Answer:
a). 3a² + 17a - 1
b). 4y (7y-6)
Step-by-step explanation:
in the second question, we find a number that can divide 28 and 24 without a remainder, which is 4
k 0 1 2 3 4 5
P(X ≤ k) 0.24 0.59 0.75 0.90 0.98 1
What is the probability (in decimal form) that X will be at least 3?
Probability distribution of a random variable X. k 0 1 2 3 4 5 P(X ≤ k) 0.24 0.59 0.75 0.90 0.98 1. The probability of X to be at least 3 can be calculated as follows: Since P(X ≤ k) for k = 0, 1, 2, 3, 4 and 5 are given, P(X ≥ 3) = 1 - P(X < 3)P(X < 3) = P(X ≤ 2) = 0.24 + 0.59 + 0.75 = 1.58P(X ≥ 3) = 1 - 1.58= -0.58 (Since probability cannot be negative. It is clear that we cannot have a negative probability.)
Thus, the probability of X to be at least 3 is 0.42. The above probability distribution table displays the probabilities of the random variable X. The column k represents the values of X. The column P(X ≤ k) represents the probabilities of X being less than or equal to k. Now, we are to determine the probability of X being at least 3, i.e., we need to find P(X ≥ 3).
To find this, we can use the complement of the event of X being less than 3. It is clear that, P(X < 3) + P(X = 3) = P(X ≤ 2) + P(X = 3) = 0.24 + 0.59 + 0.75 + P(X = 3) = 1.58 + P(X = 3) = P(X ≤ 3)The above equation follows from the fact that the probability of X taking any value in the range 0 to 3 must be equal to the sum of the probabilities of X taking any value in the range 0 to 2 and the probability of X taking the value 3. Now, P(X ≤ 3) = 0.90. (Referring to the table above)Thus, P(X ≥ 3) = 1 - P(X < 3) = 1 - P(X ≤ 2) = 1 - 0.90 = 0.10. Answer: 0.10.
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Consider the following generic C comparison function and its assembly language representation C code: byte compbyte a,byte b)/a in rdi,b in rsi Assembly code cmpb %rsi,%rdi set_inst %a1 ret Your jobs(fill-in blank):now sh given values of a and b g SET instruction and the A.5 points set CI SF OF %al setg 47 23 B.5 points set h SF OF %a setl 23 47 C.5 points ZA SF OF %al set sete 23 23 D.5 points CF ZF SF OF 00%1 set b setne 23 47
The correct answer is D. setne 23 47. Based on the provided information, I understand that you have a comparison function in C code and its corresponding assembly code. You are asked to fill in the blanks by selecting the appropriate instructions based on the given values of a and b and the status flags SF, OF, ZF, and CF. Let's go through the options:
A. setg 47 23: This option is incorrect because setg is used to set a byte to 1 if the Greater flag (ZF=0 and SF=OF) is set, but the given values of a and b are 47 and 23, respectively, so it does not satisfy the condition for setg to be set.
B. setl 23 47: This option is incorrect because setl is used to set a byte to 1 if the Less flag (SF≠OF) is set, but the given values of a and b are 23 and 47, respectively, so it does not satisfy the condition for setl to be set.
C. sete 23 23: This option is incorrect because sete is used to set a byte to 1 if the Zero flag (ZF=1) is set, but the given values of a and b are 23 and 23, respectively, so it does not satisfy the condition for sete to be set.
D. setne 23 47: This option is correct. setne is used to set a byte to 1 if the Zero flag (ZF=0) is not set, which means the values of a and b are not equal. In this case, the given values of a and b are 23 and 47, respectively, so they are not equal, and setne should be used.
Therefore, the correct answer is D. setne 23 47
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Isaac applied the steps below to find the product of (4.2)(–5.4). Step 1: (4.2)(–5.4) = (–5.4)(4.2) Step 2: = (–5.4)(4) + (–5.4)(0.2) Step 3: = (–21.6) + (–1.08) Step 4: = –22.68 Which step shows where Isaac applied the distributive property?
Answer:
Step 2
Step-by-step explanation:
Distributive Property: \(a(b+c)=ab+ac\)
Isaac's Steps are outlined below:
\(\text{Step 1:} (4.2)(-5.4) = (-5.4)(4.2) \\\\\text{Step 2:} = (-5.4)(4) + (-5.4)(0.2) \\\\\text{Step 3:} = (-21.6) + (-1.08) \\\\\text{Step 4:} = -22.68\)
We observe that in Step 2:
\((-5.4)(4.2)=(-5.4)(4+0.2)=(-5.4)(4) + (-5.4)(0.2)\)
Therefore, Isaac applied the distributive property in Step 2.
Answer:
step 2
Step-by-step explanation:
I took the test
A gymnast is performing a floor routine. In a tumbling run she spins through the air, increasing her angular velocity from 3. 40 to 5. 40 rev/s while rotating through one half of a revolution. How much time does this maneuver take
With given angular speed/velocity, the maneuver takes approximately 0.716 seconds.
What is angular speed ?Angular speed (ω) is a measure of how quickly an object is rotating around an axis or center point, and is given in units of radians per unit time (e.g., radians per second). It is also sometimes referred to as rotational speed.
Angular speed is related to the linear speed (v) of a point on the rotating object and the distance (r) of that point from the axis of rotation by the equation:
ω = v/r
Now,
As angular velocity
ω_avg = Δθ/Δt
where ω_avg is the average angular velocity, Δθ is the change in angle, and Δt is the time taken.
In this case, the gymnast rotates through half a revolution, or 0.5 × 2π radians = π radians. The initial angular velocity is ω1 = 3.40 rev/s, and the final angular velocity is ω2 = 5.40 rev/s.
We can use the formula for average angular velocity to find the time taken:
ω_avg = (ω1 + ω2)/2
ω_avg = (3.40 rev/s + 5.40 rev/s)/2
ω_avg = 4.40 rev/s
Δθ = π radians
Δt = Δθ/ω_avg
Δt = π/4.40 s
Δt ≈ 0.716 s
Therefore,
The maneuver takes approximately 0.716 seconds.
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Jameson can buy 8 bananas for $1.45 what is the cost per banana
Answer:
$11.6
Step-by-step explanation:
1.45 × 8 = $11.6
That's the Answer
Answer:
0.185 cents
Step-by-step explanation:
1.45÷8 =0.185
divide
I
need the details why we choose answer c
109) Use the following random numbers to simulation crop yield for 10 years: 37, 23, 92, 01, 69, 50, 72, 12, 46, 81. What is the estimated crop yield from the simulation? A) 425 B) 442 C) 440 D) 475 A
The estimated crop yield from the simulation is 443 (option b).
To estimate the crop yield from the given random numbers, we need to assign a specific meaning to each random number. Let's assume that each random number represents the crop yield for a particular year.
Given random numbers: 37, 23, 92, 01, 69, 50, 72, 12, 46, 81
To find the estimated crop yield, we sum up all the random numbers:
37 + 23 + 92 + 01 + 69 + 50 + 72 + 12 + 46 + 81 = 443
Therefore, the estimated crop yield from the simulation is 443. The correct option is b.
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6th grade math help me pleaseeee
Answer:
No
Step-by-step explanation:
Because first you have to distribute so you will do
\(3 \times 4 = 12\)
\(3 \times x = 3x\)
Than You will combine 5x and 3x
\(5x + 3x = 8x\)
Last you will get
\(8x - 12\)
I need help solving y! Can someone please help me!!
Answer:
-2
Step-by-step explanation:
if x+y=-4
and x-y=2
the answer is -2
Answer:
x+y=-4---1
x-y=2---2
1-2
2y=-6
y=-3
when y=-3 subs in 1
x+(-3)=-4
x-3=-4
x=-4+3
x=-1
A television station shows commercials for 7 1/2 minutes each hour how many 45 second commercials can it show per hour
the television station can show 10 45-second commercials per hour.
convert hour into minuteTo convert hours into minutes, you simply multiply the number of hours by 60, since there are 60 minutes in an hour.
So, if you want to convert 3 hours into minutes, you would do:
3 hours x 60 minutes/hour = 180 minutes
Therefore, 3 hours is equivalent to 180 minutes.
There are 60 minutes in an hour, and 7 1/2 minutes is equal to 7.5 minutes.
So, the television station shows commercials for 7.5 minutes per hour.
We can convert 45 seconds to minutes by dividing it by 60:
45 seconds ÷ 60 = 0.75 minutes
To find out how many 45-second commercials the television station can show per hour, we can divide the total number of minutes of commercials by the length of each commercial:
7.5 minutes ÷ 0.75 minutes/commercial = 10 commercials
Therefore, the television station can show 10 45-second commercials per hour.
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In 45 minutes, i will give you three likes (a) You would like to measure wind speed with a cup anemometer on a sailboat trip across the Atlantic Ocean. The measure of the rotational speed of the axle of the device has a precision of +/-0.2 rotations/s and was calibrated in a steady wind-tunne flow at 20m/s with 10 rotations/s. Define for the below-given situations,1 to 4,the type of error (random or systematic and explain how to overcome or reduce this error. 1 2 3 4 Bearing of the axle is old Turbulent flow Icing on the cups Strong tumbling of the sailboat You would like to use it for a measure of the in-cabin air flow a quiet environment Discuss why the measurement system is not well posed for this purpose.
When measuring wind speed with a cup anemometer on a sailboat trip across the Atlantic Ocean, there are a few situations that may arise, as shown below:1. When the bearing of the axle is old, the type of error that occurs is systematic error. To reduce or overcome this error, you would need to replace the bearing to avoid it.
2. When there is turbulent flow, the type of error that occurs is random error. To overcome this error, you would have to wait for the wind to stabilize or take an average of many measurements. 3. When there is icing on the cups, the type of error that occurs is also random error.
To overcome this error, you would need to remove the ice or wait for it to melt before continuing the measurement.4. When there is strong tumbling of the sailboat, the type of error that occurs is systematic error. To overcome this error, you would need to find a way to stabilize the boat or take measurements when the boat is less unstable.
It is not well posed to use a cup anemometer to measure in-cabin air flow in a quiet environment because the device is not sensitive enough. The device needs a minimum wind speed to provide accurate readings, and it is not designed to measure low wind speeds. Therefore, it may not be the right tool for the job, and a different instrument may be more appropriate.
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in huffman encoding if all the letters have the same frequency then they have equal code lengths. true or false g
If all the letters have the same frequency then they have may or may not be equal codes.
What is Huffman encoding?
A lossless data compression algorithm is Huffman coding. Input characters are given variable-length codes, the lengths of which are determined by the frequency of the matching characters.
The variable-length codes (bit sequences) assigned to input characters are Prefix Codes, which indicates that no other character will have a code that is the prefix of the code assigned to that character. This is how Huffman Coding ensures that the produced bitstream cannot contain any ambiguities during decoding.
Let's use a counter example to better grasp prefix codes. Assume that the four characters a, b, c, and d have the variable length codes 00, 01, 0 and 1, respectively. Because the code assigned to c is the prefix of the codes assigned to a and b, this coding causes uncertainty. If the bit stream being compressed is 0001, the decompressed output might be "cccd," "ccb," "acd," or "ab."
In huffman coding, if two nodes have the same frequency, they are considered to be identical for compression reasons, therefore you can select either one and gain an equal amount of compression.
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Ingrid wants to buy a $17,000 car in 6years. How much money must she deposit at the end of each quarter in an account paying 5.5% compounded quarterly so that she will have enough to pay for her car?
Ingrid needs to deposit approximately $558.95 at the end of each quarter to have enough money to buy the $17,000 car in 6 years.
To calculate the amount Ingrid needs to deposit at the end of each quarter, we can use the future value of an annuity formula. The future value (FV) of an annuity is given by the formula:
FV = P * ((1 + r/n)(n*t) - 1) / (r/n)
Where:
P is the periodic deposit
r is the annual interest rate (as a decimal)
n is the number of compounding periods per year
t is the number of years
In this case, Ingrid wants to accumulate $17,000 in 6 years, with a quarterly compounding rate of 5.5% (0.055) and 4 compounding periods per year. Plugging these values into the formula:
17,000 = P * ((1 + 0.055/4)²⁴ - 1) / (0.055/4)
By solving this equation, we find that Ingrid needs to deposit approximately $558.95 at the end of each quarter to accumulate enough money to pay for her car.
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What is the angle between the vector 3–√i j3i j and the positive x-axis?
The angle between the vector (3 - √2)i + 3j and the positive x-axis can be determined using trigonometry.
To find the angle between the vector and the positive x-axis, we can use the arctan function. The angle can be calculated by taking the arctan of the y-component divided by the x-component of the vector.
In this case, the vector is given as (3 - √2)i + 3j. The x-component is 3 - √2, and the y-component is 3. Using the arctan function, we can calculate the angle as arctan(3 / (3 - √2)).
By substituting the values into a calculator or using trigonometric identities, we can find the angle. It is important to note that the arctan function returns an angle in radians. If we want the result in degrees, we can convert it by multiplying the result by 180/π.
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there are only blue, yellow and green cubes in a bag. there are three times as many blue cubes than yellow cubes and five times as many green cubes then blue cubes. what is the chance that Sarah will get the yellow cube in its simplest form.
Answer: 1/11
Step-by-step explanation:
Let x be no. of yellow cubes.
Blue = 2x
Green = 4 x 2x = 8x
Total cubes = x + 2x + 8x = 11x
P(yellow) = x / 11x = 1/11
in fact, % of patients rejecting the kidney and % not rejecting the kidney receive incorrect test results. physicians know that in about % of kidney transplants, the body tries to reject the organ. if the new test has a positive result (indicating early warning of rejection), what is the probability that the body is attempting to reject the kidney?
Using conditional probability, it is found that there is a 0.7921 = 79.21% probability that the body is attempting to reject the kidney.
Conditional Probability:
P(A|B)=P(A∩B)/P(A)
where:
P(B|A) is the probability of event B happening, given that A happened.
P(A∩B) is the probability of both A and B happening
P(A) is the probability of A happening.
Event A: Positive test.
Event B: Body attempting to reject the kidney.
The percentages associated with a positive test are:
80% of 30%(experience kidney rejection).
9% of 70%(do not experience kidney rejection).
Hence:
P(A)=0.8*0.3+0.09+0.7
P(A)=0.303
The probability of both a positive test and the body attempting to reject the kidney is:
P(A∩B)=0.8*0.3=0.24
Hence, the conditional probability is:
P(B|A)=0.24/0.303
P(B|A)=0.7921.
0.7921 = 79.21% probability that the body is attempting to reject the kidney.
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Identify ALL solutions to the inequality. There could be more than one selection.
Answer:
Step-by-step explanation:
-3 or 0
Answer:
-3 and 0
Step-by-step explanation:
the inequality states that 11 is greater than x. That means anything less than 11 can be x
-3 is less than 11 so that can be x
0 is less than 11 so that can be it.
11 is 11 and x is not equal to 11, so that’s not the answer
16 is greater than 11 so it can’t be x
a lot of 50 electrical components numbered 1 to 50 is drawn at random, one by one, and is divided among five customers. (a) suppose that it is known that components 3, 18, 12, 26, and 46 are defective. what is the probability that each customer will receive one defective component? (b) what is the probability that one customer will have drawn five defective components? (c) what is the probability that two customers will receive two defective components each, two none, and the other one?
The probability of getting one defective component per customer is very low, less than 1/14,254. The probability of getting five defective components to a single customer is also low, 1/14,254. And the probability of getting two defective components to two different customers and the rest of the customers getting none is 10/14,254.
(a) The probability that each customer will receive one defective component is the probability that the five defective components will be drawn in a specific order, divided by the total number of ways the 50 components can be drawn. There are 5049484746 ways that the 50 components can be drawn, and 5! (5 factorial) ways that the defective components can be drawn in a specific order. So the probability is (5!)/(5049484746) = 1/14,254.
(b) The probability that one customer will have drawn five defective components is the probability that all five defective components will be drawn in a row, divided by the total number of ways the 50 components can be drawn. There are 5049484746 ways that the 50 components can be drawn, and 5! (5 factorial) ways that the defective components can be drawn in a row. So the probability is (1!)/(5049484746) = 1/14,254,
(c) The probability that two customers will receive two defective components each, two none, and the other one, is the probability that the five defective components will be drawn in a specific order and then divided among the five customers in a specific way, divided by the total number of ways the 50 components can be drawn. The number of ways to divide the defective components among the customers is 5!/(2!2!1!) = 10. There are 5049484746 ways that the 50 components can be drawn, and 5! (5 factorial) ways that the defective components can be drawn in a specific order, so the probability is (105!)/(50494847*46) = 10/14,254.
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Suppose y varies inversely with x, and y = 49 when x = 17
. What is the value of x when y = 7 ?
Answer:
119 is the value of x when y = 7
Step-by-step explanation:
Since y varies inversely with x, we can use the following equation to model this:
y = k/x, where
k is the constant of proportionality.Step 1: Find k by plugging in values:
Before we can find the value of x when y = k, we'll first need to find k, the constant of proportionality. We can find k by plugging in 49 for y and 17 for x:
Plugging in the values in the inverse variation equation gives us:
49 = k/17
Solve for k by multiplying both sides by 17:
(49 = k / 17) * 17
833 = k
Thus, the constant of proportionality (k) is 833.
Step 2: Find x when y = k by plugging in 7 for y and 833 for k in the inverse variation equation:
Plugging in the values in the inverse variation gives us:
7 = 833/x
Multiplying both sides by x gives us:
(7 = 833/x) * x
7x = 833
Dividing both sides by 7 gives us:
(7x = 833) / 7
x = 119
Thus, 119 is the value of x when y = 7.
which of the following factors is a factor of 3x^3+18x^2+27x
The factor of the given expression is (C) (x + 3).
What are the factors?In mathematics, a divisor of an integer n, often termed a factor of n, is an integer m that may be multiplied by some number to generate n.
In this scenario, one also asserts that n is a multiple of m.
A factor is a number that is multiplied by another number to produce the desired result.
A product is a solution to a multiplication problem.
Think of a multiplication problem as components being combined to find a product.
So, we have:
3x^3+18x^2+27x
Now, take the factors out as follows:
3x^3+18x^2+27x
3x(x²+6x+9)
3x(x+3)²
Factors: (x + 3)
Therefore, the factor of the given expression is (C) (x + 3).
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Complete question;
Which of the following is a factor of 3x3 + 18x2 + 27x?
a. 9x
b. x3
c. x + 3
d. x - 3
A shoe box is shown.
The shoe box has a volume of 525 cubic inches. The base of the box has an area of 105 square inches.
What is the height of the box, in inches?
Answer:
5 inches
Step-by-step explanation:
volume is base*height. just calculate 525/105.
Rewrite the following radical term into rational exponent form. √x
Answer:
x¹/²
Step-by-step explanation:
Taking the square root of a number is the same as taking it to the power of one half.
How to evaluate -4+3/4 plzzzz!
Answer:
-13/4
Step-by-step explanation:
Look for the LCM of both which is 4. 4÷1 ×-4 which is -16
then 4 divided by 4 which is 1 then × 3 which is 3.
now (-16+3)/4 to have -13/4
what is the smallest value that can be represented in 10-bit, two's complement representation?question 5 options:-1024-511-1023-512
The smallest value that can be represented in a 10-bit, two's complement representation is -512.
In two's complement representation, the most significant bit (MSB) is used to indicate the sign of the number. For a 10-bit representation, the MSB represents the negative range. Since the MSB is 1, the remaining 9 bits can represent a range of values from -2^9 to 2^9-1.
To find the smallest value, we set the MSB to 1 and the remaining 9 bits to 0, which gives us -512. This is the smallest negative value that can be represented in a 10-bit, two's complement system.
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True or False
Living expenses dont usually vary from month to month.
Answer:
False.Step-by-step explanation:
Some living expenses are fixed and won’t change often, such as your monthly rent. Other expenses are adjustable, such as food and clothing. That means that your spending and savings might differ from month to month, and that’s okay. Having a budget ensures you’re prepared and in a good financial place for whatever comes your way.
Hope this helps :)
Pls mark brainliest :3
And have an amazing day <3
Answer:
True
Step-by-step explanation:
I believe living expenses don't vary, due to the fact that every month you'll normally buy the same amount of groceries and gas. (Key word is that they expenses don't usually vary) Meaning that if you have to prepare for a party or a dinner it would be an abnormal variation.
Can we conclude that (x-5) is a factor of the polynomial x^3+8x^2+11x-20
Answer: No
Step-by-step explanation:
Let \(f(x)=x^3 +8x^2 +11x-20\).
Then, \(f(5)=5^3 +8(5)^2 +11(5)-20=360\).
Since \(f(5) \neq 0\), \((x-5)\) is not a factor of \(f(x)\) by the factor theorem.
20 POINTS!!! Use the quadratic formula above to solve for h(t) = -4.9t^2 + 8t + 1 where h is the height of the ball in meters and t is time in seconds. Round to the nearest hundredth second!
Answer:
Two solutions: -0.12 and 1.75.
Step-by-step explanation:
The quadratic formula is:
\(\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}\). Assuming that the x² term is a, the x term is b, and the constant is c, we can plug the values into the equation.
\(\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {8^2 - 4\cdot-4.9\cdot1} }}{{2\cdot-4.9}}} \end{array}\)
\(\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {64 + 19.6} }}{{-9.8}}} \end{array}\)
\(\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {83.6} }}{{-9.8}}} \end{array}\)
\(\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {9.14} }}{{-9.8}}} \end{array}\)
\(\frac{-8 + 9.14}{-9.8} = -0.12\)
\(\frac{-8-9.14}{-9.8} =1.75\)
Hope this helped!
Please help :( the question is in the image below
Answer:
A) 10.8
Step-by-step explanation:
what sample size should we select if we wish to develop a 90% confidence interval for the average diameter
The sample size required if we wish to develop a 90% confidence interval for the average diameter is more than 0.1 units.
To decide the test estimate required for a 90% certainty interim for the normal distance across, we have to know the taking after :
1. The level of certainty (which is 90% in this case).
2. The standard deviation of the populace (which we'll expect is known).
3. The margin of error (which is the greatest separation between the test cruel and the genuine populace cruel that we're willing to endure).
Assuming we know the standard deviation of the populace, ready to utilize the equation:
n = (z²* σ²) / E²
where:
n is the test measure
z is the z-score compared to the level of certainty (which is 1.645 for 90% certainty)
σ is the standard deviation of the populace
E is the edge of mistake
We ought to select esteem for E, which speaks to the most extreme separation between the test cruel and the genuine populace cruel(mean) that we're willing to endure.
For case, in the event that we need the interim to have a width of no more than 0.1 units, at that point we would select E = 0.1/2 = 0.05.
So, stopping within the values we know, we get:
n = (1.645² * σ²) / E²
In case we accept that the standard deviation of the populace is 0.5 units (fair as a case), at that point we get:
n = (1.645² * 0.5²) / 0.05²
n = 67.65
Adjusting up to the closest numbers, we would require a test estimate of 68 to create a 90% confidence interim for the normal breadth with an edge of blunder of no more than 0.1 units.
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in a probability-proportional-to-size sample with a sampling interval of $10,000, an auditor discovered that a selected account receivable with a recorded amount of $5,000 had an audited amount of $4,000. if this were the only misstatement discovered by the auditor, the projected misstatement of this sample would be
The projected misstatement of this sample would be $50,000, calculated as follows: ($4,000 / $5,000) x $10,000.
In a probability-proportional-to-size sample, each item's chance of being selected is proportional to its recorded amount, so larger accounts have a higher probability of being selected. In this case, the auditor selected an account with a recorded amount of $5,000, but found that it had an audited amount of $4,000.
To project the misstatement of this sample, the auditor needs to estimate the total misstatement in the population by multiplying the audited amount by the inverse of the sampling fraction, which is the sampling interval divided by the recorded amount of the selected item. So, the projected misstatement is ($4,000 / $5,000) x $10,000 = $8,000 x 6.25 = $50,000. This means that the auditor estimates the total misstatement in the population to be approximately $50,000 based on this sample.
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What percent of the large square is shaded?