Basketball player Darrell Griffith is on record as
attaining a standing vertical jump of 1.2 m (4 ft).
(This means that he moved upward by 1.2 m after
his feet left the floor.) Griffith weighed 890 N (200
lb). g=9.8 m/s2

1- What is his speed as he leaves the floor?


2- if the time of the part of the jump before his feet left the floor was 0.300s, what was the magnitude of his average acceleration while he was pushing against the floor?

Answer:

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Answer:

 E = (2.29 i ^ - 0.917 j ^) 10⁶ N / C

 E_{total} = 2,467 10⁶ N / A       θ = -21.8      

Explanation:

For this exercise we will use that the electric field is a vector quantity, so the total field is

        E_total = E₁₃ + E₂₃

bold font vectors .  We can work with the components of the electric field in each axis

X- axis

       E_ total x = E₁₃ₓ + E_{23x}

y-axis  

      E_{total y} = E_{13y} + E_{23y}

the expression for the electric field is

       E = k q / r²

where r is the distance between the charge and the positive test charge

in this exercise

Let's find the field created by charge 1

q₁ = 10 μC = 10 10⁻⁶ C

x₁ = 5 cm = 0.05 m

x₃ = 21 cm = 0.21 m

         E_{13x} = 9 10⁹ 10 10⁻⁶ / (0.21 -0.05)²

         E_{13x} = 3.516 10⁶ N / C

y₁ = 6 cm = 0.06 cm

y₃ = -12 cm = -0.12 m

        E_{13y} = 9 10⁹ 10 10⁻⁶ / (-0.12 - 0.06)²

        E_{13y} = 2,777 10⁶ N / C

let's find the field produced by charge 2

q₂ = -27 μC = - 27 10⁻⁶ C

x₂ = -6 cm = -0.06 m

x₃ = 0.21 m

        E_{23x} = 9 10⁹ 27 10⁻⁶ / (0.21 + 0.06)²

        E_{23x} = 1.23 10⁶ N / A

y₂ = 10 cm = 0.10 m

y₃ = -0.12 m

        E_{23y} = 9 10⁹ 27 10⁻⁶ / (-0.12 - 0.10)²

        E_{23y} = 1.86 10⁶ N / C

Taking the components we can calculate the total electric field, we must use that charge of the same sign repel and attract the opposite sign, remember that the test charge is always considered positive.

       E_{total x} = E_{13x} - E_{23x}

       E_{total x} = (3.516 - 1.23) 10⁶

       E_{total x} = 2.29 10⁶ N / A

       E_{total y} = -E_{13y} + E_{23y}

       E_{total y} = (-2.777 +1.86) 10⁶ N / A

       E_{total y} = -0.917 10⁶ N / A

we can give the result in two ways

         E = (2.29 i ^ - 0.917 j ^) 10⁶ N / C

or in the form of modulus and angle, let's use the Pythagorean theorem to find the modulus

                E_{total} = √ (E_{total x}^2 + E_{total y}^ 2)

                 E_{total} = √ (2.29² + 0.917²) 10⁶

                E_{total} = 2,467 10⁶ N / A

let's use trigonometry for the angle

                tan θ = E_total and / E_totalx

                θ = tan⁻¹ E_{total y} / E_{total x}

                θ = tan⁻¹ (-0.917 / 2.29)

                θ = -21.8

The negative sign indicates that the angle is measured with respect to the x-axis in a clockwise direction.

Answer:

the current will actually split

Explanation:

it's true that once u add a resistor of the same resistance that is already present, the OVERALL current by the circuit will stay the same but it'll branch off equally across the newly added, so if we assume the total current was initially 10Amps for a single 1ohm resistor, if u add another 1ohm resistor, 5Amps will be split for both resistors

To calculate the net force on particle q2, we need to calculate the individual forces exerted by q1 and q3 on q2, considering their charges and separation distances.

Using Coulomb's Law, the force between two charged particles can be calculated as:

\(F = (k * |q1 * q2|) / r^2\)

where F is the force, k is Coulomb's constant (8.99 x 10^9 N m²/C²), q1 and q2 are the charges of the particles, and r is the separation distance between them.

For q1 and q2:

F1 = (8.99 x 10^9 N m²/C²) * (|-66.3 x 10^-6 C * 108 x 10^-6 C|) / (0.550 m)²

For q2 and q3:

F2 = (8.99 x 10^9 N m²/C²) * (|108 x 10^-6 C * -43.2 x 10^-6 C|) / (0.550 m)²

The net force on q2 is the vector sum of F1 and F2:

Net Force = F1 + F2

By calculating these values and performing the addition, we can determine the net force acting on particle q2.

Therefore, To calculate the net force on particle q2, we need to calculate the individual forces exerted by q1 and q3 on q2, considering their charges and separation distances.

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Answer:

Option A. The speed of sound through water is 4.3 times faster than sound through air.

Explanation:

To answer the question correctly, we shall determine the speed of the wave in both cases. This is illustrated below:

For Air:

Frequency (fₐ) = 195 Hz

Wavelength (λₐ) = 1.76 m

Velocity (vₐ) =?

vₐ = λₐfₐ

vₐ = 1.76 × 195

vₐ = 343.2 m/s

For Water:

Frequency (fᵥᵥ) = 195 Hz

Wavelength (λᵥᵥ) = 7.6 m

Velocity (vᵥᵥ) =?

vᵥᵥ = λᵥᵥfᵥᵥ

vᵥᵥ = 7.6 × 195

vᵥᵥ = 1482 m/s

Finally, we shall compare the speed in water to that of air. This can be obtained as follow:

Velocity in air (vₐ) = 343.2 m/s

Velocity in water (vᵥᵥ) = 1482 m/s

Water : Air

vᵥᵥ : vₐ =>

vᵥᵥ / vₐ = 1482 / 343.2

vᵥᵥ / vₐ = 4.3

Cross multiply

vᵥᵥ = 4.3 × vₐ

Thus, the speed in water is 4.3 times the speed in air.

Option A gives the correct answer to the question.

The formation of bubbles while heating a liquid can affect the coefficient of cubical expansion γ of the liquid. The coefficient of cubical expansion is a measure of how much a liquid expands when its temperature increases.

When bubbles form in a liquid, they create voids that decrease the effective volume of the liquid. As a result, the apparent expansion of the liquid is reduced, which decreases the value of γ.

The effect of bubble formation on the coefficient of cubical expansion depends on the size, number, and location of the bubbles. For example, if the bubbles are very small and evenly distributed throughout the liquid, the effect on γ may be negligible. On the other hand, if the bubbles are large and located near the surface of the liquid, they may significantly reduce the effective volume of the liquid and decrease the value of γ.

In addition, the formation of bubbles can also lead to other effects that affect the expansion of the liquid. For example, the vaporization of the liquid can cause a decrease in pressure, which can also affect the value of γ. Therefore, the formation of bubbles while heating a liquid can have complex effects on the coefficient of cubical expansion of the liquid, and the exact effect depends on various factors.

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The change in kinetic energy of the proton is 4.8 x 10⁻²⁰.

The change in kinetic energy of the proton is calculated as follows;

ΔK.E = W = eV

where;

V = Ed

V = 3 V/m x 0.1 m = 0.3 V

ΔK.E  = 1.6 x 10⁻¹⁹ x 0.3 = 4.8 x 10⁻²⁰ J

Thus, the change in kinetic energy of the proton is 4.8 x 10⁻²⁰ J.

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The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

The density of the second liquid is 0.812 g/cm³

To calculate the density of the second liquid, we need to use the principle of displacement. The mass of the liquid can be found by subtracting the mass of the empty density bottle from the mass of the bottle filled with the liquid. Therefore, the mass of the liquid is:

mass of liquid = mass of bottle + liquid - mass of empty bottle

mass of liquid = 39.84g + x - 18.00g

where x is the mass of the liquid.

We can now use the density formula, which is:

density = mass/volume

The volume of the liquid is equal to the volume of the density bottle that is filled with the liquid, which can be calculated by subtracting the volume of the empty bottle from the volume of the bottle filled with the liquid. Therefore, the volume of the liquid is:

volume of liquid = volume of bottle filled with liquid - volume of empty bottle

We can now substitute this expression into the density formula to get:

density of liquid = mass of liquid / (volume of bottle filled with liquid - volume of empty bottle)

We know that the density of water is 1000 kg/m³, which is equal to 1 g/cm³. We can use this to find the volume of the liquid by dividing the mass of water by its density:

volume of water = mass of water / density of water

volume of water = 44.00g / 1 g/cm³

volume of water = 44.00 cm³

Now, we can calculate the volume of the density bottle filled with the second liquid by using the principle of displacement:

volume of bottle filled with liquid = volume of water - volume of liquid

volume of bottle filled with liquid = 44.00 cm³ - (39.84g - 18.00g) / 1 g/cm³

volume of bottle filled with liquid = 44.00 cm³ - 21.84 cm³

volume of bottle filled with liquid = 22.16 cm³

Finally, we can substitute these values into the density formula to get:

density of liquid = x / 22.16 cm³

Solving for x, we get:

x = density of liquid x 22.16 cm³

Substituting x back into the mass equation, we get:

mass of liquid = 39.84g + (density of liquid x 22.16 cm³) - 18.00g

Solving for the density of the liquid, we get:

density of liquid = (mass of liquid - 21.84g) / 22.16 cm³

Substituting the given values, we get:

density of liquid = (39.84g - 21.84g) / 22.16 cm³ = 0.812 g/cm³

In conclusion, the density of the second liquid is 0.812 g/cm³. This value is less than the density of water, which means that the second liquid is less dense than water and will float on top of water.

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Answer:

920000

Explanation:

Each kg contains 1,000 grams

Answer:

\(F=48.62N\)

Explanation:

From the question we are told that:

Angle \(\theta= 20\)

Mass \(m= 20kg\)

Coefficient of kinetic friction \(\mu=0.1\)

Generally the equation for Force Required to jeep sled moving is mathematically given by

 \(F= mg sin \theta - \mu N\)

Where N is normal force

 \(F_N=Wcos\theta\)

 \(F_N=20*9.8*cos 20\)

 \(F_N=184.18N\)

Therefore

 \(F= (20*9.8) sin 20 - (0.1) (184.18)\)

 \(F=48.62N\)

The image only shows the path of the ball and its different positions at different times during the flight.

To determine the speed of the ball at each position, additional information such as the time elapsed between each position and the distance traveled would be needed. Only with this information would it be possible to calculate the speed at each position and determine where the ball is traveling the fastest.

Speed is the measure of the distance traveled by an object over a specified period. It is a scalar quantity and is typically expressed in units of distance per unit of time, such as miles per hour, kilometers per hour, or meters per second. Speed can be calculated as the ratio of the distance covered by an object to the time taken to cover that distance. It is an important concept in physics and plays a critical role in determining the motion of objects, particularly in the field of mechanics.

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The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.

Since the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.

The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.

According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.

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Answer: Hot weather concreting

Liquid nitrogen has also been used as a method for cooling concrete for over twenty years. ...

LN is produced by compressing and cooling nitrogen gas to a point below its evaporation point of about − 196 °C [− 320 °F].

Explanation:

Given data

*The given velocity of the car is v(t)= 10 + 3t + 512

The acceleration of the car is calculated as

Thus, the acceleration of the car at t = 2 s is 3 m/s^2

Recall that

v² - u² = 2 a ∆x

where u and v denote initial and final velocities, respectively; a is acceleration; and ∆x is the distance traveled.

Then we get

(18 m/s)² - (26 m/s)² = 2 a (52 m)

a = ((18 m/s)² - (26 m/s)²) / (104 m)

a ≈ -3.4 m/s²

Answer:

See the explanation below.

Explanation:

First, we must determine the mass of the baseball, we know that the weight of a body is defined as the product of mass by gravity.

\(w=m*g\)

where:

w = weight = 1.47[N]

m = mass [kg]

g = gravity acceleration = 9.81 [m/s²]

Now replacing:

\(m=w/g\\m = 1.47/9.81\\m = 0.149[kg]\)

We now know that kinetic energy is converted to potential energy as the ball descends. By means of the following equation, we can determine the potential energy when the baseball is 10 meters high.

\(E_{pot}=m*g*h\\\)

where:

Epot = potential energy [J]

m = mass = 0.149[kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 10 [m]

Now replacing:

\(E_{pot}=0.149*9.81*10\\E_{pot}=14.7[J]\)

In theory, this same energy must be converted to kinetic energy just before the ball hits the floor. But we see that we only have 12 [J] of kinetic energy.

That is to say, that of the 14 [J] that were had as potential energy (mechanical energy) 2 [J] was converted to internal energy, and the rest was converted to kinetic energy (mechanical energy)

\(E_{int}=14-12\\E_{int}=2[J]\)

Note: Potential, kinetic and elastic energies are forms of mechanical energy.

The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .

Everything is always in motion, but the way we perceive it depends on our frame of reference.

In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.

It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.

In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.

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The magnitude of the potential difference between the spheres is 1.06 × 105 V. The final charge on the smaller sphere is 11.97 × 10-6 C and on the larger sphere is 9.03 × 10-6 C.

(a) ΔV = VR - Vr
where VR and Vr are the potentials at the surfaces of the larger and smaller spheres, respectively.

We can use the formula for the potential of a point charge to find the potentials at the surfaces of the spheres:
VR = (kQ)/R
Vr = (kq)/r
where k is the Coulomb constant.

Substituting the given values for Q, q, R, and r, we get:
VR = (k × 16 × 10-6 C)/(6.0 × 10-2 m)
Vr = (k × 5.0 × 10-6 C)/(3.4 × 10-2 m)

Therefore, the magnitude of the potential difference between the spheres is:
ΔV = (k × 16 × 10-6 C)/(6.0 × 10-2 m) - (k × 5.0 × 10-6 C)/(3.4 × 10-2 m)
ΔV = (8.89 × 109 N·m2/C2 × 16 × 10-6 C)/(6.0 × 10-2 m) - (8.89 × 109 N·m2/C2 × 5.0 × 10-6 C)/(3.4 × 10-2 m)
ΔV = 2.37 × 105 V - 1.31 × 105 V
ΔV = 1.06 × 105 V

(b) If we connect the spheres with a wire, the charges will redistribute until the potential difference between the spheres is zero. This means that the final charge on the smaller sphere, 11.97 × 10-6 C, will be given by:
qf = (r/R) × (Q + q)

Substituting the given values for Q, q, R, and r, we get:
qf = (3.4 × 10-2 m)/(6.0 × 10-2 m) × (16 × 10-6 C + 5.0 × 10-6 C)
qf = 0.57 × 21 × 10-6 C
qf = 11.97 × 10-6 C

(c) The final charge on the larger sphere, 9.03 × 10-6 C, will be the difference between the initial total charge and the final charge on the smaller sphere:
Qf = (Q + q) - qf

Substituting the values for Q, q, and qf, we get:
Qf = (16 × 10-6 C + 5.0 × 10-6 C) - 11.97 × 10-6 C
Qf = 9.03 × 10-6 C

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Answer:

с The handle will turn anticlockwise (to the left).

Explanation:

According to Furnham et. al (2004), openness to experience accounts for a significant proportion of the variance in C6H12O6 as a nonelectrolyte.

The mean proportional between the 2 phrases of a ratio in a proportional is the rectangular root of the product of these two. for instance, in the proportion a:b :: c:d, we can outline the implied proportion for the ratio a:b because of the rectangular root of the made of the two phrases of the ratio or √ab.

If one amount is proportional to any other, the 2 amounts increase and reduce at an equal price so there's constantly identical dating between them.

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Answer:

The pressure increases due to more force of liquid being on top of the point the sensor is monitoring travelling deeper into the liquid

The amount the needle on the meter is deflected A. increases

This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.

The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.

By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.

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Answer:

The Nucleus

Explanation:

The nucleus contains the majority of an atom's mass because protons and neutrons are much heavier than electrons, whereas electrons occupy almost all of an atom's volume.  I hope this helps you :D

The speed that the ball hits the balloon is approximately 214.43 m/s.

The velocity-time connection refers to the first motion equation, v = u + it. On the other hand, the position-time connection is denoted by the second equation of motion, s = ut + 1 / 2at2.

The following equation can be used to determine the ball's ultimate velocity:

v_f = sqrt(v_x² + v_y²)

where v_x is the horizontal component of the velocity and v_y is the vertical component of the velocity at the point of impact.

Substituting the given values, we get:

v_i_x = v_i_y = 212 / √(2) = 150.13 m/s

t = v_y / a_y = 150.13/9.8 = 15.31 s

y = v_i_y * t + 0.5 * a_y * t² = 150.13 * 15.31 + 0.5 * (-9.8) * (15.31)² = 1149.59 m

x = v_i_x * t = 150.13 * 15.31 = 2298.52 m

v_f = √(v_x² + v_y²) = √((212/√(2))² + (-9.8 * 15.31)²)

= 214.43 m/s

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Answer:

A. The angular acceleration of the disk is -1.047 radians per square second.

B. The disk turns 4.715 radians while stopping.

C. The disk did 0.750 revolutions while stopping.

Explanation:

A. In this case, the disk is deceleration at a constant rate. Hence, the angular acceleration experimented by the object (\(\alpha\)), in radians per square second, can be found by means of this kinematic expression:

\(\alpha = \frac{\omega-\omega_{o}}{t}\) (1)

Where:

\(\omega_{o}\) - Initial angular speed, in radians per second.

\(\omega\) - Final angular speed, in radians per second.

\(t\) - Time, in seconds.

If we know that \(\omega_{o} \approx 3.142\,\frac{rad}{s}\), \(\omega = 0\,\frac{rad}{s}\) and \(t = 3\,s\), then the angular acceleration of the disk is:

\(\alpha = \frac{\omega-\omega_{o}}{t}\)

\(\alpha = -1.047\,\frac{rad}{s^{2}}\)

The angular acceleration of the disk is -1.047 radians per square second.

B. The change in position of the disk (\(\Delta \theta\)), in radians, is determined by the following kinematic formula:

\(\Delta \theta = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot \alpha}\) (2)

If we know that \(\omega_{o} \approx 3.142\,\frac{rad}{s}\), \(\omega = 0\,\frac{rad}{s}\) and \(\alpha = -1.047\,\frac{rad}{s^{2}}\), then the change in position is:

\(\Delta \theta = \frac{\omega^{2}-\omega_{o}^{2}}{2\cdot \alpha}\)

\(\Delta \theta = 4.715\,rad\)

The disk turns 4.715 radians while stopping.

C. A revolution equals 2π radians, then, then number of revolutions done by the disk while stopping is found by simple rule of three:

\(\Delta \theta = 4.715\,rad \times \frac{1\,rev}{2\pi\, rad}\)

\(\Delta \theta = 0.750\,rev\)

The disk did 0.750 revolutions while stopping.

Answer:

a. The electric field lines are linear and perpendicular to the plates inside a parallel-plate capacitor, and always from positive plate to the negative plate. If a positive charge is released near the positive plate, then it will follow a linear path towards the negative plate under the influence of electrostatic force, F = Eq, where q is the charge of the particle. The electric field inside a parallel plate capacitor is constant and equal to

This can be calculated by Gauss' Law.

A positive charge always follow the electric field lines when released. Another approach is that the positive plate repels the positive charge and negative plate attracts the positive charge. Therefore, the positive charge follows a path towards the negative charge.

b. The particle moves from the higher potential to the lower potential. The direction of motion is the same as the direction of the force that moves the particle, so the work done on the particle by that force is positive.

Answer:

\(F=9.09\times 10^{-7}\ N\)

Explanation:

Given that,

Charge, q = 0.250 μC

It is released from a height of 30 cm or 0.03 m

The magnetic field strength is 1.50 T.

First we find the velocity using the conservation of energy as follows :

\(mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 0.3} \\\\v=2.424\ m/s\)

Now, the magnetic force is given by :

\(F=qvB\\\\=0.25\times 10^{-6}\times 2.424\times 1.5\\\\=9.09\times 10^{-7}\ N\)

So, the magnetic force is \(9.09\times 10^{-7}\ N\). Since, the bob is at the lowest point, the direction of the magnetic force at the lowest point is upward.