Taking into account the definition of molar mass,
In first place, the rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.
That is, what is intended with it is to find the fourth term of a proportion knowing the other three.
If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied.
To solve a direct rule of three, the following formula must be followed, being a, b and c known data and x the variable to be calculated:
a ⇒ b
c ⇒ x
So: \(x=\frac{cxb}{a}\)
The direct rule of three is applied in this case, knowing that the molar mass of Cu is 63.54 \(\frac{g}{mole}\), this is the amount of mass a substance contains in one mole.
So: if 63.54 grams of Cu are contained in 1 mole, 65.8 grams of Cu are contained in how many moles?
63.54 grams ⇒ 1 mole
65.8 grams ⇒ x
So: \(x=\frac{65.8 gramsx1 mole}{63.54 grams}\)
\(x= 1.04 moles\)
Finally, the correct answer is option A. 1.04 moles of copper (Cu) are in 65.8 g Cu.
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A. 1.04 mol Cu
Explanation:
I just took the exam
If you had 6H2 molecules and 4O2 molecules, how many H2O molecules could you produce?
Answer:
6
Explanation:
As , 2H2 + O2 = 2H2O
with 6 H2, 4O2 is excess.
H2O molecules formed = 6
Identity the organic function group in the following?
We can see here that the organic function of cannabinol is its interaction with the endocannabinoid system (ECS) in the human body.
The organic function of procainamide lies in its ability to block sodium channels in cardiac cells, leading to a decrease in the excitability of the heart muscle and a suppression of abnormal electrical signals.
What is Procainamide?Procainamide is a medication used primarily in the treatment of cardiac arrhythmias, specifically ventricular arrhythmias. It belongs to a class of drugs known as antiarrhythmics, which work by regulating the electrical activity of the heart.
In addition to its antiarrhythmic properties, procainamide also possesses mild anticholinergic effects, which contribute to its overall pharmacological profile.
Cannabinol (CBN) is a cannabinoid compound found in the cannabis plant. While it is not as well-known as other cannabinoids like THC and CBD, it has some notable organic functions and potential effects on the body.
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5. Where would you find the focus of an earthquake?
Earth Science .
Answer:
below the surface
Explanation:
classify N a + as cation, anion or neither
which type of chemical bond would be formed between two elements having electron configuration of 1s2 2s2 2p6 3s2 and 1s2 2s2 2p4
Arsenate (AsO43-) is structurally and chemically similar to inorganic phosphate (PO43-), and many enzymes that act on phosphate will also use arsenate as a substrate if it is available. However, unlike phosphates, organic compounds of arsenate are kinetically unstable. For example, acyl phosphates (such as 1,3-bisphosphoglycerate) require an enzyme to catalyze phosphate hydrolysis on a biologically relevant timescale, but acyl arsenates hydrolyze almost instantaneously in water without an enzyme.
a) Predict the effect on the net reaction catalyzed by glyceraldehyde 3-phosphate dehydrogenase if phosphate were replaced by arsenate.
b) Write a balanced overall equation for the conversion of glucose to pyruvate in the presence of ATP, ADP, NAD+, and arsenate.
c) Arsenate is extremely toxic to most organisms. Based on your answers above, explain why.
Answer:
A) The effect on the net reaction catalyzed by glyceraldehyde is that
The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )
B) There will be no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived
C ) Arsenate is very toxic to most organisms and it is used mostly regarded as poisons during the formation of glycolysis, it forms 1-arsen0, 3-phosphoglycerate which hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells
Explanation:
A) The effect on the net reaction catalyzed by glyceraldehyde is that
The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )
B) There will be no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived
C ) Arsenate is very toxic to most organisms and it is mostly regarded as poisons during the formation of glycolysis, it forms 1-arsen0, 3-phosphoglycerate which hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells
Those structures that are similar in all behavior is called homologous structure.
The answer of the following question is as follows:-
The effect on the net reaction catalyzed by glyceraldehyde is that the 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase ) There will be no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived Arsenate is very toxic to most organisms and it is used mostly regarded as a poison during the formation of glycolysis, it forms 1-arsen0, 3-phosphoglycerate which hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of a cell.For more information, refer to the link:-
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Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia.
N2(g)+3H2(g)⟶2NH3(g)
There are four molecules of nitrogen and nine molecules of hydrogen present in the diagram.
When the reaction is complete, how many molecules of NH3 are produced?
What is the limiting reactant?
How many molecules of each reactant are remain after the reaction is complete?
After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.
In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.
So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.
To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.
Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol
Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.
The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.
Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.
Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.
To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.
The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol
Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.
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Match the atoms to their type of bond.Phosphorus (P)and oxyger )?lonicSilver (Ag) andsilver (Ag)?CovalentChlorine (CI) andsodium (Na)?Metallic
Explanation:
To determine if a bond is ionic or covalent we will have to find the electronegativity difference between the atoms that are participating in the bond.
P and O:
Electronegativity of P = 2.19
Electronegativity of O = 3.44
ED of O-P = 3.44 - 2.19
ED of O-P = 1.29
Since the electronegativiy difference between O and P is less than 2.1 the bond is covalent.
Ag and Ag:
Since we are considering the bond between two atoms of the same metal the bond is metallic.
Cl and Na:
Electronegativity of Cl = 3.16
Electronegativity of Na = 0.93
ED of Cl-Na = 3.16 - 0.93
ED of Cl-Na = 2.23
Since the electronegativiy difference between Cl and Na is greater than 2.1 the bond is ionic.
Answer:
O-P ---> covalent
Ag-Ag ---> metallic
Cl-Na ---> ionic
The half-life of Zn-71 is 2.4 minutes. If one had 100.0 g at the beginning, how many grams would be left after 7.2 minutes has elapsed? Report your answer to 1 decimal place.
Answer:
12.5g
Explanation:
Half life = 2.4 Minutes.
The half life of a compound is the time it takes to decay to half of it's original concentration or mass.
Time lapsed= 7.2 minutes. This is equivalent to 3 half lives ( 3 * 2.4)
Initial mass = 100g
First half life;
100g --> 50g
Second half life;
50g --> 25g
Third half life;
25g --> 12.5g
The amount of Zn-71 that remains after 7.2 mins has elapsed is 12.5 g
We'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:
Half-life (t½) = 2.4 mins
Time (t) = 7.2 mins
Number of half-lives (n) =?\(n = \frac{t}{t_{1/2}} \\\\n = \frac{7.2}{2.4} \\\\\)
n = 3Thus, 3 half-lives has elapsed.
Finally, we shall the amount remaining. This can be obtained as follow:Original amount (N₀) = 100 g
Number of half-lives (n) = 3
Amount remaining (N) =?\(N = \frac{N_{0}}{2^{n}} \\\\N = \frac{100}{2^{3 }}\\\\N = \frac{100}{8}\\\\\)
N = 12.5 gThus, the amount of Zn-71 that remains after 7.2 mins is 12.5 g
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Difference between sublimate and distillate
Answer:
distillate is the liquid that has been condensed from vapour during distillation; normally a purified form or a fraction of an original liquid while sublimate is (chemistry) a product obtained by sublimation
DEFINITION: ABILITY OF A SUBSTANCE TO BE DISSOLVED
Answer:
Solubility
Explanation:
If its not that the answer is Dissolvable.... you didn't give a word bank.
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Are these both considered lewis structureseven though one of them has lines
Yes, both of them are considered lewis structures
ExplanationsLewis structures are ways in which the valence electron of a compound are arranged around its elements using dots. It represents and shows how electrons are arranged around individual atoms.
In lewis structure, electrons are represented as dots and if it is a bonding electron, it can be represented as lines. Since the elements in the compound given are both non-metals, they are covalently bonded. This shows the reason why one of the lewis structures contains lines.
Which elements most easily give up electrons?
A.Oxygen, hydrogen, lithium
B.Copper, gold, silver
C.Copper, oxygen, silver
D.Silver, iodine, helium
combustion always result in to formation of water. what other type of reactions may result into formation of water? examples of these reactions
As combustion always result into the formation of water, the other type of reactions that may result into formation of water are Acid-Base Neutralization Reactions and Hydrogen and Oxygen Reaction.
Acid-Base Neutralization Reactions:
A neutralisation reaction is a chemical process in which an acid and a base combine to produce salt and water as the end products.
H⁺ ions and OH⁻ ions combine to generate water during a neutralisation reaction. Acid-base neutralisation is the most common type of neutralisation reaction.
Example: Formation of Sodium Chloride (Common Salt):
HCl + NaOH → NaCl + H₂O
Hydrogen and Oxygen Reaction:
Water vapour is created when hydrogen gas (H₂) and oxygen gas (O₂) are combined directly. This reaction produces a lot of heat and releases a lot of energy.
Example: 2 H₂ + O₂ → 2 H₂O
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What is the mass of 6.02 x 1024 molecules of the compound HCl?
Answer:
First, we need to determine the molar mass of HCl.
The molar mass of HCl = the mass of hydrogen (1.008 g/mol) + the mass of chlorine (35.45 g/mol) = 36.45 g/mol.
Next, we can use Avogadro's number (6.02 x 10^23 molecules/mol) to convert the number of molecules to moles:
6.02 x 10^24 molecules / 6.02 x 10^23 molecules/mol = 10 moles
Finally, we can use the molar mass to convert moles to grams:
10 moles x 36.45 g/mol = 364.5 grams
Therefore, the mass of 6.02 x 10^24 molecules of HCl is 364.5 grams.
Science begins with an observation, true or false?
Answer:
I think that might be true ?
Explanation:
since in science you have to observe its see anything happen
what happens to a rock that has rainwater entering its cracks and then freezing
Answer:
Physical weathering is caused by the effects of changing temperature on rocks, causing the rock to break apart.
Explanation:
Freeze-thaw occurs when water continually seeps into cracks, freezes and expands, eventually breaking the rock apart.
pOH of the 0.001M NaOH solution is
The pOH of the 0.001 M NaOH solution is approximately 3.
To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.
In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.
The pOH is calculated using the equation:
pOH = -log[OH-]
Substituting the concentration of hydroxide ions, we have:
pOH = -log(0.001)
Using a calculator, we can evaluate the logarithm:
pOH ≈ 3
Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.
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Which type of cell is shown in the following image?
Answer:
A prokaryotic cell is shown in the image
Explanation:
Prokaryotic cells are the most basic types. Since they are basic, they don't have a nucleus. All eukaryotic cells have it but prokaryotic cells don't have it. A nucleus contains organelles such as a mitochondria which the diagram doesn't show as well. Thus a prokaryotic cell is shown in the image.
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Homework Answered Due Today, 11:59 PM
The reaction 3H₂(g) + N₂(g) → 2NH3(g) has an enthalpy of reaction of -92.6 kJ/mol. If 1 g of hydrogen and 2 g of nitrogen are
reacted, how much heat is produced (kJ)?
The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ
How do i determine the heat energy produced?First, we shall obtain the limiting reactant. Details below:
3H₂ + N₂ -> 2NH₃
Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 g Molar mass of H₂ = 2 g/molMass of H₂ from the balanced equation = 3 × 2 = 6 gFrom the balanced equation above,
28 g of N₂ reacted with 6 g of H₂
Therefore,
2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂
We can see that only 0.43 g of H₂ is needed in the reaction.
Thus, the limiting reactant is N₂
Finally, we the amount of heat energy produced. Details below:
3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ
Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 gFrom the balanced equation above,
When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.
Therefore,
When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ
Thus the heat energy produced from the reaction is -6.61 KJ
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Answer the questions below:
1.Give an example of something that has matter.
2.Give an example of something that doesn't have matter.
3.What is the difference between an chemical change and a physical change?
4.What 2 main kind of changes can you observe involve chemical reactions?
5.What is a precipitate?
6.What is the difference between an endothermic reaction and an exothermic reaction?
Answer:
1. An apple is something that has matter.
2. Light does not have matter. It neither has mass or takes up and space.
3. Physical changes only change the appearance of a substance, not its chemical composition. Chemical changes cause a substance to change into an entirely substance with a new chemical formula. Chemical changes are also known as chemical reactions.
4. A chemical reaction is usually accompanied by easily observed physical effects, such as the emission of heat and light, the formation of a precipitate, the evolution of gas, or a color change. Absolute confirmation of a chemical change can only be validated by chemical analysis of the products!
5. A precipitate is a solid that forms out of solution.
6. In simple terms, the endothermic reactions absorb energy from the surrounding that is in the form of heat. On the other hand, an exothermic reaction releases energy into the surrounding of the system.
Explanation:
Matter is anything that has mass and takes up volume.
Answer:
1. some thing that has matter is an apple, a person,a table. things that does 2.not Light.,Sound.,Heat.Energy.Gravity.Time.A Rainbow.Love.
3. Physical changes only change the appearance of a substance, not its chemical composition. Chemical changes cause a substance to change into an entirely substance with a new chemical formula. Chemical changes are also known as chemical reactions.
4.A chemical reaction is usually accompanied by easily observed physical effects, such as the emission of heat and light, the formation of a precipitate, the evolution of gas, or a color change. Absolute confirmation of a chemical change can only be validated by chemical analysis of the products!
5.Precipitate: In chemistry, a solid formed by a change in a solution, often due to a chemical reaction or change in temperature that decreases solubility of a solid. In meteorology a precipitate is liquid or solid water (rain, snow, etc.) falling from the sky.
6.n simple terms, the endothermic reactions absorb energy from the surrounding that is in the form of heat. On the other hand, an exothermic reaction releases energy into the surrounding of the system.
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How much water has to be evaporated from 250 mL of 1 M Ca(OH)2 to make it 3 M?
Approximately 166.67 mL of water needs to be evaporated from 250 mL of 1 M Ca(OH)2 to make it 3 M.
To find the amount of water that needs to be evaporatedThe relationship between the initial and final concentrations and volumes must be taken into account.
Given: Initial concentration \((C^1) = 1 M Initial volume (V^1) = 250 mL\)
\((C^2) = 3 M final concentration\)
We can use the equation:
\(C^1 * V^1 = C^2 * V^2\)
Where:
\(V^2\)is the final volume of the solution
Rearranging the equation to solve for V2:
\(V^2 = (C^1 * V^1) / C^2\)
Substituting the given values:
\(V^2 = (1 M * 250 mL) / 3 M\)
\(V^2 = 250 mL / 3\)
\(V^2\) ≈ \(83.33 mL\)
To find the amount of water that needs to be evaporated, we subtract the final volume from the initial volume:
Amount of water to be evaporated = \(V^1 - V^2\)
Amount of water to be evaporated = 250 mL - 83.33 mL
Amount of water to be evaporated ≈ 166.67 mL
Therefore, approximately 166.67 mL of water needs to be evaporated from 250 mL of 1 M Ca(OH)2 to make it 3 M.
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Name the substance in red blood cells that carbon monoxide from cigarette smoke combines with.
The substance in red blood cells that carbon monoxide from cigarette smoke combines with is called hemoglobin.
Hemoglobin is a protein molecule found in red blood cells that is responsible for transporting oxygen from the lungs to the rest of the body. Hemoglobin consists of four subunits, each containing a heme group. The heme group contains an iron ion, which binds to oxygen molecules in the lungs.
Carbon monoxide (CO) from cigarette smoke can bind to the iron ion in the heme group with a much greater affinity than oxygen. When CO binds to hemoglobin, it forms a stable complex called carboxyhemoglobin (COHb).
This reduces the amount of hemoglobin available for binding with oxygen, which can lead to a reduction in the amount of oxygen that can be transported to the tissues.
The formation of COHb can also affect the release of oxygen from hemoglobin in the tissues. Hemoglobin releases oxygen in response to a decrease in oxygen concentration, which is sensed by the heme group. However, when CO binds to the heme group, it alters the shape of the hemoglobin molecule and reduces its ability to release oxygen.
As a result, the presence of carbon monoxide in the blood can lead to a range of health problems, including headaches, dizziness, shortness of breath, and even death in severe cases.
The best way to prevent carbon monoxide poisoning is to avoid exposure to smoke from tobacco products and other sources of combustion, such as gas heaters and stoves.
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What’s an equation showing the beta decay of the Hydrogen-3
Answer:
Explanation:
Thus, negative beta decay results in a daughter nucleus, the proton number (atomic number) of which is one more than its parent but the mass number (total number of neutrons and protons) of which is the same. For example, hydrogen-3 (atomic number 1, mass number 3) decays to helium-3 (atomic number 2, mass number 3)
Polyethylene is 86.0% C and 14.0%
H. Determine the empirical formula of the compound.
Percent to Mass: How many grams of C/and Hare present in 100.0 g?
The empirical formula of polyethylene can be determined by converting the given percentages of carbon (C) and hydrogen (H) into grams. To find the grams of each element, we assume a 100.0 g sample of polyethylene.
For carbon:
Mass of carbon = 86.0% × 100.0 g = 86.0 g
For hydrogen:
Mass of hydrogen = 14.0% × 100.0 g = 14.0 g
Therefore, in a 100.0 g sample of polyethylene, there are 86.0 grams of carbon and 14.0 grams of hydrogen.
The empirical formula of a compound represents the simplest whole-number ratio of atoms present in the compound. To determine the empirical formula, we need to find the ratio of carbon to hydrogen in terms of moles.
First, we convert the masses of carbon and hydrogen into moles using their respective molar masses. The molar mass of carbon is approximately 12.01 g/mol, and the molar mass of hydrogen is approximately 1.008 g/mol.
Number of moles of carbon = 86.0 g / 12.01 g/mol ≈ 7.162 mol
Number of moles of hydrogen = 14.0 g / 1.008 g/mol ≈ 13.89 mol
Next, we divide the number of moles of each element by the smallest number of moles to get a simplified ratio.
Carbon: Hydrogen ≈ 7.162 mol : 13.89 mol ≈ 1 : 1.939
Since we want to express the ratio in whole numbers, we multiply both sides by 2 to get a whole number ratio.
Carbon: Hydrogen ≈ 2 : 3.878
Rounding to the nearest whole number, we find that the empirical formula of polyethylene is CH₂.
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Ionic compounds in own words
an ionic compound is made of two or more elements held by a strong electrostatic force. metal atoms lose electrons to become positive ions, and non metals gain electrons to become negative ions. ionic bonding occurs between metals and non metals
What is the mass of percent of 10 g solute in 105 g solvent?
The mass of the percent of the 10 g solute in the 105 g solvent is 8.69 %.
The mass of the solute = 10 g
The mass of the solvent = 105 g
The mass of the solution = 10 g + 105 g
The mass of the solution = 115 g
The mass of the percent is expressed as :
The mass of percent = ( mass of solute / mass of solution ) × 100 %
The mass of solute = 10 g
The mass of solution = 115 g
The mass of percent = ( 10 / 115 ) × 100 %
The mass of percent = 8.69 %
Thus, the mass of percent is 8.69 % and the mass of solute is 10 and the mass of the solution is 115 g.
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What does Etching , Stratches and sample size impact hardness results of metals
Answer:
Etching is used to reveal the microstructure of the metal through selective chemical attack. It also removes the thin, highly deformed layer introduced during grinding and polishing. ... The specimen is etched using a reagent.
Explanation:
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describe two sources of energy and explain how they work
please help me (50points)
Solar energy:-
In this way the energy generated through sun light with the help of solar panels and to be used in many works.
Wind energy:-
This is generated by moving turbines with windmills .It is used to create electric energy
How would you use a serial dilution to create about 50.00 ml each of 0.10M, 0.20M, 0.30M and 0.40M solution (using beforehand solution) starting from a stock solution of 10.0M HCl?
Answer:
uty tyuuuuuuuuuA) 1,280
B) 320
C) 144
C) 80
Explanation:
A) 1,280
B) 320
C) 144
C) 80