An object's mass times its velocity gives the object's __________.
speed
acceleration
power
momentum


the answer is momentum

Answer:

If a cow has a greater mass than the tiger, it has greater momentum, but only if they are moving at the same speed, or the tiger is going slower (i think)

Explanation:

the quantity of motion of a moving body, measured as a product of its mass and velocity.

When a person increases their activity level to gain muscle mass, their nutritional needs change.

The key changes include increasing protein intake to support muscle growth and repair, consuming a slight caloric surplus to provide energy for muscle development, ensuring sufficient carbohydrate intake for fuel, including healthy fats for overall health, staying hydrated, and considering essential micronutrients.

Individual variations exist, so seeking personalized guidance from a professional is recommended.

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Answer:

F = 1.07 x 10⁻⁷ N

Explanation:

The gravitational force of attraction between two objects can be found by the use of Newton's Gravitational Law:

\(F = \frac{Gm_{1}m_{2}}{r^2}\\\\\)

where,

F = Gravitational Force of attraction = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = m₂ = mass of spheres = 20 kg

r = distance between the objects = 50 cm = 0.5 m

Therefore,

\(F = \frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(20\ kg)(20\ kg)}{(0.5\ m)^2}\\\\\)

F = 1.07 x 10⁻⁷ N

Answer:

D

Explanation:

because of the the side of the bottom

The amount of work required to move the rock of mass 95 kg up a ramp of 100 m is 93100 J.

Work can be fined as the product of force and distance.

To calculate the amount of work required to get the rock up, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the amount of work required is 93100 J.

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(a) The time for a particle of water leaving the orifice to reach point B is 0.63 s.

(b) The horizontal distance x where it hits from surface is 3.94 m.

The time of the water to reach the surface is calculated as follows;

h = ¹/₂gt²

2h = gt²

t² = 2h/g

t = √(2h/g)

where;

t = √( (2 x 2)/(9.8) )

t = 0.63 s

The horizontal distance is calculated as follows;

X = vt

where;

X = (√2gh)t

X = (√2 x 9.8 x 2) x 0.63

X = 3.94 m

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Answer:

PE = 137.2931 J

Explanation:

PE = 137.2931 J

The frequency of the second harmonic is 880 Hz (a pitch of A5). The speed of sound through the pipe is 350 m/sec. Find the frequency of the first harmonic and the length of the pipe. The length of an air column is related mathematically to the wavelength of the wave which resonates within it.

Answer:

Net force = 11340 N

Explanation:

Given that,

Mass of an automobile, m = 2100 kg

Acceleration of the automobile, a = 5.4 m/s²

We need to find the net force required for the automobile. The net force is the product of mass and acceleration. It can be given by the formula as follows :

\(F=ma\\\\F=2100\ kg\times 5.4\ m/s^2\\\\F=11340\ N\)

So, the net force is 11340 N.

We are given that the Titanic hit an iceberg half of its mass. To determine the velocity of the iceberg after the collision we have to do a balance of momentum:

Where:

Now, since the iceberg is initially at rest, we have:

Substituting in the balance of momentum we get:

We are given that the mass of the iceberg is half of the mass of the Titanic, therefore, we have:

Substituting in the balance of momentum:

Now, we can cancel out the mass of the Titanic:

Now we solve for the final velocity of the iceberg. We subtract the final velocity of the Titanic from both sides:

Now we multiply both sides by 2:

Substituting the values we get:

Solving the operations we get:

Therefore, the final velocity of the iceberg is 16.4 meters per second.

The final speed and angle of the first puck are 1.17 m/s and 54.5° respectively.

In an elastic collision, both momentum and energy are conserved. But only momentum is conserved in inelastic collision.

Given that two hockey pucks are moving towards each other. The first one is 0.13 kg and moving at a speed of 1.11 m/s, while the second puck is 0.16 kg and moving at 1.21 m/s, and they collide. (Assume elastic collision.) After collision, the second puck ends up with a speed of 1.16m/s at an angle of 42 degrees below its original path, while the first puck ends up with an unknown speed at an angle above its original path.

The given parameters are;

The mathematical representation of the above question will be in two components.

Horizontal component

M1U1 - M2U2 = M1V1cosФ - M2V2cosФ

Substitute all the parameters

0.13 x 1.11 - 0.16 x 1.21 = 0.13 x V1 cosФ - 0.16 x 1.16cos42

0.1443 - 0.1936 = 0.13V1cosФ - 0.1379

0.13V1cosФ = 0.0886

V1cosФ = 0.0886/0.13

V1cosФ = 0.6815 ........ (1)

Vertical component

0 = M1V1sinФ - M2V2sinФ

M1V1sinФ = M2V2sinФ

Substitute all the parameters

0.13 x V1 sinФ = 0.16 x 1.16sin42

V1 sinФ = 0.1242/0.13

V1 sinФ = 0.9553 ......... (2)

Divide equation 2 by 1

V1 sinФ / V1 cosФ = 0.9553/  0.6815

Tan Ф = 1.40

Ф = \(Tan^{-1}\)(1.4)

Ф = 54.5°

Substitute Ф into equation 2

V1 sin54.5 = 0.9553

V1 = 0.9553 / 0.8141

V1 = 1.17 m/s

Therefore, the final speed and angle of the first puck are 1.17 m/s and 54.5° respectively.

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(a) The circuit diagram is in the image attached.

(b) The current flowing through the resistor is 0.003 A.

(c) The power dissipated by the resistor is  0.135 W.

(b) The current flowing through the resistor is calculated by applying Ohm's law as follows;

V = IR

I = V/R

where;

I = 45 V / 15,000Ω

I = 0.003 A

(c) The power dissipated by the resistor is calculated as follows;

P = IV

where;

P = 0.003 x 45 V

P = 0.135 W

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We have that for the Question, it can be said that

From the question we are told

From,

\(tan\theta = \frac{h}{2}\)

differentiate with respect to h

\(sec^2\theta * \frac{do}{dz} = \frac{1}{2} * \frac{dh}{dz}\\\\\frac{dh}{dz} = 2 sec^\theta * \frac{d\theta}{dz}\\\\\theta = \frac{\pi}{6} and \frac{d\theta}{dz} = 0.1rad/min\\\\\frac{dh}{dz} = 2sec^2 (\frac{\pi}{6}) * (0.1)\\\\= 0.266miles/min\)

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The shape of a line graph displaying temperature change over time before boiling is typically linear and increasing.

In a line graph showing the temperature change over time of a liquid before it starts to boil, the shape is generally linear and increasing.

This is because as heat is applied to the liquid, its temperature increases at a consistent rate.

During this phase, the heat energy is used to increase the kinetic energy of the molecules in the liquid, causing a rise in temperature.

Once the boiling point is reached, the graph may show a plateau, as the energy is then used to change the liquid's state rather than further increase the temperature.

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Answer:

The magnitude of the electric field strength is 6.4 x 10⁵ N/C, directed from positive particle to negative particle.

Explanation:

Given;

charge of each particle, Q = 2 x 10⁻⁷ C

distance between the two charges, r = 15 cm = 0.15 m

distance midway between the charges = 0.075 m

The magnitude of the electric field is calculated as;

\(E_{net} = E_{+q} + E_{-q}\\\\E_{net} = \frac{kQ}{r_{1/2}^2} + \frac{kQ}{r_{1/2}^2}\\\\E_{net} = 2(\frac{kQ}{r_{1/2}^2})\\\\E_{net} = 2 (\frac{9\times 10^9 \ \times 2\times 10^{-7}}{0.075^2} )\\\\E_{net} = 6.4\times 10^5 \ N/C\)

The direction of the electric field is from positive particle to negative particle.

The overall force of gravity that draws the cloud inward increases because the cloud's density increases.

Gravity is a natural phenomenon by which all things with mass are brought toward one another. It is most commonly experienced as the weight of objects pulling them toward the Earth’s center. Gravity is the weakest of the four fundamental forces of nature, yet it is the most dominant force in determining the structure of the universe. It is the reason why planets, moons, and galaxies remain in their orbits. Gravity is also responsible for the formation of stars and planets, as well as the attraction between objects such as planets and moons. The gravity between two objects depends upon their mass and distance between them. Gravity is an important factor in the motion of all objects in the universe and is directly responsible for the tides, the motion of the planets and their motion around the sun.

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Answer: By dividing airflow by duct cross section.

Explanation:

In short, air velocity in the ducts is calculated by dividing airflow by duct cross-section. Airflow is expressed as a simple number. Example: Air conditioner has a max. airflow of 600 CFM.

The statement that is NOT true is "the spaces between the particles increased.

option D.

If we consider the solids and liquids, when the temperature increases the molecules gain energy and start moving in all directions. This expands the substance and the volume of the substance increases.

Similar, when the ball is heated, the volume of the ball increases due to thermal expansion.

As the temperature increases, the average kinetic energy of the particles within the ball also increases, causing them to move faster.

However, the spaces between the particles do not necessarily increase. In fact, the expansion of the ball occurs due to the particles themselves moving farther apart, but the intermolecular spacing within the ball remains relatively constant.

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The temperature remains constant while the substance is changing state.The correct answer is option C.

When a substance undergoes a change of state, such as melting, boiling, or condensing, the temperature of the substance remains constant during the phase transition. The process of changing state requires the absorption or release of heat energy without a change in temperature.

For example, when a solid is heated, its temperature increases until it reaches the melting point. At this point, the substance starts to change from a solid to a liquid, but the temperature remains constant until all the solid has melted.
The absorbed heat energy is used to break the intermolecular forces holding the particles together, rather than increasing the kinetic energy of the particles.

Similarly, during the process of condensation or freezing, a substance releases heat energy as it changes state. This released energy is used to form intermolecular forces and convert the substance from a gas to a liquid or a liquid to a solid. The temperature remains constant until the phase transition is complete.
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The total momentum, both before and after, is (2m)(v/2) = mv, which is equal to the total mass times the velocity of the Centre of mass.

The system's centre of mass was at v/2 before to the collision because one automobile was travelling at v and the other at zero before the collision. Because the total momentum is equal to the total mass times the velocity of the Centre of mass, the total momentum before and after equals (2m)(v/2) = mv.

K.E1 = 1/2 m1u21 + 1/2 m2u22 is the kinetic energy of the masses prior to contact. The collision's kinetic energy, however, is given by K.E2 = 1/2 (m1 + m2) v2. However, in accordance with the rule of energy conservation: 1/2 m1u21 + 1/2 m2u22 = 1/2 (m1+ m2) v2 + Q.

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The value of  the missing resistance, R₃ = 10.35 ohms.

The value of the missing voltages, V₁ = 6 V, V ₃ = 24 V.

The value of the missing currents, I₁ = 3 A, I₃ = 2.32 A.

The values of the missing component of the circuit is calculated by applying the following formula.

The total resistance of the circuit;

For R₂, R₃, 1/R = 1/R₂ + 1/R₃

1/R = 1/12 +  1/R₃

1/R = (R₃ + 1)/(12R₃)

R = 12R₃ / (R₃ + 1)

For, R₁, R₂ and R₃, total resistance;

R = 12R₃ / (R₃ + 1) + R₁

R = [12R₃ / (R₃ + 1)] + 2

R = (12R₃ + 2(R₃ + 1) ) / (R₃ + 1)

R = (12R₃ + 2R₃ + 2 ) / (R₃ + 1)

R = (14R₃ + 2 ) / (R₃ + 1)

The total current in circuit is calculated as;

I = V/R

I = 30 / R

I = ( 30 ) / (14R₃ + 2 ) / (R₃ + 1)

I = (30R₃ + 30) / (14R₃ + 2) ------- (1)

The voltage in parallel circuit is the same

V₂ = V₃ = 24 V

V₃ = IR₃

24 = IR₃

I = 24/R₃  --------- (2)

Solve (1) and (2) together as follows;

24/R₃ = (30R₃ + 30) / (14R₃ + 2)

30R₃² - 306R - 48 = 0

Solve the quadratic equation, using formula method.

R₃ = 10.35 ohms

I₃ = V₃/R₃

I₃ = 24 V / 10.35

I₃ = 2.32 A

If the voltage drop at R₂ and R₃ = 24 V, the voltage drop at R₁ = 30V - 24 V = 6 V

The current in R₁ = V₁/R₁ = 6 V / 2 V = 3 A

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Answer:

the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.

Explanation:

Answer:

21.31 meters

Explanation:

Since we're working with gravitational potential energy (GPE):

GPE (Joules) = mass (kg) * gravity (m/s^2) * height (meters)

1. Figure out what we have:

GPE = mass * gravity * height

We're looking for height, and we have the other three, so we're set to move on.

2. Isolate the unknown variable (height):

(GPE) / (mass * gravity) = height

3. Plug in your numbers:

(3.78 * 10^7 J) / ((1.81 * 10^5 kg) * (9.8 m/s^2)) = 21.31 meters

The information we will need to demonstrate that an object is in motion include;

An object is in motion when it changes its position with time, relative to a stationary object.

Mathematically, we can use the following equation to demonstrate the motion of an object.

v = Δx / Δt

where;

So the data we will need to demonstrate that an object is in motion include;

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The  average speed vavg is 3.1818 cm/s

To calculate the value, we need to find the total sum of the products of the number of particles (Ni) and their respective speed (vi). Once the sum is obtained, we divide it by the total number of particles (22). The sum of the products of Ni and vi is (1.0*2 + 2.0*4 + 3.0*6 + 4.0*8 + 5.0*2) = 58.0. After dividing the sum by the total number of particles (22), we get vavg = 58.0 / 22 = 3.1818 cm/s. This is the average speed of the 22 particles.

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The minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.

Deceleration is defined as  the decrease in speed as the body moves away from the starting point.

The minimum deceleration required can be calculated using the equation of motion:

d = v^2 / (2 * a)

where d is the distance, v is the initial velocity, and a is the acceleration.

Rearranging the equation to solve for a:

a = v^2 / (2 * d) = (3500 m/s)^2 / (2 * 35 m) = 40000 m/s^2

In conclusion, , the minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.

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The mass of the wheel is 0.38 kg. It is related to weight, which is the force exerted on an object due to gravity and is proportional to the object's mass.

What is Mass?

Mass is a measure of the amount of matter in an object. It is a scalar quantity and is usually measured in kilograms (kg) in the SI system of units. Mass is a fundamental property of an object and does not change with its location or motion.

Let's start by finding the tension in the wire using the motion of the object. We can use the kinematic equation:

y = (1/2)at^2

where y is the distance the object moves, a is the acceleration, and t is the time. Substituting the given values:

2.95 m = (1/2)a(1.85 s)^2

Solving for the acceleration:

a = 2.47 m/s^2

Now, we can find the tension in the wire using the rotational dynamics of the wheel. The torque due to the tension is equal to the moment of inertia times the angular acceleration:

τ = Iα

where τ is the torque, I is the moment of inertia, and α is the angular acceleration. Since the wheel is rotating without friction, the torque due to the tension is the only torque acting on the wheel, so:

Tension * radius = (1/2)mr^2 * α

where m is the mass of the wheel and r is its radius. We can rearrange this equation to solve for the tension:

Tension = (1/2)ma

Substituting the values we found:

Tension = (1/2)(4.3 kg)(2.47 m/s^2) = 5.31 N

Now we can use the torque equation again to solve for the moment of inertia of the wheel:

Tension * radius = (1/2)mr^2 * α

Substituting the values we found and solving for the moment of inertia:

I = 2(Tension * radius) / α = 0.033 kg·m²

Finally, we can use the moment of inertia to find the mass of the wheel using the formula:

I = (1/2)mr^2

Substituting the values we found:

0.033 kg·m² = (1/2)m(0.288 m)^2

Solving for the mass:

m = 2I / r^2 = 0.38 kg

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The magnitude of |A-B| is given by √{A²+B²-2ABcosθ}.

In physics, a vector is a quantity with both magnitude and direction. It is often represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity.

A vector does not have position, while having magnitude and direction. In other words, a vector's shape is unaltered if it is shifted parallel to itself as long as its length is unaltered.

Let consider two vector \(\vec{A}\) and \(\vec{B}\) and angle between them is θ, then the magnitude of |A-B| is given by = √{A²+B²-2ABcosθ}

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