can someone help me with this problem?
Thank you!

Answer:

-0.4

Step-by-step explanation:

Answer/Step-by-step explanation:

The sum of the interior angles of triangle equals 180 degrees, so the measurement of Angle A can be found by calculating the sum of the two angles shown, then subtracting the sum from 180 degrees. The measure of Angle A is 36 degrees.

The expression which is equivalent to (14x)⁰y-⁷z as required in the task content is; z / y⁷.

It follows from the task content that the expression which is equivalent to the given expression (14x)⁰y-⁷z is to be determined.

Recall from the laws of indices that a⁰ = 1 where a represents any mathematical entity.

Therefore, the resulting expression is;

1 • y -⁷ • z

= z • 1 / y⁷

= z / y⁷.

Ultimately, the resulting expression which is equivalent is; z / y⁷.

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If\(v(X+3) = v(X+6)\), then X has a constant variance.

If we have a random variable X, then we know that:

\(v(X) = E[(X - μ)^2],\)

where E is the expectation operator and μ is the mean of X.

Using this formula, we can expand v(X+3) and v(X+6) as follows:

\(v(X+3) = E[(X+3 - μ)^2]\\v(X+6) = E[(X+6 - μ)^2]\)

Now we can simplify these expressions:

\(v(X+3) = E[(X - μ + 3)^2]\\= E[(X - μ)^2 + 6(X - μ) + 9]\\= v(X) + 6E[X - μ] + 9v(X+6) \\= E[(X - μ + 6)^2]\\= E[(X - μ)^2 + 12(X - μ) + 36]\\= v(X) + 12E[X - μ] + 36\)

Since v(X+3) = v(X+6), we can equate the two expressions:

\(v(X) + 6E[X - μ] + 9 = v(X) + 12E[X - μ] + 36\\\)

Simplifying this equation yields:

\(6E[X - μ] = 27\\E[X - μ] = 4.5\)

Since the expected value of X minus its mean is 4.5, we can say that the mean of X+3 is 4.5 greater than the mean of X. Similarly, the mean of X+6 is 4.5 greater than the mean of X.

Since the variance is a measure of how spread out the data is from its mean, and the difference in the means of X+3 and X+6 is constant, it follows that the variances of X+3 and X+6 must also be the same.

Therefore, we can conclude that if\(v(X+3) = v(X+6),\) then X has a constant variance.

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Answer:

The area is 6.

Hope this helps

Answer:   36/\(K^{2}\)

Step-by-step explanation:

The k on top will cancel the k to the second power.

So the only number in the numerator is 1.

Then the 1 qill go away because you cant divide anything by 1.

The expoenet -2 that was at the top near K will become positive.

Then distribute

Step-by-step explanation:

given

In a circle

Area of circle (A) = 225π

Let r be the radius of the circle then

we know

A = πr²

225π = πr²

r²= 225

r = 15 units

Step-by-step explanation:

let the odd integers be a, a+2.

a+2=8+3a

collect like term

a-3a=8-2

-2a=6

a=-3

so the integers are -3, -1

Answer:

Account 1 has the highest effective annual interest rate (0.042666142)

Step-by-step explanation:

Hi, to answer this question we have to apply the Effective Annual Interest Rate formula:  

EAIR = [(1+r/n)^n ]-1

Where:

r = nominal interest rate

n = number of periods

If interest is compounded annually, then n = 1; if semi-annually, then n = 2; quarterly, then n = 4; monthly, then n = 12

SO:

Account 1: Interest is compounded quarterly at an annual rate of 4.20%.  

EAIR = [(1+r/n)^n ]-1 = [(1+(4.20/100)/4)^4 ]-1 = 0.042666142

Account 2: Interest is compounded monthly at an annual rate of 4.15%.  

EAIR = [(1+r/n)^n ]-1 = [(1+(4.15/100)/12)^12 ]-1 =0.042298535

Account 3: Interest is compounded semiannually at an annual rate of 4.10%

EAIR = [(1+r/n)^n ]-1 = [(1+(4.10/100)/2)^2]-1 = 0.04142025

Account 4: Interest is compounded annually at a rate of 4.25%.

EAIR = [(1+r/n)^n ]-1 = [(1+(4.25/100)/1)^1 ]-1 = 0.0425

Since:

0.042666142 (1) < 0.0425 (4) < 0.042298535(2) <0.041420258(3)

Account 1 has the highest effective annual interest rate 0.042666142

The scale of the diagram as described in the task content is; 1: 8 where k= 8.

It follows from the task content that the original length of the room in discuss is 8cm. It therefore follows that the length of the room in the scale diagram is 1cm. On this note, the scale of the diagram in discuss is; 1 : 8 as 1cm on the diagram corresponds to 8cm actual length.

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The probability of winning by picking the number 30 in roulette is 1/38.

In the game of roulette, the wheel consists of 38 spaces, with numbers 0 through 36 and an additional space marked 00. When you pick a specific number, such as 30, the probability of that number coming up on the wheel can be determined by calculating the ratio of favorable outcomes to the total number of possible outcomes.

In this case, there is only one favorable outcome, which is the ball landing on the number 30. The total number of possible outcomes is 38 since there are 37 numbered spaces (0 through 36) and one additional space for 00. Therefore, the probability of winning by picking the number 30 is 1 out of 38.

To put it simply, if you were to play roulette many times, you would expect the number 30 to come up approximately once every 38 spins on average. This probability remains the same for each individual spin, as each spin of the roulette wheel is an independent event.

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Answer:

n=-20

Step-by-step explanation:

Answer:

The length of the hypotenuse of a right triangle can be found using the Pythagorean theorem, which states that the square of the length of the hypotenuse equals the sum of the squares of the lengths of the other two sides.

Step-by-step explanation:

Answer:

d3

Step-by-step explanation:d

0 .2 x + 1.2 = 0 .5 x​

collecting like terms, we have :

0. 5 x - 0 . 2 x = 1 . 2

0. 3 x = 1. 2

Divide both sides , we have:

x = 1 . 2 / 0. 3

x = 4

90 counterclockwise rotation.

Look at the shapes. When compared to C, shape D looks like it's rotated to the left 90°. This "rotation to the left" is called counterclockwise rotation.

Think about a clock. which way does a clock hand move?

It rotates to the right. This is clockwise.

So, if something is rotated to the left, it would be "counterclockwise."

Hope this helps.

Answer:

The weight of the wood before he chopped it is 245 N

Step-by-step explanation:

The law of conservation of mass states that for a given isolated system, mass (or matter) can not be created neither can it be destroyed, but it can be transformed into different forms

Therefore, whereby all the wood Chuck chops is taken as firewood, (wood which is dry is about 100% consumable as firewood) the mass of the wool before he chopped the wood = The mass of the firewood he had after chopping the wood = 25 kg

Weight = Mass × The acceleration due to gravity, g

g = Constant = 9.8 m/s²

The weight of the wood before he chopped it = 25 kg × 98 m/s² = 245 N.

Answer:

as much as it wants

Step-by-step explanation:

Answer:

f(x) = - 6/5 * x + 3

The new function of T that models the real-world situation in terms of N is T = 560N + 750

The equations of the functions are given as

A = 165N + 750

B = 395N

From the question, we understand that

T = A + B

Substitute the known values in the above equation

So, we have

T = 165N + 750 + 395N

Collect the like terms in the above equation

So, we have

T = 165N + 395N + 750

Evaluate the like terms in the above equation

So, we have

T = 560N + 750

Hence, the new function of T that models the real-world situation in terms of N is T = 560N + 750

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Answer:

1/20,2/40

Step-by-step explanation:

Answer:

x= 5 and y = 1.5

Step-by-step explanation:

5x -4y = 19

x + 2y = 8

let x = 8 - 2y...

5x - 4y = 19.......x = 8 -2y

5(8-2y) - 4y = 19

40 - 10y -4y= 19

40-14y = 19

-14y = 19-40

-14y = -21

y = 1.5

x = 8 - 2(1.5)

x = 8 - 3

x = 5

Thus, x is 5 and y is 1.5

Hope this helps!!!!

Please mark brainliest . PLEASE!!!!!!!!

Answer:

17.6 years (roughly)

Step-by-step explanation:

ok so let's consider the amount of cobalt-60 to be: \(m\) kg of cobalt.

We can model the decay of that cobalt given its half-life of \(5.3\) as:

\(f(t) = m(\frac{1}{2})^{\frac{t}{5.3}}\)

where \(t\) is the time in years.

Now, for 90% of the cobalt to decay, we get the following equation:

\(\frac{m}{10}=m\times (\frac{1}{2})^\frac{t}{5.3}\\ \\ \frac{1}{10}=(\frac{1}{2})^\frac{t}{5.3}\)

and by using logarithms, we can find t.

\(log(\frac{1}{10})=log(\frac{1}{2}^\frac{t}{5.3})\\ \\ log(1)-log(10)=\frac{t}{5.3} log(\frac{1}{2})\\\\(log(1)=0)\\\\ -log(10)=\frac{t}{5.3} [log(1)-log(2)]\\\\(log[10]=1) \\\\\)

\(-1=(\frac{t}{5.3} )\times -log(2)\\\\\\\frac{t}{5.3}=\frac{1}{log(2)}\\ \\t=\frac{5.3}{log(2)}=17.6 years\) (roughly)

a Probability that Upper X 0.0013 ,

b. Upper X less than 80 is 0.0228

c  Upper X less than 95 or Upper X greater than 125 is 0.6853.

d 99% of the values are between 76.7 and 123.3 (symmetrically distributed around the mean).

Given a normal distribution with mu equals 100 and sigma equals 10, we can use the cumulative standardized normal distribution table to complete the following parts:

a. What is the probability that Upper X greater than 70?
Using the cumulative standardized normal distribution table, we find the z-score for 70 as (70-100)/10 = -3. We then look up the probability for a z-score of -3, which is 0.0013. Therefore, the probability that Upper X greater than 70 is 0.0013. (Round to four decimal places as needed.)

b. What is the probability that Upper X less than 80?
Using the cumulative standardized normal distribution table, we find the z-score for 80 as (80-100)/10 = -2. We then look up the probability for a z-score of -2, which is 0.0228. Therefore, the probability that Upper X less than 80 is 0.0228. (Round to four decimal places as needed.)

c. What is the probability that Upper X less than 95 or Upper X greater than 125?
Using the cumulative standardized normal distribution table, we find the z-score for 95 as (95-100)/10 = -0.5 and the z-score for 125 as (125-100)/10 = 2.5. We then find the probabilities for each of these z-scores, which are 0.3085 and 0.0062, respectively. To find the probability that Upper X is either less than 95 or greater than 125, we add these two probabilities and subtract from 1 (to account for the overlap): 1 - (0.3085 + 0.0062) = 0.6853. Therefore, the probability that Upper X less than 95 or Upper X greater than 125 is 0.6853. (Round to four decimal places as needed.)

d. 99% of the values are between what two X-values (symmetrically distributed around the mean)?
To find the z-score corresponding to the 99th percentile, we look up the probability of 0.99 in the cumulative standardized normal distribution table, which is 2.33 (rounded to two decimal places). Using this z-score, we can find the corresponding X-values using the formula z = (X - mu)/sigma. Solving for X, we get: X = z*sigma + mu = (2.33)(10) + 100 = 123.3 and X = (-2.33)(10) + 100 = 76.7. Therefore, 99% of the values are between 76.7 and 123.3 (symmetrically distributed around the mean).

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Answer:

2/3

Step-by-step explanation:

To find out what x is in this case, divide 3/4 by 9/8.

3/4 / 9/8

Dividing by a fraction is the same as multiplying it's inverse.

3/4 * 8/9

Cross cancellation (3 & 9 (GCF: 3); 4 & 8 (GCF: 4)

1/1 * 2/3

We can remove the 1/1.

2/3

2/3 is the value of x that will make 3/4 ÷ x = 9/8 true.

Answer:

To find the equation that represents the average sales each day, we need to first find the inverse of the function and then solve for S.

Inverse of S is given by:

t = (S^2 + 4S - 12)/(S - 7)(S - 2)

We can rewrite this as:

t(S - 7)(S - 2) = S^2 + 4S - 12

Expanding the left side:

t(S^2 - 9S + 14S - 14) = S^2 + 4S - 12

Simplifying:

tS^2 - 9tS + 14tS - 14t = S^2 + 4S - 12

Rearranging:

(t - 1)S^2 + (5t - 4)S - 12t + 12 = 0

Finally, solving for S:

S = [(4 - 5t) ± sqrt((5t - 4)^2 + 4(t - 1)(12t - 12))] / 2(t - 1)

Therefore, the equation that represents the average sales each day for the real estate company is:

S = [(4 - 5t) ± sqrt((5t - 4)^2 + 4(t - 1)(12t - 12))] / 2(t - 1)

Answer:

D

Step-by-step explanation:

In the data set, it begins with 10, and ends with 100. So in result, the rage would be D.

Answer:165degrees

Step-by-step explanation

Use formula N-2 × 180 N is the number of sides

24-2=22

22x180=3960 total

for each angle divide total by 24=165 degrees

(a) A scatter plot of the data is shown below.

(b) A quadratic model for the data is y = 5.58x² - 85.53x + 601.96.

(c) Yes, the quadratic model is a good fit for the data.

(d) An estimate of the amounts budgeted for the years 2005 and 2010 are $575 billion and $1123 billion respectively.

(e) Yes, I believe the model is useful for predicting the national defense budgets for years beyond 2004.

In this exercise, we would plot the years on the x-axis of a scatter plot while the defense budget would be plotted on the y-axis of the scatter plot through the use of Microsoft Excel.

Part b.

On the Microsoft Excel worksheet, you should right click on any data point on the scatter plot, select format trend line, and then tick the box to display a quadratic model of the line of best fit (trend line) on the scatter plot;

y = 5.58x² - 85.53x + 601.96

Part c.

Based on the equation of the line of best fit and the trend line above, we can reasonably infer and logically deduce that the quadratic model a good fit for the data.

Part d.

Based on the equation of the line of best fit above, the amounts budgeted for the year 2005 is given by:

Years, x = 1998 to 2005 = 15 years.

y = 5.58(15)² - 85.53(15) + 601.96

y = 574.51 ≈ $575 billion

Years, x = 1998 to 2010 = 20 years.

y = 5.58(20)² - 85.53(20) + 601.96

y = 1123.36 ≈ $1123 billion

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.