Answer:
A
Step-by-step explanation:
Drawing a segment from the left side of the top base to the lower base, creates a right triangle on the left with legs 9 and x₁ and hypotenuse y
Using the tangent ratio in the right triangle and the exact value
tan45° = 1 , then
tan45° = \(\frac{opposite}{adjacent}\) = \(\frac{9}{x_{1} }\) = 1, so x₁ = 9 and
x = 7 + x₁ = 7 + 9 = 16
Using the sine ratio in the right triangle and the exact value
sin45° = \(\frac{1}{\sqrt{2} }\) , then
sin45° = \(\frac{opposite}{hypotenuse}\) = \(\frac{9}{y}\) = \(\frac{1}{\sqrt{2} }\) ( cross- multiply )
y = 9\(\sqrt{2}\)
show that the minimum ratio of cation to anion size for an octahedral (6-fold coordinated) site to be stable is 0.414.
The minimum ratio of cation to anion size for an octahedral (6-fold coordinated) site to be stable is 0.414.
The minimum ratio of cation to anion size for an octahedral (6-fold coordinated) site to be stable is 0.414 can be shown by using the radius ratio rules.
The radius ratio rules state that the ratio of the radius of the cation to the radius of the anion determines the coordination number and the structure of the compound. The minimum and maximum radius ratios for different coordination numbers are as follows:
- Coordination number 2: minimum ratio = 0.155, maximum ratio = 0.225
- Coordination number 3: minimum ratio = 0.225, maximum ratio = 0.414
- Coordination number 4: minimum ratio = 0.414, maximum ratio = 0.732
- Coordination number 6: minimum ratio = 0.732, maximum ratio = 1.000
For an octahedral (6-fold coordinated) site, the minimum ratio of cation to anion size is 0.732. If the ratio is smaller than this, the cation will be too small to fit into the octahedral site and the structure will be unstable. Therefore, the minimum ratio of cation to anion size for an octahedral (6-fold coordinated) site to be stable is 0.414.
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find t−1 for the given isomorphism t. t : p1 → r2 with t(ax b) = 8b a − b
t^-1 is the inverse of t.
To find the inverse of the given isomorphism t, we need to find a function t^-1 : r2 → p1 such that t(t^-1(x,y)) = (x,y) for all (x,y) in r2.
Let (x,y) be an arbitrary element of r2. We want to find (a,b) in p1 such that t(a,b) = (x,y). Using the definition of t, we have:
t(a,b) = (8b, a-b)
Setting this equal to (x,y), we get the system of equations:
8b = x
a - b = y
Solving for a and b in terms of x and y, we get:
a = y + x/8
b = x/8
Thus, we have found a function t^-1 : r2 → p1 given by:
t^-1(x,y) = (y + x/8, x/8)
We can check that this function is indeed the inverse of t:
t(t^-1(x,y)) = t(y + x/8, x/8) = (8(x/8), y + x/8 - x/8) = (x,y)
Therefore, t^-1 is the inverse of t.
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An angle between 180’ and 360’
Step-by-step explanation:
you start with 90 then 180 then270 then 360
what is the largest number of edges in undirected graph with n vertices can have before it must contain a cycle?
The largest number of edges in the undirected graph with 'n' vertices which is before it present cycle is equal to n( n - 1 ) / 2.
Undirected graph represents no direct edges of the graph.In cyclic undirected graph two edges are joined with each other out of n vertices.Maximum possible number of edges in only single are given by ⁿC₂.Simplify ⁿC₂ we get number of edges equals to n! / 2! ( n - 2 )! = n( n- 1 ) / 2.The number of edges in directed graph is twice that of undirected graph.Possible number of edges in acyclic is equal to ( n - 1 ).Therefore, the largest possible number of edges in the undirected graph which has 'n' vertices before it contain a cyclic is equal to n ( n - 1 ) / 2.
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in application 3, suppose that we are searching the database of seven linear algebra books for the search words elementary, matrix, algebra. form a search vector x, and then compute a vector y that represents the results of the search. explain the significance of the entries of the vector y.
In application 3, the search vector x is a vector of words (e.g. elementary, matrix, algebra) used to search the database of seven linear algebra books. The vector y represents the results of the search, with each entry of y corresponding to the number of times a word in the search vector x appears in a book. The entries in y provide insight into how relevant a particular linear algebra book is to the search vector x.
In application 3, suppose that we are searching the database of seven linear algebra books for the search words elementary, matrix, algebra. The search vector x can be defined as x = [1, 1, 1] because all of the search terms appear only once in the search query. The next part of the question and compute a vector y that represents the results of the search.Vector y is computed by multiplying the search vector x by the book matrix A, as shown below. y = [1 1 1] · [3 1 1 0 0 1 1; 1 3 0 1 1 0 1; 0 0 2 0 1 1 1] = [4 4 3 1 2 2 3].
Next up to explain the significance of the entries of the vector y. The result vector y contains seven entries, one for each book. The value of each entry represents how well the book matches the search query, with larger numbers indicating a better match.
As a result, y can be used to rank the books in order of relevance to the search query. The first and second books have the best match with a score of four, while the third book has a score of three, which is also quite strong.
The fourth, fifth, and sixth books have scores of one or two, indicating that they are not well suited to the search query.
Finally, the seventh book has a score of three, indicating that it is moderately well suited to the search query.
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Solve for x.
-4(x-5)=-24
Answer:
x = 11
Step-by-step explanation:
First distribute the -4 to x-5. This would get you -4x + 20 = -24. Now subtract 20 from both sides and get -4x = -44. Divide -4 from both sides, and get
x = 11.
79/15 en decimal???????????
Answer:
5.267
Step-by-step explanation:
Let's do long division to figure this out.
Answer: 5.26666666667
Step-by-step explanation:
If your asking for the decimal answer, than it is 5.26666666667, or you can round it to 5.3. :)
3. Find f(-2) for
the function below.
f(x) = 9• (1/5)^x
Answer: f(-2) = 225
Step-by-step explanation:
Plug in x which is -2 because f(x) = f(-2):
f(-2) = 9 • 1/5^-2
f(-2) = 9 • 25
f(-2) = 225
Hope this helps!
Answer:225
Step-by-step explanation:
BIG BRaIN
One cubic meter represents a cube shape that measures 1 meter in all three dimensions. how long is each side in centimeters?
Each side of cube is 100 cm.
What is a cube?In Maths or in Geometry, a Cube is a solid three-dimensional figure, which has 6 square faces, 8 vertices and 12 edges. It is also said to be a regular hexahedron.
Given that,
Volume of cube = 1 cubic meter
We know that,
1 m = 100 cm
Also volume of cube = \(a^{3}\)
Then,
Volume of cube = 1000000 cm
\(a^{3}\) = \(100^{3}\)
a = 100 cm
Hence, Each side of cube is 100 cm.
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why does (-96) ÷ (-6) = 16
1 ls 25% of what number?
Answer:
1 is 25% of 4
25 x 4 = 100
1 x 4 = 4
we have 9 balls of colours red, green and blue, 3 balls of each color (balls of the same color are identical). we want to place them in the sequence in such a way that no two blue balls are next to each other. how many ways do we have to do it?
There are 347,760 ways to arrange the 9 balls of colors red, green, and blue such that no two blue balls are next to each other. The principle of inclusion-exclusion is used to solve this problem.
First, we calculate the total number of ways to arrange the 9 balls without any restrictions. This can be done using the formula for permutations of n objects, which is n! (n factorial) in this case. So we have:
9! = 362,880
Next, we calculate the number of ways to arrange the balls with two blue balls next to each other. We can treat the two blue balls as a single object and arrange the remaining 7 objects in 7! ways. However, we also need to consider the 3 different ways to choose which two blue balls are next to each other. So we have:
3 x 7! = 15,120
Finally, we need to subtract the number of arrangements with two blue balls next to each other from the total number of arrangements to get the number of arrangements without any two blue balls next to each other:
9! - 3 x 7! = 347,760
Therefore, there are 347,760 ways to arrange the 9 balls of colors red, green, and blue such that no two blue balls are next to each other.
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Given the inequality 3(n − 6) < 2(n + 12), determine which integer makes the inequality false.
S:{−5}
S:{3}
S:{12}
S:{42}
The solution of the inequality 3(n - 6) > 2(n + 12) will be less than 42. Then the correct option is D.
What is inequality?Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.
The inequality is given below.
3(n - 6) < 2(n + 12)
Simplify the inequality, then we have
3(n - 6) < 2(n + 12)
3n - 18 < 2n + 24
3n - 2n < 24 + 18
n < 42
The solution of the inequality 3(n - 6) > 2(n + 12) will be less than 42. Then the correct option is D.
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Managers of a movie theater company want to learn more about what types of premium services their customers who participate in the theater's loyalty program most desire and would be willing to pay a premium price for. The managers use a computer program that selects customers in a lottery style from the company's database to receive an online survey and loyalty points for completing the survey about premium services. What kind of sampling technique do the movie theater managers use
Answer: Simple random sampling
Step-by-step explanation:
Simple random sampling is a sampling method where every member of the population of interest has an equal chance of being picked. It is the simplest sampling method as there are no parameters for picking members.
In using the entire company database and simply selecting members using a lottery style, - which is a random style - the managers of this movie theatre were using a simple random sampling method.
Which display is most likely to reveal association between X and Y ? A. Dot plot B. Scatter plot C. Histogram D. Pareto chart
Scatter plot Answ
Step-by-step explanation:
simplify 6e × 2f please help
There are 6 dogs and 5 cats. In how many different orders can these animals be placed in line if any animal can be next to any other animal?
120=!3÷!6
!2-!5=!3
to 120 modes
HELP!!! I WILL GIVE BRAINLIEST!!!!
1.Find f(4) if f(x) = (1/2)x + 13
2.Find f(5) if f(x) = (3/5)x - 10
3.Find f(-1) if f(x) = x2 + 7
4.Find f(2) if f(x) = 3x3 -12x2
Answer:
15, - 7, 8, - 24
Step-by-step explanation:
1
f(4) = \(\frac{1}{2}\) × 4 + 13 = 2 + 13 = 15
2
f(5) = \(\frac{3}{5}\) × 5 - 10 = 3 - 10 = - 7
3
f(- 1) = (- 1)² + 7 = 1 + 7 = 8
4
f(2) = 3(2)³ - 12(2)² = 3(8) - 12(4) = 24 - 48 = - 24
Find the value of the line integral Integrate C F.dr (Hint: If F is conservative, the integration may be easier on an alternative path.) Integrate C (x^2 + y^2) dx + 2xy dy (a) r1(t) = t^5i+t^2j, 0 < = t < = 2 (b) r2(t) = 5 cos(t)i + 2 sin(t)j, 0 < = t < = pi/2
We need to evaluate the line integral ∫CF.dr for two different paths, r1(t) and r2(t), where F = (x^2 + y^2) dx + 2xy dy.
We will use the fundamental theorem of line integrals to determine if F is conservative.
Since F has continuous first-order partial derivatives, we can check if F is conservative by verifying that ∂F/∂y = ∂M/∂x, where M = x^2 + y^2 and N = 2xy are the components of F. We have:
∂F/∂y = 2xy = ∂M/∂x
Therefore, F is conservative.
By the fundamental theorem of line integrals, the line integral of a conservative field depends only on the endpoints of the path, and not on the path itself.
Therefore, we can choose any path that connects the same two endpoints and calculate the line integral along that path.
(a) Using r1(t) = t^5i + t^2j, 0 ≤ t ≤ 2:
We have:
dr/dt = 5t^4i + 2tj
Substituting into F, we get:
F = (t^10 + t^4) dt + 2t^3 dt
Therefore, the line integral along r1(t) is:
∫CF.dr = ∫0^2 F(r1(t)).(dr/dt) dt
= ∫0^2 [(t^10 + t^4) dt + 2t^3 dt] . (5t^4i + 2tj)
= ∫0^2 (5t^15 + 7t^5) dt
= (5/16) (2^16 - 1) + (7/6) (2^6 - 1)
(b) Using r2(t) = 5cos(t)i + 2sin(t)j, 0 ≤ t ≤ π/2:
We have:
dr/dt = -5sin(t)i + 2cos(t)j
Substituting into F, we get:
F = (25cos^2(t) + 4sin^2(t)) dt - 20sin(t)cos(t) dt
Therefore, the line integral along r2(t) is:
∫CF.dr = ∫0^(π/2) F(r2(t)).(dr/dt) dt
= ∫0^(π/2) [(25cos^2(t) + 4sin^2(t)) dt - 20sin(t)cos(t) dt] . (-5sin(t)i + 2cos(t)j)
= ∫0^(π/2) (20cos^2(t) - 45sin^2(t)) dt
= 20(π/4) - 45(1/4)
Hence, the value of the line integral for both paths r1(t) and r2(t) is:
(5/16) (2^16 - 1) + (7/6) (2^6 - 1) = 1247.875
Note that the line integral is the same for both paths, as expected for a conservative field.
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Val is buying tickets for the amusement park. The total cost of the
tickets varies directly with the number of tickets purchased. She sees
that 12 tickets cost $27. How many tickets can Val buy for $45?
Answer: 20
Step-by-step explanation: Divide 27 by 12. You get 2.25. 2.25 is the cost of one ticket. Then divide 45 by 2.25 and your answer is 20.
Hope that helps!
He buys 20 tickets for $45.
GivenVal is buying tickets for the amusement park.
The total cost of the tickets varies directly with the number of tickets purchased.
She sees that 12 tickets cost $27.
The cost per ticket is given by;
\(\rm = \dfrac{Total \ cost \ of \ tickets }{Total \ number \ of \ tickets}\\\\= \dfrac{27}{12}\\\\= 2.25\)
Therefore,
The number of tickets can Val buy for $45 is;
\(\rm =\dfrac{Total \ number \ of \ tickets}{Cost \ of \ per \ ticket}\\\\= \dfrac{45}{2.25}\\\\= 20\)
Hence, he buys 20 tickets for $45.
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Suppose that scores on a recent statistics exam were normally distributed, that students in the 80th percentile of scores earned 85 points, and that students in the 30th percentile of scores earned 65 points. What was the mean of all exam scores in the class?.
The mean of all exam scores in the class is 72.67 ~ 73 . Mean is ratio of sum of score in all exam to the total numbers of all exams.
The exam scores are normally distributed , normally distributed is an arrangement in which most of values in middle and rest are symmetrically distributed at the ends 80th percentile of scores earned 85 it implies that 80% of students score is 85 or less and 30th percentile of scores earned 65 means 30% of students score is 65 or less .
Z-score value for 80th percentile is 0.841
Z-score value for 30th percentile is – 0.524
Formula for normally distributed,
Z =( X – μ) / σ
where μ is mean of scores , σ is standard deviations of scores ,X is sample mean
For 80th percentile , X= 85 , Z= 0.841
0.841=( 85- μ) /σ ----(1)
-0.524= (65-μ) / σ ----(2)
Solving equations (1) and (2)
- (841/524)= (85-μ )/( 65-μ) => 841μ – 841(65) = -524μ +85(524)
⇒ 1365μ= 99,205 => μ= 72.67
So, the value of mean of scores obtained by students in a class is 72.67 ~ 73
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Which graph represents the inequality \(y\le(x+2)^2\)?
The graph of the inequality y ≤ (x + 2)² is the graph (a)
How to determine the graph of the inequalityFrom the question, we have the following parameters that can be used in our computation:
(y\le(x+2)^2\)
Express properly
So, we have
y ≤ (x + 2)²
The above expression is a quadratic inequality with a less or equal to sign
This means that
The graph opens upward and the bottom part is shaded
Using the above as a guide, we have the following:
The graph of the inequality is the first graph
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(help) Miller’s Farm had apples on sale for $1.78 a pound. Maria spent $15.21 on apples. How many pounds did she buy?
Answer:
8.5 pounds
Step-by-step explanation:
$ 1.78 - 1 pound
$ 15.21 - 15.21/1.78
= 8.5
A bathtub contains 12 gallons of water. With these 12 gallons, the bathtub is only 30% full. How many gallons of water can the bathtub hold when it is completely full?
Answer:
40 gallons
Step-by-step explanation:
Let the number of gallons that would completely fill the bathtub be represented by N.
Since 12 gallons of water gives 30% of the number of gallons to fill the bathtub, then;
30% of N = 12
\(\frac{30}{100}\) x N = 12
30N = 12 x 100
30N = 1200
divide both sides by 30,
N = \(\frac{1200}{30}\)
= 40
The number of gallons that would completely fill the bathtub is 40 gallons.
The least common multiple of 24, 28 and 45 is:
Answer:
2520
Step-by-step explanation:
The least common multiple is the product of all factors in the greatest number of their occurrence.
The least common multiple of 24, 28 and 45 is 2520.
I need help please :(
Don’t answer if you don’t know please.
Answer: b is the answer
Step-by-step explanation:
The line goes up 1 over 3
Answer:
slope is rise over run. so the slope would be 1/3.
Can someone please help me with this question please please help me I really really need help please.
Answer:
1st : neither linear nor nonlinear
2nd: nonlinear
3rd: linear
4th: both linear and nonlinear
can anyone plz help me
The mayor of a local town wants to determine if there is support for a certain proposal. The mayor's assistant randomly selects 100 households and asks whether they would support the mayor's proposal. Sixty responded that they would support it.
What type of sampling is described in this study?
The sampling described in this study is simple random sampling.
This is because the mayor's assistant randomly selected 100 households from the population.
Simple random sampling is a type of probability sampling method in which each member of the population has an equal chance of being selected for the sample.
This method is often used to ensure that the sample is representative of the population, and that the results of the study can be generalized to the entire population.
In this case, since the households were selected randomly, we can assume that the results obtained from the 100 households are representative of the opinions of the entire population of the town.
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Oahu Kiki tracks the number of units purchased and sold throughout each accounting period but applies its inventory costing method at the end of each month, as if it uses a periodic inventory system. Assume Oahu Kiki’s records show the following for the month of January. Sales totaled 240 units.
Date Units Unit Cost Total Cost
Beginning Inventory January 1 120 $ 80 $ 9,600
Purchase January 15 380 $90 $34,200
Purchase January 24 200 $110 $22,000
Calculate the cost of ending inventory and cost of goods sold using the (a) FIFO, (b) LIFO, and (c) weighted average cost methods.
Cost of Ending Inventory Cost of Goods. Sold
FIFO __________________. _______________
LIFO __________________. _______________
Weighted Average Cost __________________. _______________