Calculate the simple interest on a loan of $9000 at an interest rate of 8% for 6 years? PLEASE HELP MEEE​

Answers

Answer 1

Answer:

Step-by-step explanation:

Rate = 8% = 8 / 100 = 0.08

Time (t) = 6 years

principal (P ) = 9000

i = P *r * t

i = 9000 * 0.08 + 6

i = 9000 * 0.48

i = 4320


Related Questions

5. Max and Evie are comparing the number of ride tickets they have for an amusement park. They notice that Evie has 4 less than three times the number of tickets that Max has. If the number of tickets Max has is represented by n, then which of the following represents the combined number of tickets Max and Evie have in terms of n?​

5. Max and Evie are comparing the number of ride tickets they have for an amusement park. They notice

Answers

Answer:

4n - 4

Step-by-step explanation:

3n-4 = the amount of tickets Evie has

n = the amount of tickets Mark has

3n - 4 + n = 4n - 4

The graph of a quadratic function with vertex (1,-1) is shown in the figure below. Find the domain and the range. Write your answers as inequalities, using or as appropriate. Or, you may instead click on "Empty set" or "All reals" as the answer.

Answers

The domain of the function is all real numbers and  range is  y ≥ -1.

Since the vertex is at (1,-1), the axis of symmetry is x = 1.

This means that the domain of the function is all real numbers.

To find the range, we need to consider the y-values of the graph. Since the vertex is the lowest point of the graph, the range must be all y-values greater than or equal to -1.

However, since the parabola opens upwards, there is no upper bound on the y-values.

Therefore, the range is given by y ≥ -1.

Hence, the domain of the function is all real numbers and  range is  y ≥ -1.

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Ace auto repairs needs a new mechanic so they placed a help wanted ad. the position posted job website charged $15 to post, plus $2.50 for each of the five lines and $8 for each additional line.

If x is the number of lines in the ad, write a piecewise function for the cost of the ad, c(x)

Answers

The piecewise function for the cost of the ad, denoted as c(x), where x represents the number of lines in the ad:

c(x) =

$15 + $2.50x if x ≤ 5

$15 + $12.50 + $8(x - 5) if x > 5

This function represents the total cost, c(x), based on the number of lines, x, in the ad. For x less than or equal to 5, the cost is $15 plus $2.50 per line.

For x greater than 5, there is a fixed cost of $15, an additional cost of $12.50 for the first 5 lines, and an extra $8 for each additional line beyond 5.

By using this piecewise function, Ace Auto Repairs can accurately calculate the cost of their help wanted ad based on the number of lines required, ensuring transparency and efficient financial planning.

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number that is not an irracional number​

Answers

Answer:

2

Step-by-step explanation:

Hope this helps

Find the eigenvalues λn and eigenfunctions yn(x) for the given boundary-value problem. (Give your answers in terms of n, making sure that each value of n corresponds to a unique eigenvalue.) y'' + (λ + 1)y = 0, y'(0) = 0, y'(1) = 0

Answers

λn = (nπ)^2 - 1, and the corresponding eigenfunction is y_n(x) = B sin(nπ x).

How do we calculate?

The general solution of the differential equation is of the form

y(x) = A sin(√(λ+1) x) + B cos(√(λ+1) x).

Applying the boundary condition y'(0) = 0, we have:

y'(x) = A√(λ+1) cos(√(λ+1) x) - B√(λ+1) sin(√(λ+1) x)

y'(0) = A√(λ+1) cos(0) - B√(λ+1) sin(0) = 0

Here  A = 0.

Applying  the boundary condition y'(1) = 0, we have:

y'(x) = - B√(λ+1) sin(√(λ+1) x)

y'(1) = - B√(λ+1) sin(√(λ+1)) = 0

Which means that √(λ+1) = nπ for n = 1, 2, 3, ...

In conclusiuon,  λn = (nπ)^2 - 1, and the corresponding eigenfunction is y_n(x) = B sin(nπ x).

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Suppose set s1 is [1, 2, 5] and set s2 is [2, 3, 6]. After s1.addAll(s2), s1 is __________.

Answers

After set s1.addAll(s2), s1 is [1, 2, 5, 2, 3, 6].

After performing the operation s1.addAll(s2) on sets s1 [1, 2, 5] and s2 [2, 3, 6], the set s1 would become[1, 2, 5, 2, 3, 6].

To determine the value of s1, the following steps has to be taken:

1. Start with sets s1 [1, 2, 5] and s2 [2, 3, 6].

2. Apply the addAll operation with set s2: [2, 3, 6]

3. Add each element from set s2 to set s1, while avoiding duplicates (since sets cannot have duplicate elements).

4. Therefore, suppose if set s1 is [1, 2, 5] and set s2 is [2, 3, 6] then, after s1.addAll(s2), the set s1 becomes [1, 2, 5, 2, 3, 6].

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2) A 100 cubic centimeter (c * m ^ 3) sample of soil has an initial weight of 225.1 gramsIt is oven dried at 105 deg * C to a constant weight of 220.0 gramsThe sample is then with water and has a weight of 234.6 grams. Next, the sample is then allowed to drain by gravity in an environment of 100% humidity and is reweighted at 222.4 grams. Assuming that 1c * m ^ 3 of water = 1 gram at 15.5°C:
a) Calculate the porosity;
b) Calculate the specific yield; 5y / (v/(Le)) c) Calculate the specific retention
d) Calculate the void ratio;
e) Calculate the initial moisture content;
f) Calculate the initial degree of saturation.

Answers

For the sample of soil given a) the porosity is 100.4%; b) the specific yield is 12.2%; c) the specific retention is 14.6%; d) the void ratio is 0.5342; e) the initial moisture content is 2.3%; and f) the initial degree of saturation is 41.97%.

a) The porosity of soil can be defined as the ratio of the void space in the soil to the total volume of the soil.

The total volume of the soil = Initial volume of soil = 100 c.m³

Weight of water added to the soil = 234.6 g – 220 g = 14.6 g

Volume of water added to the soil = 14.6 c.m³

Volume of soil occupied by water = Weight of water added to the soil / Density of water = 14.6 / 1 = 14.6 c.m³

Porosity = Void volume / Total volume of soil

Void volume = Volume of water added to the soil + Volume of voids in the soil

Void volume = 14.6 + (Initial volume of soil – Volume of soil occupied by water) = 14.6 + (100 – 14.6) = 100.4 c.m³

Porosity = 100.4 / 100 = 1.004 or 100.4%

Therefore, the porosity of soil is 100.4%.

b) Specific yield can be defined as the ratio of the volume of water that can be removed from the soil due to the gravitational forces to the total volume of the soil.

Specific yield = Volume of water removed / Total volume of soil

Initially, the weight of the oven dried soil is 220 g. After allowing it to drain by gravity, the weight of soil is 222.4 g. Therefore, the weight of water that can be removed by gravity from the soil = 234.6 g – 222.4 g = 12.2 g

Volume of water that can be removed by gravity from the soil = 12.2 c.m³

Specific yield = 12.2 / 100 = 0.122 or 12.2%

Therefore, the specific yield of soil is 12.2%.

c) Specific retention can be defined as the ratio of the volume of water retained by the soil due to the capillary forces to the total volume of the soil.

Specific retention = Volume of water retained / Total volume of soil

Initially, the weight of the oven dried soil is 220 g. After adding water to the soil, the weight of soil is 234.6 g. Therefore, the weight of water retained by the soil = 234.6 g – 220 g = 14.6 g

Volume of water retained by the soil = 14.6 c.m³

Specific retention = 14.6 / 100 = 0.146 or 14.6%

Therefore, the specific retention of soil is 14.6%.

d) Void ratio can be defined as the ratio of the volume of voids in the soil to the volume of solids in the soil.

Void ratio = Volume of voids / Volume of solids

Initially, the weight of the oven dried soil is 220 g. The density of solids in the soil can be calculated as,

Density of soil solids = Weight of oven dried soil / Volume of solids

Density of soil solids = 220 / (100 – (14.6 / 1)) = 2.384 g/c.m³

Volume of voids in the soil = (Density of soil solids / Density of water) × Volume of water added

Volume of voids in the soil = (2.384 / 1) × 14.6 = 34.8256 c.m³

Volume of solids in the soil = Initial volume of soil – Volume of voids in the soil

Volume of solids in the soil = 100 – 34.8256 = 65.1744 c.m³

Void ratio = Volume of voids / Volume of solids

Void ratio = 34.8256 / 65.1744 = 0.5342

Therefore, the void ratio of soil is 0.5342.

e) Initial moisture content can be defined as the ratio of the weight of water in the soil to the weight of oven dried soil.

Initial moisture content = Weight of water / Weight of oven dried soil

Initial weight of soil = 225.1 g

Weight of oven dried soil = 220 g

Therefore, the weight of water in the soil initially = 225.1 – 220 = 5.1 g

Initial moisture content = 5.1 / 220 = 0.023 or 2.3%

Therefore, the initial moisture content of soil is 2.3%.

f) Initial degree of saturation can be defined as the ratio of the volume of water in the soil to the volume of voids in the soil.

Initial degree of saturation = Volume of water / Volume of voids

Volume of water = Weight of water / Density of water

Volume of water = 14.6 / 1 = 14.6 c.m³

Volume of voids in the soil = 34.8256 c.m³

Initial degree of saturation = 14.6 / 34.8256 = 0.4197 or 41.97%

Therefore, the initial degree of saturation of soil is 41.97%.

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The table shows the high temperature on the moon during the day and the overnight low temp.

time of day | temperature
day | 253
night | -387

what is the range between the moons minimum temp in degrees fahrenheit?

Answers

The range between the moon's minimum and maximum temperature in degrees Fahrenheit is 640°F

From the question, we have

Time of Day     Temperature

   Day                 253°F

   Night              -387°F

the moon's minimum temperature =  -387°F

and maximum temperature =  253°F

range = 253 - (-387) =  640°F

Subtraction:

Subtraction represents the operation of removing objects from a collection. The minus sign signifies subtraction −. For example, there are nine oranges arranged as a stack (as shown in the above figure), out of which four oranges are transferred to a basket, then there will be 9 – 4 oranges left in the stack, i.e. five oranges. Therefore, the difference between 9 and 4 is 5, i.e., 9 − 4 = 5. Subtraction is not only applied to natural numbers but also can be incorporated for different types of numbers.

The letter "-" stands for subtraction. Minuend, subtrahend, and difference are the three numerical components that make up the subtraction operation. A minuend is the first number in a subtraction process and is the number from which we subtract another integer in a subtraction phrase.

Complete question:

The table shows the high temperature on the moon during the day and the overnight low temperature.

Time of Day Temperature

Day 253°F

Night –387°F

What is the range between the moon's minimum and maximum temperature in degrees Fahrenheit?

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Which expressions are polynomials? Select each correct answer. x2−x√+2 2 + s 4x³ + y​

Answers

Answer:

Answers are

Y

2+s

4x^3+y

Step-by-step explanation:

The mean mass of five men is 76 kg. The masses of four of the men are 72 kg, 74 kg, 75 kg and 81 kg. What is the mass of the fifth man

Answers

Answer:

78kg

Step-by-step explanation:

76×5= 380kg

380-72-74-75-81= 78kg

(72+74+75+81+x)/5=76
x=(76.5)-302
x=380-302=78

Triangle QRS triangle TUV.
Q
117⁰
V
30°
R
S
What is the measure of LQ and the measure of LS?
U
T

Answers

Answer: Since triangle QRS and triangle TUV are both triangles, we can use the fact that the sum of the interior angles in a triangle is 180 degrees.

In triangle QRS, the measure of angle Q is 117 degrees and the measure of angle R is 180 - 117 = 63 degrees. The measure of angle S is 180 - 63 = 117 degrees, since the angles in a triangle add up to 180 degrees.

In triangle TUV, the measure of angle T is 180 - 30 = 150 degrees and the measure of angle U is 30 degrees. The measure of angle V is 180 - 150 = 30 degrees, since the angles in a triangle add up to 180 degrees.

The measures of LQ and LS can be found using the fact that the exterior angle of a triangle is equal to the sum of the measures of the two interior angles that are not adjacent to it.

The measure of LQ is equal to the sum of the measures of angles R and T:

LQ = 63 + 150 = 213 degrees

The measure of LS is equal to the sum of the measures of angles Q and U:

LS = 117 + 30 = 147 degrees

So the measure of LQ is 213 degrees and the measure of LS is 147 degrees.

Step-by-step explanation:

explain the error a problem states that Ursula earns $9 per hour to write an expression that tells you how much money that Ursula earns for H hours. Joshua 9 / h and Sarah wrote 9h who's expression is correct and why

Answers

We will have that Sarah's function is the correct one, since each hour she will get $9, then when we multiply will give us the amount of money she makes in the number of hours.

H = 9h

Need help I don't understand!!! ( i-ready math )

Need help I don't understand!!! ( i-ready math )

Answers

Answer:

bottom

Step-by-step explanation:

The other ones have only one answer while the last one has multiple

I would appreciate help without guessing :)

I would appreciate help without guessing :)

Answers

Answer:

a) \(\sqrt{56\) → Definitely not undefined because 56 is a positive real number

b) \(-\sqrt{56\) → Definitely not undefined because 56 is a positive real number (and the negative sign is not under the square root)

c) \(\sqrt{-56\) → Definitely undefined because -56 is a negative number

__

We know that there is no real square root of a negative number because nothing multiplied by itself results in a negative number.

__

d) \(\sqrt h\) → Could be undefined because we don't know the value of \(h\); it could be positive or negative

e) \(-\sqrt {h\) → Could be undefined because we don't know the value of \(h\); it could be positive or negative (and the negative sign doesn't affect this because it is outside the square root)

f) \(\sqrt{-h\) (when \(h\) is positive) → Definitely undefined because the value inside of the square root is negative (a negative times a positive is a negative)

Definitely not underfined

a set of eight cards was labled m, u, t, i, p, l, y. what is the sample space for choosing one card

Answers

The sample space for choosing one card from the set of eight cards labeled m, u, t, i, p, l, y is 8.

What is sample space?

An assortment or set of potential results from a random experiment make up a sample space. With the letter "S," the sample space is denoted. Events are a subset of the possible results of an experiment. Depending on the experiment, a sample space could have several different outcomes. Discrete sample spaces, often known as finite sample spaces, are those that have a finite number of outcomes.

The sample space for choosing 1 card is given as:

Sample space = 8C1 = 8! / (1!)(8 - 1)!

Sample space = 8.

Hence, the sample space for choosing one card from the set of eight cards labeled m, u, t, i, p, l, y is 8.

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50 coins all dimes and quarters total is 10.25 how many dimes?

Answers

Answer:

You can do these "in your head" like this:

50 dimes would be $5.00

Each quarter adds 15 cents.

10.25 - 55.00 = $5.25 added

Step-by-step explanation:

525/15 = 35 quarters

--> 15 dimes

==========================

or,

d + q = 50

10d + 25q = 1025

etc

Mrs. Robertson is preparing manipulatives for her math class. Each student will receive a plastic cup with 20 two-color counters. The total
number of two-color counters, c that Mrs. Robertson needs varies directly as the number of students, S.
Draw a graph showing the proportional relationship between c and s.

Answers

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The line on the graph showing the number of counters (c) for s students will have a slope of 20.

Mrs. Robertson is preparing manipulatives for her math class. Each student will receive a plastic cup

Define the Ackermann function called ackermann in Racket. • Define the bind and lookup functions for association lists, as we discussed in class. Recall that an association list in Racket is just a list of pairs and cach pair contains a key and a value. - (bind k v al) returns a new association list, which is the result of adding a new entry (k,v) to the beginning of asso- ciation list al. - (lookup k al) returns the value for key k in al if there is an entry for k and returns #f otherwise. • Define a global variable al for the association list used in ackermann mem. (define al '() n .

Answers

In this modified version of the ackermann function, we first check whether the value of (m, n) has already been computed and stored in the association list al. If it has, we simply return the stored value. Otherwise, we compute the value using the original definition of the Ackermann function, and store it in al using the bind function.

The Ackermann function is a recursive function that takes two non-negative integers as input and returns a non-negative integer as output. It is defined as follows:

(define (ackermann m n)

 (cond ((= m 0) (+ n 1))

       ((= n 0) (ackermann (- m 1) 1))

       (else (ackermann (- m 1) (ackermann m (- n 1))))))

The bind and lookup functions for association lists can be defined as follows:

(define (bind k v al)

 (cons (cons k v) al))

(define (lookup k al)

 (cond ((null? al) #f)

       ((equal? k (caar al)) (cadar al))

       (else (lookup k (cdr al))))).

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The ackermann function is a recursive version of Ackermann. Takes parameters m and n to recursively calculate result – if m is 0, add 1 to n. If n=0, use recursion to call ackermann with m-1 and n=1. Recursively call Ackermann with m-1 and n-1.

What is the  Ackermann function?

The Ackermann function is a mathematical concept that is defined and explained on the Wolfram MathWorld website.

The Ackermann function is a clear instance of a computable total function that is not primitive recursive, serving as evidence against the widespread idea in the early 1900s that all computable functions were necessarily primitive recursive.

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see other part below

Define a global variable al for the association list used in ackermann mem. (define al '() n . Finally, define ackermann mem. When given n and n, it checks whether there is an entry for key (m n) in al; note this asso- ciation list maps a pair (n n) to the result of (ackermann n n). If there is, it returns the value in the entry; if not, it invokes (ackermann nn), adds the entry ((n n) (ackermann n n) to the association list, and returns (ackermann nn). Notes: – To distinguish the two cases in ackermann mem, add the fol- lowing display command for the case when the input (m n) is in the current association list. It displays the string on screen. (display 'memoization hit \n'') – To add an entry to al, you will have to use set! to modify the global variable al. This has the side effect of modifying al so that it is visible to the next invocation of ackermann mem. - You will also need to use the sequencing construct in Racket. In particular, (begin en e2) evaluates el (which usually has some side effect) and then evaluates e2; the value of e2 becomes the value of (begin el e2). For example, (begin (display ''memoization hit \n'') (+ 1 2)) The example displays the message and returns 3.

Define the Ackermann function called ackermann in Racket. Define the bind and lookup functions for association
Define the Ackermann function called ackermann in Racket. Define the bind and lookup functions for association

Fill in the blank.

|3.3| = ____

Answers

Answer:

it stays the same

Step-by-step explanation:

if it was -3.3 then it would change to 3.3 but because it is already in the positives it stays a positive plz double chesk if needed tho

Answer:

\(3.3\)

Step-by-step explanation:

Absolute value expresses the distance of a number from 0.

For this reason, no matter if the number is negative or positive, the absolute value of it will always be positive.

In this case, it is simply \(|3.3|=3.3\).

How to simplify 1,024,000 : 360,000 : 180,000?

Answers

The solution of the given expression is,

⇒ 256 : 90 : 45

What is mean by Ratio?

A ratio indicates how many times one number contain in another number. The ratio of two number is written as x : y, which is equivalent to x/y. Where, x and y are individual amount of two quantities. And, Total quantity gives after combine as x + y.

Given that;

The ratios are,

⇒ 1,024,000 : 360,000 : 180,000

Now,

We can simplify the ratio as;

⇒ 1,024,000 : 360,000 : 180,000

Divide by 1000;

⇒ 1,024 : 360 : 180

Divide by 4;

⇒ 256 : 90 : 45

Thus, The solution of the given expression is,

⇒ 256 : 90 : 45

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How do you solve log equations?

Answers

We can easily equalize the arguments in an equation if it has a logarithm with the same base on both sides.

Step 1: Isolate a base-identical logarithmic expression on both sides of the problem using the exponentiation rules.

Step 2: Equip the arguments with one another.

Step 3. Finally, resolve the resulting equation.

Step 4: Verify your conclusions.

The logarithm of a number is the power of 10 that must be increased in order to equal that number. Simple examples include:

\(10^2\) = 100 , therefore log100 = 2

\(10^3\) = 1000, therefore log1000 = 3

log200 = 2.301 (between log100 and log1000)

Mathematicians discover that the following statements are constant:

log(a×b) = loga + logb

log(ab) = loga - logb

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HELP!!!!!!!!!!
Write in slope-intercept form an equation of the line that passes through the point (r,p) with slope q.
The equation is y=0

Answers

Answer:

y=qx

Step-by-step explanation:

*Note to think about The Slope Intercept equation is y=mx+b, where m is the slope, b is the y-int, and x,y is an ordered pair on the line.

1. Here the slope is q, and the y-intercept is 0.

2. Now plug in the known variables in for the unkowns

y=qx+0

3. we can take out the zero because anything plus/minus zero is itself, so the answer is:

y=qx

richard cuts a $ 4\frac{1}{2} ~\text{ft} \times 7\frac{1}{2} ~\text{ft} \times 11\frac{1}{4}~ \text{ft}$ rectangular prism into congruent cubes without any part of the prism leftover. if he makes the cubes as large as possible, how many will he produce?

Answers

If he makes the cubes as large as possible, the maximum number of cubes is equal to 900 cubes.

How to determine the number of cubes?

In order to determine the number of cubes that would be produced by Richard when the rectangular prism is cut into congruent cubes without any part of the rectangular prism leftover, we would make the edges of the cube 100 times larger and then evaluate:

Length of cube = 4 1/2 ft × 100 = 450 feet.Breadth of cube = 7 1/2 ft × 100 = 750 feet.Height of cube = 11 1/4 ft × 100 = 1125 feet.

Note: The greatest common factor (GCF) of the dimensions above is 75.

Next, we would divide each of the dimension by 75:

Length of cube = = 450/75 = 6 feet.

Breadth of cube = 750/75 = 10 feet.

Height of cube = 1125/75 = 15 feet.

Therefore, the maximum number of cubes is given by:

Maximum number of cubes = 6 × 10 × 15

Maximum number of cubes = 900 cubes.

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Complete Question:

Richard cuts a 4 1/2 ft × 7 1/2 ft × 11 1/4 ft rectangular prism into congruent cubes without any part of the prism leftover. If he makes the cubes as large as possible, how many will he produce?

In each of the following, list three terms that continue the arithmetic or geometric sequences. Identify the sequences as arithmetic or geometric. a. 2,6,18,54,162 b. 1,11,21,31,41 c. 13,19,25,31,37 a. The next three terms of 2,6,18,54,162 are 486,1458 , and 4374 . (Use ascending order.) Is the sequence arithmetic or geometric? A. Geometric B. Arithmetic b. The next three terms of 1,11,21,31,41 are, , , and , (Use ascending order.)

Answers

(a) Next three terms of the series 2, 6, 18, 54, 162 are 486, 1458, 4374.

And the series is Geometric.

(b) Next three terms of the series 1, 11, 21, 31, 41 are 51, 61, 71.

The given series (a) is: 2, 6, 18, 54, 162

So now,

6/2 = 3; 18/6 = 3; 54/18 = 3; 162/54 = 3

So the quotient of the division of any term by preceding term is constant. Hence the given series (a) 2, 6, 18, 54, 162 is Geometric.

Hence the correct option is (B).

The next three terms are = (162 * 3), (162 * 3 * 3), (162 * 3 * 3 * 3) = 486, 1458, 4374.

The given series (b) is: 1, 11, 21, 31, 41

11 - 1 = 10

21 - 11 = 10

31 - 21 = 10

41 - 31 = 10

Hence the series is Arithmetic.

So the next three terms are = 41 + 10, 41 + 10 + 10, 41 + 10 + 10 + 10 = 51, 61, 71.

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what is 8 1/3x6 3/4=

Answers

Answer:

I think it is 56.25 not sure but try it

Answer:

56.25 or 56\(\frac{1}{4}\)

Step-by-step explanation:

First:

Convert any mixed numbers to fractions.

Then your initial equation becomes:

                       \(\frac{25}{3}\) × \(\frac{27}{4}\)

Applying the fractions formula for multiplication,

                       \(\frac{25}{3}\) × \(\frac{27}{4}\)

                          \(\frac{675}{12}\)

Simplifying 675/12, the answer is

                         56\(\frac{1}{4}\)

Mike plans to train for a race by running 8 miles each day for 15 days. He will run at an average speed of 6 miles per hour. At that rate, what is the total number of hours Mike will spend running?

Answers

20 hours because he runs 80 minutes per day

Joaquin wants to make his famous chocolate chip cookies to bring to his friend's birthday party. the original recipe serves 5 people and requires one quarter of a cup of butter, but he needs it to serve 28 people. how many cups of butter will he need? 2 and one fourth cups 1 and one fifth cups 1 and two fifths cups 1 and one fourth cups

Answers

Joaquin will need 1 and two fifths cups to make his famous chocolate chip cookies for his friend's birthday party

To solve this problem we will use a rule of three with the problem information:

5 people-------- 1/4 cup of butter

28 people -------- x

Applying the rule of three we get:

x = ( 28 people * 1/4 cup of butter) / 5 people

x = 1,4 cup of butter

x = 1 + 2/5 cup of butter = 1 and two fifths cups

What is rule of three?

It describes the proportionality of 3 known data and an unknown data. When you have more than 3 known facts that are involved in the proportionality, it is known as a compound rule. The rule of three is also known as a direct proportions.

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Which of the following is NOT true about similar figures?

a. Similar figures always have the same shape.

b. Similar figures have always the same size.

c. similar figures have corresponding angles that are always congruent.

d. Similar figures have corresponding sides that are always proportional.

Answers

Answer:

b. Similar figures have always the same size. is a false statement.

since size differs.

The statement that is NOT true about similar figures is: b. Similar figures have always the same size.

What are Similar Figures?

Figures that are similar to each other have corresponding angles that are congruent but have corresponding sides that are proportional.

Similar figures have the same shape but different sizes.

Thus, the statement that is NOT true about similar figures is: b. Similar figures have always the same size.

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in exercises 27 and 28, find one real root of the equation by inspection. then use descartes' rule to show that there are no other real roots

Answers

We can conclude that the equation has exactly one real root (namely, x = 0) and two complex conjugate roots.

What is the quadratic equation?

The solutions to the quadratic equation are the values of the unknown variable x, which satisfy the equation. These solutions are called roots or zeros of quadratic equations. The roots of any polynomial are the solutions for the given equation.

I can give an example to demonstrate how to use inspection and Descartes' rule to find a real root of an equation and show that there are no other real roots.

Consider the equation x³ - 3x² + 2x = 0. By inspection, we can see that x = 0 is a real root of the equation since the left-hand side of the equation evaluates to 0 when x = 0.

To use Descartes' rule, we need to count the number of sign changes in the coefficients of the polynomial f(x) = x³ - 3x²  + 2x.

There are two sign changes: from positive to negative in the coefficient of x² and from negative to positive in the constant term.

Therefore, according to Descartes' rule, the equation has either two or zero positive real roots.

Next, we need to count the number of sign changes in the coefficients of f(-x), which is obtained by replacing x with -x in f(x).

We have f(-x) = -x³ - 3x² - 2x, which has one sign change: from negative to positive in the coefficient of x².

Therefore, according to Descartes' rule, the equation has either one or three negative real roots.

Since the total number of positive and negative real roots must add up to the degree of the polynomial (which is 3 in this case),

Hence, we can conclude that the equation has exactly one real root (namely, x = 0) and two complex conjugate roots.

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Which expression is equivalent to the given expression?
232 – 14% + 24

OA 2(x – 3)(x - 4)
OB. 263 - 8) (3 + 3)
OC. (2.1 – 12)(x - 2)
OD. 2(x - 5)(3 – 2)

Answers

The answer would be the last one I think
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