an object with a mass of 2.4 kg has a force of 12.6 N applied to it. What is the resulting acceleration of the object? WITH PROOF/WORK :)

Answers

Answer 1
Newton’s Law: F = MA
A = F/M (change equation)
12.6 N/ 2.4 kg = 5.25
Answer: acceleration is 5.25 m/s^2

Related Questions

a basketball rolling across a flat floor has___ energy. PLZ HELP

Answers

Kinetic energy is the answer

Answer:

kinetic energy

Explanation:

I know the answer because Im built differen

An object in space is observed to have an altitude of 1200 nary (2209 km), a velocity of 7000 m/s, and an elevation angle (Phi) of +40 degree. Give a complete description of the trajectory. Is there anything special or different about this trajectory? Find V, v, and Phi when r = 6.378 x 10^6 m. Sketch the trajectory and locate this point.

Answers

The trajectory of the object in space has an altitude of 1200 nary (2209 km), a velocity of 7000 m/s, and an elevation angle (Φ) of +40 degrees. This trajectory describes a high-speed ascent into space, likely representing the launch of a spacecraft or a ballistic missile.

1. The given altitude of 1200 nary (2209 km) indicates the height above the Earth's surface at which the object is observed. This suggests that the object has already achieved a significant distance from the Earth's surface.

2. The velocity of 7000 m/s indicates the speed at which the object is moving. This high velocity implies that the object is traveling at a considerable speed, likely surpassing the escape velocity of the Earth.

3. The elevation angle (Φ) of +40 degrees describes the angle at which the object's trajectory deviates from the horizontal plane. A positive elevation angle indicates an upward trajectory from the observer's reference point.

4. Based on the given parameters, it can be inferred that the object is following a high-speed ascent trajectory, possibly representing a launch into space. The combination of the high altitude, high velocity, and positive elevation angle suggests that the object is moving away from the Earth's surface and is on a trajectory to reach a higher orbit or escape the Earth's gravitational pull.

5. To find V, v, and Φ when r = 6.378 x 10^6 m, we need additional information or equations related to the specific trajectory or orbital parameters. Without this information, it is not possible to determine these values accurately.

6. A sketch of the trajectory would show an upward path with an increasing altitude, indicating the object's ascent into space. The point where r = 6.378 x 10^6 m would correspond to the Earth's surface, specifically the point of reference for the altitude measurement.

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Cell phones use electromagnetic radiation with energy of about 1.08J/mol photons. Calculate the wavelength and frequency that can be used to describe light with this energy.

Answers

We know that the energy of electromagnetic radiation is given by:

\(E=hf\)

where E is the energy, h is Planck's constant and f is the frequency. Before we can use this formula we need to convert the amount of energy given to J so let's do that:

\(1.08\text{ }\frac{J}{mol}\cdot\frac{1\text{ mol}}{6.022\times10^{23}}=1.793\times10^{-24}J\)

Now that we have the energy of the radiation, we plug it on the energy equation and solve for the frequency:

\(\begin{gathered} 1.793\times10^{-24}=6.63^\times10^{-34}f \\ f=\frac{1.793\times10^{-24}}{6.63\times10^{-34}} \\ f=2.704\times10^9 \end{gathered}\)

Therefore, the frequency of the cell phone electromagnetic radiation is:

\(2.704\times10^9\text{ Hz}\)

Now that we know the frequency we just need to remember that the frequency and wavelength of electromagnetic radiation are related by:

\(\lambda=\frac{c}{f}\)

Then we have:

\(\begin{gathered} \lambda=\frac{3\times10^8}{2.704\times10^9} \\ \lambda=0.111 \end{gathered}\)

Therefore, the wavelength is 0.111 m

Determine the force p required to (a) raise and (b) lower the 40-kg cylinder at a slow, steady speed. the coefficient of friction between the cord and its supporting surface is 0.30.

Answers

Answer:

T - M g - Ff = M a     describes the acceleration of the object

T = M g + Ff      if the object moves at constant speed  (a = zero)

Ff = μ M g = .3 * 40 * 9.8 = 118 N     the force of friction

Ff will be in a direction opposite to the motion

M g = 40 kg * 9.8 m/s = 392 N

a) T = M g + Ff   for an object moving upwards

T = 392 + 118 = 510 N

b) T = M g - Ff     for an object moving downwards

T = 392 - 118 = 274 N

m + m + 3m and 3m + 2 equvilent expressions

Answers

M + 4m and 2 + 3m expressions are equivalent to M + m + 3m while M + 2m and 3 + 3m are equivalent to 3m + 2.

What are equivalent mathematical expressions?

Equivalent expressions are expressions that perform the same function despite their appearance. If two algebraic expressions are equivalent, they have the same value when the variable is set to the same value.

M + m + 3m and 3m + 2 are equivalent expressions. They can be simplified to 4m + m and 3m + 2, and further simplified to 5m and 3m + 2. They represent the same quantity, just written in a different way.

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How far will Julie travel if she moves at a speed of 7 meters per second for 20 minutes?

Answers

She would’ve traveled 5.21952 miles

Error and uncertainty are interchangeable words that describe the same concept.

Answers

Error is the difference between actual value and the calculated value.

Uncertanity of a measured value in an interval around that value such that any repetition of measurement will produce a new result that lies within the interval.

Hence, error and uncertanity are interchangeable words that describes the same concept.

The magnitude of vector vector A is 84.9 m and it points in the +y axis direction. The magnitude of vector vector B is 195.0 m and it points at an angle of 41.0° counterclockwise from +x axis. The magnitude of vector vector C is 126.2 m and it points in the +x axis direction.

Answers

Solution:

The magnitude of A vector is 84.9 m in the positive y-axis direction.

So the X component of A =0

     the Y component of A = 84.9 m

Now the magnitude of B vector is 195 m and it makes an angle of 41° in the direction from the positive x-axis direction.

So  the X component of B = B cos 41°

                                           = 195 x cos 41°

                                           = 195 x 0.75   = 146.25 m

   the Y component of B = B sin 41°

                                           = 195 x sin 41°

                                           = 195 x 0.65   = 126.75 m

Now it is given that vector C has a magnitude of 126.2 m and it makes a direction towards the positive x-axis.

So the X component of C =126.2 m

     the Y component of C = 0

Comparing all these, we get

1. B vector has the largest X component

2. B vector has the largest Y component

consider an rlc series circuit (r = 100.0 ω, l = 0.70 h, and c = 10.0 µf) connected to a generator emf v(t) = vmax cos (ωt), where vmax = 170 v and ω = 339 rad/s.

Answers

The voltage across the inductor and capacitor are equal and opposite, the voltage across the resistor, \(V_{r}\), must be equal to the voltage of the generator, \(V(t)\). Thus, \(V(t) = V_{r} = 170 V\).

An RLC series circuit can be defined as a circuit that includes one resistor, one inductor, and one capacitor that are all connected in series. Such a circuit has numerous practical applications and is typically utilized as a bandpass filter or in the creation of oscillators. The circuit is also known as a "resonant circuit," because it has the ability to resonate at a specific frequency, known as the resonant frequency. Consider the following RLC series circuit, which has an R-value of 100.0 Ω, an L-value of 0.70 H, and a C-value of 10.0 µF, connected to a generator with an emf \(V(t) = V_{max}\) cos(ωt), where \(V_{max} = 170 V\) and ω = 339 rad/s. The following is a brief description of the RLC series circuit:

At ω = 0, the capacitor in the circuit behaves as an open circuit, while the inductor behaves as a short circuit. As a result, the current flowing through the circuit is zero.

At high frequencies, the capacitor behaves as a short circuit, and the current flowing through the circuit is simply that which is determined by the resistance.

At the resonant frequency, the capacitor and inductor currents are equal and opposite, and the total current flowing through the circuit is zero. The resonant frequency, ω0, of the circuit can be calculated using the formula:ω0 = 1/√(LC)At the resonant frequency, the impedance, Z, of the circuit is equal to the resistance, R, of the circuit. The total current flowing through the circuit is the voltage divided by the impedance: I = Vmax/R.

The above RLC series circuit with an R-value of 100.0 Ω, an L-value of 0.70 H, and a C-value of 10.0 µF, connected to a generator with an emf \(V(t) = V_{max}\) cos(ωt), where \(V_{max} = 170 V\) and ω = 339 rad/s, can be analyzed in the following way:

At resonance, the impedance of the circuit is R = 100.0 Ω, and the total current flowing through the circuit is \(I = \frac{V_{max}}{R} = 1.70 A\). The phase angle of the circuit can be determined using the following formula:

tan θ \(= \frac{X_{l}- X_{c}}{R}\) Where Xl = ωL is the inductive reactance and \(X_{c}\) = 1/ωC is the capacitive reactance. At resonance, \(X_{l}= X_{c}\) = 1/ωC = ωL. As a result, the phase angle of the circuit is zero (cos θ = 1 and sin θ = 0), and the current and voltage are in phase with each other. The voltage across the inductor is \(V_{l} = X_{L}*I = I*\)ωL = 1.19 V, while the voltage across the capacitor is \(V_{c} = X_{c}*I = I\)/(ωC) = 53.77 V.

Since the voltage across the inductor and capacitor are equal and opposite, the voltage across the resistor, Vr, must be equal to the voltage of the generator, V(t). Thus, \(V(t) = V_{r} = 170 V\).

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Roark saw Alejandro sitting by himself in the quad and leaning over, with his head resting on the heels of his hands. Roark approached him and said, "Hey Alejandro, you look sad." Alejandro responded, "Huh? No, I'm just thinking." Which difficulty in interpreting nonverbal behavior does this exchange exemplify?


A. Nonverbal messages are often ambiguous.

B. Nonverbal messages are continuous.

C. Nonverbal cues are multichanneled.

D. Nonverbal interpretation is culture-based.

Answers

Answer:

Option A

Explanation:

Nonverbal communications are ambiguous because some times the face expressions (non verbal signals – Sad face or sitting alone gesture of Alejandro) and the verbal signals (communication between Roark and Alejandro) do not match or contradict each other. Some people prefer to believe on their interpretations of the nonverbal  signals as compared to that of the verbal signals

Hence, option A is correct.

Which force does not operate at a distance of 1 m?
A. Weak nuclear
O B. Electric
C. Gravitational
D. Magnetic

Answers

Answer:

A

Explanation:

The Force that doesn’t operate at the distance of 1m is Weak Nuclear

Two satelites, both with mass 10,000 kg, are in space about 30 m
apart. What is the force of gravity between them? Universal
Gravitational Constant: G = 6.674 x 10-11 m2/kg/s2

Answers

The force of gravity between the two satellites is approximately 2.22266667 x 10^-6 Newtons.

To calculate the force of gravity between two satellites, we can use Newton's law of universal gravitation. The formula is given as:

F = (G * m1 * m2) / r^2

where:

F is the force of gravity,

G is the gravitational constant (G = 6.674 x 10^-11 m^3/(kg s^2)),

m1 and m2 are the masses of the satellites, and

r is the distance between the centers of the satellites.

In this case, both satellites have a mass of 10,000 kg, and they are 30 m apart.

Plugging the values into the formula, we have:

F = (6.674 x 10^-11 * 10,000 * 10,000) / (30^2)

Calculating this expression, we find:

F = 2.22266667 x 10^-6 N

Therefore, the force of gravity between the two satellites is approximately 2.22266667 x 10^-6 Newtons.

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A member of the mafia died a quick and sudden death at a restaurant. His family
suspects that it was a poisoning. What should a forensic toxicologist request to check
right away?
O the color of the lips, to rule out arsenic
O the gastric contents because there may still be undigested pills
O the heart rate, to confirm the death
O the color of the feet, to rule out carbon monoxide poisoning

Answers

Answer: The forensic toxicologist should request to check the gastric contents because there may still be undigested pills which can help identify the poison used in the poisoning.

Explanation:

Advanced Wireless Services (AWS) is a wireless telecommunications spectrum band used for mobile voice and data services, video, and messaging. The AWS band uses frequencies in several segments: from 1695 to 2200 MHz. a) Determine the corresponding range of wavelengths used by the AWS mobile devices. b) To what region/band of electromagnetic spectrum does the range belong

Answers

Given data

*The given frequency is

\(f_1_{}=1695\text{ MHz}=1695\times10^6\text{ Hz}\)

*The another given frequency is

\(f_2=2200\text{ MHz=}2200\times10^6\text{ Hz}\)

*The given speed of light is c = 3.0 × 10^8 m/s

(a)

The formula for the wavelength is given as

\(\lambda_1=\frac{c}{f_1}\)

Substitute the known values in the above expression as

\(\begin{gathered} \lambda_1=\frac{(3\times10^8)}{(1695\times10^6)^{}} \\ =0.176\text{ m} \end{gathered}\)

The another wavelength for the another frequency is calculated as

\(\begin{gathered} \lambda_2=\frac{c}{f_2} \\ =\frac{(3.0\times10^8)}{(2200\times10^6)} \\ =0.136\text{ m} \end{gathered}\)

(b)

Radio spectrum is an electromagnetic spectrum where the frequency range belongs of wireless telecommunication.

What evidence supports the conclusion that a chemical reaction has occurred?

Answers

Answer:

Precipitation formed

Temperature change

fizzing and hissing

bubbles

change in state

Explanation:

Answer:

Precipitation formed

Temperature change

fizzing and hissing

bubbles

change in state

Explanation:

Physicist ____ was found to have completely made up some of the data on which his astounding discoveries were made.

Answers

Answer:

Jan Hendrik Schön I believe

the water enters the pipe with an inside diameter d=2.68cm and rises to a maximum height h=2.54m above the pump. what is the pressure, in pascals, at the maximum height? (neglect frictional losses.)

Answers

The density of water is approximately 1000 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s².

P = 1000 kg/m³ * 9.8 m/s² * 2.54 m

To determine the pressure at the maximum height, we can use the principle of hydrostatic pressure. This principle states that the pressure in a fluid at any given depth is directly proportional to the density of the fluid, the acceleration due to gravity, and the depth.

First, we need to convert the inside diameter of the pipe to meters. Given that d = 2.68 cm = 0.0268 m.

Next, we can calculate the pressure at the maximum height using the equation:

P = ρ * g * h

where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the height.

The density of water is approximately 1000 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s².

Substituting the values into the equation:

P = 1000 kg/m³ * 9.8 m/s² * 2.54 m

Calculating the expression will give us the pressure P in pascals (Pa).

Note: Make sure to use the correct units and double-check the values used in the calculation for accuracy.

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Consider the system with the following step response: s(k)=2δ(k)+4δ(k−1)+61(k−2) where 1(k) is the discrete-time step function. (a) Determine the impulse response of the system. (b) Construct a difference equation describing the relationship between input and output. (c) Derive an expression of
U(z)
Y(z)

. (d) Draw a block diagram relating Y(z) and U(z) using just the summer, delay and gain blocks. (e) State the order of the system, and describe its relation with the number of delay blocks used in part (d).

Answers

(a) To determine the impulse response of the system, we need to find the output of the system when the input is an impulse function.

In this case, the impulse function is given by

s(k) = 2δ(k) + 4δ(k−1) + 61(k−2), where δ(k)

is the discrete-time impulse function.

When the input is an impulse function, the output is equal to the impulse response of the system. Therefore, the impulse response can be found by setting s(k) = δ(k) and solving for the output.

By substituting δ(k) into the given expression for s(k), we have:
2δ(k) + 4δ(k−1) + 61(k−2) = δ(k)

Simplifying the equation, we get:
2 + 4δ(k−1) + 61(k−2) = 1

Now, comparing the coefficients of δ(k−1) and the constant term on both sides of the equation, we can determine the impulse response.

From the equation, we can see that the coefficient of δ(k−1) is 4, and the constant term is 2 + 61(−2) = −120.

Therefore, the impulse response of the system is h(k) = 4δ(k−1) − 120.

(b) To construct a difference equation describing the relationship between the input and output, we need to express the output of the system, y(k), in terms of the input, u(k), and past values of the output and input.

From part (a), we know that the impulse response is h(k) = 4δ(k−1) − 120.

Using this impulse response, we can write the difference equation as follows:
y(k) = 4u(k−1) − 120u(k)

(c) To derive an expression for the z-transforms of U(z) and Y(z), we need to take the z-transform of the difference equation derived in part (b).

Taking the z-transform of both sides of the difference equation, we get:
Y(z) = 4z^(-1)U(z) - 120U(z)

(d) To draw a block diagram relating Y(z) and U(z) using just the summer, delay, and gain blocks, we can represent the z-transform equation from part (c) as a block diagram.

The block diagram can be represented as follows:

                +-----+
                |     |
           ---->| z^(-1) |---+------> Y(z)
          |     |     |   |
          |     +-----+   |
          |               |
     U(z)--|     +-----+   |
          |     | 4   |   |
          +---->|     |---+
                |     |
                +-----+

In the block diagram, the delay block represents z^(-1), the gain block represents 4, and the summer block represents the addition of the two signals.
Therefore, the order of the system is 1, and it is directly related to the number of delay blocks used in the block diagram.

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A massive light hangs over the table in Jeremy's dining room. The light is supported by four strong chains which make an angle of 72° with the horizontal. The force in each chain is 36.4 N. Determine the mass of the light in kilograms (kg). Use the approximation g ≈ 10 m/s^2.

Answers

Given

A massive light hangs over the table in Jeremy's dining room. The light is supported by four strong chains which make an angle of 72° with the horizontal.

The force in each chain is F=36.4 N.

To find

The mass of the light in kg

Explanation

Let the mass of the light be m

The weight of the light acts downwards.

To balance thisi force the force on the string vertically upward is considered

In equillibrium

\(\begin{gathered} mg=4Fsin72^o \\ \Rightarrow10m=4\times36.4\times sin72^o \\ \Rightarrow m=13.84\text{ kg} \end{gathered}\)

Conclusion

The mass of the light is 13.84 kg

Sound waves move the fastest through which medium?

Answers

Answer:

Sound travels fastest through solids.

Explanation:

This is because molecules in a solid medium are much closer together than those in a liquid or gas, allowing sound waves to travel more quickly through it. In fact, sound waves travel over 17 times faster through steel than through air.

Sound waves move the fastest through the solid. The speed of the sound wave  in the liquid and gas is low,

What is sound wave?

A sound wave is produced when a medium begins to vibrate. When an entity vibrates, a pressure wave is formed, which causes sound.

Solids transmit sound the fastest. Because the molecules in a solid medium are much closer together than in a liquid or gas, sound waves can move through it much faster.

Hence, sound waves move the fastest through the solid.

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ntally Check for Understanding
POSSIBLE POINTS: 5
In a football game, the kicker kicks the football a horizontal distance of 39 m. If the ball lands 3.9 s later, what is the football's horizontal velocity just before
it lands?
0 10 m/s
41 m/s
0 34 m/s
O 14 m/s

Answers

Answer: 34

Explanation:

34

magnitude F have a
resultant of the
same magnitude F.
The angle between
the two forces is:
45 degree
120 degree
150 degree
180 degree​

Answers

Answer:

120°

Explanation:

Given forces with magnitude F and F

Applying the parallelogram law of vector

Where resultant is given as :

R = √(A^2 + B^2 + 2ABCos Ф

WHERE A and B are two forces with angle Ф

F =√(F^2 + F^2 + 2F * F Cos Ф

Square both sides

F^2 = F^2 + F^2 + 2F^2 CosФ

F^2 - 2F^2 = 2F^2 CosФ

- F^2 = 2F^2 Cos Ф

Divide both sides by 2F^2

- 1 / 2 = CosФ

Cosine(theta) = - 1/2

Ф = cosi^-1 (-1/2)

Ф = 120°

Element Z has a half-life of 5 hours. After 1 day has passed, what percentage of Element Z would be remaining? After 1 day, % of Element Z would be remaining.

Answers

After 1 day has passed, approximately 6.25% of Element Z would be remaining.

The half-life of an element is the time it takes for half of the initial amount of the element to decay or transform into another element or isotopes. In this case, Element Z has a half-life of 5 hours.

To determine the percentage of Element Z remaining after 1 day (24 hours), we need to calculate the number of half-lives that have occurred.

Since the half-life of Element Z is 5 hours, there are 24 hours divided by 5 hours, which equals 4.8 half-lives.

Each half-life reduces the amount of Element Z by half. So, after 4.8 half-lives, the remaining amount of Element Z would be (1/2)^(4.8) = approximately 0.0625 or 6.25%.

Therefore, after 1 day has passed, approximately 6.25% of Element Z would be remaining.

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which four items were invented for moving and working in space This is astrology but it didn't give me an option to put that as the subject.

Answers

Answer: Innovations originally designed for space vehicles, including artificial muscle systems, robotic sensors, diamond-joint coatings, and temper foam,

Explanation: make artificial human limbs more functional, durable, comfortable, and life-like.

A bus travels 50.0 km/hr for 3.80 hours. The distance traveled will be what?

Answers

190.0 km because 50 times three is 150 and 80% of 50 is 40 so 150+40 is 190

What is the current in a 160V circuit if the resistance is 10Ω?

Answers

Hello!!

For this, use the formula:

\(\boxed{I=V/R}\)

\(\textbf{Being:}\)

\(\sqrt{}\) \(I = Current = ?\)

\(\sqrt{}\) \(V = Voltage = 160 \ V\)

\(\sqrt{}\) \(R = Resistance = 10\ \varOmega\)

\(\textbf{If we replace and resolve it}\)

\(I = 160\ V / 10\ \varOmega\)

\(I = 16\ A\)

\(\text{The current of that circuit is \textbf{16 Amperes}}\)

a 0.690-kg basketball is dropped out of a window that is 6.75 m above the ground. the ball is caught by a person whose hands are 1.50 m above the ground. (a) how much work is done on the ball by its weight? what is the gravitational potential energy of the basketball, relative to the ground, when it is (b) released and (c) caught? (d) what is the change (pef - pe0) in the ball's gravitational potential energy?

Answers

a) The weight of the ball does 45.2 J of work on it.

b) When the basketball is released, its gravitational potential energy is zero because it is at ground level.

c) When a basketball is caught, its gravitational potential energy relative to the ground is 10.2 J.

d) The change in gravitational potential energy of the ball from release to capture is -37.0 J, indicating a decrease in potential energy.

(a) The work done on the ball by its weight when it is dropped can be calculated as:

W = mgh

where m is the mass of the ball, g is the acceleration due to gravity, and h is the height from which it is dropped. Substituting the given values, we get:

⇒             W = (0.690 kg) * (9.81 m/s^2) * (6.75 m)

⇒                    = 45.2 J

Therefore, the work done on the ball by its weight is 45.2 J.

(b) The gravitational potential energy of the basketball relative to the ground when it is released is zero, as it is at ground level.

(c) When the ball is caught by a person whose hands are 1.50 m above the ground, its gravitational potential energy can be calculated as:

⇒      PE = mgh

where m is the mass of the ball, g is the acceleration due to gravity, and h is the height above the ground. Substituting the given values, we get:

⇒       PE = (0.690 kg) * (9.81 m/s^2) * (1.50 m)

⇒             = 10.2 J

Therefore, the gravitational potential energy of the basketball relative to the ground when it is caught is 10.2 J.

(d) The change in the ball's gravitational potential energy from when it is released to when it is caught can be calculated as:

⇒       PE_f - PE_0 = mgh_f - mgh_0

where m is the mass of the ball, g is the acceleration due to gravity, h_f is the final height, and h_0 is the initial height. Substituting the given values, we get:

⇒     PE_f - PE_0 = (0.690 kg) * (9.81 m/s^2) * (1.50 m - 6.75 m)

⇒                         = -37.0 J

Therefore, the change in the ball's gravitational potential energy from when it is released to when it is caught is -37.0 J, indicating a decrease in potential energy.

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Please help will be marked most brainlist !!!

Which of the following is not a true statement?

Please help will be marked most brainlist !!!Which of the following is not a true statement?

Answers

Answer:

d

Explanation:

all of the rest are true

About how much greater is the gravitational force exerted by the moon on the near side of the earth than on the far side?.

Answers

The near side of the Earth is 12740 km closer to the Moon than the far side. As a result, the near side experiences a gravitational force that is 7% stronger than the far side.

The gravitational attraction of the moon on Earth is what primarily causes ocean tides to rise and fall. The gravitational pull of the moon creates two bulges of water in the Earth's oceans: one where the pull is strongest and the ocean waters face the moon, and the other where the pull is weakest and the ocean waters face away from the moon.The surface gravity of the Moon is around 1/6th as strong, or 1.6 meters per second every second. Because the Moon is significantly less massive than Earth, its surface gravity is weaker. The surface gravity of a body is inversely related to the square of its radius but directly proportional to its mass.

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17
Quotations
Dark They Were
Can you discuss the following quotations from the story?
1. "The wind blew, whining. At any moment the Martian air might draw his
soul from him, as marrow comes from a white bone."
2. "A radio flash just came. Atom bombs hit New York! All the space
rockets blown up. No more rockets to Mars, ever!"

Answers

The quotation highlights the colonists' fear and uncertainty about their new environment. The phrase "the Martian air might draw his soul from him" suggests that the atmosphere of Mars is so inhospitable that it could kill the colonists.

The second quotation highlights the colonists' isolation and the fragility of their situation on Mars.

What do the quotes mean?

"The wind blew, whining. At any moment the Martian air might draw his soul from him, as marrow comes from a white bone." The story takes place on Mars, where a group of human colonists have settled after leaving a war-torn Earth. The comparison to "marrow coming from a white bone" is a vivid metaphor that conveys the idea of something being drawn out of a person with great force.

"A radio flash just came. Atom bombs hit New York! All the space rockets blown up. No more rockets to Mars, ever!" The colonists on Mars receive this radio message, which tells them that a catastrophic event has occurred on Earth. The news that atom bombs have hit New York and that all the space rockets have been destroyed is a devastating blow to the colonists, who had been hoping to receive supplies and reinforcements from Earth. It also suggests that their dreams of building a new civilization on the red planet may be dashed by events beyond their control.

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