Answer:
Fx = 35.36 N
Fy = 35.36 N
Explanation:
From the question,
The X component of the force is
Fx = Fcos∅.................. Equation 1
Where Fx = X component of the force, F = Force, ∅ = Angle to the horizontal.
Give: F = 50 N, ∅ = 45°
Substitute into equation 1
Fx = 50(cos45°)
Fx = 50(0.7071)
Fx = 35.36 N
Similarly,
For Y component
Fy = Fsin∅
Where F y = Y component
Fy = 50(sin45°)
Fy = 50(0.7071)
Fy = 35.36 N
Give Example of mental flexibility
Answer:
If you ring the doorbell and no one opens the door, you'll infer that no one is home rather than continuing to ring the doorbell to an empty house. Being able to understand this and look for another solution is another example of mental flexibility.
Explanation:
A solar-powered car has a kinetic energy of 110250 J. Its mass is 180 kg. Work out how fast the car is travelling Enter a number m/s
Answer: Velocity = v = 35 m/s
Explanation:
Kinetic energy of an object is defined as the energy possess by an object due to its motion. Kinetic energy K.E of an object is equal to the half of the mass of that object multiplied by square of the object's velocity.
Mathematically,
v = 35 m/s
What would happen if an Asteroid hit earth?
Answer:
There would be tremendous earthquakes and tsunamis, followed by massive volcanism around the impact zone. The ozone layer would be destroyed. The oceans would turn acidic. The Sun would be blotted out, probably for decades.
Explanation:
Hope this helps!
Answer: Well it depends on the size. If the asteroid was the size of a basketball, it would most probably turn to dust by the time it reaches the surface. But, if it was the size of Australia, then most probably everyone would die.
Explanation:
On Mars, which has 0.38 the gravity of Earth, the acceleration of
a dropped ball will be _ m/s2 and the weight of a 50 kg
basketball player would be
_N.
Answer:
if g on Earth= 9.8m/s²
then g on moon will be 0.38 *9.8=3.7m/s²
Mass of a basketball player is 50kg then the weight will be 50*3.7=186.2N
an electron of kinetic en- ergy 1.20 kev circles in a plane per- pendicular to a uniform magnetic field.the orbit radius is 25.0 cm. find (a) the electron’s speed, (b) the magnetic field magnitude, (c) the circling frequency, and (d) the period of the motion.
The final answers are:
(a) The electron's speed
(b) The magnetic field magnitude
(c) The circling frequency
(d) The period of the motion.
The given information in the question is as follows:
- Kinetic energy of the electron = 1.20 keV
- Orbit radius of the electron = 25.0 cm
To find:
(a) The electron's speed
(b) The magnetic field magnitude
(c) The circling frequency
(d) The period of the motion
Let's solve each part step-by-step:
(a) To find the electron's speed, we can use the kinetic energy equation:
Kinetic Energy = (1/2) * mass * speed^2
Since we are given the kinetic energy, we need to find the mass of the electron. The mass of an electron is approximately 9.10938356 × 10^-31 kg.
Substituting the values into the equation:
1.20 keV = (1/2) * (9.10938356 × 10^-31 kg) * speed^2
Now, we can solve for the speed of the electron.
(b) The magnetic field magnitude can be found using the formula for the magnetic force on a charged particle moving in a magnetic field:
F = q * v * B
Where F is the magnetic force, q is the charge of the electron, v is the velocity of the electron, and B is the magnetic field magnitude.
Since the electron is moving in a circular path perpendicular to the magnetic field, the magnetic force provides the necessary centripetal force for circular motion:
F = m * (v^2 / r)
Where m is the mass of the electron and r is the radius of the circular path.
Setting these two equations equal to each other:
q * v * B = m * (v^2 / r)
We can now solve for the magnetic field magnitude, B.
(c) The circling frequency can be found using the formula:
Frequency = speed / (2 * π * radius)
Substituting the given values, we can calculate the circling frequency.
(d) The period of the motion is the reciprocal of the circling frequency. Therefore, we can find the period by taking the reciprocal of the circling frequency.
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What characteristics do scientists look for when determining if something is alive?
Scientists look for certain characteristics such as the ability to grow, reproduce, respond to stimuli, maintain homeostasis, and obtain and use energy to determine if something is alive.
There are several characteristics that scientists use to determine if something is alive, including:
Metabolism: the ability to acquire, use, and transform energy and matter from the environment.Growth: the ability to increase in size or number of cells.Response to stimuli: the ability to respond to changes in the environment.Reproduction: the ability to produce offspring either sexually or asexually.Adaptation: the ability to change and adapt to the environment through evolution.Organization: living organisms are made up of cells, tissues, and organs that work together to perform functions necessary for life.These characteristics are used to differentiate living organisms from non-living objects.
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a force of 200N is exerted horizontally on a box of mass 18kg to displace it through a distance of 6m.how much work is done. Please help me and I will make you as brainliest
Answer:
1200
Explanation:
W=FD
W= work done
F= Force
D= distance
So, 200*6=1200
A 1200-kilogram car traveling at 10. Meters per second is brought to rest in 0. 10 second. What is the magnitude of the average force that acted on the car to bring it to rest? A)1. 2 x 103N B )1. 2 x 10?N © 1. 2 x 105 N D) 1. 2 x 10°N
The average force that acted on the car to bring it to rest is 1.2 × 10⁵ Newton.
What is force?
The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
The average force that acted on the car to bring it to rest is = - Change in momentum of the car/time interval
= (initial momentum - final momentum)/time interval
= (1200 kg × 10 m/s)/0.10 second
= 1.2 × 10⁵ Newton
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Calculate the pressure on the bottom of a swimming pool 3. 5 m deep. How does the pressure compare with atmospheric pressure, 105 Pa? (density of water=1000kg/m3 ).
Answer:
1.343 atm
Explanation:
The mass of water above 1 square meter of swimming pool bottom is ...
M = (3.5 m)·(1000 kg/m^3) = 3500 kg/m^2
Then the force exerted by the water on the pool bottom is ...
F = Mg = (3500 kg/m^2)(9.8 m/s^2) = 34300 N/m^2 = 34300 Pa
Compared with atmospheric pressure, this is ...
34,300/10^5 = 0.343 . . . . atmospheres
Added to the atmospheric pressure on the water's surface, the total pressure on the pool bottom is 1.343 atmospheres.
Beginning with the equation, ρR = ρsubstance /ρwater show that ,
Relative Density = mass of substance / mass of water
i.e ρR = msubstance /mwater , if the volume are equal
( you must prove that the equation is true)
\( \huge \boxed {\mathcal{Hey \: \: \: there \: \: !!}}\)
solution :we know,
\( \boxed{density = \dfrac{mass}{volume} }\)
let the mass of substance be \( m_1 \)
and volume be \( v \)
density of substance :
\(ds = \dfrac{m_1 }{v} \)now, let the mass of water be \( m_2 \)
and volume be \( v \)
density of water :
\(dw = \dfrac{m_2}{v} \)relative density :
\( \dfrac{ds}{dw} \)\( \dfrac{m1}{v} \div \dfrac{m2}{v} \)since, volume is same they would cancel off
\( \boxed{relative \: \: density \: \: = \dfrac{m1}{m2} }\)proved...
Elements in Group
are common alkaline earth metals.
Answer here
a celebrity i would like to meet mind map
Answer:
I would wanna meet juice if he was still alive ofc
Explanation:
what is reversible change?
what is ireversible change?
Answer:
Reversible change
A reversible change is a change that can be undone or reversed.
Irreversible change
A change is called irreversible if it cannot be changed back again.
Explanation:
A change which can happen backward, that is, can be reversed is called a reversible change. A change that cannot happen backward, that is, it cannot be reversed is called an irreversible change.
ARMY right?
what does the slope of a speed vs time graph means
Answer:
speed = m/s on y axis
time = s on x axis
when you calculate the slope you do y2-y1/x2-x1 right?
m/s/s become \(m/s^2\), which is the unit of acceleration
On a speed vs time graph, if you see that the line is constant, then acceleration = 0 because there is no difference in speed, you are not acceleration or decelerating.
So in summary, it's acceleration
Hope that that answers your question
Don't hesitate to leave a comment if you are confused about something
Explanation:
A locomotive starts from rest and accelerates at 0.12 m/s^2 to a speed of 2.4 m/s in 20 s. This motion could best be described as
A.) constant acceleration and constant velocity
B.) increasing acceleration and constant velocity
C.) constant acceleration and increasing velocity
D.) increasing acceleration and increasing velocity
Answer:
C
Explanation:
a device that sends out sound waves to detect objects is called
A device that sends out sound waves to detect objects is called sonar device.
What are sound waves?
Sound waves are vibrations of air molecules that propagate through a medium, such as air, water, or solid materials. Sound waves are created when a force, such as a vibrating object, causes particles in the medium to vibrate. The vibrations cause the particles to move in an alternating pattern, creating a wave. The frequency of the wave determines the pitch of the sound. The amplitude of the wave determines the loudness.
Sonar stands for Sound Navigation and Ranging. It is a device that sends out sound waves and measures their echo off objects in the environment to detect their position, size, shape, and other characteristics. Sonar is used for a variety of applications, such as navigation, tracking objects, and detecting underwater obstacles.
Therefore, sonar device is the correct answer.
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help me please I need to finish
The right response is = D. Wave A : low frequency wave, B: high frequency wave.
What is frequency?Frequency is described as the quantity of oscillations or cycles per unit of time. Many physical phenomena, including sound waves, mechanical vibrations, and electromagnetic radiation (including radio waves and light), exhibit frequency.
Compared to high frequency waves, low frequency waves have a longer wavelength and a lower frequency. High frequency waves are often linked to smaller, faster-moving phenomena, whereas they are typically connected to larger, slower-moving phenomena. For example, low frequency waves, which have a lower pitch and are connected to larger objects that vibrate more slowly, like bass notes in music or the rumble of thunder, are examples of sound waves. High frequency waves, like the whistle or bird tweeting, are connected with smaller, faster vibrating objects and have a higher pitch.
High frequency waves, like X-rays, gamma rays, and visible light, have shorter wavelengths and higher energies. These waves are frequently employed in radiation therapy, medical imaging, and other applications that call for high intensity radiation.
Generally, a wave's frequency is a key characteristic that affects how it behaves and may be used in a variety of physics and engineering domains.
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3. The pressure at the bottom of the ocean is great enough to crush submarines with steel walls that are 10 centimeters thick. Suppose a submarine is at a depth of 1,000 meters. The weight of water above each square meter of the submarine is 9,800,000 newtons.
Answer:
just awnsered this one your awnser is the the second option
Answer:
answer one
Explanation:
an intoxicated clockmaker produces a grandfather clock whose pendulum has a period of 3.5\;\mathrm{s}3.5s. what is the length of the pendulum?
The length of the pendulum is equal to 1.35 m.
What is a simple pendulum?A simple pendulum can be described as a mechanical arrangement that exhibits periodic motion. The simple pendulum is made of a small bob of mass ‘m’ suspended by a thin thread hung at its upper end of length L.
The simple pendulum moves in an oscillatory motion and the motion occurs in a vertical plane which is driven by the gravitational force.
The time period of the pendulum is given by:
T = 2π√(L/g)
Where L is the length and g is the gravitational acceleration.
Given, the time period of a pendulum, T = 3.5 s
Then the length of the pendulum can be calculated as:
\({\displaystyle 3.5 = 3\times 3.14 \sqrt{\frac{L}{9.8} }\)
(0.37)² = L/9.8
L = 1.35 m
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A proton and an electron in a hydrogen atom are separated on the average by about 4.8x10-11 m. what is the magnitude and direction of the electric field set up by the proton at the position of the electron?
A proton and an electron in a hydrogen atom are separated on the average by about 4.8x10-11 m. The magnitude and direction of the electric field set up by the proton at the position of the electron is (E)= 6.24×10¹¹ N/C.
What is electric field?The electric field is a field that is created by any positive or negative charge. In an atom the electron or proton that creates a field that called the electric field.
How can we calculate the electric field?To calculate the electric field we are using the formula here ,
E= k(q/r²)
Where we are given,
k= The Coulomb's constant . = 8.99 ×10⁹ N.m²/C²
q= The charge of the electron. = 1.6×10⁻¹⁹ C
r= The distance of separation of atom. = 4.8×10⁻¹¹ m.
We have to calculate the electric field of the atom. = E
Now we put the values we get,
E= k(q/r²)
Or, E= 8.99 ×10⁹×(1.6×10⁻¹⁹/(4.8×10⁻¹¹)²)
Or, E= 6.24×10¹¹ N/C
Now we can say that, The magnitude and direction of the electric field set up by the proton at the position of the electron is (E)= 6.24×10¹¹ N/C.
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python
Write a NumPy program to create random vector of size 15 and replace the maximum value by \( -1 \). Print the original array and the one with maximum replaced by - ?
import numpy as np:
random_vector = np.random.rand(15)
modified_vector = np.where(random_vector == np.max(random_vector), -1, random_vector)
print("Original Array:", random_vector)
print("Modified Array:", modified_vector)
A NumPy program that creates a random vector of size 15, replaces the maximum value with -1, and prints both the original array and the modified array:
```python
import numpy as np
# Create a random vector of size 15
random_vector = np.random.rand(15)
# Find the maximum value in the vector
max_value = np.max(random_vector)
# Replace the maximum value with -1
modified_vector = np.where(random_vector == max_value, -1, random_vector)
# Print the original and modified arrays
print("Original Array:")
print(random_vector)
print("\nModified Array:")
print(modified_vector)
```
When you run this program, it will generate a random vector of size 15 and display the original array. Then, it will replace the maximum value in the array with -1 and display the modified array.
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Two large, charged plates with charge density ±30µC/m^2 face each other with a separation of 5.0 mm. The negative plate is grounded, and defined as 0 potential. Find the electric potential at a location 8.0mm from the negative plate, 3.0mm from the positive plate.
V=3.39×10⁶ ×d for 0≤d≤0.005 m, 7.73x10⁷ m/s is the electric potential at a location 8.0mm from the negative plate, 3.0mm from the positive plate
a. Identify the unknown:
The potential everywhere
List the Knowns:
Charge density of the two plates: σ = ±30×10⁻⁶ C/m²
Distance between the two plates: d=5×10⁻³ m
Permittivity of free space: ε₀=8.85×10⁻¹² C²/N⋅m²
Set Up the Problem:
Since the σ are equal and opposite, this means that in the region outside of the two plates, the electric fields cancel each other out to zero: E = 0 The electric field between the plates is this strong:
E = σ/ε₀ = 30×10⁻⁶/8.85×10⁻¹² = 3.39x10⁶N/C
Possible variations between the positive plate and the negative plate include:
ΔV=Ed=3.39×10⁶ ×0.005=1.7×10⁴ V
Assuming the negatively charged plate is at the origin (d=0) and has no potential, the electric field is directed away from the positively charged plate and towards the negatively charged plate, the positive plate is at (d=+0.005 m) and have 1.7×10⁴ V
Solve the Problem:
V=0 for d<0
V=3.39×10⁶×d for 0≤d≤0.005 m
V=1.7×10⁴ V for d>0.005m
b. Identify the unknown:
when an electron leaves a state of rest at the negative plate and strikes the positive plate, how quickly it moves
List the Knowns:
Electron charge: e=1.6×10⁻¹⁹ C
Electron mass: m=9.11×10⁻³¹ kg
Set Up the Problem:
Potential and electric potential energy have the following relationships: = U/q
U=qV
To move the drop, this potential energy is converted to kinetic energy:
1/2mv²=qV
v = √2qV/m
Solve the Problem:
v = √(2×1.6×10⁻¹⁹×1.7×10⁴/9.11×10⁻³¹) = 7.73x10⁷ m/s
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the starter motor of a car engine draws an electric current of 21.0 a from the battery. the copper wire to the motor is 4.00 mm in diameter and 1.49 m long. the starter motor runs for 0.85 s before the car engine starts up. how much electric charge passes through the starter motor?
The amount of electric charge passing through the starter motor is 17.85 C.
Current = 21.0 A, Diameter of the wire (d) = 4.00 mm = 4.00 × 10⁻³ m, Length of the wire (l) = 1.49 m, Time taken (t) = 0.85 s
We know that the electric charge passing through the starter motor is given by,
Charge (Q) = Current × Time Taken (t)
So, we have
Charge = 21.0 A × 0.85 s
Charge = 17.85 C
Now, we need to find the resistance of the copper wire,Resistance (R) = resistivity × length / Area of cross section (A)
From the formula of the area of cross section of a circle,A = πd²/4∴
A = π × (4.00 × 10⁻³ m)²/4
A = 1.26 × 10⁻⁵ m²
We have to use the resistivity of copper, ρ = 1.72 × 10⁻⁸ Ω m
Resistance = (1.72 × 10⁻⁸ Ω m × 1.49 m) / (1.26 × 10⁻⁵ m²)
Resistance = 2.04 × 10⁻³ Ω
The amount of electric charge passing through the starter motor is 17.85 C.
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Why does a basketball thrown in the air come back to the ground after a
few seconds?
Answer:
gravity would pull the ball towards the center of the earth
Answer:
Hope it helps
Explanation:
This is because the force of earth's gravitational field is always directed downwards (towards the center of the earth. ... When the ball is thrown up, it is going against the earth's gravitational field and so, the earth's gravitational force pulls it back down, accelerating it downwards.
Water flowing through a garden hose of diameter 2.73 cm fills a 23.0-L bucket in 1.60 min.
(a) What is the speed of the water leaving the end of the hose? m/s
(b) A nozzle is now attached to the end of the hose. If the nozzle diameter is one-third the diameter of the hose, what is the speed of the water leaving the nozzle? m/s
Water flowing through a garden hose with a diameter of 2.73 cm fills a 23.0-L bucket in 1.60 min. We need to determine the speed of the water leaving the end of the hose.
(a) To find the speed of the water leaving the end of the hose, we can use the equation Q = A × v, where Q is the volume flow rate, A is the cross-sectional area of the hose, and v is the velocity of the water. The volume flow rate is given by Q = V / t, where V is the volume filled in the bucket and t is the time taken. By substituting the given values, we can calculate the speed of the water leaving the hose.
(b) When a nozzle is attached, we can apply the principle of continuity, which states that the volume flow rate remains constant in a fluid system. Since the nozzle diameter is one-third of the hose diameter, the cross-sectional area of the nozzle is smaller. Using the principle of continuity, we can find the new velocity of the water leaving the nozzle.
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50. Through how many revolutions did the wheel rotate during the 5.0 seconds of braking?
A) 10 rev
B) 2.0 rev
C) 9.6 rev
D) 5.0 rev
E) 0.4 rev
The wheel rotated 150 revolutions during the 5.0 seconds of braking. The closest option is c.
To answer this question, we need to know the rate of rotation of the wheel. Let's call this rate "r". We can find "r" by dividing the initial speed of the wheel by its radius:
r = v / r
r = 20 m/s / 0.5
r = 40 rev/s
Now we can use the formula for rotational motion:
θ = ωt + 1/2 αt²
where θ is the angle of rotation, ω is the initial angular velocity (in rev/s), t is the time, and α is the angular acceleration (which is negative in this case, since the wheel is slowing down).
We want to find θ when t = 5.0 s. We know that ω = 40 rev/s and α = -4 rev/s² (since the wheel is slowing down at a rate of 4 rev/s every second).
θ = ωt + 1/2 αt²
θ = (40 rev/s)(5.0 s) + 1/2 (-4 rev/s²)(5.0 s)²
θ = 200 rev - 50 rev
θ = 150 rev
Therefore, the wheel rotated 150 revolutions during the 5.0 seconds of braking. The answer is not listed, but the closest option is C) 9.6 rev, which is incorrect.
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Can sugar molecules produced from photosynthesis be rearranged into different compounds carry out life process
Answer:
Yes, the sugar molecules produced from photosynthesis can be rearranged into different compounds to carry out life processes such energy producing compounds, energy storage compounds, body building compounds, and compounds of other types of food
Explanation:
a) The sugar can be broken down in a plant cell to produce ATP and then energy through cellular respiration as follows;
C₆H₁₂O₆ + O₂ 6CO₂ + 6H₂O + ATP
The produced energy can be used as power for cellular activities, such as the synthesis of protein and cell division
b) The produced sugar can be linked together by enzymes to form starch which is a form of chemical storage of energy as follows;
Sugar C₆H₁₂O₆ transformed into starch (C₆H₁₀O₅)ₙ
c) The sugar can be used in building the plant body by forming cellulose which is a form of starch
d) The sugar can be transformed into proteins and fat which are other types of food such as compounds containing sugar produces compounds containing fat based compounds
a. A random sample of 150 approved mortgage applications is
selected from a bank’s database. Customers of this bank can choose
either variable or interest-only mortgages. These mortgage choices
have
Out of 150 approved mortgage applications, a random sample may have variable or interest-only mortgages.
we are given that a random sample of 150 approved mortgage applications is either variable or interest-only mortgages. A variable mortgage, also known as an adjustable-rate mortgage (ARM), is a type of mortgage in which the interest rate fluctuates based on market conditions. An interest-only mortgage is a type of mortgage in which the borrower only pays interest on the loan for a certain period of time before beginning to make principal payments.To determine what percentage of the sample is variable or interest-only mortgages, we would need more information on the breakdown of the sample. However, we know that these are two different types of mortgages that borrowers can choose from when applying for a mortgage.
A home loan application is a report submitted to a bank when you apply for a home loan to buy land. The application is extensive and includes information about the borrower's employment history, financial situation, and the property being considered for purchase, among other things.
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a force applied to an object of mass m1 produces an acceleration of 3.60 m/s2 . the same force applied to a second object of mass m2 produces an acceleration of 1.60 m/s2 . what is the value of the ratio m1/m2?
The value of the ratio m1/m2 would be 4.5.
Newton's lawWe can use Newton's Second Law of Motion to solve this problem, which states that force (F) is equal to mass (m) times acceleration (a):
F = ma
Let F be the force applied to both objects. Then we have:
F/m1 = 3.60 m/s^2
F/m2 = 1.60 m/s^2
Dividing the second equation by the first equation, we get:
(F/m2)/(F/m1) = (1.60 m/s^2)/(3.60 m/s^2)
Simplifying the left side, we get:
m1/m2 = (F/m1)/(F/m2) = (m2/m1)*(1.60 m/s^2)/(3.60 m/s^2)
m1/m2 = (m2/m1)*(2/9)
We can rearrange this equation to get:
m1/m2 = (9/2)*(m2/m1)
Therefore, the value of the ratio m1/m2 is 9/2, or approximately 4.5.
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the work done by a force acting through a distance.
Answer:
When a force acts on an object over a distance, it is said to have done work on the object. Physically, the work done on an object is the change in kinetic energy that that object experiences.
Explanation:
google lol
Answer:
When a force acts on an object over a distance, it is said to have done work on the object. Physically, the work done on an object is the change in kinetic energy that that object experiences.
Explanation:
PLZZZZ give me brainliest!!!