calculate the formal charge on n in the molecule nh3

The possible Claisen condensation product from the reaction between CH3CO2Et (ethyl acetate) and CH3CH2CO2Et (ethyl propanoate) is CH3COCH2CH2CO2Et (ethyl 3-oxobutanoate).

The possible Claisen condensation product from the reaction between C6H5CO2Et (ethyl benzoate) and C6H5CH2CO2Et (ethyl phenylacetate) is C6H5COCH2C6H5CO2Et (ethyl 2-phenyl-2-phenylacetate). This product would be expected to predominate as it forms a conjugated system, which increases its stability. The possible Claisen condensation product from the reaction between EtOCO2Et (diethyl oxalate) and cyclohexanone is EtOCOC6H11CO2Et (diethyl cyclohexane-1,4-dicarboxylate). This product would be expected to predominate due to the steric hindrance around the alpha carbon of cyclohexanone, making it less favorable for deprotonation. The possible Claisen condensation product from the reaction between C6H5CHO (benzaldehyde) and CH3CO2Et (ethyl acetate) is C6H5CH=CHCO2Et (ethyl cinnamate). This product would be expected to predominate due to the presence of the aromatic ring, which stabilizes the enolate ion formed during the reaction.

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Dissolve a sugar cube in water and you still have sucrose, not oxygen, carbon, and hydrogen. This does not mean that sucrose or water cannot be broken down into simpler substances.

But methods must involve a chemical change.

The change in which the molecular composition is completely altered and a new product is formed is called a chemical change.

Chemical changes create a new product.

The changes in chemical change are irreversible and permanent.

A chemical change occurs when the substance's composition is changed. When bonds are broken and new ones are formed a chemical change occurs.

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Vinyl and aryl halides do not undergo SN1 reactions due to the unique nature of their molecular structures and the stability of their intermediate carbocations. SN1 reactions involve a two-step mechanism that first forms a carbocation intermediate and then undergoes nucleophilic attack.

In vinyl halides, the halogen atom is directly attached to a carbon-carbon double bond (alkene). This structure results in a high degree of electron density around the double bond, which prevents the formation of a stable carbocation intermediate necessary for SN1 reactions. Moreover, the sp2 hybridization of the carbon atom in vinyl halides further reduces the likelihood of a carbocation being formed.

Similarly, aryl halides have a halogen atom attached to an aromatic ring. The resonance stabilization in the aromatic ring contributes to the overall stability of the molecule, and the formation of a carbocation intermediate would disrupt this stabilization. Additionally, the partial double bond character in the carbon-halogen bond of aryl halides due to resonance makes it difficult for the bond to break in the first step of the SN1 reaction.

In summary, vinyl and aryl halides do not undergo SN1 reactions because their molecular structures prevent the formation of stable carbocation intermediates, which are necessary for the reaction to proceed. The electron density and resonance stabilization in these compounds is key factors contributing to this behavior.

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I believe it is D because a combustion reaction produces carbon dioxide (CO2) and water (H2O)

Answer:

Activation energy, in chemistry, the minimum amount of energy that is required to activate atoms or molecules to a condition in which they can undergo a chemical transformation or physical transport.

Answer:

The answer is C Hope this helps!

Complete question is;

Which of the following kinds of cells perform basic functions such as obtaining energy from food?

A) Plant cells, but not animal cells

B) Animal cells, but not plant cells

C) Both plant cells and animal cells

D) Neither animal cells nor plant cells

Answer:

Option C: Both plant cells and animal cells.

Explanation:

Correct Answer is;

Option C: Both plant cells and animal cells.

This is because both plant and animal cells need food for survival as food gives energy for movement and work operations.

Other options are not correct because they infer that either cell or none of them obtains energy from food which is false.

The gas that is not commonly produced in a double displacement reaction is carbon dioxide.

In a double displacement reaction, two compounds exchange their ions to form two new compounds. Generally, the products of a double displacement reaction are a precipitate, water, or gas. However, the gas produced is usually "hydrogen gas" (H₂) or "hydrogen sulfide" (H₂S), not "carbon dioxide" (CO₂). This is because double displacement reactions typically involve the exchange of cations and anions, not the formation of covalent bonds, which is required for the production of carbon dioxide.

Therefore, carbon dioxide is not commonly produced in a double displacement reaction.

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Answer:

1. It is stoichiometric.

2. O2 is the limiting reactant.

3. 9.0 g of C2H6 remain unreacted.

4. 17.6 g of CO2.

5. 85.2%.

Explanation:

Hello there!

In this case, for the given chemical reaction:

\(2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O\)

We can see that:

1. It is stoichiometric and is balanced because the reactants yields the products according to the law of conservation of mass.

2. In this part, it is possible to calculate the moles of ethane by using its molar mass:

\(n_{C_2H_6}=15g*\frac{1molC_2H_6}{30.08g} =0.50molC_2H_6\)

And the moles of oxygen by knowing that one mole is contained in 22.4 L at STP:

\(n_{O_2}=\frac{1mol}{22.4L} *15.68L=0.7molO_2\)

Thus, by calculating the moles of carbon dioxide product by each reactant, we can identify the limiting one:

\(n_{CO_2}^{by\ C_2H_6}=0.50molC_2H_6*\frac{4molCO_2}{2molC_2H_6} =1.0molCO_2\\\\n_{CO_2}^{by\ O_2}=0.70molO_2*\frac{4molCO_2}{7molO_2} =0.4molCO_2\\\)

Thus, since oxygen yields the fewest moles of CO2 product, we infer it is the limiting reactant.

3. In this part, we calculate the mass of C2H6 that actually react first:

\(m_{C_2H_6}^{reacted}=0.4molCO_2*\frac{2molC_2H_6}{4molCO_2}*\frac{30.08gC_2H_6}{1molC_2H_6} =6.0gC_2H_6\)

Thus, the leftover of ethane (C2H6) as the excess reactant is:

\(m_{C_2H_6 }^{leftover}=15g-6.0g=9.0g6.0C_2H_6\)

4. Since 0.4 moles of carbon dioxide were produced, we use its molar mass to calculate the mass as its theoretical yield:

\(m_{O_2}^{theoretical}=0.4molCO_2*\frac{44gCO_2}{1molCO_2}=17.6gCO_2\)

5. Finally, the percent yield is gotten by dividing the actual yield by the theoretical one:

\(Y=\frac{15g}{17.6}*100\%\\\\Y=85.2\%\)

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the answer is D. The rain cycle says that Evaporation turns water into gas

Answer:helium or the noble gases

Explanation: The ionization energy decreases from top to bottom in groups, and increases from left to right across a period. Thus, helium has the largest ionizing energy

Answer:

chemical change

Explanation:

Ash is formed as result of burning of paper which is a new product. Chemical change a new substance must form.

Answer: chemical change

Explanation: A chemical change is irreversible and also leads to the formation of a new substance. Burning paper leads to the formation of Ash. And a burnt paper can't be made to return to it's original form.

Answer:

I say 20 is ur best option

Answer:I think the answer would be 2 mol/L

The amount of heat that is required to melt 5.50 mol of gallium at 1 atm pressure is 33 kJ/mol.

Given that,

Gallium sublimation heat = 277 kj/mol

Gallium vaporization heat = 271 kj/mol

Sublimation, as we know, transforms a sold substance into a gas. Changing from a liquid to a gas is called vaporization.                                        

Hence, using the provided Data, we can derive two equations;

Ga (s)  --> Ga (g) delta, Heat = 277 kJ/mol

Ga (l)  --> Ga (g) delta Heat = 271 kJ/mol

Ga (s) --> Ga (l) delta H = 6 kJ/mol is the result of differentiating these two equations to determine the amount of heat needed to melt one mol.

Therefore, it takes 6 kJ/mol of heat to melt one mol of gallium.

Therefore, 5.5 x 6 = 33 kJ/mol of heat is needed to melt 5.5 mol of gallium.

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The structure of ethanol is shown below. As a result, the molecule CH3CH2OH C H 3 C H 2 O H is polar. Both a Lewis acid and a Lewis base, CH3CH2OH C H 3 C H 2 O H, can function.

Due to the oxygen atom's lone pair of electrons, it is primarily a Lewis base. The most polar of these is the O-H bond. The difference in electronegativity between the two atoms involved can be used to explain it. Ethanol, with the chemical formula CH3 CH2 OH, contains hydrogen bonds. Covalent bonds between hydrogen atoms produce hydrogen bonds. However, CH3CH2OH alone displays hydrogen bonding, which is substantially stronger than the intermolecular forces that are present in the other options.

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Using the Lewis diagram, I was able to determine that: 1) there are 7 C-H bonds, 2) there are 1 O-H bonds, and 3) The C-C bond count is 2, 4) The C-O bond count is 1, 5) There are 2 lone pairings.

Lewis diagram, often referred to as Lewis dot formulas, Lewis dot structures, electron dot structures, or Lewis electron dot structures (LEDS), are diagrams that depict the interactions of atoms in molecules as well as any lone pairs of electrons that may be present. Any covalently bound molecule, as well as coordination compounds, can be represented by a Lewis structure. Gilbert N. Lewis introduced the Lewis structure in his 1916 essay The Atom and the Molecule, and it bears his name. By adding lines between atoms to indicate shared pairs in a chemical bond, Lewis structures expand on the idea of the electron dot diagram.

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To determine the relative molecular weights of methylene blue and potassium permanganate, a method known as 'osmometry' can be used.

Here's how to conduct the experiment :

Experiment Set-up

Step 1: Firstly, create a solution of a known concentration of methylene blue and potassium permanganate. The concentration of the solution should be around 0.01 M.

Step 2: Take an apparatus that includes a semi-permeable membrane and two containers. The semi-permeable membrane should be permeable to the solvent used but impermeable to the solute.

Step 3: Fill the two containers with the prepared solutions, methylene blue, and potassium permanganate.

Step 4: Place the semi-permeable membrane between the two containers.

Step 5: Observe the solution levels in both containers. In the initial stage, the solution level in the container containing methylene blue will be higher, while the container containing potassium permanganate will be lower.

Step 6: The process will continue until the solution levels in both containers become equal.

Step 7: Now, record the solution levels in both containers at equilibrium.

The Relative Molecular Weight Calculation

Step 8: Apply the following formula to calculate the relative molecular weight of the solute : Δπ= MRT

Δπ = change in osmotic pressure of the solution

M = molar concentration of the solution

R = universal gas constant (8.314 J/mol K)

T = temperature in Kelvin

If we take Methylene blue as solute and KCl as solvent, then at 25°C the osmotic pressure of the solution is given as :

Δπ = 0.51 atm

Substituting all values in the above formula, we get Δπ = MRT(i)

0.51 atm = M x 8.314 J/molK x 298 K(i)

M = 0.0206 mol/L

The relative molecular weight of Methylene blue is :

M = m/2.06 x 10^-2

where m is the mass of Methylene blue dissolved in 1 litre of solvent.

From the relative molecular weight calculated, we can get the actual molecular weight by multiplying it by the molar mass of the solvent used.

For example, if the solvent used is KCl, then the molecular mass of the solvent is 74.55 g/mol.

Therefore, the molecular weight of Methylene blue = Relative molecular weight x molar mass of the solvent.

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Explanation:

employment in the country.

economic boom n latest techonology.

less poverty.

more development.

more jobs for people.

increase in exports which will make large profits n will be utilized in the development of country.

GDP per capita will increase.

high standard of living.

Answer:

A is the answer it is correct

Answer:

A

Explanation:

trust me

Answer:

\(\Large \boxed{\mathrm{A}}\)

Explanation:

Rust formed from iron and oxygen combining is a chemical change, because in a chemical change, the resulting substance(s) will have different properties from the substance(s) before the chemical change.

I cant comment... So is it Right?

The main reservoirs of the carbon cycle are the atmosphere, oceans, land (including vegetation and soils), and fossil fuels. In these reservoirs, carbon exists in both inorganic and organic forms.

The inorganic carbon cycle involves the exchange of carbon dioxide (CO2) between the atmosphere and oceans through processes like photosynthesis and respiration.

Organic carbon, on the other hand, is found in living organisms, dead organic matter, and soil organic matter. It is cycled through processes such as decomposition and consumption by organisms. The interactions between the inorganic and organic carbon cycles occur primarily in the biosphere, where photosynthesis converts inorganic carbon into organic carbon compounds. While inorganic carbon is primarily in the form of CO2, organic carbon is present in complex organic molecules. Both forms of carbon play crucial roles in energy transfer, nutrient cycling, and climate regulation.

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To determine the change in volume (V) given the changes in pressure (P) and temperature (T), we need to consider the relationship described by the ideal gas law:

\(\displaystyle PV = nRT\)

Where:

To analyze the effect of changing P and T on V, we'll assume that the number of moles (n) and the ideal gas constant (R) remain constant.

If P increases by a factor of 5, we can express the new pressure as:

\(\displaystyle P_{\text{new}} = 5P\)

If T decreases by a factor of 3, we can express the new temperature as:

\(\displaystyle T_{\text{new}} = \frac{1}{3}T\)

Now, let's consider the relationship between the initial and final volumes (V and V_new):

\(\displaystyle PV = nRT\)

\(\displaystyle V = \frac{nRT}{P}\)

\(\displaystyle P_{\text{new}}V_{\text{new}} = nRT_{\text{new}}\)

\(\displaystyle V_{\text{new}} = \frac{nRT_{\text{new}}}{P_{\text{new}}}\)

Substituting the expressions for P_new and T_new, we have:

\(\displaystyle V_{\text{new}} = \frac{nR\left(\frac{1}{3}T\right)}{5P}\)

Simplifying the expression:

\(\displaystyle V_{\text{new}} = \frac{1}{15}\left(\frac{nRT}{P}\right)\)

Comparing this with the initial volume (V), we can see that:

\(\displaystyle V_{\text{new}} = \frac{1}{15}V\)

Therefore, the change in volume (V) is such that it decreases by a factor of 15.

The correct option is E. V decreases by a factor of 15.

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Coal, oil, and natural gas are examples of fuels that store chemical energy. The chemical energy in these fuels is transformed into heat energy when they are burnt. Some fuels, known as fossil fuels.

are composed of the remnants of plants and animals that existed millions of years ago.Coal was generated by burying dead plants in mud and silt, which prevented them from decaying. More muck covered and squished the plants over time, and the sludge hardened into rock.Coal, oil, and natural gas are examples of fuels that store chemical energy. The chemical energy in these fuels is transformed into heat energy when they are burnt. Some fuels, known as fossil fuels. The dead plants were converted into coal. Plants and animals that fell to the sea floor and were covered by silt produced oil and Coal, oil, and natural gas are examples of fuels that store chemical energy. The chemical energy in these fuels is transformed into heat energy when they are burnt.

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An Arrhenius base is a molecule that when dissolved in water will break down to yield an \(OH^-\)or hydroxide ion in solution.

An Arrhenius base is a compound that increases the \(OH^-\) ion concentration in aqueous solution.

An Arrhenius base is a substance that, when dissolved in an aqueous solution, increases the concentration of hydroxide, or , \(OH^-\) ions in the solution.

Bases Properties

Arrhenius bases that are soluble in water can conduct electricity.

Bases often have a bitter taste and are found in foods less frequently than acids. Many bases, like soaps, are slippery to the touch.

Bases also change the colour of indicators. Red litmus turns blue in the presence of a base (see figure below), while phenolphthalein turns pink.

Some bases react with metals to produce hydrogen gas.

Acids (pH < 7.0) react with bases (pH > 7.0) to produce a salt and water. When equal moles of an acid and a base are combined, the acid is neutralized by the base. The resulting mixture will have a more neutral pH.

An Arrhenius acid is a substance that dissociates in water to form hydrogen ions or protons. In other words, it increases the number of \(H^+\) ions in the water. In contrast, an Arrhenius base dissociates in water to form hydroxide ions \(OH^-\).

Example, sodium hydroxide, is added to an aqueous solution. NaOH dissociates into sodium, \(Na^+\), and hydroxide, \(OH^-\) ions.

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The first two chemical equations are reversible while the other two are irreversible.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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Among the given options, the salt that will form a basic solution upon dissolving in water is sodium nitrite (NaNO2). The correct answer is option C.

When a salt dissolves in water, it can have different effects on the pH of the resulting solution. Salts can be classified as acidic, basic, or neutral based on their behavior when dissolved.

a. Potassium bromide (KBr): KBr is a neutral salt. It is composed of the alkali metal potassium (K+) and the halide ion bromide (Br-), which do not significantly affect the pH of the solution. Thus, KBr does not make the solution acidic or basic.

b. Sodium chloride (NaCl): NaCl is also a neutral salt. It consists of the alkali metal sodium (Na+) and the halide ion chloride (Cl-). Like KBr, NaCl does not significantly affect the pH of the solution and does not make it acidic or basic.

c. Sodium nitrite (NaNO2): NaNO2 is the salt that forms a basic solution. It is composed of the alkali metal sodium (Na+) and the nitrite ion (NO2-). Nitrite ions can undergo hydrolysis in water, leading to the formation of hydroxide ions (OH-) and making the solution basic.

Therefore, among the given options, only sodium nitrite (NaNO2) will form a basic solution upon dissolving in water.

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