CaF2+H2SO4—>2HF+CaSO4
In one experiment 42.0g of CaF2 was treated with 94.5g H2SO4 and 14.2g of HF was obtained in the lab

1. what is the limiting reagent
2. how much excess reagent was left over
3. calculate the theoretical yield of CaSO4
4. calculate the percent yield of HF

please answer and explain each question

Answers

Answer 1

1.) H2SO4 is the limiting reagent ; 2.) Excess H2SO4 = 41.66 g ; 3.) Theoretical yield of CaSO4 is 73.40 g. ;  4.) Percent yield of HF is 74.4%.

What is limiting reagent?

Reactant that is totally consumed when chemical reaction is completed is called limiting reagent.

1.) Moles of CaF2 = 42.0 g / 78.07 g/mol = 0.5386 mol

Moles of H2SO4 = 94.5 g / 98.08 g/mol = 0.9637 mol

Using the stoichiometric ratios, 0.5386 moles of CaF2 would produce 2 x 0.5386 = 1.0772 moles of HF, while 0.9637 moles of H2SO4 would produce only 0.9637 moles of HF. Therefore, H2SO4 is the limiting reagent.

2.) 0.9637 moles H2SO4 x (1 mole CaF2 / 1 mole H2SO4) = 0.9637 moles CaF2

This means that only 0.5386 moles of CaF2 was actually consumed in the reaction. Therefore, 0.9637 - 0.5386 = 0.4251 moles of H2SO4 was left over.

Excess H2SO4 = 0.4251 mol x 98.08 g/mol = 41.66 g

3.) Moles of CaSO4 produced = Moles of CaF2 consumed = 0.5386 mol

Mass of CaSO4 produced = 0.5386 mol x 136.14 g/mol = 73.40 g

Therefore, the theoretical yield of CaSO4 is 73.40 g.

4.) As percent yield = (Actual yield /Theoretical yield) x100

Percent yield = (14.2 g / (0.9637 mol x 20.01 g/mol)) x 100 = 74.4%

Therefore, the percent yield of HF is 74.4%.

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Related Questions

Discuss how you think oxygen levels in an estuary might be likely to rise or fall during a cold spell

Answers

Answer: In spring and summer, the uppermost layer of an estuary grows warmer and mixing between this surface water and the cooler bottom water slows. As air temperatures cool through the autumn, the surface water becomes increasingly cold and increases in density.

Explanation:

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Explain how the graph above can be used to find the half-life of an isotope.

Explain why the limit of radiocarbon dating using carbon-14 is approximately 60,000 years (10 half-lives).

Explain how the graph above can be used to find the half-life of an isotope.Explain why the limit of

Answers

The half life is the time taken for only one of the half  of the radioactive substance to remain.

What is half life?

The half life is the time taken for only one of the half  of the radioactive substance to remain. We can see the half life by looking at the graph and observing the point at which the sample decreases to half its original number.

Since the half life of carbon-14 is 5700 years, after ten half lives, almost 60000 years has elapsed thus there is little or no carbon-14 left. As a result of this carbon-14 can not be used if the sample is over 60000 years old.

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which of the following accurately describes the ph scale? which of the following accurately describes the ph scale? the ph scale runs from 0 (neutral) to 14 (most acidic), with 7 as an average acidity level. the ph scale runs from 0 (most acidic) to 14 (neutral), with 7 as an average acidity level. the ph scale runs from 0 (most basic) to 14 (most acidic), with 7 as a neutral. the ph scale runs from 0 (most acidic) to 14 (most basic), with 7 as a neutral.

Answers

Answer:

The pH scale measures acidity of a substance. known as potential of hydrogen, it varies from 0 to 14 with 7 being the pH value of a neutral solution. Below 7 shows the substance is acidic in nature and above 7 is alkaline in nature. pH 0-3 are considered strong acids while pH 4-6 are weak acids. pH 8-10 are weak alkalines and pH 11-14 are strong alkalines. This is a general trend and there may be exeptions especially if the substance has a negative pH. However, it would not be covered likely unless you are doing university chemistry.

during a physics experiment, helium gas is cooled to a temperature of 13.0 k at a pressure of 9.00×10−2 atm.] What are (a) the mean free path in the gas, (b) the rms speed of the atoms, and (c) the average energy per atom?

Answers

The mean free path in the gas is approximately 5.38 × 10^-7 m, the rms speed of the atoms is approximately 1,242 m/s, and the average energy per atom is approximately 2.84 × 10^-21 J.

To solve this problem, we will use the following equations:

(a) Mean free path = (k * T) / (sqrt(2) * pi * d^2 * P)

(b) Root mean square (rms) speed = sqrt((3 * k * T) / (m))

(c) Average energy per atom = (3/2) * k * T

where:

k is the Boltzmann constant (1.38 × 10^-23 J/K)

T is the temperature in kelvin (13.0 K)

d is the diameter of a helium atom (2.64 × 10^-10 m)

P is the pressure in atm (9.00 × 10^-2 atm)

m is the mass of a helium atom (6.646 × 10^-27 kg)

(a) Mean free path:

Mean free path = (k * T) / (sqrt(2) * pi * d^2 * P)

Mean free path = (1.38 × 10^-23 J/K * 13.0 K) / (sqrt(2) * pi * (2.64 × 10^-10 m)^2 * 9.00 × 10^-2 atm)

Mean free path ≈ 5.38 × 10^-7 m

(b) Root mean square speed:

Root mean square speed = sqrt((3 * k * T) / (m))

Root mean square speed = sqrt((3 * 1.38 × 10^-23 J/K * 13.0 K) / (6.646 × 10^-27 kg))

Root mean square speed ≈ 1,242 m/s

(c) Average energy per atom:

Average energy per atom = (3/2) * k * T

Average energy per atom = (3/2) * 1.38 × 10^-23 J/K * 13.0 K

Average energy per atom ≈ 2.84 × 10^-21 J

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consider the following saturated solution of calcium hydroxide. ca(oh)2 (s) ⇄ ca2 (aq) 2oh-(aq) what effects, if any, will adding ag have on the position of equilibrium?

Answers

The addition of Ag to the saturated solution of calcium hydroxide will cause a shift in the position of equilibrium to the right, resulting in the formation of a precipitate of Ca(OH)2.

Adding Ag (silver) to the saturated solution of calcium hydroxide will result in the formation of a precipitate. This is because Ag+ ions react with OH- ions to form AgOH(s), which is insoluble in water. As a result, the concentration of OH- ions in the solution decreases, leading to a shift in the position of equilibrium to the right, according to Le Chatelier's principle.

Le Chatelier's principle states that when a system at equilibrium is subjected to a stress, it will shift to minimize the effect of that stress. In this case, the addition of Ag+ ions acts as a stress on the equilibrium. To minimize the effect of the stress, the system shifts to the right, favoring the formation of more Ca2+ and OH- ions.

As a result of this shift, more Ca2+ ions and OH- ions will be produced, and the concentration of Ca(OH)2 (s) will decrease. The solubility of calcium hydroxide decreases as a result of the reduced concentration of OH- ions. This leads to the formation of a precipitate of Ca(OH)2.

In conclusion, the addition of Ag to the saturated solution of calcium hydroxide will cause a shift in the position of equilibrium to the right, resulting in the formation of a precipitate of Ca(OH)2.

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From the following equations, which one is an example of a decomposition reaction? *
2Cl + 2Na = 2NaCl
NaCl + Fe = FeCl + Na
2NaCl = 2Na + 2Cl
FeCl + Na = NaCl + Fe

Answers

Answer:

2NaCl = 2Na + 2Cl

Explanation:

Sodium chloride decomposes to form sodium and chlorine

the chemical formula for beryllium oxide is . a chemist measured the amount of beryllium oxide produced during an experiment. she finds that of beryllium oxide is produced. calculate the number of moles of beryllium oxide produced. be sure your answer has the correct number of significant digits.

Answers

The number of moles of beryllium oxide BeO are 2.228 moles.

The chemical formula for beryllium oxide is given to be BeO.

The mass of the amount of beryllium oxide formed is 555.7 grams.

we are asked to find the number of moles,

The moles are given by the mass of the substance divided by the molar mass of the substance.

Mass = Mass formed/molar mass

Mass of BeO formed = 55.7 grams.

Molar mass of BeO = 25g/mol.

Putting values,

Moles of BeO = 55.7/25

Moles of BeO = 2.228 moles.

So, the number of moles of beryllium oxide formed are 2.228 moles.

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Complete question - the chemical formula for beryllium oxide is BeO. A chemist measured the amount of beryllium oxide produced during an experiment. she finds that 55.7 grams of beryllium oxide is produced. calculate the number of moles of beryllium oxide produced. be sure your answer has the correct number of significant digits.

Which of the following statements is TRUE o On a given day, the temperature value of west facing wall reaches a peak before east facing wall o On a given day, the temperature value of north facing wall reaches a peak before south facing wall o From thermal comfort point of view, thick walled structures are beneficial in hot and humid climates o From thermal comfort point of view, thick walled structures are beneficial in hot and dry climates
Clear my choice

Answers

From thermal comfort point of view, thick walled structures are beneficial in hot and humid climates is the statement that is true.The correct option is C.

Thick walled structures are beneficial in hot and humid climates from the thermal comfort point of view.How do thick walled structures help in hot and humid climates - In hot and humid climates, thick walls tend to absorb the heat present in the environment. This absorption helps to keep the interior of the structure cool.

Additionally, thick walls take more time to heat up and more time to cool down. Thus, in hot and humid climates, thick walls are a better choice than thin walls because they provide thermal comfort.

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Answer question number 3

Answer question number 3

Answers

The first choice should be correct

a flask contains 2.838 m formic acid and 1.913 m formate anion. these two chemicals are a conjugate acid/base pair that should be able to form a buffer. if formic acid has a 298 k value for ka of 1.85x10-4, what is the ph of the solution in this flask?

Answers

The pH of the buffer solution given in the flask containing 2.838 m formic acid and 1.913 m Formate anion is 3.56.

The pH of a buffer solution can be calculated using the Henderson-Hasselbalch equation:

pH = pKa + log([A⁻]/[HA])

where pKa is the acid dissociation constant of formic acid (HCOOH) which is 1.85x10⁻⁴ at 298 K1, [A⁻] is the concentration of Formate anion (HCOO⁻) and [HA] is the concentration of formic acid (HCOOH).

The molarity of formic acid in the flask is 2.838 M and that of Formate anion is 1.913 M.

Since these two chemicals are a conjugate acid/base pair that should be able to form a buffer, we can assume that all of the formic acid will dissociate into H⁺ and HCOO⁻ ions.

Therefore,

[HCOO⁻] = 1.913 M and

[H⁺] = 1.85x10⁻⁴ × 2.838 / 1.913

= 2.75 x 10⁻⁴ M.

Taking -log[H⁺] gives us pH:

= -log(2.75 x 10⁻⁴) = 3.56.

Therefore, the pH of the solution in this flask is 3.56.

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What are metalloids? Give examples.​

Answers

Answer:

which shows both behaviour of metals and non metals

please come fast

Explanation:

Ctzqropejy

Answer:

The element which shows the property of both metal and nonmetal is called metalloids

Explanation:

examples of metalloids are silicon boron germanium etc

Which activity is the best demonstration of J.J. Thomson's use of creativity in his work?

Answers

cathode ray tube experiment

Answer:

Thomson used creativity to interpret the results of the cathode ray tube experiment. Explain how the atomic theory was modified from Dalton's theory to Rutherford's.

what is the reaction between phosphate ion (PO4 3-) and hydronium ion (H3O+)

Answers

Answer:

H3O+(aq) + PO43−(aq) ⇌ HPO42−(aq) + H2O(l)

Notice that the total charge (2-) is the same on both sides of the equation, and that this is reaction can take place in both directions.

Explanation:

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CO(g) + O2(g) CO2(g)

Consider the unbalanced equation above. What is the maximum mass of carbon dioxide that can be formed when 1.45 g of CO and 2.00 g O2 react?

Answers

CO(g) + O2(g) CO2(g)

Consider the unbalanced equation above. What is the maximum mass of carbon dioxide that can be formed when 1.45 g of CO and 2.00 g O2 react?

explain how you would find the number of moles that are rpresented by a certaib nunver if reoresnetatuce oartuckes

Answers

To find the number of moles represented by a certain number of particles, you can use Avogadro's number and the concept of molar mass.

Avogadro's number (symbolized as N<sub>A</sub>) is a fundamental constant that represents the number of particles (atoms, molecules, ions, etc.) in one mole of a substance. It is approximately equal to 6.022 × 10²³ particles/mole.

Molar mass is the mass of one mole of a substance and is expressed in grams/mole. It represents the sum of the atomic masses or molecular masses of the constituent particles in a substance.

To calculate the number of moles, you can follow these steps;

Determine the number of particles you have (atoms, molecules, ions, etc.).

Identify the molar mass of the substance or the average molar mass if it's a mixture.

Divide the number of particles by Avogadro's number to convert them into moles. The formula is:

Moles = Number of Particles / Avogadro's number

Moles = Number of Particles / (6.022 ×10²³ particles/mole)

The result will give you the number of moles represented by the given number of particles.

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--The given question is incorrect, the correct question is

"Explain how you would find the number of moles that are represented by a certain number of representative particles."--

Post-Laboratory Questions
(2pts)
1. Examine the magnitude of your calculated equilibrium constant, Keq. Does the equilibrium favor reactants or products? Explain your answer.

attachment

Answers

The magnitude of Keq indicates whether the equilibrium favors the formation of products or reactants.

Understanding Equilibrium Constants

In general, the magnitude of the equilibrium constant indicates whether the reaction favors the formation of products or reactants.

If Keq is much greater than 1, it means that the reaction strongly favors the formation of products. This suggests that the reaction proceeds almost entirely in the forward direction and that the products are much more stable than the reactants. Conversely, if Keq is much less than 1, it means that the reaction strongly favors the formation of reactants. This suggests that the reaction proceeds almost entirely in the reverse direction and that the reactants are much more stable than the products.

If Keq is approximately equal to 1, it means that the reaction is in a state of equilibrium, where the concentrations of products and reactants are roughly equal. This suggests that the reaction proceeds in both the forward and reverse directions at similar rates and that the concentrations of the products and reactants are stable over time.

Therefore, based on the magnitude of Keq, it can be determined whether the equilibrium favors the formation of products or reactants.

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5.79 A 29.3-g sample of Ti reacts with O2 to form 48.9 grams of product. Determine the empirical formula of the product. 5.82 A compound composed of carbon, hydrogen, and oxygen is found to have an empirical formula of CH40. Determine the molecular formula of the compound if its molar mass is 88.10 g/mol. tobar So 5.84 A compound containing carbon, hydrogen, and oxygen was found to be 55.80% and 37.18% O by mass. Determine the molecular formula of the compound if its molar mass is found to be 86.08 g/mol. 2 bra 83 87. Determine the mass (in g) of each compound that contains 2.97 102 N atoms and convert each mass to moles of compound. 2.97 x 10N atoms in Mass (g) of Compound: NO Mole of Compound: Mass (g) of Compound: (NH4O Mole of Compound: Mass (g) of Compound: AI(NO3) Mole of Compound: 84

Answers

The empirical formula of the product in question 5.79 can be determined by finding the ratio of the elements present.

Given that a 29.3 g sample of Ti reacts with O2 to form 48.9 g of product, we need to calculate the moles of Ti and O in the reaction. The molar mass of Ti is 47.87 g/mol, so the moles of Ti in the sample is:

moles of Ti = mass of Ti / molar mass of Ti

moles of Ti = 29.3 g / 47.87 g/mol = 0.612 mol

To find the moles of O, we can use the difference in mass between the sample and the product:

mass of O = mass of product - mass of Ti

mass of O = 48.9 g - 29.3 g = 19.6 g

The molar mass of O is 16.00 g/mol, so the moles of O in the product is:

moles of O = mass of O / molar mass of O

moles of O = 19.6 g / 16.00 g/mol = 1.225 mol

Now we can find the empirical formula by dividing the number of moles of each element by the smallest number of moles:

Empirical formula = Ti(0.612 mol) O(1.225 mol) = TiO2

Therefore, the empirical formula of the product is TiO2.

The given information provides the masses of titanium (Ti) and oxygen (O) in the reaction. By converting these masses to moles and comparing their ratios, we determine the empirical formula of the product to be TiO2. This means that the product contains one titanium atom and two oxygen atoms per formula unit.

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Are the properties of the element and its compounds the same? Use
fluorine and fluorides to explain your answer.
3 marks

Answers

The properties of the element and its compounds are not the same. In the case of fluorine, we know that this is a volatile and reactive element but fluorides are stable and less harmful elements that can serve beneficial purposes.

Difference between fluorine and fluorides

Fluorine is a chemical element that is known for its ability to combine easily with oxygen and other elements. It is a highly reactive substance but this is not the case with fluorides. The fluorides have already undergone a reaction so they are no longer as volatile as fluorine in the ordinary state.

They are used in toothpaste formulations to strengthen the gums but this cannot be said of fluorine which should not be tasted in the raw state.

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1. The motion of an object with constant acceleration is also known as ________. *
Motion
Uniform Motion
Constant Motion
Uniformly Accelerated Motion

2. A sepaktakraw ball is hit vertically upward by a player. What is its acceleration after 1 second? *
0
1 m/s2
19.8 m/s2
-9.8 m/s2

3. If a freely falling ball is somehow equipped with a speedometer, by how much would its speed-reading increase for every second? *
0 m/s
9.8 m/s
10 m/s
20 m/s

4. It is any motion of a body where gravity is the only force acting upon it (no friction or air resistance). *
freefall
gravity
acceleration
velocity
5. Objects fall at constant acceleration also known as acceleration due to gravity equivalent to *
1 point
9.8 m/s
9.8 m2/s
-9.8 m/s2
20 m/s
For questions 6-10, consider the illustration below.

6. At what angle of release makes the projectile reach the maximum height? *
15°
30°
45°
60°
75°
60° & 30°
30° & 75

7. Which of the following pairs of angles will make projectiles reach the same range? *
15°
30°
45°
60°
75°
60° & 30°
30° & 75

8. Which angle of release makes the projectile reach the longest range? *
15°
30°
45°
60°
75°
60° & 30°
30° & 75

9. Which angle of release are complementary angles? *
15°
30°
45°
60°
75°
60° & 30°
30° & 75

10. At what angle should a water hose be aimed for the water to land with the greatest horizontal range?
15°
30°
45°
60°
75°
60° & 30°
30° & 75

11. Which of the following statements describes momentum? *
the product of body's mass and velocity
the sum of body's mass and velocity
the product of body's mass and acceleration
the sum of body's mass and acceleration

12. Two identical cars are travelling along EDSA. Which of the two cars would have a greater momentum? *
the slower car
the faster car
both have the same momentum

13. Which has more momentum, a huge truck that is not moving or a bicycle that is moving? *
truck
bicycle
both have the same momentum

14. What are the two factors that affect the momentum of an object? *
velocity and time
force and velocity
mass and velocity
acceleration and force

15. Which has more momentum, a heavy truck moving at 30 km/h or a light truck moving at 30 km/hr? *
heavy truck
light truck
both have the same momentum

1. The motion of an object with constant acceleration is also known as ________. *MotionUniform MotionConstant

Answers

Answer:

i can't answer sorry

Explanation:

i had confused

1) A mixture of anhydrous sodium carbonate and sodium hydrogencarbonate of mass 10.000 g was heated until it reached a constant mass of 8.708 g. Calculate the composition of the mixture in grams of each component.​

Answers

The masses of the components are obtained as;

Sodium hydrogen carbonate = 3.51 gSodium carbonate =  8.708 gWhat is decomposition?

The term decomposition has to do with the breakdown of the given substance into its components. The components of sodium hydrogen carbonate could be identified as water vapor, carbon dioxide gas and sodium carbonate. Among these products that have been listed here, we can see that it is only the sodium carbonate that remains as a solid. The others are gases that move away from the system that is under study.

Now putting down the equation of the reaction, we have;

\(2NaHCO_{3} (s) ----- > Na_{2} CO_{3} (s) + CO_{2} (g) + H_{2} O(g)\)

Now, the loss in  mass must be due to the carbon dioxide and the water. Hence we obtain the loss in mass to be 10.000 g -  8.708 g = 1.292 g

Mass of sodium hydrogen carbonate = 2 * 88 g/mol * 1.292 g/62 g/mol

= 3.51 g

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Choose the proper whole-number coeffi-

cients for each substance to yield a balanced

equation.


D

1. 2, 1, 2

2. 1, 1, 1

3. 1, 2, 1

4. 2, 1,1

Answers

The proper whole number coefficient for each substance to yield a balanced equation is option 1 that is 2, 1, 2.

The proper whole number coefficient for each substance to yield a balanced equation is option 1 that is 2, 1, 2. Balancing a chemical reaction is done to find out the overview of that reaction and to find the answers related to that equation. like we can tell many things about the equation just by knowing the coefficients of the terms in that equation. we can tell about the percentage and existence of the products and reactants in the equation. if we know the coefficients of the elements and products we can tell about the mole of the reactants and products in the chemical equation. By this information, we can consider that the proper whole number coefficient for each substance to yield a balanced equation is option 1 that is 2, 1, 2.

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H2
 Define the Omnipotent view of management ( 5 pts)
 Define the Symbolic view of management ( 5 pts)
 What works best, in your opinion for the current state that ABC CO is in ? ( explain and
justify)–5pts
 The importance of setting the right organization culture is clearly an urgent need for
ABC -Describe what kind of culture should be created – what will be its characteristics ?
(5 pts)
 How about the organizational environment ? (customers , suppliers , competitors ,
economic , legal , socio cultural) - what needs to be done ? ( 5 pts)

Answers

The Omnipotent view of management refers to the belief that managers are directly responsible for an organization's success or failure. According to this view, managers have the power and control to make decisions that will significantly impact the organization's performance.

In terms of the organizational environment, ABC CO needs to focus on several aspects. Firstly, it should prioritize building strong relationships with customers by understanding their needs and delivering value through its products or services. Secondly, maintaining good relationships with suppliers is crucial to ensure a reliable supply chain and access to necessary resources. Thirdly, keeping a close eye on competitors is essential to stay competitive and identify opportunities for differentiation. Lastly, monitoring and adapting to economic, legal, and socio-cultural factors is vital to ensure compliance with regulations and aligning the organization with societal trends and expectations.

In conclusion, the Omnipotent view of management emphasizes the influence of managers in shaping organizational outcomes, while the Symbolic view recognizes the significance of external factors. For the current state of ABC CO, a balanced approach that considers both internal and external factors would be beneficial. The culture should promote collaboration, innovation, and adaptability, while the organization should focus on building strong relationships with customers, suppliers, and competitors while adapting to the economic, legal, and socio-cultural environment.

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.Answer the following questions about laboratory situations involving acids, bases, and buffer solutions.
(a) Lactic acid, HC3H5O3, reacts with water to produce an acidic solution. Shown below are the complete Lewis structures of the reactants. In the space provided, complete the equation by drawing the complete Lewis structures of the reaction products.
(b) Choosing from the chemicals and equipment listed below, describe how to prepare 100.00 mL of a 1.00 M aqueous solution of NH4Cl (molar mass 53.3 g molâ€"1). Include specific amounts and equipment where appropriate.
NH4Cl (s) 50 mL buret 100 mL graduated cylinder 100 mL pipet
Distilled water 100 mL beaker 100 mL volumetric flask Balance
Mass of NH4Cl: 100 mL = 5.33 g NH4Cl
(1) Weigh out 5.33 g NH4Cl(s) using the balance. (2) Carefully transfer the solid into a 100 mLvolumetric flask. (3) Add distilled water up to the etched line. (4) Mix.

Answers

The complete Lewis structure of lactic acid is:
H      H
|      |
H-C-C-OH
|      |
H-C-C=O
|      |
H      OH

When lactic acid reacts with water, one of the OH groups will dissociate and form H+ ions. The complete Lewis structure of the product, H3O+, is:
      H
      |
H      O-H
|      ||
H-C-C=O
|      |
H      OH

(b)
To prepare 100.00 mL of a 1.00 M aqueous solution of NH4Cl, we need to dissolve 5.33 g of NH4Cl in distilled water. Here are the steps:

(1) Use the balance to weigh out 5.33 g of NH4Cl(s).

(2) Carefully transfer the solid into a 100 mL volumetric flask.

(3) Add distilled water up to the etched line.

(4) Mix the solution thoroughly until all the solid is dissolved.
You can use a stirring rod to help dissolve the NH4Cl.
The 50 mL buret, 100 mL graduated cylinder, and 100 mL pipet are not needed for this procedure.

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When using strong acids and bases in the laboratory. You should wear? a safety shoes only. b only closed-toe shoes. c no shoes. d any shoes.

Answers

When using strong acids and bases in the laboratory, one should wear a safety shoes only (option A).

What is laboratory precaution?

Laboratory is a room, building or institution equipped for scientific research, experimentation or analysis.

However, when working in the laboratory, one is exposed to series of danger that can occur through accidents such as chemical spillage etc.

This suggests that it is necessary for laboratory personnel to place emphasis on safety and chemical hygiene at all times.

One of the safety precautions to be taken in the laboratory is that safety shoes should be worn whenever strong acids and bases are being used.

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what is the product(s) in the reaction below
2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)

Answers

Answer:

Aqueous sodium hydroxide and hydrogen gas

Can an asteroid be pure metal? (a) No; all asteroids contain rock. (b) Yes; it must have formed where only metal could condense in the solar nebula. (c) Yes; it must have been the core of a shattered asteroid.

Answers

When an asteroid enters the surface of the earth, it gets shattered. The core of a shattered asteroid contains pure metals such as iron and nickel.

Asteroids are present in space in the form of large rocks. The rocks are made up of minerals and metals. Asteroids revolve around the sun in an orbit. Asteroids are also known as small planets. Therefore, these asteroids are made up of materials similar to that of a planet.

Asteroids can be divided into 3 categories:

1) C- Type:- These asteroids contain clays and stony particles.

2) S- Type:- The asteroid will contain silicates and a composition of nickel-iron metal.

3) M-Type:- These have nickel and iron metals.

Along with these materials, dirt and dust are also found inside these small planets.

The correct answer is (C).

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What is an ethical topic?

Answers

Answer:

its an issue

Explanation:

google words not mine

"ethical issue. A problem or situation that requires a person or organization to choose between alternatives that must be evaluated as right (ethical) or wrong (unethical). ... When considering this problem, lawyers may do well to ignore the letter of the law and realize that it is, at its heart, an ethical issue."


Chlorinated fluorocarbons are listed as a hazardous waste based
on which hazardous waste characteristic?

Answers

Chlorinated fluorocarbons are considered hazardous substances due to their detrimental impact on the ozone layer, but they are not explicitly listed as hazardous waste.

Chlorinated fluorocarbons (CFCs), despite not being on the list of hazardous waste, are nonetheless regarded as toxic due to their detrimental impact on the ozone layer and the environment. The Montreal Protocol has phased out CFCs, which were once widely used in sectors like refrigeration and as aerosol propellants.

They cause ozone depletion when they are released into the atmosphere. Although CFCs are not classified as hazardous waste, they can have a severe impact on the environment and people's health if they are improperly disposed of or leaked.

The ecosystem and public health may be in danger since CFCs persist in the environment and contribute to air pollution. It's critical to handle and dispose of CFCs properly to reduce their harmful effects on the environment and to prevent further ozone layer damage.

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The first ionization energy for a gas-phase atom of a particular element is 6. 24 × 10^–19 j. What is the maximum wavelength of electromagnetic radiation that could ionize this atom?.

Answers

The maximum wavelength of electromagnetic radiation which can ionize this atom is 320 nm or 320 x 10^-9 m.

The ionization energy is the minimum amount of energy that should be given to an element to eject electrons out of it i.e ionizing it.

The relation between Energy(E) and wavelength(λ) is as follows

E = hc/λ

Here h = Planck’s Constant = 6.626 x 10-34 J s

c = speed of light = 3 x 10^8 m/s

λ = wavelength of electromagnetic radiation

Putting the given values in the above equation

6.24 x 10^-19 J = 6.626 x 10^-34 x 3 x 10^8/ λ

λ = 320 x 10^-9 m.

Thus, the maximum wavelength of electromagnetic radiation which can ionize this atom is 320 nm or 320 x 10^-9 m.

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Prevention and Maintenance - to prevent deformity and maintain existing capacity for motion
Restoration - to improve diminished capacities for motion, strength and endurance
Compensation - to adapt for limited motion

Answers

Prevention and maintenance are key aspects of maintaining optimal musculoskeletal health. To prevent deformity, it is important to maintain proper posture and alignment during activities of daily living and exercise. Regular stretching and strengthening exercises can help maintain existing capacity for motion.


In cases where diminished capacities for motion, strength, and endurance are present, restoration becomes the focus. Physical therapy and rehabilitation programs can help improve these deficits, restoring functional abilities and enhancing overall quality of life.
In some cases, compensation may be necessary to adapt for limited motion. This can involve modifying activities or using assistive devices to improve function and reduce the risk of further injury. Ultimately, a proactive approach to musculoskeletal health can help individuals maintain optimal function and mobility throughout their lives.

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