Answer:
N2O
Explanation:
hope am right.....
thiols are strong-smelling compounds responsible for
Answer:
Many thiols have pungent scents that resemble garlic or rotting eggs. Thiols are utilized as odorants to aid in the detection of natural gas (which is odorless in its pure state), and the "fragrance of natural gas" is owing to the thiol's smell.
Explanation:
A high viscosity liquid will
Answer: high viscosity fluids move sluggishly and resist deformation.
Explanation: some examples of high viscosity liquids is Honey, syrup, motor oil, and other liquids that do not flow freely
The molecule in the blank box that remains and feeds the cycle is called oxaloacetate unsubmitted , and the molecule in the blank box that leaves the cycle is called
The molecule in the blank box that remains and feeds the cycle is called oxaloacetate, and the molecule in the blank box that leaves the cycle is called citrate.
The molecule in the blank box that remains and feeds the cycle is called oxaloacetate. Oxaloacetate is a four-carbon compound that acts as an intermediate in the citric acid cycle, also known as the Krebs cycle or tricarboxylic acid (TCA) cycle. It plays a crucial role in the continuous regeneration of the cycle. After the initial steps of the citric acid cycle, oxaloacetate combines with acetyl-CoA to form citrate, which is the starting point of the cycle. Throughout the subsequent reactions, citrate is metabolized, producing energy-rich molecules such as NADH and FADH2. Oxaloacetate is then regenerated from the intermediates of the cycle, allowing it to continue. Thus, oxaloacetate serves as a key component in maintaining the cycle's function by replenishing the reactants and enabling the continued production of ATP through aerobic respiration.
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The boiling point of ethanol (c2h5oh) is 78.5 degrees c. what is the boiling point of a solution of 6.4 g of vanillin (molar mass= 152.14 g/mol) in 50.0g of ethanol? kb of ethanol= 1.22 degrees c/m.
The boiling point of a solution of 6.4 g of vanillin in 50.0g of ethanol is 77.47 degree C.
How do we calculate boiling point?Change in boiling point of solution will be calculated by using the below formula:
ΔTb = (Kb)(m), where
ΔTb = change in temperature
Kb = elevation constant = 1.22 degrees c/m
m is the molality of the solution and it will be define as the number of moles of solute present in per kilogram of solvent.
Molality of vanillin in ethanol will be calculated after calculating the moles of vanillin.
Moles of vanillin = 6.4g / 152.12g/mol = 0.042 mol
m of vanillin = 0.042mol / 0.05kg = 0.84m
On putting all these values on the above equation we get,
ΔTb = (1.22)(0.84) = 1.0248 degree C
Given that, boiling point of ethanol = 78.5 degree C
So the boiling point of vanillin = 78.5 - 1.0248 = 77.47 degree C
Hence, the boiling point of a solution of vanillin is 77.47 degree C.
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when 2 mol of a nonvolatile nonelectrolyte is dissolved in 5 mol of a solvent, the vapor pressure of the solution compared to that of the pure solvent is
When 2 mol of a nonvolatile nonelectrolyte is dissolved in 5 mol of a solvent, the vapor pressure of the solution compared to that of the pure solvent is lower.
This is because the presence of solute particles reduces the number of solvent particles at the surface, which in turn reduces the tendency of the solvent molecules to escape into the gas phase.
According to Raoult's law, the vapor pressure of the solution is proportional to the mole fraction of the solvent. Since the mole fraction of the solvent decreases when solute is added, the vapor pressure of the solution will be lower than that of the pure solvent.
For example, if the pure solvent has a vapor pressure of 100 torr, adding the solute would lower the vapor pressure of the solution to a value less than 100 torr.
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Do the chemical bonds between atoms change during cellular respiration?
How many grams of hydrogen gas are produced if 3.0 moles of magnesium are reacted with excess hydrochloric acid?
Answer k
Explanation: better luck
g take a deep breath. breathe in deeply and exhale. and again. in the presence of oxygen, which product pyruvate is the end product of glycolysis; and in the absence of oxygen, which metabolite lactate is the primary product responsible for acidic buildup in muscle; and which product oxamate favored as the final electron acceptor to regenerate nad and which product nadh is the electron carrier?
The byproduct of glycolysis in the presence of oxygen is pyruvate. Lactate is the main substance that causes acidic accumulation in muscle when oxygen is not present.
Oxamate is favored as the final electron acceptor to regenerate NAD, and NADH is the electron carrier. Glycolysis is the process through which all bodily cells generate energy. Pyruvate is the end product of glycolysis under aerobic conditions, and lactate under anaerobic conditions. Pyruvate proceeds through fermentation in the cell's cytoplasm if oxygen is not present. Fermentation comes in two flavors: Alcoholic fermentation causes the conversion of pyruvate to ethanol and CO2. This is an irreversible reaction that takes place in the cells of plants and fungi (like yeast cells).
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a language achieves ____ by avoiding special cases in the use of constructs.
Languages may be made simple to learn, create, and maintain by eliminating specific circumstances when using constructions. Software that is quicker to build and deploy and more dependable as a result.
A language becomes simple by not using constructs in exceptional situations. This means that a programming language needs to be created in a simple and understandable manner. Code must be able to be written without taking special circumstances into account for various contexts.
This is accomplished by combining constructs that may be applied in a variety of contexts to produce sophisticated reasoning. Abstraction is the method used in this situation so that the programmer may concentrate on higher-level constructs rather than the language's lower-level specifics.
For a number of reasons, programming language simplicity is crucial. It first facilitates programmers' comprehension of the language and its structures. Writing maintainable, simple-to-read code is also made simpler by it. This is crucial for large projects where a huge number of individuals may be contributing to the codebase.
Thenumbert of flaws and errors brought into the codebase can be decreased by utilising an easy-to-understand language. As a result, the system becomes more steady and dependable. This is so that programmers may pay more attention to the logic of the code and less to the difficulties of the language.
Languages may be made simple to learn, create, and maintain by eliminating specific circumstances when using constructions. Software that is quicker to build and deploy and more dependable as a result.
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if ∆h = 498 kj and ∆s = 319 j/k, the spontaneity of the reaction depends on temperature. above what temperature will the reaction be spontaneous?
The temperature at which a reaction becomes spontaneous depends on the change in enthalpy and entropy, which can be calculated using the equation ΔG = ΔH - TΔS. In this case, a temperature above 1564 Kelvin is required for the reaction to be spontaneous.
The spontaneity of a reaction is determined by the change in free energy, which is calculated using the equation ΔG = ΔH - TΔS, where ΔG is the change in free energy, ΔH is the change in enthalpy, T is the temperature in Kelvin, and ΔS is the change in entropy.
If ΔG is negative, the reaction is spontaneous. Therefore, we need to find the temperature at which ΔG becomes negative.
Given ΔH = 498 kJ and ΔS = 319 J/K, we can plug these values into the equation and solve for T:
ΔG = ΔH - TΔS
-ΔG = TΔS - ΔH
T = (ΔH/ΔS)
T = (498 kJ / 319 J/K)
T = 1564 K
Therefore, the reaction will be spontaneous above a temperature of 1564 Kelvin.
In summary, the temperature at which a reaction becomes spontaneous depends on the change in enthalpy and entropy, which can be calculated using the equation ΔG = ΔH - TΔS. In this case, a temperature above 1564 Kelvin is required for the reaction to be spontaneous.
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Calculate the molar solubility of agcl in a solution made by dissolving 10.0 g of cacl2 in enough water to make up a 1.00 l solution.
Mass of CaCl2 = 10 g.
Volume of solution = 1 L.
To determine the solubility, the concentration of CaCl2 solution has to be determined.
The formula for calculating the Molarity (conc. in mol/L) is:
Molarity = Number of Moles of the solute/Volume of solvent in L
The number of moles of solute is determined using the formula:
Number of moles = Mass in g/Molar mass in g/mol = 10g/110.98 g/mol = 0.09 mole.
Now, Molarity = 0.09/1 = 0.09 M
So, the concentration of CaCl2 is 0.09M
CaCl2 dissociates into Ca2+ and 2Cl− ions as shown below.
CaCl2→Ca2+ + 2Cl−
The concentration of Cl− ions in the solution = 2×0.09M =0.18M.
Substitute these values in the expression for the solubility product
Ksp = [Ag+][Cl−] = s×(s+0.18)
Since the value of Ksp is very low, the value of s will be negligible compared to 0.052, and hence,
(s+0.18) ≈0.18
Ksp = s×0.18
1.8×10^−10 =0.052 s
s = 1.8×10^−10/0.18
s = 10 x 10^-10 or 1 x 10^-9M
Therefore, the solubility of AgCl in the given CaCl2 solution is 1x10^-9 M
What is Molar solubility?The amount of moles of a solute that can dissolve in a solvent before it becomes saturated is known as molar solubility. The amount of solute that dissolves in a liter of solution is most frequently expressed as the number of moles. As a result, it is typically expressed as "M" and measured in moles/liter.
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please help me fast!! Which element is chemically active in between Sodium and Neon?
Answer:
Element is chemically active in between Sodium and Neon is explained below in details.
Explanation:
Electrons revolve the electron in "cases" (power levels), and only a specific quantity of electrons can survive in each case. ... For example, Sodium has one valence electron, Neon has eight valence electrons, and Chlorine has seven valence electrons. The quantity of valence electrons an atom has concluded its reactivity.
how many elements are there in the first column of the periodic table?
Answer:
2 are number of coloum o
When it burns, 24.3 grams of magnesium can react completely with 16.0 grams of oxygen gas to form a new compound, magnesium oxide. No other compounds are formed. What mass of magnesium oxide is formed in this reaction
The 20.16 grams of magnesium oxide is formed in this reaction.
To determine the mass of magnesium oxide formed in the reaction, we need to calculate the limiting reactant and then use the stoichiometry of the balanced chemical equation to find the corresponding mass of the product.
The balanced chemical equation for the reaction is:
2 Mg + O2 -> 2 MgO
Given:
Mass of magnesium (Mg) = 24.3 grams
Mass of oxygen gas (O2) = 16.0 grams
1: Calculate the moles of each reactant.
Moles of magnesium (Mg) = mass / molar mass = 24.3 g / 24.31 g/mol = 1.00 mol
Moles of oxygen gas (O2) = mass / molar mass = 16.0 g / 32.00 g/mol = 0.500 mol
2: Determine the limiting reactant.
The ratio of Mg to O2 in the balanced equation is 2:1. Since there are fewer moles of oxygen gas (0.500 mol) compared to magnesium (1.00 mol), oxygen gas is the limiting reactant.
3: Calculate the moles of magnesium oxide formed.
From the balanced equation, 2 moles of Mg react to form 2 moles of MgO.
Therefore, the moles of MgO formed is also 0.500 mol.
4: Calculate the mass of magnesium oxide formed.
Mass of magnesium oxide (MgO) = moles × molar mass
Mass of magnesium oxide (MgO) = 0.500 mol × 40.31 g/mol = 20.16 grams
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with balanced chemical equations, show the different stages of fermentation
Answer:
formula for fermentation is: C6H12O6 → 2 C2H5OH + 2 CO.
What are the coefficients needed to balance this chemical reaction to show that matter is conserved?
Answers for this assignment
The following chemical compounds are;
V₂O₅ Vanadium (V) oxide,
SF₆ Sulfur hexafluoride
HClO₂ Chlorous acid
(NH₄)₂SO₄·6H₂O Ammonium sulfate hexahydrate
What should you know about the chemical compound called Chlorous acid?Chlorous acid is a weak and unstable acid. This acid exists mainly in aqueous solutions. They are used in disinfectants, and bleaching products. They are good sanitizers and helps to reduce bacteria.
Apart from being in products we commonly use in our house, Chlorous acid is also used in the paper and textile industries for bleaching purposes.
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Convert 25 gigaseconds into centiseconds
25 gigaseconds is equal to 2,500,000,000,000 centiseconds
rumors arose that baseball bats containing this element has remarkably striking power
The element in question is cork. Cork is a type of bark harvested from the cork oak tree and is often used in the manufacturing of wine bottle stoppers, flooring, and insulation.
However, cork has also been used in baseball bats as a way to reduce the bat's weight, and subsequently increase the batter's swing speed.There has been much debate over the use of cork in baseball bats, with some players and coaches claiming that it provides a significant increase in hitting power.
However, the use of cork is strictly prohibited in Major League Baseball (MLB) and players caught using corked bats can face suspensions and fines.To test the validity of the claim that corked bats produce more powerful hits, a study was conducted in which corked and non-corked bats were compared in terms of ball exit velocity.
The results showed that corked bats did not produce significantly higher ball exit velocities than non-corked bats. In fact, in some cases, the non-corked bats produced higher exit velocities than the corked ones.Rumors that corked bats provide a significant advantage to batters are largely unfounded.
While cork may reduce a bat's weight, which could lead to increased swing speed, it does not necessarily result in more powerful hits. The use of cork in baseball bats is not only prohibited in MLB, but also deemed unnecessary by most experts in the field.
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What is the molality of a solution of naphthalene dissolved in chloroform if the solution has a freezing point of -64.7 °C?
Answer: we know that 10 g of naphthalene is added to a test tube. We determined and the cooling curve above that the freezing point of naphthalene is approximately 80.5 degreesC . We then add 1.1 g of p-dichlorobenzene to the test tube.
Explanation:
From the following compounds, identify the ones that are nonpolar covalent.
H2O
NCl3
AuCl3
ClO2
SF4
SO3
Answer:
The nonpolar covalent compounds are:
H2O (polar covalent)
NCl3 (polar covalent)
AuCl3 (ionic)
ClO2 (polar covalent)
SF4 (polar covalent)
SO3 (nonpolar covalent)
84.9 g of solid iron reacts with oxygen gas forming iron(III) oxide. How many moles of oxygen will react
Answer:
1.14 moles of oxygen will react
Explanation:
The balanced equation of reaction between iron and oxygen is
4 Fe + 3 O₂ → 2 Fe₂O₃
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
Fe: 4 molesO₂: 3 molesFe₂O₃: 2 molesThe molar mass of iron being Fe 55.85 g/mole, then the following amount of mass reacts by stoichiometry: 4 moles* 55.85 g/mole=223.4 g
You can apply the following rule of three: if by stoichiometry 223.4 grams of Fe react with 3 moles of O₂, 84.9 grams of Fe react with how many moles of O₂?
\(moles of O_{2} =\frac{84.9 grams of Fe*3 moles ofO_{2} }{223.4 grams of Fe}\)
moles of O₂= 1.14 moles
1.14 moles of oxygen will react
Energy in Chemical Reactions II: Reflect
Write a reflection about your learning in this unit. Your reflection should be at least three sentences. Use the following sentence starters as a guide.
- I feel confident about modeling how the energy in a reaction will change, because…
- To try to make sure to consider all of the bonds involved in a change from reactants to products, one strategy I used was…
- If I am not sure about the bond, energies and potential energies in a reaction, one strategy, I can use is…
- If I am not sure about how the energy moves between the system and the surroundings in a reaction on strategy, I can use it…
PLEASE HELP ME I NEED THIS ASAPP!!!!
I feel confident about modeling how the energy in a reaction will change, because this unit provided me with the information necessary to determine the type. With this knowledge, I can now interrelate with other properties and believe that this new ability will assist in future units as well. This unit has encouraged a deeper understanding of the world and its guiding principles.
(HOPE THIS HELPS <3)
Write a simple procedure for measuring out 2.6 grams of sodium bicarbonate NaHCO3 or commonly known as baking soda?
PLEASE I REALLY NEED THIS!!! :/
Answer:
See explanation
Explanation:
If I intend to measure 2.6 g of sodium bicarbonate, I need a spatula, a filter paper, and a weighing balance.
The filter paper is placed on the balance and the balance is adjusted to read zero. The spatula is now used to collect the sodium bicarbonate solid from its container and gradually drop it on the filter paper while watching the mass read out by the balance. This continues until the balance reads 2.6g.
3. Briefly discuss the results of the TLC. Was there evidence of unreacted p-nitrobenzaldehyde in either product
TLC means Thin Layer Chromatography. It is a method that can best be described as "Affinity-Based" used in the separation of compounds that are in a mixture.
What is unreacted p-nitrobenzaldehyde?Unreacted p-nitrobenzaldehyde is simply an organic aromatic compound that contains a nitro group para-substituted to an aldehyde. in this case, if it is unreacted, that means it is the same as before the chemical reation.
Note that the question is missing key information hence the general answer.
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John is hiking and notices a small stream of water flowing down the side of the mountain. What part of the water cycle is John observing?
What happens to carbon in plants when the plants die.
Answer:
Released into the atmosphere
Explanation:
The carbon that the plant had been storing when it was alive, would be released upon death into the soil
Part A)
The formation constant (Kf) of a complex depends on several factors, and it can also communicate information about the complex. Which of the following statements about the formation constant are true?
Select All that Apply
The complex [Ni(en)3]2+ is more stable than the complexes [Ni(NH3)6]2+ and [Ni(H2O)6]2+.
The value of the formation constant always increases as the number of ligands increases.
Steric hindrance of ligands will generally reduce the value of the formation constant.
The coordination number of the central metal ion is related to the formation constant of the complex.
Complexes formed with V2+ are more stable than complexes formed with V5+.
Therefore the first statement is true, second is false, third is true, fourth is true and fifth is false.
The first statement is true. [Ni(en)3]2+ is more stable than [Ni(NH3)6]2+ and [Ni(H2O)6]2+. This is because ethylenediamine (en) is a bidentate ligand and can form a chelate ring with the Ni2+ ion, which increases the stability of the complex. In contrast, NH3 and H2O are monodentate ligands and cannot form such chelate rings.
The second statement is false. The value of the formation constant does not always increase as the number of ligands increases. It depends on the nature of the ligands and the metal ion. For example, [Cu(NH3)4]2+ has a higher formation constant than [Cu(H2O)4]2+, despite having the same number of ligands.
The third statement is true. Steric hindrance of ligands can reduce the value of the formation constant. This is because bulky ligands can make it difficult for other ligands to approach the metal ion, which decreases the stability of the complex.
The fourth statement is true. The coordination number of the central metal ion is related to the formation constant of the complex. This is because the coordination number determines the number of ligands that can bind to the metal ion, which affects the stability of the complex.
The fifth statement is false. Complexes formed with V2+ are generally less stable than complexes formed with V5+. This is because V2+ is a smaller ion with a higher charge density, making it more difficult for ligands to approach the metal ion and form stable complexes. In contrast, V5+ is a larger ion with a lower charge density, making it more accessible to ligands.
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The number of molecules in 0.25 mole of BeCl2 is:
O 4.81 x 1025 molecules
O 1.33 x 1025 molecules
481 x 1025 J
O 133 x 1025 molecules
Answer:
1387j
Explanation:
i calculated
The number of molecules in 0.25 mole of \(BeCl_2\) is 1.33 x \(10^{25 }\) . Therefore, the correct option is option B.
Everything around us is made up of molecules, which are the basic units of matter. They are essentially composed of two or more atoms connected by chemical bonds. Depending on the molecule, these atoms may be of the same element or distinct elements. In several scientific disciplines, including chemistry, biology, and physics, the study of molecules is essential. Scientists can learn more about the structure and behaviour of molecules and, in turn, learn more about how different substances interact, react, and operate.
0.25 moles x (6.022 x\(10^{23}\) molecules/mol) = 1.33 x \(10^{25 }\) molecules
Therefore, the correct option is option B.
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A chemist burns 650.0 g of C4H8S2 in excess oxygen, according the following balanced chemical reaction:
C4H8S2+ 902 -> 4CO2 + 4H2O +2S03
If the chemist has 92.2% yield, how many grams of SO3 were produced?
Answer:
952.2g SO3
Explanation:
Molar mass of C4H8S2 is 120.2363 g/mol
Mol in 750.0g = 750.0/120.2363 = 6.238 mol
1mol C4H8S2 produces 2 mol SO3
6.238 mol will produce 2×6.238 = 12.476 mol SO3
Molar mass SO3 = 32+3×16 = 80.0g/mol
Theoretical yield = 12.476×80.0 = 998.08g
The actual yield is 95.4%
Actual mass-produced = 95.4/100×998.08 = 952.2g SO3 produced
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