(50 points) please answer by the end of today sat,oct,31
given the function find the x-intercepts) and the y-intercept if they exist and then use then to graph the function
1.) f(x)=5(x-4)-10
-x intercept
-y intercept
2.)g(x)=5(2^x-1)
-x intercept
-y intercept
h(x)= -2(x+3)
-x intercept
-y intercept
k(x)=2x-8
-x intercept
-y intercept
The x-intercepts and y-intercepts for each function are as follows:
1. f(x) = 5(x - 4) - 10
X-intercept: (6, 0)
Y-intercept: (0, -30)
2. g(x) = 5(2ˣ - 1)
X-intercept: (0, 0)
Y-intercept: (0, 0)
3. h(x) = -2(x + 3)
X-intercept: (-3, 0)
Y-intercept: (0, -6)
4. k(x) = 2x - 8
X-intercept: (4, 0)
Y-intercept: (0, -8)
To find the x-intercept of a function, set the function equal to zero (f(x) = 0) and solve for x. To find the y-intercept, set x = 0 and evaluate the function (f(0)).
Let's find the x-intercepts and y-intercepts for each function:
1. f(x) = 5(x - 4) - 10
X-intercept:
To find the x-intercept, set f(x) = 0 and solve for x:
0 = 5(x - 4) - 10
0 = 5x - 20 - 10
0 = 5x - 30
5x = 30
x = 6
So, the x-intercept is (6, 0).
Y-intercept:
To find the y-intercept, set x = 0 and evaluate f(0):
f(0) = 5(0 - 4) - 10
f(0) = 5(-4) - 10
f(0) = -20 - 10
f(0) = -30
So, the y-intercept is (0, -30).
2. g(x) = 5(2ˣ - 1)
X-intercept:
To find the x-intercept, set g(x) = 0 and solve for x:
0 = 5(2ˣ - 1)
5(2ˣ - 1) = 0
2ˣ - 1 = 0
2ˣ = 1
The x-intercept occurs when 2ˣ equals 1.
The solution is x = 0 because 2⁰ = 1.
So, the x-intercept is (0, 0).
Y-intercept:
To find the y-intercept, set x = 0 and evaluate g(0):
g(0) = 5(2⁰ - 1)
g(0) = 5(1 - 1)
g(0) = 5(0)
g(0) = 0
So, the y-intercept is (0, 0).
3. h(x) = -2(x + 3)
X-intercept:
To find the x-intercept, set h(x) = 0 and solve for x:
0 = -2(x + 3)
0 = -2x - 6
2x = -6
x = -3
So, the x-intercept is (-3, 0).
Y-intercept:
To find the y-intercept, set x = 0 and evaluate h(0):
h(0) = -2(0 + 3)
h(0) = -2(3)
h(0) = -6
So, the y-intercept is (0, -6).
4. k(x) = 2x - 8
X-intercept:
To find the x-intercept, set k(x) = 0 and solve for x:
0 = 2x - 8
2x = 8
x = 4
So, the x-intercept is (4, 0).
Y-intercept:
To find the y-intercept, set x = 0 and evaluate k(0):
k(0) = 2(0) - 8
k(0) = 0 - 8
k(0) = -8
So, the y-intercept is (0, -8).
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i really need to know this or imma fail!!!!!!!
The answer to the simplified expression 4⁹/4³ in index form is derived to be equal to 4⁶
How to simplify fraction of numbers in index formTo simplify a fraction written in index form, you can first express the numbers in prime factorization form by writing both the numerator and denominator as a product of prime factors. Identify common prime factors in the numerator and denominator and cancel them out. Then write the remaining factors as a product in index form.
Given the fraction 4⁹/4³, we can simplify as follows:
4⁹/4³ = (4 × 4 × 4 × 4 × 4 × 4 × 4 × 4 × 4)/(4 × 4 × 4)
we can cancel out (4 × 4 × 4) from both the numerator and denominator, living us with;
4⁹/4³ = 4 × 4 × 4 × 4 × 4 × 4
4⁹/4³ = 4⁶
Therefore, the answer to the simplified expression 4⁹/4³ in index form is derived to be equal to 4⁶
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300 mountain bike is discounted by 30% and then discounted an additional 10% for shoppers Who arrive before 5 AM find the sales price of the bike what was the total savings
Answer:
hodiwkwoleñelflelflgkkg
Which inequality is true? a. A number line going from negative 3 to positive 3 in increments of 1. b. Start Fraction 5 Over 6 End Fraction less-than negative one-third c. 2 and one-third greater-than 2 and one-sixth 2 less-than negative 2 and one-half d. 1 and one-fourth greater-than 1 and one-third
As per the concept of inequality, All the given options are true and the answer is 3 to +3 in increments of 1 5/6 to -1/3 21/3 >21/6.
Inequality:
In math, Inequality means a unequal or biased outcomes and is an unjust distribution of resources and opportunities. And it leads to an increased resolution of the opportunities and resources.
Given,
Here we have the list of options and we need to find in which inequality is true.
Here we know that, the inequality makes the comparisons between no. or the expressions in the terms of greater or less depending on how numbers are arranged on the number line.
When a number line that is going from the negative 3 to positive 3 and is in increasing order.
Here the second one shows the positive value of 5/6 towards decreasing and a negative value of the -1/3 hence is also correct
Finally, the third one depicts the 2 and one-third greater than 2 and one half.
Therefore, the option 1, 2, and 3 are true.
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Suppose "n" can't equal 0 or 1. Show that substitution v=y^(1-n) transforms the Bernoulli equation dy/dx + P(x)y=Q(x)y^(n)into the linear equation dv/dx + (1-n)P(x)v(x)=(1-n)Q(x).
Answer:v = y(1-n)dv/dx = (1-n)y-n dy/dxso dy
Step-by-step explanation:
What are even and odd numbers from 1 to 100?
In mathematics, a number is considered to be "even" if it is divisible by 2, and "odd" if it is not divisible by 2. The numbers from 1 to 100 can be divided into two groups: even numbers and odd numbers.
Even numbers are numbers that are divisible by 2, such as 2, 4, 6, 8, and so on. When you divide an even number by 2, the remainder will always be 0. Some examples of even numbers between 1 and 100 include: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, and 100.
Odd numbers are numbers that are not divisible by 2, such as 1, 3, 5, 7, and so on. When you divide an odd number by 2, the remainder will always be 1. Some examples of odd numbers between 1 and 100 include: 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49, 51, 53, 55, 57, 59, 61, 63, 65, 67, 69, 71, 73, 75, 77, 79, 81, 83, 85, 87, 89, 91, 93, 95, 97, and 99.
It is important to note that 0 is not a positive or negative number and it is not considered as odd or even.
Knowing the difference between even and odd numbers is an important concept in math, especially when working with patterns, sequences, and operations. Understanding even and odd numbers can help you better understand the properties of numbers and how they can be used in different contexts.
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Whic if the following functions is graphed
The piecewise function graphed in this problem is defined as follows:
y = x + 6, x ≤ 1.y = x² + 3, x > 1.What is a piece-wise function?A piece-wise function is a function that has different definitions, depending on the input of the function.
The definitions for this problem are given as follows:
Up to x = 1.Greater than x = 1.For the function up to x = 1, the function is a linear function with slope of 1 and intercept of 6, hence:
y = x + 6, x ≤ 1.
For the function greater than x = 1, the quadratic function y = x² + 3 is defined, hence:
y = x² + 3, x > 1.
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3-6x (34 divided by3º)2
Answer:
3^-6(81)^2=3^-6(6561)=9 which is 3^2
To prove that 2 functions are of each other, one must show that f(g(x)) = x and g(f(x)) = x
To prove that two functions are inverses of each other, it is necessary to show that both of the conditions f(g(x)) = x and g(f(x)) = x hold, but this does not necessarily mean that the two functions are equal.
We have,
This statement is not entirely correct.
To prove that two functions are inverses of each other, it is indeed necessary to show that both of the following conditions hold:
f(g(x)) = x for all x in the domain of g
g(f(x)) = x for all x in the domain of f
Now,
This does not necessarily mean that the two functions are equal to each other.
For example,
Consider the functions f(x) = x + 1 and g(x) = x - 1.
It can be shown that f(g(x)) = x and g(f(x)) = x for all values of x, which satisfies the conditions for being inverses of each other.
However, it is clear that f(x) and g(x) are not the same functions.
Thus,
To prove that two functions are inverses of each other, it is necessary to show that both of the conditions f(g(x)) = x and g(f(x)) = x hold, but this does not necessarily mean that the two functions are equal.
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Perimeter:
Area:
3.9 & 1.3
Answer:
1&0
Step-by-step explanation:
Enter a value for side 1 in metres with optional centimetres.
Enter a value for side 2 in metres with optional centimetres.
Click associated Get Results button.
Square metres (m2) and centimetres (cm2) remainder is shown.
Multiple calculations can be placed in the textbox below by pressing Move Results.
Multiple calculations total area is shown in the Grand Total Square Metres text box.
A rate that is charged for using money is called
non-interest
interest
interest rate
term
Answer:
term
Step-by-step explanation:
class limit
bin
Frequency
0-18
18
0
19-37
37
53
38-56
56
272
57-75
75
151
76-94
94
258
95-113
113
331
114-132
132
343
133-151
151
191
152-170
170
319
171-189
189
334
190-208
208
181
209-227
227
138
228-246
246
165
247-265
265
148
266-284
284
4
Explain the distribution of the Item_MRP using the shape of the distribution and the values of measures of location.
The frequency distribution table shows that the data are divided into 9 classes with each class having a class width of 19. Each class has a lower class limit and an upper class limit.
The midpoint of each class can be calculated using the formula; Midpoint = (Lower class limit + Upper class limit) / 2. The frequency column of the table shows how many products fall into each class.
For this distribution, the mean MRP is calculated as:
Mean MRP = (0 × 18 + 18 × 53 + 56 × 272 + 75 × 151 + 94 × 258 + 113 × 331 + 132 × 343 + 151 × 191 + 170 × 319 + 189 × 334 + 208 × 181 + 227 × 138 + 246 × 165 + 265 × 148 + 284 × 4) / 3333 = 141.7
The median MRP is calculated as:
Median MRP = L + [(N/2 - F) / f] × w
Where L = Lower class limit of the class containing the median value,
N = Total number of products,
F = Cumulative frequency up to the class containing the median value,
f = Frequency of the class containing the median value,
w = Class width
L = 133, N = 3333, F = 857, f = 191, w = 19
Median MRP = 133 + [(1667 - 857) / 191] × 19 = 146.6
The mode MRP is the value that appears most frequently in the data. For this distribution, the mode MRP falls in the class 114-132 since this is the class with the highest frequency. The mode MRP is 132.
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which expression is equivalent to f(x)=3x+2
one way to display formulas is by pressing this key combination. [CTRL][ ]
To display formulas, one way is to press the key combination [Ctrl]+[] (grave accent).
What key combination can be used to display formulas?The key combination [Ctrl]+[] is used to display formulas.
This is a useful feature for checking and editing formulas without altering the calculated values.
By pressing [Ctrl]+[], users can easily view the underlying formulas and ensure their accuracy.
This key combination provides a convenient way to switch between the formula view and the results view, enabling efficient editing and troubleshooting of complex calculations.
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if+the+correlation+between+two+variables+is+.496,+how+much+of+the+variance+has+not+been+accounted+for?++a.+24.6%++b.+49.6%++c.+50.4%++d.+75.4%
The remaining 50.4% of the variance has not been accounted for, and it could be due to other factors that are not captured by the two variables being studied.
If the correlation between two variables is .496, it means that 49.6% of the variance has been accounted for. This is because the correlation coefficient measures the strength and direction of the linear relationship between the two variables, and it ranges from -1 to 1.
A correlation of 1 indicates a perfect positive linear relationship, while a correlation of -1 indicates a perfect negative linear relationship. In this case, a correlation of .496 indicates a moderate positive linear relationship.
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my friend consumed 8 donuts in one sitting. 8 donuts is .... (a) a lower bound on how many donuts he is physically capable of eating in one sitting. (b) an upper bound on how many donuts he is physically capable of eating in one sitting. (c) the exact number of donuts that he is physically capable of eating in one sitting. (d) none of the other answers is correct.
My friend consumed 8 donuts in one sitting. 8 donuts is a lower bound on how many donuts he is physically capable of eating in one sitting option A.
An element of K that is bigger than or equal to each member of S is referred to as an upper limit or majorant of a subset S of some preordered set (K, ) in mathematics, notably in order theory. In addition, each element of K that is smaller than or equal to each element of S is characterised as a lower limit or minorant of S.
A set that has an upper (or lower) bound is referred to as being majorized (or minorized), bounded from above, or minorized by that bound. In the mathematical literature, sets that have upper (or lower, respectively) limits are referred to as being bounded above (or below).
Friend consumed 8 doughnuts. So it is
lower bound on how can eat in a sitting.
Many donuts he lower bound is the lowest quantity in a set, as in our.
example, we definitely know he can eat 8 of them. We don't know how many more can be eat (upper bound) or is it exact amount be can eat.
Hence option (a) is correct.
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5 1/4-2 2/3
Solve and show equations
Answer:
5 1/4 - 2 2/3 = 31/12 = 2 7/12 = 2.5833333
Step-by-step explanation:
1. Conversion a mixed number 5 1/4 to a improper fraction: 5 1/4 = 5 1/4 = 5 · 4 + 1/4 = 20 + 1/4 = 21/4
To find new numerator:
a) Multiply the whole number 5 by the denominator 4. Whole number 5 equally 5 * 4/4 = 20/4
b) Add the answer from previous step 20 to the numerator 1. New numerator is 20 + 1 = 21
c) Write a previous answer (new numerator 21) over the denominator 4.
Five and one quarter is twenty-one quarters
Conversion a mixed number 2 2/3 to a improper fraction: 2 2/3 = 2 2/3 = 2 · 3 + 2/3= 6 + 2/3 = 8/3
To find new numerator:
a) Multiply the whole number 2 by the denominator 3. Whole number 2 equally 2 * 3/3 = 6/3
b) Add the answer from previous step 6 to the numerator 2. New numerator is 6 + 2 = 8
c) Write a previous answer (new numerator 8) over the denominator 3.
Two and two thirds is eight thirds
Subtract: 21/4 - 8/3 = 21 · 3/4 · 3 - 8 · 4/3 · 4 = 63/12- 32/12 = 63 - 32/12 = 31/12
For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(4, 3) = 12. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 4 × 3 = 12. In the next intermediate step, the fraction result cannot be further simplified by canceling.
In words - twenty-one quarters minus eight thirds = thirty-one twelfths.
Given the head of a singly linked list and an integer k, split the linked list into k consecutive linked list parts.
The length of each part should be as equal as possible: no two parts should have a size differing by more than one. This may lead to some parts being null.
The parts should be in the order of occurrence in the input list, and parts occurring earlier should always have a size greater than or equal to parts occurring later.
Return an array of the k parts.
To split a singly linked list into k consecutive parts with roughly equal sizes, you can use the following algorithm:
1. Calculate the length of the linked list by iterating through it.
2. Determine the size of each part by dividing the length by k, and the remainder by using the modulus operator (%).
3. Initialize an array of linked list nodes with a size of k to store the head of each part.
4. Iterate through the linked list, and for each part:
a. Assign the current node as the head of the current part in the array.
b. Determine the number of nodes for the current part by adding the base size, and if the current part index is less than the remainder, add 1.
c. Move the current node pointer to the last node of the current part by iterating through the determined number of nodes.
d. Set the next pointer of the last node of the current part to null, and move the current node pointer to the next node in the linked list.
5. Return the array of the k parts.
This algorithm ensures that the linked list is split into k consecutive parts with sizes as equal as possible, and parts occurring earlier have a size greater than or equal to parts occurring later.
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Verify that -1, –3 and -3 are the zeros of the cubic polynomial x³ + 5x² +7x + 3 and check the relationship between zeros and the coefficients
Answer:
They are indeed the zeroes
Step-by-step explanation:
-1 | 1 5 7 3
__-1_-4_-3_
1 4 3 | 0
-3 | 1 5 7 3
__ -3_-6_-3_
1 2 1 | 0
Therefore, x=-1 and x=-3 are the zeroes of the cubic polynomial as the factor (x+1)² has a multiplicity of 2.
Can someone help me with 9a+3a+b-3a for homework?
Answer:
9a+b
Step-by-step explanation:
PLEASE ANSWER ALL BIG REWARD
Dilations involve ________ the scale factor and the pre–image ordered pair(s)? *
adding
dividing
subtracting
multiplying
All dilations produce _______. *
similar figures
vertical figures
congruent figures
supplementary figures
The rule to describe a dilation is written in _________. *
a list
scale factor
arrow notation
slope-intercept form
Which of the rules below would create a reduction/compression? *
(x, y) (–3x, –3y)
(x, y) (3.2x, 3.2y)
(x, y) (x + 9, y + 9)
(x, y) (0.23x, 0.23y)
Which of the following rules below do NOT represent a dilation? *
(x, y) --> (2x, 4y)
(x, y) --> (–8x, –8y)
(x, y) --> (1/2x, 1/2y)
(x, y) --> (3x, 3y)
(x, y) --> (1.2x, 1.2y)
In the diagram below, triangle ABC will be dilated with the origin as the center of dilation by a scale factor of 1/2. What will be the coordinates of A'? *
Captionless Image
(0, 3/2)
(12, 6)
(3, – 3/2)
(–1, –5/2)
A line segment with endpoints D (–6, –5) and E (3, –4) is dilated by a scale factor of 2. Which statement below is true? *
The line segment has become longer with endpoints D' (-12, -10) and E' (6 -8).
The line segment has become shorter with endpoints D' (-12, -10) and E' (6 -8).
The line segment has become longer with endpoints D' (-3, -5/2) and E' (3/2, -2).
The line segment stays the same length with endpoints D' (-3, -5/2) and E' (3/2, -2).
Write a rule to describe the dilation below. *
Captionless Image
(x, y)→ (1/2x, 1/2y)
(x, y)→ (1/3x, 1/3y)
(x, y)→ (3x, 3y)
(x, y)→ (2x, 2y)
If the scale factor k = 1/9 the resulting dilation will be a/an *
enlargement
reduction
If the scale factor k = 3 the resulting dilation will be a/an *
enlargement
reduction
Answer:
multiplying similar figures scale factor (x, y) (–3x, –3y) and (x, y) (0.23x, 0.23y) (x, y) --> (2x, 4y) Need diagramA. The line segment has become longer with endpoints D' (-12, -10) and E' (6 -8).Need imageReductionEnlargementgood luck, i hope this helps :)
f(x) = 5x – 2
slope of f =
Answer:
? we dint know
Step-by-step explanation:
in a math class, tests are 50% of your grade, homework is 30% of your grade, test reviews are 5% of your grade, and the final exam is 15% of your grade. at the end of the semester, your test average is 59, your homework average is 90, and your review average is 72. what score do you need on the final exam to get a c (72%) in the class? (round your answer to 2 decimal places.)
The score needed on the final exam to achieve a C grade is 79.33, rounded to 2 decimal places.
Homework is worth 30% of the grade, which is also a significant portion. The average homework score is 90, which means the average of all homework scores is 90.
Test reviews are only worth 5% of the grade, so they have the smallest impact on the overall average. The average test review score is 72, which means the average of all test review scores is 72.
Finally, the final exam is worth 15% of the grade, and we need to find out what score is needed on the final exam to achieve a C grade, which is 72%.
To calculate the overall average, we can use the weighted average formula.
Overall Average = (Tests Average x 0.5) + (Homework Average x 0.3) + (Test Reviews Average x 0.05) + (Final Exam Score x 0.15)
Substituting the values we know, we get:
Overall Average = (59 x 0.5) + (90 x 0.3) + (72 x 0.05) + (Final Exam Score x 0.15)
Simplifying this equation, we get:
Overall Average = 29.5 + 27 + 3.6 + (Final Exam Score x 0.15)
Overall Average = 60.1 + (Final Exam Score x 0.15)
To get a C grade, the overall average needs to be 72%. So we can set up an equation and solve for the Final Exam Score:
72 = 60.1 + (Final Exam Score x 0.15)
Solving for Final Exam Score, we get:
Final Exam Score = (72 - 60.1) / 0.15
Final Exam Score = 79.33
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(Q2) The set of line segments _____ meet the requirements to form a triangle.8 cm4 cm3 cm
To form a triangle, the set of line segments must satisfy the triangle inequality theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Therefore, we need to check if the given line segments 8 cm, 4 cm, and 3 cm meet this requirement.
We can start by checking if the sum of the two smaller sides (3 cm and 4 cm) is greater than the largest side (8 cm). 3 cm + 4 cm = 7 cm, which is less than 8 cm. Therefore, these three line segments cannot form a triangle.
In general, for a set of line segments to form a triangle, the largest side must be smaller than the sum of the other two sides. In this case, the line segment of 8 cm is too long compared to the other two sides, which makes it impossible to form a triangle.
In conclusion, there are no line segments that meet the requirements to form a triangle with lengths of 8 cm, 4 cm, and 3 cm.
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tina has scheduled a dinner with friends in 4.5 hours. what is the probability that her simulation study will be done by then?
The approximate distribution (give distribution name and parameters) of the total length will be = 450 minutes
The estimated distribution of the total length of Tina's simulation study is a triangular distribution with a base worth of 2 minutes, a greatest worth of 4 minutes, and a mode (most reasonable worth) of (2+4)/2 = 3 minutes.
Since the simulation time is generally consistently distributed somewhere in the range of 2 and 4 minutes, the total simulation time will be the sum of 150 free random variables each with a triangular distribution.
Hence, the total simulation time will also have a triangular distribution with a base worth of 2 minutes x 150 = 300 minutes, a greatest worth of 4 minutes x 150 = 600 minutes, and a method of (300+600)/2 = 450 minutes.
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The complete question is:
Tina is running a simulation study on her laptop. The duration of each simulation is roughly uniformly distributed between 2 and 4 minutes. She needs to run 150 simulations and she runs all her simulations back-to-back. - What is the approximate distribution (give distribution name and parameters) of the total length of Tina's simulation study? Explain your answer
Answer the question above
Answer:
EM
Step-by-step explanation:
Hope this helps :))
not sure how to explain it, sorry
HURRY!!
The sequences are:
Number of moves: 1, 3, 7, 15, 31, 63, ...
2":2, 4, 8, 16, 32, 64, ...
Compare the two sequences. What is the pattern?
How could you find the minimum number of moves
required for a given number of disks?
The minimum number of moves required for a given number of disks.
We have given that,
The sequences are number of moves 1, 3, 7, 15, 31, 63,
2,2, 4, 8, 16, 32, 64,
Compare the two sequences.
Each term in the sequence of moves is 1 less than the corresponding term in the sequence of differences.
What is the sequence?A sequence is an enumerated collection of objects in which repetitions are allowed and order matters. Like a set, it contains members. The number of elements is called the length of the sequence.
You can find any term in the sequence of moves using the formula
\(a_1=2^n-1\)
No one cares about the explanation good luck with your grade Bois.
The minimum number of moves required for a given number of disks.
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Answer:
Each term in the sequence of moves is 1
less than the corresponding term in the
sequence of differences.
You can find any term in the sequence of
moves using the formula
Step-by-step explanation:
If Jasper can walk
1/2
mile in 1/4 hour, how long will it take him to walk 1.5 miles?
45 mins
Step-by-step explanation:
A quarter of an hour is 15 mins. If jasper walks 1/2 a mile in 15 mins then in 1.5 miles is 3 times that. 15x3 is 45.
Find the area of each triangle. Round your answers to the nearest tenth.
The area of each triangle is: 7554.04 m² and 311.26 km².
Here, we have,
from the given figure,
we get,
triangle 1:
a = 104m
b = 226 m
angle Ф= 40 degrees
so, we have,
area = a×b×sinФ/2
= 104×226×sin40/2
= 7554.04 m²
triangle 2:
a = 34 km
b = 39 km
angle Ф= 28 degrees
so, we have,
area = a×b×sinФ/2
= 34×39×sin28/2
= 311.26 km²
Hence, the area of each triangle is: 7554.04 m² and 311.26 km².
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(c) find the 80th percentile of the sample mean. round the answer to at least two decimal places. the 80th percentile of the sample mean is
We can use the z-score associated with the 80th percentile to calculate the upper bound of the interval using the formula: sample mean + 0.84*(σ/√n).
To round the answer to at least two decimal places, we need to know the values of n and σ. Without that information, we can't provide a specific numerical answer.
To find the 80th percentile of the sample mean, we first need to calculate the sample mean and standard deviation. Let's assume we have a sample of size n and we know the population standard deviation σ.
Using the central limit theorem, we know that the sample mean follows a normal distribution with mean μ and standard deviation σ/√n. Since we don't know the population mean μ, we can use the sample mean as an estimate.
Next, we need to find the z-score associated with the 80th percentile. We can use a z-table or a calculator to find that z = 0.84.
Finally, we can use the formula for the confidence interval of the sample mean:
sample mean ± z*(standard deviation/√n)
Plugging in the values, we get:
sample mean ± 0.84*(σ/√n)
Since we're looking for the upper bound of the 80th percentile, we only need to consider the positive value of the interval:
sample mean + 0.84*(σ/√n)
This represents the value that separates the top 20% of sample means from the bottom 80%.
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