Can someone help me with this math homework please!

Answer:

20

Step-by-step explanation:

Answer:

20 is ur mode

hope this helped

Step-by-step explanation:

To find the y-coordinate of point P on the unit circle, given that its x-coordinate is 5/13, we can utilize the Pythagorean identity for points on the unit circle.

The Pythagorean identity states that for any point (x, y) on the unit circle, the following equation holds true:

x^2 + y^2 = 1

Since we are given the x-coordinate as 5/13, we can substitute this value into the equation and solve for y:

(5/13)^2 + y^2 = 1

25/169 + y^2 = 1

To isolate y^2, we subtract 25/169 from both sides:

y^2 = 1 - 25/169

y^2 = 169/169 - 25/169

y^2 = 144/169

Taking the square root of both sides, we find:

y = ±sqrt(144/169)

Since we are dealing with points on the unit circle, the y-coordinate represents the sine value. Therefore, the y-coordinate of point P is:

y = ±12/13

So, the y-coordinate of point P can be either 12/13 or -12/13.

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Answer:

5

Step-by-step explanation:

EF = 47 - 7x = 1/2 BC = 1/2 * (14+4x)

solve for x

x=6

so EF = 47-7*6 =  5

Answer:

average is 13.6

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

\(\huge\boxed{\boxed{\boxed{\bf{Hi\:there!}}}}\)

Perpendicular lines have slopes that are opposite reciprocals.

This means we take a number, change its sign, and flop it over.

Here, we have 1/4.

First, we change its sign:

-1/4

Now, we flop it over:

-4

So the slope of the line perpendicular to the given line is -4.

Now, we are given the slope of the line and a point that the line passes through.

We can use the Point-Slope formula:

\(\huge\sf{y-y1=m(x-x1)\)

\(\huge\sf{y-9=1/4(x-6)\)

\(\huge\sf{y-9=1/4x-1.5\)

\(\sf{y=1/4x-1.5+9\\\)

\(\sf{y=1/4x+10.5\)

\(\huge\boxed{Hope\:it\:helps!}\)

\(\huge\bold{\underline{Good\:luck!}}\)

\(\huge\mathfrak{LoveLastsAllEternity}\)

Answer:

7930.3 miles = d

Step-by-step explanation:

The circumference equals

C = pi *d

24901 = 3.14 d

Divide each side by 3.14

24901 / 3.14 = d

7930.254777 = d

Rounding to the nearest tenth

7930.3 =d

Answer:

4

Step-by-step explanation:

count with your fingers

Given:

There are 5 numbers followed by 2 letters.

Solution:

To find the answer, we will have a plate number that consists of 5 numbers followed by 2 letters. In that 5 numbers, each place has 10 choices-from 0 to 9. It will be: 10 * 10 * 10 * 10 * 10 = 100,000 .

Now, for the letters, there are 26 letters in the alphabet. We have two places for the letters and each place have 26 choices-from A to Z that will give us: 26 * 26 = 676

We will now multiply the acquired data for both the numbers and letters to arrive at the correct answer.

100,000 * 676 = 67,600,000

ANSWER: 67,600,000 possible license plates

Answer:

17

Step-by-step explanation:

Answer:

Step-by-step explanation:

A = true

D = true

Answer:

21

Step-by-step explanation:

Since the girls have the same age, let their age be x.
Then, their average is

\(\frac{x+x}{2} = \frac{2x}{2} = x\)

Let \(S_{i}\) denote the age of 'i' girls.
Then, \(S_{8} = S_{6} + x + x - eq(1)\)

Also, we have,

\(\frac{S_{8}}{8} =15 - eq(2)\)

\(\frac{S_{6}}{6} =13 - eq(3)\)

Then eq(2):

(from eq(1) and eq(3))

\(\frac{S_{6} + 2x}{8} =15\\\\\frac{13*6 + 2x}{8} = 15\\\\78+2x = 120\\\\2x = 120-78\\\\x = 21\)

The average of the other two girls with equal age​ is 21

Answer:

C) 6 ft

Step-by-step explanation:

Perimeter is just adding the side lengths together so...

31-15-10=x

6=x

so your answer is 6ft

If total cost for tuition plus room and board at state university is 2,584 dollars and  tuition costs 704 dollars more than room and board, then the tuition fees is 1644 dollars

Given,

The total cost for tuition plus room and board = 2584 dollars

Consider the cost for room and board as x

Tuition costs 704 dollars more than room and board.

Therefore the tuition fees = 704+x

Then the total cost = Cost for tuition fees+ Cost for room and board

2584 = (704+x)+x

2584= 704+2x

2x= 1880

x= 940  dollars

Then the tuition fees = 704+x

=704+940

=1644 dollars

Hence, if total cost for tuition plus room and board at state university is 2,584 dollars and  tuition costs 704 dollars more than room and board, then the tuition fees is 1644 dollars

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Answer:

Step-by-step explanation:

Let the equation of the line representing relation between the euros and dollars is,

E = mD + b

Where 'E' = Number of euros

D = Number of dollars

m = slope of the line

b = y-intercept

Slope of a line which passes through two points (120, 90) and (400, 300) will be,

m = \(\frac{y_2-y_1}{x_2-x_1}\) = \(\frac{300-90}{400-120}\)

m = 0.75

Equation of the line passing through (120, 90),

90 = 0.75(120) + b

b = 90 - 90 = 0

Therefore, equation of the line will be,

E = mD

E ∝ D

Here m = Proportionality constant

And the relation between the numbers of Euros and US dollars is a proportional relationship.

Step-by-step explanation:

mean when 82 is present

=82+44+27+96+69+80+75+83+56+98=710

10 10

= 71

mean when 42 is present

=42+44+27+96+69+80+75+83+56+98=670

10 10

=67

therefore the mean decreases with

= 71 - 67 = 4

The first constraint is a linear equation that relates the variables x1, x2, and x3, and the second constraint is an inequality constraint involving x1 and x2The given problem is a linear programming problem in its primal form.

The objective is to maximize the expression z = 7x1 - 5x2 - 2x3, subject to two constraints.. The goal is to find the values of x1, x2, and x3 that maximize the objective function while satisfying the given constraints.

In the primal problem, the objective is to maximize the expression z, which is a linear combination of the decision variables x1, x2, and x3. The coefficients 7, -5, and -2 represent the weights assigned to each variable in the objective function. The constraints represent the relationships and limitations imposed on the variables. The first constraint is an equality constraint, which means that the left-hand side of the equation must equal the right-hand side. The second constraint is an inequality constraint, indicating that the value of the expression 2x1 + x2 must be less than or equal to a certain value.

To solve this linear programming problem, various optimization techniques such as the simplex method or interior point methods can be applied. These methods iteratively adjust the values of the decision variables to find the optimal solution that maximizes the objective function while satisfying the given constraints. By solving the primal problem, the values of x1, x2, and x3 can be determined, leading to the maximum value of the objective function z.

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Answer:

2 pints

Step-by-step explanation:

if you add all of it up you get 2 pints.

1/4*8 = 2 pints

Answer: 15 months

Step-by-step explanation:

Answer:

x=32/7

Step-by-step explanation:

7x-2(1)=30  Plug in 1 as y and simplify.

7x-2=30     Add 2 on both sides of the equation.

  +2 +2

7x=32         Divide both sides of the equation by 7.

/7   /7

x=32/7

Hope this helps...have an amazing day (｡･∀･)ﾉﾞ

The chemicals under considerationm an important quantity is the total proportion Y1 +Y2 found in any sample.V(Y1 + Y2) = Var(Y1) + Var(Y2) + 2Cov(Y1, Y2) = 1/18 + 1/18 + 2(1/144) = 5/72.

To find E(Y1 + Y2), we first find the marginal distribution of Y1 and Y2 by integrating the joint density function over the other variable as follows:

f1(y1) = ∫f(y1,y2)dy2 = ∫2dy2 from 0 to 1-y1 = 2(1-y1) for 0 ≤ y1 ≤ 1

f2(y2) = ∫f(y1,y2)dy1 = ∫2dy1 from 0 to 1-y2 = 2(1-y2) for 0 ≤ y2 ≤ 1

Now we can find E(Y1 + Y2) as follows:

E(Y1 + Y2) = ∫∫(y1 + y2)f(y1,y2)dy1dy2

= ∫∫(y1 + y2)2dy1dy2 over the region 0 ≤ y1 ≤ 1-y2, 0 ≤ y2 ≤ 1

E(Y1 + Y2) = ∫0^1∫0^(1-y1) (y1 + y2)2dy2dy1

= ∫0^1[y1(y1/2 + 2/3) + 1/3]dy1

= 7/12

To find V(Y1 + Y2), we can use the fact that V(Y1 + Y2) = V(Y1) + V(Y2) + 2Cov(Y1, Y2), where Cov(Y1, Y2) is the covariance of Y1 and Y2. First, we need to find the variances of Y1 and Y2:

Var(Y1) = E(Y1^2) - [E(Y1)]^2 = ∫∫y1^22dy1dy2 - [∫∫y1f(y1,y2)dy1dy2]^2

= ∫0^1∫0^(1-y1) y1^22dy2dy1 - [∫0^1(2y1-2y1^2)dy1]^2

= 1/18

Var(Y2) = E(Y2^2) - [E(Y2)]^2 = ∫∫y2^22dy1dy2 - [∫∫y2f(y1,y2)dy1dy2]^2

= ∫0^1∫0^(1-y2) y2^22dy1dy2 - [∫0^1(2y2-2y2^2)dy2]^2

= 1/18

Now we need to find the covariance of Y1 and Y2:

Cov(Y1, Y2) = E(Y1Y2) - E(Y1)E(Y2) = ∫∫y1y2f(y1,y2)dy1dy2 - (∫∫y1f(y1,y2)dy1dy2)(∫∫y2f(y1,y2)dy1dy2)

= ∫0^1∫0^(1-y1) 2y1y2dy2dy1 - (7/12)(7/12)

= 1/144

Therefore, V(Y1 + Y2) = Var(Y1) + Var(Y2) + 2Cov(Y1, Y2) = 1/18 + 1/18 + 2(1/144) = 5/72.

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Answer:

-15x + 28y

Step-by-step explanation:

-3x + 7y + 21y - 12x

= -15x + 28y

Answer:

-15x+28y

Step-by-step explanation:

The critical points of the function are (0, 0) and (3/4, -9/4), To classify the critical points, we need to examine the second partial derivatives of f(x, y) at each point

To find the critical points of the function f(x, y) = 8x^3 + y^2 + 6xy, we need to find the values of (x, y) where the partial derivatives with respect to x and y are equal to zero.

Taking the partial derivative with respect to x, we have:

∂f/∂x = 24x^2 + 6y = 0.

Taking the partial derivative with respect to y, we have:

∂f/∂y = 2y + 6x = 0.

Solving these two equations simultaneously, we get:

24x^2 + 6y = 0,

2y + 6x = 0.

From the second equation, we can solve for y in terms of x:

Y = -3x.

Substituting this into the first equation:

24x^2 + 6(-3x) = 0,

24x^2 – 18x = 0,

6x(4x – 3) = 0.

Therefore, we have two possibilities for x:

1. x = 0,

2. 4x – 3 = 0, which gives x = ¾.

Substituting these values back into y = -3x, we get the corresponding y-values:

1. x = 0 ⇒ y = 0,

2. x = ¾ ⇒ y = -9/4.

Hence, the critical points of the function are (0, 0) and (3/4, -9/4).

To classify the critical points, we need to examine the second partial derivatives of f(x, y) at each point. However, since the original function does not provide any information about the second partial derivatives, further analysis is required to classify the critical points.

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The ounces of soda consumed by an adult next month are examples of a discrete random variable,  False

A discrete random variable are known as counts. This is because it takes on only a countable number of distinct values. This means a random variable can only be considered to be discrete if it can take on values that are countable in an interval, otherwise it can be continuous.

Now on the question of ounces of soda consumed by an adult next month is considered not to be discrete random variable. This is because ounces of soda or volume of soda consumed are countless and infinite in number.  

Hence, the statement that says ounces of soda consumed by an adult next month are an example of a discrete random variable is False.

Choice b(False) is correct.  

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Answer:

Domain = all real numbers

range = -1<= y <= 1

The domain of y=cosx is all real numbers and the range is -1 ≤ y ≤ 1.

The range of 'x' of a function is known as the domain of definition of a function and the range of 'y' of a function is known as the range of the function.

The function is continuous for all real values of 'x'.

Hence, the domain of the function is all real numbers.

The upper limit value of cosx =1 and lower limit value of cosx = -1 .

Hence, the range of the function is -1 ≤ y ≤ 1.

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Answer:

its 0.9 which is 90 I Literally divided it

Step-by-step explanation:

£6.30 divided by 7 is equal to 90 pence.

In mathematics, the division operation splits left-hand operands into right-hand operands. The division's primary goal is to create equal groups or to ascertain how many individuals are in each category following a fair distribution.

For example 4/2 = 2

To convert £6.30 to pence, we multiply it by 100 because there are 100 pence in 1 pound.

£6.30 x 100 = 630 pence

Now, to calculate 630 pence divided by 7:

630 pence / 7 = 90 pence

Therefore, £6.30 divided by 7 is equal to 90 pence.

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Explanation:

For regular tessellations, the types of polygons that we can use are

We can only pick one of those shapes.

Shapes like regular octagons or pentagons will not work on their own because there is gap or overlap if we tried to glue them together. Think of tiles on the floor. There cannot be any gap or overlap when forming a tessellation.

If you wanted to use octagons to tessellate the plane, then you'd need squares to fill in the gaps. At this point, it's not considered a regular tessellation.

Answer:

64.2580645161 words in a minute

Step-by-step explanation:

Hope that helps!

Answer:

Gordon types 72 words per minute.

Step-by-step explanation:

You divide to find the unit rate.

Answer:

An arithmetic sequence has a constant difference between each term.

For example: 2,4,6,8,10,12,…

We can see clearly that all the terms differ by +2.

We call this the common difference, d.

A geometric sequence has a constant ratio (multiplier) between each term.

An example is: 2,4,8,16,32,…

So to find the next term in the sequence we would multiply the previous term by 2.

This is called the common ratio, r.

These sequences are closely related as they both have the same first term, but I hope you can see how different they become if they have a common difference or a common ratio.

We can create a decreasing arithmetic sequence by choosing a negative common difference.

Similarly, a decreasing geometric sequence would have a common ratio of less than 1.

Step-by-step explanation:

To complete the right or left matrix of rotation about the point (0, 0) for 2D graphics in the homogeneous system (z = 1), we use the following formulas:$$\textbf{Left Matrix of Rotation: } \begin{bmatrix} \cos \theta & \sin \theta & 0 \\ -\sin \theta & \cos \theta & 0 \\ 0 & 0 & 1 \end{bmatrix}$$$$\textbf{Right Matrix of Rotation: } \begin{bmatrix} \cos \theta & -\sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1 \end{bmatrix}$$where $\theta$ is the angle of rotation.

The given matrix, we have $2p$ in the first row and $\cos a$ in the second row. Therefore, we can conclude that it represents a horizontal line segment of length $2p$ at a height of $\cos a$ above the $x$-axis. Now, we need to find the appropriate matrix for rotating this line segment about the point $(0, 0)$ by an angle of $\theta$.Since we want to know the matrix for the rotation of the line segment, we need to consider the effect of the rotation on the endpoints of the line segment.

The endpoints of the line segment can be represented in the homogeneous system as $(p, \cos a, 1)$ and $(-p, \cos a, 1)$.Left Matrix of Rotation:For the left matrix of rotation, we have:$$\begin{aligned}\begin{bmatrix} \cos \theta & \sin \theta & 0 \\ -\sin \theta & \cos \theta & 0 \\ 0 & 0 & 1 \end{bmatrix} \begin{bmatrix} p \\ \cos a \\ 1 \end{bmatrix} &= \begin{bmatrix} p\cos \theta + \sin \theta \cos a \\ -p \sin \theta + \cos \theta \cos a \\ 1 \end{bmatrix} \\ \begin{bmatrix} \cos \theta & \sin \theta & 0 \\ -\sin \theta & \cos \theta & 0 \\ 0 & 0 & 1 \end{bmatrix} \begin{bmatrix} -p \\ \cos a \\ 1 \end{bmatrix} &= \begin{bmatrix} -p\cos \theta + \sin \theta \cos a \\ p \sin \theta + \cos \theta \cos a \\ 1 \end{bmatrix}\end{aligned}$$Therefore, the left matrix of rotation is:$$\boxed{\begin{bmatrix} \cos \theta & \sin \theta & 0 \\ -\sin \theta & \cos \theta & 0 \\ 0 & 0 & 1 \end{bmatrix}}$$Right Matrix of Rotation.

For the right matrix of rotation, we have:$$\begin{aligned}\begin{bmatrix} \cos \theta & -\sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1 \end{bmatrix} \begin{bmatrix} p \\ \cos a \\ 1 \end{bmatrix} &= \begin{bmatrix} p\cos \theta - \sin \theta \cos a \\ p \sin \theta + \cos \theta \cos a \\ 1 \end{bmatrix} \\ \begin{bmatrix} \cos \theta & -\sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1 \end{bmatrix} \begin{bmatrix} -p \\ \cos a \\ 1 \end{bmatrix} &= \begin{bmatrix} -p\cos \theta - \sin \theta \cos a \\ -p \sin \theta + \cos \theta \cos a \\ 1 \end{bmatrix}\end{aligned}$$Therefore, the right matrix of rotation is:$$\boxed{\begin{bmatrix} \cos \theta & -\sin \theta & 0 \\ \sin \theta & \cos \theta & 0 \\ 0 & 0 & 1 \end{bmatrix}}$$Therefore, the left matrix of rotation is represented by the letter $\boxed{L}$ and the right matrix of rotation is represented by the letter $\boxed{R}$.

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