Answer:
kinetic energy increases because of speed and motion overall
Explanation:
dont know if i helped you but you can give me a thumbs down if you hate the answer or it is not the answer you are looking for
the largest hydroelectric dam in the world is located on one of the world’s longest rivers in this area.
The largest hydroelectric dam in the world is the Three Gorges Dam, located on the Yangtze River in China.
The Yangtze River is the longest river in Asia and the third-longest river in the world, with a total length of approximately 6,300 km. The Yangtze River Basin is a vital economic and cultural region in China, supporting more than 400 million people and serving as a major transportation artery.
The Three Gorges Dam was built to provide hydroelectric power, improve river navigation, and control flooding in the Yangtze River Basin. The dam is approximately 2.3 km long and 185 meters tall, with a reservoir capacity of over 39 billion cubic meters of water.
The Three Gorges Dam is an impressive engineering feat and has significant economic and environmental impacts on the region. The dam provides clean and renewable energy, supports increased river transportation, and helps prevent devastating floods that have historically occurred in the Yangtze River Basin.
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Complete question is:
Largest hydroelectric dam in the world is located on one of the world’s longest rivers. Where is the dam located?
A 0.450-kg baseball comes off a bat and goes straight up. At a height of 10.0 m, the baseball has a speed of 24.5 m/s.
a) Determine its mechanical energy at this height. Show your work. 2 marks
b. What is the baseball’s mechanical energy when it is at a height of 9.0 m? Explain your answer.
(a) The mechanical energy of the baseball of mass 0.45 kg at a height of 10m is 179.16 J (b) The mechanical energy of the baseball at a height of 9 m is 174.75 J.
What is mechanical energy?mechanical energy is sum of the kinetic energy, or energy of motion, and the potential of a body.
Formula:
M.E = mv²/2+mgh................... Equation 1Where:
M.E = Mechanical energyV = Velocity of the base ballm = Mass of the baseballh = Heightg = Acceleration due to gravity(a) To calculate the mechanical energy of the baseball at an height of 10m, we use the formula above
Given:
m = 0.45 kgv = 24.5 m/sh = 10 mg = 9.8 m/s²Substitute these values into equation 1
M.E = (0.45×24.5²)/2 + 0.45×9.8×10M.E = 135.06+44.1M.E = 179.16 J(b) Similarly At a height of 9 m, we substitute into equation 1
M.E = (0.45×24.5²)/2+0.45×9.8×9M.E = 135.06+39.69M.E = 174.75 JFrom the answer, the height only affect the potential energy not the kinetic energy.
Hence, (a) The mechanical energy is 179.16 J (b) The mechanical energy at a height of 9 m is 174.75 J.
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45. people are walking through a dimly lit town at night. trash cans are blown over by a very strong wind and crash to the ground, directly in front of or behind some of the people and directly to the left or right of others. who will be able to locate where the sound came from most quickly and easily?
Answer:
Explanation:
The people who experienced the sound directly to the left or right of them.
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a person stands on a scale in an elevator. as the elevator starts, the scale has a constant reading of 598 n. as the elevator later stops, the scale reading is 384 n. assume the magnitude of the acceleration is the same during starting and stopping. (a) determine the weight of the person. n (b) determine the person's mass. kg (c) determine the magnitude of acceleration of the elevator.
The magnitude of the acceleration of the elevator is approximately 3.51 \(m/s^2\).
(a) The scale reading when the elevator is at rest gives the normal force acting on the person, which is equal in magnitude to the person's weight. Thus, the weight of the person is 598 N when the elevator is at rest.
(b) The weight of an object is given by the product of its mass and the acceleration due to gravity.
weight = mass x acceleration due to gravity
598 N = mass x 9.81 \(m/s^2\)
mass = 60.9 kg
Therefore, the person's mass is approximately 60.9 kg.
(c) We can use Newton's second law (F = ma) to find the acceleration of the elevator. The net force acting on the person is given by:
net force = final force - initial force
net force = 384 N - 598 N
net force = -214 N
net force = mass x acceleration
-214 N = 60.9 kg x acceleration
acceleration = -3.51 \(m/s^2\)
Therefore, the magnitude of the acceleration of the elevator is approximately 3.51 \(m/s^2\).
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consider the titration of 100.0 ml of 0.200 m acetic acid (ka by 0.100 m koh. calculate the ph of the result- ing solution after the following volumes of koh have been added.
Answer: The pH of the solution after 50.5 mL of 0.100 M KOH has been added is 16.85.
The reaction between acetic acid and potassium hydroxide (KOH) is given by the equation:
CH3COOH + KOH → CH3COOK + H2O.
It can be observed that for every mole of KOH added, one mole of H+ from CH3COOH reacts with one mole of OH- from KOH to produce one mole of H2O. Therefore, after the addition of n moles of KOH, the number of moles of H+ remaining is (0.200 - n) moles (since 0.200 M is the initial concentration of acetic acid). On the other hand, the number of moles of CH3COOK produced is also n moles; thus the final concentration of CH3COOK is n/V (where V is the total volume of the solution).
The reaction produces a salt (CH3COOK), which is neutral. Therefore, the final pH is given by: pH = pKa + log([A-]/[HA]) where A- is CH3COOK and HA is CH3COOH.
To find the pH of the resulting solution after the following volumes of KOH have been added, we need to calculate the number of moles of KOH added, the number of moles of CH3COOK produced, the number of moles of CH3COOH remaining, and the total volume of the solution. Then we can use the Henderson-Hasselbalch equation above to find the pH.
Here are the calculations: Initial number of moles of CH3COOH = M × V = 0.200 × 0.100 = 0.020 moles. For each mole of KOH added, one mole of CH3COOH reacts with one mole of KOH to produce one mole of CH3COOK.Number of moles of KOH added Volume of KOH added (mL)Moles of KOH added0.02 0.00 (initial) 0.000.02 10.10 0.010.02 20.20 0.020.02 30.30 0.030.02 40.40 0.040.02 50.50 0.05Number of moles of CH3COOK produced = number of moles of KOH added = n moles. Concentration of CH3COOK produced = n/V = n/(Vinitial + V added) = n/(0.100 L + V added)
Number of moles of CH3COOH remaining = initial number of moles - number of moles of KOH added = 0.020 - n moles. Total volume of the solution after the addition of KOH = V initial + V added = 0.100 L + V added. We can then use the Henderson-Hasselbalch equation to find the pH: pH = pKa + log([A-]/[HA])where A- is CH3COOK and HA is CH3COOH.pKa of acetic acid = 4.76
Let's tabulate the values of n, [A-], [HA], and pH for each volume of KOH added: Number of moles of KOH added n (moles)Concentration of CH3COOK produced [A-] (M)
Number of moles of CH3COOH remaining [HA] (M)pH0.000.000.020.76 (initial)0.010.010.019.84 0.020.020.018.98 0.030.030.018.20 0.040.040.017.49 0.050.050.016.85.
The pH of the solution after 50.5 mL of 0.100 M KOH has been added is 16.85.
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1.) A negative charge of -2.0x10-4 C and a positive charge of 8.0x10-4 C are
separated by 0.30 m. What is the force between the two charges?
Answer:
The Force between the two charges is an attractive force of 16,000N
Explanation:
Expression for the electric force between the two charges is given by
F = (k*q1*q2) / r^2
Here, k = constant = 9 x 10^9 N*m^2 / C^2
q1 = - 2.0x10^-4C
q2 = + 8.0x10^-4C
r = 0.30 m
Substitute the given values in the above expression -
One charge is + and the other is a -, therefore the net force is an attractive force (opposites atract)
The attraction force is:
F= 9.0x10^9 * 2.0x10^-4 *8.0x10^-4 N/ 0.30^2
F= 16,000N
The force between the two charges will be 16,000 N.It is the force exerted by one charge on another charge.
What is electric force?The electric force between the two charges is directly propotional to the product of the charge and inversly propotional to the square of the distance between them.
The given data in the problem is;
q₁ is the megnitude of charge 1= - 2.0x10⁻⁴ C
q₂ is the megnitude of charge 2 = + 8.0x10⁻⁴ C
k is the propotionallity constant = 9 x 10⁹ Nm² / C²
r is the seperated distance = 0.30 m
F is the electric force=?
The electric force is found as;
\(\rm F = \frac{K q_14q_2}{r^2} \\\\ \rm F = \frac{9 \times 10^9 \times 2.0 \times 10^{-4}}{(0.30)^2} \\\\ \rm F = 16,000N\)
Hence the force between the two charges will be 16,000 N.
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Rita has two small containers, one holding a liquid and one holding a gas. Rita transfers the substances to two larger containers. Compare the behavior of the atoms in the liquid and in the gas once they are moved to the larger containers
Answer: liquids take the shape of the container they are in, but have definite volume. like liquids the shape of a gas changes with the container. unlike liquids the volume of a gas changes depending on the container it is in
Explanation:
Answer:
liquids flow freely, they take the shape of the container they are in, but have a definite volume. Like liquids, the shape of a gas changes with the container. This is because the atoms in a gas move rapidly and freely to fill any available space. Unlike liquids, the volume of a gas changes depending on the container it
Explanation
A dockhand rolls a barrel up a plank 6.40 m long. the barrel weighs 425 n and is displaced a height of 1.28 m. the dockhand exerts a constant force of 95.0 n parallel to the plank. a. what work is needed to overcome friction? (64.0 j) b. what is the efficiency of the person?
Work done required to overcome friction is 696.96 J. Efficiency of work is 95.5 %.
Work is done when a force does displacement in an object in the direction of the force. The energy required to do work translates into work. Its converse is also true. Work done gets stored in the form of potential energy.
Work = Force × displacement in the direction of the force
Work is a scalar quantity even though it is the dot product of two vector quantities - force and displacement.
Total distance to be displaced = 6.40m + 1.28m
= 7.68m
Net force acting on the barrel = 95-4.25 N
= 90.75 N
So, W = F × S
= 90.75 ×7.68 J
= 696.96 J
Efficiency of work = (output/ input ) × 100
If there would be no weight force and no friction, then amount of work would be = 95 × 7.68 J
= 729.6 J
So, efficiency of work = (696.96 / 729.6 ) × 100
= 95.5%
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Deduce the dimension formula for force
Answer:
M¹L¹T^-2
Explanation:
M¹L¹T^-2
.....
Its electron charge distribution or probability density is spherically symmetric
If the electron charge distribution or probability density of a particle is spherically symmetric, it means that the likelihood of finding the electron at given distance from the nucleus is same in all directions.
This type of distribution is often observed in atoms with only one electron, such as hydrogen, and is described by the wave function. The wave function represents the probability density of finding an electron in a particular location in space, and a spherically symmetric distribution means that the probability density is the same at all points on a spherical surface around the nucleus.
A situation where the electron charge distribution or probability density is spherically symmetric.
In this context, the electron charge distribution refers to how the negative charge of electrons is spread out in space. Probability density describes the likelihood of finding an electron in a particular region of space. When these two properties are spherically symmetric, it means that they are evenly distributed in all directions around a central point, forming a sphere.
For example, the hydrogen atom's ground state (1s orbital) has a spherically symmetric electron charge distribution and probability density. The electron is equally likely to be found in any direction around the nucleus, and the charge distribution is uniform in all directions. This symmetry results from the wavefunction for the electron in this orbital being dependent only on the distance from the nucleus, not on the angles in spherical coordinates.
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PLS HELP I NEED ANSWER HOMEWORK DUE SOON
A ball is initially moving with a velocity 0.5m/s. Its velocity decreases at a rate of 0.05m/s^2. How much time will it take to stop? How much distance will the ball travel before it stops
Answer:
I think its 1
Explanation:
The reason why I think it's 1 is because 0.5m/s^2 /0.5 m/s= 1 s
an indestructible bullet 2.00 cmlong is fired straight throught the board that is 10cm thick the bullet strikes th board with a speed
The indestructible bullet, 2.00 cm long, will penetrate straight through the 10 cm thick board with its initial speed.
When an indestructible bullet is fired straight through a board, its length and the thickness of the board are relevant factors in determining whether the bullet will pass through or get lodged inside. In this case, the bullet is 2.00 cm long, while the board is 10 cm thick.
Since the bullet is described as indestructible, it implies that the bullet will not deform or break upon impact with the board. As a result, the bullet will continue moving through the board, provided its length is smaller than the thickness of the board.
With the given information, we can conclude that the indestructible bullet, being 2.00 cm long, will penetrate straight through the 10 cm thick board. The initial speed of the bullet does not affect this outcome, as long as it meets the condition of being smaller in length than the board's thickness.
It is important to note that this explanation assumes ideal conditions, where the bullet and board are perfectly aligned, and there are no external factors affecting the motion of the bullet. In practical scenarios, various factors such as angle, velocity, and material properties can influence the bullet's behavior upon impact.
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The half life of a material is 100 years. If you have 1000g, how much will remain after 500 years?
The trip takes approximately 2 hours and covers approximately 1900 km. Which of the following best describes the velocity of the jets flight?
950 km/h southwest
950 km/h
3800 km/h southwest
3800 km/h
Answer:
The answer is 950km/hExplanation
step one:
In this exercise, we are expected to solve for the velocity that best describes the filght of jets given the following data
step two
data
time taken t= 2 hours
distance coverd= 1900km
we know that speed= distance/time taken
i.e s=d/t
step three:
substituting our into the expression we can solve for s
s= 1900/2
s= 950km/h
Hence the velocity that best describes the flight is 950km/h
a hanging spring has length 10 cm. a 100 g mass is hung from the spring, stretching it to 12 cm. what will be the length of the spring if this mass is replaced by a 200 g mass?
The length of the spring when a 200 g mass is hung will be 410 cm.
To determine the new length of the spring when a 200 g mass is hung instead of a 100 g mass, we can use Hooke's Law , which states that the elongation of a spring is directly proportional to the applied force.
Let's denote the initial length of the spring as L1 (10 cm) and the final length when the 100 g mass is hung as L2 (12 cm). We can calculate the spring constant (k) using the formula:
k = (m * g) / ΔL
where m is the mass (in kg), g is the acceleration due to gravity (approximately 9.8 m/s²), and ΔL is the change in length.
For the 100 g mass:
k = (0.1 kg * 9.8 m/s²) / (0.12 m - 0.1 m) = 0.49 kg/s²
Now, we can use the spring constant to find the new length (L3) when a 200 g mass is hung:
L3 = L1 + (m * g) / k
= 10 cm + (0.2 kg * 9.8 m/s²) / (0.49 kg/s²)
= 10 cm + 4 m
= 410 cm
Therefore, the length of the spring when a 200 g mass is hung will be 410 cm.
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How to convert 3 hrs and 40 min to sec
Please answer with solution.
ACTIVITY 4
Applying the equation learned, answer the following problems:
1. A bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s. What is its momentum? p = m/s. What Is Its Momentum?
Given:
Find:
Formula:
Solution:
2. A skateboard is rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s. What is its mass?
Given:
Find:
Formula:
Solution:
3. A pitcher throws a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s. What is its velocity?
Given:
Find:
Formula:
Solution:
Subject Is Science
Good Perfect Complete=Brainlist
Copy Wrong Incomplete=Report
Good Luck Answer Brainly Users:-)
Answer:
1) 10 kg-m/s
2) 2 kg
3) 20 m/s
Explanation:
The momentum of an object can be calculated using the equation:
\(\large\boxed{p=mv}\)
where:
p is momentum (measured in kilogram meters per second).m is mass (measured in kilograms).v is the velocity (measured in meters per second).\(\hrulefill\)
Question 1For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.
Given values:
m = 4.0 kgv = 2.5 m/sSubstitute the given values into the momentum formula and solve for p:
\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)
\(p=10\;\text{kg m/s}\)
Therefore, the momentum of the bowling ball is 10 kg-m/s.
\(\hrulefill\)
Question 2For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.
Given values:
p = 6.0 kg-m/sv = 3.0 m/sAs we want to find mass, rearrange the momentum formula to isolate m:
\(\large\boxed{m=\dfrac{p}{v}}\)
Substitute the given values into the formula and solve for m:
\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)
\(m=2\;\text{kg}\)
Therefore, the mass of the skateboard is 2 kg.
\(\hrulefill\)
Question 3For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.
Given values:
p = 10 kg-m/sm = 0.5 kgAs we want to find velocity, rearrange the momentum formula to isolate v:
\(\large\boxed{v=\dfrac{p}{m}}\)
Substitute the given values into the formula and solve for v:
\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)
\(v=20\;\text{m/s}\)
Therefore, the velocity of the baseball is 20 m/s.
The law of conservation of energy states that (1 point) Group of answer choices all energy in the universe comes from the sun and remains in the same form energy is neither created nor destroyed; it is transformed and transferred new energy within a system is converted or transferred and destroyed as it is used energy is created from the sun and is transformed from one type to another
The law of conservation of energy states that energy is neither created nor destroyed; it is transformed and transferred (option B).
What is the law of conservation of energy?The law of conservation of energy is a principle stating that energy may not be created or destroyed but can only be transformed i.e. converted from one form to another.
This means that a system always has the same amount of energy, unless it's added from the outside.
The law states that the total energy of an isolated system remains constant; it is said to be conserved over time.
Therefore, according to this question, the law of conservation of energy is described correctly by option B.
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what force pushes groundwater from pore space to pore space when below the water table?
The force that pushes groundwater from pore space to pore space when below the water table is primarily due to the pressure gradient within the aquifer. This pressure gradient is caused by the weight of the overlying water and the force of gravity.
Below the water table, the spaces between soil or rock particles are filled with water. These spaces are known as pore spaces. The water table represents the upper surface of the saturated zone, where all the pore spaces are filled with water. gravity acts vertically downward, causing the weight of the water above a particular point to exert a downward force. As a result, the water pressure increases with depth. This increase in pressure creates a pressure gradient within the aquifer.
The pressure gradient drives the flow of groundwater from areas of higher pressure to areas of lower pressure. When a well is drilled into the aquifer below the water table, water will naturally flow into the well and rise to the level of the water table. This is because the pressure is higher below the water table compared to the lower pressure in the well.
The movement of groundwater from pore space to pore space occurs due to the pressure difference between adjacent spaces. Water will flow from areas of higher pressure to areas of lower pressure until the pressures equalize. This movement of water is known as groundwater flow or hydraulic conductivity.
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he cars mass was only 111 kg. Suppose two of these cars are used in a stunt crash for an action film. If one car's initial velocity is 9.00 m/s to the right and the other car's velocity is 5.00 m/s to the left, how much kinetic energy is discinated in the crash
In the crash 5883 Joule kinetic energy is discinated when two of these cars are used in a stunt crash for an action film.
How do you use start kinetic energy to calculate end kinetic energy?Final kinetic energy (KE) is equal to 1/2 m1v'12 + 1/2 m2v'22 , or joules. The end kinetic energy for common things will be lower than the starting point. The only way you can increase kinetic energy is if the impact causes an energy release of some type.
How can total kinetic energy be calculated?As a result, the kinetic energy equation states that it is equal to 1/2 the object's mass times the magnitude of its velocity squared, or speed squared.
Initial kinetic energy KE,
\(KE=1/2 m_1v_1^2 + 1/2 m_2v_2^2\)
\(KE=1/2 (111)(9.00)^2 + 1/2 (111)(5.00)^2\)
\(KE= 4495.5+1387.5\)
\(KE= 5883J\)
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A car travelling at a constant velocity along a motorway covers a distance of 1.00 km in 50.0 s. To maintain this velocity the car produces a driving force of 230 N. Calculate the effective power of the car engine in maintaining this motion.
Answer:
The answer for Power is 4600W or 4.6KW
Explanation:
Power is the time rate of doing work
Power=Work done/time
P=F×d/t
convert 1km to m
1km=1000m
P=230×1000/50
P=230000/50
P=4600W
P=4.6KW
A 3-ton Toyota land cruiser travelled at a speed of 45m/s, collides with a 2- ton comfort taxi which was parked in front of the traffic lights intersection. After the collision, both cars lock together and move off in one direction. Determine the speed of cars after collision.
Answer:
v = 27 m/s
Explanation:
To find the speed of cars after the collision you take into account the momentum conservation law. Total momentum of both cars before the collision must be equal to the total momentum of both cars after the collision.
After the collision both cars traveled together, then you have:
\(m_1v_1+m_2v_2=(m_1+m_2)v\) (1)
m1: mass of the Toyota = 3-ton = 3000 kg
m2: mass of the taxi = 2-ton = 2000kg
v1: speed of the Toyota before the collision = 45m/s
v2: speed of the car before the collision = 0 m/s (it is at rest)
v: speed of both cars after the collision = ?
You solve the equation (1) for v:
\(v=\frac{m_1v_1+m_2v_2}{m_1+m_2}\)
Next, you replace the values of the rest of the variables:
\(v=\frac{(3000kg)(45m/s)+0kgm/s}{3000kg+2000kg}=27\frac{m}{s}\)
hence, just after the collision both cars have a speed of 27m/s
the blocks shown below are placed on a smooth horizontal surface and connected by a piece of string. if a 8.8-n force is applied to the 8.8-kg block, what is the tension in the string?
When a 8.8 N force is applied to the 8.8 kg block connected to another block by a string, the tension in the string can be determined. The tension in the string is equal to the applied force because the blocks are connected and the system is in equilibrium.
In this scenario, the blocks are connected by a string, and the system is at rest on a smooth horizontal surface. When an external force is applied to one of the blocks, it creates tension in the string, which is transmitted to the other block.
Since the system is in equilibrium, the tension in the string must be equal to the applied force. This is because, in equilibrium, the net force acting on each block is zero. The tension in the string balances the applied force and prevents any acceleration or motion of the blocks.
Therefore, the tension in the string is 8.8 N, which is equal to the applied force. This ensures that the system remains in equilibrium, with no net force acting on either block.
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Explain the challenges in developing an accurate rating system for earthquakes. What kinds of variables are there?
Answer:
In turn, the main factors affecting earthquake shaking intensity are earthquake depth, proximity to the fault, the underlying soil, and building characteristics—particularly height. Let's take a look at the latter two (soil and buildings) and how they interact.
The challenge in developing an accurate rating system for earthquakes is due to complicated relationship between variables such as magnitude and intensity of earthquake.
Earthquakes are associated with magnitude and intensity.
The challenge in developing an accurate rating system for earthquake is due to complicated relationship and dependency between the magnitude and intensity of the earthquake.
Intensity of earthquake is the observed effects resulting from the earthquake such as; shaking of buildings, people etc. This intensity of the earthquake depends on the location of the observer with respect to earthquake epicenter.The magnitude of the earthquake relates to the amount of energy released during the earthquake.Thus, the challenge in developing an accurate rating system for earthquakes is due to complicated relationship between variables such as magnitude and intensity of earthquake.
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Suppose a particle moves along a straight line with velocity meters per second after seconds.
Many meters will a particle have traveled after t seconds if it is moving in a straight line at a velocity of v(t)=t2e2t meters per second?
What are velocity and speed?In contrast to velocity, which describes the speed and direction of such an object's movement, speed is the rate of movement along a path. Alternatively, velocities is a vector while speed is just a scalar quantity.
Why is there a velocity formula?Velocity (v), which can be expressed by the expression v = s/t, is still a tensor quantity that determines dislocation (or the shift in position, s), over change in time (t).
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A 1,075 N sky diver has opened his parachute to slow his descent to a constant
speed the parachute applies 1,469 N of force. What deceleration does he
experiences?
The deceleration experienced by the 1075 N sky diver as he opened his parachute is 13.39 m/s²
How to determine the decelerationForce = mass × acceleration
We know that deceleration is the acceleration of stopping objects. Thus,
Force (F) = mass (m) × deceleration (a)
Thus, we can obtain the deceleration of the sky diver as follow:
Weight of diver (W) = 1075 NForce (F) = 1469 NAcceleration due to gravity (g) = 9.8 m/s²Mass of diver = W / g = 1075 / 9.8 = 109.69 KgDeceleration (a) =?Force = mass (m) × deceleration (a)
1469 = 109.69 × a
Divide both sides by 109.69
a = 1469 / 109.69
a = 13.39 m/s²
Thus, the deceleration is 13.39 m/s²
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What does the change in momentum and impulse have in common?
Answer:
Momentum is a vector quantity that has the same direction as the velocity of the object. The quantity of force multiplied by the time it is applied is called impulse. Impulse is a vector quantity that has the same direction as the force. Momentum and impulse have the same units: kg·m/s
Explanation:
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A psychologist wants to identify how the holiday season impacts the anxiety levels of Americans. She wants to get results on the feelings of anxiety from over one million Americans in the next month. What design should she use and why?
Answer: survey
Explanation:
A survey can be an interview or a questionnaire which is given to a particular group in order to know their characteristics or opinions, towards certain issues.
Since the psychologist wants to get results on the feelings of anxiety from over one million Americans in the next month, the survey should be used.
If a lever (of any class) has a mechanical advantage of 1. 5, how much effort should be required to move a resistance point weighing 300 grams?
To determine the effort required to move a resistance point weighing 300 grams (0.3 kg) using a lever with a mechanical advantage of 1.5, we can use the formula for mechanical advantage:
Mechanical Advantage = Load / Effortwhere Load refers to the resistance or weight being lifted, and Effort is the force applied to the lever.Given that the mechanical advantage is 1.5 and the Load is 0.3 kg, we can rearrange the formula to solve for Effort:Effort = Load / Mechanical AdvantageEffort = 0.3 kg / 1.5Effort ≈ 0.2 kgTherefore, the effort required to move the resistance point weighing 300 grams using a lever with a mechanical advantage of 1.5 is approximately 0.2 kg of force.
Learn more about mechanical here:
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If Bert the Bat travels eastward at 40 mph with a tailwind of 6 mph, what is his actual speed?
Answer:
36 mph.
Explanation:
Now Albert here is using the wind to his advantage but if say there was no wind then he would not have the 6 mph behind him so we subtract 6 from 40 to get 36. hope this helps :)