can someone help me please

Answer:

3x−5y=6⇒y=35x−65 . If you have y=mx+c then intercept is c . So intercept is −65 .

The coordinates of the missing endpoint are (-4, 3)

The coordinates of the midpoint of a line (x,y) is given by x =

\(x = \frac{x_{1} + x_{2}}{2}\) and \(y = \frac{y_{1} + y_{2}}{2}\) where (x₁, y₁) and (x₂, y₂) are the coordinates of the endpoints of the line.

Given that the midpoint of the line XY is W = (-1, 6) and one endpoint Y = (2, 9), the missing endpoint is X = (x₁, y₁).

Making x₁ and y₁ the subject of the formula in the equation for x and y, we have

x₁ = 2x - x₂ and y₁ = 2y - y₂

Since the midpoint is W = (-1,6), (x, y) = (-1, 6) and the other endpoint is Y = (2, 9 ). So, (x₂, y₂) = (2, 9)

So, x = -1 and x₂ = 2

Substituting the values of the variables into the expression for x₁, we have

x₁ = 2x - x₂

x₁ = 2(-1) - 2

x₁ = -2 - 2

x₁ = -4

Also, y = 6 and y₂ = 9

Substituting the values of the variables into the expression for y₁, we have

y₁ = 2y - y₂

y₁ = 2(6) - 9

y₁ = 12 - 9

y₁ = 3

Since x₁ = -4 and y₁ = 3,

The coordinates of the missing endpoint are (-4, 3)

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The length of the line segment AB is 11/2 mm.

A triangle is a three-sided closed-plane figure formed by joining three noncolinear points.

Based on the side property triangles are of three types they are Equilateral triangle, Scalene triangle, and Isosceles triangle.

We know a line segment parallel to one side of a triangle divides the other two sides in the same ratio.

Therefore, AC/AB = EC/ED.

22/AB = 44/11.

2/AB = 4/11.

4AB = 22.

AB = 11/2.

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By using the concept of bell shaped curve of normal distribution, it can be concluded that

The histogram would not look like a bell shaped curve because occurance of fire may not be constant in  all the case.

What is normal distribution?

Normal distribution is a continuous type probability distribution whose probability density function is given by

f(x) = \(\frac{1}{\sigma \sqrt{2\pi}}e^-{\frac{z^2}{2}\)

Where z = \(\frac{x - \mu}{\sigma}}\) where \(\mu\) is the mean and \(\sigma\) is the standard deviation

A fire department in a small town keeps track of the number of fires it has to fight each day for a year and records the 365 values central limit theorem.

Here, in this case it is not confident that the histogram would not look like a bell shaped curve because occurance of fire may not be constant in  all the case.

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Answer:

Correct.

Step-y-step explanation:

the sum of XY is 100. To compute the sum of X2, Y2 and XY, first we need to find the individual values for each.

For X2: X2 = 12 + 32 + 52 + 72 = 1 + 9 + 25 + 49 = 84.

For Y2: Y2 = 22 + 42 + 62 + 82 = 4 + 16 + 36 + 64 = 120.

For XY: XY = 1*2 + 3*4 + 5*6 + 7*8 = 2 + 12 + 30 + 56 = 100.

Therefore, the sum of X2 is 84, the sum of Y2 is 120, and the sum of XY is 100.

To compute ΣX2, ΣY2 and ΣXY, we need to find the sum of the squares of the values of X and Y, and the sum of the products of the values of X and Y respectively. Here's how to do it: 1. ΣX2 = (12 + 32 + 52 + 72) = (1 + 9 + 25 + 49) = 84 2. ΣY2 = (22 + 42 + 62 + 82) = (4 + 16 + 36 + 64) = 120 3. ΣXY = (1*2 + 3*4 + 5*6 + 7*8) = (2 + 12 + 30 + 56) = 100 Therefore, the values of ΣX2, ΣY2 and ΣXY are 84, 120, and 100 respectively.

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1. In the context of spacetime, the locus of points equidistant from the origin of a spacetime plane is a hyperbola.

In Euclidean space, the distance between two points is given by the Pythagorean theorem, which only considers spatial dimensions. However, in spacetime, the concept of distance is extended to include both spatial and temporal components. The spacetime distance, also known as the interval, is given by the Minkowski metric:

ds^2 = -c^2*dt^2 + dx^2 + dy^2 + dz^2,

where c is the speed of light, dt represents the temporal component, and dx, dy, dz represent the spatial components.

To determine the locus of points equidistant from the origin, we need to find the set of points where the spacetime interval from the origin is constant. Setting ds^2 equal to a constant value, say k^2, we have:

-c^2*dt^2 + dx^2 + dy^2 + dz^2 = k^2.

If we focus on a spacetime plane where dy = dz = 0, the equation simplifies to:

-c^2*dt^2 + dx^2 = k^2.

This equation represents a hyperbola in the spacetime plane. It differs from a circle in Euclidean space due to the presence of the negative sign in front of the temporal component, which introduces a difference in the geometry.

Therefore, the locus of points equidistant from the origin in a spacetime plane is a hyperbola.

(Note: The explanation provided assumes a flat spacetime geometry described by the Minkowski metric. In the case of a curved spacetime, such as that described by general relativity, the shape of the locus of equidistant points would be more complex and depend on the specific curvature of spacetime.)

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Answer: In Stalin's view, counter-revolutionary elements will attempt to derail the transition to full communism, and the state must be powerful enough to defeat them. For this reason, Communist regimes influenced by Stalin have been widely described as totalitarian.

Step-by-step explanation:

The population proportion who participated in voting (63%) is higher than the sample proportion from this survey (58.91%).

To determine whether the population proportion who participated in voting or the sample proportion from the survey is higher, we need to compare the percentages.

The population proportion who participated in voting is given as 63% of all registered voters.

This means that out of every 100 registered voters, 63 participated in voting.

In the survey of retired voters, 162 out of 275 participants voted. To calculate the sample proportion, we divide the number of retired voters who participated (162) by the total number of retired voters in the sample (275) and multiply by 100 to get a percentage.

Sample proportion = (162 / 275) \(\times\) 100 ≈ 58.91%, .

Comparing the population proportion (63%) with the sample proportion (58.91%), we can see that the population proportion who participated in voting (63%) is higher than the sample proportion from this survey (58.91%).

Therefore, based on the given data, the population proportion who participated in voting is higher than the sample proportion from this survey.

It's important to note that the sample proportion is an estimate based on the surveyed retired voters and may not perfectly represent the entire population of registered voters.

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The first quartile of the data set represented by the box plot is 12.

The median of the data set is 16.

We have,

The box plot is drawn using five summary statistics: minimum, maximum, median, and the first and third quartiles.

The box in the plot represents the middle 50% of the data, with the lower end of the box representing the first quartile (Q1) and the upper end representing the third quartile (Q3).

The median is shown as a line inside the box.

From the box plot,

Median = 16

First quartile = 12

Third quartile = 19

Lowest value = 9

Largest value = 24

Thus,

The first quartile of the data set represented by the box plot is 12

The median of the data set is 16.

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The required Matlab code to find the greatest common divisor of a number using the Euclidean algorithm is shown.

To find the greatest common divisor (GCD) of two numbers using the Euclidean algorithm in MATLAB, you can use the following code:

% Replace '12345678' with your actual student number

studentNumber = '12345678';

% Extract the first 4 digits as the first number

firstNumber = str2double(studentNumber(1:4));

% Extract the last 3 digits as the second number

secondNumber = str2double(studentNumber(end-2:end));

% Find the GCD using the Euclidean algorithm

gcdValue = gcd(firstNumber, secondNumber);

% Display the result

disp(['The GCD of ' num2str(firstNumber) ' and ' num2str(secondNumber) ' is ' num2str(gcdValue) '.']);

Make sure to replace '12345678' with your actual student number. The code extracts the first 4 digits as the first number and the last 3 digits as the second number using string indexing. Then, the gcd function in MATLAB is used to calculate the GCD of the two numbers. Finally, the result is displayed using the disp function.

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The above question is related to probability and has seven possible choices. The question requires finding the probabilities of selecting the correct and incorrect choices in different scenarios, such as selecting a choice randomly or after eliminating two of the options. To solve the question, we need to use basic probability concepts and formulas, such as the formula for probability, which is the number of favorable outcomes divided by the total number of possible outcomes.

(a) The probability of selecting the correct choice is 1/7 or approximately 0.143.

(b) The probability of selecting an incorrect choice is 6/7 or approximately 0.857.

(c) If two choices are eliminated, there will be five remaining choices, and the probability of selecting the correct choice will be 1/5 or approximately 0.2.

(d) If two choices are eliminated, there will be five remaining choices, and the probability of selecting an incorrect choice will be 4/5 or approximately 0.8.

It's crucial to remember that while deleting options might enhance the likelihood of picking the correct option, it can also raise the likelihood of selecting an erroneous option if the deleted options were more likely to be inaccurate. In each instance, the overall chance of making a correct or bad decision is always 1.

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The measures of central tendency of the first psychology exam in a semester are the average score, which was an 85.

The correlation coefficient and the range of scores from 95 to 65 are not measures of central tendency either.

The standard deviation is a measure of variability, not central tendency, that the measures of central tendency of the first psychology exam are the average and median scores. This states that the mode, correlation coefficient, range of scores, and standard deviation are not measures of central tendency.

Hence, the measures of central tendency for the first psychology exam in a semester are the average score (85) and the median score (80).

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The measures of central tendency for the psychology exam scores include the average, median, and mode.

The measures of central tendency of the first psychology exam in a semester include the average score, median score, and mode (most frequently occurring score).

The average score on the exam was 85, which represents the mean of all the scores.

The median score on the exam was 80, which represents the middle value when all the scores are arranged in order.

The most frequently occurring score was 82, which represents the mode of the scores.

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The probability that the coin will come up heads on the fourth try is 1/2.

Given,

If a fair coin were tossed three times and each time it landed on its head.

We have to find the probability that it will come up heads on the fourth try;

Here,

Coming up short in the first three of four attempts.

The probability will not depend on the first three occurrences in the fourth try.

Consequently, the likelihood of winning the fourth time will be as follows:

Desired outputs as a percentage of overall output

=> 1 / 2

Hence,

The probability of the coming head in the fourth time is 1/2 because the coming head in the fourth time is independent of the coming head in the first three times.

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It will take the town 21 years 4 months to reach 4600 in population

a rate is a ratio that compares two different quantities which have different units. For example, if we say John types 50 words in a minute, then his rate of typing is 50 words per minute. The word "per" gives a clue that we are dealing with a rate.

initial population = 3000

population increase every year = 2.5% of 3000

which is 2.5/100 x 3000 = 75

let the time taken to reach 4600 be d

increment for d number of years = 75d

Total population after d years is 75d + 3000

so 75d + 3000 = 4600

75d = 4600  - 3000

75d = 1600

d = 1600/75

d = 21.33 years which is 21 years 4 months

In conclusion 21 years 4 months is the time taken for the ton tto get tto 4600

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The correct option is 2000.

To find the variance of a random variable X, we need to calculate the expected value of the squared deviations from the mean.

The expected value of X (ElX) = 200Variance of X = E[(X - ElX)^2]Here, we have three possible values of X: 100, 200, and 300.

So, let's calculate the deviations of X from its expected value: Xi - ElX 100 - 200 = -100200 - 200 = 0300 - 200 = 100Next, let's square these deviations:(Xi - ElX)^2 (-100)^2 = 10,000(0)^2 = 0(100)^2 = 10,000

Now, we need to multiply each squared deviation by its corresponding probability, and sum the results: Variance of X = E[(X - ElX)^2]= (-100)^2 * 0.1 + (0)^2 * 0.8 + (100)^2 * 0.1= 10,000 * 0.1 + 0 * 0.8 + 10,000 * 0.1= 1,000 + 0 + 1,000= 2,000

Therefore, the variance of the random variable X is 2,000. Hence, the correct option is 2000.

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Answer:

x^4

Explanation:

Breakdown x^4 = x · x · x · x

Breakdown x^5 = x · x ·  x · x · x

Here the common factor is x · x · x · x = x^4

Hence, the greatest common factor of x^4 and x^5 is x^4.

Answer:

Step-by-step explanation:

The sides of a triangle measure 6, 8 and 10 cm. What is the area of the triangle?

from the data it is a right triangle, 10 cm is the hypotenuse

so

1/2 (6 * 8) =

1/2 * 48 =

24 units²

Planning, designing, gathering data, analyzing, creating relevant interpretations, and publishing the research findings are all statistical approaches that go into conducting a study.

The statistical analysis lends meaning to the abstract numbers, giving the data some life. Only when appropriate statistical tests are applied will the results and inferences be accurate. Science's field of statistics deals with gathering, organizing, analyzing, and extrapolating data from samples to the entire population. This necessitates the use of an acceptable statistical test, an adequate study design, and an appropriate study sample selection.  However, if we want additional information about these, a consulting company may be able to assist us. we will benefit more from Silver Lake Consulting for our project.

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A piecewise function is a function that is defined by different equations on different intervals.

Graphing a piecewise function on a graph is a great way to visualize its behavior and understand its properties. One of the most popular and user-friendly ways to graph piecewise functions is using the online graphing calculator Desmos.

Here is a step-by-step guide on how to graph a piecewise function on Desmos:

Go to the Desmos website

and click on the "Graphing Calculator" button.

On the left side of the screen, you will see a text box labeled "y=". This is where you will enter the equation of your piecewise function. You can enter multiple equations by separating them with commas.

To graph a piecewise function, you will need to enter different equations for different intervals.

For example, if you have a piecewise function that is defined by the equation y = x^2 for x < 0 and y = x + 2 for x ≥ 0, you would enter y = x^2, x < 0 and y = x + 2, x ≥ 0 in the "y=" text box.

Once you have entered your equations, press the "Graph" button to see the graph of your piecewise function on the screen.

If you want to adjust the graph, you can use the sliders on the left side of the screen to change the range of the x- and y-axis. You can also use the buttons at the top of the screen to zoom in and out or pan around the graph.

To see the graph of multiple piecewise functions at once you can use the "Add another equation" button under the "y=" text box to add additional equations.

You can also use the "Table" tab to see the values of the function at certain x-values and also can use the "Slider" tab to change the value of x and see how that effects the graph of the function.

By following these steps, you can easily graph piecewise functions on Desmos and visualize the behavior of the function. Desmos is a great tool that allows you to experiment with different equations and see how they affect the graph of the function.

It is a great way to understand the properties of piecewise functions and to visualize them in multiple ways.

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There are 2 ways that 3 students be seated in a row of 3 chairs with jack in the first chair

It is the ordered arrangement of members belonging to a set with no repeats.

To solve this problem the formula and the permutation procedure we must use is:

nPr = n! / (n-r)!

Where:

Information about the problem:

Applying the permutation formula we have:

nPr = n! / (n-r)!

3P3 = 2! / (2-2)!

3P3 = 2! / 0!

3P3 = 2*1 / 1

3P3 = 2

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The weight of the eggs in grams 95.38 grams.

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X ~ N(58,21)

where µ = 58 and σ = 21

The z score for this case is given by this formula:

z = x -  µ/σ

We know that the value of z = 1.78 and we want to estimate the value of X. If we solve for X from the z formula we got:

X =  µ+1.78σ

= 58 + 1.78×21

= 95.38

So, the corresponding weight for a z score of 1.78 is 95.38 grams.

Hence we get the required answer.

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The length of chord XY is 5√2.

What is the length of the chord?

It is described as the line segment that connects any two points on the circle's circumference without going through the circle's center. As a result, the diameter is the chord of a particular circle that is the longest and goes through its center. In mathematics, determining the chord's length can be crucial at times.

Here, we have

Given: A circle with center O and radius 5 has a central angle XOY. X and Y are points on the circle. ​If the measure of arc XY is 90 degrees.

We have to find the length of chord XY.

∠XOY = 90°

OX = OY = 5

We draw a perpendicular from the center to chord XY bisect XY at D.

Now, since OD bisects ∠XOY

∠XOD = ∠YOD = 90°/2 = 45°

Now, in ΔXOD

sin45° = XD/OX

1/√2 = XD/5

5/√2  = XD...(1)

In ΔYOD

sin45° = YD/OY

5/√2  = YD...(2)

Adding (1) and (2), we get

XD + YD = 5/√2 + 5/√2

XY = 5√2

Hence, the length of chord XY is 5√2.

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The number of edges that the prism has is

When a plane intersects a prism, the shape formed is known as the cross section. The cross section of the prism will have the same form as the base if it is divided by a plane that runs horizontally and parallel to the base.

A prism is a 3-dimensional object with two congruent and parallel bases (which are polyggonal) connected by rectangular lateral faces. The number of edges of a prism is equal to the sum of the number of edges of the two bases and the number of lateral faces.

Each base of the prism has n edges, so the two bases together have 2n edges. The number of lateral faces of the prism is equal to the number of edges of one of its bases, so there are n lateral faces. Each lateral face has 4 edges, so the total number of edges of the lateral faces is 4n.

Therefore, the total number of edges of the prism is equal to the sum of the number of edges of the two bases (2n) and the number of lateral faces (4n), which is 2n + 4n = 6n.

In conclusion, the cross section of a prism is an n-sided polygon and the prism has n + 2 edges.

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Answer:

9

Step-by-step explanation: subtract 3 from 12 and you get 9 as your answer

Answer:

Radius = 3.38 cm

Step-by-step explanation:

Here's your solution

=> The volume of cylinder = 720π cm^3

=> The height of cylinder = 20 cm

=> Radius = ?

=> Formula of volume of cylinder = πr^2h

=> 22/7 * r^2 * 20 = 720π cm^3

=> r^2 = (720*7)/20*22

=> r^2 = 11.45

=> r = √11.45

=> r = 3.38 cm

hope it helps

Answer:

2

Step-by-step explanation:

17.5-9.5=8

\(4\sqrt{8}\)=2

Each bag of dog food weight 2 pounds.

The quadrilateral is a trapezoid. The value of x is 5 by applying midsegment theorem for trapezoids.

The midsegment of a trapezoid is parallel to each base and its length is one half the sum of the lengths of the bases.

The side with length 21 units and 27 units are parallel to each other.

From the given diagram, the expression below is true:

5x-1 = (21 + 27)/2

2(5x - 1) = 21 + 27

10x - 2 = 48

10x = 48 + 2

10x = 50

Divide both sides by 10

x = 50/10

x = 5

Hence the value of x is 5

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The image of this question is probably this.