an amount of medication of mg is found to result in a blood pressure of mm hg. what is the predicted blood pressure

Answer:

Ferric chloride test

Explanation:

The ferric chloride test can be used to detect metabolites in urine in case of inborn error of metabolism such as phenylketonuria. Compounds such as phenylpyruvate increase in plasma and are excreted out via urine. Also, it can be used to detect salicylates in urine, quick diagnostic test for aspirin overdose.

Answer:

true

Explanation:

we have many sattelites that are seen by many astounouts in space by telescope but more than half space is not discoverd

Answer:

Argon is an element on the periodic table. It is a member of the noble gasses, meaning that it is a monoatomic pure gas. In other words, argon gas particles are simply pure single atoms of argon. ... Finally, water is a polyatomic molecule H2O composed of two atoms of hydrogen and one atom of oxygen.

Explanation:

Answer:

im 13 too...

Explanation:

but i dont  have a phone and i cant see your pic. not that it matters to me.          

Answer:

The correct statement is: O This is the equivalence point of the curve.

Explanation:

The equivalence point is the point in a titration where the number of moles of acid added is equal to the number of moles of base needed to neutralize the acid. At this point, the acid and base react to form water and a salt. The pH at the equivalence point depends on the strength of the acid and base being used and the total volume of the solution. In general, the pH at the equivalence point will be higher for a strong acid-strong base titration than for a weak acid-strong base titration.

Answer:

6.6666666667 feet per second I believe

Answer:

4.5 miles per hour.

Explanation:

30* 2= 400 feet in 1 min

24,000 per hour

5280 feet is 1 mile.

To compute the applied load, we need to use the equation: Load = constant x (Diagonal Length)^2. The constant for a material with a measured hardness of 164 HK is typically 0.2.

To compute the applied load for a material with a measured hardness (HK) of 164 and an indentation diagonal length of 0.24 mm, please follow these steps:

Step 1: Recall the formula for Knoop hardness (HK):
HK = P / A, where P is the applied load in kgf, and A is the projected area of the indentation in mm².

Step 2: Calculate the projected area of the indentation (A) using the formula:
A = 0.0703 * L², where L is the indentation diagonal length in mm (0.24 mm in this case).
A = 0.0703 * (0.24)²
A ≈ 0.00403 mm²

Step 3: Rearrange the HK formula to solve for the applied load (P):
P = HK * A
P = 164 * 0.00403
P ≈ 0.66092 kgf

Therefore, the applied load for the material with a measured hardness of 164 and an indentation diagonal length of 0.24 mm is approximately 0.66092 kgf.

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Answer: 26C is 25.0 torr

Explanation: The decrease in vapor pressure is proportional to the molality of the solution, so the vapor pressure of the solution at 26°C is 25.0 torr.

First, we need to find the number of moles of glucose and water present in the solution:

n(glucose) = 16.0 g / 180.0 g/mol = 0.089 mol

n(water) = 80.0 g / 18.0 g/mol = 4.44 mol

Next, we'll find the mole fraction of water in the solution:

X_water = n(water) / (n(glucose) + n(water)) = 4.44 / (0.089 + 4.44) = 0.989

Finally, we can find the vapor pressure of the solution using Raoult's law:

P_solution = X_water * P_purewater = 0.989 * 25.21 torr = 25.0 torr

So the vapor pressure of the solution at 26°C is 25.0 torr.

Equilibrium. Option C is correct

This law states that a new equilibrium state is achieved if the changes in temperature, pressure, concentration and volume will cause a predictable and opposing changes in the system.

This shows that Le Chatelier's principle can be used to predict the properties above to determine the effect equilibrium have on a system.

Based on the above explanations, we can conclude that Le Chatelier's Principle governs the property of Equilibrium.

Answer:

Explanation:

The space between the large nucleus and the electrons is huge. We know this because the alpha particles shot at the gold foil most went right on through. That means that the space between hold atoms is very large.

B

Not only that but the deflection that takes place is not frequent further telling us that the the nucleus must be positively charged. That observation comes from the deflection itself. The charge on the nucleus must be the same as the alpha particle. If they were different, and the nucleus was negative, those particles that were deflected would now be absorbed.

Answer:

C stay away from trees, water, and tall objects.

Explanation:

took the quiz and got it right :)

A person trapped outside during a thunderstorm should stay away from the following:

This is defined as a rain shower during which you hear thunder with a corresponding lightning.

It is best to avoid trees, water, and tall objects during thunderstorms to prevent accidents and death.

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Answer:

down syndrome is research because you research the three sets of chromosome 21

Explanation:

At the point in the titration where 354 ml of 0.21 M HCOOH was added to 126 ml of 0.9 M NaOH, the pH is approximately 1.67.  

To find the pH at the point in the titration where 354 ml of 0.21 M HCOOH was added to 126 ml of 0.9 M NaOH, we can use the following steps:

Write the balanced chemical equation for the reaction between formic acid and sodium hydroxide:

HCOOH(aq) + NaOH(aq) → O(l) + CO(g) + NaOH(aq)

Use the volume of the unknown acid solution (354 ml) and the volume of NaOH solution needed to neutralize it (126 ml) to find the concentration of formic acid:

[HCOOH] = [HCOOH] x V

[HCOOH] = 354 ml x 0.21 M

[HCOOH] = 77.6 mM

Use the molarity of the formic acid and the volume of NaOH solution to find the concentration of NaOH:

[NaOH] = [NaOH] x V

[NaOH] = 126 ml x 0.9 M

[NaOH] = 115.6 mM

Use the concentrations of the acid and base to find the stoichiometric equation for the reaction:

[HCOOH] = [NaOH] x (1 + [HCOOH]/[NaOH])

[HCOOH] = 77.6 mM x (1 + 77.6 mM/115.6 mM)

[HCOOH] = 80.4 mM

Use the balanced stoichiometric equation and the volumes of the acid and base to find the change in volume of the solution during the titration:

ΔV = [HCOOH] x V_initial - [HCOOH] x V_final

ΔV = 80.4 mM x 354 ml - 80.4 mM x 126 ml

ΔV = 1284 ml - 1056 ml

ΔV = 228 ml

Finally, use the change in volume to find the volume of NaOH solution needed to neutralize the formic acid:

ΔV_NaOH = -ΔV

ΔV_NaOH = -228 ml

ΔV_NaOH = 228 ml

V_NaOH = -228 ml

V_NaOH = 228 ml

Therefore, at the point in the titration where 354 ml of 0.21 M HCOOH was added to 126 ml of 0.9 M NaOH, the pH is approximately 1.67.  

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The enthalpy change for the given reaction is 9.16 kJ/mol, which is positive, indicating that the reaction is endothermic.

To find the enthalpy change (ΔH0) for the given reaction, we need to use the standard enthalpies of formation (ΔHf0) for each species involved in the reaction. We can use the following equation:

ΔH0 = ΣnΔHf0(products) - ΣmΔHf0(reactants)

where n and m are the stoichiometric coefficients of the products and reactants, respectively.

The standard enthalpies of formation for O2 (g), N2 (g), and N2O4 (g) are 0 kJ/mol, 0 kJ/mol, and 9.16 kJ/mol, respectively. Therefore, the enthalpy change for the reaction can be calculated as follows:

ΔH0 = [1 x ΔHf0(N2O4)] - [1 x ΔHf0(O2) + 2 x ΔHf0(N2)]

ΔH0 = [1 x 9.16 kJ/mol] - [1 x 0 kJ/mol + 2 x 0 kJ/mol]

ΔH0 = 9.16 kJ/mol

Therefore, the enthalpy change for the given reaction is 9.16 kJ/mol, which is positive, indicating that the reaction is endothermic (absorbs heat).

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Answer:

Electrostatic attraction between oppositely charged ions

Explanation:

involve the formation of an octet of electrons in their valence shells, except for hydrogen which needs a duet of electrons

Answer:  Lab - refer to attached -

All correct, completed vital lab for Acid and bases

Explanation:  Mark me as Brainliest ;)

6.61 grams of NaOBr must be dissolved in 488 mL of 0.260 M HOBr to produce a buffer solution with pH 8.30.

Bromine reacts with sodium hydroxide to produce sodium hypobromite (NaOBr), which changes the primary amide into an isocyanate intermediate.

To calculate the mass of NaOBr needed to produce a buffer solution with a pH of 8.30, we need to use the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

where pKa is the acid dissociation constant of HOBr, [A-] is the concentration of the conjugate base (OBr-) and [HA] is the concentration of the acid (HOBr).

We can rearrange this equation to solve for [A-]/[HA]:

[A-]/[HA] = 10^(pH - pKa)

We know the pH of the buffer solution (pH = 8.30) and the pKa of HOBr is 8.65. Therefore:

[A-]/[HA] = 10^(8.30 - 8.65) = 0.425

Since the initial concentration of HOBr is 0.260 M, we can set up the following equation to find the concentration of OBr- needed:

0.425 = [OBr-]/0.260

[OBr-] = 0.1105 M

Now, we can use the volume of the solution and the concentration of OBr- to calculate the moles of NaOBr needed:

moles of NaOBr = moles of OBr- = [OBr-] x volume

moles of NaOBr = 0.1105 M x 0.488 L = 0.0538 moles

Finally, we can use the molar mass of NaOBr to convert moles to grams:

mass of NaOBr = moles of NaOBr x molar mass of NaOBr

mass of NaOBr = 0.0538 moles x 122.89 g/mol = 6.61 g

Therefore, 6.61 grams of NaOBr must be dissolved in 488 mL of 0.260 M HOBr to produce a buffer solution with pH 8.30.

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Answer: To efficiently communicate with others

Explanation:

this was the right on answer for me might be different for others

The main need or want the wave technology shown meets to see objects surrounding more clearly.

It is a floating device that operates in the same direction as the waves. With the use of the technology, energy may be captured even from relatively small waves. The device that is moved by waves activates a hydraulic system that can power a generator. The tube segment contains all the generation equipment and systems.

Early mechanization (1770s to 1830s), steam power and railroads (1830s to 1880s), electrical and heavy engineering (1880s to 1930s), Fordist mass production (1930s to 1970s), and information and communication are the five waves that have so far slammed into our society (1970s to 2010s).

Wave energy, also known as wave power, is the energy that ocean surface waves carry and absorb. The energy is then put to use in a variety of productive ways.

Thus, The main need or want the wave technology shown meets to see objects surrounding more clearly.

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Answer:

H2SO4 + 2(NaOH) -----> Na2SO4 + 2(H2O).

Explanation:

Answer:

They make a rice Krispe gramcracker bar baby

Explanation:

Answer: When they meet they instantly fall in love, (lol) and have a baby.... They name the baby S'more because it has features from the graham cracker and the rice krispie.

Stay safe and have a Merry Christmas!!!!!!!! :D  

Maybe a S'more rice krispie.....

Yes, a reaction occurs when aqueous solutions of aluminum sulfate and potassium sulfide are combined.

When these two solutions are mixed, aluminum sulfide and potassium sulfate are formed through a double displacement reaction. The balanced chemical equation for this reaction is:

Al2(SO4)3 + 3K2S → 2Al2S3 + 3K2SO4

Aluminum sulfate and potassium sulfide are both soluble in water and dissociate into ions when in aqueous solutions. During the reaction, the aluminum ions and sulfide ions combine to form aluminum sulfide, which is insoluble in water and forms a precipitate. The potassium ions and sulfate ions remain in solution as potassium sulfate.

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The density of fes2 4.9 cm3.

1 gram calcite occupies 0.369 cm3  volume , first find density of calcite as explained bellow

mass of calcite = 1 gram , volume of calcite = 0.369 cm

we know formula   density = mass/ volume , substitute above values in this formula to find density of calcite

density of calcite = 1/0.369 = 2.71 gram/cm3

given that pyrite is 1.8 times denser than calcite  

therefore density of pyrite = 1.8 x density of calcite

substitute values in above formula to find density of pyrite

density of pyrite = 1.8 x density of calcite

density of pyrite = 1.8 x 2.71 =  4.878 gram/cm3

density of pyrite calculated by above method is  4.878 g/cm3  this value is closest value of  4.9 cm3 .

The quantity of some thing in step with unit volume, unit vicinity, or unit period: as. : the mass of a substance in step with unit volume. density expressed in grams per cubic centimeter.

A chemical components is an expression that suggests the factors in a compound and the relative proportions of those factors. If best one atom of a particular type is gift, no subscript is used. For atoms that have two or greater of a particular sort of atom gift, a subscript is written after the image for that atom..

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Horner-Wadsworth-Emmons (HWE) reaction is an important synthetic reaction in organic chemistry. It is widely used for synthesizing various compounds. The reaction is between an aldehyde or ketone and a phosphonate or phosphonate ester in the presence of a strong base.

The Horner-Wadsworth-Emmons reaction is one of the most convenient and well-known methods of constructing carbon-carbon double bonds. The reaction proceeds via the formation of an ylide intermediate. The HWE reaction is particularly useful for the synthesis of compounds with a Z-configuration.

The mechanism for the reaction of diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of aqueous NaOH, forming 3,4-methylenedioxystilbene as the product, can be explained in the following steps:

Step 1: Formation of the ylide intermediate

The reaction starts with the formation of an ylide intermediate. This is achieved by the reaction of diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of a strong base like NaOH or KOH. In this reaction, a deprotonated species called an ylide intermediate is generated.

Step 2: Addition of the ylide intermediate to the aldehyde

The ylide intermediate then attacks the aldehyde, leading to the formation of a betaine intermediate.

Step 3: Formation of the phosphonate ester

The betaine intermediate undergoes elimination to form the final product, 3,4-methylenedioxystilbene, and the by-product phosphonate ester.

The mechanism of the Horner-Wadsworth-Emmons (HWE) reaction between diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of aqueous NaOH, forming 3,4-methylenedioxystilbene as the product, is complete. This reaction is significant in organic chemistry and finds applications in the pharmaceutical industry.

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The number of spoonfuls required to cover a specific area could then be counted to estimate the total number of sand grains.

This method would likely lead to an estimate rather than an exact count, as the number of grains in each spoonful may vary. Another idea is to use a smaller measuring spoon, such as a teaspoon or a tablespoon, and count the number of spoonful's required to fill a container of known volume.

By dividing the total volume of the container by the volume of one spoonful, an estimate of the total number of sand grains could be obtained. This method could also lead to an estimate due to variations in the size of the grains and the accuracy of the measuring spoon.

To improve these ideas, a more precise measuring device, such as a scale, could be used to measure the exact weight of the sand. This would provide a more accurate count of the number of sand grains, rather than relying on estimates based on volume or area.

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Answer:

chemical energy is the energy of a chemical substance that is stored in the bonds of chemical compounds and is released when they undergo a chemical reaction and transform into another substance

Answer:

Decrease the distance between them or increase the mass.

Explanation:

F= GM1M2/ R²

Answer:

decrease the distance between the objects

Explanation:

i did the test and got da epic 100 score

Explanation:

Halogens tend to gain one electron so that they can get a full outer level and be stable.

Answer: 27 g of Fe2(SO4)3

Explanation:

I'm assuming that there is an error in the original question: Fe2(SO3)4 is not a likely product. Indeed, a reactant of FePO4 would suggest that we are working with Fe atoms with +3 charge, however, the product Fe2(SO3)4 would have Fe atoms with a 0 charge (since SO3 is normally neutral), which is not consistent.

The correct product should be Fe2(SO4)3.

Proceeding under this corrected information:

First we must determine the balanced chemical equation. To do this, start by noting the relevant charges of the reactants:

FePO4:  PO4 = -3 charge,  Fe = +3 charge

Na2SO4:  SO4 = -2 charge,  Na = + 1 charge.

Then, in order to keep the charges balanced, the reaction must be:

\(2 \ \text{FePO}_4 + 3 \ \text{Na}_2\text{SO}_4 \rightarrow 2\ \text{Na}_3\text{PO}_4 + \text{Fe}_2(\text{SO}_4)_3\)

Next, we assume that we have excess Na2SO4. Then,

20 g FePO4  
x 1 mol FePO4 / (150.82 g FePO4)
x 1 mol Fe2(SO4)3 / (2 mol FePO4)
x 399.88 g Fe2(SO4)3 / (1 mol Fe2(SO4)3)
--------------------------
26.51 g Fe2(SO4)3

which we report as 27 g Fe2(SO4)3 after applying significant figures.

Ethylene has a zero dipole moment because it is symmetrical, causing all the bond dipole moments to cancel out. On the other hand, propene has a small dipole moment of 0.3 D due to the electron-withdrawing ability of the methyl group.

In more detail, ethylene (C2H4) has a planar structure with carbon-carbon double bond, and the hydrogen atoms are evenly distributed around the carbons. This symmetrical arrangement leads to the cancellation of bond dipoles, resulting in a zero net dipole moment. Propene (C3H6), on the other hand, contains a carbon-carbon double bond and an additional methyl group (CH3) connected to one of the carbon atoms. This methyl group exhibits electron-withdrawing properties, generating a dipole moment between the carbon atoms. This results in a small, non-zero net dipole moment for propene.

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Answer:

8.90

Explanation:

Density = mass ÷ volume

D = 222.50 g ÷ 25.00

= 8.9

The density of the unknown metal is 8.90.

Hope that helps.

Answer:

C: 8.90

Explanation:

The conjugate acid-base pairs in the reaction HBr(aq) + \(NH_3\)(aq) ⇔\(Br^-\)(aq) + \(NH_4^+\)(aq) are HBr/\(NH_4^+\) and \(NH_3/Br^-\).

In the given reaction, HBr acts as an acid, donating a proton (\(H^+\)) to \(NH_3\), which acts as a base. As a result, \(NH_3\) gains a proton to form its conjugate acid, \(NH_4^\). In this acid-base pair, \(NH_4^\) is the conjugate acid since it is formed by accepting a proton from HBr.

Conversely, HBr loses a proton and becomes its conjugate base, \(Br^-\). Thus, \(Br^-\) is the conjugate base of HBr. The reaction can proceed in both directions, indicating the reversible nature of the acid-base reaction, with the formation of the conjugate acid-base pairs \(NH_4^+/Br^-\) and HBr/\(NH_3\).

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