Answer:
Step-by-step explanation:
find the anglewhose complement is 1/4 its supplement
Answer:
The angle is 60°------------------
Let the angle be x.
Its complement is 90 - x and its supplement is 180 - x.
Set up an equation to reflect that its complement is 1/4 its supplement:
90 - x = (1/4)(180 - x)4(90 - x) = 180 - x360 - 4x = 180 - x4x - x = 360 - 1803x = 180x = 600. A rental agency charges $80 to rent a car. They also charge $0.10 for each mile Hillary has
udgeted $200 for a car rental fee. How many miles con she drive and stay under budgen?
Answer
1200
Step-by-step explanation:
initial fee: $80
per mile: $0.10
budget:$200
200-80=120
120 divided by 0.10 = 1200
you can drive 1200 miles with a budget of $200
pls pls help with this. extra points. why would i use factoring to solve this quadratic equation?
Answer: x =
-1/6 -2
explanation:
I looked it up on Math
way
Answer: x=-2 x=-1/6
Step-by-step explanation: you can use factoring to solve this becuase it is factorable to real numbers. You would want to use quadratic formula is there is an imaginary number or square roots.
(6x+1)(x+2)=0
set them both equal to zero and solve, foil your answer
Problem 1 Unit Conversion The density of gold is approximately p= 19.32 g/cm³: what is the density of gold in kg/m³? (5 points)
Answer:
19320 kg/m³
Step-by-step explanation:
Pre-SolvingWe are given that the density of gold is 19.32 g/cm³, and we want to convert that density to kg/m³.
We can solve this in a manner similar to dimensional analysis, which is common in chemistry. When we do dimensional analysis, we use conversion factors with labels that we cancel out in order to get to the labels that we want.
SolvingRecall that 1 kg is 1000 g, and 1 m³ is cm. These will be our conversion factors.
So, we can do the following:
\(\frac{19.32g}{1 cm^3} * \frac{1000000 cm^3}{1 m^3} * \frac{1kg}{1000g}\) = 19320 kg/m³
So, the density of gold is 19320 kg/m³.
When the price of a good is $5, the quantity demanded is 100 units per month; when the price is $7, the quantity demanded is 80 units per month. Using the midpoint method, the price elasticity of demand is about.
Using the midpoint method, the price elasticity of demand is approximately -0.67.
To calculate the price elasticity of demand using the midpoint method, we'll use the following formula:
Price Elasticity of Demand (Ed) = (% change in quantity demanded) / (% change in price)
First, let's find the percentage changes:
% change in quantity demanded = ((New Quantity Demanded - Old Quantity Demanded) / Midpoint of Quantities) * 100
= ((80 - 100) / ((100 + 80) / 2)) * 100
= (-20 / 90) * 100
= -22.22%
% change in price = ((New Price - Old Price) / Midpoint of Prices) * 100
= ((7 - 5) / ((5 + 7) / 2)) * 100
= (2 / 6) * 100
= 33.33%
Now, let's plug the values into the formula:
Ed = (-22.22% / 33.33%)
= -0.67
So, the price elasticity of demand is approximately -0.67.
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∠A and ∠B are complementary. If m∠B = 64° , what is the measure of ∠A?
26°
36°
11°
64°
Answer: 26
Step-by-step explanation:
Two Angles are Complementary when they add up to 90 degrees (a Right Angle). Then
∠A + ∠B = 90
∠A =90- ∠B
∠A = 26
Answer:
The measure of \(\angle A\):
\(\angle A = 26\textdegree\)
Step-by-step explanation:
Since both \(\angle A\) and \(\angle B\) are complementary (Which they both add up to 90°), and you want to find the measure of
Measure of \(\angle A\): unknown
Measure of \(\angle B\): 64°
Finding the measure of \(\angle A\):
\(90 - 64 = 26\)
\(\angle A = 26\textdegree\)
So, the measure for \(\angle A\) is \(26\textdegree\).
Triangle A has side lengths 2, 3, and 4. Triangle B has side lengths 4, 5, and 6. Is Triangle A similar to Triangle B ? (will give brainliest)
Answer:
No
Step-by-step explanation:
Describe how to determine the average rate of change between x = 2 and x = 4 for the function f(x) = 2x3 + 1. Include the average rate of change in your answer.
The average rate of change of the function given is 56
Rate of change of a functionThe formula for calculating the rate of change of a function is expressed as;
f'(x) = f(b)-f(a)/b-a
where
b = 4
a = 2
f(4) = 2(4)^3 +1
f(4) = 129
f(2) = 2(2)^3 + 1
f(2) = 17
Substitute
f'(x) = 129-17/4-2
f'(x) = 112/2
f'(x) = 56
Hence the average rate of change of the function given is 56
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How much would $120 invested at 6% interest compounded monthly be
worth after 21 years? Round your answer to the nearest cent.
A(t)= P(1+r/n)^nt
Answer:
$421.72
Step-by-step explanation:
Compounded Monthly Interest Rate Formula: A = P(1 + 4/12)^12t
Simply plug in our known variables:
A = 120(1 + 0.06/12)²¹⁽¹²⁾
A = 120(1.005)²⁵²
A = 120(3.51437)
A = 421.724
Which of the following functions shows the quadratic parent function, F(x) =
x2, shifted left?
Answer: choice B
Step-by-step explanation:
just took the quiz
omm its B. G(x)=(x+8)^2
just took the test
PLEASE HELP (LOOK AT THE PICTURE)
Which of the equations matches the line shown in the diagram?
A
B)
y=-x-1
C)
D)
Answer:
The answer should be D) y = 5/3x - 1/3
Step-by-step explanation: The slope is positive ruling out the negative slope answers leaving C and D, however D is the only answer to get the y intercept correct.
Suppose that the metal used for the top and bottom of the soup can costs 4 cents per square centimeter, while the sides of the can cost only 2 cents per square centimeter. Find the minimum cost of a soup can. What dimensions will it be
The minimum cost of a soup can is 12 times the cube root of the volume of the can divided by 2π, and the dimensions of the can are given by:
\(r = (V/(2\pi ))^{(1/3)}\\h = 2V/[(\pi (V/(2\pi ))^{(1/3))}]\)
To find the minimum cost of a soup can, we need to optimize the surface area of the can while considering the cost of each square centimeter of metal used.
Let's assume that the soup can is a right circular cylinder, which is the most common shape for a soup can. Let the radius of the can be "r" and the height be "h". Then, the surface area of the can is given by:
A = 2πr² + 2πrh
To minimize the cost, we need to minimize the surface area subject to the constraint that the volume of the can is fixed. The volume of a cylinder is given by:
V = πr²h
We can solve for "h" in terms of "r" using the volume equation:
h = V/(πr²)
Substituting this value of "h" into the surface area equation, we get:
A = 2πr² + 2πr(V/(πr²))
A = 2πr² + 2V/r
Now, we can take the derivative of the surface area with respect to "r" and set it equal to zero to find the value of "r" that minimizes the surface area:
dA/dr = 4πr - 2V/r² = 0
4πr = 2V/r²
r³ = V/(2π)
Substituting this value of "r" back into the equation for "h", we get:
h = 2V/(πr)
Therefore, the dimensions of the can that minimize the cost are:
\(r = (V/(2\pi ))^{(1/3)}\\h = 2V/[(\pi (V/(2\pi ))^{(1/3))]\)
To find the minimum cost, we need to calculate the total cost of the metal used. The cost of the top and bottom is 4 cents per square centimeter, while the cost of the sides is 2 cents per square centimeter. The area of the top and bottom is:
A_topbottom = 2πr²
The area of the sides is:
A_sides = 2πrh
Substituting the values of "r" and "h" we found above, we get:
\(A_topbottom = 4\pi (V/(2\pi ))^{(2/3)}\\A_sides = 4\pi (V/(2\pi ))^{(2/3)}\)
The total cost is:
\(C = 2(4\pi (V/(2\pi ))^{(2/3)}) + 4(4\pi (V/(2\pi ))^{(2/3)}) = 12(V/(2\pi ))^{(2/3)\)
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HEELLP PLS-123 Write as a decimal number. 500
Answer:
0.246
hope this helps!
Answer:
It is 0.246
Step-by-step explanation:
123÷500=0.246
HELP ME I WILL BRAINLIST U
Answer:
C
Step-by-step explanation:
This question you can use simple elimination, can save you time if it's right. Obviously its not A or B as the hypotenous needs to be bigger than the base. Knowing the base is 32, there is not enough room to justify an additional 20 feet, eliminating D. Answer must be C. If you wanted to do it the right way use trig/socatoa to find the missing hypotenouse as the top angle of the triangle is 45, just like the other upside down one.
A number multiplied by 2 is no more than 12
X > 12
x < 12
2<_12
2x > 12
Find the mode for the following data set:10 30 10 36 26 22
In this particular data set, 10 is the only value that occurs more than once, so it is the only mode
The mode is the value that occurs most frequently in a data set. In the given data set {10, 30, 10, 36, 26, 22}, we can see that the value 10 occurs twice, and all other values occur only once. Therefore, the mode of the data set is 10, since it occurs more frequently than any other value in the set.
Note that a data set can have multiple modes if two or more values occur with the same highest frequency. However, in this particular data set, 10 is the only value that occurs more than once, so it is the only mode.
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HELP IM SO CLOSE TO BEING FINISHED
Answer:
Step-by-step explanation:
we know that the interior angles are supplementary,
(2x-10)+(4x+16)=180
2x-10+4x+16=180
6x=180+6
6x=186
x=31
WILL GIVE BRAINLIEST!!!!!!!
Answer:
A.measure of centre?
measure of spread is Independent variable ie y and dependent variable is x
B.measure canter integers
measure spread is variable x
I hope it helped
A system of linear equations is given by the tables. one of the tables is represented by the equation . x y 0 5 3 6 6 7 9 8 x y -6 9 -3 8 0 7 3 6 the equation that represents the other equation is y = x . the solution of the system is ( , )
The solution of the system would be (3,6).
Lets solve the problem,
Other equation: y = 1/3x+5
Slope-Intercept Form: y = mx + b
Slope Formula:
y2-y1/x2-x1 = m
Have to find equation now:
m = (6 - 5)/(3 - 0)
m = 1/3
y = 1/3x + b
5 = 1/3(0) + b
b=5
y = 1/3x + 5
Lets put the substituition method here,
1/3x + 5 = -1/3x + 7
2/3x + 5 = 7
2/3x = 2
x = 3
y = 1/3(3) + 5
y = 1 + 5
y = 6
Therefore the coordinates are (3,6)
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Two office supply stores sell their brand of copy paper by the pound. One company offers a flat rateshipping charge and the other offers free shipping.Use the graph provided to construct a linear system to model this situation. Solve the system todetermine the amount of copy paper for which the cost is the same at both stores. Use the graph to verifythat your answer is reasonable.220200(450,202.51180160(400,156)1401Cost ($)1201008060(0.56)4020(0,0)Amount of copy paper (lb)-1 (x)-9 (X)50100150200250300350150 00The y-intercept, b, of f(x) isand the slope, m, offix) is
Given the graph in the attached image.
The red line represents f(x) and the blue line represents g(x);
From the graph;
The intercept, b, of f(x) is
\(b=56\)and the slope, m, of f(x) is;
\(\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1}=\frac{156-56}{400-0} \\ m=\frac{100}{400} \\ m=\frac{1}{4} \\ m=0.25 \end{gathered}\)So, f(x) is;
\(\begin{gathered} f(x)=mx+b \\ f\mleft(x\mright)=0.25x+56 \end{gathered}\)For g(x)
The y-intercept, b, of g(x) is;
\(b=0\)and the slope, m, of g(x) is;
\(\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1}=\frac{202.5-0}{450-0} \\ m=\frac{202.5}{450} \\ m=0.45 \end{gathered}\)So, g(x) is;
\(\begin{gathered} g(x)=mx+b \\ g(x)=0.45x+0 \\ g(x)=0.45x \end{gathered}\)To derive the solution, let us equate the two equations;
\(undefined\)4-2(5x-1)>5x+3 how do I solve this
3. A linear quadrupole is a series of three charges in a line, in this case, along the z-axis. Consider charges +Q at z=±D and charge −2Q at z=0. Find an exact expressoin for the electrostatic potential at a point P in the x,y-plane at a distance r from the center of the quadrupole. (Hint: it may be easier to find V(x) on the x axis and then use symmetry to argue that you can switch from x to r.)
The exact expression for the electrostatic potential at a point P in the x, y plane at a distance r from the center of the quadrupole is given by V(r) = k [Q/(r2 + D2)1/2 – Q/[(r2 + 2d + D2)1/2]] + k [-2Q/D].
Let's consider that three charges are placed in a straight line along the z-axis, and the charges are +Q on z=+D, -Q on z=-D, and -2Q at z=0.
To find the electrostatic potential at a point P in the x, y plane at a distance r from the center of the quadrupole, let's proceed with the following steps:
To find the electrostatic potential at a point P in the x-axis, we need to consider that the distance from the charges that are on the axis is r, and the distance from the charges that are on the axis and are at +D and -D is d.
The distance from the charges on the axis and at 0 is x. Now we can write,
V(x) = k [Q/(x2 + D2)1/2 – Q/[(x + d)2 + D2]1/2] + k [-2Q/D].
Now, we can substitute the values in the above expression and obtain,
V(x) = k [Q/(x2 + D2)1/2 – Q/[(x + d)2 + D2]1/2] + k [-2Q/D] .
Now, we need to use symmetry to argue that we can switch from x to r, which is given by r2 = x2 + y2.
Thus, the exact expression for the electrostatic potential at a point P in the x, y plane at a distance r from the center of the quadrupole is given by V(r) = k [Q/(r2 + D2)1/2 – Q/[(r2 + 2d + D2)1/2]] + k [-2Q/D].
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if Mr. Davis ate 20 of the 50 chocolate chip cookies from the bag,what percent of the bag of cookies did he eat?
Answer:
He ate 40% of it
Step-by-step explanation:
20/50 is 2/5, which is basically 4/10 therefore equaling 40%
A boat is heading towards a lighthouse, whose beacon-light is 107 feet above the water. From point A, the boat’s crew measures the angle of elevation to the beacon, 12∘, before they draw closer. They measure the angle of elevation a second time from point B at some later time to be 20∘. Find the distance from point A to point B. Round your answer to the nearest foot if necessary.
Rounding to the nearest foot, we get that the distance from point A to point B is approximately 204 feet.
Let's call the distance from point A to the lighthouse "x," and let's call the distance from point B to the lighthouse "y."
We want to find the distance from point A to point B, which is the difference between x and y.
From the first measurement, we can use trigonometry to find that:
tan(12°) = 107/x
Multiplying both sides by x, we get:
x tan(12°) = 107
Solving for x, we get:
x = 107 / tan(12°)
≈ 514.62 feet
From the second measurement, we can use trigonometry to find that:
tan(20°) = 107/y
Multiplying both sides by y, we get:
y tan(20°) = 107
Solving for y, we get:
y = 107 / tan(20°)
≈ 310.32 feet
The distance from point A to point B is:
x - y ≈ 204.3 feet
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Evaluate the double integral for the function f(x,y) and the given first quadrant region R. (Give your answer correct to 3 decimal places.)
f(x, y) = 2xe-y2; R is bounded by x = 0, y = x2, and y = 1
The required integral is ∫0¹ ∫x²¹ f(x, y) dydx will be approximately equal to 0.103
The given integral is ∫0¹ ∫x²¹ f(x, y) dydx.
To evaluate this double integral,
we first integrate with respect to y and then integrate with respect to x. Integrating with respect to y:
∫x²¹ f(x, y) dy = [(-1/2)e-y²2x]
x²¹= (-1/2)e-x⁴ + (1/2)e-2x⁴.
Now, integrating this result with respect to x:
∫0¹ (-1/2)e-x⁴ + (1/2)e-2x⁴ dx=[(-1/8)e-x⁴ + (1/16)e-2x⁴]
0¹= (-1/8)e-1 + (1/16)e-2.
Evaluating this expression,
We will get the value of the given integral as approximately 0.103 to 3 decimal places.
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Which ordered pair is a solution and f the equation? y-3=5(x-2)
Answer:
135=
3=5−10
Step-by-step explanation:
im not good at this but my mom said to try so i its not right
Reflect triangle ABC across the line x = 2. Then the reflect (image) A', B' and C' across the line x = -3.
Answer:
The first reflection makes the points (1,1), (-1,1) and (1,4) and the second reflection changes THOSE to (-7,1) (-5,1) and (-7,4). Just connect the dots to make the triangle.
Let me know if anything did not make sense.
Step-by-step explanation:
Reflect just means how far away is each point to the line of reflection? then ake a new point the sae distance, but in the opposite direction. You always want to use a line that makes a right angle to the line of reflection too, so since x=2 and x=-3 are verticallines you are going to use horizontal lines to measure where A, B and C are.
So the three points are A:(3,1), B:(5,1) and C:(3,4)
Now use a horizontal line to measure how far A, B and C are from x=2.
A is 1 spance to the right of x=2, so A' (what A turns into) is 1 space to the left. so (3,1) becomes (1,1) The y value does not change since you are only using the horizontal direction for reflection. B changes fro (5,1) to (-1,1) and finally C changes from (3,4) to (1,4)
Now the second reflection is the exact same process, but witht he new points reflected across x = -3. So the new points are (-7,1) (-5,1) and (-7,4).
If $y>0$, find the range of all possible values of $y$ such that $\lceil{y}\rceil\cdot\lfloor{y}\rfloor
Range is R={n^2: n is natural number} U {n(n+1) : n is natural number}
The expression ⌈y⌉⋅⌊y⌋ represents the product of the ceiling and floor functions of y.
To find the range of all possible values of y, we need to consider the possible values of the ceiling and floor functions individually.
1. Ceiling function (⌈y⌉): This function rounds y up to the nearest integer. Since y is greater than 0, the ceiling of y will always be greater than or equal to y.
2. Floor function (⌊y⌋): This function rounds y down to the nearest integer. Again, since y is greater than 0, the floor of y will always be less than or equal to y.
Now, let's consider the product of the ceiling and floor functions, ⌈y⌉⋅⌊y⌋.
The product ⌈y⌉⋅⌊y⌋ will always be greater than or equal to 0 since y > 0 and this can take only integral values.
Therefore, the range of all possible values of y such that ⌈y⌉⋅⌊y⌋ is the set R={n^2: n is natural number} U {n(n+1): n is natural number}
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T/F: solving a linear programming model and rounding the optimal solution down to the nearest integer value is the best way to solve a mixed integer programming problem.
False. While it may be tempting to round the optimal solution of a linear programming model down to the nearest integer value to solve a mixed integer programming problem, this approach is not always guaranteed to produce an optimal solution.
In fact, mixed integer programming problems require specialized algorithms and techniques that are specifically designed to handle integer variables in the objective function and constraints. These methods search for feasible solutions within the space of integer values, which can be more computationally intensive than solving a linear programming model.
So, while rounding the optimal solution of a linear programming model may sometimes provide a good approximate solution to a mixed integer programming problem, it is not always the best or most reliable way to solve these types of problems.
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Generate ordered pairs for the function y = 2x2 − 1 using x = −2, −1, 0, 1, 2. Graph the ordered pairs and describe the pattern.
The ordered pairs for the function are [-2,7] [-1,1] [0,-1] [1,1] [2,7] and graph is attached below and the pattern form a parabola.
A pair of numbers written in a certain sequence is known as an ordered pair. The standard notation for ordered pairs is (x, y), where x denotes the x-coordinate and y denotes the y-coordinate.
Finding the ordered pairs by putting the value of x,
Putting x = -2,
\(y = 2x^2 - 1 \\y = 2(-2)^2 - 1 \\= 8 - 1 \\= 7\)
So, the ordered pair is (-2,7).
Putting x = -1,
\(y = 2x^2 - 1 \\y = 2(-1)^2 - 1 \\= 2 - 1 \\= 1\)
So, the ordered pair is (-1,1).
Putting x = -1,
\(y = 2x^2 - 1 \\y = 2(-1)^2 - 1 \\= 2 - 1 \\= 1\)
So, the ordered pair is (-1,1).
Putting x = -1,
\(y = 2x^2 - 1 \\y = 2(-1)^2 - 1 \\= 2 - 1 \\= 1\)
So, the ordered pair is (-1,1).
Putting x = 0,
\(y = 2x^2 - 1 \\y = 2(0)^2 - 1 \\= - 1\)
So, the ordered pair is (0,-1).
Putting x = 1,
\(y = 2x^2 - 1 \\y = 2(1)^2 - 1 \\= 2 - 1 \\= 1\)
So, the ordered pair is (1,1).
Putting x = 2,
\(y = 2x^2 - 1 \\y = 2(2)^2 - 1 \\= 8 - 1 \\= 7\)
So, the ordered pair is (2,7).
The graph is attached below and the ordered pair form a parabola.
Therefore, the ordered pair are [-2,7], [-1,1], [0,-1], [1,1], and [2,7]. The graph is attached below and the pattern forms a parabola.
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