An aircraft is flying straight and level at an altitude h=6000 ft and a constant speed of 500 ft/sec. It then releases a bomb. 5 seconds after the bomb was released, a gun determines the firing soluti

The interiors of Saturn and Jupiter contain a large amount of large metallic hydrogen because liquid hydrogen transforms into liquid metallic hydrogen as one descends, reaching a depth of 12,000 kilometers as the radius of Jupiter is 71,000 kilometers the hydrogen is below the cloud layers.

Helium and hydrogen make up the majority of the atmospheres of Jupiter and Saturn. The hydrogen changes from a high-pressure gas to liquid hydrogen a few hundred kilometers below the cloud levels. It would take some fairly intense pressures to create this on Earth, but it is possible. It's a component of rocket fuel.

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Answer:

Total resistance (Rt) =2

Explanation:

Rt=R1*R2/R1+R2

Rt=6*3/6+3

Rt=18/9

Rt=2

Answer:

Parallel universe, or alternate reality, is a hypothetical self-contained plane of existence, co-existing with one's own

Answer:

Parallel Universe is a hypothetical self-contained plane of existence, co-existing with one's own

Answer:

Explanation:

ok it's correct

It's important to know that the wavelength and the frequency has inverse relationship, which means the longest is its wavelength, the more intense will be the frequency.

Answer:

1 watt is the same as the transfer of 1 joules per second.

1 watt is the same as the transfer of energy at a rate of 1 joule per second.

A watt is a unit of power, representing the amount of energy transferred or converted per unit of time. Specifically, 1 watt is equivalent to 1 joule of energy being transferred every second. It is a common metric used to measure the rate of energy flow or work done in various systems. For example, a 100-watt light bulb converts electrical energy into light and heat at a rate of 100 joules per second. Understanding power in terms of watts helps us quantify and compare the efficiency and performance of different devices and processes.

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gas is the answer for this question

can you make me a brainlist

Answer:

B. lower, greater

...............

The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.

d (distance) from A to B is = √2gh

In this case given are, g = 9.8 m/s² and h = 100m,

so here d = √(2⋅9.8⋅100) = 44.3m.

Final velocity ,v = √2gh

Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,

g = 9.8 m/s² ,h = 100m,

v = √(2⋅9.8⋅100)

= 44.3 m/s (final velocity)

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Answer:

LOL i belive its 200 because i did this exact same thing yesterday for homework and got it right bcs i got it lol, yw btw! hahaha! good luck also, subscribe to my channel!

Explanation:

Answer:

\(2.8\; {\rm s}\).

Explanation:

The velocity of vehicle \(2\) relative to vehicle \(1\) is:

\(\begin{aligned}& \text{velocity of 2 relative to 1} \\ =\; & (\text{velocity of 2 relative to ground}) \\ &- (\text{velocity of 1 relative to ground}) \\ =\; & 33\; {\rm m\cdot s^{-1} - 28\; {\rm m\cdot s^{-1}} \\ =\; & 5\; {\rm m\cdot s^{-1}} && (\text{to the east})\end{aligned}\).

The displacement of vehicle \(2\) relative to vehicle \(1\) is currently \(0\; {\rm m}\). The rate at which this displacement increases is equal to the velocity of vehicle \(2\!\) relative to vehicle \(1\!\), which is \(5\; {\rm m\cdot s^{-1}}\).

Thus, it would take \((14 \; {\rm m}) / (5\; {\rm m\cdot s^{-1}}) = 2.8\; {\rm s}\) for this displacement to reach \(14\; {\rm m}\).

If the motorcyclist applies the front brake too hard, the front brake can lock up and skid, Option b is correct.

When a motorcyclist applies the front brake too hard, the front wheel can lock up and skid, causing the rider to lose control of the motorcycle. This happens because the front brake is responsible for most of the motorcycle's stopping power, and if it is applied too forcefully, the wheel can stop rotating altogether.

It is essential for motorcyclists to be aware of proper braking techniques and to apply the brakes smoothly and evenly to avoid skidding and accidents. Hence option b is correct choice.

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Answer:

your answer is 0.814.

Explanation:

you divide the total distance traveled by the time taken

Answer:

Explanation:

•Scientists have found that the rocks that make up the seabed are hidden in their "threads". This strip contains a record of the rotation of the Earth's magnetic field. The rocks on the seabed contain iron. ... When the rock cools down, the iron fragments inside align with the direction of the Earth's magnetic poles.

Answer:

The work done by the 20 N force is 61.3 J

Explanation:

20 N Force at horizon is: F=20 N*cos 40=15.32 N

The work done by 20 N at horizon is: W=F*S=15.32 N* 4 m=61.3 J

Answer:

The work done by the 20 N force is 61.3 J

Explanation:

Force can be defined as the product of mass and acceleration. It is measured in Newtons (N). Power can be defined as the rate at which work is done per unit of time. It is measured in Watts (W).

The pushing force can be determined using the following formula: Force = Magnetic force on the wire.

The magnetic force on the wire can be calculated using the formula: Fm = BIl, Where, Fm is the magnetic force, B is the magnetic field strength, I is the current, and l is the length of the wire.

Magnetic force on the wire: Fm = BIl = 0.50 T × I × 0.1 m. The resistance of the wire is zero, so the induced current will be given by the formula: I = V/R = Blv/R = 0.50 T × 0.1 m × 0.50 m/s / 0 ΩI = 2.5 A.

The magnetic force on the wire: Fm = 0.50 T × 2.5 A × 0.1 m = 0.125 N. The pushing force is 0.125 N.

The power supplied to the wire can be calculated as follows: Power = Force × VelocityPower = 0.125 N × 0.50 m/sPower = 0.0625 W. Power supplied to the wire is 0.0625 W.

The direction of the induced current will be in the opposite direction of the magnetic field, according to Lenz's law. The magnitude of the induced current is 2.5 A.

The power dissipated in the resistor can be calculated using the following formula: Power = I²RPower = (2.5 A)² × 2.0 ΩPower = 12.5 W.

The power dissipated in the resistor is 12.5 W.

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Answer:

yes because if red light was natural then it should cause more damage because that how it is

Answer:

its yes because if red light was natural then it should cause more damage because that how it is

Answer:

the first amendment

Explanation:

the first amendment to the United States constitution allows the freedoms concerning religion, expression, assembly, and the right to gather and petition.

Answer:

No, because the graph with the steepest slope experiences the greatest rate of change in velocity. That object has the greatest acceleration.

What does constant acceleration look like on an acceleration graph?

Constant acceleration means a horizontal line for the acceleration graph. The acceleration is the slope of the velocity graph. Constant acceleration = constant slope = straight line for the velocity graph. The area under the acceleration graph is the change in velocity.

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To determine the initial velocity of the cork as seen by an observer on the ground, we need to consider the relative motion between the balloon and the cork.

The velocity of the cork relative to the observer on the ground is the vector sum of the velocity of the cork relative to the balloon and the velocity of the balloon relative to the ground.

Given:

Velocity of the cork relative to the balloon: (4.00 m/s)x^

Velocity of the balloon relative to the ground: (3.00 m/s)y^

To find the initial velocity of the cork relative to the ground, we add the two velocities:

Velocity of the cork relative to the ground = Velocity of the cork relative to the balloon + Velocity of the balloon relative to the ground

In vector form:

\(V_cork\)-ground = \(V_cork\)-balloon + \(V_balloon\)-ground

In magnitude:

|\(V_cork\)-ground| = |\(V_cork\)-balloon| + |\(V_balloon\)-ground|

The magnitude of the velocity of the cork relative to the balloon is 4.00 m/s, and the magnitude of the velocity of the balloon relative to the ground is 3.00 m/s. Since the velocities are perpendicular to each other, we can use the Pythagorean theorem to find the magnitude of the velocity of the cork relative to the ground:

|\(V_cork\)-ground| =\(\sqrt{} 4.00 m/s)^2\) + (3.00 m/s)^2)

|\(V_cork\)-ground| = \(\sqrt{16.00 m^2/s^2\)+ 9.00 m^2/s^2)

|\(V_cork\)-ground| =\(\sqrt 25.00 m^2/s^2)\)

|\(V_cork\)-ground| = 5.00 m/s

Therefore, the initial velocity of the cork as seen by an observer on the ground is 5.00 m/s.

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Answer:

Approximately \(2.1\; \rm km\), assuming that \(g = -9.8\; \rm m \cdot s^{-2}\).

Explanation:

Let \(t\) denote the time required for the package to reach the ground. Let \(h(\text{initial})\) and \(h(\text{final})\) denote the initial and final height of this package.

\(\displaystyle h(\text{final}) = \frac{1}{2}\, g\, t^2 + h(\text{initial})\).

For this package:

Solve for \(t\), the time required for the package to reach the ground after being released.

\(\displaystyle t^{2} = \frac{2\, (h(\text{final}) - h(\text{initial}))}{g}\).

\(\begin{aligned} t &= \sqrt{\frac{2\, (h(\text{final}) - h(\text{initial}))}{g} \\ &\approx \sqrt{\frac{2\times (0\; \rm m - 2500\; \rm m)}{(-9.8\; \rm m \cdot s^{-2})}} \approx 22.588\; \rm s\end{aligned}\).

Assume that the air resistance on this package is negligible. The horizontal ("forward") velocity of this package would be constant (supposedly at \(95\; \rm m \cdot s^{-1}\).) From calculations above, the package would travel forward at that speed for about \(22.588\; \rm s\). That corresponds to approximately:\(95\; \rm m \cdot s^{-1} \times 22.588\; \rm s \approx 2.1 \times 10^{3}\; \rm m = 2.1\; \rm km\).

Hence, the package would land approximately \(2.1\; \rm km\) in front of where the plane released the package.

The term you are looking for is "chemical battery". Chemical batteries work by converting chemical energy into electrical energy through a series of chemical reactions. These reactions take place within the battery's cells, which are composed of two electrodes and an electrolyte.

When the battery is connected to a circuit, the chemical reactions produce an electrical current that can be used to power devices. Chemical batteries are widely used in many applications, including consumer electronics, electric vehicles, and renewable energy systems. They are a crucial component of our modern technological society, and ongoing research is focused on developing more efficient and sustainable battery technologies to meet growing energy demands.

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Given: Force F = 4i − 8j + 5k Distance = √(6 - 0)² + (16 - 10)² + (24 - 4)² = √36 + 36 + 400 = √472Newtons (N)Work done is given by the dot product of force F and distance. So, Work done = F.

Swhere S is the displacement = final position - initial position = (6i + 16j + 24k) - (0i + 10j + 4k) = 6i + 6j + 20kWork done = F.S= (4i - 8j + 5k).(6i + 6j + 20k) = 4(6) - 8(6) + 5(20) = 24 - 48 + 100 = 76J

Therefore, the work done by force F = 4i − 8j + 5k that moves an object from the point (0, 10, 4) to the point (6, 16, 24) along a straight line is 76J (Joules).

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Answer: F = 32 N

Explanation:  

F= m x a

m = 8 kg

a = 4 m/s²

F = 8 kg x 4 m/s² = 32  kg m /s² = 32 Newton

a) The isocost curve equation is G = (20000 - 100C)/500. b) The isocost curve equation is G = (30000 - 100c)/500. c) The isocost curve equation is G = (20000 - 100C)/375. d)  The isocost curve equation is G = (20000 - 120C)/500.

To draw the isocost curve showing the different combinations of gas and coal, we need to use the cost per unit values for coal and gas, as well as the given expenditure (TC) and the changes in expenditure or prices.

Let's denote the quantity of coal as C and the quantity of gas as G. The cost per unit of coal is 100, and the cost per unit of gas is 500.

(a) Initial expenditure (TC) of 20000:

To find the combinations of gas and coal that can be purchased with an initial expenditure of 20000, we can use the following isocost equation

TC = 100C + 500G

We can rearrange the equation to solve for G in terms of C

G = (TC - 100C) / 500

Now we can plot the isocost curve with TC = 20000 using the equation above.

(b) Expenditure (TC) increases by 50%

If the expenditure increases by 50%, the new expenditure (TC_new) becomes 1.5 × TC = 1.5 × 20000 = 30000.

We can use the same isocost equation as before, but with the new expenditure value:

TC_new = 100C + 500G

Rearranging the equation to solve for G

G = (TC_new - 100C) / 500

Now we can plot the isocost curve with TC_new = 30000.

(c) Gas price reduced by 25%:

If the gas price is reduced by 25%, the new cost per unit of gas (Gas_new) becomes 0.75 × 500 = 375.

We can use the original isocost equation, but with the new cost per unit value:

TC = 100C + 375G

Rearranging the equation to solve for G

G = (TC - 100C) / 375

Now we can plot the isocost curve with the reduced gas price.

(d) Coal price rises by 20%

If the coal price rises by 20%, the new cost per unit of coal (Coal_new) becomes 1.2 × 100 = 120.

We can use the original isocost equation, but with the new cost per unit value:

TC = 120C + 500G

Rearranging the equation to solve for G:

G = (TC - 120C) / 500

Now we can plot the isocost curve with the increased coal price.

By plotting these isocost curves on a graph with G on the y-axis and C on the x-axis, we can visualize the different combinations of gas and coal that can be purchased at the given expenditures or price changes.

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In a purely resistive circuit, the phase difference between the voltage and current is zero, which means the circuit consumes all the power delivered to it by the source. In other words, the power delivered is entirely converted into heat energy dissipated by the resistance. Therefore, 100% of the apparent power is used or consumed in a purely resistive circuit. So this statement is true.

Apparent power is the product of the root mean square (RMS) voltage and RMS current, and it represents the total power delivered to the circuit. In a purely resistive circuit, the apparent power and real power are equal since there is no reactive power. Reactive power arises in circuits with inductance and capacitance, where energy is stored and returned to the circuit, leading to a phase shift between voltage and current.

In a purely resistive circuit, the current and voltage are in phase with each other, meaning they reach their maximum and minimum values at the same time. This results in a power factor of 1, which indicates that all of the apparent power drawn by the circuit is converted into real power, which is the actual power consumed by the resistive elements in the circuit. Therefore, it is true that 100% of the apparent power is used or consumed in a purely resistive circuit.

This is not the case in circuits that have reactive elements, such as inductors and capacitors, where the current and voltage are out of phase with each other. This results in a power factor that is less than 1, and the apparent power drawn by the circuit includes both real power and reactive power. In such cases, some of the apparent power is not consumed by the resistive elements but instead is stored in the reactive elements and returned to the circuit at a later time.

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Answer:

The best thermal insulators have free electrons