Calculate the mass of 45.0 L of NH3 at 57.0° C and 900. mm Hg.

Use the Ideal Gas Law formula and here are values for R:

8.134 (L * kPa)/(mol * K)

0.0821 (atm * L)/(mol * K)

62.364 (L * mmHg)/(mol * K)

Include the following with your answer:

Which Gas Law constant did you use? Why?
The numerical answer to the question.
An explanation of the correct number of significant figures you will use for the numerical answer.

The model shown should demonstrate why planets do not end up going into the sun as follows: The planets move too fast to go into the sun. (option A).

Planets are the bodies that orbit round the sun. The planets are seven in number as follows:

According to this question, a student looks at an animated model of the planets orbiting the sun. In reality, this planets do not go into the sun because they are far away from the sun.

The Earth as a planet for example is not moving fast enough to escape the sun's gravity and leave the solar system, but it is going too fast to be pulled into the sun. Therefore, it keeps going around and around in an orbital manner.

Therefore, the model shown should demonstrate why planets do not end up going into the sun as follows: The planets move too fast to go into the sun.

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Answer:

D

Explanation:

I have a crush on the same and I

The correct answer to the given question is option c) Metals.

What were the materials used during the 1960s?

The materials used during the 1960s included metals, ceramics, glasses, semiconductors, polymers, and elastomers.

The 1960s were a period of significant technological advances.

A number of new and innovative materials emerged during this time that would shape the world for decades to com. Metals were the second most used material during the 1960s. During this time, there was significant demand for materials that could withstand high temperatures and pressures, as well as resist wear and tear and corrosion .Metals were used for a wide range of applications, including the construction of aircraft, automobiles, and other machinery.

They were also used in the production of electronic components, such as resistors and capacitors, and for the manufacture of a wide range of consumer goods, from kitchen utensils to jewellery. Metals remain a critical material in today's world, with a wide range of applications in industries ranging from aerospace and automotive to electronics and construction.

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The molar mass of h2x is 222.22 g/mol

H2X + 2NaOH  → Na2X + 2H2O

Mole NaOH = concentration × volume

                    = 0.450 × 44.2 × \(10^{-3}\)

                    = 0.01989mol

Mole H2X = 0.01989 / 2 = 0.0099mol

H2X and NaOH has 1 : 2 molar ratio

Molar mass = mass / mole =2.20/0.0099 = 222.22 g/mol

A chemical compound's molar mass is calculated by dividing its mass by the number of moles measured in moles that make up the sample of that compound. In contrast to molecular properties, a substance's molar mass is a bulk property. The comp0und is present in many different forms, each with a different mass as a result of the isotopes. The mlar mass represents the average of these masses. The molar mass is most frequently calculated from the standard atomic weights and is a function of the relative abundance of the constituent atoms' isotopes on Earth. It is thus a terrestrial average. The conversion betwen a substance's mass and amount can be done using the molar mass.

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Answer:

Glucose has a chemical formula of: C6H12O6 That means glucose is made of 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms

Explanation:

To determine the value of ∆Hrxn for the reaction, we can use the equation:

∆Hrxn = q / n

where q is the heat of the reaction, n is the number of moles of reactants, and ∆Hrxn is the change in enthalpy of the reaction.

We can use the equation for calculating heat:

q = mc∆T

where q is the heat, m is the mass of the solution, c is the specific heat of the substance, and ∆T is the change in temperature.

The mass of the solution is equal to the volume of the solution times the density:

m = V * d

Plugging this equation into the equation for calculating heat, we get:

q = (V * d) * c * ∆T

We can use the values given in the problem to solve for q:

q = (0.200 L * 1.00 g/mL) * (4.18 J/g°C) * (23.48°C - 22.15°C)

q = 4.32 J

To determine the value of ∆Hrxn, we need to know the number of moles of reactants. The concentration of the HCl solution is 0.2 M, so the number of moles of HCl is:

n = (0.200 L) * (0.200 mol/L) = 0.040 mol

Plugging this value into the equation for ∆Hrxn, we get:

∆Hrxn = q / n = (4.32 J) / (0.040 mol) = 108 J/mol

Therefore,  ∆Hrxn=108 J/mol

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Answer:

b

Explanation:

This means that it takes more energy or heat to increase water's temperature than it does for most other substances. The specific heat of water is greater than that of dry soil, therefore water both absorbs and releases heat more slowly than land.

: PM2.5 is defined as the mass concentration of particles in the air less than or equal to 2.5 micrometers in diameter.Question 15: False, carbon dioxide (CO2) is not considered a criteria air pollutant.

Question 16: The closest answer is 50%, but the exact percentage is not provided in the question.Question 17: The term "photochemical smog" is most synonymous with ozone (O3), which is a criteria air pollutant.Question 18: True, attainment of ambient air quality standards requires that measured concentrations at all monitoring stations within an air district are below ambient air standards.

Question 14 asks about the definition of PM2.5. PM2.5 refers to particulate matter with a diameter less than or equal to 2.5 micrometers. It represents the mass concentration of particles suspended in the air, which are small enough to be inhaled into the respiratory system and can have adverse health effects.

Question 15 states whether carbon dioxide (CO2) is a criteria air pollutant. Criteria air pollutants are a set of pollutants regulated by environmental agencies due to their detrimental impact on air quality and human health. However, carbon dioxide is not considered a criteria air pollutant because it does not directly cause harm to human health or the environment in the same way as pollutants like ozone or particulate matter.

Question 16 asks about the percentage of carbon monoxide (CO) emissions from mobile sources in Santa Clara County. While the exact percentage is not provided in the question, the closest answer option is 50%. However, it is important to note that the precise percentage may vary depending on specific local conditions and emissions sources.

Question 17 inquires about the criteria air pollutant most synonymous with the term "photochemical smog." Photochemical smog is primarily associated with high levels of ground-level ozone (O3). Ozone is formed when nitrogen oxides (NOx) and volatile organic compounds (VOCs) react in the presence of sunlight, creating a hazy and polluted atmospheric condition.

Question 18 addresses the concept of "attainment" of ambient air quality standards. To achieve attainment, measured concentrations of pollutants at all monitoring stations within an air district must be below the established ambient air quality standards. This ensures that the air quality in the given area meets the required standards for protecting human health and the environment.

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Answer:

An object that has a higher density than the liquid it's in will sink

Explanation:

hopefully I helped

Explanation:

An acid is a substance that ionizes to produce excess hydrogen ion in solutions.

Answer:

the answer is i think it's b

Explanation:

Potassium is a chemical element with atomic number 19 which means there are 19 protons and 19 electrons in the atomic structure12.

An atom of the most common isotope of potassium has a nucleus composed of 19 protons and 20 neutrons3.

The nucleus of a neutral potassium atom is surrounded by 19 electrons3.

Key words

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In this question, we have to find the mass of Mn3(PO4)4, we will be using the molar mass of the compound, which is 544.7g/mol

544.7g = 1 mol

x grams = 3 moles

x = 1634 grams of Mn3(PO4)4

Answer:

lithium, and sodium can be cut with a knife

Answer:

Basically, the more hot the state is, the more kinetic energy it will have. This means that answer D. would be right, as it goes from coldest to hottest states!

Answer:

The answer is D. solid, liquid, gas, plasma

Explanation:

a. There are four peaks in the chromatogram due to the presence of four different dyes. b. A gradient elution would result in sharper and more distinct peaks for each dye

a. There are four tops in the chromatogram since there are four distinct colors present in the example. Each pinnacle compares to an alternate color with an alternate maintenance time, which is the time it takes for the color to go through the HPLC section and be distinguished by the identifier.

b. In the event that a rising slope of water (i.e., expanded extremity of the portable stage) were utilized after some time, the chromatogram would show a more isolated and settled top for each color. This is on the grounds that the more polar versatile stage would assist with isolating the colors all the more really as they travel through the section, bringing about a higher goal and more clear partition between the pinnacles. The subsequent chromatogram would show more honed and more unmistakable tops, with each pinnacle addressing a solitary color in the example. The inclination elution would take more time than the isocratic technique, yet would yield more exact and itemized results.

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Answer: Fractional Distallation

Explanation: this technique relies on the compounds of the mixture. This is able to happen when there is diffrent boilling points.

The rate of reaction of calcium carbonate with hydrochloric acid likely depends on the concentration of hydrochloric acid, surface area of calcium carbonate, temperature, and the presence of a catalyst.

The rate of reaction of calcium carbonate (chalk) with hydrochloric acid likely depends on the following factors:

1. Concentration of hydrochloric acid: Higher concentrations of hydrochloric acid generally result in a faster reaction rate.

2. Surface area of calcium carbonate: Finely powdered calcium carbonate provides more surface area for the reaction, leading to a faster reaction rate compared to larger pieces or chunks.

3. Temperature: Higher temperatures increase the kinetic energy of the reactant particles, causing them to move faster and collide more frequently, resulting in a faster reaction rate.

4. Presence of a catalyst: The addition of a catalyst can increase the rate of the reaction by providing an alternative reaction pathway with lower activation energy.

Therefore, the rate of reaction of calcium carbonate with hydrochloric acid likely depends on the concentration of hydrochloric acid, surface area of calcium carbonate, temperature, and the presence of a catalyst. These factors influence the frequency of collisions and the energy available for successful collisions, affecting the rate at which the reaction occurs.

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The firm should order 65 units this week to meet the order-up-to level of 80 units and cover the backordered units.

To determine how many units a firm should order this week given an order-up-to level of 80 units, no on-hand units, 20 on-order units, and 5 backordered units, follow these steps:

1. Calculate the total units needed: Order-up-to level (80) minus on-hand units (0) equals 80 units needed.
2. Subtract the on-order units from the total units needed: 80 units needed minus 20 on-order units equals 60 units still required.
3. Account for the backordered units: 60 units still required plus 5 backordered units equals 65 units.

So, the firm should order 65 units this week to meet the order-up-to level of 80 units and cover the backordered units.

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Answer:

30 neutrons

Explanation:

neutrons = atomic mass - atomic number

neutrons = 56 - 26 = 30

The pressure of the gas that has 3.00mol sample of CO2(g) is in a rigid 6.00L container at 400°C is 27.6atm.

The pressure of a gas can be calculated using the ideal gas law equation as follows:

PV = nRT

Where;

P × 6 = 3 × 0.0821 × 673

6P = 165.76

P = 165.76 ÷ 6

P = 27.6atm

Therefore, the pressure of the gas that has 3.00mol sample of CO2(g) is in a rigid 6.00L container at 400°C is 27.6atm.

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Answer:

Examples of chemical changes are burning, cooking, rusting, and rotting. Examples of physical changes are boiling, melting, freezing, and shredding. Often, physical changes can be undone, if energy is input.

Hope this helped.

Answer:

376.56

Explanation:

using the formula q=mcΔT, where m=15g, C=4.18J/g°C and ΔT=6.0°C

Actually, no. While their mass may be the same (1kg), the volume of lead is a lot smaller than that of feathers. As there is the same mass stuffed in a smaller space, it must be denser. The density of water is 1 g/cm3, so if the density of the lead is more than 1g/cm3, it has to sink

The two processes of formation and decomposition of ozone are :

a)  \(O_{2}\) + UV light -> 2O
  O + \(O_{2}\) ->  \(O_{3}\)

b) \(O_{3}\) + UV light ->  \(O_{2}\) + O

To describe the chemical processes that lead to the natural balance between decomposition and formation of stratospheric ozone, we must consider the absorption of solar energy by ozone molecules.

The chemical processes involved in this natural balance are as follows:

1. Formation of ozone: Ozone is formed when oxygen molecules ( \(O_{2}\)) absorb ultraviolet (UV) light from the sun. This process, called photodissociation, causes the oxygen molecule to break into two individual oxygen atoms (O). These highly reactive oxygen atoms then combine with other oxygen molecules ( \(O_{2}\)) to form ozone ( \(O_{3}\)).
\(O_{2}\) + UV light -> 2O
O + \(O_{2}\) ->  \(O_{3}\)

2. Decomposition of ozone: Ozone can also absorb UV light, leading to its decomposition. When an ozone molecule absorbs UV light, it breaks down into an oxygen molecule ( \(O_{2}\)) and an oxygen atom (O).
   \(O_{3}\) + UV light ->  \(O_{2}\) + O

These two processes of formation and decomposition of ozone occur simultaneously in the stratosphere, creating a dynamic equilibrium. The continuous absorption of solar energy by stratospheric ozone and the subsequent chemical reactions help to maintain the natural balance of ozone in the atmosphere, protecting life on Earth from harmful ultraviolet radiation.

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Smoke and flare bomb class usually causes smoke and flash upon impact.

When it comes to bombs, there are a variety of factors that can cause smoke and a small flash upon impact. The specific design and purpose of the bomb play a key role in determining these effects. One type of bomb that is particularly known for producing smoke and flash is the smoke or flare bomb.

Smoke bombs serve the purpose of emitting a dense cloud of smoke when triggered, which can be utilized for signaling, marking targets or obstructing visibility. Additionally, these devices could include a minor flash or light burst as part of their mechanism.

When it comes to flare bombs, their purpose is to emit a brilliant burst of light when activated. This feature can be utilized for illuminating a specific target or area. Additionally, some flare bombs are designed to produce smoke as a secondary effect.

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