The sum of two solutions Ψ1(x,t) and Ψ2(x,t) to the one-dimensional time-dependent Schrödinger's wave equation is also a solution.
The probabilities can be calculated as follows:
(a) P = 0.393
(b) P = 0.239
(c) P = 0.865
The Schrödinger's wave equation describes the behavior of quantum particles and is given by:
iħ ∂Ψ/∂t = - (ħ²/2m) ∂²Ψ/∂x²
where ħ is the reduced Planck's constant, m is the mass of the particle, Ψ is the wave function, t is time, and x is the position.
To show that the sum of two solutions, Ψ1(x,t) and Ψ2(x,t), is also a solution, we substitute Ψ(x,t) = Ψ1(x,t) + Ψ2(x,t) into the Schrödinger's wave equation:
iħ ∂(Ψ1 + Ψ2)/∂t = - (ħ²/2m) ∂²(Ψ1 + Ψ2)/∂x²
Expanding the derivatives, we have:
iħ (∂Ψ1/∂t + ∂Ψ2/∂t) = - (ħ²/2m) (∂²Ψ1/∂x² + ∂²Ψ2/∂x²)
Since Ψ1 and Ψ2 individually satisfy the Schrödinger's wave equation, we know that:
iħ ∂Ψ1/∂t = - (ħ²/2m) ∂²Ψ1/∂x²
iħ ∂Ψ2/∂t = - (ħ²/2m) ∂²Ψ2/∂x²
Therefore, the equation becomes:
(iħ ∂Ψ1/∂t + iħ ∂Ψ2/∂t) = - (ħ²/2m) (∂²Ψ1/∂x² + ∂²Ψ2/∂x²)
Simplifying further:
iħ (∂Ψ1/∂t + ∂Ψ2/∂t) = - (ħ²/2m) (∂²Ψ1/∂x² + ∂²Ψ2/∂x²)
Since both Ψ1 and Ψ2 satisfy the Schrödinger's wave equation, the terms (∂Ψ1/∂t + ∂Ψ2/∂t) and (∂²Ψ1/∂x² + ∂²Ψ2/∂x²) are both zero. Thus, the equation simplifies to:
iħ(0) = - (ħ²/2m)(0)
Which is true. Therefore, we can conclude that Ψ(x,t) = Ψ1(x,t) + Ψ2(x,t) is a valid solution to the Schrödinger's wave equation.
In quantum mechanics, the wave function describes the probability distribution of finding a particle at a particular position. The wave function squared, |Ψ(x,t)|², gives the probability density of finding the particle at a specific position x at a given time t.
To determine the probability of finding the particle between two limits, we integrate the probability density over the specified range.
(a) For 0 ≤ x ≤ a₀/4:
The probability P is given by:
P = ∫(|Ψ(x,t)|²) dx from
0 to a₀/4
(b) For a₀/4 ≤ x ≤ a₀/2:
The probability P is given by:
P = ∫(|Ψ(x,t)|²) dx from a₀/4 to a₀/2
(c) For 0 ≤ x ≤ a₀:
The probability P is given by:
P = ∫(|Ψ(x,t)|²) dx from 0 to a₀
By evaluating these integrals using the given wave function Ψ(x), the probabilities can be calculated as follows:
(a) P = 0.393
(b) P = 0.239
(c) P = 0.865
These probabilities represent the likelihood of finding the particle within the specified ranges, based on the given wave function.
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____ developed the first model of the atom that showed the structure of the inside of an atom. A. Dalton B. Bohr C. Rutherford D. Thomson
Answer:
D. Thomson
Explanation:
The first model of the atom was proposed by J. J. Thomson.
true/false. straighterline meissner's corpuscles sense deep pressure.
False. Meissner's corpuscles do not sense deep pressure.
Meissner's corpuscles, also known as tactile corpuscles, are specialized sensory receptors located in the dermal papillae of the skin, particularly in areas with high tactile sensitivity such as the fingertips, palms, and soles of the feet. They are most sensitive to light touch, fluttering sensations, and fine textures. Meissner's corpuscles are especially responsive to low-frequency vibrations.
However, when it comes to deep pressure, other sensory receptors are responsible for detecting and relaying this information to the brain. Pacinian corpuscles, located deeper in the skin and within connective tissue, are specialized receptors that sense deep pressure and high-frequency vibrations. These receptors are larger and more responsive to mechanical forces associated with deep pressure.
In summary, Meissner's corpuscles are not involved in sensing deep pressure. They are primarily associated with light touch and fine tactile discrimination, while Pacinian corpuscles are the receptors specialized for deep pressure sensations.
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Astronomers call the vast, rotating cloud of vapor and dust from which the solar system formed:
A) The Milky Way B) The Kuiper Belt C) The Oort Cloud D) The Solar Nebula
Astronomers call the vast, rotating cloud of vapor and dust from which the solar system formed as D) The Solar Nebula.
The Solar Nebula is the rotating cloud of gas and dust that is believed to have formed the Sun and the solar system approximately 4.6 billion years ago. This theory is supported by observations of other star-forming regions in our galaxy, which exhibit similar conditions and structures. As the Solar Nebula collapsed under its own gravity, it began to spin faster and flatten into a disk shape, with the Sun forming at the center and the planets forming from the material in the disk.
The Solar Nebula theory is currently the most widely accepted explanation for the formation of the solar system. It states that a rotating cloud of gas and dust collapsed under its own gravity, eventually forming the Sun and the planets.
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A force of 27 N stretches a given spring by 4.4 cm. How much potential energy is stored in the spring when it is compressed 3.5 cm?
Give detail answer
Answer:
Explanation:
Easy!(assuming it's a horizontal spring)
Fs = kx
27N = k(4.4cm)
k = 118.8N/m
Us = k * x^2 / 2
Us = 118.8N/m * 0.035m^2 / 2
Us = 0.072Nm(J)
What is elementary entities?
Answer:
Answer: Elementary Entities are any of several entities, such as electrons, neutrons, or protons, that are less complex than atoms and are regarded as the constituents of all matter.
what is an assumption bohr made about the hydrogen atom?
Bohr's assumption about the hydrogen atom was that the electrons in the atom could only occupy certain energy levels, and that these energy levels were quantized.
This meant that the electrons could only exist in certain specific energy states, and that they could only transition between these energy levels by absorbing or emitting discrete packets of energy, known as photons. This assumption was based on the observation that the hydrogen atom only produced specific, discrete emission spectra, rather than a continuous range of wavelengths.
Bohr's model of the hydrogen atom was revolutionary at the time, as it allowed scientists to better understand the behavior of atoms and their constituent particles. It paved the way for the development of quantum mechanics, which is now the foundation of modern physics. The concept of energy quantization remains a fundamental aspect of our understanding of atoms and molecules, and has led to many important discoveries and applications in fields such as chemistry, materials science, and electronics.
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What is the mass for both??
Answer:
forever alone uwu......
On a typical day at an ocean port, the water has a maximum depth of 20m at 8:00 am. The minimum depth of 8m occurs 6.2hrs later. Assume that the relation between time and water depth is a sinusoidal function. The period and median depth of this data are
The median depth of the sinusoidal function is 14m represents the average or middle value of the water depth over one complete cycle.
To determine the period and median depth of the sinusoidal function that relates time and water depth at the ocean port, we need to analyze the given information.
The period of a sinusoidal function represents the time it takes for one complete cycle. In this case, the period would be the time it takes for the water depth to repeat its pattern.
Given that the maximum depth of 20m occurs at 8:00 am and the minimum depth of 8m occurs 6.2 hours later, we can calculate the period as follows:
Period = Time for one complete cycle = Time of minimum depth - Time of maximum depth
Period = 6.2 hours
Finally, the period of the sinusoidal function is 6.2 hours.
The median depth represents the average or middle value of the water depth over one complete cycle. To find the median depth, we can calculate the average of the maximum and minimum depths:
Median depth = (Maximum depth + Minimum depth) / 2
Median depth = (20m + 8m) / 2
Median depth = 14m
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A film with maximum contrast is required. The original technique is: 80 kV; 20 mAs; all other factors being equal. In order to enhance the contrast, the new technique should be: O 70 kV; 15 mAs O 70 kV; 30 mAs O 80 kV; 15 mAs O 60 kV; 60 mAs
The correct option for maximizing contrast is 70 kV and 15 mAs. A film with maximum contrast requires a new technique that involves the reduction of kV and mAs parameters. The new technique should be 70 kV and 15 mAs.
Radiography is a technique that enables the creation of medical images of the human body, using an X-ray beam. X-rays are an example of ionizing radiation, and their interaction with the tissues in the body results in the formation of an image. Contrast is the difference in tone between adjacent areas in the image, and it is essential to obtain high contrast in radiography, to ensure the visualization of the structures of interest and to make it possible to detect abnormalities.
Maximizing contrast is a common technique used in radiography, and it involves the adjustment of parameters such as kV, mAs, and exposure time. A high-contrast image can be achieved by reducing kV and mAs and increasing exposure time. The kV and mAs settings are the most important variables to adjust to enhance contrast. A high-kV setting will result in a low-contrast image, while a low-kV setting will produce a high-contrast image.In the given scenario, the original technique is 80 kV and 20 mAs, and all other factors are equal. To enhance the contrast, the new technique should be a combination of reduced kV and mAs. The possible options for a new technique are:
70 kV and 15 mAs70 kV and 30 mAs80 kV and 15 mAs60 kV and 60 mAs
The best option for maximizing contrast is the first option, which is 70 kV and 15 mAs. This is because the kV value has been reduced by 10, and the mAs has been reduced by 5, which will result in an increase in contrast.
The new technique to enhance contrast requires a reduction in kV and m As parameters, and the best option for maximizing contrast is 70 kV and 15 mAs.
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An investor wishes to install a wind farm in the Snoqualmie pass area located in Washington State, United States. The pass is about 920 m above the sea level. The average low temperature of the air is −4°C, and the average high is 18°C.1.Compute the power density of the wind in winter and summer assuming that the average wind speed is 15 m/s.2.Compute the length of the blades to capture 200 kW of wind power during the summer. Assume the coefficient of performance is 30%.
The length of the blades needed to capture 200 kW of wind power during the summer is approximately 38.06 meters (twice the blade radius).
What is Densty?
Density is a physical property of matter that describes the amount of mass per unit of volume. It is defined as the ratio of the mass of an object to its volume, and is typically expressed in units of grams per cubic centimeter (g/cm³) or kilograms per cubic meter (kg/m³).
To compute the power density of the wind, we can use the formula:
Power Density = 1/2 x air density x swept area x wind speed^3
where air density is 1.225 kg/\(m^{3}\), swept area is pi x \((blade radius)^{2}\), and wind speed is 15 m/s.
For winter:
Power Density = 1/2 x 1.225 kg/\(m^{3}\) x (pi x (blade radius)^2) x \((15 m/s)^{3}\)
Power Density = 682.97 W/\(m^{2}\)
For summer:
Power Density = 1/2 x 1.225 kg/\(m^{3}\) x (pi x\((blade radius)^{2}\)) x \((15 m/s)^{3}\)
Power Density = 682.97 W/\(m^{2}\)
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How does convection play a role in ocean currents?
What is the charge of the particle on an aluminum rod with a 0. 946 that you pass between the poles of a 0. 41-T permanent magnet at a speed of 4. 05 m/s at a 90o angle?
The charge of the electron on aluminum rod is approximately\(1.61 * 10^{-19}\) Coulombs.
We can use formula for magnetic force on a moving charged particle to solve this problem. The magnetic force is given by:
\(F = qvB*sin(theta)\)
We are given the velocity of electron, v = 4.05 m/s, and magnetic field strength, B = 0.41 T. The angle between velocity vector and magnetic field vector is 90 degrees, so sin(theta) = 1.
The force can be found using formula above:
\(F = qvB*sin(theta)\)
Plugging in given values:
\(F = q * 4.05 m/s * 0.41 T * 1\)
F = 1.663 q N
The magnitude of the force Keeping the electron moving in a circle is :
F = m*a
The centripetal acceleration is:
a = v^2 / r
F = qvB
Substituting the expression , we get:
r = mv / (qB)
\(r = (9.11 * 10^{-31 }kg) * (4.05 m/s) / (q * 0.41 T)\)
Solving for q, we get:
\(q = (9.11 * 10^{-31} kg) * (4.05 m/s) / (0.946 * 0.41 T * 1.663)\\q = 1.61 * 10^{-19} C\)
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This is the question
Answer:
B
Explanation:
If the net force on an object is zero, the object could (a) be at rest, (b) be in motion at a constant velocity, (c) have zero acceleration , (d) all of the preceding.
Answer:
BLACKPINK IN YOUR AREA MATH IS SO MUCH FUN
Explanation:
PERIOD AHH
what is the general relationship between wavelength and wave base? group of answer choices wave base lies at a depth equal to four wavelengths. wave base lies at a depth equal to three wavelengths. wave base lies at a depth equal to two wavelengths. wave base lies at a depth equal to half the wavelength. wave base lies at a depth equal to one wavelength.
The general relationship between wavelength and wave base is that the wave base lies at a depth equal to half the wavelength.
Therefore we can say that two times the depth the wave base lies equals to a whole wavelength. The other options " wave base lies at a depth equal to four wavelengths. wave base lies at a depth equal to three wavelengths. wave base lies at a depth equal to two wavelengths. wave base lies at a depth equal to one wavelength." are therefore inaccurate.
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In the the table there is 20 kj of coal, how much energy in joules is 1g of coal?
Answer:
what do u meN by this i really don't know
Sumin runs 50 meters from her house to the park down the street. She then keeps running in the same direction to her friend's house 150 Meters from the park. She then turns around and goes back to the park. What is Sumin's average velocity during her run if it takes her 2 minutes to complete?
A. 25 m/s
B.2.92 m/s
C.3.33 m/s
D.0.417 m/s
Answer:
d. 0.417 m/s
Explanation:
v= ▲x/t
(350-150)/120 s
= .417 m/s
a horseshoe magnet is a type of magnet true or false?
________________________________
STAY SAFE, STAY HEALTHY AND BLESSED .HAVE A GREAT DAY !THANK YOU !
Question 75
Which term is used to show the exposure of large populations to low level radiation?
a. Person-rem
b. Gamma-rem
c. Radiation-rem
d. Quantum-rem
The term used to show the exposure of large populations to low level radiation is "person-rem".
The term used to show the exposure of large populations to low level radiation is Radiation-rem. A rem is a unit of radiation dose equivalent and is equal to 1,000 millirems (mrem). A rem is used to measure the absorbed dose of radiation for a person, and it is calculated by multiplying the absorbed dose in rads by a quality factor that takes into account the type of radiation and its associated health risks. A rem is a unit of measure for the radiation absorbed by the body and is used to evaluate the health effects of radiation exposure. Radiation-rem is the unit of measure used to describe the exposure of large populations to low level radiation.
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To take off from an aircraft carrier, a 21000 kg jet needs to accelerate at 36.9 m/s^2. How much force is required? (unit = N)
The force required for the jet to take off from an aircraft carrier is 773,490 N (Newton).
To calculate the force required for the jet to take off from the aircraft carrier, you can use Newton's second law of motion, which is:
Force (F) = Mass (m) × Acceleration
(a) Given the mass (m) of the jet as 21,000 kg and the acceleration
To calculate the force required for the 21000 kg jet to accelerate at 36.9 m/s^2, we need to use Newton's second law of motion which states that force (F) is equal to mass (m) multiplied by acceleration (a).
So,
F = m x a
F = 21000 kg x 36.9 m/s^2
F = 773,490 N
∴ force required = 773,490 N
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According to what you have learned so far, which applications are examples of solid-state physics? check all that apply. revealing the structure of dna studying the arrangement of atoms in a molecule mixing salt crystals with water ice crystals recording information in magnetic strips reacting gas or plasma phase in chemical reactions activating an anti-lock brake system
According to what I have learned so far, the applications that are examples of solid-state physics include A. revealing the structure of DNA, B. studying the arrangement of atoms in a molecule, D. ice crystals, and recording information in magnetic strips.
Solid-state physics focuses on the properties and behaviors of solid materials. Revealing the structure of DNA and studying the arrangement of atoms in a molecule involve understanding the properties and interactions of solid-state materials at the atomic level. Ice crystals, being a solid phase of water, are also an example of solid-state physics as their formation and structure depend on the properties of solid materials.
Recording information in magnetic strips is another application of solid-state physics, as it involves the manipulation and storage of data in a solid medium, this technology relies on the magnetic properties of materials and the understanding of their behavior in the solid-state. So therefore the correct answer is A. revealing the structure of DNA, B. studying the arrangement of atoms in a molecule, D. ice crystals, and recording information in magnetic strips, are examples of solid-state physics.
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A 2. 0-kg object is thrown towards a wall with a speed of 8. 0 m/s. The ball hits the wall. And rebounds backwards with a speed of 6. 0 m/s. What is the magnitude of the impulse experienced by the hall?
Answer:
\(28\; {\rm kg \cdot m\cdot s^{-1}}\).
Explanation:
The impulse on an object is equal to the change in momentum.
By the conservation of momentum, the total momentum of this system will stay unchanged. In other words, the sum of the change in the momentum of the wall and the projectile will be \(0\):
\(\Delta p(\text{projectile}) + \Delta p(\text{wall}) = 0\).
Rearrange to obtain:
\(\Delta p(\text{wall}) = -\Delta p(\text{projectile})\).
The change in the momentum of the projectile is:
\(\begin{aligned} & \Delta p(\text{projectile}) \\ &= m(\text{projectile}) \, \Delta v(\text{projectile}) \\ &= (2.0\; {\rm kg})\, ((8.0 - (-6.0))\; {\rm m\cdot s^{-1}}) \\ &= 28\; {\rm kg\cdot m\cdot s^{-1}} \end{aligned}\).
The change in the momentum of the wall would then be:
\(\Delta p(\text{wall}) = -\Delta p(\text{projectile}) = -28\; {\rm kg\cdot m\cdot s^{-1}}\).
Thus, the magnitude of the impulse on the wall would be \(28\; {\rm kg\cdot m\cdot s^{-1}}\).
A wall in a house contains a single window. The window consists of a single pane of glass whose area is 0.15 m2 and whose thickness is 7 mm. Treat the wall as a slab of the insulating material Styrofoam whose area and thickness are 17 m2 and 0.20 m, respectively. Heat is lost via conduction through the wall and the window. The temperature difference between the inside and outside is the same for the wall and the window. Of the total heat lost by the wall and the window, what is the percentage lost by the window
Answer:
88 %
Explanation:
The rate of heat loss by a conducting material of thermal conductivity K, cross-sectional area,A and thickness d with a temperature gradient ΔT is given by
P = KAΔT/d
The total heat lost by the styrofoam wall is P₁ = K₁A₁ΔT₁/d₁ where K₁ =thermal conductivity of styrofoam wall 0.033 W/m-K, A₁ = area of styrofoam wall = 17 m², ΔT₁ = temperature gradient between inside and outside of the wall and d₁ = thickness of styrofoam wall = 0.20 m
The total heat lost by the glass window is P₂ = K₂A₂ΔT₂/d₂ where K₂ =thermal conductivity of glass window pane wall 0.96 W/m-K, A₂ = area of glass window pane = 0.15 m², ΔT₂ = temperature gradient between inside and outside of the window and d₂ = thickness of glass window pane = 7 mm = 0.007 m
The total heat lost is P = P₁ + P₂ = K₁A₁ΔT₁/d₁ + K₂A₂ΔT₂/d₂
Now, since the temperatures of both inside and outside of both window and wall are the same, ΔT₁ = ΔT₂ = ΔT
So, P = K₁A₁ΔT/d₁ + K₂A₂ΔT/d₂
Since P₂ = K₂A₂ΔT₂/d₂ = K₂A₂ΔT/d₂is the heat lost by the window, the fraction of the heat lost by the window from the total heat lost is
P₂/P = K₂A₂ΔT/d₂ ÷ (K₁A₁ΔT/d₁ + K₂A₂ΔT/d₂)
= 1/(K₁A₁ΔT/d₁÷K₂A₂ΔT/d₂ + 1)
= 1/(K₁A₁d₂÷K₂A₂d₁ + 1)
= 1/[(0.033 W/m-K × 17 m² × 0.007 m ÷ 0.96 W/m-K × 0.15 m² × 0.20 m) + 1]
= 1/(0.003927/0.0288 + 1)
= 1/(0.1364 + 1)
= 1/1.1364
= 0.88.
The percentage is thus P₂/P × 100 % = 0.88 × 100 % = 88 %
The percentage of heat lost by window of the total heat is 88 %
The saying is "Money can buy happiness, but research finds that in the United States those who earn more than
amount.
O $92,000
O $55,000
O $40,000
O $75,000
Save Answer
per year are not measurably happler than those who earn below that
Answer:
$92,000
Explanation:Happiness starts from within.
The United States those who earn more than amount is $92000. Hence option 1 is correct.
What is happiness?Happiness is defined as an emotional condition characterized by emotions of happiness, pleasure, and satisfaction. The following three things have an impact on happiness: meaningful relationships with other people. preserving a nice hobby or workplace. assisting individuals in need or the community.
People who place a higher value on time than money are generally happier than those who do not think that having more time is preferable to having more money, according to a UCLA research of 4,400 Americans. In a six-month experiment, those who received $10,000 financial transfers generally felt happier than those who did not.
Thus, the United States those who earn more than amount is $92000. Hence option 1 is correct.
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What is the difference between a physical and chemical change ?
Answer:
In a physical change the appearance or form of the matter changes but the kind of matter in the substance does not.
However in a chemical change, the kind of matter changes and at least one new substance with new properties is formed.
Hope this helps :)
a pilot flying low and slow drops a weight; it takes 2.4 s to hit the ground, during which it travels a horizontal distance of 200 m . now the pilot does a run at the same height but twice the speed. how much time does it take the weight to hit the ground?
(1) The time does pilot take the weight to hit the ground = 2.4 s
(2) The pilot travel before land = 400 m
Because fall time is proportional to fall height and acceleration due to gravity (g) is constant,
t₁ = t₂
s₁ = initial distance
s₂ = final distance
t₁ = initial time
t₂ = final time
Hence, the time does it take the weight to hit the ground = 2.4 s
The initial distance (s₁) = 200 m, and the pilot does a run at the same height but twice the speed.
So, the pilot travel before land:
s₂ = 2 x s₁
= 2 x 200 m
= 400 m
The question is incomplete, it should be:
There are competitions in which pilots fly small planes low over the ground and drop weights, trying to hit a target. A pilot flying low and slow drops a weight; it takes 2.4 s to hit the ground, during which it travels a horizontal distance of 200 m. Now the pilot does a run at the same height but twice the speed. How much time does it take the weight to hit the ground? How far does it travel before it lands?
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Compared to red light, blue light has higher frequency and:_________
Blue light has a greater frequency and carries more energy than red light when compared.
Electromagnetic frequencies that can be seen by human eyes make up visible light. This spectrum excludes ultraviolet and infrared radiation. The wavelengths and frequencies that an object reflects determine the colours we see. Both waves and particles of light exist. It has wave characteristics like amplitude, period, wavelength, and frequency.
The number of times a wave completes a cycle each second is known as its frequency. Hertz, or cycles per second, is the unit of measurement (Hz).
There is more energy in the light the higher the frequency. As a result, its wavelength shrinks.
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Between two times, an athletic mouse moves to the right for an unknown distance and then to the left for 2.06
m. Between these two times the mouse has an average speed of 2.93 m/s and an average velocity of 1.18 m/s.
What is the unknown distance that the mouse traveled to the right?
a. 5.419 m
b. 4.403 m
c. 2.951 m
d. 4.838 m
The magnitude of the unknown distance is 4.838 m. The correct option is d
What is Average Speed ?Average speed is the total distance travelled per total time. While average velocity is the total displacement per total time.
Given that an athletic mouse moves to the right for an unknown distance and then to the left for 2.06m. Between these two times the mouse has an average speed of 2.93 m/s and an average velocity of 1.18 m/s.
Let the unknown distance be d
Total distance s = d + 2.06
Speed = s/t
2.93 = ( d + 2.06 ) / t
Make t the subject of the formula
t = ( d + 2.06 ) / 2.93
Total displacement D = d - 2.06
Velocity v = D/t
1.18 = ( d - 2.06 ) / t
t = ( d - 2.06 ) / 1.18
Since t is the same,
( d - 2.06 ) / 1.18 = ( d + 2.06 ) / 2.93
Cross multiply
2.93( d - 2.06 ) = 1.18( d + 2.06 )
2.93d - 6.0358 = 1.18d + 2.4308
Collect the like terms
2.93d - 1.18d = 2.4308 + 6.0358
1.75d = 8.4667
d = 8.4667 / 1.75
d = 4.838 m
Therefore, the magnitude of the unknown distance that the mouse traveled to the right is 4.838 m. The correct option is d which is 4.838 m
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A projectile is launched horizontally at a speed of 40 meters per second from a platform located a vertical distance h above the ground. The projectile strikes the ground after time at horizontal distance from the base of the platform. [Neglect friction.]
Calculate the vertical distance, h, if the projectile's total time of flight is 4.5 seconds. You must show work to earn full credit with the minimum 3 steps:
1. Equation used
2. Substitution with correct units
3. Final answer with correct units
Answer:1
Explanation:t=rad2h/g
The launch of projectiles allows to find the height of the body launched horizontally is:
The height is 99.2 m
Projectile launching is an application of kinematics where there is no acceleration on the x-axis and the y-axis is the gravity acceleration.
In the attachment we see a diagram of the movement, as the body is thrown horizontally, its initial vertical speed is zero.
y = y₀ + \(v_o_y\) t - ½ g t²
Where y, y₀i are the current and initial heights, respectively, \(v_{oy}\) the vertical initial velocity, g the acceleration of gravity and t the time.
0 =y₀ + 0 - ½ g t²
y₀ = ½ g t²
let's calculate
y₀ = ½ 9.8 4.5²
y₀ = 99.2 m
y₀ = h = 99.2 m
This is the initial height of the object when it is thrown.
In conclusion using the projectile launch we can find the height of the horizontally launched body is:
The height is 99.2 m
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2. What are the innate defense systems?
3. What are the components of the first line of defense?
4. What are the components of the second line of defense?
5. What is the adaptive defense system?
6. Which is a simple physical barrier? 7. What are phagocytes?
8. What are two types of phagocytes?
Answer:
2)Innate, or nonspecific, immunity is the defense system with which you were born. It protects you against all antigens. Innate immunity involves barriers that keep harmful materials from entering your body. These barriers form the first line of defense in the immune response.
3)The first line of defence (or outside defence system) includes physical and chemical barriers that are always ready and prepared to defend the body from infection. These include your skin, tears, mucus, cilia, stomach acid, urine flow, 'friendly' bacteria and white blood cells called neutrophils.
4)The second line of defense is nonspecific resistance that destroys invaders in a generalized way without targeting specific individuals: Phagocytic cells ingest and destroy all microbes that pass into body tissues. For example macrophages are cells derived from monocytes (a type of white blood cell).
5)The adaptive defense consists of antibodies and lymphocytes, often called the humoral response and the cell mediated response. The term 'adaptive' refers to the differentiation of self from non-self, and the tailoring of the response to the particular foreign invader.
6)Innate immunity is comprised of different components including physical barriers (tight junctions in the skin, epithelial and mucous membrane surfaces, mucus itself); anatomical barriers; epithelial and phagocytic cell enzymes (i.e., lysozyme), phagocytes (i.e., neutrophils, monocytes, macrophages), inflammation- .
8)Types of phagocytes
In humans, and in vertebrates generally, the most-effective phagocytic cells are two kinds of white blood cells: the macrophages (large phagocytic cells) and the neutrophils (a type of granulocyte)