τ / (μ * B * I * A))
to know more about wire here;
brainly.com/question/12984460
#SPJ1
A motorcycle travels 90.0 km/h. How many seconds will it take the motorcycle to cover 2100 km
Answers
1 hour = 3600 seconds
Find the number of hours it takes by dividing total distance by speed:
2100 km / 90 km/h = 23 1/3 hours
Multiply total hours by 3600:
231/3 x 3600 = 84,000 seconds
It will take the motorcycle 84 seconds to cover 2100 km at a speed of 90.0 km/h. The correct answer is 84 seconds.
Given:
Speed = 90.0 km/h
Distance = 2100 km
The time it takes for the motorcycle to cover 2100 km at a speed of 90.0 km/h, you can use the formula:
Time = Distance / Speed
Convert the speed to meters per second
1 km = 1000 m
1 hour = 3600 seconds
The speed in meters per second:
Speed = 90.0× (100 / 1 ) × (1 / 3600 )
Speed = 25 m/s
The formula to calculate the time:
Time = Distance / Speed
Time = 2100 / 25
Time = 84 seconds
It will take the motorcycle 84 seconds to cover 2100 km at a speed of 90.0 km/h.
To know more about the distance and time:
https://brainly.com/question/31756299
#SPJ3
A vehicle, starting from rest, accelerates on a circular track with a 335m diameter.
Answers
The distance travelled by the vehicle around the circular track is 1,052.4 m.
What is the distance travelled by the vehicle in one complete cycle?
The distance travelled by the vehicle in one complete cycle is calculated by using the following equation as show below.
d = 2πr
d = πd
Where;
r is the radius of the circular trackd is the diameter of the circular trackIn one complete cycle, the vehicle will travel the circular track only once.
d = π(335 m)
d = 1,052.4 m
Thus, the distance travelled by the vehicle around the circular track is a function of the diameter of the circular track.
Learn more about distance round a circle here: https://brainly.com/question/3100527
#SPJ1
The complete question is below:
A vehicle, starting from rest, accelerates on a circular track with a 335m diameter. What is the distance travelled by the vehicle when it makes one complete cycle?
At what horizontal velocity would a satellite have to be launched from the top of Mt. Everest to be placed in a circular orbit around the Earth.
Given formula:
GM/R = v^2
G= 6.67 x 10^-11 N.m^2/kg^2
M= 5.98 x 10^24kg
R= 6.38 x 10^3 km
Answers
An orbital projectile should be launched with such a horizontal speed exceeding 8000 m/s. Determine the speed of the a satellite inside an orbit 1000 km, M is 5.98x1024 kg, and R is 6.4x10m. [Ans x 10 = 7.34 m/s].
How far is the top of Mount Everest from outer space?At 328,084 feet, the barrier between earth and space is the highest point you have probably ever gone and is around 11 times greater than Mount Everest. Consider that for a second. If looking at this image doesn't inspire awe in you, perhaps contemplating it in a different way would.
What speed is necessary to send a satellite up at the very least?A: At low earth orbit, an object must travel at a speed of roughly 28,000 km/h (17,500 mph) in order to orbit the Earth. At this speed, the object would be able to leave Earth's atmosphere and keep a steady orbit around it at a height of about 325 km (200 km).
To know more about horizontal visit:
https://brainly.com/question/30004581
#SPJ1
Which of the following graph will give a straight line graph that will not pass through the origins
Answers
Answer:
A line only passes through the origin if it is of the form y = mx where m is your slope. In any other case, the line may not pass through the origin
Explanation:
Equation of path of projectile is y=x(1-x)
Answers
The equation of the path of a projectile is y = x(1 - x). Projectile motion is the movement of an object in a parabolic trajectory as a result of being propelled or released under the influence of gravity. A projectile, in simple terms, is any object that is launched into the air, such as a bullet, a baseball, or a rock. It's important to note that the parabolic trajectory is due to the force of gravity acting on the object.
To better understand projectile motion, we must first examine the horizontal and vertical components of motion. The horizontal component of motion is constant, indicating that there is no acceleration in that direction. The vertical component, on the other hand, has acceleration because of gravity. The parabolic trajectory is the result of these two components of motion.As the projectile is launched, it travels a certain distance horizontally before beginning to descend as a result of gravity's influence, resulting in a parabolic path.The general formula for the trajectory of a projectile in two dimensions is given by:y = xtanθ - (gx²) / 2(v₀cosθ)²Where:y is the vertical distance covered by the projectilex is the horizontal distance covered by the projectileθ is the angle of projectiong is the acceleration due to gravityv₀ is the initial velocity of the projectile In the case of the given equation, y = x(1 - x), the path of the projectile will be a parabolic trajectory with a vertex at x = 0.5 and y = 0.25. The equation represents the projectile's vertical distance, y, as a function of its horizontal distance, x. It is crucial to note that the projectile's initial velocity and angle of projection are not considered in this equation.For such more question on acceleration
https://brainly.com/question/460763
#SPJ8
A racket causes a tennis ball to rebound at a speed of 25 m/s The tennis ball is 0.4 kg and is initially moving at a speed of 12 m/s. A high-speed movie film determines that the racket and ball are in contact for 0.05 s. What is the average net force exerted on the ball by the racket
Answers
Hi there!
We know that:
I = Δp = mΔv = m(vf - vi)
Let the positive direction be towards the wall. Plug in the given values:
Δp = 0.4(-25 - 12) = -14.8 Ns
Δp = Ft, so:
Δp/t = F
-14.8/0.05 = -296 N (depending on which direction you assign positive/negative, the answer would be positive/negative)
Describe what is required for work to be considered done by a physicist. Give an example in two or more complete sentences.
Answers
For work to be considered done by a physicist, it must involve the application of physics principles and concepts to solve a problem or answer a research question. This can involve theoretical work, such as mathematical modeling, or experimental work, such as designing and conducting experiments to test hypotheses.
An example of work done by a physicist would be the design and analysis of experiments to study the properties of a new material. This could involve developing a theoretical model to predict the behavior of the material, designing and building experimental apparatus, conducting experiments, and analyzing the resulting data using statistical and mathematical techniques. The physicist would use their knowledge of physics principles and concepts to interpret the data and draw conclusions about the properties of the material.