Complete question is;
Which of these is an exponential parent function?
A. f(x) = x
B. f(x) = 2^(x)
C. f(x) = x²
D. f(x) = |x|
Answer:
B. f(x) = 2^(x)
Step-by-step explanation:
> In option A, f(x) = x
This function depicts a straight line with intercept as 0 and slope as 1.
> In option C, f(x) = x²
This function depicts a parabola open up since the leading coefficient is greater than 0.
> In option D: f(x) = |x|
This function depicts a straight line y = x for x > 0 and y = -x for x < 0
In option B f(x) = 2^(x)
This function depicts an exponential function because the x is in the exponent form with a base of 2.
How do you subtract mixed fractions with different denominators examples?
Answer: To subtract mixed fractions with different denominators, you need to convert the mixed fractions to equivalent fractions with a common denominator. Once the fractions have a common denominator, you can simply subtract the numerators and keep the denominator the same.
Example:
the difference of 2 1/3 and 1 3/4 is 5/12.
Step-by-step explanation:
First, convert 2 1/3 to an improper fraction: 2 1/3 = 7/3
Next, convert 1 3/4 to an improper fraction: 1 3/4 = 7/4
Now, both fractions have the same denominator, 3. So, you can subtract the numerators:
7/3 - 7/4 = (7 * 4 - 7 * 3) / (3 * 4) = 28/12 - 21/12 = 7/12
Finally, convert the answer back to a mixed fraction: 7/12 = 7 ÷ 12 = 5/12.
ten kids line up in a random order. there are three boys and seven girls in the group. let x be a random variable denoting the number of boys in the front half of the line. what is e[x]?
The expected value of the random variable X, denoting the number of boys in the front half of the line, is E[X] ≈ 1.5.
To find the expected value of the random variable X, which denotes the number of boys in the front half of the line, follow these steps:
1. Determine the total number of ways the kids can line up, which is 10! (10 factorial) since there are 10 kids.
2. Calculate the number of ways to choose 5 kids for the front half of the line: C(10, 5) = 10! / (5! * 5!).
3. For each possible value of X (0, 1, 2, or 3 boys in the front half), compute the probability of that value occurring:
- P(X=0): C(7, 5) * C(3, 0) / C(10, 5) [5 girls, 0 boys]
- P(X=1): C(7, 4) * C(3, 1) / C(10, 5) [4 girls, 1 boy]
- P(X=2): C(7, 3) * C(3, 2) / C(10, 5) [3 girls, 2 boys]
- P(X=3): C(7, 2) * C(3, 3) / C(10, 5) [2 girls, 3 boys]
4. Multiply each probability by its corresponding value of X and sum the products:
- E[X] = P(X=0)*0 + P(X=1)*1 + P(X=2)*2 + P(X=3)*3
Following these, you'll find that the expected value of the random variable X, denoting the number of boys in the front half of the line, is E[X] ≈ 1.5.
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Which equation is graphed?
Answer:
C
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b ) a point on the line
Calculate m using the slope formula
m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)
with (x₁, y₁ ) = (- 2, 2 ) and (x₂, y₂ ) = (2, - 4) ← 2 points on the line
m = \(\frac{-4-2}{2-(-2)}\) = \(\frac{-6}{2+2}\) = - \(\frac{6}{4}\) = - \(\frac{3}{2}\)
and using (a, b ) = (2, - 4 ) , then
y - (- 4) = - \(\frac{3}{2}\)(x - 2) , that is
y + 4 = - \(\frac{3}{2}\) (x - 2) → C
onsider an nxn matrix A with the property that the row sums all equal the same number s. Show that s is an eigenvalue of A. [Hint: Find an eigenvector.] In order for s to be an eigenvalue of A, there must exist a nonzero x such that Ax = Sx. n For any nonzero vector v in R", entry k in Avis ĉ Arivin i = 1 Which choice for v will allow this expression to be simplified using the fact that the rows all sum to s? O A. the vector v; = i for i = 1, 2, ..., n B. the vector or v; =n-i+ 1 for i = 1, 2, ..., n = a vector v; = C +i for i = 1, 2, ..., n and any integer C D. the zero vector VE = 0 E. a vector v; = C for any real number C Use this definition for v; and the property that the row sums of A all equal the same number s to simplify the expression for entry k in Av. (AV)k
We have shown that the row sum s is an eigenvalue of the matrix A with eigenvector x = (1, 1, ..., 1)T.
To show that s is an eigenvalue of the nxn matrix A, we need to find a nonzero vector x such that Ax = sx, where s is the row sum of A. One way to find such a vector is to take the vector x = (1, 1, ..., 1)T, where T denotes transpose.
Using this choice of x, we have
Ax = (s, s, ..., s)T = sx,
which shows that s is indeed an eigenvalue of A with eigenvector x.
To see why this works, consider the kth entry of Av for any nonzero vector v in R^n. We have
(Av)_k = ∑ A_ki v_i, i=1 to n
where A_ki denotes the entry in the kth row and ith column of A. Since the row sums of A all equal s, we can write
(Av)_k = ∑ A_ki v_i = s ∑ v_i
where the sum on the right-hand side is taken over all i such that A_ki is nonzero.
If we take v = x, then we have ∑ v_i = nx, and hence
(Ax)_k = s(nx) = (ns)x_k,
which shows that x is an eigenvector of A with eigenvalue s.
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simplify the complex rational expression
Answer:
\(2(x+2)/x+1\)
Step-by-step explanation:
Answer:
2( x +2 )
x+1
Step-by-step explanation:
to add or subtract expressions expand them to make their denominators the same, multiply 1 time \(\frac{x-2}{x-2}\)
since \(\frac{x}{x-2}\) and \(\frac{x-2}{x-2}\) have the same denominators add them by adding their numerators
combine x + x -2
factor \(x^{2}\) - 4
to add or subtract expressions expand them and multiply by 1
have same denominator add them by adding their numerators
do the multiplications in 3 + ( x-2 )(x+2)
combine like terms in 3 + \(x^{2}\) + 2x - 2x -4
divide \(\frac{2x-2}{x-2}\) by \(\frac{-1 + x^{2} }{(x-2)(x+2) }\) multiplying \(\frac{2x-2}{x-2}\)
cancel out x-2 in both numerator and denominator
factor the expression that are not already factored
cancel out x-1 in both numerator and denominator
expand the expression
Trinity drives 3 miles then walks another 930 yd. How many feet does she
travel in total?
What is an equation of the line that passes through the points (-6, -3) and
(-8,-4)
Answer:
Equation is Y=x/2
Step-by-step explanation:
Find the gradient of the line : graduent= -4-(-3)÷ -8-(-6) which = to 1\2Sustitutes any of the values of y and x coordinates and your gradient in order to find the value of c: Y =mx + c : (-4)=1/2(-8) + c then C =OY=x/2please help need both answers please will give 30 points please i need both answered i dont need work shown i just need both answers please
Answer:
Angle A = Angle L
Angle D = Angle M
Angle C = Angle N
Segment AB = Segment LB
Segment CD = Segment NM
Segment DA = Segment ML
2nd part
Quadrilateral URST has moved by a translation of (x-5,y+2)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Find the angle between vector bold lower u equals 3 bold lower I plus start root 3 end root bold lower j and vector bold lower v equals negative 2 bold lower I minus 5 bold lower j to the nearest degree. A. 82° B. 38° C. 142° D. 98°
Answer:
C. 142°
Step-by-step explanation:
You want the angle between vectors u=3i+√3j and v=-2i-5j.
AngleThere are a number of ways the angle between the vectors can be found. For example, the dot-product relation can give you the cosine of the angle:
u•v = |u|·|v|·cos(θ) . . . . . . where θ is the angle of interest
You can find the angles of the vectors individually, and subtract those:
u = |u|∠α
v = |v|∠β
θ = α - β
When the vectors are expressed as complex numbers, the angle between them is the angle of their quotient:
\(\dfrac{\vec{u}}{\vec{v}}=\dfrac{|\vec{u}|\angle\alpha}{|\vec{v}|\angle\beta}=\dfrac{|\vec{u}|}{|\vec{v}|}\angle(\alpha-\beta)=\dfrac{|\vec{u}|}{|\vec{v}|}\angle\theta\)
This method is used in the calculation shown in the first attachment. The angle between u and v is about 142°.
A graphing program can draw the vectors and measure the angle between them. This is shown in the second attachment.
__
Additional comment
The approach using the quotient of the vectors written as complex numbers is simply computed using a calculator with appropriate complex number functions. There doesn't seem to be any 3D equivalent.
The dot-product relation will work with 3D vectors as well as 2D vectors.
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Solve the right triangle. Round decimal answers to the nearest tenth.
A right triangle X Y Z with base X Y is drawn. The length of side Y Z is 18 units and length of side X Z is 25 units. Angle X Y Z is a right angle.
The length of the hypotenuse is approximately 30.8 units.
The angle at vertex X is approximately 36.9 degrees.
The angle at vertex Y is approximately 35.2 degrees.
In your problem, we have a right triangle XYZ, where the angle at vertex Y is the right angle. The length of leg YZ is given as 18 units, and the length of leg XZ is given as 25 units.
In this particular problem, we can use the sine ratio to solve for the length of leg XY. Specifically, we have:
sin(XYZ) = XY / XZ
Since we know that XYZ is a right angle (i.e., 90 degrees), we can substitute in the appropriate values to get:
sin(90) = XY / 25
Since the sine of 90 degrees is 1, we can simplify this to:
1 = XY / 25
Multiplying both sides by 25 gives us:
XY = 25
So the length of leg XY is 25 units.
To find the other angles in the triangle, we can use the inverse trigonometric functions (such as arcsine or arccosine). For example, we can use the cosine ratio to solve for the angle at vertex X:
cos(XYZ) = XZ / hypotenuse
cos(90) = 25 / hypotenuse
0 = 25 / hypotenuse
Since the cosine of 90 degrees is 0, we know that hypotenuse = 25 / 0 is undefined. However, we can use the Pythagorean theorem to find the length of the hypotenuse:
hypotenuse² = XY² + XZ²
hypotenuse² = 25² + 18²
hypotenuse² = 625 + 324
hypotenuse² = 949
Taking the square root of both sides gives us:
hypotenuse = √(949) ≈ 30.8
Now that we know the lengths of all three sides of the triangle, we can use the sine and cosine ratios to solve for the other angles. For example, to find the angle at vertex X, we can use the cosine ratio:
cos(X) = XZ / hypotenuse
cos(X) = 25 / 30.8
cos(X) ≈ 0.811
Taking the inverse cosine (or arccosine) of both sides gives us:
X ≈ 36.9 degrees
Similarly, we can use the sine ratio to find the angle at vertex Y:
sin(Y) = YZ / hypotenuse
sin(Y) = 18 / 30.8
sin(Y) ≈ 0.584
Taking the inverse sine (or arcsine) of both sides gives us:
Y ≈ 35.2 degrees
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5 (t+3)=-3.5 solve for t
Answer:
t=-3.7
Step-by-step explanation:
5 (t+3)=-3.5
solving the bracket we have;
5t+15=-3.5
collect like terms
5t=-3.5-15
5t=-18.5
divide both sides by 5;
t=-3.7
The value of t in the given algebraic expression is; t = -2.3
We are given the equation;
5(t + 3) = 3.5
Using distributive property on the left hand side, we have;
5t + (5 × 3) = 3.5
5t + 15 = 3.5
Using subtractive property of equality, subtract 15 from both sides to get;
5t + 15 - 15 = 3.5 - 15
5t = -11.5
Divide both sides by 5 to get;
5t/5 = -11.5/5
t = -2.3
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evaluate the integral by reversing the order of integration. 4 0 12 11ex2 dx dy 3y
To evaluate the integral by reversing the order of integration, we first need to draw the region of integration. From the given limits of integration, we can see that the region is a rectangle with vertices at (0,4), (0,12), (11,4), and (11,12).
Now, we can reverse the order of integration by integrating with respect to y first, and then x. The new limits of integration will be y = 4 to y = 12 and x = 0 to x = 11e^(2y/3).
So, the new integral will be:
∫(0 to 11) ∫(4 to 12) 3y e^(2x/3) dy dx
We can evaluate this integral using integration by parts. Integrating with respect to y gives us:
∫(0 to 11) [3y^2/2 e^(2x/3)] from y = 4 to y = 12
Simplifying this expression gives us:
∫(0 to 11) [36e^(2x/3) - 6e^(8x/3)]/2 dx
Now, integrating with respect to x gives us:
[27e^(2x/3) - 9e^(8x/3)] from x = 0 to x = 11
Substituting these values and simplifying gives us the final answer:
(27e^22/3 - 9e^88/3) - (27 - 9) = 27e^22/3 - 9e^88/3 - 18
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Please help me with this question.
Answer:
aww i help u.....
Step-by-step explanation:
my answer is letter ~~B CAUSE STUDEN BIS CONDYCTION LIKR FREE AT THE SCORED
I need help with solving these math problems please!!!
Answer:
In the triangle below the red side is a leg and should be labeled a . The pink side is a leg and should be labeled b. and the light blue side is the hypotenuse and should be labeled c.
In right triangles the angles are labeled with upper case letters and the sides are labeled with lower case letters.
Step-by-step explanation:
what proportion of customers need an oil change who wait 9 minutes or less?
The proportion of customers who require an oil change and wait for nine minutes or less is 0.07.
The information provided by the question can be used to calculate the percentage of customers who wait for nine minutes or less, and the percentage of customers who wait for nine minutes or less and require an oil change. This information can be used to find out the ratio between these two percentages, which is the percentage of customers who wait for nine minutes or less and require an oil change.
The proportion of customers who require an oil change and wait for nine minutes or less can be calculated using the following formula:
Proportion of customers who require an oil change and wait for nine minutes or less = (Number of customers who require an oil change and wait for nine minutes or less) / (Total number of customers who wait for nine minutes or less)
The number of customers who wait for nine minutes or less and require an oil change is 35. The total number of customers who wait for nine minutes or less is 500. Thus, the proportion of customers who require an oil change and wait for nine minutes or less is:
Proportion of customers who require an oil change and wait for nine minutes or less = 35/500 = 0.07 or 7%.
Thus, 7% of customers who wait for nine minutes or less require an oil change.
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Complete Question:
Using classes of 0-4, 5-9, and so on, show the proportion of customers needing an oil change who wait 9 minutes or less.
The owner of an automobile repair shop studied the waiting times for customers who arrive at the shop for an oil change. The following data with waiting times in minutes were collected over a 1-month period:
2 5 10 12 4 4 5 17 11 8 9 8 12 21 6 8 7 13 18 3
Determine whether the graph represents a function. *
Answer:
Not a function
Step-by-step explanation:
There are two points that correspond to the same variable
Hope this helps
Answer:
not a function
Step-by-step explanation:
There are two points that have the same x and different y values
This would fail the vertical line test.
a) Fill in the table of values for
the equation
b) Draw the straight line y = 2x - 3
How do I put the line on the graph?
The equation shows that we need the graph of a line with a slope of 2 and cross the y-axis at (0, -3)
A line is defined as the shortest distance between two points. The equation of a line in slope-intercept form is given as:
y = mx +b
where
m is the slopeb is the y-interceptAccording to the question we are to graph the equation y = 2x- 3. This means that we need the graph of a line with a slope of 2 and cross the y-axis at (0, -3)
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suppose that q(x) is the statement ""x 2 = 2x."" what are the truth values of the following statements? assume x is representing all real numbers.
The truth values of the given statements in terms of q(x) are: q(0) is true, q(1) is false, q(-2) is false, and q(2) is true.
The statement q(x) is x² = 2x. Now, we will check the truth value of each statement in terms of q(x):
(i) q(0): \(0^2=2\times 0\)
q(0): 0 = 0; so, the statement q(0) is true.
(ii) q(1): \(1^2=2\times 1\)
q(1): 1 = 2; so, the statement q(1) is false.
(iii) q(-2): \((-2)^2=2\times (-2)\)
q(-2): 4 = -4; so, the statement q(-2) is false.
(iv) q(2): \(2^2=2\times 2\)
q(2): 4 = 4; so, the statement q(2) is true.
So, the truth values of the given statements in terms of q(x) are: q(0) is true, q(1) is false, q(-2) is false, and q(2) is true.
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Determine if the following pairs of lines are parallel, perpendicular, or neither.
x+y = -3
x+y = 5
I need help please I need it ASAP
Answer:
Step-by-step explanation:
Answers and explanations in attachment. Problem 29 was cut off a bit. I assumed the question was what percent of the total are cubs.
Creates a histogram in kotlin that allows you to inspect the frequency visually.
Kotlin code has had nine or fewer lines.
The program should generate 200 random integers in the range 1 through 100 inclusive and store these into an array. Loop through the array and sort the ranges so that you can then print out the report.
Produce a chart like the one indicated at the bottom. How many values fell in the range 1 to 10, 11 to 20, and so on. Print one asterisk for each value entered.
Range # Found Chart
-------- ---------- -------------------------------------------
1 - 10 | 28 | ****************************
11 - 20 | 18 | ******************
21 - 30 | 21 | *********************
31 - 40 | 26 | **************************
41 - 50 | 23 | ***********************
51 - 60 | 7 | *******
61 - 70 | 18 | ******************
71 - 80 | 24 | ************************
81 - 90 | 14 | **************
91 - 100 | 22 | *********************
The complete code to create a histogram in Kotlin that allows you to inspect the frequency visually with nine or fewer lines is shown below:import kotlin.random.
Randomfun main() {val array = Array(200) { Random.nextInt(1, 101) }array.sort()var i = 1while (i < 100) {val count = array.count { it < i + 10 && it >= i }println("${i} - ${i + 9} | ${count} | " + "*".repeat(count))i += 10}}
The program above first generates an array of 200 random integers between 1 and 100 inclusive. It then sorts the array in ascending order. Next, the program loops through the ranges from 1 to 100 in steps of 10.
Within the loop, the program counts the number of elements in the array that fall within the current range and prints out the corresponding row of the histogram chart.
Finally, the program increments the loop variable by 10 to move to the next range and continues the loop.
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HELP, WILL GIVE BRAINLEST..
Factor the GCF: -6x³y + 9x²y2 - 12xy³ (5 points)
O 3xy(-2x² + 3xy - 4y²)
O-3xy(2x² + 3xy - 4y²)
O-3xy(2x2-3xy + 4y²)
O-3(2x³y - 3x²y² + 4xy³)
Answer:
\(\sf -3xy\left(2x^2-3xy+4y^2\right)\)
Step-by-step explanation:
\(\sf -6x^3y+9x^2y^2-12xy^3\)
To factor the GCF of 6x³y + 9x²y2 - 12xy³ let's apply the exponent rule:-
\(\boxed{\sf a^{b+c}=a^ba^c}\)
\(\boxed{\sf x^3y=xx^2y,\:x^2y^2=xxyy,\:xy^3=xyy^2}\)
\(\sf -6xx^2y+9xxyy-12xyy^2\)
Rewrite,
-6 as 2 * 39 as 3 * 3-12 as 4 * 3\(\sf 2\cdot \:3xx^2y+3\cdot \:3xxyy+4\cdot \:3xyy^2\)
Now, factor out the common term \(\sf -3xy\):-
\(\sf -3xy\left(2x^2-3xy+4y^2\right)\)__________________________
Simplify 1/2+2/3-1/4
Answer:
11/12
Step-by-step explanation:
State if the given functions are inverses.
1)
F(x)=1/2x -2
g(x) = 2x + 4
Answer:
Yes
Step-by-step explanation:
if \(f(x)=\frac{1}{2}x-2\) then what is \(f^-1(x)\) (the inverse of f(x)? let's find out\(f(x)=\frac{1}{2}x-2\\y=\frac{1}{2}x-2\) make f(x) into yThen make y into x and make x into y so \(x=\frac{1}{2}y-2\)\(x=\frac{1}{2}y-2\) now get the new y on the left and everything else on the right\(x=\frac{1}{2}y-2\\x+2=\frac{1}{2}y\\2(x+2)=(2)\frac{1}{2}y\\y=2x+4\) now make y = g(x)\(g(x)=2x+4\) So you found the inverse of f(x) and it is the same as g(x), so the functions are inverses of each otherHow do you write the slope-intercept form of the equation of the line through the given point and parallel to the given line?.
The slope-intercept form of the equation of the line through the given point and parallel to the given line is y=x−14.
In the given question we have to write the slope-intercept form of the equation of the line through the given point and parallel to the given line.
The given points are (–2, –16).
The given equation of line is y = x – 5.
Standard equation of line is y=mx+c.
After comparing to the standard equation.
Slope m(1) = 1
The line passes through (−2,−16), so the point will satisfy the equation y=mx+c. So
−16=−2*1+c
Simlifying
−16=−2+c
Add 2 on both side, we get
c = −16+2
c = −14
As we know that if line is parallel then
m(1)=m(2)
So the value of solpe m = 1
Now the equation of line
y=1*x+(−14)
y=x−14
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The right answer is:
How do you write the slope-intercept form of the equation of the line through the given point and parallel to the given line?
Point (−2,−16), y = x – 5
how does a form differ from shape? form is defined by its allegiance to mathematical construction. form has more than three sides. form has the third dimension of depth. shape has more volume than form. save
Form refers to three-dimensional objects with depth, while shape pertains to the two-dimensional outline or boundary of an object.
We have,
In the context of geometry and visual representation, the terms "form" and "shape" have distinct meanings and characteristics.
Form generally refers to a three-dimensional object that has depth, such as a solid object or a structure with volume.
It encompasses objects that have length, width, and height, and it extends beyond a two-dimensional representation.
Form can have irregular or complex shapes and is not limited to a specific number of sides.
Shape, on the other hand, refers to the two-dimensional outline or boundary of an object.
It is limited to the external appearance or silhouette of an object without considering its depth or volume.
Shapes are typically described by their attributes, such as the number of sides (e.g., triangle, square) or specific geometric properties (e.g., circle, rectangle).
Thus,
Form refers to three-dimensional objects with depth, while shape pertains to the two-dimensional outline or boundary of an object.
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Suppose a bag contains 6 red balls and 5 blue balls. How may ways are there of selecting 5 balls from the bag, consisting of 3 red balls and 2 blue balls? (After selecting a ball you do not replace it.)
There are 60 ways of selecting 5 balls from the bag, consisting of 3 red balls and 2 blue balls.
To calculate the number of ways, we can break it down into two steps:
Selecting 3 red balls
Since there are 6 red balls in the bag, we need to calculate the number of ways to choose 3 out of the 6. This can be done using the combination formula: C(n, r) = n! / (r! * (n - r)!), where n is the total number of items and r is the number of items to be chosen. In this case, we have C(6, 3) = 6! / (3! * (6 - 3)!), which simplifies to 6! / (3! * 3!) = (6 * 5 * 4) / (3 * 2 * 1) = 20.
Selecting 2 blue balls
Similarly, since there are 5 blue balls in the bag, we need to calculate the number of ways to choose 2 out of the 5. Using the combination formula, we have C(5, 2) = 5! / (2! * (5 - 2)!), which simplifies to 5! / (2! * 3!) = (5 * 4) / (2 * 1) = 10.
To find the total number of ways, we multiply the results from Step 1 and Step 2 together: 20 * 10 = 200.
Therefore, there are 200 ways of selecting 5 balls from the bag, consisting of 3 red balls and 2 blue balls.
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170 people are asked how many siblings they have?
# of Siblings Frequency Relative Frequency Cumulative Frequency
0 33 0.1941 1 36 0.2118 69
2 35 0.2059 104
3 142
4 28 0.1647 170
a. Complete the table (Use 4 decimal places when applicable)
b. What percent of the people have exactly one sibling? %
Can you please explain how you to do this?
The approximately 21.18% of the people surveyed have exactly one sibling.
To complete the table, we need to calculate the cumulative frequency, which is the sum of the frequencies up to and including the given value.
The table should look like this:
# of Siblings Frequency Relative Frequency Cumulative Frequency
0 33 0.1941 33
1 36 0.2118 69
2 35 0.2059 104
3 42 0.2471 146
4 or more 24 0.1412 170
To find the percentage of people who have exactly one sibling, we need to look at the frequency for that value and divide it by the total number of people (which is the last value in the cumulative frequency column). Then we multiply by 100 to convert to a percentage.
So, the percentage of people who have exactly one sibling is:
(36 / 170) x 100%
= 21.18%
Therefore, approximately 21.18% of the people surveyed have exactly one sibling.
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Which of the following is a line through the point (-1, 2) with a slope of
in graph form
The equation of the line passing through the point (-1,2) with slope m is y = mx + m-2. This is a general equation of the line and we can find different equations by putting different values of m.
We know that when a point and slope of the equation are given, an equation can be written as
\(\frac{y-y_{1} }{x - x_{1} } =m\)
which is known as the slope-point form
where m is the slope of the equation
y1 is the y coordinate of the given point
x1 is the x coordinate of the given point
In the given question, y1 = 2 and x1 = -1
Substituting the value of coordinates in the slope point equation, we get
\(\frac{y-2}{x-(-1)} = m\)
\(\frac{y-2}{x+1}=m\)
y-2 = mx + m
y = mx + m-2
Hence, the equation of the line passing through the point (-1,2) with slope m is y = mx + m-2.
To learn more about the slope:
https://brainly.com/question/3605446
What is the equation of the line passing the point (-1, 2) with a slope m?
Use a calculator to simplify: N (-8 - 92.5) / -32
Answer:
3.14
Step-by-step explanation:
-8 - 92.5 = -100.5, and then -100.5/(-32) = 3.14
Alternatively, type in (-8 -92.5)/(-32)