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Write an expression for the perimeter of the rectangle with a length of 2x and width of x.

Answers

Answer 1

Step-by-step explanation:

2x + 2x + x + x = Perimeter

6x = Perimeter

x = Perimeter ÷ 6


Related Questions

• 3 pages are edited every 5 minutes.
• 5 pages are edited every 3 minutes.
• 6/10 of a page is edited per minute.
• 1 2/3 of a page is edited per minute.

a) 1 and 2
b) 1 and 3
c) 3 and 4
d) None of the above

 3 pages are edited every 5 minutes. 5 pages are edited every 3 minutes. 6/10 of a page is edited per

Answers

Answer:

1 and 3

Step-by-step explanation:

where the dots on the graph are, you can read that in 5 minutes, 3 pages are edited. in 10 minutes, 6 pages.
so statement 1 is correct.
when every 10 minutes 6 pages are edited, divide both by 10 to get what is edited per minute. -> 6/10 pages are edited per minute.

The answer is B) 1 and 3

Express as a trinomial.
(x-9)(x+4)

Answers

X^2-5x-36
Hope this helps!

STORMS During a storm, a tree breaks 6 feet above the ground and falls to form a right triangle. If the top of the tree rests 20 feet from the base of the tree, approximately how tall was the tree before the storm?

Answers

Answer:

Step-by-step explanation:

First find the hyp..

6^2 + 20^2 = x^2

x = 20.88

Using x, we now know the extra height missing from the original tree height, so we add 6 to find the original.

20.88 + 6 = 26.88ft

The tree was 26.88 feet tall before the storm.

What is Pythagoras theorem?

The relationship between the three sides of a right-angled triangle is explained by the Pythagoras theorem, commonly known as the Pythagorean theorem. The Pythagorean theorem states that the square of a triangle's hypotenuse is equal to the sum of its other two sides' squares.

We have Perpendicular = 6 feet

and, base = 20 feet

Using Pythagoras theorem we get

H² = P² + B²

H² = 6²+ 20²

H²= 36+400

H² = 436

H = 20.88 feet

thus, the height of the tree = 20.88 + 6 = 26.88 feet

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In finance, we need to do partial observations of data and estimate the data generating process (DGP) -- for example, log-normal returns. Sometimes, we can observe only the data points of a certain process, but we don't know what is the function generating the process. Consider the following graph is a plot of the f ′
(x), of a function f(x) given. What is the underlaying function ( f(x −
​ i)) that is the generator of the observed points in the plot f ′
(x −
​ i), for points x −
​ 1=−1,x −
​ 2=−0.9,…,x −
​ n=1?

Answers

The underlying function f(x - i) that generates the observed points f'(x - i) in the plot can be determined by integrating the observed points. By integrating f'(x - i), we can obtain f(x - i) up to a constant of integration.

The constant of integration can be determined by incorporating additional information or constraints related to the problem or by considering the behavior of the function at a specific point.

To find the underlying function f(x - i) that generates the observed points f'(x - i), we need to integrate the observed points.

Integration is the reverse process of differentiation, so by integrating f'(x - i), we can recover f(x - i) up to a constant of integration.

The constant of integration arises because integration does not provide a unique solution.

The constant represents an arbitrary additive term that can vary depending on the specific problem or additional constraints.

To determine the constant of integration, we may need additional information or consider specific conditions related to the problem.

It is also important to note that the accuracy of estimating the underlying function f(x - i) depends on the quality and quantity of the observed data points f'(x - i). More data points and precise measurements can lead to a better estimation of the underlying function.

Additionally, the behavior of the function at a specific point can provide valuable insights for determining the constant of integration and refining the estimation of the underlying function.

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Andy rapidly pedaled his bike to reach a certain speed, then continued at that speed. He rapidly pedaled again, then quickly pressed on his brakes to come to a stop.
Which graph best represents Andy’s bike ride?

Andy rapidly pedaled his bike to reach a certain speed, then continued at that speed. He rapidly pedaled
Andy rapidly pedaled his bike to reach a certain speed, then continued at that speed. He rapidly pedaled
Andy rapidly pedaled his bike to reach a certain speed, then continued at that speed. He rapidly pedaled
Andy rapidly pedaled his bike to reach a certain speed, then continued at that speed. He rapidly pedaled

Answers

The 1st graph best represents Andy’s bike ride

How to determine which graph best represents Andy’s bike ride?

(Consider the image I attached)

Andy's speed and time were initially at point 1 (starting point). That is he is not moving

If he rapidly pedaled his bike to reach a certain speed. That is, he moved from point 1 to point 2. This implies the speed increase with an increase in time.

Then continued at that speed.  That is, he moved from point 2 to point 3.   This implies the speed remains the same with an increase in time

He rapidly pedaled again. That is, he moved from point 3 to point 4. The speed increase with an increase in time again.

Then quickly pressed on his brakes to come to a stop. That is, he moved from point 4 to point 5.

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Andy rapidly pedaled his bike to reach a certain speed, then continued at that speed. He rapidly pedaled

mary drew a picture of a building. she used the scale shown 1 in:16 ft. the building in her pictures 9 inches tall. what is the height, in feet, of the actual building.

Answers

Answer:

okay

i am not sure the answer but hi i am ok

The probability distribution is?
Answer is not positively skewed.

The probability distribution is?Answer is not positively skewed.

Answers

Answer: This is negatively skewed

Step-by-step explanation: we can see that the graph increases from left to right, hence it is skewed to the left. In Statistics, we call left skews "negative". Also bro, this stuff was due like a week ago on edge, gl getting back on track man :)

Tekan-Tekan Sdn. Bhd. has order for 200 Model AS-120 calculator for delivery on day 200. The calculator consists of three parts. Components 2 and 3 form subassembly 1 . Sub-assembly 1 and component 4 form the final assembly. Following are the work centers and times of each operation. Table Q3(a) shows routine file of the operation. Assuming: - Only one machine is assigned to each operation - The factory works on 8-hour shift, 5 days a week - All parts move in one lot of 200. (a) Illustrate the backward schedule based on the information given above. (12 marks) (b) Identify when component 3 must be started to meet the delivery date. (2 marks)

Answers

Component 3 must be started on day 197 to meet the delivery date of day 200.

To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.

(a) Backward schedule:

Operation    |  Work Center  |  Time (hours)  |  Start Day

--------------------------------------------------------

Final Assembly |   Work Center 1  |        1       |     200

Sub-assembly 1 |   Work Center 2  |        2       |     199

Component 4     |   Work Center 3  |        3       |     197

Component 2     |   Work Center 4  |        4       |     196

Component 3     |   Work Center 5  |        3       |     ????

(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.

From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.

Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.

Hence, component 3 must be started on day 197 to meet the delivery date of day 200.

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plsssssssssssssssss help

plsssssssssssssssss help

Answers

Answer:

1/2

Step-by-step explanation:

do trust me on this one if you dare go head

Answer: 1/2

Step-by-step explanation:

Do the rise over run strategy, go up 1 and then right 2

Two 7th grade , Monique and Matt, both solved the following math problem.

If the temperature drops from 30*F to -5*F by how much did the temperature decrease?
The students came up with different answers.Monique said the answer is 35*F , And Matt said the answer is 25*F. Who is correct?

Two 7th grade , Monique and Matt, both solved the following math problem.If the temperature drops from

Answers

Answer:

Monique is correct

Step-by-step explanation:

The actually temperature decrease = 30 - (-5) = 35*F

Monique is correct

solve for E, in S=E^2/Z

Answers

Answer:

E = √(SZ).

Step-by-step explanation:

S=E^2/Z

Multiply both sides by Z:

SZ = E^2

E = √(SZ)

this is an emergency please help!!!!!!!!!!!!!

its d0wn below will mark brainlist

Answers

Answer:

ill edit this message in a moment with the answers

Step-by-step explanation:

Which of the following is a perfect square?

A.) 115
B.) 169
C.) 154
D.) 279

Answers

Answer:

B (169)

Step-by-step explanation:

As part of the Pew Internet and American Life Project, researchers surveyed a random sample of 800 teens and a separate random sample of 400 young adults. For the teens, 79% said that they own an iPod or MP3 player. For the young adults, this figure was 67%. Do the data give convincing evidence of a difference in the proportions of all teens and young adults who would say that they own an iPod or MP3 player? State appropriate hypotheses for a test to answer this question. Define any parameters you use.

Answers

the data provide convincing evidence of a difference in the proportions of teens and young adults who own an iPod or MP3

To determine if there is convincing evidence of a difference in the proportions of all teens and young adults who own an iPod or MP3 player, we can perform a hypothesis test.

Let's define the following parameters:

- p₁: Proportion of all teens who own an iPod or MP3 player.

- p₂: Proportion of all young adults who own an iPod or MP3 player.

The null hypothesis (H₀) assumes that there is no difference between the proportions:

H₀: p₁ = p₂

The alternative hypothesis (H₁) assumes that there is a difference between the proportions:

H₁: p₁ ≠ p₂

To test this hypothesis, we can use a two-proportion z-test. We calculate the test statistic using the formula:

z = ((p₁ - p₂) - 0) / √((\(\hat{p}_1\) * (1 - \(\hat{p}_1\)) / n₁) + (\(\hat{p}_2\) * (1 - \(\hat{p}_2\)) / n₂))

Where:

- \(\hat{p}_1\): Sample proportion of teens who own an iPod or MP3 player (79% or 0.79)

- \(\hat{p}_2\): Sample proportion of young adults who own an iPod or MP3 player (67% or 0.67)

- n₁: Sample size of teens (800)

- n₂: Sample size of young adults (400)

Using the given values, we can calculate the test statistic:

z = ((0.79 - 0.67) - 0) / √((0.79 * (1 - 0.79) / 800) + (0.67 * (1 - 0.67) / 400))

Calculating this yields the test statistic z = 5.525.

Next, we can determine the critical value or p-value associated with this test statistic using a significance level (α). Assuming a significance level of 0.05, for a two-tailed test, the critical values are approximately -1.96 and 1.96.

Since the calculated test statistic (5.525) is beyond the critical values of -1.96 and 1.96, we can reject the null hypothesis. There is convincing evidence to suggest that there is a difference in the proportions of all teens and young adults who own an iPod or MP3 player.

In conclusion, the data provide convincing evidence of a difference in the proportions of teens and young adults who own an iPod or MP3 player.

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The appropriate hypotheses for testing the difference in proportions of all teens and young adults who own an iPod or MP3 player are:

Null Hypothesis (H0): The proportion of teens who own an iPod or MP3 player is equal to the proportion of young adults who own an iPod or MP3 player.

Alternative Hypothesis (Ha): The proportion of teens who own an iPod or MP3 player is not equal to the proportion of young adults who own an iPod or MP3 player.

To test if there is a significant difference in the proportions of all teens and young adults who own an iPod or MP3 player, we need to set up appropriate hypotheses. Let's denote the proportion of teens who own an iPod or MP3 player as p1 and the proportion of young adults who own an iPod or MP3 player as p2.

The null hypothesis (H0) assumes that there is no difference between the proportions, so we can state it as:

H0: p1 = p2

The alternative hypothesis (Ha) assumes that there is a difference between the proportions, so we can state it as:

Ha: p1 ≠ p2

Here, p1 represents the true proportion of teens who own an iPod or MP3 player, and p2 represents the true proportion of young adults who own an iPod or MP3 player.

To test these hypotheses, we can use a significance level (α) of 0.05, which is a common choice in hypothesis testing. If the p-value (the probability of observing a test statistic as extreme as the one calculated) is less than 0.05, we reject the null hypothesis and conclude that there is a significant difference in the proportions.

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when graphing frequency distributions, ________ are most commonly used to depict simple descriptions of categories for a single variable.

Answers

When graphing frequency distributions, bar charts are most commonly used to depict simple descriptions of categories for a single variable.

Bar charts provide a visual representation of the frequencies or counts of different categories or classes of a variable.

A bar chart consists of a series of rectangular bars, where the length or height of each bar represents the frequency or count of the corresponding category. The categories are displayed on the horizontal axis, while the frequency or count is shown on the vertical axis. Each bar is separate and distinct, allowing for easy comparison between categories.

The use of bar charts is particularly effective when working with categorical or discrete variables. Categorical variables represent data that can be divided into distinct groups or categories, such as colors, types of animals, or levels of satisfaction. By using a bar chart, we can clearly visualize the distribution of data across these categories.

Bar charts have several advantages that make them suitable for displaying frequency distributions. Firstly, they are easy to understand and interpret. The length or height of each bar directly corresponds to the frequency or count, making it straightforward to identify the relative magnitudes of the categories. Additionally, the spacing between the bars allows for clear differentiation between categories, enhancing readability.

Furthermore, bar charts facilitate the comparison of frequencies or counts across different categories. By aligning the bars side by side, we can easily assess the differences in frequencies or counts between categories. This visual comparison is especially useful for identifying dominant or minority categories, patterns, or trends within the data.

Bar charts also allow for additional visual enhancements to convey additional information. For example, different colors can be used to represent different categories, making it easier to distinguish between them. Labels can be added to the bars or axes to provide further context or explanation. These visual cues help in enhancing the overall clarity and communicability of the graph.

It is worth noting that bar charts are most appropriate when dealing with discrete or categorical variables. For continuous variables, a histogram is commonly used to depict the frequency distribution. Histograms are similar to bar charts, but the bars are connected to form a continuous distribution to represent the frequency or count of data within specific intervals or bins.

In conclusion, when graphing frequency distributions, bar charts are the most commonly used method to depict simple descriptions of categories for a single variable. Bar charts provide a clear and intuitive visual representation of the frequencies or counts of different categories, facilitating easy comparison and interpretation of the data. Their simplicity and versatility make them a valuable tool in data analysis and visualization.

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9x-3÷3 = 2x+2÷6 solve​

Answers

Using BODMAS principle
9x-1=2x+1/3
9x-2x=1+1/3
7x=4/3
x=4/21

Answer:

Hope this is helpful to you

Step-by-step explanation:

9x-3÷3 = 2x+2÷6

or,9x-2x=2÷6+3×3

or,7x=0.33+3×3

or,7x=0.33+9

or,7x=9.33

or,x=9.33/7

;x=1.33

What is the location of the second endpoint if the first endpoint is at (5,2) and
the midpoint is at (-5,5)?

Answers

The second midpoint is (-15,8)

The measures of the angles of a triangle are shown in the figure below. Solve for x.

The measures of the angles of a triangle are shown in the figure below. Solve for x.

Answers

Answer:

x=17 degrees

Step-by-step explanation:

All 3 angles = 180 degrees

So 90 + 54 + (x+19) = 180

Combine like terms

163 + x = 180

Subtract 163 from both sides

x = 180-163

x = 17

HELP PLEASE AND SHOW WORK​

HELP PLEASE AND SHOW WORK

Answers

Answer:

7 seconds, 6 seconds

Step-by-step explanation:

a) For the object to reach the ground, the height from the ground has to be 0. therefore, let the function h = 0

0 = -16t^2 + 700

the amswers are + or - 6.61

we cant have negative time so it is approximately 7 seconds.

b) for the object to reach a 100 feet, h =100

100 = -16t^2 + 700

0 = -16t^2 + 600

solve: + or - 6.12

therefore it takes approximately 6 seconds to reach 100 feet.

The quantity of charge through a conductor is modeled as
Q=0.004t^4-0.015t+6.00mC.
What is the current at time t= 3.35 s?
I(t=3.35s) = ___ A

Answers

To find the current at time t = 3.35 s, we need to differentiate the charge function Q with respect to time (t) to obtain the current function I(t).

Given: Q = 0.004t^4 - 0.015t + 6.00 mC

Taking the derivative of Q with respect to t:

dQ/dt = 0.016t^3 - 0.015

The current function I(t) represents the rate of change of charge with respect to time, which is equal to the derivative dQ/dt. Therefore, we can evaluate the current at t = 3.35 s by substituting the value of t into the current function:

I(t=3.35s) = 0.016(3.35)^3 - 0.015

Calculating this expression:

I(t=3.35s) = 0.016(37.226) - 0.015

I(t=3.35s) ≈ 0.59536 - 0.015

I(t=3.35s) ≈ 0.58036 A

Therefore, the current at time t = 3.35 s is approximately 0.58036 A.

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HELP ASAP ! Find the slope of the line.

A. \(\frac{1}{3}\)

B. 3

C. -\(\frac{1}{3}\)

D. -3

HELP ASAP ! Find the slope of the line.A. [tex]\frac{1}{3}[/tex]B. 3C. -[tex]\frac{1}{3}[/tex]D. -3

Answers

Answer:

A. \(\frac{1}{3}\)

Step-by-step explanation:

Slope = rise/run or (y2 - y1) / (x2 - x1)

Pick 2 points (0,2) (3,3)

We see the y increase by 1 and the x increase by 3, so the slope is

m = 1/3

So, the answer is A. \(\frac{1}{3}\)

Vector
A
is in the direction 39.0

clockwise from the −y-axis. The x-component of
A
is A
x

=−18.0 m. What is the y-component of
A
? Express your answer with the appropriate units. Part B What is the magnitude of
A
? Express your answer with the appropriate units.

Answers

A vector is in the direction 39.0∘ clockwise from the −y-axis. The x-component of A is Ax = -18.0 m. What is the y-component of A? To determine the y-component of A, we will use the trigonometric ratio.

sinθ = opposite/hypotenuse where θ = 39.0°, hypotenuse = |A|, and opposite = Ay. Therefore, sinθ = opposite/hypotenuse Ay/|A| = sinθ ⟹ Ay = |A| sinθSince A is in the third quadrant, its y-component is negative.

Ay = - |A| sinθWe know the x-component and we know that it is negative, so the vector is in the third quadrant, and the y-component is negative.

Ax = -18.0 m, θ = 39.0°We know that the magnitude of A is:

A = √(Ax² + Ay²)Since Ax = -18.0 m, we can substitute it into the equation:

A = √((-18.0)² + Ay²)B) The magnitude of A is |A| = 19.4 m.

We can conclude that the y-component of A is -11.5 m, and the magnitude of A is 19.4 m.

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Final answer:

The y-component of vector A, given that the vector is pointing 39 degrees clockwise from the -y axis and has an x-component of -18 m, is approximately -14.67 m. The magnitude of this vector is about 23.03 m.

Explanation:

Firstly, since the vector A is pointing 39 degrees clockwise from the -y axis, it means our angle with respect to the standard x-axis is 180-39 = 141 degrees. We use the trigonometric relation cos(α) = Ax/A or Ax = A cos(α) to isolate A in the equation (magnitude of A), we get that A = Ax/cos(α). Substituting given values, we get A approximately equal to 23.03 m.

Then, the y-component can be found using sine relation: Ay = A sin(α). Substituting A=23.03 m and α= 141 degrees gives us Ay approximately equal to -14.67 m. Therefore, the y-component of A is -14.67 m and the magnitude of A is approximately 23.03 m.

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Estimate the minimum number of subintervals to approximate the value of 12 ds with an error of magnitude less than 10 -5 S 1 a the error estimate formula for the Trapezoidal Rule. b. the error estimate formula for Simpson's Rule. using Save

Answers

a) The error estimate formula for the Trapezoidal Rule is given by:Error ≤ (b - a)³ * max|f''(x)| / (12 * n²)

Where:

- Error is the maximum error in the approximation.

- (b - a) is the interval length.

- f''(x) is the second derivative of the function.

- n is the number of subintervals.

In this case, we want the error to be less than 10^(-5), so we can set up the inequality:

(b - a)³ * max|f''(x)| / (12 * n²) < 10^(-5)

Since we want to estimate the minimum number of subintervals, we can rearrange the inequality to solve for n:

n² > (b - a)³ * max|f''(x)| / (12 * 10^(-5))

n > sqrt((b - a)³ * max|f''(x)| / (12 * 10^(-5)))

We need to know the values of (b - a) and max|f''(x)| to calculate the minimum number of subintervals.

b) The error estimate formula for Simpson's Rule is given by:

Error ≤ (b - a)⁵ * max|f⁴(x)| / (180 * n⁴)

Where:

- Error is the maximum error in the approximation.

- (b - a) is the interval length.

- f⁴(x) is the fourth derivative of the function.

- n is the number of subintervals.

Similar to the Trapezoidal Rule, we can set up an inequality to estimate the minimum number of subintervals:

(b - a)⁵ * max|f⁴(x)| / (180 * n⁴) < 10^(-5)

Rearranging the inequality:

n⁴ > (b - a)⁵ * max|f⁴(x)| / (180 * 10^(-5))

n > ([(b - a)⁵ * max|f⁴(x)|] / (180 * 10^(-5)))^(1/4)

Again, we need the values of (b - a) and max|f⁴(x)| to compute the minimum number of subintervals.

Please provide the specific values of (b - a), f''(x), and f⁴(x) to proceed with the calculations and estimate the minimum number of subintervals for both the Trapezoidal Rule and Simpson's Rule.

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The cost of three gallons of milk is $8.85 and five gallons of milk is $14.75.

Answers

Answer:

2.95 each

Step-by-step explanation:

i believe this means it’s 2.95 each

heyy! i’ll give brainliest please help

heyy! ill give brainliest please help

Answers

Answer:

option 2nd it you answer

Plz help me solve for x and y

Plz help me solve for x and y

Answers

Answer:

x = 40°

y = 30°

Step-by-step explanation:

Given parallelogram ABCD :

∠A = 3x°∠B = 2y°∠C = 120°∠A = ∠C∠B = ∠D∠A + ∠B = 180°∠B + ∠C = 180°∠A + ∠B + ∠C + ∠D = 360°

∠A = ∠C

3x = 120

x = 120 ÷ 3

x = 40°

∠B + ∠C = 180°

2y + 120 = 180

2y = 180 - 120

2y = 60

y = 60 ÷ 2

y = 30°

Answer:

x = 40°

y = 30°

Step-by-step explanation:

Given the diagram of a parallelogram, where:

∠A = 3x°, ∠B = 2y°, and ∠C = 120°

The given problem also requires us to find the values of x and y.

In reference to the Parallelogram Opposite Angles Theorem, where it states that: if a quadrilateral is a parallelogram, then it will have congruent opposite angles.  In other words, ∠A ∠C , and ∠B ∠D.

Solve for x:

Hence, we can establish the following equality statement to solve for the value of x:

m∠A = m∠C

3x° =  120°

Divide both sides by 3 to solve for x:

\(\displaystyle\mathsf{\frac{3x^{\circ}}{3}=\:\frac{120^{\circ}}{3}}\)

x = 40°

Therefore, the value of x = 40°.

Solve for y:  

In order to solve for y, we must refer to the Parallelogram Consecutive Angles Theorem, where it states that if a quadrilateral is a parallelogram, then its consecutive angles are supplementary whose sum add up to 180°.

In the given diagram, ∠A and ∠D, ∠B and ∠C are consecutive angles.  

We can establish the following equation to solve for the value of y:

m∠B + m∠C = 180°

2y° + 120° = 180°

Subtract 120° from both sides:

2y° + 120° - 120° = 180° - 120°

2y° = 60°

Divide both sides by 2 to solve for y:

\(\displaystyle\mathsf{\frac{2y^{\circ}}{2}=\:\frac{60^{\circ}}{2}}\)

y = 30°

Therefore, the value of y = 30°.

tentukan panjang BC dari gambar berikut​

Answers

Answer:

man I

Step-by-step explanation:

hey

Answer:

manatap Fanny neff

Franko

Step-by-step explanation:

alucard

order Operation

SIMPLIFY : −2b−5z−6+4b−3z​

Answers

Answer:

2b - 8z - 6

Step-by-step explanation:

Rearrange the equation, so like terms are near each other

-2b+4b-3z-5z-6

Now we add the b's and z's to get,

2b - 8z - 6

Answer:

2b -8z -6

Step-by-step explanation:

−2b−5z−6+4b−3z​

Combine like terms

−2b+4b−5z−3z​−6

2b -8z -6

Need help it’s really hard

Need help its really hard

Answers

Given:

\(OA=3\) units

\(OA'=9\) units

To find:

The scale factor of the dilation.

Solution:

From the given figure it is clear that the center of dilation is point O. Point A' is the image of point A. So,

\(\text{Scale factor}=\dfrac{OA'}{OA}\)

Putting the given values, we get

\(\text{Scale factor}=\dfrac{9}{3}\)

\(\text{Scale factor}=3\)

Therefore, the scale factor of the dilation is 3.

Mr. ivin's algebra class is learning the pythagorean theorem. he has two students that are auditory learners and are struggling with the concept. what activity would best help them learn the theorem?

Answers

In a right - angled triangle, the square of the hypotenuse of a triangle is equal to the sum of the square of the other two sides.

Step 1: Make a right - angled triangle with base, perpendicular and hypotenuse has length of their side a, b, c respectively.

Step 2: Make squares on the base, perpendicular and hypotenuse with side length a, b and c respectively.

Step 3: Now measure the area of square with side b and a, which are on perpendicular and base of a triangle respectively.

Step 4: Measure the area of the with side c, which is on the hypotenuse of a triangle, area is: \(c^{2}\).

Step 5: Add the area of squares with sides a and b, sum of their area is: \(a^{2} + b^{2}\).

Observation and Result:

We will notice that the area of square with side a and b is equal to the area of square with side c.

\(a^{2} + b^{2} = c^{2}\)

∴ The square of the hypotenuse in a right-angled triangle is equal to the sum of the square of the other two sides.

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Mr. ivin's algebra class is learning the pythagorean theorem. he has two students that are auditory learners

In a right  triangle, the square of the hypotenuse of the triangle is equal to the sum of the squares of the other two sides.

Construct a right triangle with base, perpendicular and hypotenuse lengths a, b and c respectively.

Create a square with base, perpendicular and hypotenuse sides of lengths a, b and c respectively.

Next, measure the area of ​​the square whose sides b and a are  perpendicular and base of the triangle, respectively.

If you measure the area of ​​side c that is the hypotenuse of the triangle,  the area is c².

Adding the areas of the squares with sides a and b gives the sum of their area gives  a² + b².

Note that the area of ​​the square with sides a and b is equal to the area of ​​the square with side c.  

a² + b² = c²

Therefore, the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

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