B/ Evaluate e^(πi/2)

The option that is not a property of refrigerants is;

D: Its pressure remains unchanged during the cooling cycle.

A refrigerant is defined as a working fluid that is used in the refrigeration cycle of air conditioning systems and heat pumps.

Now, there are a couple of desirable properties of refrigerants and they are;

Lokking at the given options, the only one that is not a property of a refrigerant is that  Its pressure remains unchanged during the cooling cycle.

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Question:

All of the following are advantages of using a pressure transducer rather than a vacuum gauge EXCEPT:

A. greater accuracy.  

B. easier identification of the cylinder.

C. measuring higher pressures.

D. ability to see the levels graphically

Answer:

The correct answer is D) ability to see the levels graphically

Explanation:

The above question derives from the Rudiments of Automotive Technology.

The function of the pressure transducer is to enable the diagnostic who is testing the engine vacuum to detect the cylinder with a faulty vacuum.

The pressure transducer does allow its user to see the vacuum graphically NOT  the levels.

Cheers.

Technician B is correct and he is providing the correct guidance to the customer.

A faulty driveshaft, commonly found near the front wheels, can make the vehicle difficult to control. This faulty drive shaft can be the result of worn U-joints or bushings. This can cause the drive shaft to vibrate when attempting to turn or accelerate.

The part that connects the drive shaft to the differential and sometimes connects the drive shaft to the transmission or two drive shafts to each other is called U-Joints and breaking of u- joints is known as bushing.

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CFC-12 recovery equipment has SAE 3/8-inch service fittings, which means that it is designed to work with refrigerants that use this specific fitting. On the other hand, HFC-134a recovery equipment has a different design. It uses 1/2 inch Acme threads or 10mm threads, or sometimes a quick-couple design, depending on the specific equipment.

This difference in fittings is due to the fact that CFC-12 and HFC-134a are different types of refrigerants with different chemical properties. CFC-12 is a chlorofluorocarbon (CFC) that has been phased out due to its harmful impact on the ozone layer. HFC-134a, on the other hand, is a hydrofluorocarbon (HFC) that is considered to be more environmentally friendly.

The different fittings on the recovery equipment are necessary to ensure that the refrigerant is safely and efficiently recovered from the system. Using the wrong fittings can result in leaks, contamination of the refrigerant, and potential safety hazards. Therefore, it is important to use the appropriate equipment for the specific refrigerant being handled.

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Answer:

\(X=-\$19318\)

Explanation:

From the question we are told that:

Initial cost \(P= $100,000\)

Annual benefits \(A= $12,500\)

Salvage value \(S= $30,000\)

Interest rate \(I=10\%=>0.10\)

Time \(t=8years\)

Generally the equation for Net Project worth X is mathematically given by

  \(X=-P+A+S\)

Where

Present worth of Annual benefits A is

 \(A'=A(P/a,0.10,8)\)

 \(A'=12500*5.3349\)

 \(A'=\$66686.25\)

Present worth of Salvage Price S is

 \(S'=S(P/a,0.10,8)\)

 \(S'=30000*0.46651\)

 \(S'=\$13995.3\)

Therefore

 \(X=-P+A'+S'\)

 \(X=-100000+66686.25+\$13995.3\)

 \(X=-\$19318\)

We can see here that The Public or Livery Conveyance Exclusion Endorsement is designed to be attached to all personal auto policies (PAPs): D. Unless one of the Insurance Services Office, Inc. (ISO) transportation network driver endorsements is attached.

Policy refers to a set of principles, guidelines, or rules that are established to guide decision-making and actions within a particular organization, institution, or government.

It serves as a framework for addressing specific issues, achieving goals, and promoting consistency and fairness in decision-making processes.

Policies serve as a framework for consistency, fairness, and effective decision-making.

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The complete question is:

The Public or Livery Conveyance Exclusion Endorsement is designed to be attached to all personal auto policies (PAPs)

A. And applies to only Part A—Liability Coverage.

B. With insureds who are drivers for a transportation network company (TNC) but not to PAPs with insureds who are not TNC drivers.

C. In combination with the Transportation Network Driver Coverage (No Passenger) Endorsement.

D. Unless one of the Insurance Services Office, Inc. (ISO) transportation network driver endorsements is attached.

If the graph is going upward in the right direction then the motion on the graph is "Forward Motion".

Answer:

"Use your gloves correctly" and "Inspect your gloves for any damage before wearing."

Explanation:

If you don't use your gloves correctly you could risk your hands being infected/burned. If your gloves are damaged they will provide minimum protection but there is still a potential safety hazard.

Answer:

Use your gloves correctly

Inspect your gloves for any damage before wearing

An extremum is a point where the function has its highest or lowest value, and at which the slope is zero.

The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum is as follows;

Reason:

The given parameters are;

Form of silo = Cylinder surmounted by a hemisphere

Cost of construction of hemisphere per square unit = 2 × The cost of of construction of the cylindrical side wall

Required:

The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum

Solution:

The fixed volume of the silo, V, can be expressed as follows;

\(V = \pi \cdot r^2 \cdot h + \dfrac{2}{3} \cdot \pi \cdot r^3\)

Where;

h = The height of the cylinder

r = The radius of the cylinder

The surface area is, Surface Area = 2·π·r·h + 2·π·r²

The cost, C = 2·π·r·h + 2×2·π·r² = 2·π·r·h + 4·π·r²

Therefore;

\(C = 2 \times \pi \times r\times \dfrac{V - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } + 4 \cdot \pi \cdot r^2 = \dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r}\)

At the minimum value, we have;

Which gives;

16·π·r³ = 6·V

Which gives;

\(h = \dfrac{\dfrac{8 \cdot \pi \cdot r^3}{3} - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } = 2 \cdot r\)

h = 2·r

The height of the silo, h = 2 × The radius, 2

Therefore, the dimensions to be used if the volume is fixed and the cost is to be kept to a minimum is, height, h = 2 times the radius

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Answer:

Relative density = 0.7 or 70%

Explanation:

The following information was provided by this question

Pd = 1.72mg/mg³

Pd max = 1.81 mg/mg³

Pd min = 1.54 mg/mg³

We substitute into the formula. This formula is contained in the attachment.

[(1/1.54)-(1/1.72)]/[1/1.54 - 1/1.81]

= 0.649350 - 0.581395 / 0.649350 - 0.552486

= 0.067955/0.096864

= 0.7015

= 0.7

The relative density is Therefore 0.7 or 70% when converted to percentage

Answer:

Option B (Starter Control Circuit) is the right option.

Explanation:

All other given options are not related to the given instance. So the above option is correct.

Answer:

Parasite drag and induced drag.

In this scenario, the statements describe trust model C. Aliza trusts the browser, the browser trusts the certificate authority, and the certificate authority trusts the website.

In this scenario, the trust model works as follows: Aliza trusts the browser to accurately display the security status of the website she is visiting. The browser, in turn, trusts the certificate authority (CA) to properly verify and issue valid digital certificates for websites. The certificate authority is responsible for validating the identity of the website and issuing a digital certificate to confirm its secure connection.

When Aliza sees the lock icon in the URL bar, it indicates that the browser has verified the digital certificate provided by the website, confirming that the connection is secure and the website's identity has been validated by the trusted CA. This trust model helps ensure that Aliza can confidently transmit sensitive information over the HTTPS connection, knowing that her data is being securely transmitted and protected from potential interception by unauthorized parties. Therefore, the correct option is C.

The question was incomplete, Find the full content below:

aliza visited a website over https and saw a lock icon in the url bar, indicating a secure connection with a valid digital certificate. which of these statements describes the trust model in this scenario? choose 1 answer: choose 1 answer:

A. the browser trusts aliza, aliza trusts the certificate authority, and the certificate authority trusts the website.

B. aliza trusts the certificate authority, the certificate authority trusts the browser, and the browser trusts the website.

C. aliza trusts the browser, the browser trusts the certificate authority, and the certificate authority trusts the website.

D. the certificate authority trusts aliza, aliza trusts the browser, and the browser trusts the website.

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Sheeting is supported by bracing cut . It consists of wires that have been tensioned and are anchored outside the excavation. true.

A wire is a flexible metallic conductor that typically contains copper and transports electricity in a circuit. A flexible, cylindric metal strand is what is known as a wire. Wires are used to establish electrical conductivity between two elements of an electrical circuit. They provide extremely little current flow resistance. The wires are coated with various colored insulating materials. a concealed listening device used by a secret agent to record potentially damaging spoken testimony. Electrical energy is produced by electrons, which are tiny charged particles that typically move via a wire. Lightning is a prime example of electrical energy in nature.

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The pressure drop across the straw is greater than the maximum vacuum pressure the lungs can produce, so, the students would be unable to drink the milkshake.

The pressure drop across the straw can be calculated using the Hagen-Poiseuille equation which is ΔP = (8μLQ)/(πr⁴)

ΔP = pressure drop

μ = viscosity of the shake

L = length of the straw

Q = flow rate

r = radius of the straw.

Substituting the values, we get:

ΔP = (8 x 6 x 0.3 x Q)/(π x (8 x 10^-3)⁴)

ΔP = 1181103.52Q

The maximum vacuum pressure the human lungs can develop is 3000 Pa. Converting to Pascals, we get:

3000 Pa = 3000 N/m²

So, the pressure drop across the straw is greater than the maximum vacuum pressure the lungs can produce.

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:Step 1: Start by finding a plastic base with an appropriate size. Drill two small holes on the base to screw the motor into the base.

Step 2: Find a small motor that has low voltage and high revolutions per minute. Glue the motor onto the base. Make sure that the shaft of the motor is pointing upwards. Step 3: Next, find a rubber belt and a PVC pipe. Cut the PVC pipe to a length of about 6 inches. Fix the rubber belt around the PVC pipe. Then, attach the PVC pipe to the shaft of the motor.Step 4: On the base of the generator, attach two metal collectors, one on either side of the rubber belt. These collectors should be made of metal wire. Make sure that they are positioned near the PVC pipe and touch the rubber belt. Step 5: On the top of the collector, fix a metallic dome. The dome should be large enough to hold a high charge. Attach a rod to the dome and attach the rod to the PVC pipe using an insulator. This will create an insulating support for the dome. Step 6: Connect a high-voltage power supply to the metallic dome. The positive terminal of the power supply should be connected to the dome. The negative terminal should be connected to the base of the generator. Once the generator is switched on, the motor will turn the PVC pipe and the rubber belt. Step 7: The combs will start to collect electrons from the belt as it passes them. This will create a high voltage difference between the belt and the metallic dome. The charge on the dome will gradually increase until it reaches a high voltage. Step 8: The dome will then start to discharge into the air in the form of a corona discharge. This will create sparks and arcs of electricity. The voltage of the generator can be increased by increasing the speed of the motor, increasing the size of the dome, or by using a power supply with a higher voltage output.

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Answer:

Explanation:The directive that tells the assembler to recognize 80x86 instructions that use 32-bit operands is:

B) .586

The .586 directive enables the assembler to recognize and support instructions specific to the 586 (Pentium) processor and later versions. This includes instructions that use 32-bit operands, as the 586 processor and subsequent processors introduced the ability to work with 32-bit data.

A) .STACK 4096 is a directive used to allocate stack memory for the program.

C) .MODEL FLAT is a directive that specifies the memory model used for the program, but it does not directly enable recognition of 32-bit operands.

Therefore, the correct answer is B) .586.

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In the radio communication system, multipath is the propagation phenomenon that causes diffusion or reflection in multiple different directions of a signal.

Multipath is a propagation mechanism that impacts the propagation of signals in radio communication. Multipath results in the transmission of data to the receiving antenna by two or more paths. Diffusion and reflection are the causes that create multiple paths for the signal to be delivered.

Diffraction occurs when a signal bends around sharp corners; while reflection occurs when a signal impinges on a smooth object. When a signal is received through more than one path because of the diffraction or reflection, it creates phase shifting and interference of the signal.

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The question is asking whether that statement is true or false. Options are;

A) True

B) False

We want to know whether it is true or false that Swing arm restraints are intended to prevent a vehicle from falling off a lift and the answer is;

Option B; False

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Answer:

Technician B says that the reading is determined by where a dial points on a scale.

Explanation:

A refractometer is a devise used by scientists to gauge a liquids index of refraction.

The refractive index of a liquid is the ratio of light velocity of a specific wavelength in air to its velocity in the substance in evaluation.

The steps of reading a measurement are;

The largest commonly-used drill bit size among the options provided is 2 inches.

The correct answer to the given question is option C.

Drill bits are used for creating holes in various materials, and their sizes are typically measured in inches. The size of a drill bit refers to its diameter, and larger drill bits are commonly used for specific applications that require larger holes.

While drill bits larger than 2 inches do exist, they are not as commonly used in typical DIY or commercial applications. In everyday projects, such as woodworking, construction, or metalworking, the majority of holes can be adequately drilled using smaller-sized bits.

Option A (1.5 inches) and option D (1 inch) represent smaller drill bit sizes that are more commonly used for general-purpose drilling tasks. Option B (12 inches) represents an extremely large drill bit size that is not commonly used in most standard applications.

It's important to note that drill bit sizes can vary depending on specific needs and industries. There may be specialized applications or industries that require even larger drill bits beyond the commonly-used range. However, in the context of commonly-used drill bits for general-purpose tasks, 2 inches represents a relatively large size.

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In 1974, researchers were alarmed to discover that the Gulf of Mexico had an area of water that was almost devoid of oxygen and was thus unsuitable for marine life. The oxygen-deprived zone is known as the “Dead Zone,” and it is caused by excessive nutrient pollution from human activities.

Dead zones are hypoxic (low-oxygen) areas in the world's oceans and lakes, where aquatic life is unable to survive due to insufficient oxygen levels in the water. These hypoxic regions are caused by large quantities of nutrient pollution (particularly nitrogen and phosphorus) from human activities, such as fertilizer runoff from agricultural fields, sewage discharge from urban areas, and emissions from factories and vehicles.The oxygen-deprived area in the Gulf of Mexico was first discovered in the 1970s, and it has grown larger and more persistent over time.

The zone's size can fluctuate from year to year, but it typically covers a region of the Gulf of Mexico that is roughly the size of Connecticut.

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Wheelbase, trackwidth, and tire load data can be used to determine the longitudinal CG location. The distance in inches between the center of gravity and the front wheel.

Wheelbase, trackwidth, and tire load data can be used to determine a car's longitudinal center of gravity (CG) location. The distance between the centers of the front and rear wheels is known as the wheelbase, while the distance between the left and right tire centerlines is known as the trackwidth. The amount of weight on each of the four tires that are in contact with the ground is known as the tire load. The entire weight of the vehicle is divided by the wheelbase and trackwidth, and the resulting number is multiplied by the wheelbase to determine the longitudinal center of gravity (CG) location. The resultant measurement, taken from the front wheel, is the longitudinal CG location in inches.

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To determine the isentropic efficiency of the turbine and the thermal efficiency of the cycle,the isentropic efficiency of the turbine is 65.4%, and the thermal efficiency of the cycle is 19.3%.

Saturated steam enters the turbine, but irreversibilities in the turbine cause the steam quality at the outlet of the turbine to be 70 percent. We can use steam tables to find the properties of the steam at the inlet and outlet of the turbine.

From the steam tables, we find that the entropy of the steam at the inlet is 6.8006 kJ/kg-K and the entropy at the outlet is 7.3079 kJ/kg-K. The isentropic efficiency of the turbine can be calculated using the formula:

isentropic efficiency = (h1 - h2s) / (h1 - h2)

Where h1 is the enthalpy at the inlet, h2s is the enthalpy at the outlet assuming isentropic expansion, and h2 is the actual enthalpy at the outlet. From the steam tables, we find that h1 is 3,146.8 kJ/kg, h2s is 2,181.4 kJ/kg, and h2 is 1,951.4 kJ/kg.

Plugging in the values, we get:

isentropic efficiency = (3146.8 - 2181.4) / (3146.8 - 1951.4) = 65.4%

Next, we can calculate the thermal efficiency of the cycle using the formula:

thermal efficiency = (Wnet / Qin) * 100%

Where Wnet is the net work output of the cycle and Qin is the heat input. The net work output can be calculated as the difference between the turbine work output and the pump work input. From the steam tables, we find that the enthalpy at the inlet of the pump is 191.8 kJ/kg and the enthalpy at the outlet of the pump is 816.7 kJ/kg.

The work input to the pump is then:

Wpump = (h2 - h1) = (816.7 - 191.8) = 624.9 kJ/kg

The work output of the turbine is:

Wturbine = (h1 - h2) = (3146.8 - 1951.4) = 1195.4 kJ/kg

The net work output is then:

Wnet = Wturbine - Wpump = 1195.4 - 624.9 = 570.5 kJ/kg

The heat input can be calculated as the difference between the enthalpy at the inlet of the boiler and the enthalpy at the outlet of the condenser. From the steam tables, we find that the enthalpy at the inlet of the boiler is 3,146.8 kJ/kg and the enthalpy at the outlet of the condenser is 191.8 kJ/kg.

The heat input is then:

Qin = h1 - h4 = 3,146.8 - 191.8 = 2,955 kJ/kg

Finally, we can calculate the thermal efficiency:

thermal efficiency = (Wnet / Qin) * 100% = (570.5 / 2955) * 100% = 19.3%

Therefore, the isentropic efficiency of the turbine is 65.4%, and the thermal efficiency of the cycle is 19.3%.

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Understanding a product LCA (Life Cycle Assessment) helps in waste management and in assessing environmental impacts.

The process of life cycle assessment evaluates the environmental effects of a product over the course of its existence. The following are the most crucial applications:

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The pressure at the inlet of the 0.5 cm diameter pipe is 1.0384 bar.

Mechanical energy balance can be applied to the given problem in the following manner:

The Bernoulli equation states that the sum of the pressure (P), density (ρ), and gravitational potential energy (ρgh) at any point in a fluid flow system is constant. If there are no energy losses due to friction, this formula may be used to predict the pressure of a fluid in the pipeline if the upstream pressure is known.

The formula for Bernoulli's equation is given by:

P1 + 1/2 ρV1^2 + ρgh1 = P2 + 1/2 ρV2^2 + ρgh2

Where P is the pressure, V is the velocity, ρ is the density, g is the acceleration due to gravity, h is the height above a reference point, and 1 and 2 represent any two points along the streamline.

Assuming that there is negligible friction, the problem can be solved as follows:

P1 + 1/2 ρV1^2 + ρgh1 = P2 + 1/2 ρV2^2 + ρgh2

Substitute the given values:

P1 + 1/2 ρV1^2 = P2 + 1/2 ρV2^2 + ρgh2

Since the diameter of the first pipe is 0.5 cm, its radius is 0.0025 m. Similarly, the diameter of the second pipe is 1 cm, so its radius is 0.005 m.

Since the flow rate of the water is 20 L/min, its velocity can be determined using the following formula:

V1 = (4Q1)/πd1^2

Where Q1 is the flow rate, d1 is the diameter of the first pipe, and π is the constant pi.

V1 = (4 × 20 × 10^-3)/π(0.005^2) = 2.546 m/s

The velocity V2 in the second pipe can be determined using the following formula:

V2 = Q2/[(π/4)d2^2]

V2 = (20 × 10^-3)/[(π/4)(0.01^2)] = 2.546 m/s

Substitute the given values:

P1 + 1/2 ρV1^2 = P2 + 1/2 ρV2^2 + ρgh2

P1 + 1/2 ρV1^2 = P2 + 1/2 ρV2^2 + ρgh1 + 50 m

The density of water at room temperature is 1000 kg/m³. Substituting the given values:

P1 + 1/2 × 1000 × 2.546^2 = 1 atm + 1/2 × 1000 × 2.546^2 + 1000 × 9.81 × 50

P1 + 6502.8 = 1.1038 × 10^5

P1 = 1.0384 × 10^5/10^5

P1 = 1.0384 bar.

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Answer:

Explanation:

Step one:

given data

V1=0.25m^3

T1=290k

P1=100kPa

V2=0.5m^2

T2=405k

P2=? final pressure

Step two:

The combined gas equation is given as

P1V1/T1=P2V2/T2

Substituting we have

(100*0.25)/290=P2*0.05/405

25/290=0.5P2/405

0.086=0.05P2/405

cross multiply

0.086*405=0.05P2

34.9=0.05P2

divide both sides by 0.05

P2=34.9/0.05

P2=698.3Kpa

Therefore the new pressure is 698.3Kpa when the gas is compressed

Answer:

when car vroom it go electric

Explanation:

i think then it goes to some spinny thing that spins and make the electric and the electic spins the spinny thing and the smoke comes outside the back