Answer:
Speed of gamma rays = 3 x 10⁸ m/s
Explanation:
Given:
Frequency of gamma ray = 3 x 10¹⁹ Hz
Wavelength of gamma rays = 1 x 10⁻¹¹ meter
Find:
Speed of gamma rays
Computation:
Velocity = Frequency x wavelength
Speed of gamma rays = Frequency of gamma ray x Wavelength of gamma rays
Speed of gamma rays = [3 x 10¹⁹][1 x 10⁻¹¹]
Speed of gamma rays = 3 x [10¹⁹⁻¹¹]
Speed of gamma rays = 3 x [10⁸]
Speed of gamma rays = 3 x 10⁸ m/s
I need help
Come up with a hypothetical experiment and explain how you would set it up.
Tell me:
What observation/phenomenon is your experiment about?
What is your Hypothesis? (What do you think the results will be?)
How would you conduct your experiment?
Remember to consider how you would collect your sample, the need for a control group, and the need to avoid serious connections and isolate relevant data.
In this scenario, you have unlimited resources and no ethical restrictions. You can turn this in person or online.
The observation or phenomenon that is said to be my experiment about is: The long time effect of plastic waste in the environment.
What is the Hypothesis?H0 = There is no long time effect of plastic waste in the environment.
Ha = There is a long time effect of plastic waste in the environment.
How would you conduct your experiment?Samples will be collected from places where there are different kinds of plastic waste. It will be done in several location. Soil and chemical analysis will be done and data will be extracted. The control will be an environment that has no plastic waste.
Data will be collected on some types of Plastics such as:
Polyethylene (PE) Polyethylene terephthalate (PET) Polypropylene (PP) Polystyrene (PS) Polyvinylchloride (PVC)Therefore, The observation or phenomenon that is said to be my experiment about is: The long time effect of plastic waste in the environment.
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A horizontal spring with a constant of 3000 N/m is compressed 4.0 cm from equilibrium. A 2.0 kg mass is placed on front of the compressed spring and then is released. The object drags on a flat surface with a coefficient of friction equal to .23 and eventually comes to rest. How far from the spring does the mass travel?
Regarding a spring-mass system's duration, the square root of the mass and the spring constant have opposing correlations. The length of spring will be longer and vice versa as the mass grows. Therefore, the mass influences spring.
What far from the spring does the mass travel?They swing back and forth around a stationary point. Classic examples of this type of vibrating motion are a simple pendulum and a mass on a spring.
Therefore, The use of motion detectors demonstrates that the vibrations of these objects have a sinusoidal nature, even if this is not obvious from plain viewing.
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the distance between an object and its real image is 40 cm, if the magnification is 3, calculate the object and image distance if the focal length of the lens is 15 cm
The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.
What is the image and object distance?The object and image distance formed by the lens is calculated by applying the following lens formula.
v + u = 40 ------- (1)
v/u = 3 ------------ (2)
v = 3u
Substitute v into equation (1);
3u + u = 40
4u = 40
u = 40/4
u = 10 cm
The image distance = 3u
= 3 x 10 cm
= 30 cm
Thus, the object distance is 10 cm and the image distance is 30 cm.
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Using a refracting telescope, you observe the planet Mars when it is 1.99×1011 m from Earth. The diameter of the telescope's objective lens is 0.977 m . What is the minimum feature size, in kilometers, on the surface of Mars that your telescope can resolve for you? Use 563 nm for the wavelength of light.
The minimum feature size, in kilometers, on the surface of Mars that your telescope can resolve for you is 140km.
What is telescope?Telescope is device through which we can see the distant objects very clearly as it seems like they are some meters away.
Distance of the Mars from the Earth D = 1.99 x 10¹¹ m
Diameter of telescope's objective lens d = 0.977 m
The wavelength of light λ in m, λ = 563nm = 563 x 10⁻⁹ m
The distance y or the minimum feature size =1.22λD/d
Substitute the value, we get
y = 1.22 x 563 x 10⁻⁹ x 1.99 x 10¹¹ /0.977
y = 140 km (approximately)
Thus, the minimum feature size, in kilometers, on the surface of Mars that your telescope can resolve for you is 140km.
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How far does a person travel in coming to a complete stop in 38 ms at a constant acceleration of 60 g ?
The distance traveled by the person to come to a complete stop in 38 ms at a constant acceleration of 60 g is approximately 273.42 meters.
The distance that a person covers to come to a complete stop in 38 ms at a constant acceleration of 60 g can be calculated using the kinematic equation.
The formula is given by, d = (v^2 - u^2) / 2a, where d is the distance traveled, v is the final velocity, u is the initial velocity, and a is the acceleration given in g units.
To solve the problem, we need to first convert the acceleration given in g units to meters per second squared (m/s²). We know that 1 g is equivalent to 9.8 m/s².
Hence, 60 g is equivalent to 60 × 9.8 m/s² = 588 m/s².
Substituting the values in the above formula, we get,d = (0 - u^2) / 2a= u^2 / 2a, since the final velocity is 0 when the person comes to a complete stop= u^2 / 2 × 588= u^2 / 1176 m
The time taken, t = 38 ms = 0.038 s.
Now, we know that acceleration, a = (v - u) / t.
We can rearrange the above equation to find the final velocity, v. We get,v = u + at
Substituting the values, we get,588 = u + (588 × 0.038)u = 588 - (588 × 0.038)u = 567.816 m/s
Using the value of u, we can now find the distance traveled using the kinematic equation as, d = u^2 / 1176= (567.816)^2 / 1176≈ 273.42 m.
Therefore, the distance traveled by the person to come to a complete stop in 38 ms at a constant acceleration of 60 g is approximately 273.42 meters.
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what is the terminal velocity of blood
Answer:
25.1
Explanation:
Please answer this question correctly
20 push ups
hope thats correct^^
The pendulum consists of two slender rods AB and OC which have a mass of 3 kg/m. The thin plate has a mass of 12 kg/m2 . a) Determine the location ӯ of the center of mass G of the pendulum, then calculate the mass moment of inertia of the pendulum about z axis passing through G. b) Calculate the mass moment of inertia about z axis passing the rotation center O.
Answer:
The answer is below
Explanation:
a) The location ӯ of the center of mass G of the pendulum is given as:
\(y=\frac{0+(\pi*(0.3\ m) ^2*12kg/m^2*1.8\ m-\pi*(0.1\ m) ^2*12kg/m^2*1.8\ m)+0.75\ m*1.5\ m *3\ kg/m}{(\pi*(0.3\ m) ^2*12kg/m^2-\pi*(0.1\ m) ^2*12kg/m^2)+3\ kg/m^2*0.8\ m+3\ kg/m^2*1.5\ m} \\\\y=0.88\ m\)
b) the mass moment of inertia about z axis passing the rotation center O is:
\(I_G=\frac{1}{12}*3(0.8)(0.8)^2+ 3(0.8)(0.888)^2-\frac{1}{2}*(12)(\pi)(0.1)^2(0.1)^2 -(12)(\pi)(0.1)^2(1.8-\\0.888)^2+\frac{1}{2}*(12)(\pi)(0.3)^2(0.3)^2 +(12)(\pi)(0.3)^2(1.8-0.888)^2+\frac{1}{12}*3(1.5)(1.5)^2+\\3(1.5)(0.888-0.75)^2\\\\I_G=13.4\ kgm^2\)
c) The mass moment of inertia about z axis passing the rotation center O is:
\(I_o=\frac{1}{12}*3(0.8)(0.8)^2+ \frac{1}{3}* 3(1.5)(1.5)^2+\frac{1}{2}*(12)(\pi)(0.3)^2(0.3)^2 +(12)(\pi)(0.3)^2(1.8)^2-\\\frac{1}{2}*(12)(\pi)(0.1)^2(0.1)^2 -(12)(\pi)(0.1)^2(1.8)^2\\\\I_o=13.4\ kgm^2\)
How does solar weather affect Earth’s magnetosphere? Select the two correct answers.
It causes geomagnetic storms.
It generates auroras.
It develops solar wind.
It forms radiation belts.
Who was Dr. Shirley Jackson?
Answer:
she is an American physicist, and the eighteenth president of Rensselaer Polytechnic Institute. She is also the second African-American woman in the United States to earn a doctorate in physics
Which type of heat transfer takes place in gases by the movement of particles through a medium?
Answer: Convention
Explanation: Convention is pretty well known for being a process that transmits heat from one place to another place with the movements of heated particles. I got this answer from my notebook during my chemistry class.
Hope this answer helps!
PLZZ HELP
How many kg are there in 335 m
____ can be calculated if you know the distance that an object travels in one unit of time.
A.motion
B.meter
C.Rate
D.Speed
E.velocity
F.slope
G.refrence point
PLS HELP NOW !!!
Answer:
D.Speed
Explanation:
The speed of an object is the distance the object travels in one unit of time.
Speed can be calculated if you know the distance that an object travels in one unit of time, therefore the correct answer is option D.
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.
The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.
Thus, Speed can be calculated if you know the distance that an object travels in one unit of time, therefore the correct answer is option D.
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3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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PLEASE HELP
What is the change in internal energy if 80 J of thermal energy is released
from a system, and 30 J of work are done on the system? Use AU = Q-W.
Answer: Delta U = 30 - 80; -50 jules
Explanation:
The system is losing 80 J, but it is also gaining 30 J because the surroundings are doing work on it. So the net change in energy is -50 J
A car accelerates from 20 m/s to 30m/s in 10s
,draw velocity time graph to show cars motion.find the distance its travels by calculating the area under the graphing?
Answer:
250 m
Explanation:
Refer to the attachment for the graph. Here, we are asked to calculate the distance travelled.
⇒ Area under the graph = Distance travelled by the body
Let the distance travelled by the body be S. Area under the graph will be the area of the trapezium ABCD.Area of trapezium = ½ × Sum of parallel sides × Height
\( \twoheadrightarrow \quad \sf {S = \dfrac{1}{2}\times (AD + BC) \times OC} \\ \)
\( \twoheadrightarrow \quad \sf {S = \dfrac{1}{\cancel{2}}\times (10+30) \times \cancel{10}} \\ \)
\( \twoheadrightarrow \quad \sf {S = 1\times 50 \times 5} \\ \)
\(\twoheadrightarrow \quad \boxed{\red{\sf{ S = 250 \; m}}}\\\)
❝ Therefore, distance travelled by the body is 250 m. ❞
a copper wire has a radius of 1 [mm]. the wire is carrying a current of 1 [a] in the positive z direction. determine the velocity vector of the electrons inside the copper wire (hint: see the similar example in notes 3, as use the same parameters for the copper as in this example.)
The velocity vector of the electrons can be represented as:
v = v_d * z = v_d * (0, 0, 1)
where z is the unit vector in the positive z direction.
To determine the velocity vector of the electrons inside the copper wire,
we can use the drift velocity formula, which relates the drift velocity of electrons to the electric current and the density of electrons in a conductor.
The drift velocity can be calculated as:
v_d = I / (neA)
where I is the current,
n is the number of electrons per unit volume, e is the charge of an electron, and
A is the cross-sectional area of the wire.
For copper, n can be calculated as:
n = (8.5 x 10^28 electrons/m^3) * (density of copper / 63.54 g/cm^3)
With a wire radius of 1 mm, the cross-sectional area can be calculated as:
A = πr^2
= π * (1 x 10^-3 m)^2
So, plugging in the values, we have:
v_d = 1 A / (n * A)
= 1 A / (8.5 x 10^28 electrons/m^3 * π * (1 x 10^-3 m)^2)
The velocity vector of the electrons is in the same direction as the current, which is the positive z direction,
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An astronaut has a mass of 85 kg. The acceleration due to gravity at the surface of Earth is 9.8 m/s^2. The acceleration due to gravity at the surface of Earth's moon is 1.6 m/s^2. Calculate his weight on the Earth’s moon.
Answer: 136 Newtons (136N)
Explanation:
Newton's Law of Gravitation states that the gravitational force is proportional to the masses of the two objects, and their separation distance between them. The proportionality constant is called Newtons constant denoted as capital 'G':
\(F=GMm/r^2\)
Now, due to Newton's 2nd Law of motion, we know that a net force acting on an object causes an acceleration. We can also say that the force is:
\(F=ma\)
Setting both of these equations equal to each other, we get:
\(ma=GMm/r^2\)
The smaller 'm' will cancel giving that the acceleration is:
\(a=GM/r^2\)
This is the equation which gives the gravitational field created from a source mass 'M'. To find the weight, find the product between the test mass and the gravitational field created by the source mass:
\(Weight=mass*acceleration\)
\(W=ma\)
\(W=(85kg)(1.6m/s^2)\)
\(W=136N\)
The units are Newtons due to weight being a force.
A cat jumps horizontally from a 3.2 meter shelf at a velocity of 7m/s. How far from the base of the shelf does the cat land? At what velocity does the cat land? (Magnitude and Direction).
The position of a particle is r⃗ (t)=(3.0t2iˆ+5.0jˆ−6.0tkˆ)m. (a) Determine its velocity and acceleration as functions of time. (b) What are its velocity and acceleration at time t = 0?
Explanation:
It is given that,
The position of a particle is given by :
\(r(t)=(3t^2i+5j-6tk)\ m\)
(a) Velocity of a particle is given by :
\(v=\dfrac{dr(t)}{dt}\)
Putting values,
\(v=\dfrac{d}{dt}(3t^2+5-6t)\\\\v=(6ti-6k)\ m/s\)
The acceleration of the particle is given by :
\(a=\dfrac{dv}{dt}\\\\a=\dfrac{d}{dt}(6t-6)\\\\a=6i\ m/s^2\)
(b) At t = 0,
Velocity, v = 6k m/s
Acceleration, a = 6i m/s²
why is the world so small compared to the sun and jupider
The Sun appears smaller than the Earth from here on Earth, but that is only because the Earth is considerably closer to you than the Sun is. Jupiter due to its rapid revolution, which increases its diameter in the midsection.
What are the bodies of the solar system?Our solar system consists of the star, Sun, planets: Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune, and small planets such as Pluto.
While the Sun is 150 million kilometers away from where you are, you are on the surface of the Earth.
The planet is an oblate spheroid due to its rapid revolution, which increases its diameter in the midsection.
Therefore, Jupiter due to its rapid revolution increases its diameter in the midsection making it bigger as compared to the world, so it is believed small compared to the Sun and Jupiter.
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Based on the data, which statement describes the most reliable way to
encode and transmit data and tells why?
A. Digital waves are more reliable because they are less likely to
change when copied.
B. Analog waves are more reliable because they include a range of
values like the original.
C. Analog waves are more reliable because they are less likely to
change when copied.
D. Digital waves are more reliable because they are slightly different
from the original.
Answer:it’s A. right for ape x
Explanation:
Based on data, digital waves are more reliable because they are less likely to change when copied (Option A).
What is a wave?A wave is a periodic distortion capable of traveling through a suitable media (either air or water).
The waves can be classified according to their direction into transversal and perpendicular.In conclusion, based on data, digital waves are more reliable because they are less likely to change when copied (Option A).
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22
Carly mentions to her friends that her new scented oils have been helping heal her headaches. With no scientific evidence that this "aromatherapy"
actually works, her friends should caution her and tell her to be careful. What do Carly's friends think she may be diving into?
O A. astrology
OB. phrenology
OC. pseudoscience
O D. astronomy
(c) Friends think she may be diving into pseudoscience.
Friends of Carly speculate that she may be engaging in pseudoscience.
A claim, discovery, or explanatory framework lacks the objectivity required for scientific investigation when it is presented as pseudoscience. Pseudoscience can also result from research that is based on dubious theories, poor experimental layouts, or incorrect data.
A single assertion or claim that is purported to be supported by facts or science but breaks down when subjected to the test of reason is referred to as pseudoscience.
Another illustration of a pseudoscience is a complex system, such as astrology, that purports to explain how astronomical events influence and are affected by global events. Numerous bogus sciences, such as astrology, are largely risk-free.
The correct option is (c).
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I will mark you brainlist!!
How is primary succession different from secondary succession? Give an example of an event that may lead to primary succession.
Answer:
Primary Succession is defined as the type of ecological succession, which occurs or start from the barren, uninhabited and unoccupied areas, such as the newly formed pond, rock, dunes, etc., while such kind of succession, which occurs in the area where there was the existence of life previously but got abandoned due to natural disturbances like deforestation, natural calamities (flood, earthquake, tsunami), the field with no vegetation is known as Secondary Succession
Explanation:
Some examples of primary succession include the formation of a new ecosystem after a volcano, glacier outbursts, or a nuclear explosion. Some examples of secondary succession include succession after fire, harvesting, logging, or abandonment of land or the renewal after a disease outbreak
i hope this answer helps :)
A 0.45 kg football traveling at a speed of 22 m/s is caught by a stationary receiver. If the football comes to a rest in the receiver's arms, the magnitude of the impulse imparted to the receiver by the ball is
Answer:
0.9Ns
Explanation:
Impulse formula is expressed as;
Impulse = Ft = m(v-u)
Impulse = m(v-u)
m is the mass of football = 0.45kg
v is the final velocity = 22m/s
u is the initial velocity = 0m/s
Impulse = 0.45(22-0)
Impulse = 0.45 * 22
Impulse = 0.9Ns
Hence the magnitude of the impulse imparted to the receiver by the ball is 0.9Ns
Please answer these questions correctly (photo is attached) I’ll give brainliest
In Figure below, m₁=2.00kg and m₂-4.00kg. Consider the pulley to be frictionless. (a) If m₂ is released, what will its acceleration be? (b) What is the tension in the string? m₂ 55 m₂
(a) When m₂ is released, its acceleration will be approximately -3.27 m/s².
(b) The tension in the string is approximately -13.08 N.
To determine the acceleration of m₂ when it is released and the tension in the string, we need to consider the forces acting on the system.
(a) Acceleration of m₂:
Since the pulley is assumed to be frictionless, the tension in the string is the same on both sides of the pulley. We can consider the system consisting of m₁ and m₂ as one body. The net force acting on this system is the difference between the weight of m₁ and the weight of m₂:
Net force = m₁g - m₂g
Applying Newton's second law, F = ma, where F is the net force and a is the acceleration, we have:
m₁g - m₂g = (m₁ + m₂)a
Rearranging the equation to solve for the acceleration, we get:
a = (m₁g - m₂g) / (m₁ + m₂)
Substituting the given values, m₁ = 2.00 kg and m₂ = 4.00 kg, and the acceleration due to gravity, g = 9.8 m/s², we can calculate the acceleration:
a = ((2.00 kg)(9.8 m/s²) - (4.00 kg)(9.8 m/s²)) / (2.00 kg + 4.00 kg)
a = (19.6 N - 39.2 N) / 6.00 kg
a = -19.6 N / 6.00 kg
a = -3.27 m/s²
Therefore, when m₂ is released, its acceleration will be approximately -3.27 m/s². The negative sign indicates that the acceleration is in the opposite direction of the gravitational force.
(b) Tension in the string:
The tension in the string can be determined by considering the forces acting on m₂. The net force on m₂ is equal to its mass multiplied by its acceleration:
Net force = m₂a
Substituting the given values, m₂ = 4.00 kg and a = -3.27 m/s², we can calculate the tension:
Tension = (4.00 kg)(-3.27 m/s²)
Tension = -13.08 N
Therefore, the tension in the string is approximately -13.08 N. The negative sign indicates that the tension acts in the opposite direction of the weight of m₂.
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What are the magnitude and the direction of the electric field that will allow an electron to fall with an acceleration of 4.3 m/s2?
Answer:
Explanation:
The acceleration of an electron in an electric field is given by the equation:
a = qE/m
where a is the acceleration, q is the charge of the electron, E is the electric field, and m is the mass of the electron.
Given that the acceleration of the electron is 4.3 m/s^2, and the mass of the electron is 9.11 × 10^-31 kg, and the charge of the electron is -1.6 × 10^-19 C, we can solve for the electric field E:
E = ma/q
E = (4.3 m/s^2) × (9.11 × 10^-31 kg) / (-1.6 × 10^-19 C)
E = -2.44 × 10^4 N/C
The negative sign indicates that the direction of the electric field is opposite to the direction of the electron's motion. Therefore, the magnitude of the electric field required to accelerate an electron with an acceleration of 4.3 m/s^2 is 2.44 × 10^4 N/C and the direction is opposite to the direction of motion of the electron.
Help anyone
Please I don’t understand it at alll
Answer:
a) 24525 Newtons
b)240590.25 Joules
c)4009.8375 Watt
d)294300 Joules
Explanation:
a) Weight is a force, and can be calculated by multiplying mass by acceleration due to gravity. Earth's acceleration due to gravity is 9.81m/s/s. To find the water's weight, we multiply its mass (2500) by acceleration due to gravity.
W=mg
=(2500)(9.81)
=24525 Newtons
b) Work is calculated by multiplying force by distance. In this case, the force is the weight (as found in part a) and the distance is 16m.
W=fd
=(24525)(9.81)
=240590.25 Joules
c) Power is calculated by dividing the work by the time. In this case the work is our answer for part b and the time is sixty seconds.
P=w/t
=240590.25/60
=4009.8375 Watt
d) The first bit of part d tells us that (the waters potential energy)(0.75)=(electric energy). To find potential energy, multiply mass by acceleration due to gravity by height.
PE=mgh
=2500*9.81*16
=392400 Joules
Multiply by 0.75 to find electric energy: 294300 Joules
One of the fastest roller coasters (2000 kg) in the world is the Magnum XL - 200 at
Cedar Point Park in Sandusky, Ohio. This ride includes an initial vertical drop of 59.3 m.
Assume that the roller coaster has a speed of nearly zero as it crests the top of the hill.
a. If the track was frictionless, find the speed of the roller coaster at the bottom of
the hill.
The speed of the roller coaster at the bottom of the hill is 33.9 m/s.
The conservation of mechanical energy is used to determine the speed of the roller coaster at the bottom of the hill, as there is no friction. According to the law of conservation of energy, mechanical energy is constant at all points in a frictionless environment.Let's look at the equation below:PEg + KE = PEg + KEwhere PEg is gravitational potential energy and KE is kinetic energyThe kinetic energy is maximum and the gravitational potential energy is zero when the roller coaster is at the bottom of the hill. The gravitational potential energy is highest when the roller coaster is at the top of the hill, with its potential energy equal to its kinetic energy when it reaches the bottom of the hill.Initially, the roller coaster is at rest at the top of the hill. The gravitational potential energy of the roller coaster is transformed into kinetic energy as it descends the hill. We can calculate the speed of the roller coaster using the law of conservation of energy.Solution:Given,Height of the hill, h = 59.3 mGravitational acceleration, g = 9.8 m/s²Mass of roller coaster, m = 2000 kgWe need to find the speed of the roller coaster at the bottom of the hill, v.To begin, calculate the potential energy at the top of the hill.Potential energy at the top of the hill = mgh Where m is the mass of the roller coaster, g is the acceleration due to gravity, and h is the height of the hill.
The potential energy at the top of the hill is given by:PEg = mgh= 2000 kg × 9.8 m/s² × 59.3 m= 1.15 × 10⁶ JNow, let's figure out the velocity at the bottom of the hill.Using the conservation of energy, we can write,PEg = KE + KEwhere PEg is gravitational potential energy and KE is kinetic energyThe gravitational potential energy is equal to the kinetic energy.KE = PEg= 1.15 × 10⁶ JKE = 1/2 × mv²Where m is the mass of the roller coaster and v is the velocity of the roller coaster.Substituting the given values in the above equation, we get;1.15 × 10⁶ = 1/2 × 2000 × v²v² = (2 × 1.15 × 10⁶) / 2000v² = 1150v = √1150v = 33.9 m/s.
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