As you drive down the road at 13 m/s , you press on the gas pedal and speed up with a uniform acceleration of 1.02 m/s2 for 0.70 s. If the tires on your car have a radius of 33 cm, what is their angular displacement during this period of acceleration?

Answer:

669.1 ft and 743.1 ft

Explanation:

Given data

Lenght of wire= = 1000ft

Angle =  42˚

Applying SOH CAH TOA

1. How tall is the tower?

SOH

sine ∅= opp/hyp

sin 42= opp/1000

0.6691= Opp/1000

0.6691*1000= Opp

Opp=669.1 ft

Applying SOH CAH TOA

2.How far away from the base of the tower does the wire hit the ground?

CAH

cos ∅= adj/hyp

cos 42= adj/1000

0.7431*1000=adj

adj=743.1 ft

Explanation:

Sorry but the question is incomplete

a) The average force with which the woman pushed the man is 210 N.

b.  the woman's recoil speed is still 3.68 m/s

c.  If  she now throws her 2.50-kg purse at him at a 20.0° angle, the speed is 0.

We first calculate  the Momentum  = (70.0 kg)(-1.50 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s)

0 = (70.0 kg)(0 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s) - (70.0 kg)(-1.50 m/s)

v = 3.68 m/s

Δp = (70.0 kg)(1.50 m/s) - (70.0 kg)(0 m/s) = 105 kg·m/s

The average force exerted on the man by the woman is:

Average force =   Δp / Δt

Average force  = 105 kg·m/s / 0.500 s

Average force  = 210 N

b) The woman's recoil speed is :

0 = (70.0 kg)(-1.50 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s)

v = 3.68 m/s

c) If the woman throws her 2.50-kg purse at the man at a 20.0° angle, we apply the conservation of momentum equation in two dimensions and get the speed as 0.

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Answer:

Black's Law Dictionary defines a retroactive law as a law “that looks backward or contemplates the past, affecting acts or facts that existed before the act came into effect.” While Congress often considers legislation that would apply retroactively, the Constitution imposes some limited constraints on such laws.

Answer:

F = 1280 N

Explanation:

Given that,

Acceleration experienced by a space shuttle, a = 32 m/s²

Mass of the astronauts, m = 40 kg

We need to find the force experienced by the astronaut.

We know that the net force is equal to the product of acceleration and its mass. So,

F = ma

F = 40 kg × 32 m/s²

So,

F = 1280 N

So, 1280 N of force is experienced by the Astronaut.

Hello..!

To calculate its displacement, we first apply the data to the problem.

Data:

Now, we apply a conversion.

Conversion:

Then, we apply the formula that is.

Formula:

Finally we develop the problem.

Developing:

The displacement of the bike is 83100 meters.

Answer:

83,333.33 m (2 d.p.)

Explanation:

\(\boxed{\sf Speed=\dfrac{Distance}{Time}}\)

Given values:

As there are 60 minutes in one hour, convert minutes into hours by dividing by 60:

\(\implies \sf Time=\dfrac{50}{60}=\dfrac{5}{6}\;hour\)

Substitute the values into the formula and solve for distance:

\(\implies \sf 100=\dfrac{Distance}{\frac{5}{6}}\)

\(\implies \sf 100=Distance \times \dfrac{6}{5}\)

\(\implies \sf Distance=\dfrac{100 \times 5}{6}\)

\(\implies \sf Distance=\dfrac{250}{3}\;km\)

\(\implies \sf Distance=83.33333...\;km\)

At there are 1000 meters in one kilometer, convert kilometers into meters by multiplying by 1000:

\(\implies \sf Distance=83.33333...\times 1000=83333.33\;m\;(2\;d.p.)\)

Answer:

The tension in the light rope must be equal to the weight of the bucket

Explanation:

Given that,

Constant velocity of bucket and direction of bucket in downward

We need to find the tension in the rope

Using given data,

When a bucket  moves downward with a constant velocity then the net force does not applied on the bucket.

So, The weight of the bucket will be equal to the tension in the light rope

In mathematically,

\(T=mg\)

Where, T = tension

m = mass of bucket

g = acceleration due to gravity

Hence, The tension in the light rope must be equal to the weight of the bucket.

Answer:

With 8.8 MeV binding energy per nucleon, iron-56 is one of the most tightly bound nuclei.

Pls mark brainliest

Answer:

Planks?

Explanation:

It's kinda resting

Answer:

weights

walking

stretching

etc.

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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The caps used with boomwhacker tubes alter the sound of the notes by changing the effective length of the air column inside the tube.

This modification affects the fundamental frequency produced when the tube is struck or tapped against a surface.The fundamental frequency determines the pitch of the sound we hear.

When a boomwhacker tube is struck without any cap, the air column inside vibrates at its natural frequency, producing a specific pitch. By adding caps to the tube, we effectively shorten its length, which increases the frequency of the vibrations and raises the pitch. Conversely, removing caps increases the effective length, lowering the frequency and lowering the pitch.

To visualize this, imagine a tube with a cap on one end. The cap acts as a barrier, preventing the air column from vibrating in that direction. Therefore, the effective length of the tube becomes the distance between the cap and the open end. This shorter length results in a higher pitch. Removing the cap increases the effective length, resulting in a lower pitch.By using different combinations of caps on the boomwhacker tubes, we can produce a range of pitches, creating a musical and colorful experience.

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Answer:

The vertical component of the velocity can be found using the formula:

V₀y = V₀ * sin(θ)

where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.

Substituting the given values, we have:

V₀y = 48 * sin(53°)

Using a calculator, we can evaluate sin(53°) to be approximately 0.799:

V₀y = 48 * 0.799

V₀y ≈ 38.352

Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.

Answer:

B.) 38 meters/second

Explanation:

The voltage between the plates is 3.9 × \(10^-^3\) V.

The work-energy theorem states that the delta in the equation equals the change in kinetic energy plus the change in potential energy. Here, a charge's potential energy is expressed as qV, where V is the position's electric potential.  The greater the change in voltage per unit distance, the greater the electric field.

The kinetic energy of the electrons = 4.1 × \(10^-^1^5\) J

Charge of the electron = 1.602 × \(10^-^1^9\) coulomb

Using,

     ΔU = q × ΔV

4.1 × \(10^-^1^5\) = 1.602 × \(10^-^1^9\) × ΔV

      ΔV  = 3.9 × \(10^-^3\) V

Therefore, the voltage between the plates is 3.9 × \(10^-^3\) V.

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Answer:

Dehydration could possibly take place if lost fluid is not replaced adequately. Hypothermia can not possibly take place due to loss of fluid. Nor can emphysema. So, dehydration looks to be the more suitable answer

Newton's second law allows to find the result for the acceleration of the file and the ball is:

Newton's second law says that the force is proportional to the product of the acceleration for the mass of a body.

                F = ma

Where F is the force, the acceleration and m the mass of the body.

                \(a = \frac{F}{m}\)  

In this case we have a baseball with a mass m and a filing cabinet with a mass M.

           M> m

Therefore, using Newton's second law, the acceleration of the cabinet must be less than the acceleration of the ball since the mass of the cabinet is greater than mass ball.

In conclusion using Newton's second law we can find the result for the acceleration of the filing cabinet and the ball is:

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Answer:

when air or water cools it sinks

To calculate the torque required to create an angular acceleration, we can use the formula:

Torque = Moment of Inertia × Angular Acceleration

The moment of inertia of a disk can be calculated using the formula:

Moment of Inertia = (1/2) × Mass × Radius^2

Given:

Mass = 15,000 kg

Radius = 6.14 m

Angular Acceleration = 0.0500 rad/s^2

First, calculate the moment of inertia:

Moment of Inertia = (1/2) × Mass × Radius^2

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Next, calculate the torque:

Torque = Moment of Inertia × Angular Acceleration

Torque = Moment of Inertia × 0.0500 rad/s^2

Now, let's plug in the values and calculate:

Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2

Moment of Inertia ≈ 283,594.13 kg·m^2

Torque = 283,594.13 kg·m^2 × 0.0500 rad/s^2

Torque ≈ 14,179.71 N·m

Rounding to three significant figures, the torque required to create an angular acceleration of 0.0500 rad/s^2 is approximately 14,180 N·m.

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The frictional force is taken away from the net force. Mr. London will pull with a force of 388.9 N

Force can simply be defined as a pull or push. It is a product of mass and acceleration. It is a vector quantity.

Given that Mr. London applies a horizontal force to accelerate Mr. Schneider (mass of 84 kg) rightward at a rate of 1.2 m/s/s. If the coefficient of friction between Mr. Schneider 's socks and the freshly waxed floors is 0.35, then the force F in which Mr. London is pulling will be;

F - Fr = ma

Where

N = mg

N = 84 × 9.8

N = 823.2 N

Fr = μN

Fr = 0.35 × 823.2

Fr = 288.12 N

F - 288.12 = 84 × 1.2

F - 288.12 = 100.8

F = 100.8 + 288.12

F = 388.92 N

Therefore, Mr. London must be pulling with a force of 388.9 N

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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a) The tension in the rope is 123.9 N.

b) The moment of inertia of the wheel is 0.09 kg m².

c) The angular speed of the wheel 3.50 s after it begins rotating, starting from rest, is 58.5 rad/s.

(a) To determine the tension in the rope, we need to analyze the forces acting on the object. There are two forces: the force of gravity pulling the object down the incline and the tension force pulling the object up the incline.

The force of gravity can be broken down into two components: one parallel to the incline and one perpendicular to the incline.

The parallel component causes the object to accelerate down the incline, while the perpendicular component is balanced by the normal force of the incline.

The tension force is responsible for the object's acceleration down the incline, so we can set up the following equation:

T - mg sin(theta) = ma

where T is the tension force, m is the mass of the object, g is the acceleration due to gravity, theta is the angle of the incline, and a is the acceleration of the object down the incline.

Putting in the given values, we get:

T - (12.5 kg)(9.81 m/s²)(sin(37°)) = (12.5 kg)(2.00 m/s²)

Solving for T, we get:

T = 123.9 N

Therefore, the tension in the rope is 123.9 N.

(b) To determine the moment of inertia of the wheel, we can use the following equation:

I = (1/2)MR²

where I is the moment of inertia, M is the mass of the wheel, and R is the radius of the wheel.

Putting in the given values, we get:

I = (1/2)(12.5 kg)(0.12 m)²

 = 0.09 kg m²

Therefore, the moment of inertia of the wheel is 0.09 kg m².

(c) To determine the angular speed of the wheel after 3.50 s, we can use the following equation:

ω = ω₀ + αt

where ω is the final angular speed, ω₀ is the initial angular speed (which is zero in this case), α is the angular acceleration, and t is the time.

We can find the angular acceleration using the following equation:

α = a/R

where a is the acceleration of the object down the incline (which we already know) and R is the radius of the wheel.

Putting in the given values, we get:

α = 2.00 m/s² / 0.12 m

  = 16.7 rad/s²

Putting in the values for α and t, we get:

ω = 0 + (16.7 rad/s²)(3.50 s)

   = 58.5 rad/s

Therefore, the angular speed of the wheel 3.50 s after it begins rotating, starting from rest, is 58.5 rad/s.

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Answer:

The position at t=11 seconds is -96 m or 96 m to the left of the origin

Explanation:

Constant speed and constant acceleration motion

If a body travels the same distance per unit of time, the body has a constant speed. The equation for the distance x is:

\(x=v.t\)

Where v is the constant speed and t is the time.

At time t=0 the body is moving at a constant speed of v=24 m/s in the positive x-direction. It keeps that condition for t=1 sec. The distance traveled is:

\(x=24m/s\cdot 1\ s=24\ m\)

Now the body is given a constant acceleration of 6 m/s^2 in the negative x-direction, that is, a=-6 m/s^2

The distance traveled by a body at constant acceleration is given by:

\(\displaystyle x=v_o.t+\frac{a.t^2}{2}\)

Where vo is the initial speed and t is the time.

We need to find the position at t=11 sec, but we must subtract the one second already passed, thus t=10 s

\(\displaystyle x=24m/s\cdot 10s+\frac{-6m/s^2.(10)^2}{2}\)

\(\displaystyle x=240\ m-360\ m=-120\ m\)

This distance must be added to the actual position of the body, that is:

-120 m + 24 m = -96 m

The position at t=11 seconds is -96 m or 96 m to the left of the origin

Answer:

HI THERE

Explanation:

MEIOSIS produces sperm and ova

thank you

I am also reading this chapter

it will come in my exams

All four planets contain stable atmospheric layers, a mantle, and a core. One of the following is FALSE regarding the four terrestrial planets (Earth, Mars, Mercury, and Venus).

Terrestrial planets include Mercury, Venus, Earth, and Mars because of their compact, stony surfaces that resemble terra firma on Earth. The four innermost planets in the solar system are the four terrestrial planets.

The four innermost planets are known to as terrestrial planets and feature a moon or moons, valleys, volcanoes, and craters. They also have a liquid heavy-metal core.

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Answer:

Cuboid?

Explanation:

Answer:

−10.1−3.−7VX,2

Explanation:

Answer:

Evaluate (2 - 3)4(4) - 9 ÷ 3.

-7

-2

1

2

Explanation:

answer is 1

Given data:

* The initial value of the time is 0 s.

* The final value of the time is 12 s.

Solution:

The average speed from the graph is,

Substituting the known values,

Thus, the average speed from 0 to 12 seconds is 0.583 m/s.

Hence, fourth option is the correct answer.

The current flowing through the 1Ω resistor in the circuit is 0.66 A.

The emf of the cells, V = 1.1 V

Internal resistance of the cells, r = Ω

Resistance across the circuit, R = 1 Ω

According to Kirchhoff's current law, the total current flowing into and out of a junction in an electrical circuit is equal.

According to Kirchoff's current law,

(1.1 - V'/2) + (1.1 - V'/2) + (1.1 - V'/2) = V'/1

3/2(1.1 - V') = V'

3.3 - 3V' = 2V'

5V' = 3.3

Therefore, the terminal velocity of the battery is,

V' = 3.3/5

V' = 0.66 V

Therefore, according to Ohm's law, the current flowing through the 1Ω resistor is given by,

I = V'/R

I = 0.66/1

I = 0.66 A

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Given the work done, the force exerted on the taco stand through the given distance is 2.3 × 10³ Newtons.

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = f × d

Where f is force applied and d is distance travelled.

Given that;

W = f × d

3500kgm²/s² = f × 1.5m

f = 3500kgm²/s² ÷ 1.5m

f = 2.3 × 10³ kgm/s²

f = 2.3 × 10³ N

Given the work done, the force exerted on the taco stand through the given distance is 2.3 × 10³ Newtons.

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